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Graphics driver for ubuntu on dell latitude XT

- by marc.riera

we have a laptop (dell latitude xt) on our company, and we would like to install ubuntu on it. windows 7 works fine out of the box, so the hardware is fine. since this laptop has a touchscreen we just installed ubuntu 10.10 netbook edition 32x. But, we do not manage to enable the touchscreen, neither the vga graphic drivers. this is the output from lspci, if somebody cares. 00:00.0 Host bridge: ATI Technologies Inc Radeon Xpress 7930 Host Bridge 00:01.0 PCI bridge: ATI Technologies Inc RS7932 PCI Bridge 00:04.0 PCI bridge: ATI Technologies Inc Device 7934 00:06.0 PCI bridge: ATI Technologies Inc RS7936 PCI Bridge 00:07.0 PCI bridge: ATI Technologies Inc Device 7937 00:13.0 USB Controller: ATI Technologies Inc SB600 USB (OHCI0) 00:13.1 USB Controller: ATI Technologies Inc SB600 USB (OHCI1) 00:13.2 USB Controller: ATI Technologies Inc SB600 USB (OHCI2) 00:13.3 USB Controller: ATI Technologies Inc SB600 USB (OHCI3) 00:13.4 USB Controller: ATI Technologies Inc SB600 USB (OHCI4) 00:13.5 USB Controller: ATI Technologies Inc SB600 USB Controller (EHCI) 00:14.0 SMBus: ATI Technologies Inc SBx00 SMBus Controller (rev 14) 00:14.1 IDE interface: ATI Technologies Inc SB600 IDE 00:14.2 Audio device: ATI Technologies Inc SBx00 Azalia (Intel HDA) 00:14.3 ISA bridge: ATI Technologies Inc SB600 PCI to LPC Bridge 00:14.4 PCI bridge: ATI Technologies Inc SBx00 PCI to PCI Bridge 01:05.0 VGA compatible controller: ATI Technologies Inc Radeon Xpress 1250 03:01.0 CardBus bridge: Texas Instruments PCIxx12 Cardbus Controller 03:01.1 FireWire (IEEE 1394): Texas Instruments PCIxx12 OHCI Compliant IEEE 1394 Host Controller 03:01.3 SD Host controller: Texas Instruments PCIxx12 SDA Standard Compliant SD Host Controller 09:00.0 Ethernet controller: Broadcom Corporation NetXtreme BCM5756ME Gigabit Ethernet PCI Express 0b:00.0 Network controller: Broadcom Corporation BCM4321 802.11a/b/g/n (rev 03) I've tryied to install ati drivers 9.3 , which I downloaded and installed, unpacked and installed, builded and installed, but nothing worked. Looks like the latests version is just accepted to work on jaunty 9.04, so they are kind of old. what else I can do? thanks. Marc Information added: lsusb and lspci -n |grep 01:05.0 sysop@wl083517:~$ lspci -n |grep 01:05.0 01:05.0 0300: 1002:7942 sysop@wl083517:~$ lsusb Bus 006 Device 002: ID 413c:8138 Dell Computer Corp. Wireless 5520 Voda I Mobile Broadband (3G HSDPA) Minicard EAP-SIM Port Bus 006 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 005 Device 002: ID 413c:8140 Dell Computer Corp. Wireless 360 Bluetooth Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 002: ID 0483:2016 SGS Thomson Microelectronics Fingerprint Reader Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 003 Device 002: ID 1b96:0001 N-Trig Duosense Transparent Electromagnetic Digitizer Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 002 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 001 Device 002: ID 03f0:1807 Hewlett-Packard Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub sysop@wl083517:~$

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Applications: The Mathematics of Movement, Part 2

- by TechTwaddle

In part 1 of this series we saw how we can make the marble move towards the click point, with a fixed speed. In this post we’ll see, first, how to get rid of Atan2(), sine() and cosine() in our calculations, and, second, reducing the speed of the marble as it approaches the destination, so it looks like the marble is easing into it’s final position. As I mentioned in one of the previous posts, this is achieved by making the speed of the marble a function of the distance between the marble and the destination point. Getting rid of Atan2(), sine() and cosine() Ok, to be fair we are not exactly getting rid of these trigonometric functions, rather, replacing one form with another. So instead of writing sin(?), we write y/length. You see the point. So instead of using the trig functions as below, double x = destX - marble1.x; double y = destY - marble1.y; //distance between destination and current position, before updating marble position distanceSqrd = x * x + y * y; double angle = Math.Atan2(y, x); //Cos and Sin give us the unit vector, 6 is the value we use to magnify the unit vector along the same direction incrX = speed * Math.Cos(angle); incrY = speed * Math.Sin(angle); marble1.x += incrX; marble1.y += incrY; we use the following, double x = destX - marble1.x; double y = destY - marble1.y; //distance between destination and marble (before updating marble position) lengthSqrd = x * x + y * y; length = Math.Sqrt(lengthSqrd); //unit vector along the same direction as vector(x, y) unitX = x / length; unitY = y / length; //update marble position incrX = speed * unitX; incrY = speed * unitY; marble1.x += incrX; marble1.y += incrY; so we replaced cos(?) with x/length and sin(?) with y/length. The result is the same. Adding oomph to the way it moves In the last post we had the speed of the marble fixed at 6, double speed = 6; to make the marble decelerate as it moves, we have to keep updating the speed of the marble in every frame such that the speed is calculated as a function of the length. So we may have, speed = length/12; ‘length’ keeps decreasing as the marble moves and so does speed. The Form1_MouseUp() function remains the same as before, here is the UpdatePosition() method, private void UpdatePosition() { double incrX = 0, incrY = 0; double lengthSqrd = 0, length = 0, lengthSqrdNew = 0; double unitX = 0, unitY = 0; double speed = 0; double x = destX - marble1.x; double y = destY - marble1.y; //distance between destination and marble (before updating marble position) lengthSqrd = x * x + y * y; length = Math.Sqrt(lengthSqrd); //unit vector along the same direction as vector(x, y) unitX = x / length; unitY = y / length; //speed as a function of length speed = length / 12; //update marble position incrX = speed * unitX; incrY = speed * unitY; marble1.x += incrX; marble1.y += incrY; //check for bounds if ((int)marble1.x < MinX + marbleWidth / 2) { marble1.x = MinX + marbleWidth / 2; } else if ((int)marble1.x > (MaxX - marbleWidth / 2)) { marble1.x = MaxX - marbleWidth / 2; } if ((int)marble1.y < MinY + marbleHeight / 2) { marble1.y = MinY + marbleHeight / 2; } else if ((int)marble1.y > (MaxY - marbleHeight / 2)) { marble1.y = MaxY - marbleHeight / 2; } //distance between destination and marble (after updating marble position) x = destX - (marble1.x); y = destY - (marble1.y); lengthSqrdNew = x * x + y * y; /* * End Condition: * 1. If there is not much difference between lengthSqrd and lengthSqrdNew * 2. If the marble has moved more than or equal to a distance of totLenToTravel (see Form1_MouseUp) */ x = startPosX - marble1.x; y = startPosY - marble1.y; double totLenTraveledSqrd = x * x + y * y; if ((int)totLenTraveledSqrd >= (int)totLenToTravelSqrd) { System.Console.WriteLine("Stopping because Total Len has been traveled"); timer1.Enabled = false; } else if (Math.Abs((int)lengthSqrd - (int)lengthSqrdNew) < 4) { System.Console.WriteLine("Stopping because no change in Old and New"); timer1.Enabled = false; } } A point to note here is that, in this implementation, the marble never stops because it travelled a distance of totLenToTravelSqrd (first if condition). This happens because speed is a function of the length. During the final few frames length becomes very small and so does speed; and so the amount by which the marble shifts is quite small, and the second if condition always hits true first. I’ll end this series with a third post. In part 3 we will cover two things, one, when the user clicks, the marble keeps moving in that direction, rebounding off the screen edges and keeps moving forever. Two, when the user clicks on the screen, the marble moves towards it, with it’s speed reducing by every frame. It doesn’t come to a halt when the destination point is reached, instead, it continues to move, rebounds off the screen edges and slowly comes to halt. The amount of time that the marble keeps moving depends on how far the user clicks from the marble. I had mentioned this second situation here. Finally, here’s a video of this program running,

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LWJGL Circle program create's an oval-like shape

- by N1ghtk1n9

I'm trying to draw a circle in LWJGL, but when I draw I try to draw it, it makes a shape that's more like an oval rather than a circle. Also, when I change my circleVertexCount 350+, the shape like flips out. I'm really not sure how the code works that creates the vertices(I have taken Geometry and I know the basic trig ratios). I haven't really found that good of tutorials on creating circles. Here's my code: public class Circles { // Setup variables private int WIDTH = 800; private int HEIGHT = 600; private String title = "Circle"; private float fXOffset; private int vbo = 0; private int vao = 0; int circleVertexCount = 300; float[] vertexData = new float[(circleVertexCount + 1) * 4]; public Circles() { setupOpenGL(); setupQuad(); while (!Display.isCloseRequested()) { loop(); adjustVertexData(); Display.update(); Display.sync(60); } Display.destroy(); } public void setupOpenGL() { try { Display.setDisplayMode(new DisplayMode(WIDTH, HEIGHT)); Display.setTitle(title); Display.create(); } catch (LWJGLException e) { e.printStackTrace(); System.exit(-1); } glClearColor(0.0f, 0.0f, 0.0f, 0.0f); } public void setupQuad() { float r = 0.1f; float x; float y; float offSetX = 0f; float offSetY = 0f; double theta = 2.0 * Math.PI; vertexData[0] = (float) Math.sin(theta / circleVertexCount) * r + offSetX; vertexData[1] = (float) Math.cos(theta / circleVertexCount) * r + offSetY; for (int i = 2; i < 400; i += 2) { double angle = theta * i / circleVertexCount; x = (float) Math.cos(angle) * r; vertexData[i] = x + offSetX; } for (int i = 3; i < 404; i += 2) { double angle = Math.PI * 2 * i / circleVertexCount; y = (float) Math.sin(angle) * r; vertexData[i] = y + offSetY; } FloatBuffer vertexBuffer = BufferUtils.createFloatBuffer(vertexData.length); vertexBuffer.put(vertexData); vertexBuffer.flip(); vao = glGenVertexArrays(); glBindVertexArray(vao); vbo = glGenBuffers(); glBindBuffer(GL_ARRAY_BUFFER, vbo); glBufferData(GL_ARRAY_BUFFER,vertexBuffer, GL_STATIC_DRAW); glVertexAttribPointer(0, 2, GL_FLOAT, false, 0, 0); glBindBuffer(GL_ARRAY_BUFFER, 0); glBindVertexArray(0); } public void loop() { glClear(GL_COLOR_BUFFER_BIT); glBindVertexArray(vao); glEnableVertexAttribArray(0); glDrawArrays(GL_TRIANGLE_FAN, 0, vertexData.length / 2); glDisableVertexAttribArray(0); glBindVertexArray(0); } public static void main(String[] args) { new Circles(); } private void adjustVertexData() { float newData[] = new float[vertexData.length]; System.arraycopy(vertexData, 0, newData, 0, vertexData.length); if(Keyboard.isKeyDown(Keyboard.KEY_W)) { fXOffset += 0.05f; } else if(Keyboard.isKeyDown(Keyboard.KEY_S)) { fXOffset -= 0.05f; } for(int i = 0; i < vertexData.length; i += 2) { newData[i] += fXOffset; } FloatBuffer newDataBuffer = BufferUtils.createFloatBuffer(newData.length); newDataBuffer.put(newData); newDataBuffer.flip(); glBindBuffer(GL_ARRAY_BUFFER, vbo); glBufferSubData(GL_ARRAY_BUFFER, 0, newDataBuffer); glBindBuffer(GL_ARRAY_BUFFER, 0); } } 300 Vertex Count(This is my main problem) 400 Vertex Count - I removed this image, it's bugged out, should be a tiny sliver cut out from the right, like a secant 500 Vertex Count Each 100, it removes more and more of the circle, and so on.

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