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Search found 356 results on 15 pages for 'telephone'.

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  • dialing on iphone/ipod touch not working with documented procedures

    - by dave
    I'm trying to set up an iphone app to the phone number of a various sports store using the tel:// url passing method- I am developing on an ipod touch- usually on the touch you see the error message "Unsupported URL - This URL wasn't loaded tel://99887766" when you try and dial a number. I cant get this message to appear on the simulator or the ipod touch. do I need to do some sort of fancy signing before the app will dial properly? I am using this code: [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel:%@", [selectedBar phoneNumber]]]]; and I've tried adding the slashes: [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel://%@", [selectedBar phoneNumber]]]]; but neither work. I have also tried this way: [[UIApplication application] openURL:[NSURL URLWithString:@"tel://99887766"]]; and this way: NSMutableString *phone = [[@"+ 12 34 567 89 01" mutableCopy] autorelease]; [phone replaceOccurrencesOfString:@" " withString:@"" options:NSLiteralSearch range:NSMakeRange(0, [phone length])]; [phone replaceOccurrencesOfString:@"(" withString:@"" options:NSLiteralSearch range:NSMakeRange(0, [phone length])]; [phone replaceOccurrencesOfString:@")" withString:@"" options:NSLiteralSearch range:NSMakeRange(0, [phone length])]; NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"tel:%@", phone]]; [[UIApplication sharedApplication] openURL:url]; No matter what i do i can't get any response from the simulator / ipod touch that it is dealing with a phone number- When I press the button associated with this code, it doesnt crash, it's like its processed it and decided not to do anything. i even put an NSLog(@"button called"); in just before the code to confirm the button was working, which it is.

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  • android Convert phone number in International Format

    - by Arutha
    I'd like to know whether it's possible to have phone numbers converted into international format when a call is outgoing. For instance, if a french user (sorry it's the only format i know i won't make a mistake :-) try to call with the national format : 01.47.12.34.56 then a method will convert it into international format like this : +33.1.47.12.34.56 I've looked into the doc of the PhoneNumberUtils but i don't know if there is a method doing what i want.

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  • Find telephonenumbers - finding number with and without an phone extension

    - by nWorx
    Hello there I've a table with about 130 000 records with telephonenumbers. The numbers are all formated like this +4311234567. The numbers always include international country code, local area code and then the phonenumber and sometimes an extension. There is a webservice which checks for the caller's number in the table. That service works already. But now the client wants that also if someone calls from a company which number is already in the database but not his extension, that the service will return some result. Example for table. **id** | **telephonenumber** | **name** | 1 | +431234567 | company A | 2 | +431234567890 | employee in company A | 3 | +4398765432 | company b now if somebody from company A calls with a different extension for example +43123456777, than it should return id1. But the problem is, that I don't know how many digits the extensions have. It could have 3,4 or more digits. Are there any patterns for string kind of matchings? The data is stored in a sql2005 database. Thanks

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  • A comprehensive regex for phone number validation

    - by Nicholas Trandem
    I'm trying to put together a comprehensive regex to validate phone numbers. Ideally it would handle international formats, but it must handle US formats, including the following: 1-234-567-8901 1-234-567-8901 x1234 1-234-567-8901 ext1234 1 (234) 567-8901 1.234.567.8901 1/234/567/8901 12345678901 I'll answer with my current attempt, but I'm hoping somebody has something better and/or more elegant.

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  • JUnit testing, exception in threa main

