Search Results

Search found 77950 results on 3118 pages for 'large file upload'.

Page 303/3118 | < Previous Page | 299 300 301 302 303 304 305 306 307 308 309 310  | Next Page >

  • Open files on client side from ORACLE Forms

    - by Mousarules
    I'm trying to put a code on a button so that the used would be able to open a specific excel file whenever he pressed it , unfortunately the code i was using ( AppID ) happened to be opening the file on the server side not the client side ; please find the code below : DECLARE AppID PLS_INTEGER; BEGIN AppID := DDE.App_Begin('C:\Program Files\Microsoft Office\Office12\WINWORD.EXE C:\test\'||:TT_PER_RF_MAIN.T_NUMBER||'.docx', DDE.APP_MODE_NORMAL); END; Can anyone help me how to let the users ( client side ) be able to open it on thier own PCs?

    Read the article

  • May the FileInputStream.available foolish me?

    - by Tom Brito
    This FileInputStream.available() javadoc says: Returns an estimate of the number of remaining bytes that can be read (or skipped over) from this input stream without blocking by the next invocation of a method for this input stream. The next invocation might be the same thread or another thread. A single read or skip of this many bytes will not block, but may read or skip fewer bytes. In some cases, a non-blocking read (or skip) may appear to be blocked when it is merely slow, for example when reading large files over slow networks. I'm not sure if in this check: if (new FileInputStream(xmlFile).available() == 0) can I rely that empty files will always return zero?

    Read the article

  • Cropping an image, saving output to a new file and get crop coordinates

    - by synic
    I'm interfacing with a service that allows you to upload an image, and also upload coordinates of a thumbnail of that image. I'm thinking that (if there isn't some sort of prefab Activity specifically for this) that I can use Android's crop utility. The only problem is that I can't overwrite the original file, the crop window needs to have a custom message (instead of "crop image"), and I'll need the coordinates of the crop. Is this possible? Is there another way to do this without writing my own Activity?

    Read the article

  • Can I make a folder writeable in Medium trust?

    - by harpo
    My web app writes to several folders (logs, uploads, etc), and I've always set these permissions manually through my hosting provider. I'd like to create a setup script that performs this on new installations. Is this possible under Medium trust? I can't even call File.GetAccessControl, let alone File.SetAccessControl, but I don't need such a "big hammer", anyway. I just want to do what the ISP (in this case GoDaddy) is letting me do through a management console. I believe PHP is able to do this, and I'd be willing to consider a PHP page for this purpose if that's possible.

    Read the article

  • Force save files all browsers - not open in browser window

    - by Joshc
    I'm after a simple solution to work in all browsers. For specific file types, or targeted links via a class: how can I get them to simply force download in all major browsers. I thought I found the perfect solution for apachce server - by adding this into the .htaccess. http://css-tricks.com/snippets/htaccess/force-files-to-download-not-open-in-browser/ AddType application/octet-stream .csv AddType application/octet-stream .xls AddType application/octet-stream .doc AddType application/octet-stream .avi AddType application/octet-stream .mpg AddType application/octet-stream .mov AddType application/octet-stream .pdf Seems to work in Firefox and Safari, but not chrome or IE (have not tested anything else) Can any one please help me with a solution on how to make links to force download the file, instead of opening in the browser, for ALL browsers. I can't seem to find a full browser proof solution. Is it not possible? Any links to tutorial or snippets would be awesome. My website if PHP based so can make it work with PHP if posible. Thanks

    Read the article

  • How do I take advantage of Android's "Clear Cache" button

    - by Jay Askren
    In Android's settings, in the "Manage Applications" activity when clicking on an app, the data is broken down into Application, Data, and cache. There is also a button to clear the cache. My app caches audio files and I would like the user to be able to clear the cache using this button. How do I store them so they get lumped in with the cache and the user can clear them? I've tried storing files using both of the following techniques: newFile = File.createTempFile("mcb", ".mp3", context.getCacheDir()); newFile = new File(context.getCacheDir(), "mcb.mp3"); newFile.createNewFile(); In both cases, these files are listed as Data and not Cache.

    Read the article

  • connect to mssql from batch script

    - by JPro
    Hi, I am supplying a batch script to create a DSN connection in the user computer before they start to use my application. I am using this in a .bat file. ODBCConf ConfigSysDSN "SQL Server" "DSN=CONNAME|SERVER=PCNAME\INSTANCENAME But I want to make sure they will be able to connect to the database, considering the fact that proper drivers may not be installed in their systems. So, is there any way to check the connection from the same batch file and inform the user if something unable to connect to the database? thanks.

    Read the article

  • allowing index access only with .htaccess

    - by YsoL8
    Hello I have this in my .htaccess file, in the site root: Options -Indexes <directory ../.*> Deny from all </directory> <Files .htaccess> order allow,deny deny from all </Files> <Files index.php> Order allow,deny allow from all </Files> What I'm trying to achieve is to block folder and file access to anything that isn't called index.php, regardless of which directory is accessed. I have the folder part working perfectly and the deny from all rule is working as well - but my attempt to allow access to index.php is failing. Basically could someone tell me how to get it working?

    Read the article

  • Own data format for the iPhone

    - by Stefan
    Hi, I would like to create my own data format for an iPhone app. The files should be similar structured as e.g. Apple's iWork files (.pages). That means, I have a folder with some files in it: The file 'Juicy.fruit' contains: Fruits ---> Apple.xml ---> Banana.xml ---> Pear.xml ---> PreviewPicture.png This folder "Fruits" should be packed in a handy file 'Juicy.fruit'. Compression isn't necessary. How could I achieve this? I've discovered some open source ZIP-libraries. However, I would like to to build my own data format with the iPhones built-in libs (if possible). Best regards, Stefan

    Read the article

  • Is it possible to change a exe's icon without recompiling it?

    - by Microkernel
    Hi all, I have lot of executable that I have compiled (long time back) for many of which I don't have sourcecode now. But when I compiled them I didn't put any icons for them, so they all look like same dull, bald default icon. So my questions are, (1) is it possible for me to write a software that can change the resources section of the exe and change its looks? If so, can anyone plz point me to the location where its explained? (I am a beginner, I have no idea on the exe format and all) Also its fun to keep changing Icons without having the pain of recompiling everything just for the icon change... (2) This is raises a natural converse question, Is it similarly possible to zap out the icon used by some file and use it for some other file? (If so, plz point me to location where I can get some details. I am a C/C++ developers and I am looking for solution on Windows Platform... Regards, MicroKernel

    Read the article

  • Groovy Grails, How do you stream or buffer a large file in a Controller's response?

    - by Julian Noye
    Hi Guys I have a controller that makes a connection to a url to retrieve a csv file. I am able to send the file in the response using the following code, this works fine. def fileURL = "www.mysite.com/input.csv" def thisUrl = new URL(fileURL); def connection = thisUrl.openConnection(); def output = connection.content.text; response.setHeader "Content-disposition", "attachment; filename=${'output.csv'}" response.contentType = 'text/csv' response.outputStream << output response.outputStream.flush() However I don't think this method is inappropriate for a large file, as the whole file is loaded into the controllers memory. I want to be able to read the file chunk by chunk and write the file to the response chunk by chunk. Any ideas?

    Read the article

  • Included php file calling Javascript function

    - by Illes Peter
    Hi there! Here's the deal. I've got index.php which links to an internal JS file in it's header. index.php then includes another .php file, which outputs this: + add file. addFile() is a Javascript function defined in the external JS file. By doing this nothing happens, the included php does not "see" the JS function. Encapsulating the JS in the included PHP makes it all work. But I don't want to do it that way. Any ideas? EDIT: here's the source <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Archie</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <link rel="stylesheet" href="/screen.css" type="text/css" media="screen"/> <script src="/lib/js/archie.js" type="text/javascript"></script> </head> <body> ... ... //included php starts here <form action="/lib/course.php" method="post"> <fieldset> <div id="addFileLocation"></div> <a href="#" onClick="addFile()">+ add file</a> <input type="hidden" id="addFileCount" value="0"/> </fieldset> </form> //ends here ... ... </body> </html> and the js: <script type="text/javascript"> //Dynamically add form fields //add file browser function addFile() { var location = document.getElementById('addFileLocation'); var num = document.getElementById('addFileCount'); var newnum = (document.getElementById('addFileCount').value -1)+ 2; num.value = newnum; var newname = 'addFile_'+newnum; var newelement = document.createElement('input'); newelement.setAttribute('name',newname); newelement.setAttribute('type','file'); location.appendChild(newelement); } </script>

    Read the article

  • Java IO (javase 6)- Help me understand the effects of my sample use of Streams and Writers...

    - by Daddy Warbox
    BufferedWriter out = new BufferedWriter( new OutputStreamWriter( new BufferedOutputStream( new FileOutputStream("out.txt") ) ) ); So let me see if I understand this: A byte output stream is opened for file "out.txt". It is then fed to a buffered output stream to make file operations faster. The buffered stream is fed to an output stream writer to bridge from bytes to characters. Finally, this writer is fed to a buffered writer... which adds another layer of buffering? Hmm...

    Read the article

  • How to efficiently manage files on a filesystem in Java?

    - by Tuukka Mustonen
    I am creating a few JAX-WS endpoints, for which I want to save the received and sent messages for later inspection. To do this, I am planning to save the messages (XML files) into filesystem, in some sensible hierarchy. There will be hundreds, even thousands of files per day. I also need to store metadata for each file. I am considering to put the metadata (just a couple of fields) into database table, but the XML file content itself into files in a filesystem in order not to bloat the database with content data (that is seldomly read). Is there some simple library that helps me in saving, loading, deleting etc. the files? It's not that tricky to implement it myself, but I wonder if there are existing solutions? Just a simple library that already provides easy access to filesystem (preferrably over different operating systems). Or do I even need that, should I just go with raw/custom Java?

    Read the article

  • Why does this code read all ' ' for the anything after the 4th character?

    - by djs22
    #define fileSize 100000 int main(int argc, char *argv[]){ char *name=argv[1]; char ret[fileSize]; FILE *fl = fopen(name, "rb"); fseek(fl, 0, SEEK_END); long len = fileSize; fseek(fl, 0, SEEK_SET); //fread(ret, 1, len, fl); int i; *(ret+fileSize) = '\0'; for (i=0; i<fileSize; i++){ *(ret+i)=fgetc(fl); printf("byte : %s \n", ret); } fclose(fl); } In the above code, when I feed the name of a jpeg file, it reads anything after the 4th character as ' '...any ideas? Thanks!

    Read the article

  • VS2008: Disable asking whether to reload files changed outside the IDE

    - by SealedSun
    Hi, I have a Visual Studio 2008 project where some code files are generated with each build (a parser, integrated via MSBuild aka editing the *.csproj file). VS does not know about the generated nature of these files (i.e. they are not the result of a "Custom Tool). So they "change" with every build, naturally. And VS2008 asks me after every build if I would like to reload those files: This file has been modified outside the source Do you want to reload it? That would be ok if I had one of those files opened and in front of me, but I get these modal dialogs even with none of the code files opened. So my question is: Is there a way to disable this dialog, per project, per solution or globally? Thanks!

    Read the article

  • css file not getting updated

    - by fusion
    the font of the content of my facebook app keeps getting italicized even when i've removed the italics from the css file. if i make minor changes in the css file and upload it to the server, the firebug shows the unedited previous css file and hence, the app keeps showing unformatted content. what exactly is going wrong here? i made a new css file and copied the contents of the previous css exactly as it was, and i linked it in all the files which require css. but when i upload these files to the server, facebook canvas doesn't show any css at all. i replaced the css filename with the previous one, and it works. why is this?

    Read the article

  • Working with multiple input and output files in Python

    - by Morlock
    I need to open multiple files (2 input and 2 output files), do complex manipulations on the lines from input files and then append results at the end of 2 output files. I am currently using the following approach: in_1 = open(input_1) in_2 = open(input_2) out_1 = open(output_1, "w") out_2 = open(output_2, "w") # Read one line from each 'in_' file # Do many operations on the DNA sequences included in the input files # Append one line to each 'out_' file in_1.close() in_2.close() out_1.close() out_2.close() The files are huge (each potentially approaching 1Go, that is why I am reading through these input files one at a time. I am guessing that this is not a very Pythonic way to do things. :) Would using the following form good? with open("file1") as f1: with open("file2") as f2: # etc. If yes, could I do it while avoiding the highly indented code that would result? Thanks for the insights!

    Read the article

  • SSIS process files from folder

    - by RT
    Background: I've a folder that gets pumped with files continuously. My SSIS package needs to process the files and delete them. The SSIS package is scheduled to run once every minute. I'm picking up the files in ascending order of file creation time. I'm building an array of files and then processing-deleting them one at a time. Problem: If an instance of my package takes longer than one minute to run, the next instance of the SSIS package will pick up some of the files the previous instance has in its buffer. By the time the second instance of teh package gets around to processing a file, it may already have been deleted by the first instance, creating an exception condition. I was wondering whether there was a way to avoid the exception condition. Thanks.

    Read the article

  • Extract some data from a lot of xml files

    - by LifeH2O
    I have cricket player profiles saved in the form of .xml files in a folder. each file has these tags in it <playerid>547</playerid> <majorteam>England</majorteam> <playername>Don</playername> the playerid is same as in .xml (each file is of different size,1kb to 5kb). These are about 500 files. What i need is to extract the playername, majorteam, and playerid from all these files to a list. I will convert that list to XML later. If you know how can i do it directly to XML i will be very thankful.

    Read the article

  • Why does C's "fopen" take a "const char *" as its second argument?

    - by Chris Cooper
    It has always struck me as strange that the C function "fopen" takes a "const char *" as the second argument. I would think it would be easier to both read your code and implement the library's code if there were bit masks defined in stdio.h, like "IO_READ" and such, so you could do things like: FILE* myFile = fopen("file.txt", IO_READ & IO_WRITE); Is there a programmatic reason for the way it actually is, or is it just historic? (i.e. "That's just the way it is.")

    Read the article

  • Files written with FileWriter are either 32 KB, 24 KB, 16 KB, ... big or empty

    - by Bernhard V
    Hi, I read a file into a string, change the first line and then write this string into a new file. I do this through the following code (a little bit shortened): while(jspIterator.hasNext()){ String line = (String) jspIterator.next(); if (i == 0) { if (line.startsWith("bla bla") && line.endsWith("yada")) { line = line.replaceFirst("this", "that"); } } jspAsString += line; i++; } FileWriter newJspWriter = new FileWriter(newJspFile); newJspWriter.write(jspAsString); Now the files written this way are either 32, 24, 16, 8 KByte big or completely empty. When debugging I see that the String is assembled correctly. When I print the variable jspAsString to the console it also appears correct. Do you know why FileWriter behaves this way?

    Read the article

  • Checking contents of Uploaded file

    - by kapil
    Hi all, I am using ASP.NEt MVC . I want to upload .zip files for which I am using html input file upload control on my view. I want only .zip files to be uploaded. I want to check that my .zip contains only two files - both having extensions .txt and one of them having name "start". Can anyone please suggest me about how to check this? How can we assure that the uploaded .zip is really a zipped folder and not any other file having just .zip extension. can we use HttpPostedFileBase.ContentType? thanks in advance, kaps

    Read the article

  • Jquery Ajaxform with input type=file and multifile

    - by crunchingnumbers
    Im using ajax form with multifile. However ajaxform just seems to quietly die and does not do anything if using multifile. Multifile is just a jquery plugin that builds a list of input type=file so that you can upload multiple files at once, before which you can add/delete your file upload list. I've looked at multifile and made one change to ensure that it generated a unique name as well as id which it didn't do before and i've checked the form elements multifile is building which all appear to be correct. From looking at ajaxform, it seems that it shoulld just generate the iframe as normal and post the multiple input type=file but it does nothing. Has anyone else experienced problems with multiple input type=file uploads

    Read the article

< Previous Page | 299 300 301 302 303 304 305 306 307 308 309 310  | Next Page >