Search Results

Search found 3825 results on 153 pages for 'regex negation'.

Page 30/153 | < Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >

  • Extract known pattern substring from NSString (without regex)

    - by d11wtq
    I'm really tempted to drop RegexKit (or my own libpcre wrapper) into my project in order to do this, but before I do that I want to know how Cocoa developers manage to do half of this basic stuff without really convoluted code or without linking with RegexKit or another regular expression library. I find it gobsmacking that Cocoa does not include any regular expression matching features. I've so accustomed to using regular expressions for all kinds of things that I'm lost without them. I can do what I need without them, but the code would be rather convoluted. So, Cocoa devs, I ask you, what's the "Cocoa way" to do this... The problem is an everyday problem in programming as far as I'm concerned. Cocoa must have ways of doing this with the built-in features. Note that the position of the elements I want to match changes, and sometimes "quotes" are present. Whitespace is variable. Take the following strings: Content-Type: application/xml; charset=utf-8 Content-Type: text/html; charset="iso-8859-1" Content-Type: text/plain; charset=us-ascii Content-Type: text/plain; name="example.txt"; charset=utf-8 From all of these strings, how would you go about determining the mime type (e.g. text/plain) and the charset (e.g. utf-8) using just the built-in Cocoa classes? I'd end up performing a series of -rangeOfString: and substring calls, with conditional checks to deal with the optional quotes etc. Is there a way to do this with NSScanner? The NSScanner class seems to have a pretty naive API to me. Something like C's sscanf() that works for NSString objects would be an ideal fit. Most of my string parsing needs are simple such as this example so maybe regular expressions, while I'm accustomed to them, are overkill?

    Read the article

  • parsing string according to oracle operators with regex

    - by haluk
    Hi, Basically I was trying to replace the part of string with its actual value which comes immediately after oracle operators. I can do this for limited operators list like {=,,<} but I wonder that is there any way out to gather all the operators rather than giving them by hands? For instance, I have this string; "a = xyz", then I will replace xyz with lets say 3. But as you know we have bunch of operator namely "like,in,exists etc". So my string can also be this: "a like xyz". So what do you suggest me? Thanks.

    Read the article

  • Regex to extract this semi formatted data

    - by Codygman
    Alright, I can't quite figure out how to do this. Given the following text: Roland AX-1: /start Roland's AX-1 strap-on remote MIDI controller has a very impressive 45-note velocity sensitive keyboard, and has switchable velocity curves, goes octave up/down, transpose, split/layering zones, and has fun tempo control for sequencers and more. Roland's AX-1 comes with a built-in GS control for total MIDI control of GM/GS synths. Its "Expression Bar" can control pitch and mod via an almost ribbon-like controller. It's also the newest and most advanced remote controller for your synths or midi modules. /end Roland AX-7: /start Roland's AX-7 builds on the infamous Roland AX-1 design. You just strap it on and put it to the front of the stage. Offering several controllers, such as: a D-Beam, then you can open the door to amazing live performance. 7-segment LED display, larger patch memory (Around 128 patches with MIDI data backup), and comes with GM2/GS compatibility make it extra easy to use. The 45-note, velocity-sensitive keyboard. 5 realtime controllers including a data entry knob, touch controller knob, opression bar, a hold button, and D-Beam. 128 patches with MIDI data backup. 2 MIDI zones. /end I'm trying to use the following: /^([\w\d \-]*):\s\s\s\s^\/start([^\:]*)\/end$/im You can see on rubular here: http://rubular.com/r/BVRRHsnWdp Thanks for any help. I guess i'm trying to match blocks of text until I hit the next title which always ends with a :$

    Read the article

  • Regex to repeat a capture across a CDL?

    - by richardtallent
    I have some data in this form: @"Managers Alice, Bob, Charlie Supervisors Don, Edward, Francis" I need a flat output like this: @"Managers Alice Managers Bob Managers Charlie Supervisors Don Supervisors Edward Supervisors Francis" The actual "job title" above could be any single word, there's no discrete list to work from. Replacing the ,  with \r\n is easy enough, as is the first replacement: Replace (^|\r\n)(\S+\s)([^,\r\n]*),\s With $1$2$3\r\n$2 But capturing the other names and applying the same prefix is what is eluding me today. Any suggestions?

