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  • Passing JS variable from child Iframe to parent JSP on cross sub domain

    - by Tarun
    I am stuck at 1 location and need some help. I created two subdomains on apache tomcat server like domain1.localhost.com and domain2.localhost.com in server.xml. On domain1 I have a JSP that includes iFrame (hosted on domain2). How can we pass the JS variable from child Iframe to parent JSP and store it in local variable of JSP hosted on domain1.localhost.com? I tried defining document.domain = "localhost" on both JSP but didn't work. Even parent DOM window is also not available in child iFrame (on sub-domain) because of obvious cross domain policies. Any help would be highly appreciated.

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  • How to declare a variable that spans multiple lines

    - by Chris Wilson
    I'm attempting to initialise a string variable in C++, and the value is so long that it's going to exceed the 80 character per line limit I'm working to, so I'd like to split it to the next line, but I'm not sure how to do that. I know that when splitting the contents of a stream across multiple lines, the syntax goes like cout << "This is a string" << "This is another string"; Is there an equivalent for variable assignment, or do I have to declare multiple variables and concatenate them? Edit: I misspoke when I wrote the initial question. When I say 'next line', I'm just meaning the next line of the script. When it is printed upon execution, I would like it to be on the same line.

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  • How to use the variable declared in one class in another class in Obj C.

    - by srikanth rongali
    I have a NSDate *date1 in class1 implementation file(I initialized it as Global variable). I have NSDate *date2 in class 2 implementation file (initialized it as Global variable). I need to calculate the NSTimeInterval between the two dates in class 2. But I could not do it. I could not access date1 in this class. It is giving error as (date2 undeclared). Please give me help in how to call other class variables in this class. Thank you.

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  • Problem with parsing XML into table variable

    - by Stanley Ross
    I'm using the following code to read a SQL XML Variable into a table variable. I am getting the following error. " Incorrect syntax near '.'. " Can't quite Figure it out DECLARE @LOBS Table ( LineGUID varchar(40) ) DECLARE @lg xml SET @lg = '<?xml version="1.0" encoding="utf-16" standalone="yes"?> <Table> <LOB> <LineGuid>d6e3adad-8c53-4768-91a3-745c0dae0e08</LineGuid> </LOB> <LOB> <LineGuid>4406db8f-0d19-47da-953b-afc1db38b124</LineGuid> </LOB> </Table>' INSERT INTO @LOBS(LineGUID) SELECT ParamValues.ID.value('.','VARCHAR(40)') FROM @lg.nodes('/Table/LOB/LineGuid') AS ParamValues(ID)

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  • Use Javascript variable in PHP

    - by Rhepungus
    I have seen some answers to this question in previous posts, but no one has given a real working example, just psuedo code. Has anyone ever done this before? Basically, what i have is a variable in javascript (jquery), and i want to use this variable to drive a query (for an overlay window) i am going to run in php. From what i have read you can do this using an ajax call to the same page so it doesnt refresh itself, but i must be missing something because i can't get it working... Any examples out there? Thanks.

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  • Actionscript 2 call function from variable

    - by NebNeb
    How can i call a function form a variable. var upfunction = init; //or var upfunction = init(); I have tried the above code and it does not work. I want to be able to call that variable from a keypress and change the variables function. For example. function init(){ //Do whatever } function init2(){ //Do another thing } var upfunction = init(); if (Key.getCode() == Key.UP) { upfunction; } Then later doing upfunction = init2(); That way i could change the function without having much code. Sorry if this is a noob question but all i do is copy and paste code i have found.

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  • How to refresh site if $_SESSION variable has changed

    - by 4ndro1d
    I'm writing in my $_SESSION variable from a database, when i clicked a link. public function getProjectById($id){ $query="SELECT * FROM projects WHERE id=\"$id\""; $result=mysql_query($query); $num=mysql_numrows($result); while ($row = mysql_fetch_object($result)) { $_SESSION['projectid'] = $row->id; $_SESSION['projecttitle'] = $row->title; $_SESSION['projectinfo'] = $row->info; $_SESSION['projecttext'] = $row->text; $_SESSION['projectcategory'] = $row->category; } } Now my variable is overwritten and I want to show these variables in my index.php like this: <div id="textContent"> <?php if(isset($_SESSION['projecttext']) && !empty($_SESSION['projecttext'])) { echo $_SESSION['projecttext']; }else { echo 'No text'; } ?></div> But of course, my page will not refresh automatically. How can I do that?

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  • [Android] Pass variable/intent to an activity when launched from a Widget

    - by Pelly
    Hi, Currently within an activity in my application I can call another activity and pass a variable to it in the following manner: Intent myIntent = new Intent(parentView.getContext(), ShowStations.class); myIntent.putExtra("stationName", stations[position].StationName); startActivity(myIntent); This works fine, but now I want to be able to do the same from my Widget. Currently this code works fine for launching a specific activity from my widget: Intent WidgetIntent = new Intent(Intent.ACTION_MAIN).addCategory(Intent.CATEGORY_LAUNCHER).setComponent(new ComponentName("grell.com", "grell.com.FavStations")); PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, WidgetIntent, 0); updateViews.setOnClickPendingIntent(R.id.widget_main, pendingIntent); So now I am wondering how can I launch the same activity as shown in the first example but also pass through the 'stationName' variable. Any help would be greatly appreciated. Cheers

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  • C++ Array of Variable sized Arrays

    - by adam
    I am very new to C++ and I realise the following is not necessarily as easy as I'd like it to be, but I'd really appreciate a more expert opinion. I am essentially trying to achieve a dynamic iteration over a variable sized array of variable sized arrays similar to the following. String *2d_array[][] = {{"A1","A2"},{"B1","B2","B3"},{"C1"}}; for (int i=0; i<2d_array.length; i++) { for (int j=0; j<2d_array[i].length; j++) { print(2d_array[i][j]); } } Is there a reasonable way to do this? Perhaps by using a vector, or another struct? Thanks :)

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  • Keep a javascript variable after an ajax call

    - by Guillaume le Floch
    I'm new in javascript and jQuery. I'm using ajax calls to get data from my server. The fact is, I'm losing my javascript variables after the call .. Here is what I did : the variable is define outside any function and treat in an other function. var a = 0; function myfunction(url){ $.ajax({ url: url, timeout: 20000, success: function(data){ // Do some stuff // The a variable is now undefined }, error: function(){ // Do some stuff } }); } Everything is working fine, the only thing is that I need to keep my variables ... but it looks like it's gone .. Does anyone know why? Thanks

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  • Static variable for optimization

    - by keithjgrant
    I'm wondering if I can use a static variable for optimization: public function Bar() { static $i = moderatelyExpensiveFunctionCall(); if ($i) { return something(); } else { return somethingElse(); } } I know that once $i is initialized, it won't be changed by by that line of code on successive calls to Bar(). I assume this means that moderatelyExpensiveFunctionCall() won't be evaluated every time I call, but I'd like to know for certain. Once PHP sees a static variable that has been initialized, does it skip over that line of code? In other words, is this going to optimize my execution time if I make a lot of calls to Bar(), or am I wasting my time?

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  • How can I evaluate variable to another variable before assigning?

    - by HH
    #!/usr/bin/python # # Description: trying to evaluate array -value to variable before assignment # but it overwrites the variable # # How can I evaluate before assigning on the line 16? #Initialization, dummy code? x=0 y=0 variables = [x, y] data = ['2,3,4', '5,5,6'] # variables[0] should be evaluted to `x` here, i.e. x = data[0], how? variables[0] = data[0] if ( variables[0] != x ): print("It does not work, why?"); else: print("It works!");

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  • how to pass variable arguments from one function to other in tcl

    - by vaichidrewar
    I want to pass variable arguments obtained in one function to other function but I am not able to do so. Function gets even number of variable arguments and then it has to be converted in array. Below is the example. Procedure abc1 gets two arguments (k k) and not form abc1 procedure these have to be passed to proc abc where list to array conversion it to be done. List to array conversion works in proc1 i.e. abc1 but not in second proc i.e. abc Error obtained is given below proc abc {args} { puts "$args" array set arg $args } proc abc1 {args} { puts "$args" array set arg $args set l2 [array get arg] abc $l2 } abc1 k k abc k k Output: k k {k k} list must have an even number of elements while executing "array set arg $l1" (procedure "abc" line 8) invoked from within "abc $l2" (procedure "abc1" line 5) invoked from within "abc1 k k" (file "vfunction.tcl" line 18)

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  • How to print size_t variable portably?

    - by ArunSaha
    I have a variable of type size_t, and I want to print it using printf(). What format specifier do I use to print it portably? In 32-bit machine, %u seems right. I compiled with g++ -g -W -Wall -Werror -ansi -pedantic, and there was no warning. But when I compile that code in 64-bit machine, it produces warning. size_t x = <something>; printf( "size = %u\n", x ); warning: format '%u' expects type 'unsigned int', but argument 2 has type 'long unsigned int' The warning goes away, as expected, if I change that to %lu. The question is, how can I write the code, so that it compiles warning free on both 32- and 64- bit machines? Edit: I guess one answer might be to "cast" the variable into an unsigned long, and print using %lu. That would work in both cases. I am looking if there is any other idea. (C, C++)

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  • how to set and access variable values from another classess

    - by BittenApple
    I am modifying QuartzDemo example app and want to do set and read values of integer type variables in other classes which are already included. For example, in MainViewController.m I want to set a numeric value (simple numbers from 1-100) to a variable which is then going to be called (read) in file QuartzImages.m. Question is how to define variable properly, set and access (read) the value. I am a beginner with Obj C and iPhone SDK in general and have some experience with Delphi and VB but this doesn't help at all :) Thank you, whoever and wherever you are, person who will take me out of this endless googling loop.

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  • update value of a variable outside a class in VB.NET

    - by dpp
    I have a class derived from a Form, it has textbox for username and password and an OK button. I want it to behave like an InputBox so I can use it like this: Dim Username As String = "" Dim Password As String = "" Dim authorization As New Authorization(Username, Password) authorization.ShowDialog() 'The user will click OK and I will expect the Username and Password to change based on the user input MsgBox(Username & " " & Password) The Authorization class: Public Class Authorization Dim RefUsername As String Dim RefPassword As String Public Sub New(ByRef Username As String, ByRef Password As String) InitializeComponent() RefUsername = Username 'I'm trying to pass reference instead of value RefPassword = Password 'I'm trying to pass reference instead of value End Sub Private Sub OKButton_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AuthorizeButton.Click RefUsername = Username.Text 'I'm trying to change value of variable outside the class RefPassword = Password.Text 'I'm trying to change value of variable outside the class Me.Close() End Sub End Class In short, I want to change the value of variables outside the class when the user clicks the OK, how am I going to accomplish that?

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  • Objective-C: Cannot Change Value of Instance Variable Inside a Function

    - by user262325
    Hello everyone, I cannot change the value of an instance variable inside a function. I have defined a class: // info.h #import <Foundation/Foundation.h> @interface NSMyObject : NSObject { NSInteger i; } -(void) setI:(NSInteger)v; @end #import "info.h" @implementation NSMyObject -(void) setI:(NSInteger)v ; { i=v; } - (void)dealloc { [super dealloc]; } @end I call a function 'myFunction' with parameter temObj which is a NSMyObject instance. myFunction(temObj);//temObj is NSMyObject In the function, I can change the value of the instance variable of parameter obj. -(void)myFunction:(NSMyObject*) obj; { [obj setI:0]; } ... expecting this to change the content of temObj. But when I check the results of operation on obj in function myFunction the value of temObj.i has not changed. Welcome any comment Thanks

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  • Release variable and assigning it again

    - by David Gonrab
    What is the preferred and/or correct way to release an NSMutableString (or any other class for that matter) instance and assign a new instance to the same variable in Objective-C on the iPhone? Currently I'm using [current release]; current = [NSMutableString new]; but I understand that the following works, too. NSMutableString *new = [NSMutableString new]; [current release]; current = [new retain]; [new release]; The variable current is declared in the interface definition of my class and gets released in dealloc.

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  • ruby confusing -- local variable or instance_method ?

    - by boblu
    I have the following program. module C def self.included(base) base.extend(ClassMethods) end module ClassMethods def test_for class_eval <<-DEFINECLASSMETHODS def self.my_method(param_a) puts "SELF is: #{self.inspect}" puts param_a puts "#{param_a}" end DEFINECLASSMETHODS end end end class A include C end class B < A test_for end when I run B.new.my_method("aaa"), I got this error NameError: undefined local variable or method `param_a' for B:Class I am quite confused. I define param_a as a local variable in class method my_method, puts param_a runs good, and will output the "aaa". however, puts "#{param_a}" output that error. why? Can anyone explain this?

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  • Execute query stored in variable in a very specific way

    - by niao
    Greetings, I have a problem as follows: I have an SQL variable declared: DECLARE @myVariable nvarchar(max) a third party library set a value for this variable. To simplify, lets say that the value is as follows: SET @myVariable = 'Select ROWGUID from MySampleTable' Now, I want to execute the following query: SELECT ROWGUID FROM myTable WHERE ROWGUID in (exec sp_executesql @myVariable ) However, the above statement does not work because it returns an error telling me that I can't execute stored procedure in that way. I made a workaround and this is what I wrote: create table #temptable (ID uniqueidentifier null) if(@myVariable is not null AND @myVariable !='') insert into #temptable exec sp_executesql @myVariable SELECT ROWGUID FROM myTable WHERE ROWGUID in (select * from #temptable) DROP TABLE #temptable This works fine.However I don't think it is a good idea to use temporary table. How can I achieve the same result without necessity of creating temporary tables? I am using SQL SERVER 2005

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  • How to set PATH to another variable value with spaces in Windows batch file

    - by Evgeny
    I've got a Windows batch script issue that I'm bashing my head against (no pun intended). The problematic script looks like this: if defined _OLD_VIRTUAL_PATH ( set PATH=%_OLD_VIRTUAL_PATH% ) When I run it and _OLD_VIRTUAL_PATH is set I get: \Microsoft was unexpected at this time. _OLD_VIRTUAL_PATH is a variable that was originally set from PATH and it contains spaces - I'm pretty sure that's the problem. But what's the solution? It runs successfully if I enclose it in quotes, but I don't think the entire value of the PATH variable is supposed to be in quotes.

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  • Random password variable disappears

    - by snaken
    Hi, I'm using the following to generate a random password in a shell script: DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) When i run this in a file on its own like this: #!/bin/sh DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) echo $DBPASS A password is echoed. When i incorporate it into a larger script though the variable never seems to get created for some reason, so for example this doesn't work: DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) sed -i s/oldpass/$DBPASS/ mysql_connect.php If i manually set the variable though everything is fine.. can anyone see why?

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