    - by Crystal
    I am new to JUnit and am trying to follow my prof's example. I have a Person class and a PersonTest class. When I try to compile PersonTest.java, I get the following error: Exception in thread "main" java.lang.NoSuchMethodError: main I am not really sure why since I followed his example. Person.java public class Person implements Comparable { String firstName; String lastName; String telephone; String email; public Person() { firstName = ""; lastName = ""; telephone = ""; email = ""; } public Person(String firstName) { this.firstName = firstName; } public Person(String firstName, String lastName, String telephone, String email) { this.firstName = firstName; this.lastName = lastName; this.telephone = telephone; this.email = email; } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public String getTelephone() { return telephone; } public void setTelephone(String telephone) { this.telephone = telephone; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } public int compareTo(Object o) { String s1 = this.lastName + this.firstName; String s2 = ((Person) o).lastName + ((Person) o).firstName; return s1.compareTo(s2); } public boolean equals(Object otherObject) { // a quick test to see if the objects are identical if (this == otherObject) { return true; } // must return false if the explicit parameter is null if (otherObject == null) { return false; } if (!(otherObject instanceof Person)) { return false; } Person other = (Person) otherObject; return firstName.equals(other.firstName) && lastName.equals(other.lastName) && telephone.equals(other.telephone) && email.equals(other.email); } public int hashCode() { return this.email.toLowerCase().hashCode(); } public String toString() { return getClass().getName() + "[firstName = " + firstName + '\n' + "lastName = " + lastName + '\n' + "telephone = " + telephone + '\n' + "email = " + email + "]"; } } PersonTest.java import org.junit.Test; // JDK 5.0 annotation support import static org.junit.Assert.assertTrue; // Using JDK 5.0 static imports import static org.junit.Assert.assertFalse; // Using JDK 5.0 static imports import junit.framework.JUnit4TestAdapter; // Need this to be compatible with old test driver public class PersonTest { /** A test to verify equals method. */ @Test public void checkEquals() { Person p1 = new Person("jj", "aa", "[email protected]", "1112223333"); assertTrue(p1.equals(p1)); // first check in equals method assertFalse(p1.equals(null)); // second check in equals method assertFalse(p1.equals(new Object())); // third chk in equals method Person p2 = new Person("jj", "aa", "[email protected]", "1112223333"); assertTrue(p1.equals(p2)); // check for deep comparison p1 = new Person("jj", "aa", "[email protected]", "1112223333"); p2 = new Person("kk", "aa", "[email protected]", "1112223333"); assertFalse(p1.equals(p2)); // check for deep comkparison } }

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  • AttributeError in my Python program regarding classes

    - by Axel Finkel
    I'm doing an exercise out of the Python book that involves creating a class and a subclass. I am getting the following error when I try to run the program: AttributeError: 'Customer' object has no attribute 'name', when it tries to go through this bit of code: self.name.append(name) As this is my first time dealing with classes and objects in Python, I'm sure I am making some overt mistake somewhere, but I can't seem to figure it out. I've looked over the documentation for creating classes and writing member functions, and it looks correct, but it is obviously not. I want the Customer subclass to inherit the name, address, and telephone attributes from the Person superclass, but it doesn't seem to be doing so? Here is my code: class Person: def __init__(self): self.name = None self.address = None self.telephone = None def changeName(self, name): self.name.append(name) def changeAddress(self, address): self.address.append(address) def changeTelephone(self, telephone): self.telephone.append(telephone) class Customer(Person): def __init__(self): self.customerNumber = None self.onMailingList = False def changeCustomerNumber(self, customerNumber): self.customerNumber.append(customerNumber) def changeOnMailingList(): if onMailingList == False: onMailingList == True else: onMailingList == False def main(): customer1 = Customer() name = 'Bob Smith' address = '123 Somewhere Road' telephone = '111 222 3333' customerNumber = '12345' customer1.changeName(name) customer1.changeAddress(address) customer1.changeTelephone(telephone) customer1.changeCustomerNumber(customerNumber) print("Customer name: " + customer1.name) print("Customer address: " + customer1.address) print("Customer telephone number: " + customer1.telephone) print("Customer number: " + customer1.customerNumber) print("On mailing list: " + customer1.OnMailingList) customer1.changeOnMailingList() print("On mailing list: " + customer1.OnMailingList) main()

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  • Titanium webview bug or "feature"? Numbers converted to telephone links

    - by Alan Neal
    I can't stop Titanium's webview from converting numbers to telephone links. For instance, let's say I programmatically set the innerHTML of a div called test to 96840664702 and then write javascript... alert(document.getElementById('test').innerHTML In Mobile Safari on the iPhone, Firefox, etc., the alert will read "96840664702". If I point Titanium's webview to the same page, the alert will read: <a href="tel:96840664702" x-apple-data=detectors="true">96840664702</a> How can I globally disable the data-detectors? I tried a couple meta-tags... <meta name=”format-detection” content=”telephone=no” > <meta name="x-" http-equiv="x-rim-auto-match" forua="true" content="none"/> ... but they didn't work. I couldn't find a reference for a meta tag that specifically mentioned Apple's detectors. Again, it's only a problem in Titanium's webview. It works everywhere else.

