Search Results

Search found 5968 results on 239 pages for 'generator expression'.

Page 30/239 | < Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >

  • how to record mic input and pipe the output to another program

    - by acrs
    Hi everyone Im trying to follow a tutorial on generating truly random bits How To Generate Truly Random Bits This is the command from the tutorial but it does not work rec -c 1 -d /dev/dsp -r 8000 -t wav -s w - | ./noise-filter >bits I know i can record my mic input using rec -c 1 no.wav this is the command i tried using rec -c 1 -r 8000 -t wav -s noise.wav | ./noise-filter >bits but i get root@xxc:~/cc# rec -c 1 -r 8000 -t wav -s noise.wav - | ./noise-filter >bits rec WARN formats: can't set sample rate 8000; using 48000 rec FAIL sox: Input files must have the same sample-rate I have complied noise-filter noise-filter I think the tutorial is using an older version of SOX and REC I'm using sox: SoX v14.3.2 on Ubuntu 12.04 server Can someone please help me ?

    Read the article

  • Reg Expression htaccess RewriteRule

    - by Rick
    I am new to using regular expressions for rewriting URL's in htaccess I need to redirect mysite.com/123 to mysite.com/, IF cookie named 'ref' is set. my current htaccess is: <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteCond %{HTTP_COOKIE} ref=true [NC] RewriteRule ^/([0-9]+)/$ http://www.mysite.com </IfModule> The goal is that when someone enters site with: mysite.com/111(some number) that they are redirected to the home page of the site after the cookie is set. Be nice... I'm new! ;o)

    Read the article

  • Exclude regular expression from virtual host

    - by Joao Trindade
    I have a virtual host in apache which is redirecting requests to another web server. <VirtualHost *:80> DocumentRoot /var/www ServerName another.host ProxyPass / http://another.host2:8081/ ProxyPassReverse / http://another.host2:8081/ </VirtualHost> I need to exclude an URL pattern from being catch by this virtual host. Basically I don't want requests with the url: http://another.host:8081/~username to be forwarded to the other server. Can this be done?

    Read the article

  • Quick Replace in Visual Studio 2010 fails to use Tagged Expression n

    - by slomojo
    I'm trying to do some basic regex Quick Replace operations in Visual Studio 2010, but when I use regex grouping I don't get Tagged Expressions (ie. \1 \2 etc.) returning their values, instead they are blank. For example: Text int a = int.Parse("10"); int b = int.Parse("20"); int c = int.Parse("30"); Search Pattern (regex enabled) int\.Parse\("([0-9]*)"\); Replace \1; Replaced Text int a = ; int b = ; int c = ;

    Read the article

  • Excel Matching problem with logic expression

    - by abelenky
    I have a block of data that represents the steps in a process and the possible errors: ProcessStep Status FeesPaid OK FormRecvd OK RoleAssigned OK CheckedIn Not Checked In. ReadyToStart Not Ready for Start I want to find the first Status that is not "OK". I have attempted this: =Match("<>""OK""", StatusRange, 0) which is supposed to return the index of the first element in the range that is NOT-EQUAL (<) to "OK" But this doesn't work, instead returning #N/A. I expect it to return 4 (index #4, in a 1-based index, representing that CheckedIn is the first non-OK element) Any ideas how to do this?

    Read the article

  • Regular expression in mySQL [migrated]

    - by Rayne
    I have a mysql table that has 2 columns - Column 1 contains a string value, and Column 2 contains the number of times that string value occurred. I'm trying to find the string abc.X.def, where the beginning of the string is "abc.", followed by one or more characters, then the string ".def". There could be more characters following ".def". How can I find such strings, then add the occurrence of such strings and display the results? For example, if I have abc.111.def23 1 abc.111.def 2 abc.22.def444 1 abc.111.def 1 Then I will get abc.111.def23 1 abc.111.def 3 abc.22.def444 1 Thank you.

    Read the article

  • Why is my /dev/random so slow when using dd?

    - by Mikey
    I am trying to semi-securely erase a bunch of hard drives. The following is working at 20-50Mb/s dd if=/dev/zero of=/dev/sda But dd if=/dev/random of=/dev/sda seems not to work. Also when I type dd if=/dev/random of=stdout It only gives me a few bytes regardless of what I pass it for bs= and count= Am I using /dev/random wrong? What other info should I look for to move this troubleshooting forward? Is there some other way to do this with a script or something like makeMyLifeEasy | dd if=stdin of=/dev/sda Or something like that...

    Read the article

  • Aplication for generating cross table

    - by Ajtak
    I need advice on whether there is an application for generating cross tables. I would imagine it so that I entered at the beginning of team names. Subsequently I wrote results, but always one and the second correct field would enrolled opposite result. I want it to count the total score etc. .. I hope I have expanded well. I would like recommendations for any program. In Excel I dont. Thank you a thousand times for any advice. http://imageshack.us/a/img849/9100/d70m.png

    Read the article

  • Use QuickCheck by generating primes

    - by Dan
    Background For fun, I'm trying to write a property for quick-check that can test the basic idea behind cryptography with RSA. Choose two distinct primes, p and q. Let N = p*q e is some number relatively prime to (p-1)(q-1) (in practice, e is usually 3 for fast encoding) d is the modular inverse of e modulo (p-1)(q-1) For all x such that 1 < x < N, it is always true that (x^e)^d = x modulo N In other words, x is the "message", raising it to the eth power mod N is the act of "encoding" the message, and raising the encoded message to the dth power mod N is the act of "decoding" it. (The property is also trivially true for x = 1, a case which is its own encryption) Code Here are the methods I have coded up so far: import Test.QuickCheck -- modular exponentiation modExp :: Integral a => a -> a -> a -> a modExp y z n = modExp' (y `mod` n) z `mod` n where modExp' y z | z == 0 = 1 | even z = modExp (y*y) (z `div` 2) n | odd z = (modExp (y*y) (z `div` 2) n) * y -- relatively prime rPrime :: Integral a => a -> a -> Bool rPrime a b = gcd a b == 1 -- multiplicative inverse (modular) mInverse :: Integral a => a -> a -> a mInverse 1 _ = 1 mInverse x y = (n * y + 1) `div` x where n = x - mInverse (y `mod` x) x -- just a quick way to test for primality n `divides` x = x `mod` n == 0 primes = 2:filter isPrime [3..] isPrime x = null . filter (`divides` x) $ takeWhile (\y -> y*y <= x) primes -- the property prop_rsa (p,q,x) = isPrime p && isPrime q && p /= q && x > 1 && x < n && rPrime e t ==> x == (x `powModN` e) `powModN` d where e = 3 n = p*q t = (p-1)*(q-1) d = mInverse e t a `powModN` b = modExp a b n (Thanks, google and random blog, for the implementation of modular multiplicative inverse) Question The problem should be obvious: there are way too many conditions on the property to make it at all usable. Trying to invoke quickCheck prop_rsa in ghci made my terminal hang. So I've poked around the QuickCheck manual a bit, and it says: Properties may take the form forAll <generator> $ \<pattern> -> <property> How do I make a <generator> for prime numbers? Or with the other constraints, so that quickCheck doesn't have to sift through a bunch of failed conditions? Any other general advice (especially regarding QuickCheck) is welcome.

    Read the article

  • How do I use Sketchflow sample data for a ListBoxItem Template at design time?

    - by Boris Nikolaevich
    I am using Expression Blend 4 and Visual Studio 2010 to create a Sketchflow prototype. I have a Sample Data collection and a ListBox that is bound to it. This displays as I would expect both at design time and at run time. However, the ListBoxItem template it just complex enough that I wanted to pull it out into its own XAML file. Even though the items still render as expected in the main ListBox where the template is used, when I open the template itself, all of the databound controls are empty. If I add a DataContext to the template, I can see and work with the populated objects while in the template, but then that local DataContext overrides the DataContext set on the listbox. A bit of code will illustrate. Start by creating a Sketchflow project (I am using Silverlight, but it should work the same for WPF), then add a project data source called SampleDataSource. Add a collection called ListData, with a single String property called Title. Here is the (scaled down) code for the main Sketchflow screen, which we'll call Main.xaml: <UserControl xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:local="clr-namespace:DemoScreens" mc:Ignorable="d" x:Class="DemoScreens.Main" Width="800" Height="600"> <UserControl.Resources> <ResourceDictionary> <ResourceDictionary.MergedDictionaries> <ResourceDictionary Source="ProjectDataSources.xaml"/> </ResourceDictionary.MergedDictionaries> <DataTemplate x:Key="ListBoxItemTemplate"> <local:DemoListBoxItemTemplate d:IsPrototypingComposition="True" Margin="0,0,5,0" Width="748"/> </DataTemplate> </ResourceDictionary> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="#5c87b2" DataContext="{Binding Source={StaticResource SampleDataSource}}"> <ListBox Background="White" x:Name="DemoList" Style="{StaticResource ListBox-Sketch}" Margin="20,100,20,20" ItemTemplate="{StaticResource ListBoxItemTemplate}" ItemsSource="{Binding ListData}" ScrollViewer.HorizontalScrollBarVisibility="Disabled"/> </Grid> </UserControl> You can see that it references the DemoListBoxItemTemplate, which is defined in its own DemoListBoxItemTemplate.xaml: <UserControl xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:local="clr-namespace:DemoScreens" mc:Ignorable="d" x:Class="DemoScreens.DemoListBoxItemTemplate"> <Grid x:Name="LayoutRoot"> <TextBlock Text="{Binding Title}" Style="{StaticResource BasicTextBlock-Sketch}" Width="150"/> </Grid> </UserControl> Obviously, this is way simpler than my actual listbox, but it should be enough to illustrate my problem. When you open Main.xaml in the Expression designer, the list box is populated with sample data. But when you open DemoListBoxItemTemplate.xaml, there is no data context and therefore no data to display—which makes it more difficult to identify controls visually. How can I have sample data displayed when I am working with the template, while still allowing the larger set of sample data to be used for the ListBox itself?

    Read the article

  • Application Screen Repainting Issues

    - by Jeff Sheldon
    I have this issue lately at work. It drives be nuts, and I finally stopped to ask this question. It's quite often that an application I've been running just randomly fails to repaint itself for a while, usually in the editor screen. I most often see this occurring with Expression Web, Visual Studio 2008/2010 and SQL Server Management studio. These applications are what I work in the most, so I'm not surprised to mostly see it here. But I was curious if anyone else had a solution for this. I've tried: Reboots. The screen shot below is about 10 minutes after a reboot. New Video Drivers. This machine is running a Nvidia Quadro NVS 290 video card with the latest drivers. Closing other applications, this is the only thing running right now. As far as hardware, this machine has Dual Quad-Core Xeon 2.83ghz Processors, with 10 gigs of memory, running Windows XP SP3 64bit. Any help would be great. JNK EDIT: Per comments from deleted (wrong) answer: I'm running dual monitors. Set it to single display, still occurred. Rebooted, and tried it again, and it still occurred. Switched it back to dual screen. My resolution is only 1400x900 on each.

    Read the article

  • How can I get objects and property values from expression trees?

    This is a follow-up to the Getting Information About Objects, Types, and Members with Expression Trees post, so I would recommend that you read that one first. Among other code examples in that blog post, I demonstrated how you can get a property name as a string by using expression trees. Here is the method. public static string GetName<T>(Expression<Func<T>> e) { var member = (MemberExpression)e.Body; return member.Member.Name; } And here is how you can use it. string...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • How can I get objects and property values from expression trees?

    This is a follow-up to the Getting Information About Objects, Types, and Members with Expression Trees post, so I would recommend that you read that one first. Among other code examples in that blog post, I demonstrated how you can get a property name as a string by using expression trees. Here is the method. public static string GetName<T>(Expression<Func<T>> e) { var member = (MemberExpression)e.Body; return member.Member.Name; } And here is how you can use it. string...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • Microsoft sort une RC de Silverlight 4 pour les développeurs, et une Bêta de Expression Blend 4

    Microsoft sort une RC de Silverlight 4 Pour les développeurs, et une Bêta de Expression Blend 4 Microsoft vient d'annoncer une version RC (Release Candidate) de sa technologie web Silverlight 4. Elle est la suite logique de la version bêta, qui elle avait été diffusée lors de la Professional Developers Conference en novembre denier. Silverlight 4 RC permet notamment la prise en charge d'outils de développement tels que Visual Studio et Expression Blend avec la technologie Sketchflow. Dans le même temps, le MIX10 qui se déroule actuellement à Las Vegas a également permis à Microsoft de dévoiler la Bêta de Expression Blend 4, l'outil de conception d'interfaces ...

    Read the article

  • Complex(?) regex: Is expression, but not another

    - by Kieron
    (If you can make a better title, please do) Hi, I need to make sure a string matches the following regex: ^[0-9a-zA-Z]{1}[0-9a-zA-Z\.\-_]*$ (Starts with a letter or number, then any number of letters, numbers, dots, dashes or underscores) But given that, I need to make sure it doesn't match a Guid, my Guid matching reg-ex looks like this (obviously, this needs to be negated in the merged result): ^([0-9a-fA-F]){8}-([0-9a-fA-F]){4}-([0-9a-fA-F]){4}-([0-9a-fA-F]){4}-([0-9a-fA-F]){12}$ The last requirement here is that they must (if it's possible) be merged into a single expression.

    Read the article

  • How is this Quartz Cron Expression executed

    - by n002213f
    I have a the following; private String cronExpression = ""; private final String jobID = "MyJObID"; ... Scheduler scheduler = ServiceLocator.getInstance().getScheduler(); CronTrigger trigger = new CronTrigger(jobID , Scheduler.DEFAULT_GROUP, cronExpression); JobDetail jobDetail = new JobDetail(jobID , Scheduler.DEFAULT_GROUP, MyJob.class); scheduler.scheduleJob(jobDetail, trigger); My question is when is this job triggered for the empty cron expression?

    Read the article

  • Regular expression replace a word by a link

    - by AnhTu
    I want to write a regular expression that will replace the word Paris by a link, for only the word is not ready a part of a link. Example: i'm living <a href="Paris" atl="Paris link">in Paris</a>, near Paris <a href="gare">Gare du Nord</a>, i love Paris. would become i'm living.........near <a href="">Paris</a>..........i love <a href="">Paris</a>.

    Read the article

  • javascript regular expression search a pattern A(xyz).

    - by Paul
    I need to find all substrings from a string that starting with a given string following with a left bracket and then any legal literal and then the right bracket. For example, a string is abcd(xyz)efcd(opq), I want to a function that returns "cd(xyz)" and "cd(opq)". I wrote a regular expression, but it returns only cd( and cd(...

    Read the article

< Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >