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  • Static member variable containing object instances

    - by tom
    I have the following: function Preferences() { } Preferences.players = { 'player1': new Player() } players is a static member variable of Preferences and I'm trying to make it an object containing an instance of a Player. However, it doesn't appear to let me do this. It seems like it will allow me to define players if I make it a non-static member variable however. Like so: function Preferences() { var players = { 'player1' : new Player() } } Is it possible to create a static member variable containing instances of an object in JS?

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  • jquery ajax calls with scope safety

    - by acidzombie24
    My gut tells me that if i am on a laggy server and the user fires two events fast enough on the success function c will be the value of the most recent event causing func1 to use the wrong value. <--- This is a guess, i haven't proved it. Its a feeling. How do i ensure that i use the right value when calling func1? I prefer not to send c to the server and i dont know if or how to serialize the data and deserialize it back. How do i make this code safe? $('.blah').click(function (event) { var c = $(this).closest('.comment'); ... $.ajax({ url: "/u", type: "POST", dataType: "json", data: { ... }, success: function (data) { func1(c. data.blah);//here

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  • Variable Binding Class

    - by Davis
    Hi, I believe this is a tough one... I'm trying to create a collection of variable binding in a class. It is intended to look something like this: Dim x as integer, s as string Dim c as new VBindClass x = 1 s = "Hello" c.Add x, s Debug.Print c.value(x) '= 1 Debug.Print c.value(s) '= "Hello" Is there some function that allow us to retrieve a unique ID for a given variable and also get/set based on variable?

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  • Login with Google OAuth api and return url with variable

    - by user2833721
    I am using the Google API for login in my site and I appending my variable with URL and I want that variable in the return URL of OAuth API because of update purpose can I return back that variable For example: <a href="<?php echo($authUrl); ?>&kicker"> I append the kicker in $authUrl and when I return back from Oauth api print $me['displayName']; print $user['email']; print $me['gender']; print $me['id']; with this output I also want my variable "kicker" how can I get it

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  • Long variable names

    - by RaouL
    Lets say i have a variable that contains the number of search engine names in a file, what would you name it? number_of_seach_engine_names search_engine_name_count num_search_engines engines engine_names other name? The first name describes what the variable contains precisely, but isn't it too long?, any advice for choosing variable names? especially how to shorten a name that is too long or what kind of abbreviations to use?

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  • Scope of Groovy's ExpandoMetaClass?

    - by TicketMonster
    Groovy exposes an ExpandoMetaClass that allows you to dynamically add instance and class methods/properties to a POJO. I would like to use it to add an instance method to one of my Java classes: public class Fizz { // ...etc. } Fizz fizz = new Fizz(); fizz.metaClass.doStuff = { String blah -> fizz.buzz(blah) } This would be the equivalent to refactoring the Fizz class to have: public class Fizz { // ctors, getters/setters, etc... public void doStuff(String blah) { buzz(blah); } } My question: Does this add doStuff(String blah) to only this particular instance of Fizz? Or do all instances of Fizz now have a doStuff(String blah) instance method? If the former, how do I get all instances of Fizz to have the doStuff instance method? I know that if I made the Groovy: fizz.metaClass.doStuff << { String blah -> fizz.buzz(blah) } Then that would add a static class method to Fizz, such as Fizz.doStuff(String blah), but that's not what I want. I just want all instances of Fizz to now have an instance method called doStuff. Ideas?

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  • Getting 'choice' to work in Highline Ruby Gem without error and getting variable from it

    - by The Warm Jets
    I'm having a couple of problems using Highline in Ruby, and trying to get the choice element, detailed here, to work. At the moment the following code produces the error "error: wrong number of arguments (0 for 1). Use --trace to view backtrace" How do I get the variable out of choice? At the moment I have the 'do' setup, but I have no idea about how to get the variable the user has chosen out and into a variable for use elsewhere. Sorry if this is a bit beginner, I'm brand new to ruby and this is my first project, in at the deep end. Thanks in advance. if agree("Are these files going to be part of a set? ") set_title = ask("Title: ") set_desc = ask("Description:") set_genre = ask("Genre: ") set_label = ask("Record Label: ") set_date = ask_for_date("Release Date (yy-mm-dd): ") set_label = ask("EAN/UPC: ") set_buy = ask("Buy this set link: ") set_tags = ask_for_array("Tags (seperated by space): ") # Sort out license choose do |menu| menu.prompt = "Please choose the license for this set? " menu.choices(:all_rights_reserved, :cc_by) do # put the stuff in a variable end end end # End setup set

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  • C++: Pointers and scope

    - by oh boy
    int* test( ) { int a = 5; int* b = &a; return b; } Will the result of test be a bad pointer? As far as I know a should be deleted and then b would become a messed up pointer, right? How about more complicated things, not an int pointer but the same with a class with 20 members or so?

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  • jQuery/Javascript Cookies and variable returning with value [object Object]

    - by user1706661
    I am attempting to set a cookie to a site using jQuery, ONLY if the user came from a specific site. In this case, lets use -http://referrersite.com- as the site they must come from for the cookie to be created as an example. The cookie value is being stored in a variable and everything up to this point is working fine. There is a conditional statement checking whether the user came from the referred site, if the cookie exists already and if the cookie doesn't exist and the user did not come from the referred site. If the user came from the referred site the cookie is created and stored in a variable. If the cookie already exists, it is then stored in a variable. If the cookie does not exist and the user did not come from the referred site I am assigning the variable a static string of characters - this is where the issue lies. When the variable is alerted from the non referred site and no existing cookie, it returns: [object Object], not the static string of characters. The code I am using is below: $(document).ready(function() { var referrer = document.referrer; if(referrer == "http://referrersite.com") { $.cookie("code","123456", { expires: 90, path: '/' }); cookieContainer = $.cookie("code"); alert(cookieContainer); } else if($.cookie("code")) { cookieContainer = $.cookie("code"); alert(cookieContainer); } else if($.cookie("code") == null && referrer != "http://referrersite.com") { cookieContainer = "67890"; alert(cookieContainer); } }); Please let me know if there is something I am missing as the code to me looks like it should work. Thanks!

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  • Access a static variable by $var::$reference

    - by chuckg
    I am trying to access a static variable within a class by using a variable class name. I'm aware that in order to access a function within the class, you use call_user_func(): class foo { function bar() { echo 'hi'; } } $class = "foo"; all_user_func(array($class, 'bar')); // prints hi However, this does not work when trying to access a static variable within the class: class foo { public static $bar = 'hi'; } $class = "foo"; call_user_func(array($class, 'bar')); // nothing echo $foo::$bar; // invalid How do I get at this variable? Is it even possible? I have a bad feeling this is only available in PHP 5.3 going forward and I'm running PHP 5.2.6. Thanks.

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  • Accessing initialized variable on different class C++

    - by d0pe
    I'm having some difficulties with this problem. The main idea is, I initialized a variable of class type B in class A, class A.h has the variable Z declared as public, like B *Z; In class A.cpp, I initialized it as Z = new B(); Now, I want to access that variable from class C and I'm unable to do so. C.h includes A.h and B.h

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  • Variable pre-fixes, Visual Studio 2010 onwards?

    - by thedixon
    I'm a bit bewildered on this subject, as I relate variable prefixes to being a thing of the past now, but with Visual Studio 2010 onwards (I'm currently using 2012), do people still do this and why? I only ask because, these days, you can hover over any variable and it'll tell you the variable type and scope. There's literally no requirement for pre-fixing being there for readability. By this I mean: string strHello int intHello etc. And I'm being language/tool biased here - as Visual Studio takes a lot of the legwork out for you in terms of seeing exactly what type the variable is, including after conversions in the code. This is not a "general programming" question.

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  • Route outbound connections from local network through VPN

    - by Sharkos
    I have a server A running OpenVPN, an OpenVPN client B (a rooted Android phone as it happens) and a third party C (a laptop, tablet etc.) tethered to B. B can use the VPN to access the internet via A; C can use the tethered connection WITHOUT the VPN to access the internet via B. However, with the VPN on B active, I cannot load information from the internet on C. A appears to log similar traffic inbound and outbound when B or C attempt to load a webpage, say, but the VPN on device B reports no inbound traffic when the connection originated from C. Where should I look for packets being dropped, and what ip rules should I use to make sure they are passed back through the VPN and into the local network B <- C? (I'll obviously post whatever further information is needed.) Further info Without VPN: root@android:/ # ip route default via [B's External Gateway] dev rmnet0 [B's External Subnet] dev rmnet0 proto kernel scope link src [B's External IP] [B's External Gateway] dev rmnet0 scope link 192.168.43.0/24 dev wlan0 proto kernel scope link src 192.168.43.1 With VPN: root@android:/ # ip route 0.0.0.0/1 dev tun0 scope link default via [B's External Gateway] dev rmnet0 [B's External Subnet] dev rmnet0 proto kernel scope link src [B's External IP] [B's External Gateway] dev rmnet0 scope link [External address of A] dev tun0 scope link 128.0.0.0/1 dev tun0 scope link 172.16.0.0/24 dev tun0 scope link 172.16.0.8/30 dev tun0 proto kernel scope link src 172.16.0.10 192.168.43.0/24 dev wlan0 proto kernel scope link src 192.168.43.1 192.168.168.0/24 dev tun0 scope link

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  • /etc/enviorment not being read into PATH variable

    - by Dan
    In Ubuntu the path variable is stored in /etc/enviorment. This is mine (I've made no changes to it, this is the system default): $ cat /etc/environment PATH="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games" but when I examine my PATH variable: $ echo $PATH /home/dan/bin:/home/dan/bin:/bin:/usr/bin:/usr/local/bin:/usr/bin/X11 You'll notice /usr/games is missing (it was there up until a few days ago). My /etc/profile makes no mention of PATH. My ~/.profile is the default and only has: if [ -d "$HOME/bin" ] ; then PATH="$HOME/bin:$PATH" fi This only happens in gnome, not in tty1-6. This is missing from both gnome terminal and when I try to call applications from the applications dropdown. Anyone know what could be causing this? Thanks.

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  • /etc/environment not being read into PATH variable

    - by Dan
    In Ubuntu the path variable is stored in /etc/environment. This is mine (I've made no changes to it, this is the system default): $ cat /etc/environment PATH="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games" but when I examine my PATH variable: $ echo $PATH /home/dan/bin:/home/dan/bin:/bin:/usr/bin:/usr/local/bin:/usr/bin/X11 You'll notice /usr/games is missing (it was there up until a few days ago). My /etc/profile makes no mention of PATH. My ~/.profile is the default and only has: if [ -d "$HOME/bin" ] ; then PATH="$HOME/bin:$PATH" fi This only happens in gnome, not in tty1-6. This is missing from both gnome terminal and when I try to call applications from the applications dropdown. Anyone know what could be causing this? Thanks.

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  • Python version priority in OSX/UNIX PATH environment variable

    - by mindthief
    Hi all, I want my system to use /usr/bin/python, but it's currently using /opt/local/bin/python, which points to /usr/bin/python2.6. I tried modifying the PATH variable in my .bashrc as PATH=~/bin:$PATH ...and then set a symbolic link in ~/bin to point to /usr/bin/python. i.e. ~/bin/python --> /usr/bin/python I figured this might prioritize this symlink over the /opt/local version if it came before the other one in the PATH variable, but when I opened a new shell I still found python pointing to /opt/local/bin. Any advice on a good way to get the system to use /usr/bin/python? Also, I usually use ipython as opposed to python directly. I'm assuming that if the system starts to use the correct version of python then ipython would also use that version? If not, how could I also get ipython to use the correct version? Thanks!

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  • where.exe does not find OpenSSL libs when %ProgramFiles% variable is used in the PATH environment variable

    - by Piotr Dobrogost
    I installed both 32bit and 64bit version of OpenSSL libs on Vista x64. The 32bit version was installed in c:\Program Files (x86)\OpenSSL and the 64bit version was installed in c:\Program Files\OpenSSL. Then I added the entry %ProgramFiles%\OpenSSL to the PATH environment variable. %ProgramFiles%\OpenSSL is expanded to c:\Program Files (x86)\OpenSSL for 32bit programs and it's expanded to c:\Program Files\OpenSSL for 64bit programs. The idea is to have 32bit programs use 32bit version of OpenSSL libs and 64bit programs use 64bit version. I wanted to check if this works by running 32bit cmd.exe and issuing where ssleay32.dll and then by running 64bit cmd.exe and issuing the same. However in both cases I get the error INFO: Could not find files for the given pattern(s). What's wrong? This is a follow up to Different PATH environment variable for 32bit and 64bit Windows - is it possible?

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  • Need to set mailx variable to specify the From address

    - by user256817
    Running Oracle Linux 5.8 (which is just re-branded RedHat EL 5.8) I must change the From address. But we have scripts that use mailx which cannot be re-written to use any extra flags, so I'd like to use internal variables instead, which I see on the linux.die.net manpage on mailx is an alternative to the -r flag: -r address Sets the From address. Overrides any from variable specified in environment or startup files. Tilde escapes are disabled. The -r address options are passed to the mail transfer agent unless SMTP is used. This option exists for compatibility only; it is recommended to set the from variable directly instead. (Source: http://linux.die.net/man/1/mailx) How can we use these mailx variables? I tried adding this to /root/.mailrc, no go: set [email protected] I also added that to /etc/mail.rc with no gold. So I am turning to you, SuperUsers...

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  • Modify PATH variable for X11 during log-in

    - by user1028435
    I am working on some lab computers (read: no administrative rights) that, if I log in, I need to change the PATH variable as X11 starts. The reason is that I need to change the PATH variable at this time, as opposed to later, is that the Print Screen command seems to "bind" during login (forgive my bad explanation of this). Currently, I have a .bashrc script as a workaround: #!/bin/bash export PATH=/home/username/bin:$PATH I can make it work by starting a new X, but I was wondering if it is possible to change upon login. cat /etc/redhat-release tells me my distribution is: Red Hat Enterprise Linux Client release 5.8 (Tikanga)

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  • set a global environment variable in linux that sticks when going root

    - by Scott
    When I SSH into a linux box, I want to have the /etc/profile file save the results of the whoami command to a global environment variable. if I were to go root with the command sudo su -, I do not want that command to run again when gonig root, I want it to stick with the result of whoami as my regular username from before I went root, and I need to access that variable as the root user even though it will run the /etc/profile file again when I go root. What can I do to only run that command once in the /etc/profile command?

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  • Mac OS X keeps "old" environment variable around

    - by Xymak1y
    So far I had /Applications/play-1.2.5/ added to my $PATH variable. Now I'm working with 2.2.1, which I installed in /Applications/play-2.2.1 and changed in ~/.bash_profile (which is getting sourced at startup). However, when printing $PATH, 1.2.5 is somehow still around: mbp:~ user$ echo $PATH /usr/local/share/npm/bin:/Applications/play-2.2.1:/usr/local/heroku/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/Applications/play-1.2.5:/Applications/XAMPP/xamppfiles/bin/:/opt/X11/bin As far as I now, I only entered $PATH variables in .bash_profile, which looks like this: mbp:~ user$ cat .bash_profile source ~/.git-completion.bash ### Added by the Heroku Toolbelt export PATH="/usr/local/heroku/bin:$PATH" ### Play Framework export PATH="/Applications/play-2.2.1:$PATH" export PATH="/usr/local/share/npm/bin:$PATH" I'm also not sure where the XAMPP extension to the variable comes from. Can I see somewhere which other files are being sourced on startup?

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