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  • possible to make text messaging with php have a constant "telephone number" value?

    - by Rees
    hello, i have an iphone 3g and can successfully send text messages using the PHP mail() function. My issue is that for each message i receive, the "telephone number" associated with the incoming text message changes each time. If possible, I would like to somehow make this number constant so that I can take advantage of iphone's ability to aggregate all text messages from the same telephone number -Otherwise my iphone would be cluttered with messages. Is there a way to do this? an example of the numbers I receive would be 1(410) 000-001, 1(410) 000-002, 1(410) 000-003, etc... can i make this constant somehow? $message = stripslashes("new user just joined!"); mail("[email protected]", "Subject", "$message"); please let me know! thanks...

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  • save data in the database to xml in c [closed]

    - by Jayanth N
    I have some data in the database. I want those data in database to be stored as an xml file. I'm using postgresql 9.1 for database, for xml processing I'm using libxml (http://xmlsoft.org/). I'm writing the code in C language. Please help me. Detailed explanation: I have a client, which sends me a xml file. Server receives the xml file, parses the xml file and stores it in the db. From db i want to send the details in the form of an xml to the client. client: <employee> <name>glen</name> <telephone>123456789</telephone> </employee> <employee> <name>gwen</name> <telephone>123456789</telephone> </employee> server parses this xml file as displayed below: name : glen telephone:123456789 name : gwen telephone: 123456789 and saves it in a database(postgresql9.1) if the client requests for details of the employees, i've to send it in xml form from database.I don't know how to do it can u help me out.

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  • Sorting in Hash Maps in Java

    - by Crystal
    I'm trying to get familiar with Collections. I have a String which is my key, email address, and a Person object (firstName, lastName, telephone, email). I read in the Java collections chapter on Sun's webpages that if you had a HashMap and wanted it sorted, you could use a TreeMap. How does this sort work? Is it based on the compareTo() method you have in your Person class? I overrode the compareTo() method in my Person class to sort by lastName. But it isn't working properly and was wondering if I have the right idea or not. getSortedListByLastName at the bottom of this code is where I try to convert to a TreeMap. Also, if this is the correct way to do it, or one of the correct ways to do it, how do I then sort by firstName since my compareTo() is comparing by lastName. import java.util.*; public class OrganizeThis { /** Add a person to the organizer @param p A person object */ public void add(Person p) { staff.put(p.getEmail(), p); //System.out.println("Person " + p + "added"); } /** * Remove a Person from the organizer. * * @param email The email of the person to be removed. */ public void remove(String email) { staff.remove(email); } /** * Remove all contacts from the organizer. * */ public void empty() { staff.clear(); } /** * Find the person stored in the organizer with the email address. * Note, each person will have a unique email address. * * @param email The person email address you are looking for. * */ public Person findByEmail(String email) { Person aPerson = staff.get(email); return aPerson; } /** * Find all persons stored in the organizer with the same last name. * Note, there can be multiple persons with the same last name. * * @param lastName The last name of the persons your are looking for. * */ public Person[] find(String lastName) { ArrayList<Person> names = new ArrayList<Person>(); for (Person s : staff.values()) { if (s.getLastName() == lastName) { names.add(s); } } // Convert ArrayList back to Array Person nameArray[] = new Person[names.size()]; names.toArray(nameArray); return nameArray; } /** * Return all the contact from the orgnizer in * an array sorted by last name. * * @return An array of Person objects. * */ public Person[] getSortedListByLastName() { Map<String, Person> sorted = new TreeMap<String, Person>(staff); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; } private Map<String, Person> staff = new HashMap<String, Person>(); public static void main(String[] args) { OrganizeThis testObj = new OrganizeThis(); Person person1 = new Person("J", "W", "111-222-3333", "[email protected]"); Person person2 = new Person("K", "W", "345-678-9999", "[email protected]"); Person person3 = new Person("Phoebe", "Wang", "322-111-3333", "[email protected]"); Person person4 = new Person("Nermal", "Johnson", "322-342-5555", "[email protected]"); Person person5 = new Person("Apple", "Banana", "123-456-1111", "[email protected]"); testObj.add(person1); testObj.add(person2); testObj.add(person3); testObj.add(person4); testObj.add(person5); System.out.println(testObj.findByEmail("[email protected]")); System.out.println("------------" + '\n'); Person a[] = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("------------" + '\n'); a = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("SORTED" + '\n'); a = testObj.getSortedListByLastName(); for (Person b : a) { System.out.println(b); } } } Person class: public class Person implements Comparable { String firstName; String lastName; String telephone; String email; public Person() { firstName = ""; lastName = ""; telephone = ""; email = ""; } public Person(String firstName) { this.firstName = firstName; } public Person(String firstName, String lastName, String telephone, String email) { this.firstName = firstName; this.lastName = lastName; this.telephone = telephone; this.email = email; } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public String getTelephone() { return telephone; } public void setTelephone(String telephone) { this.telephone = telephone; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } public int compareTo(Object o) { String s1 = this.lastName + this.firstName; String s2 = ((Person) o).lastName + ((Person) o).firstName; return s1.compareTo(s2); } public boolean equals(Object otherObject) { // a quick test to see if the objects are identical if (this == otherObject) { return true; } // must return false if the explicit parameter is null if (otherObject == null) { return false; } if (!(otherObject instanceof Person)) { return false; } Person other = (Person) otherObject; return firstName.equals(other.firstName) && lastName.equals(other.lastName) && telephone.equals(other.telephone) && email.equals(other.email); } public int hashCode() { return this.email.toLowerCase().hashCode(); } public String toString() { return getClass().getName() + "[firstName = " + firstName + '\n' + "lastName = " + lastName + '\n' + "telephone = " + telephone + '\n' + "email = " + email + "]"; } }

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  • http_post() variables to php script from SMS message but only append data to text file if certain variable (telephone number) equals a known

    - by user1592162
    All, I have an SMS gateway application running on my server that passes incoming SMS messages to a php script. That script writes the data to a text file. Certain aspects of the message can be extracted as variables - for example: Message content: $msgdata Sender: $originator Time: $receivedtime etc... Using the script below I can easily write the message to a text file but it will write the data of every SMS that comes in. I only want to write to a text file if the $originator variable is a certain telephone number (e.g 07123456321) $date = date("d.m.Y H:i:s"); $msgdata = $_REQUEST["msgdata"]; $myFile3 = "test.txt"; $fh = fopen($myFile3, 'a') or die("can't open file"); $stringData3 = "$date - $msgdata\n"; fwrite($fh, $stringData3); fclose($fh); Your assistance is bery much appreciated. Many thanks in advance.

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  • add presence for a remote user to a legacy telephone system?

    - by niko
    we have a small call center that uses an old nortel phone system with analog lines. one of our sales people works from home so her calls do not go through the phone system. this creates a problem at time as the receptionist does not know if she is on the phone or not. we can easily get around this by using instant messenger status but i wanted to ask if there is another way that we can do it so that calls can also be forwarded to her when she is not on the phone. i realize that we can do this with a voip system but we're not planning on upgrading to voip until next year. does anyone know if there is an inexpensive way to add this capability today?

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  • Easiest way to find out if user has either Windows 7 or Vista (through telephone support)?

    - by Rabarberski
    If you have to provide some initial troubleshooting support by phone [or email], and you don't have access to the PC itself, what is the easiest and most foolproof question to find out if the 'dumb' user is using either Windows 7 or Windows Vista? For example: determining if the user has either Windows XP or Windows Vista/7 is easy. Just ask the user if the button at the left bottom corner is (a) either square with the word 'Start' on it, or (b) it is a round button. But how to determine the difference between Vista and 7? Edit: For all the existing answers the user has to type something, and do it correctly. Sometimes even that is already hard for a computer illiterate user. My XP example just requires looking. If it exists (although I am afraid it doesn't), I think a solution that is just based on something this is visually different between Vista and 7 would stand above all others. (Which makes Dan's suggestion to turn over the box and look at the label" not so stupid). Perhaps the small 'show desktop' rectangle at the right side of the task bar (was that present in Vista)?

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  • I wired up a z 80 using telephone wire and put a jump to 0000 0000 0000 0000

    - by john
    I put 1100 0011 0000 0000 0000 0000 in the 2764 eprom --- this is supposed to test the z80 -- I have a 555 timer running at 500 khz. Can this small program work with the z80 ? I looked at the address pins on a m465 oscilloscope. The address shows highs up to 0100 0000. I think it should only count to 0000 0000 0000 0011. Can the z80 be tested? The Santa Clara Valley also made the lm1871 radio control chip that could not show a high or a low without completing the entire rc loop.

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  • how to effectively keep/update postal and telephone code format for each country?

    - by melaos
    hi there, currently we have a table for regex format for phone and postal code for countries that we use to validate when the user register through our forms. but the problem remains on the maintenance on the correctness of these format, thus what's a good way to ensure that we always have the latest copy of this information? is there a web service/etc that i can use to get this? or does it even make sense to keep all these format but instead use a relaxed method to ensure that the user just keys in something which roughly matches the format? the information is used solely for shipping and billing address. we're using asp.net 2.0 btw. thanks ~steve

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  • BlackBerry 10 en images (8/9) : un téléphone ? Non, six ! A tous les prix, avec et sans clavier

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • T-SQL Right Joins to ALL Entries inc Selected Column

    - by Pace
    Hi Experts, I have the following Query which produces the output below; SELECT TBLUSERS.USERID, TBLUSERS.ADusername, TBLACCESSLEVELS.ACCESSLEVELID, TBLACCESSLEVELS.AccessLevelName FROM TBLACCESSLEVELS INNER JOIN TBLACCESSRIGHTS ON TBLACCESSLEVELS.ACCESSLEVELID = TBLACCESSRIGHTS.ACCESSLEVELID INNER JOIN TBLUSERS ON TBLACCESSRIGHTS.USERID = TBLUSERS.USERID The output is this; 29 administrator 1 AllUsers 29 administrator 2 JobQueue 29 administrator 3 Telephone Directory Admin 29 administrator 4 Jobqueueadmin 29 administrator 5 UserAdmin 29 administrator 6 Product System 27 alan 1 AllUsers 97 andy 1 AllUsers 26 barry 1 AllUsers 26 barry 2 JobQueue 26 barry 3 Telephone Directory Admin 26 barry 4 Jobqueueadmin 26 barry 5 UserAdmin 26 barry 6 Product System 26 barry 7 Newseditor 26 barry 8 GreetingBoard What I would like to do is modify the query so I get all Access Levels regardless of weather there is an entry for that user. What I would also like to do is some sort of exist case so that I get output like the following; 29 administrator 1 AllUsers True 29 administrator 2 JobQueue True 29 administrator 3 Telephone Directory Admin True 29 administrator 4 Jobqueueadmin True 29 administrator 5 UserAdmin True 29 administrator 6 Product System True 29 administrator 7 Newseditor False 29 administrator 8 GreetingBoard False 27 alan 1 AllUsers True 27 alan 2 JobQueue False 27 alan 3 Telephone Directory Admin False 27 alan 4 Jobqueueadmin False 27 alan 5 UserAdmin False 27 alan 6 Product System False 27 alan 7 Newseditor False 27 alan 8 GreetingBoard False 97 andy 1 AllUsers True 97 andy 2 JobQueue False 97 andy 3 Telephone Directory Admin False 97 andy 4 Jobqueueadmin False 97 andy 5 UserAdmin False 97 andy 6 Product System False 97 andy 7 Newseditor False 97 andy 8 GreetingBoard False 26 Barry 1 AllUsers True 26 Barry 2 JobQueue True 26 Barry 3 Telephone Directory Admin True 26 Barry 4 Jobqueueadmin True 26 Barry 5 UserAdmin True 26 Barry 6 Product System True 26 Barry 7 Newseditor True 26 Barry 8 GreetingBoard True ......................................... So the rules are ALWAYS show ALL Entries for ACCESSLEVELS and where EXISTS in ACCESSRIGHTS produce a true / false to show this. I hope this makes sense and hopefully you dont need the table definitions as everything I need to work with is in the original Query. I just need a way of manipulating it slightly and getting the join in the right place. Thank you. Pace

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  • Pos receipt printer

    - by unknown (google)
    Is it possible to connect a receipt printer to a telephone for printing similar to how a Credit card terminal works when connected to a telephone line. Our clients donot have internet connections where we can connect the printer over Ethernet, so was thinking if it was possible to do the same via telephone line.

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  • Broad Band LAN connection through existing 6 wire phone line ( no phone connected )

    - by Paul Taylor
    I have an (up to but never achieved ) 10 mb broadband signal coming into my house along the telephone line. The modem then connects the broadband signal via a LAN connection and Wi-Fi signal to my computers and iPad. My workshop desk is 54 yards (approx. 50m) downhill from the modem (part of a separate building) – too far to give a good direct signal. The inside corner of the workshop (by a window) receives a weak signal. I have a disconnected telephone cable consisting of 6 wires going from the house to the workshop. The telephone is no longer used in the workshop - we use our mobile number for business calls. A broad band signal using the cable would not have to share with a phone. What would be the most economic price/efficient way to get the broadband signal to the workshop? I am writing in hope that since the telephone didn't need the six wires, an Ethernet connection might be similar and not need all the eight wires for a LAN connection. In theory could use the telephone wire to pull an Ethernet cable trough the underground pipe but I doubt if the cable would survive the strain. The broad band connection in the workshop does not have to have network facility. My skill level is high enough to do house wiring, plumbing and gas fitting; so given any sound advice and a wiring diagram or instructions I can probably work out the rest myself.

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  • Linq To Xml problems using XElement's method Elements(XName)

    - by Dorian McHensie
    Hello everyone. I have a problem using Linq To Xml. A simple code. I have this XML: <?xml version="1.0" encoding="utf-8" ?> <data xmlns="http://www.xxx.com" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.xxx.com/directory file.xsd"> <contact> <name>aaa</name> <email>[email protected]</email> <birthdate>2002-09-22</birthdate> <telephone>000:000000</telephone> <description>Description for this contact</description> </contact> <contact> <name>sss</name> <email>[email protected]</email> <birthdate>2002-09-22</birthdate> <telephone>000:000000</telephone> <description>Description for this contact</description> </contact> <contact> <name>bbb</name> <email>[email protected]</email> <birthdate>2002-09-22</birthdate> <telephone>000:000000</telephone> <description>Description for this contact</description> </contact> <contact> <name>ccc</name> <email>[email protected]</email> <birthdate>2002-09-22</birthdate> <telephone>000:000000</telephone> <description>Description for this contact</description> </contact> I want to get every contact mapping it on an object Contact. To do this I use this fragment of code: XDocument XDoc = XDocument.Load(System.Web.HttpRuntime.AppDomainAppPath + this.filesource); XElement XRoot = XDoc.Root; //XElement XEl = XElement.Load(this.filesource); var results = from e in XRoot.Elements("contact") select new Contact((string)e.Element("name"), (string)e.Element("email"), "1-1-1", null, null); List<Contact> cntcts = new List<Contact>(); foreach (Contact cntct in results) { cntcts.Add(cntct); } Contact[] c = cntcts.ToArray(); // Encapsulating element Elements<Contact> final = new Elements<Contact>(c); Ok just don't mind that all: focus on this: When I get the root node, it is all right, I get it correctly. When I use the select directive I try to get every node saying: from e in XRoot.Elements("contact") OK here's the problem: if I use: from e in XRoot.Elements() I get all contact nodes, but if I use: from e in XRoot.Elements("contact") I GET NOTHING: Empty SET. OK you tell me: Use the other one: OK I DO SO, let's use: from e in XRoot.Elements(), I get all nodes anyway, THAT's RIGHT BUT HERE COMES THE OTHER PROBLEM: When Saying: select new Contact((string)e.Element("name"), (string)e.Element("email"), "1-1-1", null, null); I Try to access <name>, <email>... I HAVE TO USE .Element("name") AND IT DOES NOT WORK TOO!!!!!!!!WHAT THE HELL IS THIS????????????? IT SEEMS THAT I DOES NOT MATCH THE NAME I PASS But how is it possible. I know that Elements() function takes, overloaded, one argument that is an XName which is mapped onto a string. Please consider that the code I wrote come from an example, It should work. Please somebody help me. THANKS IN ADVANCE

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  • Regular Expression Longes Possible Matching

    - by syker
    So I have an input string which is a directory addres: Example: ProgramFiles/Micro/Telephone And I want to match it against a list of words very strictly: Example: Tel|Tele|Telephone I want to match against Telephone and not Tel. Right now my reg looks like this: my( $output ) = ( $input =~ m/($list)/o ); The regex above will match against Tel. What can I do to fix it?

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  • I can't create a view in oracle database using sqlplus (insufficient privileges)

    - by Nubkadiya
    I'm running this SQL: CREATE VIEW showMembersInfo(MemberID,Fname,Lname,Address,DOB,Telephone,NIC,Email,WorkplaceID,WorkName,WorkAddress,WorkTelephone,StartingDate,ExpiryDate,Amount,WitnessID,WitName,WitAddress,WitNIC,WitEmail,WitTelephone) AS SELECT mem.MemberID,mem.FirstName,mem.LastName,mem.Address,mem.DOB,mem.Telephone,mem.NIC,mem.Email, wrk.WorkPlaceID,wrk.Name,wrk.Address,wrk.Telephone, anl.StartingDate,anl.ExpiryDate,anl.Amount, wit.WitnessID,wit.Name,wit.Address,wit.NIC,wit.Email,wit.Telephone FROM Member mem, WorkPlace wrk, AnnualFees anl, Witness wit WHERE mem.MemberID = anl.MemberID AND mem.WorkPlaceID = work.WorkPlaceID AND mem.WitnessID = wit.WitnessID When I try to create the view I get this error: ERROR at line 1: ORA-01031: insufficient privileges Why is that? I'm logged in to sqlplus using sysman

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  • Why All The Hype Around Live Help?

    - by ruth.donohue
    I am pleased to introduce guest blogger, Damien Acheson today. Based in Cambridge, MA, Damien is the Product Marketing Manager for ATG’s Live Help products. Welcome, Damien!! BY DAMIEN ACHESON Why all the hype around live help? An eCommerce professional recently asked me: “Why all the hype around live chat and click to call?” I already have a customer service phone number that’s available to my online visitors. Why would I want to add live help? If anything, I want my website to reduce the number of calls to my contact center, not increase it!” The effect of adding live help to a website is counter-intuitive. Done right, live help doesn’t increase your call volume; it optimizes it by replacing traditional telephone calls with smarter, more productive, live voice and live chat interactions. This generates instant cost savings, and a measurable lift in sales and customer retention. A live help interaction differs from a traditional telephone call in six radical ways: Targeting. With live help you can target specific visitors at just the exact right time with a live call or live chat invitation based on hundreds of different parameters. For example, visitors who appear to hesitate before making a large purchase may receive a live help invitation, while others may not. Productivity. By reserving live voice to visitors with complex questions, and offering self-service and live chat for more simple interactions, agents with the right domain expertise can handle simultaneous queries and achieve substantial productivity gains. Routing. Live help interactions take into account visitors’ web context to intelligently route queries to the best available agent, thereby lifting first contact resolution. Context. Traditional telephone numbers force online customers to “change channels” and “start over” with a phone agent. With Live help, agents get the context of the web session and can instantly access the customer’s transaction details and account information, substantially reducing handle times. Interaction. Agents can solve a customer’s problem more effectively co-browsing and collaborating with the visitor in real-time to complete online forms and transactions. Analytics. Unlike traditional telephone numbers, live help allows you to tie Web analytics to customer satisfaction and agent performance indicators. To better understand these differences and advantages over traditional customer service, watch this demo on optimizing customer interactions with Live Help. Technorati Tags: ATG,Live Help,Commerce

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