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• How to parse kanji numeric characters using ICU?

  - by Aki

  I'm writing a function using ICU to parse an Unicode string which consists of kanji numeric character(s) and want to return the integer value of the string. "?" = 5 "???" = 31 "???????" = 5972 I'm setting the locale to Locale::getJapan() and using the NumberFormat::parse() to parse the character string. However, whenever I pass it any Kanji characters, the parse() method is returning U_INVALID_FORMAT_ERROR. Does anyone know if ICU supports Kanji character strings in the NumberFormat::parse() method? I was hoping that since I'm setting the Locale to Japanese that it would be able to parse Kanji numeric values. Thanks! #include <iostream> #include <unicode/numfmt.h> using namespace std; int main(int argc, char **argv) { const Locale &jaLocale = Locale::getJapan(); UErrorCode status = U_ZERO_ERROR; NumberFormat *nf = NumberFormat::createInstance(jaLocale, status); UChar number[] = {0x4E94}; // Character for '5' in Japanese '?' UnicodeString numStr(number); Formattable formattable; nf->parse(numStr, formattable, status); if (U_FAILURE(status)) { cout << "error parsing as number: " << u_errorName(status) << endl; return(1); } cout << "long value: " << formattable.getLong() << endl; }

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• LaTex, align alignment characters between align blocks

  - by ccook

  I would like to align two alignment characters between two align blocks so that I can have some text in the middle of a derivation with equations maintaining the horizontal alignment. For example the following excerpt of latex using align \begin{align*} \frac{\delta \phi}{\delta x_1} = {} &\frac{9}{8}\frac{\delta_1\phi}{\delta_1x_1}-\frac{1}{8}\frac{\delta_3\phi}{\delta_3x_1} \\ & \frac{9}{8}\frac{1}{h_1}\left[\phi(x_1+h_1/2)-\phi(x_i-h_1/2)\right]-\frac{1}{8}\frac{1}{3h_1}\left[\phi(x_i+3h_1/2)-\phi(x_1-3h_1/2)\right] \end{align*} some text in the middle \begin{align*} & \frac{9}{8}\frac{1}{h_1}\left[\phi(x_1+h_1/2)-\phi(x_i-h_1/2)\right]-\frac{1}{8}\frac{1}{3h_1}\left[\phi(x_i+3h_1/2)-\phi(x_1-3h_1/2)\right] \end{align*} Ideally I would like the left of the equation in the second block to line up with that of the second equation in the first block. I could do a workaround by not having text in the middle, however, I would like this functionality. EDIT I would like to have a good amount of text between. Say three to four lines that line up as normal paragraphs. Adding text in the alignment block is the workaround I poorly alluded to.

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• R: convert data.frame columns from factors to characters

  - by Mike Dewar

  Hi, I have a data frame. Let's call him bob: > head(bob) phenotype exclusion GSM399350 3- 4- 8- 25- 44+ 11b- 11c- 19- NK1.1- Gr1- TER119- GSM399351 3- 4- 8- 25- 44+ 11b- 11c- 19- NK1.1- Gr1- TER119- GSM399352 3- 4- 8- 25- 44+ 11b- 11c- 19- NK1.1- Gr1- TER119- GSM399353 3- 4- 8- 25+ 44+ 11b- 11c- 19- NK1.1- Gr1- TER119- GSM399354 3- 4- 8- 25+ 44+ 11b- 11c- 19- NK1.1- Gr1- TER119- GSM399355 3- 4- 8- 25+ 44+ 11b- 11c- 19- NK1.1- Gr1- TER119- I'd like to concatenate the rows of this data frame (this will be another question). But look: > class(bob$phenotype) [1] "factor" Bob's columns are factors. So, for example: > as.character(head(bob)) [1] "c(3, 3, 3, 6, 6, 6)" "c(3, 3, 3, 3, 3, 3)" [3] "c(29, 29, 29, 30, 30, 30)" I don't begin to understand this, but I guess these are indices into the levels of the factors of the columns (of the court of king caractacus) of bob? Not what I need. Strangely I can go through the columns of bob by hand, and do bob$phenotype <- as.character(bob$phenotype) which works fine. And, after some typing, I can get a data.frame whose columns are characters rather than factors. So my question is: how can I do this automatically? How do I convert a data.frame with factor columns into a data.frame with character columns without having to manually go through each column? Bonus question: why does the manual approach work?

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• Using Regex Replace when looking for un-escaped characters

  - by Daniel Hollinrake

  I've got a requirement that is basically this. If I have a string of text such as "There once was an 'ugly' duckling but it could never have been \'Scarlett\' Johansen" then I'd like to match the quotes that haven't already been escaped. These would be the ones around 'ugly' not the ones around 'Scarlett'. I've spent quite a while on this using a little C# console app to test things and have come up with the following solution. private static void RegexFunAndGames() { string result; string sampleText = @"Mr. Grant and Ms. Kelly starred in the film \'To Catch A Thief' but not in 'Stardust' because they'd stopped acting by then"; string rePattern = @"\\'"; string replaceWith = "'"; Console.WriteLine(sampleText); Regex regEx = new Regex(rePattern); result = regEx.Replace(sampleText, replaceWith); result = result.Replace("'", @"\'"); Console.WriteLine(result); } Basically what I've done is a two step process find those characters that have already been escaped, undo that then do everything again. It sounds a bit clumsy and I feel that there could be a better way.

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• Munging non-printable characters to dots using string.translate()

  - by Jim Dennis

  So I've done this before and it's a surprising ugly bit of code for such a seemingly simple task. The goal is to translate any non-printable character into a . (dot). For my purposes "printable" does exclude the last few characters from string.printable (new-lines, tabs, and so on). This is for printing things like the old MS-DOS debug "hex dump" format ... or anything similar to that (where additional whitespace will mangle the intended dump layout). I know I can use string.translate() and, to use that, I need a translation table. So I use string.maketrans() for that. Here's the best I could come up with: filter = string.maketrans( string.translate(string.maketrans('',''), string.maketrans('',''),string.printable[:-5]), '.'*len(string.translate(string.maketrans('',''), string.maketrans('',''),string.printable[:-5]))) ... which is an unreadable mess (though it does work). From there you can call use something like: for each_line in sometext: print string.translate(each_line, filter) ... and be happy. (So long as you don't look under the hood). Now it is more readable if I break that horrid expression into separate statements: ascii = string.maketrans('','') # The whole ASCII character set nonprintable = string.translate(ascii, ascii, string.printable[:-5]) # Optional delchars argument filter = string.maketrans(nonprintable, '.' * len(nonprintable)) And it's tempting to do that just for legibility. However, I keep thinking there has to be a more elegant way to express this!

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• iPhone/iPad : Check for invalid characters in a textbox made for Integers only

  - by JustinXXVII

  I noticed that the iPhone OS is pretty good about picking out Integer values when asked to. Specifically, if you use NSString *stringName = @"6("; int number = [stringName intValue]; the iPhone OS will pick out the 6 and turn the variable number into 6. However, in more complex mistypes, this also makes the int variable 6: NSString *stringName = @"6(5"; int number = [stringName intValue]; The iPhone OS misses the other digit, when what could have possibly been the user trying to enter the number 65, the OS only gets the number 6 out of it. I need a solution to check a string for invalid characters and return NO if there is anything other than an unsigned integer in a textbox. This is for iPad, and currently there is no numeric keyboard like the iPhone has, and I'm instead limited to the standard 123 keyboard. I was thinking that I need to use NSRange and somehow loop through the entire string in the textbox, and checking to see if the current character in the iteration is a number. I'm lost as far as that goes. I can think of testing it against zero, but zero is a valid integer. Can anyone help?

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• Convert UCS-2 characters to UTF-8 Using C#

  - by quanticle

  I'm pulling some internationalized text from a MS SQL Server 2005 database. As per the defaults for that DB, the characters are stored as UCS-2. However, I need to output the data in UTF-8 format, as I'm sending it out over the web. Currently, I have the following code to convert: SqlString dbString = resultReader.GetSqlString(0); byte[] dbBytes = dbString.GetUnicodeBytes(); byte[] utf8Bytes = System.Text.Encoding.Convert(System.Text.Encoding.Unicode, System.Text.Encoding.UTF8, dbBytes); System.Text.UTF8Encoding encoder = new System.Text.UTF8Encoding(); string outputString = encoder.GetString(utf8Bytes); However, when I examine the output in the browser, it appears to be garbage, no matter what I set the encoding to. What am I missing? EDIT: In response to the answers below, the reason I thought I had to perform a conversion is because I can output literal multibyte strings just fine. For example: OutputControl.Text = "????????????????????????????????????????????????????????????????"; works. Here, OutputControl is an ASP.Net Literal. However, OutputControl.Text = outputString; //Output from above snippet results in mangled output as described above. My hypothesis was that the database's output was somehow getting mangled by ASP.Net. If that's not the case, then what are some other possibilities?

