Search Results

Search found 20224 results on 809 pages for 'query optimization'.

Page 30/809 | < Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >

  • Return segmented average from SQL Query?

    - by Guillaume Filion
    Hi, I measure the load on DNS servers every minute and store that into an SQL DB. I want to draw a chart of the load for the last 48 hours. That's 69120 (48*24*60) data points but my chart's only 800 pixels wide so to make things faster I would like my SQL query to return only ~800 data points. It's seems to me like a pretty standard thing to do, but I've been searching the web and in books for such a thing for a while now and the closest I was able to find was a rolling average. What I'm looking for a more of a "segmented average": divide the 69120 data points in ~800 segments, then average each segment. My SQL table is: CREATE TABLE measurements ( ip int, measurement_time int, queries int, query_time float ) My query looks like this SELECT ip, queries FROM measurements WHERE measurement_time>(time()-172800) Thanks a lot!

    Read the article

  • Mysql Query - Order By Not Working

    - by jwzk
    I'm running Mysql 5.0.77 and I'm pretty sure this query should work? SELECT * FROM purchases WHERE time_purchased BETWEEN '2010-04-15 00:00:00' AND '2010-04-18 23:59:59' ORDER BY time_purchased ASC, order_total DESC time_purchased is DATETIME, and an index. order_total is DECIMAL(10,2), and not an index. I want to order all purchases by the date (least to greatest), and then by the order total (greatest to least). So I would output similar to: 2010-04-15 $100 2010-04-15 $80 2010-04-15 $20 2010-04-16 $170 2010-04-16 $45 2010-04-16 $15 2010-04-17 $274 .. and so on. The output I am getting from that query has the dates in order correctly, but it doesn't appear to sort the order total column at all. Thoughts? Thanks.

    Read the article

  • one query instead of four - is it possible?

    - by Syom
    i must get data from four tables. i wrote the script with four queries, but i use it in ajax, and i wan't to do it by one query. here is queries... $query1 = "SELECT `id`,`name_ar` FROM `tour_type` ORDER BY `order`"; $query2 = "SELECT `id`,`name_ar` FROM `hotel_type` ORDER BY `order`"; $query3 = "SELECT `id`,`name_ar` FROM `food_type` ORDER BY `order`"; $query4 = "SELECT `id`,`name_ar` FROM `cities` WHERE `id_parrent` = '$id_parrent' ORDER BY `name_ar`"; is it possible to write in one query? thanks

    Read the article

  • SQL Query: Using IF statement in defining new field

    - by Tofig Hasanov
    I have a table with many fields and additionally several boolean fields (ex: BField1, BField2, BField3 etc.). I need to make a Select Query, which will select all fields except for boolean ones, and a new virtual field (ex: FirstTrueBool) whose value will equal to the name of the first TRUE Boolean Field. For ex: Say I have BField1 = False, BField2 = True, BField3 = true, BField4=false, in that case SQL Query should set [FirstTrueBool] to "BField2". Is that possible? Thank you in advance. P.S. I use Microsoft Access (MDB) Database and Jet Engine.

    Read the article

  • Hibernate Query - Get latest versions by timestamp?

    - by Slim
    I have a database that is being used as a sort of version control system. That is, instead of ever updating any rows, I add a new row with the same information. Each row also contains a version column that is a date timestamp, so the only difference is the new row will have a more recent timestamp. What I'm having trouble with is writing an efficient hibernate query to return the latest version of these rows. For the sake of example, these are rows in a table called Product, the timestamped column is version. There are multiple versions of multiple products in the table. So there may be multiple versions (rows) of ProductA, multiple versions of ProductB, etc. And I would like to grab the latest version of each. Can I do this in just a single hibernate query? session.createQuery("select product from Product product where...?"); Or would this require some intermediate steps?

    Read the article

  • SQL query problem

    - by Brisonela
    Hi, I'm new to StackOverflow, and new to SQL Server, I'd like you to help me with some troublesome query. This is my database structure(It's half spanish, hope doesn't matter) Database My problem is that I don't now how to make a query that states which team is local and which is visitor(using table TMatch, knowing that the stadium belongs to only one team) This is as far as I can get Select P.NroMatch, (select * from fnTeam (P.TeamA)) as TeamA,(select * from fnTeam (P.TeamB)) as TeamB, (select * from fnEstadium (P.CodEstadium)) as Estadium, (cast(P.GolesTeamA as varchar)) + '-' + (cast(P.GolesTeamA as varchar)) as Score, P.Fecha from TMatch P Using this functions: If object_id ('fnTeam','fn')is not null drop function fnTeam go create function fnTeam(@CodTeam varchar(5)) returns table return(Select Name from TTeam where CodTeam = @CodTeam) go select * from fnTeam ('Eq001') go ----**** If object_id ('fnEstadium','fn')is not null drop function fnEstadium go create function fnEstadium(@CodEstadium varchar(5)) returns table return(Select Name from TEstadium where CodEstadium = @CodEstadium) go I hope I'd explained myself well, and I thank you help in advance

