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  • Submit information to url, but also open PDF

    - by Mad Ducky Digital Branding
    I have a client whose desire is to have her Wordpress blog show a MailChimp form on her home page as a gateway to a .pdf. I need the following behavior to occur when the user clicks "Submit": execute the included MailChimp's javascript file; this ensures the form was properly filled, and then performs the sign-up to the newsletter list (don't need help with this part) then show the user an informational PDF for download or viewing EDIT: The logical order was flipped from when I originally posted this. The script should execute, and only if the script gets executed properly should the PDF show to the user Note: My experience level with HTML and PHP is 3/4, and with JS I am 2/4 EDIT: (seems more like 1/4 at this point lol). If my research is correct, PHP (server-side language) would be used to do that which the client wants. Additional validation is not necessary beyond what MailChimp's script provides (it ensures that user has submitted a completed form) is not necessary in this case (the client says it's ok if the e-mail isn't valid at all). EDIT: Reworded this sentence from original post to be more clear The .pdf URL and content is static, and simply needs to be shown, not generated. ----RESEARCH---- I know that the Mailchimp form uses the following line to actually submit the information, but I want to do the action mentioned below, as well as open the aforementioned .pdf: <form action="http://*BLAH*.us2.list-manage.com/subscribe/post?u=*BLAHBLAH*&amp;id=*BLAHBLAHBLAH*" method="post" id="mc-embedded-subscribe-form" name="mc-embedded-subscribe-form" class="validate" target="_blank"> I am reading on other sites that I can conceivably point "action" to a .php file, but if there is a way to do this with javascript - since its using the .js file that I created for that already anyways, then I would be most happy. Barring that, I'll take what I can get.. ----SOLUTION?---- ...

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  • How to return id of a submitted form using Prototype?

    - by pstinnett
    I have a page that has several ajax submission forms. Each form has a dynamic id assigned to it when it's written to the page. Does anyone know if there is an easy way to return the id of the form that is being submitted? I'm basically looking to click "submit" and alert the id of the submitted form. From there I can use it in the ajax onSuccess function.

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  • JQuery Validation Plugin: Prevent validation issue on nested form

    - by Majid
    I have a form on which I use validation. This form has a section for photo upload. Initially this section contains six elements with the following code: <img class="photo_upload" src="image/app/photo_upload.jpg"> I have bound a function to the click event for the class of photo_upload. This function replaces the image with a minimal form with this code: Copy code <form onsubmit="startUploadImage();" target="control_target" enctype="multipart/form-data" method="post" action="index.php"> <input type="hidden" value="add_image" name="service"> <input type="hidden" value="1000000" name="MAX_FILE_SIZE"> <input type="file" size="10" name="photo" id="photo_file_upload"><br> <button onclick="javascript:cancel_photo_upload();return false;">Cancel</button> </form> So, essentially, after the image is clicked, I'd have a new form nested in my original, validated form. Now, when I use this new form and upload an image, I receive an error (repeated three times) saying: validator is undefined http://host.com/path/index.php Line 286 What is going on here? My guess is this Submit event bubbles up to the outer form As we have validation on that form, validation is triggered, Validation tries to find the form triggering it, Since we have not bound validation to the inner form it returns 'undefined' Now, is my assessment correct? Whether it is or not, how can I solve this issue?

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  • How to submit the form using JQuery UI?

    - by Vafello
    I have a form in html with a default submit button. After the form is submitted, a php file is run (with action = homelocation). I decided to use JQuery UI dialog to display the form. I have 2 default buttons there - one to save and one to close the dialog. Can anyone tell me how to assign the form submit button action to the JQuery dialog button(i.e. replace the submit button from the form with the one in the dialog)? Here's my code: <div id="userdialog" title="Add"> <form id="add" action="engine.php" method="POST"> <input type="hidden" name="action" value="homelocation" id="action"> <button type="submit">Save this location</button> </form></div> Dialog: $('#userdialog').dialog({ width: 260, position: [250,100], buttons: { "Save": function() { HERE GOES THE REQUIRED FUNCTION $(this).dialog('close'); }, "Don't Save": function() { $(this).dialog("close"); } } });

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  • how to pass values from one page to another on jquery form submit

    - by andy787899
    I'm trying to build a form using php & jquery, but I'm a little confused as to what to do with the jquery portion of it... Basically, when the user submits the first form, I want to direct them to the "next step" form, but I want to retain the values submitted from the first one in a hidden input field... If someone can either show me how or point me to a good tutorial, I'd appreciate it... I don't have any of the php or jquery yet, and this is just a simplified version of the html markup... //first.php <form name="form1" method="post" action="second.php"> <input type="text" name="name" value="" />Name <input type="submit" name="step1" value="Next" /> </form> //second.php <form name="form2" method="post" action="process.php"> <input type="hidden" name="name" value="{$_POST['name']}" /> <input type="text" name="message" value="" />message <input type="submit" name="step2" value="Finish" /> </form>

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  • how to pass values from one page to another on jquery form submit

    - by andy787899
    I'm trying to build a form using php & jquery, but I'm a little confused as to what to do with the jquery portion of it... Basically, when the user submits the first form, I want to direct them to the "next step" form, but I want to retain the values submitted from the first one in a hidden input field... If someone can either show me how or point me to a good tutorial, I'd appreciate it... I don't have any of the php or jquery yet, and this is just a simplified version of the html markup... //first.php <form name="form1" method="post" action="second.php"> <input type="text" name="name" value="" />Name <input type="submit" name="step1" value="Next" /> </form> //second.php <form name="form2" method="post" action="process.php"> <input type="hidden" name="name" value="{$_POST['name']}" /> <input type="text" name="message" value="" />message <input type="submit" name="step2" value="Finish" /> </form>

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  • How to submit ?

    - by user281180
    Can I have a submit in <% using (Ajax.BeginForm("ChangePassword", new AjaxOptions { OnComplete = "ChangePasswordComplete" })) without having a submit button on the form? I yes, how? Let`s say I want to submit the above when a user click on an input of type button simply?

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  • jQuery fadeout a div that's revealed by php and not Javascript?

    - by songdogtech
    Seems like this might be easy, but from reading other SO answers there are a number of ways for it to possibly work: I have the "thanks" div below that shows when a php form is sucessfully submitted: <?php if(isset($emailSent) && $emailSent == true) { ?> <div class="thanks"></div> The page does not reload after the form is submitted; the php for the form is included in the page header, the php above is in <body>, and when the form is submitted, the "thanks" div appears. Question: How can the div be faded out (or simply removed) after a few seconds? Document ready doesn't seem like it would work because the page is not reloaded. Can jQuery detect the appearance of the div and then start the fadeout timer? If possible, I'd like to stay with the php form and not move to a jQuery form.

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  • Submit form with JS

    - by Thomas
    Im working with a shopping cart plugin and that uses a basic form on the product page to submit values like price, product name, etc.. The problem is that the plugin uses a standard submit button to send the values and I would like to replace said button with a prettier custom jquery rollover. In order to make this happen I used some JS and tossed a link around my custom submit button: <a href="#" onclick="document.forms[0].submit()" value="Add to Cart" onsubmit="return ReadForm(this, true);"> <img class="fade" src="style/img/add_btn.jpg" style="background: url(style/img/add_ro.png);" alt=""/> </a> The form submits and the user is redirected to the homepage but the data in the form doesn't seem to get submitted and the product never gets added to the 'cart' page. I suspect that the form is getting submitted but I am failing to fire some additional JS function that submits the data. The plugin adds some JS to the top of the page: <!-- // function ReadForm (obj1, tst) { // Read the user form var i,j,pos; val_total="";val_combo=""; for (i=0; i<obj1.length; i++) { // run entire form obj = obj1.elements[i]; // a form element if (obj.type == "select-one") { // just selects if (obj.name == "quantity" || obj.name == "amount") continue; pos = obj.selectedIndex; // which option selected val = obj.options[pos].value; // selected value val_combo = val_combo + "(" + val + ")"; } } // Now summarize everything we have processed above val_total = obj1.product_tmp.value + val_combo; obj1.product.value = val_total; } //--> If you want to check out the the site in question, take a look here and click 'add to cart button': http://hardtopdepot.com/?p=34 You can see the cart at the top: http://hardtopdepot.com/?page_id=50 Any help would be super appreciated- thanks!

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  • Font-awesome, input type 'submit'

    - by denis.peplin
    It seems no class for input type 'submit' in font-awesome. Is it possible to use some class from font-awesome for button input? I've added icons to all buttons (which actually links with class 'btn' from twitter-bootstrap) in my applications, but can't add icons on 'input type submit'. Or, how to use this code: input#image-button{ background: #ccc url('icon.png') no-repeat top left; padding-left: 16px; height: 16px; } html: <input type="submit" id="image-button">Text</input> (which I took from HTML: How to make a submit button with text + image in it?) with font-awesome?

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  • Retrieving models from form with ModelMultipleChoiceField

    - by colinjameswebb
    I am having difficulties with forms, specifically ModelMultipleChoiceField. I've pieced together this code from various examples, but it sadly doesn't work. I would like to be able to: Search for some Works on work_search.html Display the results of the search, with checkboxes next to each result Select the Works I want, via the checkboxes After pressing Add, display which works were selected. I believe everything is okay except the last part. The page simply displays "works" :( Here is the code - sorry about the length. Models.py class Work(models.Model): title = models.CharField(max_length=200) artist = models.CharField(max_length=200) writers = models.CharField(max_length=200) def __unicode__(self): return self.title + ' - ' + self.artist forms.py class WorkSelectForm(forms.Form): def __init__(self, queryset, *args, **kwargs): super(WorkSelectForm, self).__init__(*args, **kwargs) self.fields['works'] = forms.ModelMultipleChoiceField(queryset=queryset, widget=forms.CheckboxSelectMultiple()) views.py def work_search(request): query = request.GET.get('q', '') if query: qset = ( Q(title__icontains=query) | Q(artist__icontains=query) | Q(writers__icontains=query) ) results = Work.objects.filter(qset).distinct() form = WorkSelectForm(results) return render_to_response("work_search.html", {"form": form, "query": query }) else: results = [] return render_to_response("work_search.html", {"query": query }) def add_works(request): #if request.method == POST: form = WorkSelectForm(request.POST) #if form.isvalid(): items = form.fields['works'].queryset return render_to_response("add_works.html", {"items":items}) work_search.html {% extends "base.html" %} {% block content %} <h1>Search</h1> <form action="." method="GET"> <label for="q">Search: </label> <input type="text" name="q" value="{{ query|escape }}"> <input type="submit" value="Search"> </form> {% if query %} <h2>Results for "{{ query|escape }}":</h2> <form action="add_works" method="post"> <ul> {% if form %} {{ form.as_ul }} {% endif %} </ul> <input type="submit" value="Add"> </form> {% endif %} {% endblock %} add_works.html {% extends "base.html" %} {% block content %} {% if items %} {% for item in items %} {{ item }} {% endfor %} {% else %} <p>Nothing selected</p> {% endif %} {% endblock %}

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  • onblur deletes data when submit, why?

    - by Syom
    i have the following script <input style="color: #ccc" type="text" value="something" name="country" onFocus="if (this.value == 'something') { this.value='';this.style.color='black';}" onblur="if (this.value != 'something') { this.value='something'}" /> <input type="submit" value="save" /> it works fine, but when i click on submit button, it also deletes the value "something" so, what can i do, if i want, that when i click on submit button, value doesn't delete? thanks

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  • How to redirect to the current page with form in php?

    - by garcon1986
    Hello, I tried to redirect to the current page with form in my php application. Now i have met a problem. <form name="myform" action="?page=matching" method="GET"> <input id="match_button" type="submit" name="button" value="button" onClick="func_load3()" /> </form> action="?page=matching" means the current page, because i use the single entry in my php application. With the code upon, When i click the button, it redirects to the homepage. And I tried to use: <form name="myform" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="GET"> but it still doesn't work. So i have to ask for help from you. Do you have any ideas about that? How to fix it? Thanks in advance.

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  • Folder permission and submit button

    - by bob
    I want to create a simple installation script. Below are simple code. <ul> <?php function check_perms($path,$perm) { clearstatcache(); $configmod = substr(sprintf('%o', fileperms($path)), -4); $css = (($configmod != $perm) ? " class='error r2'" : " class='none'"); echo "<li".$css.">\n"; echo '<span style="float:left; padding-right:20px;">'.$path.'</span>'; echo '<span style="float:right; width:100px; text-align:right;"> <strong>'.$perm.'</strong></span>'; echo '<span style="float:right; padding-right:100px;"><strong>'.$configmod.'</strong></span>'; echo '<div class="clear"></div>'; echo "</li>"; } check_perms("config.php","0777"); check_perms("themes","0777"); check_perms("themes/images","0777"); check_perms("useruploads","0777"); ?> </ul> How to make if all file and folder is valid permission to 777 will appear Submit button. <input type='submit' name='submit' value='Submit' /> If there still have incorrect permission do not show the Submit button Let me know.

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  • Submit to open up a popup window and carry through input data

    - by zac
    Hi, I have a input box on one page that on submit opens a new page with a longer form and the first field is populated with what was entered from the previous pages input box. So on page 1 there is this code: <form action="sign-up.php"> <input type="text" name="email" value="sign up for email" onFocus="clearText(this)" onBlur="clearText(this)" style="float: left;"> <input value='Submit' /> </form> Then on the sign-up page the receiving form grabs the string out of the url //<!-- Begin function getParams() { var idx = document.URL.indexOf('?'); if (idx != -1) { var tempParams = new Object(); var pairs = document.URL.substring(idx+1,document.URL.length).split('&'); for (var i=0; i<pairs.length; i++) { nameVal = pairs[i].split('='); tempParams[nameVal[0]] = nameVal[1]; } return tempParams; } } var params = getParams(); // End --> I would like to keep all of this functionality but it have it occur in a popup. I added this function to the submit: function myPopup() { window.open( "sign-up.php", "myWindow", "status = 1, height = 300, width = 300, resizable = 0" ) and the form becomes <form> <input type="text" name="email" value="sign up for email" onFocus="clearText(this)" onBlur="clearText(this)" style="float: left;"> <input onClick="myPopup()" value='Submit' /> </form> But it no longer appends the input data to the url string. Anyone have any ideas on how I can accomplish this?

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  • How to get Tkinter to input text and submit with button

    - by Rob
    Hi I was wondering if anybody could help me submit code from the test fields to the login fields from Tkinter import * import tkMessageBox if ( __name__ == "__main__" ): import resources.lib.mechanize as mechanize mechanize # Start Browser br = mechanize.Browser(factory=mechanize.RobustFactory()) # User-Agent (Firefox) br.addheaders = [('User-agent', 'Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.0.6')] br.open('http://razetheworld.com/wp-login.php?redirect_to=http%3A%2F%2Frazetheworld.com') br.select_form(name="loginform") br['log'] = 'entryWidget_U must enter here' br['pwd'] = 'entryWidget_P must enter here' br.submit(name="wp-submit") print br.geturl() def displayText(): """ Display the Entry text value. """ global entryWidget_U global entryWidget_P if entryWidget_U.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Username") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_U.get().strip()) if entryWidget_P.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Password") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_P.get().strip()) if __name__ == "__main__": root = Tk() root.title("Tkinter Entry Widget") root["padx"] = 40 root["pady"] = 20 # Create a text frame to hold the text Label and the Entry widget textFrame_U = Frame(root) textFrame_P = Frame(root) #Create a Label in textFrame entryLabel = Label(textFrame_U) entryLabel["text"] = "Enter Username:" entryLabel.pack(side=LEFT) entryLabel = Label(textFrame_P) entryLabel["text"] = "Enter Password:" entryLabel.pack(side=LEFT) # Create an Entry Widget in textFrame entryWidget_U = Entry(textFrame_U) entryWidget_U["width"] = 50 entryWidget_U.pack(side=LEFT) entryWidget_P = Entry(textFrame_P) entryWidget_P["width"] = 50 entryWidget_P.pack(side=LEFT) textFrame_U.pack() textFrame_P.pack() button = Button(root, text="Login", command=#Run br.submit(name="wp-submit")) button.pack() root.mainloop()

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  • How do I add descriptive text to form link .gif ?

    - by erynion
    I want to make the descriptive text around a form link also open the form. I want to make it so you can click on "Some Text Here" (below) and open the form on somesomite.com just as if you clicked on the image below this text (somebut.gif, below) <DIV style="position: absolute; top:10px; right:10px; width:70px; height:25px"> <font color="white"><b>Some Text Here<b></font> </div> <DIV style="position: absolute; top:50px; right:10px; width:70px; height:25px"> <form action="https://www.somesite.com/cgi-bin/something" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="image" src="https://www.somesite.com/somebut.gif" border="0" name="submit"> <input type="hidden" name="encrypted" value="-----BEGIN PKCS7-----LONG_KEY...> </form> </div> Thanks

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  • How can I retrieve the values of controls in the form that posted?

    - by Mike at KBS
    I know this has got to be the simplest-sounding question ever asked about ASP.Net but I'm baffled. I have a form wherein my visitor will enter name, address, etc. Then I am POSTing that form via the PostBackUrl property of my Submit button to another page, where the fields are supposed to be all re-formed into new hidden fields, then POSTed again to Paypal. My problem is I cannot get at the values entered by the visitor in the original page. Any time I put in "runat='server'", ASP.Net completely changes the ID of the control, making it impossible to figure out how to access. In the POSTed form I tried Request.Form["_txtFirstName"] and that turned up null. Then I tried ((TextBox)PreviousPage.FindControl("_txtFirstName")).Text and that was null, too. I've tried variations on those. I cannot figure out how I'm supposed to get at these controls. Why does this stuff need to be so difficult?

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  • Serializing form data with field names that have dots in them.

    - by Dave
    Does the serialize function in jQuery replace dots ('.') with underscores? For example, I have a form field such as: <input id="Project.name" name="Project.name" type="text"> When the form is POSTed, I'm serializing the form data and sending it to another PHP file to save. The dots seem to be converted to underscores. Is this normal behavior?

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  • Why is my form triggering the wrong controller action?

    - by COCoach
    This form has multiple submit buttons, when clicked, it calls a simple JavaScript function to change the value of a hidden input (function is called "setHidden". This worked before, after some other not relevant code, it has ceased working. Essentially, the action it is supposed to call is never called, instead it seems to default back to a previous URL. The Form: <form action="/League/RemoveOwner" method="post"> <input type="hidden" value="1007" name="lid"/> <input type="hidden" value="0" id="index" name="index"/> <input type="image" src="../../Resources/Images/Delete.png" height="12" alt="Remove Owner" title="Remove Owner" onclick="setHidden('index', '1031')"/></a> coach<br /> </form> The Controller: [HttpPost] public ActionResult RemoveOwner(int id, string index) { //yada return PartialView(); } When clicking the image, it should call the remove owner controller, instead it calls the "View" controller: public ActionResult View(int id) { //yada return View(); }

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  • Jquery validation on click event instead of on submit

    - by Mazzi
    I looked all around SOF but no luck to find me answer. It is either too easy or the answer is not just there. What I simply need to do is to validate the form when my <img id='submit'/> is clicked and submit it afterwards. $(document).ready(function(){ $('#submit').click(function() { }); // Validation $('#suzuki_scb').validate({ // My Rules and Messages! }); });

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  • Javascript Submit

    - by Mick
    Hi I have the following script in my form function pdf() { var frm = document.getElementById("form1"); frm.action = "http://www.abbysoft.co.uk/index.php"; frm.target="_blank" frm.submit() } this is called from the following in my form <input class="buttn" type="button" value="Test" onclick="pdf()" The code work up to the frm.submit() but it will not submit Can anyone offer any advice please ?

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