    Read the article

  • Regex not equal to string

    - by Kieron
    Hi, I'm banging my head against a wall with a regular expression. I'm trying to define an expression that excludes exactly this text 'System' (case insensitive), but can contain the word 'System' providing it's not just that. Examples: System == INVALID SYSTEM == INVALID system == INVALID syStEm == INVALID asd SysTem == Valid asd System asd == Valid System asd == Valid asd System == Valid asd == Valid

    Read the article

  • Java Regex Matcher Question

    - by Yang
    How do I match an URL string like this: img src = "http://stackoverflow.com/a/b/c/d/someimage.jpg" where only the domain name and the file extension (jpg) is fixed while others are variables? The following code does not seem working: Pattern p = Pattern.compile("<img src=\"http://stachoverflow.com/.*jpg"); // Create a matcher with an input string Matcher m = p.matcher(url); while (m.find()) { String s = m.toString(); }

    Read the article

  • Using regex to fix phone numbers in a CSV with PHP

    - by Hurpe
    My new phone does not recognize a phone number unless it's area code matches the incoming call. Since I live in Idaho where an area code is not needed for in-state calls, many of my contacts were saved without an area code. Since I have thousands of contacts stored in my phone, it would not be practical to manually update them. I decided to write the following PHP script to handle the problem. It seems to work well, except that I'm finding duplicate area codes at the beginning of random contacts. <?php //the script can take a while to complete set_time_limit(200); function validate_area_code($number) { //digits are taken one by one out of $number, and insert in to $numString $numString = ""; for ($i = 0; $i < strlen($number); $i++) { $curr = substr($number,$i,1); //only copy from $number to $numString when the character is numeric if (is_numeric($curr)) { $numString = $numString . $curr; } } //add area code "208" to the beginning of any phone number of length 7 if (strlen($numString) == 7) { return "208" . $numString; //remove country code (none of the contacts are outside the U.S.) } else if (strlen($numString) == 11) { return preg_replace("/^1/","",$numString); } else { return $numString; } } //matches any phone number in the csv $pattern = "/((1? ?\(?[2-9]\d\d\)? *)? ?\d\d\d-?\d\d\d\d)/"; $csv = file_get_contents("contacts2.CSV"); preg_match_all($pattern,$csv,$matches); foreach ($matches[0] as $key1 => $value) { /*create a pattern that matches the specific phone number by adding slashes before possible special characters*/ $pattern = preg_replace("/\(|\)|\-/","\\\\$0",$value); //create the replacement phone number $replacement = validate_area_code($value); //add delimeters $pattern = "/" . $pattern . "/"; $csv = preg_replace($pattern,$replacement,$csv); } echo $csv; ?> Is there a better approach to modifying the csv? Also, is there a way to minimize the number of passes over the csv? In the script above, preg_replace is called thousands of times on a very large String.

    Read the article

  • Java doesn't work with regex \s, says: invalid escape sequence

    - by Jayomat
    hi, I want to replace all whitespace characters in a string with a "+" and all "ß" with "ss"... it works well for "ß", but somehow eclipse won't let me use \s for a whitespace.. I tried "\t" instead, but it doesn't work either.. I get the following error: Invalid escape sequence (valid ones are \b \t \n \f \r \" \' \ ) this is my code: try { String temp1 = from.getText().toString(); start_from = temp1.replaceAll("ß", "ss"); start_from = start_from.replaceAll("\s", "+"); } why doesn't it work? is it a problem with android, eclipse or what? thanks in advance!

    Read the article

  • Regex: Search and replace left side = to right side

    - by ctrlShiftBryan
    How do I use regular expressions and search and replace to turn this [UserID] = <UserID, int,> [UserID] = 123123 [UserID] = asd123123 into [UserID] = [UserID] [UserID] = [UserID] [UserID] = [UserID] In other words I want to take everything from left side of the line up to the '=' character and replace everything on the right side of the '=' with the match from the left side. We can assume a line break at the end of each line. What are my Find what: and Replace with: values?

    Read the article

  • Simple regex question?

    - by Joan Venge
    In the streams I am parsing I need to parse something in this pattern: <b>PaintTitle</b></td><td class=detail valign="top" align=left><div align=left><font size=small><b>The new great album by Pet Shop Boys</b> How would I get the string "The new great album by Pet Shop Boys" where <b>PaintTitle</b> is guaranteed to be once per album?

