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  • php open_socket

    - by sea_1987
    Hello, I am trying to open a socket to use with secure tradings xpay api, however when I check to see if the socket is open I get error returned, Can't assign requested address I need to open up 127.0.0.1:5000 is there something wring with my code that means I cannot do this? if (isset($xpay_port) and ($socket=socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) and (socket_connect($socket, $address, $port))) { $text="Connection successful on IP $address, port $port"; socket_close($socket); } else $text="Unable to connect<pre>".socket_strerror(socket_last_error())."</pre>"; echo "<html><head></head><body>". $text. "</body></html>";

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  • PHP Xml add edit delete

    - by user560411
    Hi there. I am kind of new and I have the following XML structure an I would like to have codes that INSERTS DELETES Delete an entire element based on it's TITLE value. EDIT Replace Publisher's value with another value <Game type="XXX"> <TITLE>XXX</TITLE> <PUBLISHER>XXX</PUBLISHER> </Game> This is my XML structure <Game type="adventure"> <TITLE>Assassin's Creed: Brotherhood</TITLE> <PUBLISHER>Ubisoft</PUBLISHER> </Game> <Game type="adventure"> <TITLE>Batman: Arkham Asylum</TITLE> <PUBLISHER>Eidos</PUBLISHER> </Game> </GameStore> Any help would be great and thank you in avdance!

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  • Problem with Xpath PHP

    - by user294597
    Im tring to access some links through Google using xpath. The below does works fine and all the links are shown. $query = $xpath->evaluate("/html/body//a"); for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('href'); echo $url."<br>"; } But when i try the below xpath nothing is shown..Im sure that the xpath is correct coz its evaluated and the result is shown in xpather.. /html/body[@id='gsr']/div[@id='cnt']/div[@id='res']/div[1]/ol/li/div//cite for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('cite'); echo $url."<br>"; } can some one please tell me what i am doin wrong? any help will be much appreciated

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  • PHP is not returning me a number type

    - by Tristan
    Hello, i tryed to follow that great tutorial (STAR rating with css : http://stackoverflow.com/questions/1987524/turn-a-number-into-star-rating-display-using-jquery-and-css) but i've just a big problem : When i do <span class="stars">1.75</span> or $foo='1.75'; echo '<span class="stars">'.$foo.'</span> the stars is correctly shown, but as soon as i do : while($val = mysql_fetch_array($result)) { $average = ($val['services'] + $val['serviceCli'] + $val['interface'] + $val['qualite'] + $val['rapport'] ) / 5 ; <span class="stars">.$average.</span> } the stars stops working i double checked the data type in mysql : they're all TINYINT(2) and i tryed that : $average = intval($average); but it's still not working, Thank you

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  • Linux/PHP Question

    - by user369770
    I'm a pretty Huge n00b when it comes to Linux exec ('whoami', $output, $return); echo $return; // Outputs 127 Which means the command is not executing. I can get it to execute when I root into the server. Any help would be greatly appreciated!

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  • php regex - replace on "\${1}"

    - by Qiao
    found this regex: insert " " every 10 characters: $text = preg_replace("|(.{10})|u", "\${1}"." ", $text); can you, please, explain what \${1} means. Why using \ and what curly brackets means?

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  • php foreach getting values from an array

    - by sea_1987
    I am having trouble accessing the values in an array, the array looks like this, Array ( [0] => Array ( [id] => 1661 [code] => 849651318 [job_status] => 4 [looking_for] => Lorem ipsum [keywords_education] => Derby University [sector_id_csv] => 10,21,9,22,26 [last_job_title_1] => Programmer [last_job_employer_1] => HBOS [city] => Bury [expected_salary_level] => LEVEL_2 [education_level] => COLLEGE [job_looking_for] => [is_contract] => Y [is_permanent] => N [is_temporary] => Y ) ) Array ( [0] => Array ( [id] => 402 [code] => 849650059 [job_status] => 3 [looking_for] => Lorem ipsum [keywords_education] => Paris College [sector_id_csv] => 27,22,19,21,12 [last_job_title_1] => Programmer [last_job_employer_1] => HSBC [city] => Bury [expected_salary_level] => LEVEL_2 [education_level] => COLLEGE [job_looking_for] => [is_contract] => N [is_permanent] => Y [is_temporary] => Y ) ) Array ( [0] => Array ( [id] => 1653 [code] => 849651310 [job_status] => 3 [looking_for] => Lorem ipsum [keywords_education] => Crewe University [sector_id_csv] => 27,15,19,21,24 [last_job_title_1] => Programmer [last_job_employer_1] => ICI [city] => Bury [expected_salary_level] => LEVEL_2 [education_level] => UNIVERSITY [job_looking_for] => [is_contract] => N [is_permanent] => Y [is_temporary] => Y ) ) I am trying to get the values out, I have tried doing the following, foreach ($result as $rslt) { echo $rslt->id; } I have also tried, foreach ($result as $rslt) { $rslt['id']; } But none of this works, I dont know why, can anyone help?

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  • php mysql timestamp

    - by user342391
    I need to track the date and time a user was created in my mysql database. I have column called 'created' and the data type as TIMESTAMP. The problem is that when a user changes their password or other information the TIMESTAMP value changes. How can I set this to not change????

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  • Adding "selected" into option from matching variable. PHP

    - by Dolan
    I have $country which stores the 2 letter country code of a user. US for example. <select id="countries"> <option value="US">United States</option> <option value="EN">England</option> <option value="AU">Australia</option> <option value="CA">Canada</option> etc. </select> What's the best practice to add "selected" to the option of the users country code? I'm against adding a million if's. Also note, the countries are harcoded in HTML, so no array. :(

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  • What exactly does this PHP code do?

    - by Rob
    Alright, my friend gave me this code for requesting headers and comparing them to what the header should be. It works perfectly, but I'm not sure why. Here is the code: $headers = apache_request_headers(); $customheader = "Header: 7ddb6ffab28bb675215a7d6e31cfc759"; foreach ($headers as $header => $value) { // 1 $custom .= "$header: $value"; // 2 } $mystring = $custom; // 3 $findme = $customheader; // 4 $pos = strpos($mystring, $findme); if ($pos !== false) { // Do something } else{ exit(); } //If it doesn't match, exit. I commented with some numbers relating to the following questions: 1: What exactly is happening here? Is it setting the $headers as $header AND $value? 2: Again, don't have any idea what is going on here. 3: Why set the variable to a different variable? This is the only area where the variable is getting used, so is there a reason to set it to something else? 4: Same question as 3. I'm sorry if this is a terrible question, but its been bothering me, and I really want to know WHY it works. Well, I understand why it works, I guess I just want to know more specifically. Thanks for any insight you can provide.

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  • [PHP] Read and write to a file while keeping lock

    - by Znarkus
    Hi! I am making a simple page load counter by storing the current count in a file. This is how I want to do this: Lock the file Read the current count Increment it Write new count Unlock file/close it Can this be done? As I understand it, the file can't be written to without losing the lock. The only way I have come up with to tackle this, is to write a character using "r+" mode, and then counting characters.

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  • How to force adodb php library to use lowercase field names

    - by spam
    I'm trying to use adodb for db access in my webapp. However my hosting provider has mysql case sensitive, and I have all my fields in lowercase. But when I call getInsertSQL function, I got them in uppercase. Is there a way to force adodb to use lowercase? I tried with define('ADODB_ASSOC_CASE', 0); $ADODB_ASSOC_CASE = 0; But it seems to be ignored as the constant is suppose to be used only with oracle, MSSQL and other DBMS $conn = &ADONewConnection($this->DbType); $conn = PConnect($dbServer,$dbUser, $dbPassword,$database); $tableName = "sample"; $insertSQL = $conn->GetInsertSQL($tableName,$objDB); And I got the SQL statement with the column names in uppercase.

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  • PHP array pointer craziness

    - by JMan
    I'm trying to create a "GetCurrentLevel" method that takes a point value as an input and returns what "Level" that corresponds to. I'm storing the Level = Points mapping in an array, but the array pointer is not moving logically when I use it a foreach loop. I've added echo statements for debugging. Here's my class definition: class Levels extends Model { protected $_map = array ( 'None' => 0, 'Bronze' => 50, 'Silver' => 200, 'Gold' => 500 ); public function __construct() { parent::__construct(); } public function GetCurrentLevel($points) { foreach ($this->_map as $name => $threshold) { echo "Level Name: $name<br/>"; echo "Level Threshold: $threshold<br/>"; echo "Current Level: " . key($this->_map) . "<br/>"; echo "Current Threshold: " . current($this->_map) . "<br/>"; if ($points < $threshold) /* Threshold is now above the points, so need to go back one level */ { $previousThreshold = prev($this->_map); echo "Previous Threshold: $previousThreshold<br/>"; echo "Final Level: " . key($this->_map) . "<br/>"; return key($this->_map); } echo "Go to next level <br/>"; } } And here is what I see when I call GetCurrentLevel(60): Level Name: None Level Threshold: 0 Current Level: Bronze //* Looks like foreach immediately moves the array pointer *// Current Threshold: 50 Go to next level Level Name: Bronze Level Threshold: 50 Current Level: Bronze //* WTF? Why hasn't the array pointer moved? *// Current Threshold: 50 Go to next level Level Name: Silver Level Threshold: 200 Current Level: Bronze //* WTF? Why hasn't the array pointer moved? *// Current Threshold: 50 Previous Threshold: 0 Final Level: None But the "Final Level" should be 'Bronze' since 60 points is above the 50 points needed for a Bronze medal, but below the 200 points needed for a Silver medal. Sorry for the long post. Thanks for your help!

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  • Use of date function in PHP to output a user-friendly date

    - by Jamie
    I have a MySQL database column named DateAdded. I'd like to echo this as a readable date/time. Here is a simplified version of the code I currently have: $result = mysql_query(" SELECT ListItem, DateAdded FROM lists WHERE UserID = '" . $currentid . "' "); while($row = mysql_fetch_array($result)) { // Make the date look nicer $dateadded = date('d-m-Y',$row['DateAdded']); echo $row['ListItem'] . ","; echo $dateadded; echo "<br />"; } Is the use of the date function the best way to output a user-friendly date? Thanks for taking a look,

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  • PHP Looping....need some advice

    - by Homer_J
    Hi all, I have the following code: $q1 = $_POST["q1"]; $q2 = $_POST["q2"]; $q3 = $_POST["q3"]; $q4 = $_POST["q4"]; $q5 = $_POST["q5"]; $q6 = $_POST["q6"]; $q7 = $_POST["q7"]; $q8 = $_POST["q8"]; At the moment, this is hard coded and I need to manually change it each time, I'd like to use variables instead so that it's not a manual process. Is it a case of using a loop, while or foreach? If I had the the information $q and q in an array would that help? Thanks, Homer.

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  • PHP rewrite giving 404, .htaccess problem?

    - by Hamid
    I have the following .htaccess: #Options +FollowSymLinks RewriteEngine on RewriteBase /phptest on my local testing server (http://localhost) I have to uncomment the first line for the site to work. Otherwise I get Error 403 (Forbidden). Once I upload the page to my webserver (FastHosts) I get Error 500 (Internal Server Error) if the first line is not commented out. If I comment it out, my page loads but it cannot find the page content which is mydomain.com/phptest/Home I get a 404. Any suggestions on what the problem might be?

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  • update mysql db through form in php

    - by DAFFODIL
    I am getting this error, You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' address='xxxxx', city='sssssssss', pincode='333333333', state='Assam', count' at line 1 Thanks in advance. http://dpaste.com/hold/181959/

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  • PHP: Handling Multiple Submit Buttons

    - by sebb
    Would like to get a consensus as to what the best practice is in this scenario: Muliple submit buttons, is it better to handle this by having separate FORMS for each one of the submits, OR is it okay to have one form and check which button was pressed? thank you for your input :D

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  • PHP for loop isn't looping after APC installation

    - by BoRo
    So I installed APC and i all of the sudden my for loops only run once and increment the value then stops. I dont get what's going on, it worked fine before APC was installed. Any Suggestions? EDIT: I managed to narrow it down to the increment. for some reason if I have an array let's say string[], and have the for loop list through the values like with string[$i] It only does it for the first one, I can manually echo/print out the array elements to check if the array is the problem but all elements have the appropriate data/values. EDIT #2: Well the code looks something like (it scrapes a page for images and gets some data from it): $str = explode('<div class="images" align="center">',$str); for($i=1;$i<11;$i++){ $url3 = $str[$i]; $url3 = extstr3($url3,'class="filename">','</div>'); $urlname = extstr3($url3,'<a href="','</a>'); $name = extstr3($urlname,'target="_blank">','.jpg'); $url3 = extstr3($url3,'<a href="','" target="_blank">'); $name = str_replace ('_', ' ', $name); . . .

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