    Read the article

  • SQL Query to select upcoming events with a start and end date

    - by Chris T
    I need to display upcoming events from a database. The problem is when I use the query I'm currently using any events with a start day that has passed will show up lower on the list of upcoming events regardless of the fact that they are current My table (yaml): columns: title: type: string(255) notnull: true default: Untitled Event start_time: type: time end_time: type: time start_day: type: date notnull: true end_day: type: date description: type: string(500) default: This event has no description category_id: integer My query (doctrine): $results = Doctrine_Query::create() ->from("sfEventItem e, e.Category c") ->select("e.title, e.start_day, e.description, e.category_id, e.slug") ->addSelect("c.title, c.slug") ->orderBy("e.start_day, e.start_time, e.title") ->limit(5) ->execute(array(), Doctrine_Core::HYDRATE_ARRAY); Basically I'd like any events that is currently going on (so if today is in between start_day and end_day) to be at the top of the list. How would I go about doing this if it's even possible? Raw sql queries are good answers too because they're pretty easy to turn into DQL.

    Read the article

  • mysql query takes 145 seconds

    - by suomee
    I have a a mysql db with myisam engine. Along with many other table I have this table "et" which has around 8137037 records. I have created indexes (individual index of column hname and pnum, it did not help much later created joint index of hname and pnum and it help execute within a second)such that queries like "select st from et where hname='name' and pnum='1' limit 1;" execute fast (with in a second) but the problem is I must execute this query "select st from et where hname='name' and pnum='1' order by id limit 1" where id is the primary key of the table and this query sometimes take 145 seconds :( how can i resolve this issue?

    Read the article

  • PHP mySQL query's and PHP Variables

    - by jon
    I'm trying to make an OO Login system for a project I'm working on, and am having trouble with inserting variables into the query strings. In the code below, if I replace "$TBL_NAME" with the actual table name it works. Why isn't $TBL_NAME translating to the value of $TBL_NAME? class UserDB { private $TBL_NAME = "users"; public static function CheckLogin($username, $password) { Database::Connect(); $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT uid FROM $TBL_NAME WHERE username='$username' AND password='$password' "; $result =mysql_query($sql); $count=mysql_num_rows($result); if ($count==1) return true; else return false; } The Query is returning false.

    Read the article

  • MySql Query to return number of photos in each album

    - by GivenPie
    MY table is set up like this, all I need to do is call a query to my Photos table. I have PhotoID as the primary key and GalleryID as the foreign key to Gallery. How can I could the number of unique PhotoID's for each multiple GalleryIDs. So to speak there are may duplicate GalleryIDs because there are many photos in a gallery. So I just need to could the number of unique PhotoIDs associated with that GalleryID. Can it be done in one query?

    Read the article

  • Help optimizing a query with 16 subqueries

    - by Webnet
    I have indexes/primaries on all appropriate ID fields for each type. I'm wondering though how I could make this more efficient. It takes a while to load the page with only 15,000 rows and that'll quickly grow to 500k. The $whereSql variable simply has a few more parameters for the main ebay_archive_listing table. NOTE: This is all done in a single query because I have ASC/DESC sorting for each subquery value. NOTE: I've converted some of the sub queries to INNER JOIN's SELECT product_master.product_id, ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id) as listing_count, sku, type_id, ( SELECT AVG(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as average_bid_price, ( SELECT AVG(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.buy_it_now_price > 0 ) as average_buyout_price, ( SELECT MIN(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_bid_price, ( SELECT MAX(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_bid_price, ( SELECT MIN(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_buyout_price, ( SELECT MAX(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_buyout_price, round((( SELECT COUNT(ebay_archive_listing.id) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.status_id = 2 ) / ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id ) * 100), 1) as sold_percent FROM product_master '.$joinSql.' WHERE product_master.product_id IN ( SELECT product_id FROM ebay_archive_product_listing_assoc INNER JOIN ebay_archive_listing ON ( ebay_archive_listing.id = ebay_archive_product_listing_assoc.listing_id AND '.$whereSql.' ) )

    Read the article

  • SQL SERVER – Introduction to PERCENT_RANK() – Analytic Functions Introduced in SQL Server 2012

    - by pinaldave
    SQL Server 2012 introduces new analytical functions PERCENT_RANK(). This function returns relative standing of a value within a query result set or partition. It will be very difficult to explain this in words so I’d like to attempt to explain its function through a brief example. Instead of creating a new table, I will be using the AdventureWorks sample database as most developers use that for experiment purposes. Now let’s have fun following query: USE AdventureWorks GO SELECT SalesOrderID, OrderQty, RANK() OVER(ORDER BY SalesOrderID) Rnk, PERCENT_RANK() OVER(ORDER BY SalesOrderID) AS PctDist FROM Sales.SalesOrderDetail WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY PctDist DESC GO The above query will give us the following result: Now let us understand the resultset. You will notice that I have also included the RANK() function along with this query. The reason to include RANK() function was as this query is infect uses RANK function and find the relative standing of the query. The formula to find PERCENT_RANK() is as following: PERCENT_RANK() = (RANK() – 1) / (Total Rows – 1) If you want to read more about this function read here. Now let us attempt the same example with PARTITION BY clause USE AdventureWorks GO SELECT SalesOrderID, OrderQty, ProductID, RANK() OVER(PARTITION BY SalesOrderID ORDER BY ProductID ) Rnk, PERCENT_RANK() OVER(PARTITION BY SalesOrderID ORDER BY ProductID ) AS PctDist FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY PctDist DESC GO Now you will notice that the same logic is followed in follow result set. I have now quick question to you – how many of you know the logic/formula of PERCENT_RANK() before this blog post? Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Running & Managing Concurrent Queries in SQL Developer

    - by thatjeffsmith
    We’ve all been there – you’ve managed to write a query that takes longer than a few seconds to execute. Tuning aside, sometimes it takes longer than you want for a query to run. So what’s a SQL Developer user to do? I say, keep going! While you’re waiting for your query to finish, there’s no reason why you can’t continue on with your work. If you need to execute something else in a worksheet, there’s no reason to launch a 2nd or 3rd copy of SQL Developer. Just open an un-shared worksheet. Now while you’ve got 1 or more queries running, you can easily get yourself into a situation where you’re not sure what’s running where. Or maybe you want to cancel a query or just check how long something’s been running. Just open the Task Progress Panel If a query or task in SQL Developer takes more than 3-5 seconds, it will appear in the Task Progress panel. You can then watch the throbbers go back and forth while you sip your coffee/soda/Red Bull. Run a query, spawn a new worksheet, run another query, watch them in the Task Progress panel. Kudos and thanks to @leight0nn for helping me get the title of this post right If you’re looking for help in managing and monitoring sessions in general, check out this post.

    Read the article

  • LAMP server has gone down a few times. Ideas for server optimization?

    - by MattB
    Hi all, Our production web server has gone down a few times over the course of the last half year. In the end, we've needed to contact the web host and have them restart as I'm unable to even SSH in. This appears to only affect the web server and not the MySQL database server which is separate. When it affects the web server, all hosted websites time out. I'd like to examine web server optimization/corrections to get to the root of this issue. Any recommendations on how to proceed with that? I'm sure log files would play a role. I'm able to find my way around a Linux-based server and make needed changes, but would be interested in any tips I may not have thought of yet. It may be best for us to speak with an outside consultant as another option. Thanks.

    Read the article

  • How Web Optimization Services Work to Increase Your on the Internet Reputation

    SEO is a symbol of search engine optimization and that is the key to success from the enterprise. No site has meaning if it seriously isn't properly promoted. Anytime any web surfer is in look up of any certain merchandise, providers or data he makes use of the easiest method of browsing as a result of search engine optimization and this is habit of many individuals to only search straight into 5 or six major sites for their goal. No person has time to seem directly into 100 pages of internet search engine as there is no need to have when he finds in major pages.

    Read the article

  • Web optimization

    - by hmloo
    1. CSS Optimization Organize your CSS code Good CSS organization helps with future maintainability of the site, it helps you and your team member understand the CSS more quickly and jump to specific styles. Structure CSS code For small project, you can break your CSS code in separate blocks according to the structure of the page or page content. for example you can break your CSS document according the content of your web page(e.g. Header, Main Content, Footer) Structure CSS file For large project, you may feel having too much CSS code in one place, so it's the best to structure your CSS into more CSS files, and use a master style sheet to import these style sheets. this solution can not only organize style structure, but also reduce server request./*--------------Master style sheet--------------*/ @import "Reset.css"; @import "Structure.css"; @import "Typography.css"; @import "Forms.css"; Create index for your CSS Another important thing is to create index at the beginning of your CSS file, index can help you quickly understand the whole CSS structure./*---------------------------------------- 1. Header 2. Navigation 3. Main Content 4. Sidebar 5. Footer ------------------------------------------*/ Writing efficient CSS selectors keep in mind that browsers match CSS selectors from right to left and the order of efficiency for selectors 1. id (#myid) 2. class (.myclass) 3. tag (div, h1, p) 4. adjacent sibling (h1 + p) 5. child (ul > li) 6. descendent (li a) 7. universal (*) 8. attribute (a[rel="external"]) 9. pseudo-class and pseudo element (a:hover, li:first) the rightmost selector is called "key selector", so when you write your CSS code, you should choose more efficient key selector. Here are some best practice: Don't tag-qualify Never do this:div#myid div.myclass .myclass#myid IDs are unique, classes are more unique than a tag so they don't need a tag. Doing so makes the selector less efficient. Avoid overqualifying selectors for example#nav a is more efficient thanul#nav li a Don't repeat declarationExample: body {font-size:12px;}h1 {font-size:12px;font-weight:bold;} since h1 is already inherited from body, so you don't need to repeate atrribute. Using 0 instead of 0px Always using #selector { margin: 0; } There’s no need to include the px after 0, removing all those superfluous px can reduce the size of your CSS file. Group declaration Example: h1 { font-size: 16pt; } h1 { color: #fff; } h1 { font-family: Arial, sans-serif; } it’s much better to combine them:h1 { font-size: 16pt; color: #fff; font-family: Arial, sans-serif; } Group selectorsExample: h1 { color: #fff; font-family: Arial, sans-serif; } h2 { color: #fff; font-family: Arial, sans-serif; } it would be much better if setup as:h1, h2 { color: #fff; font-family: Arial, sans-serif; } Group attributeExample: h1 { color: #fff; font-family: Arial, sans-serif; } h2 { color: #fff; font-family: Arial, sans-serif; font-size: 16pt; } you can set different rules for specific elements after setting a rule for a grouph1, h2 { color: #fff; font-family: Arial, sans-serif; } h2 { font-size: 16pt; } Using Shorthand PropertiesExample: #selector { margin-top: 8px; margin-right: 4px; margin-bottom: 8px; margin-left: 4px; }Better: #selector { margin: 8px 4px 8px 4px; }Best: #selector { margin: 8px 4px; } a good diagram illustrated how shorthand declarations are interpreted depending on how many values are specified for margin and padding property. instead of using:#selector { background-image: url(”logo.png”); background-position: top left; background-repeat: no-repeat; } is used:#selector { background: url(logo.png) no-repeat top left; } 2. Image Optimization Image Optimizer Image Optimizer is a free Visual Studio2010 extension that optimizes PNG, GIF and JPG file sizes without quality loss. It uses SmushIt and PunyPNG for the optimization. Just right click on any folder or images in Solution Explorer and choose optimize images, then it will automatically optimize all PNG, GIF and JPEG files in that folder. CSS Image Sprites CSS Image Sprites are a way to combine a collection of images to a single image, then use CSS background-position property to shift the visible area to show the required image, many images can take a long time to load and generates multiple server requests, so Image Sprite can reduce the number of server requests and improve site performance. You can use many online tools to generate your image sprite and CSS, and you can also try the Sprite and Image Optimization framework released by The ASP.NET team.

    Read the article

  • Math behind multivariate testing for website optimization

    - by corkjack
    I am looking for theoretical resources (books, tutorials, etc.) to learn about making sound statistical inferences given (plenty of) multivariate website conversion data. I'm after the math involved, and cannot find any good non-marketing stuff on the web. The sort of questions I want to answer: how much impact does a single variable (e.g. color of text) have? what is the correlation between variables? what type of distribution is used for modelling (Gaussian, Binomial, etc.)? When using statistics to analyze results - what should be considered as a random variable - the web-page element that gets different variations or the binary conversion-or-no-conversion outcome of an impression? There's plenty of information about different website optimization testing methods and their benefits\pitfalls, plenty of information about multivariate statistics in general, do you guys know of resources that discuss statistics in this specific context of website optimization ? Thanks for any info!

    Read the article

  • What is Search Engine Optimization?

    SEO stands for search engine optimization involves running and managing a web site or webpage on a given search engine so as to gain more results and make more and more people visit the web site or the web page. The wanted amount of people can be captured by putting up and highlighting the right keywords on your website so as get maximum hits on your website and to make your website rise higher in the list of the search engine. The more your web site is optimized, you get a phenomenal response and the number of hits on your website or webpage increase. Search engine optimization can be carried out in number of different ways.

    Read the article

  • The Schema returned by the new query differ from the base query

    - by sochandara
    I am working on class project which required to work with Windows Application and this issue occurred to me that i don understand how to solved it can anybody help please? I want to show the NATIONALITYNAME instead of showing NATIONALITYID in the grid view SELECT COACH.COACHID, COACH.COACHFIRSTNAME, COACH.COACHLASTNAME, NATIONALITY.NATIONALITY FROM COACH INNER JOIN NATIONALITY ON COACH.NATIONALITYID = NATIONALITY.NATIONALITYID Error Message: "The Schema returned by the new query differ from the base query"![alt text][1]

    Read the article

< Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >