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  • Launch a new page in Zend/php on button click

    - by BlueMonster
    PHP & Zend Noob here I've downloaded the skeleton project from here: https://github.com/zendframework/ZendSkeletonApplication Say i want to open a new page that simply displays "hello world" text if click on the "ZF2 Development Portal" button(bottom left green button) on the page that launches --- how do i do this? See image: I've read through this tutorial, but i'm not sure how the model, view, or controller are actually launched? See tutorial: http://blog.wilgucki.pl/2012/07/tworzenie-modulw-w-zend-framework-2.html From looking at the code, i know that i will have to change this line of code: <div class="span4"> <h2><?php echo $this->translate('Follow Development') ?></h2> <p><?php echo sprintf($this->translate('Zend Framework 2 is under active development. If you are interested in following the development of ZF2, there is a special ZF2 portal on the official Zend Framework website which provides links to the ZF2 %swiki%s, %sdev blog%s, %sissue tracker%s, and much more. This is a great resource for staying up to date with the latest developments!'), '<a href="http://framework.zend.com/wiki/display/ZFDEV2/Home">', '</a>', '<a href="http://framework.zend.com/zf2/blog">', '</a>', '<a href="http://framework.zend.com/issues/browse/ZF2">', '</a>') ?></p> <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> </div> More specifically this line: <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> but i'm really confused as to what i'm supposed to change it to in order to launch a new page. Any ideas? Thanks in advance!

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  • startup Error for Zend Server CE

    - by Jamison
    Hello! I've got a strange startup error for Zend Server CE - it's probably easy to fix, but I don't have much experience with Zend Server! I'm running the latest OSX 10.6.6 and the latest Zend Server CE for Mac. When I run the "start" command from the command line, here is what I get: /usr/local/zend/bin/apachectl start [OK] spawn-fcgi: child spawned successfully: PID: 4206 /usr/local/zend/bin/shell_functions.rc: line 133: 4210 Bus error $WATCHDOG -i $BINARY 1>&3 2>&4 /usr/local/zend/bin/shell_functions.rc: line 133: 4211 Bus error $WATCHDOG -u $WD_UID -g $WD_GID -s $BINARY 1>&3 2>&4 Starting Zend Server GUI [Lighttpd] [FAILED] /usr/local/zend/bin/lighttpdctl.sh: line 46: 4212 Bus error $WATCHDOG -i $BINARY Starting MySQL SUCCESS! /usr/local/zend/bin/shell_functions.rc: line 133: 4304 Bus error $WATCHDOG -i $BINARY 1>&3 2>&4 /usr/local/zend/bin/shell_functions.rc: line 133: 4425 Bus error $WATCHDOG -u $WD_UID -g $WD_GID -s $BINARY 1>&3 2>&4 Starting Java bridge [FAILED] /usr/local/zend/bin/java_bridge.sh: line 39: 4426 Bus error $WATCHDOG -i $BINARY Zend Server started... The challenge is that ZEND SERVER wont open the GUI with this error, and seemingly I can click on Zend Server in the Applications folder and it opens for a second and immediately closes. I've made sure that Web Sharing is turned off to avoid conflicts, and I've run Disk Utility from my recovery disk to make sure there are no file system errors. Here is what the lines that are referenced in the errors have in terms of code: shell_functions.rc: (starting on line 132 - the error message says line 133...): launch() { if [ -z "$DEBUG" ]; then exec 3>/dev/null 4>&3 else exec 3>&1 4>&2 fi $WATCHDOG -i $BINARY 1>&3 2>&4 RET=$? if [ $RET -eq 0 ];then $ECHO_CMD "$BINARY watchdog is up and running.. ${OK_COLOR}[OK]${T_RESET}" return $RET else #$WATCHDOG -u $WD_UID -g $WD_GID -s $BINARY >> "$PREFIX/logs/watchdog_$BINARY.log" 2>&1 $WATCHDOG -u $WD_UID -g $WD_GID -s $BINARY 1>&3 2>&4 report $? "Starting" fi } _kill() { $WATCHDOG -i $BINARY > /dev/null 2>&1 if [ $? -eq 1 ];then $ECHO_CMD "$BINARY is not running" else $WATCHDOG -t $BINARY > /dev/null 2>&1 report $? "Stopping" fi } lighttpdctl.sh: (starting on line 45 - the error message says line 46...): status() { $WATCHDOG -i $BINARY } case "$1" in start) start status ;; stop) stop ;; restart) stop sleep 1 start ;; status) status ;; *) usage exit 1 esac exit $? java_bridge.sh: (starting on line 38 - the error message says line 39...): status() { $WATCHDOG -i $BINARY } Question: "Watchdog" is library in this zend BIN folder - it seems to handle error reporting? all the errors in my start command seem to deal with this Watchdog thing, but I don't know what to do about it... Thanks!

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  • MVVM View-First Approach How Change View

    - by CodeWeasel
    Hi everybody, Does anybody have an idea how to change screens (views) in a MVVM View-First-Approach (The view instantiates the ViewModel: DataContext="{Binding Source={StaticResource VMLocator}, Path=Find[EntranceViewModel]}" ) For example: In my MainWindow (Shell) I show a entrance view with a Button "GoToBeach". <Window> <DockPanel> <TextBox DockPanel.Dock="Top" Text="{Binding Title}" /> <view.EntranceView DockPanel.Dock="Top" /> </DockPanel> </Window> When the button is clicked I want to get rid of the "EntranceView" and show the "BeachView". I am really curious if somebody knows a way to keep the View-First Approach and change the screen (view) to the "BeachView". I know there are several ways to implement it in a ViewModel-First Approach, but that is not the question. Perhabs I missed something in my mvvm investigation and can't see the wood for the trees... otherwise i am hoping for a inspiring discussion.

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  • Zend DB returning NULL value

    - by davykiash
    I have the following query that extends from Zend_DB_Table_Abstract $select = $this->select() ->from('expense_details', array('SUM(expense_details_amount) AS total')) ->where('YEAR(expense_details_date) = ?', '2010') ->where('MONTH(expense_details_date) = ?', '01') ->where('expense_details_linkemail = ?', '[email protected]'); However it returning a NULL value despite its "equivalent" returning the desired value SELECT SUM(expense_details_amount) AS total FROM expense_details WHERE YEAR(expense_details_date) = '2010' AND MONTH(expense_details_date) = '01' AND expense_details_linkemail = '[email protected]' Is my Zend_DB_Table construct above correct?

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  • Table Decorators on Zend Framework Form

    - by ulduz114
    hello i created a form that it decorates as table form its my code for decorates $this->setElementDecorators(array( 'ViewHelper', 'Errors' array(array('data'=>'HtmlTag'), array('tag'=>'td','class'=>'element')), array('Label',array('tag'=>'td')), array(array('row'=>'HtmlTag'),array('tag'=>'tr')), )); $this->setDecorators(array( 'FormElements', array('HtmlTag',array('tag'=>'table')), 'Form' )); it works correctly, now i wana errors message decorates too what do i change my code?

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  • Giving Zend Navigation Pages Multiple ACL Privileges

    - by Sonny
    I'm using Zend_Navigation and am trying to integrate it with Zend_Acl. Each page in the navigation has a privilege attribute. What I can't determine is how to define multiple privileges for a single page. Use case: A page that is for managing users. I want to display that page (in navigation) if the current signed in user's role has add, edit, or delete privileges on the Users resource. Example entry in the navigation XML: <admin_users> <label>Users</label> <route>default</route> <controller>admin</controller> <action>users</action> <resource>Users</resource> <privilege>add,edit,delete</privilege> </admin_users> Using a comma-separated list as above doesn't lend the desired behavior.

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  • Zend Server with xampp MySQL

    - by Vincent
    I am running Zend Server,Zend Studio (Trial versions) on Ubuntu 9.10. I am also using xampp to do most of my development. I plan to use Zend Server only to do URL profiling to know function level performance of my code. Is it possible to configure Zend Server to use XAMPP's MySQL database instead of installing a new mysql instance for Zend Server? Thanks

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  • how to Decorate the error message on zend framework

    - by ulduz114
    this is the decorator code $mydecorate = array( 'ViewHelper', array('Errors', array('placement' => 'append','class' => 'error')), array('Label', array('separator' => '')), array('HtmlTag', array('tag' => 'p', 'class' => 'element-form')) ); html result of two input elements with the above decorator: <p class="element-form"> <label for="firstname" class="required">First Name:</label> <input name="firstname" id="firstname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> <p class="element-form"> <label for="lastname" class="required">Last Name:</label> <input name="lastname" id="lastname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> I'd like the error message to be placed inside the p.element-form tag, any idea pleas? thanks

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  • Zend Framework Relationships - findDependentRowset

    - by Morten Nielsen
    Hello, When I call the method findDependentRowset, the returning rowset contains all the rows in the dependent table, and not only the rowsets that matches the reference. Hoping someone could explain this, since I was of the assumption that findDependentRowset would only return rowset matching my 'rule'? I have the following DbTable Models: class Model_DbTable_Advertisement extends Zend_Db_Table_Abstract { protected $_name = 'Advertisements'; protected $_primary = 'Id'; protected $_dependentTables = array ( 'Model_DbTable_Image', ); } class Model_DbTable_Image extends Zend_Db_Table_Abstract { protected $_name = 'Images'; protected $_primary = 'Id'; protected $_referenceMap = array( 'Images' => array( 'column' => 'AdvertisementId', 'refColumn' => 'Id', 'refTableClass' => 'Model_DbTable_Advertisement', ) ); } Now when i execute the following: (Simplified for Question sake) $model = new Model_DbTable_Advertisement(); $rowSet = $model->fetchAll(); $row = $rowSet->current(); $dRow = $row->findDependentRowset('Model_DbTable_Image'); I would expect $dRow to only contain 'Images' that has the same advertisementId as $row, but instead i receive all rows in the Images table. Any help appriciated. Kind regards, Morten

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  • Passing variables to a Custom Zend Form Element

    - by user322003
    Hi, I'm trying to create a custom form element which extends Zend_Form_Element_Text with a validator (so I don't have to keep setting up the validator when I use certain elements). Anyway, I'm having trouble passing $maxChars variable to it when I instantiate it in my Main form. I've provided my shortened code below This is my custom element below class My_Form_Custom_Element extends Zend_Form_Element_Text { public $maxChars public function init() { $this->addValidator('StringLength', true, array(0, $this->maxChars)) } public function setProperties($maxChars) { $this->maxChars= $maxChars; } } This is where I instantiate my custom form element. class My_Form_Abc extends Zend_Form { public function __construct($options = null) { parent::__construct($options); $this->setName('abc'); $customElement = new My_Form_Custom_Element('myCustomElement'); $customElement->setProperties(100); //**<----This is where i set the $maxChars** $submit = new Zend_Form_Element_Submit('submit'); $submit -> setAttrib('id', 'submitbutton'); $this->addElements(array($customElement ,$submit)); } } When I try to pass '100' using $customElement-setProperties(100) in my Form, it doesnt get passed properly to my StringLength validator. I assume it's because the validator is getting called in Init? How can I fix this?

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  • zend-framework navigation

    - by ulduz114
    i have this xml file for Creating a container , if i want create a db for save this items and and create container from db how should i do ? <?xml version="1.0" encoding="utf-8"?> <config> <nav> <logout> <label>logout</label> <controller>authentication</controller> <action>logout</action> <resource>logout</resource> </logout> <login> <label>login</label> <controller>authentication</controller> <action>login</action> <resource>login</resource> </login> <test> <label>test</label> <uri>#</uri> <resource>test</resource> <pages> <list> <label>list</label> <controller>tset</controller> <action>listtest</action> </list> <archive> <label>archive</label> <controller>myarchive</controller> <action>archive</action> </archive> </pages> </test> </nav> </config> and code in bootsrap $navContainerConfig = new Zend_Config_Xml(APPLICATION_PATH . 'navigation.xml', 'nav'); $navContainer = new Zend_Navigation($navContainerConfig);

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  • Zend Framework: Controller Plugins vs Action Helpers

    - by Laimoncijus
    Could someone give few tips and/or examples how Controller Plugins and Action Helpers are different? Are there situations where particular task could be accomplished with one but not another? For me they both look more or less the same and I'm often having trouble having to decide when to use what... Are there any big differences?

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  • What the difference between zend framework and Wordpress as framework ?

    - by justjoe
    i only know wordpress and start to seek another alternative framework, zend. i heard hearsay that zend's better from others framework. if you're "a serous coder", or try to act like one, you need to use it on building your web app. some said zend is better. But it's subjective. It's fast ans secure. But nobody tell me the reason or at leas compare it with with wordpress. ultimate question : Do zend have theme or plugin just like wordpress ? any hint will be helpful

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  • Integrating Zend Controller Standalone - without the rest of Zend Framework

    - by ssmusoke
    I am using specific parts of the Zend Framework in my application, and I would like to replace my home grown controller with a Zend Framework controller. My home grown controller is based on an index.php file to which all requests are submitted. A controller is instantiated based on parameters sent within the request After processing the user is forwarded to url which is based on the request information, either a url is specified or some data is analysed I would like ideas on how to integrate the Zend Controller within my application Thanks in advance

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  • Zend framework Zend_Controller_Action_HelperBroker::addPath does not work

    - by Carl Adam McDade
    I get this message regardless of the path used and even if I place the class file in the default directory location. Zend_Controller_Action_HelperBroker::addPath('./Plugins/Helpers','Helper'); Sorry, An error has occured: Application Error:exception 'Zend_Loader_PluginLoader_Exception' with message 'Plugin by name 'FormLoader' was not found in the registry; used paths: Zend_Controller_Action_Helper_: Zend/Controller/Action/Helper/' in C:\PHP\Zendframework\Zend\Loader\PluginLoader.php:412 Stack trace: #0 C:\PHP\Zendframework\Zend\Controller\Action\HelperBroker.php(366): Zend_Loader_PluginLoader->load('FormLoader') #1 C:\PHP\Zendframework\Zend\Controller\Action\HelperBroker.php(293): Zend_Controller_Action_HelperBroker::_loadHelper('FormLoader') #2 C:\PHP\Zendframework\Zend\Controller\Action\HelperBroker.php(323): Zend_Controller_Action_HelperBroker->getHelper('formLoader') #3 D:\websites\maklare.easypic.se\appfiles\application\controllers\UserController.php(13): Zend_Controller_Action_HelperBroker->__call('formLoader', Array) #4 D:\websites\maklare.easypic.se\appfiles\application\controllers\UserController.php(13): Zend_Controller_Action_HelperBroker->formLoader('login') #5 C:\PHP\Zendframework\Zend\Controller\Action.php(513): UserController->indexAction() #6 C:\PHP\Zendframework\Zend\Controller\Dispatcher\Standard.php(295): Zend_Controller_Action->dispatch('indexAction') #7 C:\PHP\Zendframework\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #8 C:\PHP\Zendframework\Zend\Controller\Front.php(212): Zend_Controller_Front->dispatch() #9 D:\websites\maklare.easypic.se\index.php(23): Zend_Controller_Front::run('D:\websites\mak...') #10 {main} Next exception 'Zend_Controller_Action_Exception' with message 'Action Helper by name FormLoader not found' in C:\PHP\Zendframework\Zend\Controller\Action\HelperBroker.php:369 Stack trace: #0 C:\PHP\Zendframework\Zend\Controller\Action\HelperBroker.php(293): Zend_Controller_Action_HelperBroker::_loadHelper('FormLoader') #1 C:\PHP\Zendframework\Zend\Controller\Action\HelperBroker.php(323): Zend_Controller_Action_HelperBroker->getHelper('formLoader') #2 D:\websites\maklare.easypic.se\appfiles\application\controllers\UserController.php(13): Zend_Controller_Action_HelperBroker->__call('formLoader', Array) #3 D:\websites\maklare.easypic.se\appfiles\application\controllers\UserController.php(13): Zend_Controller_Action_HelperBroker->formLoader('login') #4 C:\PHP\Zendframework\Zend\Controller\Action.php(513): UserController->indexAction() #5 C:\PHP\Zendframework\Zend\Controller\Dispatcher\Standard.php(295): Zend_Controller_Action->dispatch('indexAction') #6 C:\PHP\Zendframework\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #7 C:\PHP\Zendframework\Zend\Controller\Front.php(212): Zend_Controller_Front->dispatch() #8 D:\websites\maklare.easypic.se\index.php(23): Zend_Controller_Front::run('D:\websites\mak...') #9 {main}

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  • How do I use ViewScripts on Zend_Form File Elements?

    - by Sonny
    I am using this ViewScript for my standard form elements: <div class="field" id="field_<?php echo $this->element->getId(); ?>"> <?php if (0 < strlen($this->element->getLabel())) : ?> <?php echo $this->formLabel($this->element->getName(), $this->element->getLabel());?> <?php endif; ?> <span class="value"><?php echo $this->{$this->element->helper}( $this->element->getName(), $this->element->getValue(), $this->element->getAttribs() ) ?></span> <?php if (0 < $this->element->getMessages()->length) : ?> <?php echo $this->formErrors($this->element->getMessages()); ?> <?php endif; ?> <?php if (0 < strlen($this->element->getDescription())) : ?> <span class="hint"><?php echo $this->element->getDescription(); ?></span> <?php endif; ?> </div> Trying to use that ViewScript alone results in an error: Exception caught by form: No file decorator found... unable to render file element Looking at this FAQ revealed part of my problem, and I updated my form element decorators like this: 'decorators' => array( array('File'), array('ViewScript', array('viewScript' => 'form/field.phtml')) ) Now it's rendering the file element twice, once within my view script, and extra elements with the file element outside my view script: <input type="hidden" name="MAX_FILE_SIZE" value="8388608" id="MAX_FILE_SIZE" /> <input type="hidden" name="UPLOAD_IDENTIFIER" value="4b5f7335a55ee" id="progress_key" /> <input type="file" name="upload_file" id="upload_file" /> <div class="field" id="field_upload_file"> <label for="upload_file">Upload File</label> <span class="value"><input type="file" name="upload_file" id="upload_file" /></span> </div> Any ideas on how to handle this properly with a ViewScript?

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  • Is Zend Certification "needed" before starting with the Zend Framework?

    - by mojah
    Hi, We're starting a new project using the Zend Framework, because the ideas and expandability speaks to us. But now I'm wondering, should we first get some form of Zend Certification before starting with the Zend Framework? Will we miss fundamental yet basic groundrules if we just start "hacking away" using the Zend Framework? I don't want to see us have to redo (part of) the project, because we missed some vital guidelines from the beginning, forcing us to rewrite our code. If possible, I'd love to hear stories of others having used the Zend Framework, without certification, to see what limitations they ran accross.

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  • Proper 'cleartool mkview' for ClearCase Snapshot view creation

    - by Jörg Battermann
    Good afternoon, seems like I am somewhat stuck in CC-land these days, but I have one (hopefully) final question regarding proper CC-handling: When using the CC View Creation Wizard with the two steps / details below, I can create a proper Snapshot view on my machine perfectly fine, however when trying to do the same with the mkview command, it fails... Here are the screenshots of the view creation wizard: Now that results into the (working) following view: cleartool> lsview battjo6r_view2 battjo6r_view2 \\Eh40yd4c\Views\battjo6r_view2.vws cleartool> lsview -long battjo6r_view2 Tag: battjo6r_view2 Global path: \\Eh40yd4c\Views\battjo6r_view2.vws Server host: Eh40yd4c Region: CT_WORK Active: NO View tag uuid:f34cf43f.b4d048df.845d.ed:21:a2:9c:45:ff View on host: Eh40yd4c View server access path: D:\Views\battjo6r_view2.vws View uuid: f34cf43f.b4d048df.845d.ed:21:a2:9c:45:ff View attributes: snapshot View owner: WW005\battjo6r However, when trying to create the view manually via mkview -snapshot -tag battjo6r_view2 -vws \\Eh40yd4c\Views\battjo6r_view2.vws -host Eh40yd4c -hpath D:\Views\battjo6r_view2.vws -gpath \\Eh40yd4c\Views\battjo6r_view2.vws battjo6r_view2 ... I get the following error: cleartool> mkview -snapshot -tag battjo6r_view2 -vws \\Eh40yd4c\Views\battjo6r_view2.vws -host Eh40yd4c -hpath D:\Views\battjo6r_view2.vws -gpath \\Eh40yd4c\Views\battjo6r_view2.vws battjo6r_view2 Created view. Host-local path: Eh40yd4c:D:\Views\battjo6r_view2.vws Global path: \\Eh40yd4c\Views\battjo6r_view2.vws cleartool: Error: Unable to find view by uuid:6f99f7ae.6a5d40e4.ba32.37:8e:e5:a4:ed:18, last known at "<viewhost>:<stg_path>". cleartool: Error: Unable to establish connection to snapshot view "6f99f7ae.6a5d40e4.ba32.37:8e:e5:a4:ed:18": ClearCase object not found cleartool: Warning: Unable to open snapshot view "D:\SnapShotViews\battjo6r_view2". cleartool: Error: Unable to create snapshot view "battjo6r_view2". Removing the view ... Any idea why this is happening? Am I missing something?

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  • Silverlight Tree View with Multiple Levels

    - by psheriff
    There are many examples of the Silverlight Tree View that you will find on the web, however, most of them only show you how to go to two levels. What if you have more than two levels? This is where understanding exactly how the Hierarchical Data Templates works is vital. In this blog post, I am going to break down how these templates work so you can really understand what is going on underneath the hood. To start, let’s look at the typical two-level Silverlight Tree View that has been hard coded with the values shown below: <sdk:TreeView>  <sdk:TreeViewItem Header="Managers">    <TextBlock Text="Michael" />    <TextBlock Text="Paul" />  </sdk:TreeViewItem>  <sdk:TreeViewItem Header="Supervisors">    <TextBlock Text="John" />    <TextBlock Text="Tim" />    <TextBlock Text="David" />  </sdk:TreeViewItem></sdk:TreeView> Figure 1 shows you how this tree view looks when you run the Silverlight application. Figure 1: A hard-coded, two level Tree View. Next, let’s create three classes to mimic the hard-coded Tree View shown above. First, you need an Employee class and an EmployeeType class. The Employee class simply has one property called Name. The constructor is created to accept a “name” argument that you can use to set the Name property when you create an Employee object. public class Employee{  public Employee(string name)  {    Name = name;  }   public string Name { get; set; }} Finally you create an EmployeeType class. This class has one property called EmpType and contains a generic List<> collection of Employee objects. The property that holds the collection is called Employees. public class EmployeeType{  public EmployeeType(string empType)  {    EmpType = empType;    Employees = new List<Employee>();  }   public string EmpType { get; set; }  public List<Employee> Employees { get; set; }} Finally we have a collection class called EmployeeTypes created using the generic List<> class. It is in the constructor for this class where you will build the collection of EmployeeTypes and fill it with Employee objects: public class EmployeeTypes : List<EmployeeType>{  public EmployeeTypes()  {    EmployeeType type;            type = new EmployeeType("Manager");    type.Employees.Add(new Employee("Michael"));    type.Employees.Add(new Employee("Paul"));    this.Add(type);     type = new EmployeeType("Project Managers");    type.Employees.Add(new Employee("Tim"));    type.Employees.Add(new Employee("John"));    type.Employees.Add(new Employee("David"));    this.Add(type);  }} You now have a data hierarchy in memory (Figure 2) which is what the Tree View control expects to receive as its data source. Figure 2: A hierachial data structure of Employee Types containing a collection of Employee objects. To connect up this hierarchy of data to your Tree View you create an instance of the EmployeeTypes class in XAML as shown in line 13 of Figure 3. The key assigned to this object is “empTypes”. This key is used as the source of data to the entire Tree View by setting the ItemsSource property as shown in Figure 3, Callout #1. Figure 3: You need to start from the bottom up when laying out your templates for a Tree View. The ItemsSource property of the Tree View control is used as the data source in the Hierarchical Data Template with the key of employeeTypeTemplate. In this case there is only one Hierarchical Data Template, so any data you wish to display within that template comes from the collection of Employee Types. The TextBlock control in line 20 uses the EmpType property of the EmployeeType class. You specify the name of the Hierarchical Data Template to use in the ItemTemplate property of the Tree View (Callout #2). For the second (and last) level of the Tree View control you use a normal <DataTemplate> with the name of employeeTemplate (line 14). The Hierarchical Data Template in lines 17-21 sets its ItemTemplate property to the key name of employeeTemplate (Line 19 connects to Line 14). The source of the data for the <DataTemplate> needs to be a property of the EmployeeTypes collection used in the Hierarchical Data Template. In this case that is the Employees property. In the Employees property there is a “Name” property of the Employee class that is used to display the employee name in the second level of the Tree View (Line 15). What is important here is that your lowest level in your Tree View is expressed in a <DataTemplate> and should be listed first in your Resources section. The next level up in your Tree View should be a <HierarchicalDataTemplate> which has its ItemTemplate property set to the key name of the <DataTemplate> and the ItemsSource property set to the data you wish to display in the <DataTemplate>. The Tree View control should have its ItemsSource property set to the data you wish to display in the <HierarchicalDataTemplate> and its ItemTemplate property set to the key name of the <HierarchicalDataTemplate> object. It is in this way that you get the Tree View to display all levels of your hierarchical data structure. Three Levels in a Tree View Now let’s expand upon this concept and use three levels in our Tree View (Figure 4). This Tree View shows that you now have EmployeeTypes at the top of the tree, followed by a small set of employees that themselves manage employees. This means that the EmployeeType class has a collection of Employee objects. Each Employee class has a collection of Employee objects as well. Figure 4: When using 3 levels in your TreeView you will have 2 Hierarchical Data Templates and 1 Data Template. The EmployeeType class has not changed at all from our previous example. However, the Employee class now has one additional property as shown below: public class Employee{  public Employee(string name)  {    Name = name;    ManagedEmployees = new List<Employee>();  }   public string Name { get; set; }  public List<Employee> ManagedEmployees { get; set; }} The next thing that changes in our code is the EmployeeTypes class. The constructor now needs additional code to create a list of managed employees. Below is the new code. public class EmployeeTypes : List<EmployeeType>{  public EmployeeTypes()  {    EmployeeType type;    Employee emp;    Employee managed;     type = new EmployeeType("Manager");    emp = new Employee("Michael");    managed = new Employee("John");    emp.ManagedEmployees.Add(managed);    managed = new Employee("Tim");    emp.ManagedEmployees.Add(managed);    type.Employees.Add(emp);     emp = new Employee("Paul");    managed = new Employee("Michael");    emp.ManagedEmployees.Add(managed);    managed = new Employee("Sara");    emp.ManagedEmployees.Add(managed);    type.Employees.Add(emp);    this.Add(type);     type = new EmployeeType("Project Managers");    type.Employees.Add(new Employee("Tim"));    type.Employees.Add(new Employee("John"));    type.Employees.Add(new Employee("David"));    this.Add(type);  }} Now that you have all of the data built in your classes, you are now ready to hook up this three-level structure to your Tree View. Figure 5 shows the complete XAML needed to hook up your three-level Tree View. You can see in the XAML that there are now two Hierarchical Data Templates and one Data Template. Again you list the Data Template first since that is the lowest level in your Tree View. The next Hierarchical Data Template listed is the next level up from the lowest level, and finally you have a Hierarchical Data Template for the first level in your tree. You need to work your way from the bottom up when creating your Tree View hierarchy. XAML is processed from the top down, so if you attempt to reference a XAML key name that is below where you are referencing it from, you will get a runtime error. Figure 5: For three levels in a Tree View you will need two Hierarchical Data Templates and one Data Template. Each Hierarchical Data Template uses the previous template as its ItemTemplate. The ItemsSource of each Hierarchical Data Template is used to feed the data to the previous template. This is probably the most confusing part about working with the Tree View control. You are expecting the content of the current Hierarchical Data Template to use the properties set in the ItemsSource property of that template. But you need to look to the template lower down in the XAML to see the source of the data as shown in Figure 6. Figure 6: The properties you use within the Content of a template come from the ItemsSource of the next template in the resources section. Summary Understanding how to put together your hierarchy in a Tree View is simple once you understand that you need to work from the bottom up. Start with the bottom node in your Tree View and determine what that will look like and where the data will come from. You then build the next Hierarchical Data Template to feed the data to the previous template you created. You keep doing this for each level in your Tree View until you get to the last level. The data for that last Hierarchical Data Template comes from the ItemsSource in the Tree View itself. NOTE: You can download the sample code for this article by visiting my website at http://www.pdsa.com/downloads. Select “Tips & Tricks”, then select “Silverlight TreeView with Multiple Levels” from the drop down list.

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  • Zend database query result converts column values to null

    - by David Zapata
    Hi again. I am using the next instructions to get some registers from my Database. Create the needed models (from the params module): $obj_paramtype_model = new Params_Model_DbTable_Paramtype(); $obj_param_model = new Params_Model_DbTable_Param(); Getting the available locales from the database // This returns a Zend_Db_Table_Row_Abstract class object $obj_paramtype = $obj_paramtype_model->getParamtypeByValue('available_locales'); // This is a query used to add conditions to the next sentence. This is executed from the Params_Model_DbTable_Param instance class, that depends from Params_Model_DbTable_Paramtype class (reference map and dependentTables arrays are fine in both classes) $obj_select = $this->select()->where('deleted_at IS NULL')->order('name'); // Execute the next query, applying the select restrictions. This returns a Zend_Db_Table_Rowset_Abstract class object. This means "Find Params by Paramtype" $obj_params_rowset = $obj_paramtype->findDependentRowset('Params_Model_DbTable_Param', 'Paramtype', $obj_paramtype); // Here the firebug log displays the queries.... Zend_Registry::get('log')->debug($obj_params_rowset); I have a profiler for all my DB executions from Zend. At this point the log and profiler objects (that includes Firebug writers), shows the executed SQL Queries, and the last line displays the resulting Zend_Db_Table_Rowset_Abstract class object. If I execute the SQL Queries in some MySQL Client, the results are as expected. But the Zend Firebug log writer displays as NULL the column values with latin characters (ñ). In other words, the external SQL client shows es_CO | Español de Colombia and en_US | English of United States but the Query results from Zend displays (and returns) es_CO | null and en_US | English of United States. I've deleted the ñ character from Español de Colombia and the query results are just fine in my Zend Log Firebug screen, and in the final Zend Form element. The MySQL database, tables and columns are in UTF-8 - utf8_unicode_ci collation. All my zend framework pages are in UTF-8 charset. I'm using XAMPP 1.7.1 (PHP 5.2.9, Apache at port 90 and MySQL 5.1.33-community) running on Windows 7 Ultimate; Zend Framework 1.10.1. I'm sorry if there is so much information, but I don't really know why could that happen, so I tryed to provide as much related information as I could to help to find some answer.

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  • Commitment to Zend Framework - any arguments against?

    - by Pekka
    I am refurbishing a big CMS that I have been working on for quite a number of years now. The product itself is great, but some components, the Database and translation classes for example, need urgent replacing - partly self-made as far back as 2002, grown into a bit of a chaos over time, and might have trouble surviving a security audit. So, I've been looking closely at a number of frameworks (or, more exactly, component Libraries, as I do not intend to change the basic structure of the CMS) and ended up with liking Zend Framework the best. They offer a solid MVC model but don't force you into it, and they offer a lot of professional components that have obviously received a lot of attention (Did you know there are multiple plurals in Russian, and you can't translate them using a simple ($number == 0) or ($number > 1) switch? I didn't, but Zend_Translate can handle it. Just to illustrate the level of thorougness the library seems to have been built with.) I am now literally at the point of no return, starting to replace key components of the system by the Zend-made ones. I'm not really having second thoughts - and I am surely not looking to incite a flame war - but before going onward, I would like to step back for a moment and look whether there is anything speaking against tying a big system closely to Zend Framework. What I like about Zend: As far as I can see, very high quality code Extremely well documented, at least regarding introductions to how things work (Haven't had to use detailed API documentation yet) Backed by a company that has an interest in seeing the framework prosper Well received in the community, has a considerable user base Employs coding standards I like Comes with a full set of unit tests Feels to me like the right choice to make - or at least, one of the right choices - in terms of modern, professional PHP development. I have been thinking about encapsulating and abstracting ZF's functionality into own classes to be able to switch frameworks more easily, but have come to the conclusion that this would not be a good idea because: it would be an unnecessary level of abstraction it could cost performance the big advantage of using a framework - the existence of a developer base that is familiar with its components - would partly be cancelled out therefore, the commitment to ZF would be a deep one. Thus my question: Is there anything substantial speaking against committing to the Zend Framework? Do you have insider knowledge of plans of Zend Inc.'s to go evil in 2011, and make it a closed source library? Is Zend Inc. run by vampires? Are there conceptual flaws in the code base you start to notice when you've transitioned all your projects to it? Is the appearance of quality code an illusion? Does the code look good, but run terribly slow on anything below my quad-core workstation?

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  • Zend Framework 2 loading slow and loss of connection using WAMP

    - by Charlie
    I've been facing an issue with Zend framework running on my local Wamp 2.2 server. I am not sure what I'm doing wrong but ZF2 seems to load really slow when making an http request. Any other request to a php or html file seems to run smoothly. Also, sometimes when the loading time takes longer, I get this message: "The connection to [virtualhostname] was interrupted" I then need to hit refresh to complete the request. I checked apache error log and everything looks fine. Please, I appreciate any type of guide/suggestion to take care of this issue. I followed the starter guide word by word.

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