    Read the article

  • javascript RegEx hashtag matching #foo and #foo-fåäö but not http://this.is/no#hashtag

    - by Simon B.
    Currently we're using javascript new RegExp('#[^,#=!\s][^,#=!\s]*') (see [1]) and it mostly works, except that it also matches URLs with anchors like http://this.is/no#hashtag and also we'd rather avoid matching foo#bar Some attempts have been made with look-ahead but it doesn't seem to work, or that I just don't get it. With the below source text: #public #writable #kommentarer-till-beta -- all these should be matched Verkligen #bra jobbat! T ex #kommentarer till #artiklar och #blogginlägg, kool. -- mixed within text http://this.is/no#hashtag -- problem xxy#bar -- We'd prefer not matching this one, and... #foo=bar =foo#bar -- we probably shouldn't match any of those either. #foo,bar #foo;bar #foo-bar #foo:bar -- We're flexible on whether these get matched in part or in full . We'd like to get below output: (showing $ instead of <a class=tag href=.....>...</a> for readability reasons) $ $ $ -- all these should be matched Verkligen $ jobbat! T ex $ till $ och $, kool. -- mixed within text http://this.is/no$ -- problem xxy$ -- We'd prefer not matching this one, and... $=bar =foo$ -- we probably shouldn't match any of those either. $,bar $ $ $ -- We're flexible on whether these get matched in part or in full [1] http://github.com/ether/pad/blob/master/etherpad/src/plugins/twitterStyleTags/hooks.js

    Read the article

  • How to use regex to match ASTERISK in awk

    - by Ken Chen
    I'm stil pretty new to regular expression and just started learning to use awk. What I am trying to accomplish is writing a ksh script to read-in lines from text, and and for every lines that match the following: *RECORD 0000001 [some_serial_#] to replace $2 (i.e. 000001) with a different number. So essentially the script read in batch record dump, and replace the record number with date+record#, and write to separate file. So this is what I'm thinking the format should be: awk 'match($0,"/*FTR")!=0{$2="$DATE-n++"; print $0} match($0,"/*FTR")==0{print $0}' $BATCH > $OUTPUT but obviously "/*FTR" is not going to work, and I'm not sure if changing $2 and then write the whole line is the correct way to do this. So I am in need of some serious enlightenment.

    Read the article

  • javascript regex: match altered version of first match with only one expression

    - by theseion
    Hi there I'm writing a brush for Alex Gorbatchev's Syntax Highlighter to get highlighting for Smalltalk code. Now, consider the following Smalltalk code: aCollection do: [ :each | each shout ] I want to find the block argument ":each" and then match "each" every time it occurrs afterwards (for simplicity, let's say every occurrence an not just inside the brackets). Note that the argument can have any name, e.g. ":myArg". My attempt to match ":each": \:([\d\w]+) This seems to work. The problem is for me to match the occurrences of "each". I thought something like this could work: \:([\d\w]+)|\1 but the right hand side of the alternation seems to be treated as an independent expression, so backreferencing doesn't work. So my question is: is it even possible to accomplish what I want in a single expression? Or would I have to use the backreference within a second expression (via another function call)? Cheers.

    Read the article

  • Perl regex matching output from `w -hs` command

    - by Bushman
    I'm trying to write a Perl script that will work better with KDE's kwrited, which, as far as I can tell, is connected to a pts and puts every line it receives through the KDE system tray notifications, with the title "KDE write daemon". Unfortunately, it makes a separate notification for each and every line, so it spams up the system tray with multiline messages on regular old write, and for some reason it cuts off the entire last line of the message when using wall (One-line messages are also goners.). I was also hoping to make it so that it could broadcast across a LAN with thick clients. Before starting on that (which would require ssh, of course), I tried to make an ssh-less version to make sure it works. Unfortunately, it doesn't. perl ./write.pl "Testing 1 2 3" where the following is the contents of ./write.pl: #!/usr/bin/perl use strict; use warnings; my $message = ""; my $device = ""; my $possibledevice = '`w -hs | grep "/usr/bin/kwrited"`'; #Where is kwrited? $possibledevice =~ s/^[^\t][\t]//; $possibledevice =~ s/[\t][^\t][\t ]\/usr\/bin\/kwrited$//; $possibledevice = '/dev/'.$possibledevice; unless ($possibledevice eq "") { $device = $possibledevice; } if ($ARGV[0] ne "") { $message = $ARGV[0]; $device = $ARGV[1]; } else { $device = $ARGV[0] unless $ARGV[0] eq ""; while (<STDIN>) { chomp; $message .= <STDIN>; } } if ($message ne "") { system "echo \'$message\' > $device"; } else { print "Error: empty message" } produces the following error: $ perl write.pl "Testing 1 2 3" Use of uninitialized value $device in concatenation (.) or string at write.pl line 29. sh: -c: line 0: syntax error near unexpected token `newline' sh: -c: line 0: `echo 'foo' > ' Somehow, the regular expressions and/or the backtick escape in processing $possibledevice are not working properly, because where kwrited is connected to /dev/pts/0, the following works perfectly: $ perl write.pl "Testing 1 2 3" /dev/pts/0

    Read the article

  • regex , php, preg_match

    - by Michael
    I'm trying to extract the mileage value from different ebay pages but I'm stuck as there seem to be too many patterns because the pages are a bit different . Therefore I would like to know if you can help me with a better pattern . Some examples of items are the following : http://cgi.ebay.com/ebaymotors/1971-Chevy-C10-Shortbed-Truck-/250647101696?cmd=ViewItem&pt=US_Cars_Trucks&hash=item3a5bbb4100 http://cgi.ebay.com/ebaymotors/1987-HANDICAP-LEISURE-VAN-W-WHEEL-CHAIR-LIFT-/250647101712?cmd=ViewItem&pt=US_Cars_Trucks&hash=item3a5bbb4110 http://cgi.ebay.com/ebaymotors/ws/eBayISAPI.dll?ViewItemNext&item=250647101696 Please see the patterns at the following link (I still cannot figure it out how to escape the html here http://pastebin.com/zk4HAY3T However they are not enough many as it seems there are still new patters....

    Read the article

  • Fuzzy Regex, Text Processing, Lexical Analysis?

    - by justinzane
    I'm not quite sure what terminology to search for, so my title is funky... Here is the workflow I've got: Semi-structured documents are scanned to file. The files are OCR'd to text. The text is parsed into Python objects The objects are serialized (to SQL, JSON, whatever) for use. The documents are structures like this: HEADER blah blah, Page ### blah Garbage text... 1. Question Text... continued until now. A. Choice text... adsadsf. B. Another Choice... 2. Another Question... I need to extract the questions and choices. The problem is that, because the text is OCR output, there are occasional strange substitutions like '2' - 'Z' which makes ordinary regular expressions useless. I've tried the Levenshtein module and it helps, but it requires prior knowledge of what edit distance is to be expected. I don't know whether I'm looking to create a parser? a lexer? something else? This has lead me down all kinds of interesting but nonrelevant paths. Guidance would be greatly appreciated. Oh, also, the text is generally from specific technical domains, so general spelling tools are not so helpful. Regarding the structure of the documents, there is no clear visual pattern -- like line breaks or indentation -- with the exception of the fact that "questions" usually begin a line. Crap on the document can cause characters to appear before the actual beginning of the line, which means that something along the lines of r'^[0-9]+' does not reliably work. Though the "questions" always begin with an int, a period and a space; the OCR can substitute other characters or skip characters. This is not so much a problem with Tesseract or Cunieform, rather with the poor quality of the paper documents. # Note: for the project in question, it was decided that having a human prep the OCR'd text was better that spending the time coding a solution. I'd still love good pointers, however.

    Read the article

  • sed regex to match ['', 'WR' or 'RN'] + 2-4 digits

    - by Karl
    Hi I'm trying to do some conditional text processing on Unix and struggling with the syntax. I want to acheive Find the first 2, 3 or 4 digits in the string if 2 characters before the found digits are 'WR' (could also be lower case) Variable = the string we've found (e.g. WR1234) Type = "work request" else if 2 characters before the found digits are 'RN' (could also be lower case) Variable = the string we've found (e.g. RN1234) Type = "release note" else Variable = "WR" + the string we've found (Prepend 'WR' to the digits) Type = "Work request" fi fi I'm doing this in a Bash shell on Red Hat Enterprise Linux Server release 5.5 (Tikanga) Thanks in advance, Karl

    Read the article

  • RegEx - How To Insert String Before File Extension

    - by st4ck0v3rfl0w
    Hi All, How would I insert "_thumb" into files that are being dyanmically generated. For example, I have a site that allows users to upload an image. The script takes the image, optimizes it and saves to file. How would I make it insert the string "_thumb" for the optimized image? I'm currently saving 1 version of the otpimized file. ch-1268312613-photo.jpg I want to save the original as the above string, but want to append, "_thumb" like the following string ch-1268312613-photo_thumb.jpg

    Read the article

  • Modify jQuery Highlight? Javascript Regex

    - by Matrym
    How can I modify jquery highlight such that it doesn't find matches that appear directly before or after an alpha character? In other words, how do I prevent a match mid-word? /* highlight v3 Highlights arbitrary terms. <http://johannburkard.de/blog/programming/javascript/highlight-javascript-text-higlighting-jquery-plugin.html> MIT license. Johann Burkard <http://johannburkard.de> <mailto:[email protected]> */ jQuery.fn.highlight = function(pat) { function innerHighlight(node, pat) { var skip = 0; if (node.nodeType == 3) { var pos = node.data.toUpperCase().indexOf(pat); if (pos >= 0) { var spannode = document.createElement('span'); spannode.className = 'highlight'; var middlebit = node.splitText(pos); var endbit = middlebit.splitText(pat.length); var middleclone = middlebit.cloneNode(true); spannode.appendChild(middleclone); middlebit.parentNode.replaceChild(spannode, middlebit); skip = 1; } } else if (node.nodeType == 1 && node.childNodes && !/(script|style)/i.test(node.tagName)) { for (var i = 0; i < node.childNodes.length; ++i) { i += innerHighlight(node.childNodes[i], pat); } } return skip; } return this.each(function() { innerHighlight(this, pat.toUpperCase()); }); }; jQuery.fn.removeHighlight = function() { return this.find("span.highlight").each(function() { this.parentNode.firstChild.nodeName; with (this.parentNode) { replaceChild(this.firstChild, this); normalize(); } }).end(); };

    Read the article

  • Regex for finding an unterminated string

    - by Austin Hyde
    I need to search for lines in a CSV file that end in an unterminated, double-quoted string. For example: 1,2,a,b,"dog","rabbit would match whereas 1,2,a,b,"dog","rabbit","cat bird" 1,2,a,b,"dog",rabbit would not. I have very limited experience with regular expressions, and the only thing I could think of is something like "[^"]*$ However, that matches the last quote to the end of the line. How would this be done?

    Read the article

  • Scite Lua - escaping right bracket in regex?

    - by ~sd-imi
    Hi all, Bumped into a somewhat weird problem... I want to turn the string: a\left(b_{d}\right) into a \left( b_{d} \right) in Scite using a Lua script. So, I made the following Lua script for Scite: function SpaceTexEquations() editor:BeginUndoAction() local sel = editor:GetSelText() local cln3 = string.gsub(sel, "\\left(", " \\left( ") local cln4 = string.gsub(cln3, "\\right)", " \\right) ") editor:ReplaceSel(cln4) editor:EndUndoAction() end The cln3 line works fine, however, cln4 crashes with: /home/user/sciteLuaFunctions.lua:49: invalid pattern capture >Lua: error occurred while processing command I think this is because bracket characters () are reserved characters in Lua; but then, how come the cln3 line works without escaping? By the way I also tried: -- using backslash \ as escape char: local cln4 = string.gsub(cln3, "\\right\)", " \\right) ") -- crashes all the same -- using percentage sign % as escape chare local cln4 = string.gsub(cln3, "\\right%)", " \\right) ") -- does not crash, but does not match either Could anyone tell me what would be the correct way to do this? Thanks, Cheers!

    Read the article

  • Need to add $_GET args to my regex

    - by TaMeR
    url.rewrite-once = ( ".*\.(js|ico|gif|jpg|png|css|html)$" => "$0", "^/([^?]*)(\?.*)?$" => "/$1.php/$2", ) This is what I got but the args don't work. I like following url http://www.example.com/index.php/?r=something To look like this: http://www.example.com/index/?r=something Thanx

    Read the article

< Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >