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  • Android - How can I upload a txt file to a website?

    - by Donal Rafferty
    I want to upload a txt file to a website, I'll admit I haven't looked into it in any great detail but I have looked at a few examples and would like more experienced opinions on whether I'm going in the right direction. Here is what I have so far: DefaultHttpClient httpClient = new DefaultHttpClient(); HttpContext localContext = new BasicHttpContext(); private String ret; HttpResponse response = null; HttpPost httpPost = null; public String postPage(String url, String data, boolean returnAddr) { ret = null; httpClient.getParams().setParameter(ClientPNames.COOKIE_POLICY, CookiePolicy.RFC_2109); httpPost = new HttpPost(url); response = null; StringEntity tmp = null; try { tmp = new StringEntity(data,"UTF-8"); } catch (UnsupportedEncodingException e) { System.out.println("HTTPHelp : UnsupportedEncodingException : "+e); } httpPost.setEntity(tmp); try { response = httpClient.execute(httpPost,localContext); } catch (ClientProtocolException e) { System.out.println("HTTPHelp : ClientProtocolException : "+e); } catch (IOException e) { System.out.println("HTTPHelp : IOException : "+e); } ret = response.getStatusLine().toString(); return ret; } And I call it as follows: postPage("http://www.testwebsite.com", "data/data/com.testxmlpost.xml/files/logging.txt", true)); I want to be able to upload a file from the device to a website. But when trying this way I get the following response back. HTTP/1.1 405 Method Not Allowed Am I trying the correct way or should I be doing it another way?

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  • How can I use different metadata for a Dynamic Data form view and the list view?

    - by ProfK
    We often need a summarised list view with more detailed form view. So far, the only two way I can think of doing this are using a 'custom' list or form view than uses a sumplimentary 'remove' or 'add' list of fields anb generalise this over all entity sets, or create a custom metadata provider that infers somehow which columns to supply. Are there any other ways of distinguishing these two views? PS, I wrote a fun little general details page, that handles insert, edit, and view, all on one page template. Maybe I could somehow use that? It's here.

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  • how to preform an activity at the android lock screen?

    - by John
    I would like to perform an activity at the key guard screen, but the only way I can find to do so is to disable the key guard, do my activity, then re enable the key guard. This would be ok if it didn't cause the key guard screen to flash off and on (disable makes it disappear then re enable brings it back). I am wondering how I can perform an activity with it still being displayed? Kinda like how when the alarm goes off it shows a pop-up which is displayed over the key-guard screen?

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  • [N]Hibernate: view-like fetching properties of associated class

    - by chiccodoro
    (Felt quite helpless in formulating an appropriate title...) In my C# app I display a list of "A" objects, along with some properties of their associated "B" objects and properties of B's associated "C" objects: A.Name B.Name B.SomeValue C.Name Foo Bar 123 HelloWorld Bar Hello 432 World ... To clarify: A has an FK to B, B has an FK to C. (Such as, e.g. BankAccount - Person - Company). I have tried two approaches to load these properties from the database (using NHibernate): A fast approach and a clean approach. My eventual question is how to do a fast & clean approach. Fast approach: Define a view in the database which joins A, B, C and provides all these fields. In the A class, define properties "BName", "BSomeValue", "CName" Define a hibernate mapping between A and the View, whereas the needed B and C properties are mapped with update="false" insert="false" and do actually stem from B and C tables, but Hibernate is not aware of that since it uses the view. This way, the listing only loads one object per "A" record, which is quite fast. If the code tries to access the actual associated property, "A.B", I issue another HQL query to get B, set the property and update the faked BName and BSomeValue properties as well. Clean approach: There is no view. Class A is mapped to table A, B to B, C to C. When loading the list of A, I do a double left-join-fetch to get B and C as well: from A a left join fetch a.B left join fetch a.B.C B.Name, B.SomeValue and C.Name are accessed through the eagerly loaded associations. The disadvantage of this approach is that it gets slower and takes more memory, since it needs to created and map 3 objects per "A" record: An A, B, and C object each. Fast and clean approach: I feel somehow uncomfortable using a database view that hides a join and treat that in NHibernate as if it was a table. So I would like to do something like: Have no views in the database. Declare properties "BName", "BSomeValue", "CName" in class "A". Define the mapping for A such that NHibernate fetches A and these properties together using a join SQL query as a database view would do. The mapping should still allow for defining lazy many-to-one associations for getting A.B.C My questions: Is this possible? Is it [un]artful? Is there a better way?

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  • Xcode: view references for a variable?

    - by David.Chu.ca
    I am new to Xcode. I am not sure if there is a way to view a variable's references just like "Find all references" in Visual Studio by right click on a var? For example, in my .h file, I would like to know or view all the references for property isSet: @interface MyInterface { ... BOOL isSet; // view all references to this var? ... }

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  • CCK NodeReference - Pass current user id as argument to selection view

    - by Chaulky
    Hi all, I'm trying to create a view to limit the options available to a user for a CCK NodeReference field. I want to pass the current user's ID as an argument to the view that selects the options for the CCK NodeReference field. Basically when the user creates a new item, I only want them to be able to reference a node which they created (not someone else's node). I've got a view set up that accepts a user ID as an argument, but how do I pass the current user's ID to the view from the CCK NodeReference field? Thanks in advance!!!

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  • In partial view: "The model item passed into the dictionary is of type"

    - by Dave
    I lack understanding of some basic MVC concepts, despite all my searching. I created an MVC project in Visual Studio, which contains the partial view _LogOnPartial.shtml. I just want to access information within the view pertaining to the user, to put in a user dropdown menu. When I try to put this at the top of the partial view cshtml page I get the above error: @model MyProject_MVC.Models.UserRepository When I try this I also get an error: @Html.Partial("_LogOnPartial", MyProject_MVC.Models.UserRepository) 'MyProject_MVC.Models.UserRepository' is a 'type', which is not valid in the given context

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  • How to determine the current view bounds in split view of Ipad App?

    - by Mahesh
    Hello friends, I have tried following code to determine current view bounds in shouldAutoRotate.. fn UIViewController *temp1 = [appDelegate.splitViewController.viewControllers objectAtIndex:1]; float screenwidth = temp1.view.bounds.size.width; float screenheight = temp1.view.bounds.size.height; bt actually when u rotate from one mode to another, it provides the bound values of old one insted the fresh bound values..? Any one know that how to achieve it?

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  • explaining $this->load->view()

    - by ajsie
    in a controller you can use this method to load a view. but i want to know behind the scenes here. im new to php and frameworks, but i’ve learned the basics of OOP. when $this-view() is made then the method in the current class or the parent class is used. but what does this mean: $this-load-view(). what is the intermediate load? is it a function or is it a property? where is it located? how could it contain view()? grateful for explanation.

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  • Android/Eclipse: Creating multiple builds with different com identifiers.

    - by Dave
    Hi, I have an app that requires two builds - one is a demo app, the other uses the same codebase but uses a flag to introduce different functionality. The identifier must be different each time (e.g. com.siteA.appA and com.siteB.appB). However it doesn't appear to be trivial to use the refactor functionality in Eclipse to change the com identifier - all references change apart from the "import com.siteA.appA.R" reference. Is there a way to create different builds with different com identifiers/app name within Eclipse? Thanks

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  • iPhone crashing when presenting modal view controller

    - by Michael Waterfall
    I'm trying to display a modal view straight after another view has been presented modally (the second is a loading view that appears). - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; // Show load LoadViewController *loader = [[LoadViewController alloc] init]; [self presentModalViewController: loader animated:NO]; [loader release]; } But when I do this I get a "Program received signal: "EXC_BAD_ACCESS"." error. The stack trace is: 0 0x30b43234 in -[UIWindowController transitionViewDidComplete:fromView:toView:] 1 0x3095828e in -[UITransitionView notifyDidCompleteTransition:] 2 0x3091af0d in -[UIViewAnimationState sendDelegateAnimationDidStop:finished:] 3 0x3091ad7c in -[UIViewAnimationState animationDidStop:finished:] 4 0x0051e331 in run_animation_callbacks 5 0x0051e109 in CA::timer_callback 6 0x302454a0 in CFRunLoopRunSpecific 7 0x30244628 in CFRunLoopRunInMode 8 0x32044c31 in GSEventRunModal 9 0x32044cf6 in GSEventRun 10 0x309021ee in UIApplicationMain 11 0x00002154 in main at main.m:14 Any ideas? I'm totally stumped! The loading view is empty so there's definitely nothing going on in there that's causing the error. Is it something to do with launching 2 views modally in the same event loop or something? Thanks, Mike Edit: Very strange... I have modified it slightly so that the loading view is shown after a tiny delay, and this works fine! So it appears to be something within the same event loop! - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; // Show load [self performSelector:@selector(doit) withObject:nil afterDelay:0.1]; } - (void)doit { [self presentModalViewController:loader animated:YES]; }

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  • How to make divider part of each item in listview in android?

    - by sunil
    Hi, I wanted to change the divider height dynamically. From whatever I have searched it seems that it is possible through setting divider as part of each item in listview. But I am not very clear with this. So, can someone be more specific as how can one make the divider as part of item in listview? Can someone please help? Regards Sunil

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  • Why is native libmpg123 taking so long on android with libgdx?

    - by cmbryan
    I'm trying to use the gdx-audio extensions, but am having trouble decoding mp3s. It works, but very slowly!! A 10-second file is taking 6.57 seconds to decode :( Here is the method: public void decode() { Mpg123Decoder decoder = new Mpg123Decoder(externalFile); short[] sampleArray = new short[1024]; // read until we reach the end of the file while (decoder.readSamples(sampleArray, 0, sampleArray.length) > 0) {} } Can anyone tell me why this is taking so long?

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  • How is the Viewflipper handling the back button in Android?

    - by Janusz
    I'm thinking about using a ViewFlipper for an Wizard like Activity. But I see one problem with this approach. The back button. Will the back button go back to the last shown activity or will the the Viewflipper somehow catch the back button event and only change to the last shown activity? I suspect the ViewFlipper to be treated as one Activity on the BackStack so is seems that is the wrong aproach for a wizard. Is this correct?

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  • How to make Android Service run even when the device is not awake?

    - by Deema
    hi my application objective is to save location updates every ,let say, 20 minuets . I used service and it worked fine , but when i lock the screen or it is locked automatically the service stop running . when i unlock it , service runs again. highlight on my code: Service xxx onCreat(){ call timer(); } timer(){ code } How to make my code run all the time in all conditions?

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  • Render partial view with updated value.

    - by janiya
    I am working on asp.net mvc project using views and partial views. Multiple partial views are being rendered in single view. Now my problem is that when ever i update some values in partial view and render it again through controller it does not show partial view with updated value.... to see updated value i have to refresh the page each time.

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  • ANDROID : how to get value stored in ArrayList<HashMap<key,value>>?

    - by Roshni Kyada
    I have ArrayList. At another activity i want to access all values stored in ArrayList. I tried following code. ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>(); for(Hashmap<String, String> map: mylist) { for(Entry<String, String> mapEntry: map) { String key = mapEntry.getKey(); String value = mapEntry.getValue(); } } but it shows an error at for(Entry mapEntry: map) that it only interate over Array.

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