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• Windows 7 Standy/Hibernate Freeze/Lockup

  - by Kyle

  I'm running Windows 7 Ultimate on a MSI U100 Netbook which often experiences a lockup or freeze whilst hibernating or shutting down. I have a friend with an Asus netbook running Windows 7 who has experienced the same issue. This happens to me perhaps 1-2 times a week, and is frustrating as hell because it will just sit there running flat out (the fan goes to max after a while) until the battery dies if I don't notice it first. Just wondering if anyone has had any similar issues or might be able to point me in the right direction. The freeze occurs when the screen has faded to black. The HDD light flickers for a few moments then just sticks on solid. I haven't been able to isolate any apps which may be causing this either. It will be fine one standby, and lock up the next with no new apps open. Any thoughts greatly appreciated. Cheers, Kyle

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• Windows 8 auto-hibernate from sleep not working on Retina MacBook Pro

  - by frenchglen

  I have a similar question to this one. Only my context is the 15" Retina MacBook Pro - and Windows 8. I have just the original Mac OS X Mountain Lion on there, then Windows 8 via Bootcamp. no rEFIt installed. (I just press ALT every time I restart windows, actually as a security measure to stop tech-unsavvy thugs, who, if the laptop is stolen, think it's only a mac and don't discover my Windows as quickly as they would've, and by that time I remotely activate various anti-theft mac apps and nab them that way). SO: like the related question asks, why isn't it behaving like it should? The Windows 7 FAQ states: Will sleep eventually drain my laptop battery? If your laptop battery charge gets critically low while the computer is asleep, Windows automatically puts the laptop into hibernation mode. But this is just not happening - on my rMBP Windows 8. It seems EVERY time I set the laptop to sleep (when it reaches 10%), then arriving home and plugging it in and hoping to simply resume my work, it does NOT save the session to disk and I lose ALL my work. Who's fault is it? Win 8's (a bug, grr)? Or Apple's EFI system (maybe fixable via editing EFI options/do I have to install refit to make it work perhaps?) Or maybe changing windows power options can somehow fix the problem? Thanks for your help.

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• Trigger Task Scheduler in Windows 7 when computer wakes up from sleep/hibernate

  - by Adam

  I don't want task scheduler or whatever to wake the computer, but when I open the laptop back up and the machine wakes I'd like that to be the trigger that task scheduler or something uses to run an app.

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• Dell Inspiron/Windows Vista sleep/hibernate issue

  - by sarge

  When I hit the sleep button in Windows the computer looks like it's going into Sleep mode but a few seconds later it's restarted, and stops with this error message: internal hard disk drive not found To resolve this issue, try to reseat the drive. No bootable devices--strike F1 to retry boot, F2 for setup utility Press F5 to run onboard diagnostics. The computer is running Windows Vista (SP2) and I have installed all available Windows Updates and the latest manufacturer drivers. I have already tried to reseated the drive, ran the onboard diagnostics and there were no errors. I have changed the power settings for all devices where it's available so that they are not allowed to wake up the computer. Any ideas?

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• Help me find the offending process waking my Windows 7 PC from hibernate every night

  - by DavidGugick

  Recently my Windows 7 64-bit PC has started waking every night from hibernation around 3:30am. I have done the following to try and figure out what is causing the issue with no luck: Examined the Windows Event logs. Nothing is noted Ran powercfg -lastwake and that reports nothing c:\powercfg -lastwake Wake History Count - 1 Wake History [0] Wake Source Count - 0 Ran powercfg to find what devices are armed for wake. Interestingly, this reports two items (I've already unchecked the "Allow this device to wake the computer" in device manager): The keyboard and something called the "eHome Infrared Receiver (USBCIR)". This is a desktop PC and it does not have an Infrared received, so I'm not sure what that device is. Suffice to say it does not have the option to "Allow device to wake..." available in Device Manager. C:\powercfg -devicequery wake_armed eHome Infrared Receiver (USBCIR) HID Keyboard Device My next step is to disable the Keyboard from wake, but I'm not convined that's the problem. This is on a Dell XPS435 if that helps anyone.

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• Alright to truncate database tables when also using Hibernate?

