Search Results

Search found 8023 results on 321 pages for 'admin topics'.

Page 30/321 | < Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >

  • Django Caught an exception while rendering: No module named registration

    - by Arno Smit
    I seem to have run into a bit of an issue. I am busy creating an app, and over the last few weeks setup my server to use Git, mod_wsgi to host this app. Since deploying it, everything seems to be running smoothly however, I had to go through all my files and insert the absolute url of the project to make sure it works fine. on my local machine from registration.models import UserRegistration on server from myapp.registration.models import UserRegistration Am I doing something wrong? And this has also caused an issue for me where I cannot access my django admin interface. All i get is this: Caught an exception while rendering: No module named registration Exception Value: Caught an exception while rendering: No module named registration As far as I am concerned my app has all the relevant urls, but it does not seem to work. Thank you in advance

    Read the article

  • Django make model field name a link

    - by Daniel Garcia
    what Im looking to do is to have a link on the name of a field of a model. So when im filling the form using the admin interface i can access some information. I know this doesn't work but shows what i want to do class A(models.Model): item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>") Other option would be to put a description next to the field. Im not even sure where to start from.

    Read the article

  • Alternate datasource for django model?

    - by slypete
    I'm trying to seamlessly integrate some legacy data into a django application. I would like to know if it's possible to use an alternate datasource for a django model. For example, can I contact a server to populate a list of a model? The server would not be SQL based at all. Instead it uses some proprietary tcp based protocol. Copying the data is not an option, as the legacy application will continue to be used for some time. Would a custom manager allow me to do this? This model should behave just like any other django model. It should even pluggable to the admin interface. What do you think? Thanks, Pete

    Read the article

  • Django loaddata throws ValidationError: [u'Enter a valid date in YYYY-MM-DD format.'] on null=true f

    - by datakid
    When I run: django-admin.py loaddata ../data/library_authors.json the error is: ... ValidationError: [u'Enter a valid date in YYYY-MM-DD format.'] The model: class Writer(models.Model): first = models.CharField(u'First Name', max_length=30) other = models.CharField(u'Other Names', max_length=30, blank=True) last = models.CharField(u'Last Name', max_length=30) dob = models.DateField(u'Date of Birth', blank=True, null=True) class Meta: abstract = True ordering = ['last'] unique_together = ("first", "last") class Author(Writer): language = models.CharField(max_length=20, choices=LANGUAGES, blank=True) class Meta: verbose_name = 'Author' verbose_name_plural = 'Authors' Note that the dob DateField has blank=True, null=True The json file has structure: [ { "pk": 1, "model": "books.author", "fields": { "dob": "", "other": "", "last": "Carey", "language": "", "first": "Peter" } }, { "pk": 3, "model": "books.author", "fields": { "dob": "", "other": "", "last": "Brown", "language": "", "first": "Carter" } } ] The backing mysql database has the relevent date field in the relevant table set to NULL as default and Null? = YES. Any ideas on what I'm doing wrong or how I can get loaddata to accept null date values?

    Read the article

  • PHP Framework / Library Suggestions for a Backend

    - by frbry
    I am about to start to developing backend site of a php project. Companies and site admins will login to this site and manage their data on the project. My previous admin panel experiences were full of agony and pain. So I want to make sure that I choose correct tools for my purpose. By the way, please note, I'm not looking for scaffolding. There won't be much tables in my database. Instead, there will be complex logic between entities. I want clear seperation of markup and logic code and easy-to-use and standardized user-interface. Thank you.

    Read the article

  • Passing session data to ModelForm inside of ModelAdmin

    - by theactiveactor
    I'm trying to initialize the form attribute for MyModelAdmin class inside an instance method, as follows: class MyModelAdmin(admin.ModelAdmin): def queryset(self, request): MyModelAdmin.form = MyModelForm(request.user) My goal is to customize the editing form of MyModelForm based on the current session. When I try this however, I keep getting an error (shown below). Is this the proper place to pass session data to ModelForm? If so, then what may be causing this error? TypeError at ... Exception Type: TypeError Exception Value: issubclass() arg 1 must be a class Exception Location: /usr/lib/pymodules/python2.6/django/forms/models.py in new, line 185