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• Fill in word form field with more than 255 characters

  - by user1308743

  I am trying to programmaticly fill in a microsoft word form. I am successfully able to do so if the string is under 255 chars with the following code below, however it says the string is too long if i try and use a string over 255 chars... How do I get past this limitation? If I open the word doc in word I can type in more than 255 chars without a problem. Does anyone know how to input more characters via c# code? object fileName = strFileName; object readOnly = false; object isVisible = true; object missing = System.Reflection.Missing.Value; //open doc _oDoc = _oWordApplic.Documents.Open(ref fileName, ref missing, ref readOnly, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref isVisible, ref missing, ref missing, ref missing, ref missing); _oDoc.Activate(); //write string _oDoc.FormFields[oBookMark].Result = value; //save and close oDoc.SaveAs(ref fileName, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing); _oWordApplic.Application.Quit(ref missing, ref missing, ref missing);

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• XSLT 1.0 : Iterate over characters in a string

  - by subtenante

  I need to iterate over the characters in a string to build an XML structure. Currently, I am doing this : <xsl:template name="verticalize"> <xsl:param name="text">Some text</xsl:param> <xsl:for-each select="tokenize(replace(replace($text,'(.)','$1\\n'),'\\n$',''),'\\n')"> <xsl:element name="para"> <xsl:value-of select="."/> </xsl:element> </xsl:for-each> </xsl:template> This produces something like : <para>S</para> <para>o</para> <para>m</para> <para>e</para> <para> </para> <para>t</para> <para>e</para> <para>x</para> <para>t</para> This works fine with Xpath 2.0. But I need to apply the same treatment in a XPath 1.0 environment, where the replace() method is not available. Do you know a way to achieve this ?

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• Maximum number of characters using keystrokes A, Ctrl+A, Ctrl+C and Ctrl+V

  - by munda

  This is an interview question from google. I am not able to solve it by myself. Can somebody shed some light? Write a program to print the sequence of keystrokes such that it generates the maximum number of character 'A's. You are allowed to use only 4 keys: A, Ctrl+A, Ctrl+C and Ctrl+V. Only N keystrokes are allowed. All Ctrl+ characters are considered as one keystroke, so Ctrl+A is one keystroke. For example, the sequence A, Ctrl+A, Ctrl+C, Ctrl+V generates two A's in 4 keystrokes. Ctrl+A is Select All Ctrl+C is Copy Ctrl+V is Paste I did some mathematics. For any N, using x numbers of A's , one Ctrl+A, one Ctrl+C and y Ctrl+V, we can generate max ((N-1)/2)2 number of A's. For some N M, it is better to use as many Ctrl+A's, Ctrl+C and Ctrl+V sequences as it doubles the number of A's. The sequence Ctrl+A, Ctrl+V, Ctrl+C will not overwrite the existing selection. It will append the copied selection to selected one.

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• Getting XML Numbered Entities with PHP 5 DOM

  - by user343607

  Hello guys, I am new here and got a question that is tricking me all day long. I've made a PHP script, that reads a website source code through cURL, then works with DOMDocument class in order to generate a sitemap file. It is working like a charm in almost every aspect. The problem is with special characters. For compatibility reasons, sitemap files needs to have all special chars encoded as numbered entities. And I am not achieving that. For example, one of my entries - automatically read from site URLs, and wrote to sitemap file - is: http://www.somesite.com/serviços/redesign/ On the source code it should looks like: http://www.somesite.com/servi*ç*os/redesign/ Just this. But unfortunately, I am really not figuring it out how to do it. Source code file, server headers, etc... everything is encoded as UTF-8. I'm using DOMDocument and related extensions to build the XML. (Basically, DOMDocument, $obj-createElement, $obj-appendChild). htmlentities gives ç instead of ç str_replace does not work. It makes the character just vanish in the output. I was using $obj-createElement("loc", $url); on my code, and just now I read in PHP manual that I should use $document-createTextNode($page), in order to have entities encoding support. Well, it is not working either. Any idea on how to get unstuck of this? Thanks.

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• ASP.Net MVC, JS injection and System.ArgumentException - Illegal Characters in path

  - by Mose

  Hi, In my ASP.Net MVC application, I use custom error handling. I want to perform custom actions for each error case I meet in my application. So I override Application_Error, get the Server.GetLastError(); and do my business depending on the exception, the current user, the current URL (the application runs on many domains), the user IP, and many others. Obviousely, the application is often the target of hackers. In almost all the case it's not a problem to detect and manage it, but for some JS URL attacks, my error handling does not perform what I want it to do. Ex (from logs) : http://localhost:1809/Scripts/]||!o.support.htmlSerialize&&[1 When I got such an URL, an exception is raised when accessing the ConnectionStrings section in the web.config, and I can't even redirect to another URL. It leads to a "System.ArgumentException - Illegal Characters in path, etc." The screenshot below shows the problem : http://screencast.com/t/Y2I1YWU4 An obvious solution is to write a HTTP module to filter the urls before they reach my application, but I'd like to avoid it because : I like having the whole security being managed in one place (in the Application_Error() method) In the module I cannot access the whole data I have in the application itself (application specific data I don't want to debate here) Questions : Did you meet this problem ? How did you manage it ? Thanks for you suggestions, Mose

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• Ruby - calling constructor without arguments & removal of new line characters

  - by Raj

  I am a newbie at Ruby, I have written down a sample program. I dont understand the following: Why constructor without any arguments are not called in Ruby? How do we access the class variable outside the class' definition? Why does it always append newline characters at the end of the string? How do we strip it? Code: class Employee attr_reader :empid attr_writer :empid attr_writer :name def name return @name.upcase end attr_accessor :salary @@employeeCount = 0 def initiaze() @@employeeCount += 1 puts ("Initialize called!") end def getCount return @@employeeCount end end anEmp = Employee.new print ("Enter new employee name: ") anEmp.name = gets() print ("Enter #{anEmp.name}'s employee ID: ") anEmp.empid = gets() print ("Enter salary for #{anEmp.name}: ") anEmp.salary = gets() theEmpName = anEmp.name.split.join("\n") theEmpID = anEmp.empid.split.join("\n") theEmpSalary = anEmp.salary.split.join("\n") anEmp = Employee.new() anEmp = Employee.new() theCount = anEmp.getCount puts ("New employee #{theEmpName} with employee ID #{theEmpID} has been enrolled, welcome to hell! You have been paid as low as $ #{theEmpSalary}") puts ("Total number of employees created = #{theCount}") Output: Enter new employee name: Lionel Messi Enter LIONEL MESSI 's employee ID: 10 Enter salary for LIONEL MESSI : 10000000 New employee LIONEL MESSI with employee ID 10 has been enrolled, welcome to hell! You have been paid as low as $ 10000000 Total number of employees created = 0 Thanks

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• ANTLR : How to replace all characters defined as space with actual space

  - by Puneet Pawaia

  Hi All, My ANTLR code is as follow : LPARENTHESIS : ('('); RPARENTHESIS : (')'); fragment CHARACTER : ('a'..'z'|'0'..'9'|); fragment QUOTE : ('"'); fragment WILDCARD : ('*'); fragment SPACE : (' '|'\n'|'\r'|'\t'|'\u000C'|';'|':'|','); WILD_STRING : (CHARACTER)* ( ('?') (CHARACTER)* )+ ; PREFIX_STRING : (CHARACTER)+ ( ('*') )+ ; WS : (SPACE) { $channel=HIDDEN; }; PHRASE : (QUOTE)(LPARENTHESIS)?(WORD)(WILDCARD)?(RPARENTHESIS)?((SPACE)+(LPARENTHESIS)?(WORD)(WILDCARD)?(RPARENTHESIS)?)*(SPACE)+(QUOTE); WORD : (CHARACTER)+; What I would like to do is to replace all characters marked as space to be replaced with actual space character in the PHRASE. Also if possible, I would then like all continuous spaces to be represented by a single space. Any help would be most appreciated. For some reason, I am finding it hard to understand ANTLR. Any good tutorials out there ?

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• How to query MySQL for exact length and exact UTF-8 characters

  - by oskarae

  I have table with words dictionary in my language (latvian). CREATE TABLE words ( value varchar(255) COLLATE utf8_unicode_ci DEFAULT NULL ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; And let's say it has 3 words inside: INSERT INTO words (value) VALUES ('teja'); INSERT INTO words (value) VALUES ('vejš'); INSERT INTO words (value) VALUES ('feja'); What I want to do is I want to find all words that is exactly 4 characters long and where second character is 'e' and third character is 'j' For me it feels that correct query would be: SELECT * FROM words WHERE value LIKE '_ej_'; But problem with this query is that it returs not 2 entries ('teja','vejš') but all three. As I understand it is because internally MySQL converts strings to some ASCII representation? Then there is BINARY addition possible for LIKE SELECT * FROM words WHERE value LIKE BINARY '_ej_'; But this also does not return 2 entries ('teja','vejš') but only one ('teja'). I believe this has something to do with UTF-8 2 bytes for non ASCII chars? So question: What MySQL query would return my exact two words ('teja','vejš')? Thank you in advance

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• Special Characters in JS, how to use "/" character

  - by user1461222

  I've vbulletin 4.2.0 i added an special button to it's editor with this article; http://www.vbulletinguru.com/2012/add-a-new-toolbar-button-to-ckeditor-tutorial/ The thing i want to do is add an syntax highlighter code with this button. When i use below code it's working fine; CKEDITOR.plugins.add( 'YourPluginName', { init: function( editor ) { editor.addCommand( 'SayHello', { exec : function( editor ) { editor.insertHtml( "Hello from my plugin" ); } }); editor.ui.addButton( 'YourPluginName', { label: 'My Button Tooltip', command: 'SayHello', icon: this.path + 'YourPluginImage.png' } ); } } ); so i changed this code to this, because i wannt to add specific text like below; CKEDITOR.plugins.add( 'DKODU', { init: function( editor ) { editor.addCommand( 'SayHello', { exec : function( editor ) { editor.insertHtml( '[kod=delphi][/kod]' ); } }); editor.ui.addButton( 'DKODU', { label: 'My Button Tooltip', command: 'SayHello', icon: this.path + 'star.png' } ); } } ); after update the code when i press the button nothings happen, i checked with google and this site but i couldn't figure it out i think i made mistake with some special characters but i couldn't find what's the problem. If i made some mistakes when i publish this question forgive me and also forgive me for my bad english, thanks.

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• assign characters to key combinations in XP or Visual Studio .Net

  - by cpj

  I'm running Mac OSX on a MacBookPro (UK keyboard). I run windows XP under parallels in a VM. I run Visual Studio .Net 2003 and 2008 in XP in the VM when i need to. I have English United Kingdom and English United states keyboards setup in XP. (they switch sometimes for no apparent reason) There is no hash "#" key on my mac's keyboard. However, in OSX I can get a hash with an alt+3 key combination. But In Windows XP... I can not make a "#" character. I can go to the character map in windows and copy a hash.. switch into OSX and copy a hash.. search in code and copy a hash.. but I can not make a hash in XP using my keyboard without typing U+0023: ... which you can imagine is annoying. coding anything with hash symbols is becoming a choir. Anyone got any advice or key mapping tricks I can use to get hash characters working in XP using my mac UK keyboard?

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• Java - Counting how many characters show up in another string

  - by Vu Châu

  I am comparing two strings, in Java, to see how many characters from the first string show up in the second string. The following is some expectations: matchingChars("AC", "BA") ? 1 matchingChars("ABBA", "B") ? 2 matchingChars("B", "ABBA") ? 1 My approach is as follows: public int matchingChars(String str1, String str2) { int count = 0; for (int a = 0; a < str1.length(); a++) { for (int b = 0; b < str2.length(); b++) { char str1Char = str1.charAt(a); char str2Char = str2.charAt(b); if (str1Char == str2Char) { count++; str1 = str1.replace(str1Char, '0'); } } } return count; } I know my approach is not the best, but I think it should do it. However, for matchingChars("ABBA", "B") ? 2 My code yields "1" instead of "2". Does anyone have any suggestion or advice? Thank you very much.

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• Getting Junk characters while trying to print the file contents using Java

  - by user1523797

  I am reading a file's contents and trying to print the contents using java. But it prints junk characters along with the file content. Code: import java.io.*; public class ReadFile { public String readFile(String filePath){ StringBuilder contents = new StringBuilder(); File file = new File(filePath); try{ String lines = null; FileReader fileReader1 = new FileReader(file); BufferedReader buffer = new BufferedReader(fileReader1); while((lines = buffer.readLine())!=null){ contents.append(lines); } buffer.close(); } catch(FileNotFoundException ex){ System.out.println("File not found."); }catch(IOException ex){ System.out.println("Exception ocurred."); } return contents.toString(); } public static void main(String[] args){ ReadFile rf = new ReadFile(); String lines = rf.readFile("C:\\Data\\FaultDn.txt"); System.out.println("Original file contents: " + lines); } } The file contents are: partner.cisco.com:org-root/mac-pool-QA_MAC_Pool_5-Sep-2012_12:00 The output is:  Can you please point me to what I am missing in this code?

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• Working with a string as an array of characters

  - by Malfunction

  I'm having some trouble with a string represented as an array of characters. What I'd like to do, as I would do in java, is the following: while (i < chars.length) { char ch = chars[i]; if ((WORD_CHARS.indexOf(ch) >= 0) == punctuation) { String token = buffer.toString(); if (token.length() > 0) { parts.add(token); } buffer = new StringBuffer(); } buffer.append(ch); i++; } What I'm doing is something like this: while(i < strlen(chars)) { char ch = chars[i]; if(([WORD_CHARS rangeOfString:ch] >= 0) == punctuation) { NSString *token = buffer.toString(); if([token length] > 0) { [parts addObject:token]; } buffer = [NSMutableString string]; } [buffer append(ch)]; i++; } I'm not sure how I'm supposed to convert String token = buffer.toString(); to objective c, where buffer is an NSMutableString. Also, how do I check this if condition in objective c? if ((WORD_CHARS.indexOf(ch) >= 0) == punctuation) WORD_CHARS is an NSString. I'm also having trouble with appending ch to buffer. Any help is greatly appreciated.

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• *UPDATED* help with django and accented characters?

  - by Asinox

  Hi guys, i have a problem with my accented characters, Django admin save my data without encoding to something like "&aacute;" Example: if im trying a word like " Canción ", i would like to save in this way: Canci&oacute;n, and not Canción. im usign Sociable app: {% load sociable_tags %} {% get_sociable Facebook TwitThis Google MySpace del.icio.us YahooBuzz Live as sociable_links with url=object.get_absolute_url title=object.titulo %} {% for link in sociable_links %} <a href="{{ link.link }}"><img alt="{{ link.site }}" title="{{ link.site }}" src="{{ link.image }}" /></a> {% endfor %} But im getting error if my object.titulo (title of the article) have a accented word. aught KeyError while rendering: u'\xfa' Any idea ? i had in my SETTING: DEFAULT_CHARSET = 'utf-8' i had in my mysql database: utf8_general_ci COMPLETED ERROR: Traceback: File "C:\wamp\bin\Python26\lib\site-packages\django\core\handlers\base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\views\generic\date_based.py" in object_detail 366. response = HttpResponse(t.render(c), mimetype=mimetype) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 173. return self._render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in _render 167. return self.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\loader_tags.py" in render 125. return compiled_parent._render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in _render 167. return self.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\loader_tags.py" in render 62. result = block.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\sociable\templatetags\sociable_tags.py" in render 37. 'link': sociable.genlink(site, **self.values), File "C:\wamp\bin\Python26\lib\site-packages\sociable\sociable.py" in genlink 20. values['title'] = quote_plus(kwargs['title']) File "C:\wamp\bin\Python26\lib\urllib.py" in quote_plus 1228. s = quote(s, safe + ' ') File "C:\wamp\bin\Python26\lib\urllib.py" in quote 1222. res = map(safe_map.__getitem__, s) Exception Type: TemplateSyntaxError at /noticia/2010/jun/10/matan-domingo-paquete-en-la-avenida-san-vicente-de-paul/ Exception Value: Caught KeyError while rendering: u'\xfa' thanks, sorry with my English

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• NSMutableURLRequest and a Password with special Characters won't work

  - by twickl

  I'm writing a small program (using Cocoa Touch), which communicates with a webservice. The code for calling the webservice, is the following: - (IBAction)send:(id)sender { if ([number.text length] > 0) { [[UIApplication sharedApplication] beginIgnoringInteractionEvents]; [activityIndicator startAnimating]; NSString *modded; modded = [self computeNumber]; NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL: [NSURL URLWithString:@"https://tester:%=&[email protected]/RPC2"]]; [theRequest setHTTPMethod:@"POST"]; [theRequest addValue:@"text/xml" forHTTPHeaderField:@"content-type"]; [theRequest setCachePolicy:NSURLCacheStorageNotAllowed]; [theRequest setTimeoutInterval:5.0]; NSString* pStr = [[NSString alloc] initWithFormat:@"<?xml version=\"1.0\" encoding=\"UTF-8\"?><methodCall><methodName>samurai.SessionInitiate</methodName><params><param><value><struct><member><name>LocalUri</name><value><string></string></value></member><member><name>RemoteUri</name><value><string>sip:%@@sipgate.net</string></value></member><member><name>TOS</name><value><string>text</string></value></member><member><name>Content</name><value><string>%@</string></value></member><member><name>Schedule</name><value><string></string></value></member></struct></value></param></params></methodCall>", modded, TextView.text]; NSData* pBody = [pStr dataUsingEncoding:NSUTF8StringEncoding]; [theRequest setHTTPBody:pBody]; NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:theRequest delegate:self]; if (!theConnection) { UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error" message:@"A Connection could not be established!" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles: nil]; [alert show]; [alert release]; sendButton.enabled = TRUE; return; } [pStr release]; [pBody release]; } } The Username and Password have to be in the URL, and it works in most cases, but when the password consists of special characters like in the example "%=&=-Test2009", the Webservice does not respond. If it is something like "Test2009" it works fine. Does anyone have an idea why, and maybe a solution for that?

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• Stuck at being unable to print a substring no more than 4679 characters

  - by Newcoder

  I have a program that does string manipulation on very large strings (around 100K). The first step in my program is to cleanup the input string so that it only contains certain characters. Here is my method for this cleanup: public static String analyzeString (String input) { String output = null; output = input.replaceAll("[-+.^:,]",""); output = output.replaceAll("(\\r|\\n)", ""); output = output.toUpperCase(); output = output.replaceAll("[^XYZ]", ""); return output; } When i print my 'input' string of length 97498, it prints successfully. My output string after cleanup is of length 94788. I can print the size using output.length() but when I try to print this in Eclipse, output is empty and i can see in eclipse output console header. Since this is not my final program, so I ignored this and proceeded to next method that does pattern matching on this 'cleaned-up' string. Here is code for pattern matching: public static List<Integer> getIntervals(String input, String regex) { List<Integer> output = new ArrayList<Integer> (); // Do pattern matching Pattern p1 = Pattern.compile(regex); Matcher m1 = p1.matcher(input); // If match found while (m1.find()) { output.add(m1.start()); output.add(m1.end()); } return output; } Based on this program, i identify the start and end intervals of my pattern match as 12351 and 87314. I tried to print this match as output.substring(12351, 87314) and only get blank output. Numerous hit and trial runs resulted in the conclusion that biggest substring that i can print is of length 4679. If i try 4680, i again get blank input. My confusion is that if i was able to print original string (97498) length, why i couldnt print the cleaned-up string (length 94788) or the substring (length 4679). Is it due to regular expression implementation which may be causing some memory issues and my system is not able to handle that? I have 4GB installed memory.

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• C++ using cdb_read returns extra characters on some reads

  - by Moe Be

  Hi All, I am using the following function to loop through a couple of open CDB hash tables. Sometimes the value for a given key is returned along with an additional character (specifically a CTRL-P (a DLE character/0x16/0o020)). I have checked the cdb key/value pairs with a couple of different utilities and none of them show any additional characters appended to the values. I get the character if I use cdb_read() or cdb_getdata() (the commented out code below). If I had to guess I would say I am doing something wrong with the buffer I create to get the result from the cdb functions. Any advice or assistance is greatly appreciated. char* HashReducer::getValueFromDb(const string &id, vector <struct cdb *> &myHashFiles) { unsigned char hex_value[BUFSIZ]; size_t hex_len; //construct a real hex (not ascii-hex) value to use for database lookups atoh(id,hex_value,&hex_len); char *value = NULL; vector <struct cdb *>::iterator my_iter = myHashFiles.begin(); vector <struct cdb *>::iterator my_end = myHashFiles.end(); try { //while there are more databases to search and we have not found a match for(; my_iter != my_end && !value ; my_iter++) { //cerr << "\n looking for this MD5:" << id << " hex(" << hex_value << ") \n"; if (cdb_find(*my_iter, hex_value, hex_len)){ //cerr << "\n\nI found the key " << id << " and it is " << cdb_datalen(*my_iter) << " long\n\n"; value = (char *)malloc(cdb_datalen(*my_iter)); cdb_read(*my_iter,value,cdb_datalen(*my_iter),cdb_datapos(*my_iter)); //value = (char *)cdb_getdata(*my_iter); //cerr << "\n\nThe value is:" << value << " len is:" << strlen(value)<< "\n\n"; }; } } catch (...){} return value; }

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• Web Url contains Spanish Characters which my NSXMLParser is not parsing

  - by mAc

  I am Parsing Web urls from server and storing them in Strings and then displaying it on Webview. But now when i am parsing Spanish words like http://litofinter.es.milfoil.arvixe.com/litofinter/PDF/Presentación_LITOFINTER_(ES).pdf it is accepting it PDF File Name ++++++ http://litofinter.es.milfoil.arvixe.com/litofinter/PDF/Presentaci PDF File Name ++++++ ón_LITOFINTER_(ES).pdf i.e two different strings... i know i have to make small change that is append the string but i am not able to do it now, can anyone help me out. Here is my code :- - (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict { currentElement = elementName; if([currentElement isEqualToString:@"category"]) { NSLog(@"Current element in Category:- %@",currentElement); obj = [[Litofinter alloc]init]; obj.productsArray = [[NSMutableArray alloc]init]; } if([currentElement isEqualToString:@"Product"]) { obj.oneObj = [[Products alloc]init]; } } - (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string { if([currentElement isEqualToString:@"Logo"]) { obj.cLogo=[NSString stringWithFormat:@"%@",string]; NSLog(@"Logo to be saved in Array :- %@",obj.cLogo); } if([currentElement isEqualToString:@"Name"]) { obj.cName=[NSString stringWithFormat:@"%@",string]; NSLog(@"Name to be saved in Array :- %@",string); } if([currentElement isEqualToString:@"cid"]) { obj.cId=(int)[NSString stringWithFormat:@"%@",string]; NSLog(@"CID to be saved in Array :- %@",string); } if([currentElement isEqualToString:@"pid"]) { //obj.oneObj.id = (int)[NSString stringWithFormat:@"%@",oneBook.id]; obj.oneObj.id = (int)[oneBook.id intValue]; } if([currentElement isEqualToString:@"Title"]) { obj.oneObj.title = [NSString stringWithFormat:@"%@",string]; } if([currentElement isEqualToString:@"Thumbnail"]) { obj.oneObj.thumbnail= [NSString stringWithFormat:@"%@",string]; } // problem occuriing while parsing Spanish characters... if([currentElement isEqualToString:@"pdf"]) { obj.oneObj.pdf = [NSString stringWithFormat:@"%@",string]; NSLog(@"PDF File Name ++++++ %@",string); } } - (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName { if([elementName isEqualToString:@"category"]) { NSLog(@"Current element in End Element Category:- %@",currentElement); [TableMutableArray addObject:obj]; } if([elementName isEqualToString:@"Product"]) { [obj.productsArray addObject:obj.oneObj]; } currentElement = @""; } I will be thankful to you.

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