  - by Marcus

  Is it OK to truncate tables while at the same time using Hibernate to insert data? We parse a big XML file with many relationships into Hibernate POJO's and persist to the DB. We are now planning on purging existing data at certain points in time by truncating the tables. Is this OK? It seems to work fine. We don't use Hibernate's second level cache. One thing I did notice, which is fine, is that when inserting we generate primary keys using Hibernate's @GeneratedValue where Hibernate just uses a key value one greater than the highest value in the table - and even though we are truncating the tables, Hibernate remembers the prior value and uses prior value + 1 as opposed to starting over at 1. This is fine, just unexpected. Note that the reason we do truncate as opposed to calling delete() on the Hibernate POJO's is for speed. We have gazillions of rows of data, and truncate is just so much faster.

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• PostgreSQL like + Hibernate problem

  - by Marat_Galiev

  Hi all. I want to do search in PostgreSQL for INTEGER based columns. if (!sSearch.isEmpty()) { sSearch = sSearch.replaceAll("[^a-zA-Z0-9]", "_").toLowerCase(); String[] search = sSearch.split(" "); sWhere = " "; for (NewsColumns column : NewsColumns.values()) { for (String s : search) { sWhere += "lower(" + column + "::TEXT) LIKE '%" + s + "%' OR "; } } sWhere = sWhere.substring(0,sWhere.length()-3); } Ok, I want to convert INT value to String before search, with '::TEXT' expression. But after executing I'm getting: org.hibernate.QueryException: Not all named parameters have been set: [:TEXT] [select * from news WHERE lower(ID::TEXT) LIKE '%5%' Exception. Looks like hibernate parse my convert exp as parameter. Any help is appreciated. Thanks.

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• JPA 2.0 Provider Hibernate 3.6 for DB2 v9.5 type 2 driver is throwing exception in configuration prepration

  - by Deep Saurabh

  The JPA 2.0 Provider Hibernate is throwing exception while preparing configuration for entity manager factory, I am using DB2 v9.5 database and DB2 v9.5 JDBC type 2 driver . java.sql.SQLException: [IBM][JDBC Driver] CLI0626E getDatabaseMajorVersion is not supported in this version of DB2 JDBC 2.0 driver. at COM.ibm.db2.jdbc.app.SQLExceptionGenerator.throwNotSupportedByDB2(Unknown Source) at COM.ibm.db2.jdbc.app.DB2DatabaseMetaData.getDatabaseMajorVersion(Unknown Source) at org.hibernate.cfg.SettingsFactory.buildSettings(SettingsFactory.java:117) at org.hibernate.cfg.Configuration.buildSettingsInternal(Configuration.java:2833) at org.hibernate.cfg.Configuration.buildSettings(Configuration.java:2829) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1840) at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:902) at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:57) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:48) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:32)

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• Simple search only searching last word of record

  - by bennett_an

  I set up a simple search as instructed in part of railscast #240. in controller @reports = Report.search(params[:search]).order('created_at DESC').paginate(:page => params[:page], :per_page => 5) in model def self.search(search) if search where('apparatus LIKE ?', "%#{search}") else scoped end end in view <%= form_tag reports_path, :method => :get do %> <p> <%= text_field_tag :search, params[:search] %> <%= submit_tag "Search", :name => nil %> </p> <% end %> it all works... but... I have a few records for example, one with "another time test" and another with "last test of time" if i search "test" the first comes up but the second doesn't, and if i search "time" the second comes up but not the first. It is only seeing the last word of the record. what gives?

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• How to populate Java (web) application with initial data using Spring/JPA/Hibernate

  - by Tuukka Mustonen

  I want to setup my database with initial data programmatically. I want to populate my database for development runs, not for testing runs (it's easy). The product is built on top of Spring and JPA/Hibernate. Developer checks out the project Developer runs command/script to setup database with initial data Developer starts application (server) and begins developing/testing then: Developer runs command/script to flush the database and set it up with new initial data because database structures or the initial data bundle were changed What I want is to setup my environment by required parts in order to call my DAOs and insert new objects into database. I do not want to create initial data sets in raw SQL, XML, take dumps of database or whatever. I want to programmatically create objects and persist them in database as I would in normal application logic. One way to accomplish this would be to start up my application normally and run a special servlet that does the initialization. But is that really the way to go? I would love to execute the initial data setup as Maven task and I don't know how to do that if I take the servlet approach. There is somewhat similar question. I took a quick glance at the suggested DBUnit and Unitils. But they seem to be heavily focused in setting up testing environments, which is not what I want here. DBUnit does initial data population, but only using xml/csv fixtures, which is not what I'm after here. Then, Maven has SQL plugin, but I don't want to handle raw SQL. Maven also has Hibernate plugin, but it seems to help only in Hibernate configuration and table schema creation (not in populating db with data). How to do this?

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• Duplicate a collection of entities and persist in Hibernate/JPA

  - by Michael Bavin

  Hi, I want to duplicate a collection of entities in my database. I retreive the collection with: CategoryHistory chNew = new CategoryHistory(); CategoryHistory chLast = (CategoryHistory)em.createQuery("SELECT ch from CategoryHistory ch WHERE ch.date = MAX(date)").getSingleResult; List<Category> categories = chLast.getCategories(); chNew.addCategories(categories)// Should be a copy of the categories: OneToMany Now i want to duplicate a list of 'categories' and persist it with EntityManager. I'm using JPA/Hibernate. UPDATE After knowing how to detach my entities, i need to know what to detach: current code: CategoryHistory chLast = (CategoryHistory)em.createQuery("SELECT ch from CategoryHistory ch WHERE ch.date=(SELECT MAX(date) from CategoryHistory)").getSingleResult(); Set<Category> categories =chLast.getCategories(); //detach org.hibernate.Session session = ((org.hibernate.ejb.EntityManagerImpl) em.getDelegate()).getSession(); session.evict(chLast);//detaches also its child-entities? //set the realations chNew.setCategories(categories); for (Category category : categories) { category.setCategoryHistory(chNew); } //set now create date chNew.setDate(Calendar.getInstance().getTime()); //persist em.persist(chNew); This throws a failed to lazily initialize a collection of role: entities.CategoryHistory.categories, no session or session was closed exception. I think he wants to lazy load the categories again, as i have them detached. What should i do now?

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• Using Hibernate's ScrollableResults to slowly read 90 million records

  - by at

  I simply need to read each row in a table in my MySQL database using Hibernate and write a file based on it. But there are 90 million rows and they are pretty big. So it seemed like the following would be appropriate: ScrollableResults results = session.createQuery("SELECT person FROM Person person") .setReadOnly(true).setCacheable(false).scroll(ScrollMode.FORWARD_ONLY); while (results.next()) storeInFile(results.get()[0]); The problem is the above will try and load all 90 million rows into RAM before moving on to the while loop... and that will kill my memory with OutOfMemoryError: Java heap space exceptions :(. So I guess ScrollableResults isn't what I was looking for? What is the proper way to handle this? I don't mind if this while loop takes days (well I'd love it to not). I guess the only other way to handle this is to use setFirstResult and setMaxResults to iterate through the results and just use regular Hibernate results instead of ScrollableResults. That feels like it will be inefficient though and will start taking a ridiculously long time when I'm calling setFirstResult on the 89 millionth row... UPDATE: setFirstResult/setMaxResults doesn't work, it turns out to take an unusably long time to get to the offsets like I feared. There must be a solution here! Isn't this a pretty standard procedure?? I'm willing to forgo Hibernate and use JDBC or whatever it takes. UPDATE 2: the solution I've come up with which works ok, not great, is basically of the form: select * from person where id > <offset> and <other_conditions> limit 1 Since I have other conditions, even all in an index, it's still not as fast as I'd like it to be... so still open for other suggestions..

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• Hibernate limitations on using variables in queries

  - by sammichy

  I had asked the following question I have the following table structure for a table Player Table Player { Long playerID; Long points; Long rank; } Assuming that the playerID and the points have valid values, can I update the rank for all the players based on the number of points in a single query? If two people have the same number of points, they should tie for the rank. And received the answer from Daniel Vassalo (thank you). UPDATE player JOIN (SELECT p.playerID, IF(@lastPoint <> p.points, @curRank := @curRank + 1, @curRank) AS rank, IF(@lastPoint = p.points, @curRank := @curRank + 1, @curRank), @lastPoint := p.points FROM player p JOIN (SELECT @curRank := 0, @lastPoint := 0) r ORDER BY p.points DESC ) ranks ON (ranks.playerID = player.playerID) SET player.rank = ranks.rank; When I try to execute this as a native query in Hibernate, the following exception is thrown. java.lang.IllegalArgumentException: org.hibernate.QueryException: Space is not allowed after parameter prefix ':' Apparently this has been an open issue for the last couple of years, I want to know if the ranking query can be made to work either Without using any variables in the SQL query OR Using any workaround for Hibernate.

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• Ternary (and n-ary) relationships in Hibernate

  - by Bytecode Ninja

  Q 1) How can we model a ternary relationship using Hibernate? For example, how can we model the ternary relationship presented here using Hibernate (or JPA)? Ideally I prefer my model to be like this: class SaleAssistant { Long id; //... } class Customer { Long id; //... } class Product { Long id; //... } class Sale { SalesAssistant soldBy; Customer buyer; Product product; //... } Q 1.1) How can we model this variation, in which each Sale item might have many Products? class SaleAssistant { Long id; //... } class Customer { Long id; //... } class Product { Long id; //... } class Sale { SalesAssistant soldBy; Customer buyer; Set<Product> products; //... } Q 2) In general, how can we model n-ary, n = 3 relationships with Hibernate? Thanks in advance.

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• executing stored procedure from Spring-Hibernate using Annotations

  - by HanuAthena

  I'm trying to execute a simple stored procedure with Spring/Hibernate using Annotations. Here are my code snippets: DAO class: public class UserDAO extends HibernateDaoSupport { public List selectUsers(final String eid){ return (List) getHibernateTemplate().execute(new HibernateCallback() { public Object doInHibernate(Session session) throws HibernateException, SQLException { Query q = session.getNamedQuery("SP_APPL_USER"); System.out.println(q); q.setString("eid", eid); return q.list(); } }); } } my entity class: @Entity @Table(name = "APPL_USER") @Inheritance(strategy = InheritanceType.SINGLE_TABLE) @DiscriminatorFormula(value = "SUBSCRIBER_IND") @DiscriminatorValue("N") @NamedQuery(name = "req.all", query = "select n from Requestor n") @org.hibernate.annotations.NamedNativeQuery(name = "SP_APPL_USER", query = "call SP_APPL_USER(?, :eid)", callable = true, readOnly = true, resultClass = Requestor.class) public class Requestor { @Id @Column(name = "EMPL_ID") public String getEmpid() { return empid; } public void setEmpid(String empid) { this.empid = empid; } @Column(name = "EMPL_FRST_NM") public String getFirstname() { return firstname; } ... } public class Test { public static void main(String[] args) { ApplicationContext ctx = new ClassPathXmlApplicationContext( "applicationContext.xml"); APFUser user = (APFUser)ctx.getBean("apfUser"); List selectUsers = user.getUserDAO().selectUsers("EMP456"); System.out.println(selectUsers); } } and the stored procedure: create or replace PROCEDURE SP_APPL_USER (p_cursor out sys_refcursor, eid in varchar2) as empId varchar2(8); fname varchar2(50); lname varchar2(50); begin empId := null; fname := null; lname := null; open p_cursor for select l.EMPL_ID, l.EMPL_FRST_NM, l.EMPL_LST_NM into empId, fname, lname from APPL_USER l where l.EMPL_ID = eid; end; If i enter invalid EID, its returning empty list which is OK. But when record is there, following exception is thrown: Exception in thread "main" org.springframework.jdbc.BadSqlGrammarException: Hibernate operation: could not execute query; bad SQL grammar [call SP_APPL_USER(?, ?)]; nested exception is java.sql.SQLException: Invalid column name Do I need to modify the entity(Requestor.class) ? How will the REFCURSOR be converted to the List? The stored procedure is expected to return more than one record.

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• Setting database-agnostic default column timestamp using Hibernate

  - by unsquared

  I'm working on a java project full of Hibernate (3.3.1) mapping files that have the following sort of declaration for most domain objects. <property name="dateCreated" generated="insert"> <column name="date_created" default="getdate()" /> </property> The problem here is that getdate() is an MSSQL specific function, and when I'm using something like H2 to test subsections of the project, H2 screams that getdate() isn't a recognized function. It's own timestamping function is current_timestamp(). I'd like to be able to keep working with H2 for testing, and wanted to know whether there was a way of telling Hibernate "use this database's own mechanism for retrieving the current timestamp". With H2, I've come up with the following solution. CREATE ALIAS getdate AS $$ java.util.Date now() { return new java.util.Date(); } $$; CALL getdate(); It works, but is obviously H2 specific. I've tried extending H2Dialect and registering the function getdate(), but that doesn't seem to be invoked when Hibernate is creating tables. Is it possible to abstract the idea of a default timestamp away from the specific database engine?

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• Hibernate triggering constraint violations using orphanRemoval

  - by ptomli

  I'm having trouble with a JPA/Hibernate (3.5.3) setup, where I have an entity, an "Account" class, which has a list of child entities, "Contact" instances. I'm trying to be able to add/remove instances of Contact into a List<Contact> property of Account. Adding a new instance into the set and calling saveOrUpdate(account) persists everything lovely. If I then choose to remove the contact from the list and again call saveOrUpdate, the SQL Hibernate seems to produce involves setting the account_id column to null, which violates a database constraint. What am I doing wrong? The code below is clearly a simplified abstract but I think it covers the problem as I'm seeing the same results in different code, which really is about this simple. SQL: CREATE TABLE account ( INT account_id ); CREATE TABLE contact ( INT contact_id, INT account_id REFERENCES account (account_id) ); Java: @Entity class Account { @Id @Column public Long id; @OneToMany(cascade = CascadeType.ALL, orphanRemoval = true) @JoinColumn(name = "account_id") public List<Contact> contacts; } @Entity class Contact { @Id @Column public Long id; @ManyToOne(optional = false) @JoinColumn(name = "account_id", nullable = false) public Account account; } Account account = new Account(); Contact contact = new Contact(); account.contacts.add(contact); saveOrUpdate(account); // some time later, like another servlet request.... account.contacts.remove(contact); saveOrUpdate(account); Result: UPDATE contact SET account_id = null WHERE contact_id = ? Edit #1: It might be that this is actually a bug http://opensource.atlassian.com/projects/hibernate/browse/HHH-5091

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• How do I display two different objects in a search?

  - by JZ

  github url I am using a simple search that displays search results: @adds = Add.search(params[:search]) In addition to the search results I'm trying to utilize a method, nearbys(), which displays objects that are close in proximity to the search result. The following method displays objects which are close to 2, but it does not display object 2. How do I display object 2 in conjunction with the nearby objects? @adds = Add.find(2).nearbys(10) While the above code functions, when I use search, @adds = Add.search(params[:search]).nearbys(10) a no method error is returned, undefined methodnearbys' for Array:0x30c3278` How can I search the model for an object AND use the nearbys() method AND display all results returned? Model: def self.search(search) if search find(:all, :conditions => ['address LIKE ?', "%#{search}%"]) # where('address LIKE ?', "%#{search}") else find(:all) end end

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• can i use javabeans with hibernate ?

  - by Dilllllo

  Hello i'm using a plugin of hibernate2 in my webproject with jsp ,in my project i have a register page. Can i use javabeans to send information from a html <form> using hibernate class's ? with out hibernate i creat class with get and set like that package com.java2s; public class Lang { private String choix; private String comm; public String getChoix() { return choix; } public void setChoix(String choix) { this.choix = choix; //System.out.println(choix); } public String getComm() { return comm; } public void setComm(String comm) { this.comm = comm; // System.out.println(comm); } } but i know that hibernate generate a get and set class ! and recive it with that : <jsp:useBean id='user' class='com.java2s.Lang' type='com.java2s.Lang' scope='session' /> <jsp:setProperty name='user' property='*'/> any idea how to do that ?

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• How to prevent Hibernate from nullifying relationship column during entity removal

  - by Grzegorz

  I have two entities, A and B. I need to easily retrieve entities A, joined with entities B on the condition of equal values of some column (some column from A equal to some column in B). Those columns are not primary or foreign keys, they contain same business data. I just need to have access from each instance of A to the collection of B's with the same value of this column. So I model it like this: class A { @OneToMany @JoinColumn(name="column_in_B", referencedColumnName="column_in_A") Collection<B> bs; This way, I can run queries like "select A join fetch a.bs b where b...." (Actually, the real relationship here is many-to-many. But when I use @ManyToMany, Hibernate forces me to use join table, which doesnt exist here. So I have to use @OneToMany as workaround). So far so good. The main problem is: whenever I delete an instance of A, hibernate calls "Update B set column_in_B = null", becuase it thinks the column_in_B is foreign key pointing at primary key in A (and because row in A is deleted, it tries to clean the foreign key in B). BUT the column_in_B IS NOT a foreign key, and can't be modified, because it causes data lost (and this column is NOT NULL anyway in my case, causing data integerity exception to be thrown). Plese help me with this. How to model such relationships with Hibernate? (I would call it "virtual relationships", or "secondary relationships" or so: as they are not based on foreign keys, they are just some shortcuts which allows for retrieving related objects and quering for them with HQL)

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• Applying the Hibernate filter attribute to a Bag with a many-to-many relationship

  - by David P

  Consider the following Hibernate mapping file: <hibernate-mapping ...> <class name="ContentPackage" table="contentPackages"> <id name="Id" column="id" type="int"><generator class="native" /></id> ... <bag name="Clips" table="contentAudVidLinks"> <key column="fk_contentPackageId"></key> <many-to-many class="Clip" column="fk_AudVidId"></many-to-many> <filter name="effectiveDate" condition=":asOfDate BETWEEN startDate and endDate" /> </bag> </class> </hibernate-mapping> When I run the following command: _session.EnableFilter("effectiveDate").SetParameter("asOfDate", DateTime.Today); IList<ContentPackage> items = _session.CreateCriteria(typeof(ContentPackage)) .Add(Restrictions.Eq("Id", id)) .List<ContentPackage>(); The resulting SQL has the WHERE clause on the intermediate mapping table (contentAudVidLinks), rather than the "Clips" table even though I have added the filter attribute to the Bag of Clips. What am I doing wrong?

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• Eager loading OneToMany in Hibernate with JPA2

  - by pihentagy

  I have a simple @OneToMany between Person and Pet entities: @OneToMany(mappedBy="owner", cascade=CascadeType.ALL, fetch=FetchType.EAGER) public Set<Pet> getPets() { return pets; } I would like to load all Persons with associated Pets. So I came up with this (inside a test class): @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration public class AppTest { @Test @Rollback(false) @Transactional(readOnly = false) public void testApp() { CriteriaBuilder qb = em.getCriteriaBuilder(); CriteriaQuery<Person> c = qb.createQuery(Person.class); Root<Person> p1 = c.from(Person.class); SetJoin<Person, Pet> join = p1.join(Person_.pets); TypedQuery<Person> q = em.createQuery(c); List<Person> persons = q.getResultList(); for (Person p : persons) { System.out.println(p.getName()); for (Pet pet : p.getPets()) { System.out.println("\t" + pet.getNick()); } } However, turning the SQL logging on shows, that it executes 3 queries (having 2 Persons in the DB). Hibernate: select person0_.id as id0_, person0_.name as name0_, person0_.sex as sex0_ from Person person0_ inner join Pet pets1_ on person0_.id=pets1_.owner_id Hibernate: select pets0_.owner_id as owner3_0_1_, pets0_.id as id1_, pets0_.id as id1_0_, pets0_.nick as nick1_0_, pets0_.owner_id as owner3_1_0_ from Pet pets0_ where pets0_.owner_id=? Hibernate: select pets0_.owner_id as owner3_0_1_, pets0_.id as id1_, pets0_.id as id1_0_, pets0_.nick as nick1_0_, pets0_.owner_id as owner3_1_0_ from Pet pets0_ where pets0_.owner_id=? Any tips? Thanks Gergo

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• Escaping colons in hibernate createSQLQuery

  - by Stratosgear

  I am confused on how I can create an SQL statement containing colons. I am trying to create a view and I am using (notice the double colons): create view MyView as ( SELECT tableA.colA as colA, tableB.colB as colB, round(tableB.colD / 1024)::numeric, 2) as calcValue, FROM tableA, tableB WHERE tableA.colC = 'someValue' ); This is a postgres query and I am forced to use the double colons (::) in order to correctly run the statement. I then pass the above statement through: s.createSQLQuery(myQuery).executeUpdate(); and I get a: Exception in thread "main" org.hibernate.exception.DataException: \ could not execute native bulk manipulation query at org.hibernate.exception.SQLStateConverter.convert(\ SQLStateConverter.java:102) ... more stacktrace... with an output of my above statement changed as (notice the question mark): create view MyView as ( SELECT tableA.colA as colA, tableB.colB as colB, round(tableB.colD / 1024)?, 2) as calcValue, FROM tableA, tableB WHERE tableA.colC = 'someValue' ); Obviously, hibernate confuses my colons with named parameters. Is there a way to escape the colons (a google suggestion that mentions that a single colon is escaped as a double colon does NOT work) or another way of running this statement? Thanks.

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• Avoiding secondary selects or joins with Hibernate Criteria or HQL query

  - by Ben Benson

  I am having trouble optimizing Hibernate queries to avoid performing joins or secondary selects. When a Hibernate query is performed (criteria or hql), such as the following: return getSession().createQuery(("from GiftCard as card where card.recipientNotificationRequested=1").list(); ... and the where clause examines properties that do not require any joins with other tables... but Hibernate still performs a full join with other tables (or secondary selects depending on how I set the fetchMode). The object in question (GiftCard) has a couple ManyToOne associations that I would prefer to be lazily loaded in this case (but not necessarily all cases). I want a solution that I can control what is lazily loaded when I perform the query. Here's what the GiftCard Entity looks like: @Entity @Table(name = "giftCards") public class GiftCard implements Serializable { private static final long serialVersionUID = 1L; private String id_; private User buyer_; private boolean isRecipientNotificationRequested_; @Id public String getId() { return this.id_; } public void setId(String id) { this.id_ = id; } @ManyToOne @JoinColumn(name = "buyerUserId") @NotFound(action = NotFoundAction.IGNORE) public User getBuyer() { return this.buyer_; } public void setBuyer(User buyer) { this.buyer_ = buyer; } @Column(name="isRecipientNotificationRequested", nullable=false, columnDefinition="tinyint") public boolean isRecipientNotificationRequested() { return this.isRecipientNotificationRequested_; } public void setRecipientNotificationRequested(boolean isRecipientNotificationRequested) { this.isRecipientNotificationRequested_ = isRecipientNotificationRequested; } }

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• Hibernate: Querying objects by attributes of inherited classes

  - by MichaelD

  Hi all, I ran into a problem with Hibernate concerning queries on classes which use inheritance. Basically I've the following class hierarchy: @Entity @Table( name = "recording" ) class Recording { ClassA attributeSet; ... } @Entity @Inheritance( strategy = InheritanceType.JOINED ) @Table( name = "classA" ) public class ClassA { String Id; ... } @Entity @Table( name = "ClassB1" ) @PrimaryKeyJoinColumn( name = "Id" ) public class ClassB1 extends ClassA { private Double P1300; private Double P2000; } @Entity @Table( name = "ClassB2" ) @PrimaryKeyJoinColumn( name = "Id" ) public class ClassB2 extends ClassA { private Double P1300; private Double P3000; } The hierarchy is already given like this and I cannot change it easily. As you can see ClassB1 and ClassB2 inherit from ClassA. Both classes contain a set of attributes which sometimes even have the same names (but I can't move them to ClassA since there are possible more sub-classes which do not use them). The Recording class references one instance of one of this classes. Now my question: What I want to do is selecting all Recording objects in my database which refer to an instance of either ClassB1 or ClassB2 with e.g. the field P1300 == 15.5 (so this could be ClassB1 or ClassB2 instances since the P1300 attribute is declared in both classes). What I tried is something like this: Criteria criteria = session.createCriteria(Recording.class); criteria.add( Restrictions.eq( "attributeSet.P1300", new Double(15.5) ) ); criteria.list(); But since P1300 is not an attribute of ClassA hibernate throws an exception telling me: could not resolve property: P1300 of: ClassA How can I tell hibernate that it should search in all subclasses to find the attribute I want to filter? Thanks MichaelD

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