    Read the article

  • Overwrite queryset which builds filter sidebar

    - by cw
    Hi, I'm writing a hockey database/manager. So I have the following models: class Team(models.Model): name = models.CharField(max_length=60) class Game(models.Model): home_team = models.ForeignKey(Team,related_name='home_team') away_team = models.ForeignKey(Team,related_name='away_team') class SeasonStats(models.Model): team = models.ForeignKey(Team) Ok, so my problem is the following. There are a lot of teams, but Stats are just managed for my Club. So if I use "list_display" in the admin backend, I'd like to modify/overwrite the queryset which builds the sidebar for filtering, to just display our home teams as a filter option. Is this somehow possible in Django? I already made a custom form like this class SeasonPlayerStatsAdminForm(forms.ModelForm): team = forms.ModelChoiceField(Team.objects.filter(club__home=True)) So now just the filtering is missing. Any ideas?

    Read the article

  • Not quite nested inlines?

    - by Lynden Shields
    Not quite sure what to call this, it's not quite nested inlines, but is probably related. I have a 3 level hierarchy of objects, A one-to-many B one-to-many C. Therefore, every C implicitly also belongs to an A. class A(models.Model): stuff = models.CharField("Stuff", max_length=50) class B(models.Model): a = models.ForeignKey(A) class C(models.Model): b = models.ForeignKey(B) I would like all C's that belong to an A to be listed on the admin page for A in an in-line. They do not have to show which B they belong to on the same page. Is this possible or is it the same problem as nested inlines anyway? If it's possible, how do I do it? I'm using django 1.3

    Read the article

  • What are some topics you'd like to see covered in an 'Introduction to Network Security' book?

    - by seth.vargo
    I'm trying to put together a list of topics in Network Security and prioritize them accordingly. A little background on the book - we are trying to gear the text towards college students, as an introduction to security, and toward IT professionals who have recently been tasked with securing a network. The idea is to create a book that covers the most vital and important parts of securing a network with no assumptions. So, if you were a novice student interested in network security OR an IT professional who needed a crash course on network security, what topics do you feel would be of the upmost importance in such a text?

    Read the article

  • How do I access admin shares on windows 2008 r2?

    - by Jim Geurts
    I am not able to access admin file shares on a Windows 2008 R2 box, if I'm logged in as a user who is part of the Administrators group. The only way I can access those shares is if I use the built in Administrator account. How can I configure the server to allow any administrator to access the file system via admin shares? Btw, this works with Windows 2003. By admin shares, I refer to: \192.168.1.4\c$ or \192.168.1.4\e$

    Read the article

  • Presentation software requires admin rights to install - any way to remove this requirement?

    - by James F
    I have some wireless presentation software which I use in a meeting room in order to allow end users to hold presentations here and wirelessly have their laptop screens showing on the TV on the wall. Unfortunately the .exe file requires admin rights to install therefore requiring that either the user requests temporary admin rights beforehand, I install it using my admin account or that we use a VGA/HDMI cable. Is there a way to remove the admin right requirement from a .exe or a .msi file so that it can be installed freely by any user? We are using XP for now but will be moving to 7 soon. Thanks James

    Read the article

  • Utility to grant admin rights to a user in Windows XP for few hours/days?

    - by user15660
    I have two accounts on my windows xp home desktop. The default regular user is used for everything and the 2nd user which has admin rights is used only for installations. I do this to avoid malware infestations during web browsing and limited user account is guarding against online threats to a good extend but many programs refuse to run under limited rights like revo uninstaller. many installs i run from limited user by selectin "run as" from right click context menu of the .exe file. but some apps need admin rights for certain. I use "switch user" to go to admin mode and do the install/uninstall. but the admin user has none of my preferences bookmarks setup nor has my locate32 indexing done and ready for fast search Is there a utility which I can use "run as" login in administration login and use that to grant my limited user admin rights for a limited amount of period like few hours or days? Please help. I guess MS might have closed many doors of it for fear of exploitation of the API. are there any?

    Read the article

  • Does admin=true and root has the same privileges on AIX?

    - by Boaz Tirosh
    Does a user in /etc/security/user with the parameter admin set to true (admin = true) has the same privileges as the root user? According to IBM (full information here): admin Defines the administrative status of the user. Possible values are: true The user is an administrator. Only the root user can change the attributes of users defined as administrators. false The user is not an administrator. This is the default value. Is there another type of user, or are admin and root the same?

    Read the article

  • What do the "ALL"s in the line " %admin ALL=(ALL) ALL " in Ubuntu's /etc/sudoers file stand for?

    - by sri
    What does each ALL mean? I understand that the whole line indicates that the admin group members get admininstartive privileges, but would like to know more info about the position of the ALLS and if they each refer to a different set of permissions or something like that? $sudo cat /etc/sudoers ... # User privilege Information root ALL=(ALL) ALL #... %sudo ALL=(ALL) ALL # #includedir /etc/sudoers.d #Members of the admin group may gain root privileges %admin ALL=(ALL) ALL # If it matters: OS: Ubuntu : 10.4

    Read the article

  • Is it normal that Software installs in Admin user folder?

    - by RoToRa
    I've got a new computer with Windows 7, which I'm using for the first time. For security I decided to create a standard user for everyday work instead of using an admin account. However when I install programs logged in as the standard user (such as Aptana right now) they always try to install in the admin's user folder (C:\Users\Admin\AppData...). I'd expect the programs to install to the standard user's folder or Progran Files as in XP. This also leads to that I need to grant admin rights whenever I start such a program. Of course I could just change the installation path every time, but I find this behavior strange. Ist it normal, or did I somehow mess up the Windows 7 installation?

    Read the article

  • What is the equivalent of domain admin on Sharepoint 2010?

    - by user54266
    I have to support Sharepoint on a daily basis but do not have the equivalent of domain access so I'm constantly having to ask the guy in charge of Sharepoint to add me to a new security group to complete my task. Rather than having to bug him all the time (he is only somewhat technical) it would be easier to simply have the equivalent of domain admin access for Sharepoint (I'm a sys admin and have domain admin access already but this doesn't seem to carry over to FOSS). What is the equivalent of domain admin access on Sharepoint 2010? Thanks in advance.

    Read the article

  • Django: Complex filter parameters or...?

    - by minder
    This question is connected to my other question but I changed the logic a bit. I have models like this: from django.contrib.auth.models import Group class Category(models.Model): (...) editors = ForeignKey(Group) class Entry(models.Model): (...) category = ForeignKey(Category) Now let's say User logs into admin panel and wants to change an Entry. How do I limit the list of Entries only to those, he has the right to edit? I mean: How can I list only those Entries which are assigned to a Category that in its "editors" field has one of the groups the User belongs to? What if User belongs to several groups? I still need to show all relevant Entries. I tried experimenting with changelist_view() and queryset() methods but this problem is a bit too complex for me. I'm also wondering if granular-permissions could help me with the task, but for now I have no clue. I came up only with this: First I get the list of all Groups the User belongs to. Then for each Group I get all connected Categories and then for each Category I get all Entries that belong to these Categories. Unfortunately I have no idea how to stitch everything together as filter() parameters to produce a nice single QuerySet.

    Read the article

  • JQuery tablesorter - Second click on column header doesn't resort

    - by Jonathan
    I'm using tablesorter in on a table I added to a view in django's admin (although I'm not sure this is relevant). I'm extending the html's header: {% block extrahead %} <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.js"></script> <script type="text/javascript" src="http://mysite.com/media/tablesorter/jquery.tablesorter.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#myTable").tablesorter(); } ); </script> {% endblock %} When I click on a column header, it sorts the table using this column in descending order - that's ok. When I click the same column header a second time - it does not reorder to ascending order. What's wrong with it? the table's html looks like: <table id="myTable" border="1"> <thead> <tr> <th>column_name_1</th> <th>column_name_2</th> <th>column_name_3</th> </tr> </thead> <tbody> {% for item in extra.items %} <tr> <td>{{ item.0|safe }} </td> <td>{{ item.1|safe }} </td> <td>{{ item.2|safe }} </td> </tr> {% endfor %} </tbody> </table>

    Read the article

  • Is it dangerous to keep an admin page to administer your database?

