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  • Microsoft Excel; Two conditions have to be true then be counted

    - by Chris Jones
    I'm working on a spreadsheet that two conditions have to true in order to be counted. If the month is January, and the number next to it is less than or equal to 30, then it's counted. Same rule applies for all the other months. Thus far, I have: =COUNTIFS(Sheet1!D2:D7,(SUMPRODUCT(--(MONTH(D2:D7)=1))),Sheet1!E2:E7,(COUNTIFS(E2:E7,"<=30"))) For example: Column D Jan 1, 2014 Feb 3, 2014 Feb 16, 2014 Mar 5, 2014 Mar 13, 2014 Mar 29, 2014 Column E 37 25 30 31 1 16 Outcome Jan 0 Feb 2 Mar 2

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  • if string is alphabetically greater than other string in objective

    - by Jonathan
    I'm trying to use an if statement to work out which of 2 strings comes first alphabetically. Like with numbers and greater and less than: if (1 < 2) { just with strings: if(@"ahello" < @"bhello") { Or would I have to have a string containing all the letters and then check the index of the first char in each string and see which index is greater, and the index that is less than the other comes first in the alphabet and then if they are equal move on to the next char and repeat?

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  • Matlab help: I am given a second order differential equation.I need to use matlab to find unit step response and impulse response?

    - by Cady Smith
    I have the second order differential equation d^2(y(t))/dt^2+ B1*d(y(t))/dt+ c1*y(t)=A1*x(t) t is in seconds and is greater than 0. A1, B1, C1 are constants that equal: A1= 3.8469x10^6 B1= 325.6907 C1= 3.8469x10^6 This system is linear, time-invariant, and casual. The system is called H1. I want to use Matlab to compute and plot the impulse response function h1(t) and the unit step response function g1(t) of this system.

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  • Linq to Sql: Generic Stored Procedures

    - by Eric
    Hello everyone, I am using Linq-to-Sql for a C# application and am currently working on some stored procedures. The application is for a newspaper, and a sample stored procedure is the following: ALTER PROCEDURE dbo.Articles_GetArticlesByPublication @publicationDate date AS SELECT * FROM Articles WHERE Articles.PublicationDate=@publicationDate Anyway, this query gets all of the articles where the publication date is equal to the argument (publicationDate). How can I alter this so that the argument can handle multiple publication dates? Also, I'd prefer not to use "BETWEEN," rather, I want to pick and choose dates.

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  • How do I write an Oracle SQL query for this tricky question?

    - by atrueguy
    Here is the table data with the column name as Ships. +--------------+ Ships | +--------------+ Duke of north | ---------------+ Prince of Wales| ---------------+ Baltic | ---------------+ Replace all characters between the first and the last spaces (excluding these spaces) by symbols of an asterisk (*). The number of asterisks must be equal to number of replaced characters.

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  • How to with extract url from tweet using Regular Expressions

    - by neutreno
    Ok so i'm executing the following line of code in javascript RegExp('(http:\/\/t.co\/)[a-zA-Z0-9\-\.]{8}').exec(tcont); where tcont is equal to some string like 'Test tweet to http://t.co/GXmaUyNL' (the content of a tweet obtained by jquery). However it is returning, in the case above for example, 'http://t.co/GXmaUyNL,http://t.co/'. This is frustracting because I want the url without the bit on the end - after and including the comma. Any ideas why this is appearing? Thanks

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  • How to get the width of a string in pixels?

    - by MA1
    I am using wxPython's HyperTreeList and I want to set the column width exactly equal to length of the largest string in it. To accomplish that, I'd like to to convert a python string size into pixels. For Example: If we have a string like str = "python" len(str) = 6 How could I convert the above string length/size into pixels? Is there another way?

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  • Less than in Groovy case/switch statement

    - by UltraVi01
    I have the following switch statement switch (points) { case 0: name = "new"; break; case 1..14: badgeName = "bronze-coin"; break; case 15..29: badgeName = "silver-coin"; break; default: badgeName = "ruby"; } I'd like the first case (case 0) to include points less than or equal to 0. How can I do this in Groovy?

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  • How does compiler understand the pointer type?

    - by Narek
    How c++ compiler understands the pointer type? As I know pointer has a size equal to WORD of the OS (32 or 64). So does it store dome info in that 32(or 64) bits about type? Just because you can not have a pointer on one type and assign to that pointer another pointer with a different type.

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  • Ping remote server and wait to get data

    - by infinity
    Hi I'm building my first application for android and I've reached a point where I can't find a solution even have no idea what to search for in Google. So the problem: I am pinging a remote server with GET request through the application passing some parameters like file_id. Then the server gives back confirmation if the file exists or error otherwise, both in plain text. The error string is $$$ERROR$$$. Actually the confirmation is JSON string that holds the path to the file. If the file doesn't exists on the server it generated the error message and start downloading the file and processing it which normally takes 10-30 seconds. What would be the best way to check if the file is ready for download? I have DownloadFile class that extends AsyncTask but before I reach the point to download the file I need the URL which is dependant on the previous request which is in the main class in the UI thread. Here is some code: public class MainActivity extends Activity { private String getInfo() { // Create a new HttpClient and Post Header HttpClient httpClient = new DefaultHttpClient(); HttpGet httpPost = new HttpGet(infoUrl); StringBuilder sb = null; String data; JSONObject jObject = null; try { HttpResponse response = httpClient.execute(httpPost); // This might be equal "$$$ERROR$$$" if no file exists sb = inputStreamToString(response.getEntity().getContent()); } catch(ClientProtocolException e) { // TODO Auto-generated catch block Log.v("Error: pushItem ClientProtocolException: ", e.toString()); } catch (IOException e) { // TODO Auto-generated catch block Log.v("Error: pushItem IOException: ", e.toString()); } // Clean the data to be complaint JSON format data = sb.toString().replace("info = ", ""); try { jObject = new JSONObject(data); data = jObject.getString("h"); fileTitle = jObject.getString("title"); } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } downloadUrl = String.format(downloadUrl, fileId, data); return downloadUrl; } } So my idea was to get the content and if equal to $$$ERROR$$$ go into loop until JSON data is passed but I guess there is better solution. Note: I don't have control over the server output so have to deal with what I have.

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  • j2me or android file upload to jsp

    - by user313613
    hi i new to mobile development i like to upload the file from blackberry and android how to develop the mobile side to this jsp page. please do reply me thanks here i mention the jsp file from roseindia.net. <%@ page import="java.io.*" % <% //to get the content type information from JSP Request Header String contentType = request.getContentType(); //here we are checking the content type is not equal to Null and as well as the passed data from mulitpart/form-data is greater than or equal to 0 if ((contentType != null) && (contentType.indexOf("multipart/form-data") = 0)) { DataInputStream in = new DataInputStream(request. getInputStream()); //we are taking the length of Content type data int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead, formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1, contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)) .getBytes()).length; // creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream(saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); %><Br><table border="2"><tr><td><b>You have successfully upload the file by the name of: <% out.println(saveFile); % <% } %

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  • Getting maximum value of float in SQL programatically

    - by Axarydax
    Is there an method for programatically (in T-SQL) retrieving the maximum (and minimum) value of a datatype? That it would act like float.MaxValue in C#. I would like to use it in some selection when the parameter does not equal any actual values in the database, so I would use something like declare @min float declare @max float /*fill @min and @max, can be null if undefined*/ select * from foo where bar between isnull(@min,0 ), isnull(@max,max(float)/*magic*/) Thanks

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  • Simple C++ program on multidimensional arrays - Getting C2143 error among others. Not sure why?

    - by noobzilla
    Here is my simple multidimensional array program. The first error occurs where I declare the function addmatrices and then a second one where it is implemented. I am also getting an undefined variable error for bsize. What am I doing incorrectly? #include <iostream> #include <fstream> #include <string> #include <iomanip> using namespace std; //Function declarations void constmultiply (double matrixA[][4], int asize, double matrixC[][4], int bsize, double multiplier); //Pre: The address of the output file, the matrix to be multiplied by the constant, the matrix in which // the resultant values will be stored and the multiplier are passed in. //Post: The matrix is multiplied by the multiplier and the results are displayed on screen and written to the // output file. int addmatrices (double matrixA[][4], int asize, double matrixB[]4], int bsize, double matrixC[][4], int csize); //Pre: The addresses of three matrices are passed in //Post: The values in each of the two matrices are added together and put into a third matrix //Error Codes int INPUT_FILE_FAIL = 1; int UNEQUAL_MATRIX_SIZE = 2; //Constants const double multiplier = 2.5; const int rsize = 4; const int csize = 4; //Main Driver int main() { //Declare the two matrices double matrix1 [rsize][csize]; double matrix2 [rsize][csize]; double matrix3 [rsize][csize]; //Variables double temp; string filename; //Declare filestream object ifstream infile; //Ask the user for the name of the input file cout << "Please enter the name of the input file: "; cin >> filename; //Open the filestream object infile.open(filename.c_str()); //Verify that the input file opened correctly if (infile.fail()) { cout << "Input file failed to open" <<endl; exit(INPUT_FILE_FAIL); } //Begin reading in data from the first matrix for (int i = 0; i <= 3; i++)//i = row { for (int j = 0; j <= 3; j++)// j = column { infile >> temp; matrix1[i][j] = temp; } } //Begin reading in data from the second matrix for (int k = 0; k <= 3; k++)// k = row { for (int l = 0; l <= 3; l++)// l = column { infile >> temp; matrix2[k][l] = temp; } } //Notify user cout << "Input file open, reading matrices...Done!" << endl << "Read in 2 matrices..."<< endl; //Output the values read in for Matrix 1 for (int i = 0; i <= 3; i++) { for (int j = 0; j <= 3; j ++) { cout << setprecision(1) << matrix1[i][j] << setw(8); } cout << "\n"; } cout << setw(40)<< setfill('-') << "-" << endl ; //Output the values read in for Matrix 2 for (int i = 0; i <= 3; i++) { for (int j = 0; j <= 3; j ++) { cout << setfill(' ') << setprecision(2) << matrix2[i][j] << setw(8); } cout << "\n"; } cout << setw(40)<< setfill('-') << "-" << endl ; //Multiply matrix 1 by the multiplier value constmultiply (matrix1, rsize, matrix3, rsize, multiplier); //Output matrix 3 values to screen for (int i = 0; i <= 3; i++) { for (int j = 0; j <= 3; j ++) { cout << setfill(' ') << setprecision(2) << matrix3[i][j] << setw(8); } cout << "\n"; } cout << setw(40)<< setfill('-') << "-" << endl ; // //Add matrix1 and matrix2 // addmatrices (matrix1, 4, matrix2, 4, matrix3, 4); // //Finished adding. Now output matrix 3 values to screen // for (int i = 0; i <= 3; i++) // { //for (int j = 0; j <= 3; j ++) //{ // cout << setfill(' ') << setprecision(2) << matrix3[i][j] << setw(8); //} //cout << "\n"; // } // cout << setw(40)<< setfill('-') << "-" << endl ; //Close the input file infile.close(); return 0; } //Function implementation void constmultiply (double matrixA[][4], int asize, double matrixC[][4], int bsize, double multiplier) { //Loop through each row and multiply the value at that location with the multiplier for (int i = 0; i < asize; i++) { for (int j = 0; j < 4; j++) { matrixC[i][j] = matrixA[i][j] * multiplier; } } } int addmatrices (double matrixA[][4], int asize, double matrixB[]4], int bsize, double matrixC[][4], int csize) { //Remember that you can only add two matrices that have the same shape - i.e. They need to have an equal //number of rows and columns. Let's add some error checking for that: if(asize != bsize) { cout << "You are attempting to add two matrices that are not equal in shape. Program terminating!" << endl; return exit(UNEQUAL_MATRIX_SIZE); } //Confirmed that the matrices are of equal size, so begin adding elements for (int i = 0; i < asize; i++) { for (int j = 0; j < bsize; j++) { matrixC[i][j] = matrixA[i][j] + matrixB[i][j]; } } }

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  • How do you make a wrapped div fill the window horizontally?

    - by Alex Parkinson
    I have a div which is contained by another 960px-wide centered div. I'm adding a background to the inner div which should expand all the way to the window's edges horizontally, essentially escaping the boundaries of its container. If I apply a large negative margin and equal amount of padding, this works on the left side, but the right side causes a scroll bar to appear. Does anyone know how I can achieve this without causing scroll bars?

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  • Big Oh Notation - formal definition.

    - by aloh
    I'm reading a textbook right now for my Java III class. We're reading about Big-Oh and I'm a little confused by its formal definition. Formal Definition: "A function f(n) is of order at most g(n) - that is, f(n) = O(g(n)) - if a positive real number c and positive integer N exist such that f(n) <= c g(n) for all n = N. That is, c g(n) is an upper bound on f(n) when n is sufficiently large." Ok, that makes sense. But hold on, keep reading...the book gave me this example: "In segment 9.14, we said that an algorithm that uses 5n + 3 operations is O(n). We now can show that 5n + 3 = O(n) by using the formal definition of Big Oh. When n = 3, 5n + 3 <= 5n + n = 6n. Thus, if we let f(n) = 5n + 3, g(n) = n, c = 6, N = 3, we have shown that f(n) <= 6 g(n) for n = 3, or 5n + 3 = O(n). That is, if an algorithm requires time directly proportional to 5n + 3, it is O(n)." Ok, this kind of makes sense to me. They're saying that if n = 3 or greater, 5n + 3 takes less time than if n was less than 3 - thus 5n + n = 6n - right? Makes sense, since if n was 2, 5n + 3 = 13 while 6n = 12 but when n is 3 or greater 5n + 3 will always be less than or equal to 6n. Here's where I get confused. They give me another example: Example 2: "Let's show that 4n^2 + 50n - 10 = O(n^2). It is easy to see that: 4n^2 + 50n - 10 <= 4n^2 + 50n for any n. Since 50n <= 50n^2 for n = 50, 4n^2 + 50n - 10 <= 4n^2 + 50n^2 = 54n^2 for n = 50. Thus, with c = 54 and N = 50, we have shown that 4n^2 + 50n - 10 = O(n^2)." This statement doesn't make sense: 50n <= 50n^2 for n = 50. Isn't any n going to make the 50n less than 50n^2? Not just greater than or equal to 50? Why did they even mention that 50n <= 50n^2? What does that have to do with the problem? Also, 4n^2 + 50n - 10 <= 4n^2 + 50n^2 = 54n^2 for n = 50 is going to be true no matter what n is. And how in the world does picking numbers show that f(n) = O(g(n))? Please help me understand! :(

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  • How to build a tree from a list of items and their children recursively in php?

    - by k1lljoy
    I have a list of items stored in the DB, simplified schema is like this: id, parent, name I need to generate a tree structure (in a form of a multi-dimensional array) that can be infinite levels deep. Top level items would have parent = 0. Next level down would have parent equal to the the id of the parent item, fairly straight forward. What would be the best way to do this, while consuming as little resources as possible?

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  • mySQL query not returning correct results!

    - by Pete Herbert Penito
    Hi! This query that I have is returning therapists whose 'therapistTable.activated' is equal to false as well as those set to true! so it's basically selecting all of the db, any advice would be appreciated! ` $query = "SELECT therapistTable.* FROM therapistTable WHERE therapistTable.activated = 'true' ORDER BY therapistTable.distance "; `

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  • Adding LambaExpression to an instance of IQueryable

    - by Paul Knopf
    ParameterExpression parameter = Expression.Parameter(typeof(Product), "x"); MemberExpression Left = Expression.MakeMemberAccess(parameter, typeof(Product).GetProperty("Name")); ConstantExpression Right = Expression.Constant(value, typeof(String)); BinaryExpression expression = Expression.Equal(Left, Right); LambdaExpression lambada = Expression.Lambda<Func<Product, bool>>(expression, parameter); Now how do I add this lambada to an instance of an IQuerybale, lets say _query _query.Where(lambada.Compile());?

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