    - by Scarface
    Hey guys I have an admin page that checks if you are admin before submitting any queries, and contains a header to the index page if you are not admin, but I am worried about protecting the page. I am concerned someone may be able to destroy my database with it. Does anyone have any recommendation into protecting a page like this, if not, should I just manually admin my database through phpmyadmin and delete the page all together?

    Read the article

  • Servlet 3.1, Expression Language 3.0, Bean Validation 1.1, Admin Console Replay: Java EE 7 Launch Webinar Technical Breakouts on YouTube

    - by arungupta
    As stated previously (here, here, here, and here), the On-Demand Replay of Java EE 7 Launch Webinar is already available. You can watch the entire Strategy and Technical Keynote there, and all other Technical Breakout sessions as well. We are releasing the final set of Technical Breakout sessions on GlassFishVideos YouTube channel as well. In this series, we are releasing Servlet 3.1, Expression Language 3.0, Bean Validation 1.1, and Admin Console. Here's the Servlet 3.1 session: Here's the Expression Language 3.0 session: Here's the Bean Validation 1.1 session: And finally the Admin Console session: Enjoy watching all of them together in a consolidated playlist: And don't forget to download Java EE 7 SDK and try the numerous bundled samples.

    Read the article

  • How to prevent the google users found my index of admin page?

    - by krish
    I am running a website but for some days i stopped it and put the under-construction page because the Index of admin page is visible to the outside world through the Google search. One of my friend told me that your websites index is visible and its one step away to access the password file and he shows me that very simply using the Google search. How can i prevent this and i am hosting my site with a hosting company and i report about this to them but they simply replied to me still its secure so you no need to worry... am i really don need to worry and continue my site with the visible index of admin page?

    Read the article

  • How to prevent Google from finding my admin index page?

    - by krish
    I am running a website but for some days i stopped it and put the under-construction page because the Index of admin page is visible to the outside world through the Google search. One of my friend told me that your websites index is visible and its one step away to access the password file and he shows me that very simply using the Google search. How can i prevent this and i am hosting my site with a hosting company and i report about this to them but they simply replied to me still its secure so you no need to worry... am i really don need to worry and continue my site with the visible index of admin page?

    Read the article

  • SugarCRM - how to make users see only child users?

    - by John
    Hello, I want to change the behaviour of Sugar CRM community version. Here's what sugar currently does: 1) Admin logs into Sugar. 2) Admin clicks on Admin tab. 3) Admin creates a new user named George with admin access 4) Under user information section, Admin makes George report to Admin (in the database, it will show users.report_to_id is the admin's user_id) 5) Admin saves and logs out 6) George logs in with his password 7) George goes to admin tab. 8) George goes to list users page and sees all users, including Admin, the person he is supposed to report to. I want to change step 8 such that George is not allowed to see the user he reports to. Additionally, he is not allowed to see his grand parent user, great grand parent user, great great grand parent user etc... George should only be able to see users that he creates. How can I achieve this? Is this even possible?

    Read the article

  • How do you guys handle custom yum repository?

    - by luckytaxi
    I have a bunch of tools (nagios, munin, puppet, etc...) that gets installed on all my servers. I'm in the process of building a local yum repository. I know most folks just dump all the rpms into a single folder (broken down into the correct path) and then run createrepo inside the directory. However, what would happen if you had to update the rpms? I ask because I was going to throw each software into its own folder. Example one, put all packages inside one folder (custom_software) /admin/software/custom_software/5.4/i386 /admin/software/custom_software/5.4/x86_64 /admin/software/custom_software/4.6/i386 /admin/software/custom_software/4.6/x86_64 What I'm thinking of ... /admin/software/custom_software/nagios/5.4/i386 /admin/software/custom_software/nagios/5.4/x86_64 /admin/software/custom_software/nagios/4.6/i386 /admin/software/custom_software/nagios/4.6/x86_64 /admin/software/custom_software/puppet/5.4/i386 /admin/software/custom_software/puppet/5.4/x86_64 /admin/software/custom_software/puppet/4.6/i386 /admin/software/custom_software/puppet/4.6/x86_64 Ths way, if I had to update to the latest version of puppet, I can save manage the files accordingly. I wouldn't know which rpms belong to which software if I threw them into one big folder. Makes sense?

    Read the article

< Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >