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  • .NET Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program:

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  • Problem with for-loop in python

    - by Protean
    This code is supposed to be able to sort the items in self.array based upon the order of the characters in self.order. The method sort runs properly until the third iteration, unil for some reason the for loop seems to repeat indefinitely. What is going on here? class sorting_class: def __init__(self): self.array = ['ca', 'bd', 'ac', 'ab'] #An array of strings self.arrayt = [] self.globali = 0 self.globalii = 0 self.order = ['a', 'b', 'c', 'd'] #Order of characters self.orderi = 0 self.carry = [] self.leave = [] self.sortedlist = [] def sort(self): for arrayi in self.arrayt: #This should only loop for the number items in self.arrayt. However, the third time this is run it seems to loop indefinitely. print ('run', arrayi) #Shows the problem if self.order[self.orderi] == arrayi[self.globali]: self.carry.append(arrayi) else: if self.globali != 0: self.leave.append(arrayi) def srt(self): self.arrayt = self.array my.sort() #First this runs the first time. while len(self.sortedlist) != len(self.array): if len(self.carry) == 1: self.sortedlist.append(self.carry) self.arrayt = self.leave self.leave = [] self.carry = [] self.globali = 1 self.orderi = 0 my.sort() elif len(self.carry) == 0: if len(self.leave) != 0: #Because nothing matches 'aa' during the second iteration, this code runs the third time" self.arrayt = self.leave self.globali = 1 self.orderi += 1 my.sort() else: self.arrayt = self.array self.globalii += 1 self.orderi = self.globalii self.globali = 0 my.sort() self.orderi = 0 else: #This is what runs the second time. self.arrayt = self.carry self.carry = [] self.globali += 1 my.sort() my = sorting_class() my.srt()

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  • Producing a Form from an Overlay from Reporting Services rdlc Reports

    - by Mike Wills
    I am not sure what you call it in other technologies, on the IBM i (or iSeries) we call it overlays. The overlay is an image of a form that is stored on the server then a program generates the form with fields from the database so you can eliminate preprinted forms. I had a problem last year with the method I was trying at the time. It was a rush job at the time to be revisited at a later point. The work-around at the time was to export to PDF. So now it is "later" and once again is a rush (imagine that). This is all done through a web-based interface. So how do you generate forms from something that was once a preprinted form? What method do you recommend? This is a legal form and must be filled out a certain way and can have many in a batch (up to 50 or so). I would prefer to not have them print one page at a time. Any ideas would be appreciated!

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  • Have you considered doing revenue sharing to fund development of a mobile app? How would you do it?

    - by Brennan
    I am looking to build multiple mobile apps which leverage existing content and resources by enabling these mobile apps with web services. I will duplication much of the same features which are also in place and add more features that are possible on a mobile device like address book, maps and calendar integration to make the service much more useful. To fund these projects I see that I have 2 options. First I could simply quote them for the project based on my hourly rate and the estimate in hours that I will take the to complete the job. That may be a high number. The second option would be to do shared revenue with ads placed in the app. I could then take a percentage of any revenue that is generated from the app. There is also a hybrid where I might charge for a percentage of the estimated quote and then take a percentage of the revenue sharing. So my question is how much should I propose for the revenue sharing? Should it be 30%? Or maybe I should make it 70% up to a point that a certain dollar amount is reached? And should the revenue sharing agreement be for 12 months, 24 months or more? Should I include in the proposal an agreement that they will help promote this app with their content and resources? Ultimately this system will benefit both sides because it extends their reach into the mobile space instead of where they are currently with just print and web. I have tried to find some examples with a few Google searches but I keep hitting content about the Google and Apple revenue sharing models. I would like to get some solid examples that are working to compare against so that my proposal do build these apps is not completely off base.

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  • dynamic lib can't find static lib

    - by renyufei
    env: gcc version 4.4.1 (Ubuntu 4.4.1-4ubuntu9) app: Bin(main) calls dynamic lib(testb.so), and testb.so contains a static lib(libtesta.a). file list: main.c test.h a.c b.c then compile as: gcc -o testa.o -c a.c ar -r libtesta.a testa.o gcc -shared -fPIC -o testb.so b.c gcc -o main main.c -L. -ltesta -ldl then compile success, but runs an error: ./main: symbol lookup error: ./testb.so: undefined symbol: print code as follows: test.h #include <stdio.h> #include <stdlib.h> #include <errno.h> #include <string.h> #include <dlfcn.h> int printa(const char *msg); int printb(const char *msg); a.c #include "test.h" int printa(const char *msg) { printf("\tin printa\n"); printf("\t%s\n", msg); } b.c #include "test.h" int printb(const char *msg) { printf("in printb\n"); printa("called by printb\n"); printf("%s\n", msg); } main.c #include "test.h" int main(int argc, char **argv) { void *handle; int (*dfn)(const char *); printf("before dlopen\n"); handle = dlopen("./testb.so", RTLD_LOCAL | RTLD_LAZY); printf("after dlopen\n"); if (handle == NULL) { printf("dlopen fail: [%d][%s][%s]\n", \ errno, strerror(errno), dlerror()); exit(EXIT_FAILURE); } printf("before dlsym\n"); dfn = dlsym(handle, "printb"); printf("after dlsym\n"); if (dfn == NULL) { printf("dlsym fail: [%d][%s][%s]\n", \ errno, strerror(errno), dlerror()); exit(EXIT_FAILURE); } printf("before dfn\n"); dfn("printb func\n"); printf("after dfn\n"); exit(EXIT_SUCCESS); }

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  • Get Json and output to text file undecoded

    - by Gary
    Hi, I want to fetch json script and write it to a txt file undecoded, exactly how it was originally. I do have a script that I use that I am modifying but unsure what to commands to use. This script decodes, which is what I want to advoid. //Get Age list($bstat,$bage,$bdata) = explode("\t",check_file('./advise/roadsnow.txt',60*2+15)); //Test Age if ( $bage > $CacheMaxAge ) { //echo "The if statement evaluated to true so get new file and reset $bage"; $bage="0"; $file = file_get_contents('http://somesite.jsontxt'); $out = (json_decode($file)); $report = wordwrap($out->mainText, 100, "\n"); //$valid = $out->validTo; //write the data to a text file called roadsnow.txt $myFile = "./advise/roadsnow.txt"; $fh = fopen($myFile, 'w') or die("can't open file"); $stringData = $report; fwrite($fh, $stringData); } else { //echo the test evaluated to false; file is not stale so read local cache //print "we are at the read local cache"; $stringData = file_get_contents("./advise/roadsnow.txt"); } // if/else is done carry on with processing //Format file $data = $stringData

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  • Installing Rails on Mountain Lion

    - by Jordan Medlock
    I was wondering if you could help me find why I cannot install Ruby on Rails on my MBP with OS X Mountain Lion. It's a weird problem and I'll give you as much info as I can. I've installed ruby and it's working at version 1.9.3 And I've installed ruby gems and it's worked for every other gem I've tried to install. It's version is 1.8.24 When I run $ sudo gem install rails it replies with the message: Successfully installed rails-3.2.8 1 gem installed Although when I ask it rails -v it returns: `Rails is not currently installed on this system. To get the latest version, simply type: $ sudo gem install rails You can then rerun your "rails" command.` What should I do? The rails bash file (/usr/bin/rails) contains: #!/usr/bin/ruby # Stub rails command to load rails from Gems or print an error if not installed. require 'rubygems' version = ">= 0" if ARGV.first =~ /^_(.*)_$/ and Gem::Version.correct? $1 then version = $1 ARGV.shift end begin gem 'railties', version or raise rescue Exception puts 'Rails is not currently installed on this system. To get the latest version, simply type:' puts puts ' $ sudo gem install rails' puts puts 'You can then rerun your "rails" command.' exit 0 end load Gem.bin_path('railties', 'rails', version) That must mean that the gem files aren't there or are old or corrupted How can I check that?

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  • View transform seems to be ignored when animating on iphone. Why?

    - by heymon
    I have views that can be rotated, scaled and moved around the screen. I want the view to resize and be orthogonal when the user double tap's the view to edit the textview within. The code is below. Somewhere the transform is getting reset. The NSLog statement below prints the identity transform, but a print of the transform when the animation is complete in transitionDidStop reveals that the transform is what it was before I thought I set it to identity. The view resizes, but it acts like the transform was never set to identity? Any ideas/pointers? originalBounds = self.bounds; originalCenter = self.center; originalTransform = self.transform; r = CGRectMake(0, 0, [UIScreen mainScreen].bounds.size.width - 70, 450); [UIView beginAnimations: nil context: NULL]; [UIView setAnimationDelegate: self]; [UIView setAnimationDidStopSelector: @selector(transitionDidStop:finished:context:)]; self.transform = CGAffineTransformIdentity; NSLog(@"%@ after set", NSStringFromCGAffineTransform([self transform])); [self setBounds: r]; [self setCenter: p]; [self setAlpha: 1.0]; [UIView commitAnimations]; [textView becomeFirstResponder];

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  • ArrayList<Int> Collections.Sort and LineNumberReader Help How to

    - by user1819551
    I have a issue i can't get it to work now let going to the point a explain in the code thanks. This is my class: what I want to do is insert the Integers sort the list and buffer writer in a column with out coma. Now I getting this: [1110018, 1110032, 1110056, 1110059, 1110063, 1110085, 1110096, 1110123, 1110125, 1110185, 1110456, 1110459] I want like this: 111xxxxx 111xxxx xxxx....... I can't do it in single array, have to be in ArrayList. This is my collecting: list.addNumbers(numbers); list.display(); This is my writer: Is buffered coma.write("\n"+list.display()); coma.flush();<br/> Here is my class: public class IdCount {<br/> private ArrayList<Integer> properNumber = new ArrayList<>(); public void addNumbers(Integer numbers) { properNumber.add(numbers); Collections.sort(properNumber); } public String display() { //(I try .toString() Not work) return properNumber.toString(); } My second issue is LineNumberReader: This is my collecting and my writing: try { Reader input = new BufferedReader( new FileReader(inputFile)); try (Scanner in = new Scanner(input)) { while (in.hasNext()) { //(More Code) asp = new LineNumberReader(input); int rom = 0; while (asp.readLine()!=null){ rom++; } System.out.println(rom); coma.write(rom); This one will not write anything an my System Print give me only 12 0 in column.

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  • JNI Stream binary data from C++ to Java

    - by Cliff
    I need help passing binary data into Java. I'm trying to use jbytearray but when the data gets into Java it appears corrupt. Can somebody give me a hand? Here's a snip of some example code. First the native C++ side: printf("Building audio array copy\n"); jbyteArray rawAudioCopy = env-NewByteArray(10); jbyte toCopy[10]; printf("Filling audio array copy\n"); char theBytes[10] = {0,1,2,3,4,5,6,7,8,9}; for (int i = 0; i < sizeof(theBytes); i++) { toCopy[i] = theBytes[i]; } env->SetByteArrayRegion(rawAudioCopy,0,10,toCopy); printf("Finding object callback\n"); jmethodID aMethodId = env->GetMethodID(env->GetObjectClass(obj),"handleAudio","([B)V"); if(0==aMethodId) throw MyRuntimeException("Method not found error",99); printf("Invoking the callback\n"); env->CallVoidMethod(obj,aMethodId, &rawAudioCopy); and then the Java callback method: public void handleAudio(byte[] audio){ System.out.println("Audio supplied to Java [" + audio.length + "] bytes"); byte[] expectedAudio = {0,1,2,3,4,5,6,7,8,9}; for (int i = 0; i < audio.length; i++) { if(audio[i]!= expectedAudio[i]) System.err.println("Expected byte " + expectedAudio[i] + " at byte " + i + " but got byte " + audio[i]); else System.out.print('.'); } System.out.println("Audio passed back accordingly!"); } I get the following output when the callback is invoked: library loaded! Audio supplied to Java [-2019659176] bytes Audio passed back accordingly!

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  • Any merit to a lazy-ish juxt function?

    - by NielsK
    In answering a question about a function that maps over multiple functions with the same arguments (A: juxt), I came up with a function that basically took the same form as juxt, but used map: (defn could-be-lazy-juxt [& funs] (fn [& args] (map #(apply %1 %2) funs (repeat args)))) => ((juxt inc dec str) 1) [2 0 "1"] => ((could-be-lazy-juxt inc dec str) 1) (2 0 "1") => ((juxt * / -) 6 2) [12 3 4] => ((could-be-lazy-juxt * / -) 6 2) (12 3 4) As posted in the original question, I have little clue about the laziness or performance of it, but timing in the REPL does suggest something lazy-ish is going on. => (time (apply (juxt + -) (range 1 100))) "Elapsed time: 0.097198 msecs" [4950 -4948] => (time (apply (could-be-lazy-juxt + -) (range 1 100))) "Elapsed time: 0.074558 msecs" (4950 -4948) => (time (apply (juxt + -) (range 10000000))) "Elapsed time: 1019.317913 msecs" [49999995000000 -49999995000000] => (time (apply (could-be-lazy-juxt + -) (range 10000000))) "Elapsed time: 0.070332 msecs" (49999995000000 -49999995000000) I'm sure this function is not really that quick (the print of the outcome 'feels' about as long in both). Doing a 'take x' on the function only limits the amount of functions evaluated, which probably is limited in it's applicability, and limiting the other parameters by 'take' should be just as lazy in normal juxt. Is this juxt really lazy ? Would a lazy juxt bring anything useful to the table, for instance as a compositing step between other lazy functions ? What are the performance (mem / cpu / object count / compilation) implications ? Is that why the Clojure juxt implementation is done with a reduce and returns a vector ? Edit: Somehow things can always be done simpler in Clojure. (defn could-be-lazy-juxt [& funs] (fn [& args] (map #(apply % args) funs)))

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  • how to return response from post in a variable? jQuery

    - by robertdd
    i use this function to return the response of post: $.sendpost = function(){ return jQuery.post('inc/operations.php', {'operation':'test'}, "json"); }, i want to make something like this: in: $.another = function(){ var sendpost = $.sendpost(); alert(sendpost); } but i get: [object XMLHttpRequest] if i print the object with: jQuery.each(sendpost, function(i, val) { $(".displaydetails").append(i + " => " + val + "<br/>"); }); i get: details abort => function () { x && h.call(x); g("abort"); } dispatchEvent => function dispatchEvent() { [native code] } removeEventListener => function removeEventListener() { [native code] } open => function open() { [native code] } setRequestHeader => function setRequestHeader() { [native code] } onreadystatechange => [xpconnect wrapped nsIDOMEventListener] send => function send() { [native code] } readyState => 4 status => 200 getResponseHeader => function getResponseHeader() { [native code] } responseText => mdaaa from php how to return only the response in the variable?

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  • Pairs from single list

    - by Apalala
    Often enough, I've found the need to process a list by pairs. I was wondering which would be the pythonic and efficient way to do it, and found this on Google: pairs = zip(t[::2], t[1::2]) I thought that was pythonic enough, but after a recent discussion involving idioms versus efficiency, I decided to do some tests: import time from itertools import islice, izip def pairs_1(t): return zip(t[::2], t[1::2]) def pairs_2(t): return izip(t[::2], t[1::2]) def pairs_3(t): return izip(islice(t,None,None,2), islice(t,1,None,2)) A = range(10000) B = xrange(len(A)) def pairs_4(t): # ignore value of t! t = B return izip(islice(t,None,None,2), islice(t,1,None,2)) for f in pairs_1, pairs_2, pairs_3, pairs_4: # time the pairing s = time.time() for i in range(1000): p = f(A) t1 = time.time() - s # time using the pairs s = time.time() for i in range(1000): p = f(A) for a, b in p: pass t2 = time.time() - s print t1, t2, t2-t1 These were the results on my computer: 1.48668909073 2.63187503815 1.14518594742 0.105381965637 1.35109519958 1.24571323395 0.00257992744446 1.46182489395 1.45924496651 0.00251388549805 1.70076990128 1.69825601578 If I'm interpreting them correctly, that should mean that the implementation of lists, list indexing, and list slicing in Python is very efficient. It's a result both comforting and unexpected. Is there another, "better" way of traversing a list in pairs? Note that if the list has an odd number of elements then the last one will not be in any of the pairs. Which would be the right way to ensure that all elements are included? I added these two suggestions from the answers to the tests: def pairwise(t): it = iter(t) return izip(it, it) def chunkwise(t, size=2): it = iter(t) return izip(*[it]*size) These are the results: 0.00159502029419 1.25745987892 1.25586485863 0.00222492218018 1.23795199394 1.23572707176 Results so far Most pythonic and very efficient: pairs = izip(t[::2], t[1::2]) Most efficient and very pythonic: pairs = izip(*[iter(t)]*2) It took me a moment to grok that the first answer uses two iterators while the second uses a single one. To deal with sequences with an odd number of elements, the suggestion has been to augment the original sequence adding one element (None) that gets paired with the previous last element, something that can be achieved with itertools.izip_longest().

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  • C standard addressing simplification inconsistency

    - by Chris Lutz
    Section §6.5.3.2 "Address and indirection operators" ¶3 says (relevant section only): The unary & operator returns the address of its operand. ... If the operand is the result of a unary * operator, neither that operator nor the & operator is evaluated and the result is as if both were omitted, except that the constraints on the operators still apply and the result is not an lvalue. Similarly, if the operand is the result of a [] operator, neither the & operator nor the unary * that is implied by the [] is evaluated and the result is as if the & operator were removed and the [] operator were changed to a + operator. ... This means that this: int *i = NULL; printf("%p", (void *) (&*i) ); printf("%p", (void *) (&i[10]) ); Should be perfectly legal, printing the null pointer (probably 0) and the null pointer plus 10 (probably 10). The standard seems very clear that both of those cases are required to be optimized. However, it doesn't seem to require the following to be optimized: struct { int a; short b; } *s = 0; printf("%p", (void *) (&s->b) ); This seems awfully inconsistent. I can see no reason that the above code shouldn't print the null pointer plus sizeof(int) (possibly 4). Simplifying a &-> expression is going to be the same conceptually (IMHO) as &[], a simple address-plus-offset. It's even an offset that's going to be determinable at compile time, rather than potentially runtime with the [] operator. Is there anything in the rationale about why this is so seemingly inconsistent?

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  • need to display info for user within active-directory

    - by Brad
    The following code will search for the user within the domain controller, but I want to display the info of each thing noted within the justthese variable: "displayname","mail","samaccountname","sn","givenname","department","telephonenumber" $dn = "dc=xxx,dc=xxx"; $justthese = array("displayname","mail","samaccountname","sn","givenname","department","telephonenumber"); $sr=ldap_search($ldapconn, $dn,'SAMAccountName=username', $justthese); $info = ldap_get_entries($ldapconn, $sr); echo "<h3>".$info["count"]." entries returned</h3>"; foreach($justthese as $key=>$value){ print '<p><strong>'.$value.'</strong></p>'; } It displays each item within the $justthese array, I want to display the info for that user for each thing noted in $justthese array. Right now it outputs it like this: displayname mail samaccountname sn givenname department telephonenumber I want it to have the actual data to the right of it, which I know I am doing something wrong with the foreach loop, any help is appreciated. So it'd look like this displayname Chuck mail [email protected] samaccountname chucknorris sn chuckisthebest givenname Chuck Norris department Security telephonenumber 555-555-5555

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  • PowerPoint Printing Problem c# - Nothing gets printed.

    - by Zeeshan Ahmad
    Guys, i am trying to print powerpoint docs through my windows application in c#. I am using Microsoft.Office.Interop.PowerPoint for this functionality. Following is the code which I have used. It sends the request to printer but nothing gets printed. if you guys have any knowledge plz help. string filename = "C:\\test.ppt"; int copies = 1; Microsoft.Office.Interop.PowerPoint.Presentation work = null; Microsoft.Office.Interop.PowerPoint.Application app = new Microsoft.Office.Interop.PowerPoint.ApplicationClass(); Microsoft.Office.Interop.PowerPoint.Presentations presprint = app.Presentations; work = presprint.Open(filename, Microsoft.Office.Core.MsoTriState.msoCTrue, Microsoft.Office.Core.MsoTriState.msoCTrue, Microsoft.Office.Core.MsoTriState.msoFalse); //app.Visible = Microsoft.Office.Core.MsoTriState.msoTrue; work.PrintOptions.PrintInBackground = Microsoft.Office.Core.MsoTriState.msoFalse; //work.PrintOptions.PrintInBackground = Microsoft.Office.Core.MsoTriState.msoTrue; //work.PrintOptions.ActivePrinter = "HP LaserJet 5000 Series PCL6"; work.PrintOptions.ActivePrinter = app.ActivePrinter; work.PrintOut(1, work.Slides.Count, app.ActivePrinter, copies, Microsoft.Office.Core.MsoTriState.msoFalse); work.Close(); app.Quit();`

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  • Syntax error beyond end of program

    - by a_m0d
    I am experimenting with writing a toy compiler in ocaml. Currently, I am trying to implement the offside rule for my lexer. However, I am having some trouble with the ocaml syntax (the compiler errors are extremely un-informative). The code below (33 lines of it) causes an error on line 34, beyond the end of the source code. I am unsure what is causing this error. open Printf let s = (Stack.create():int Stack.t); let rec check x = ( if Stack.is_empty s then Stack.push x s else if Stack.top s < x then ( Stack.push x s; printf "INDENT\n"; ) else if Stack.top s > x then ( printf "DEDENT\n"; Stack.pop s; check x; ) else printf "MATCHED\n"; ); let main () = ( check 0; check 4; check 6; check 8; check 5; ); let _ = Printexc.print main () Ocaml output: File "lexer.ml", line 34, characters 0-0: Error: Syntax error Can someone help me work out what the error is caused by and help me on my way to fixing it?

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  • How spoof referrer using curl

    - by golu molu
    I am using curl code below to spoof referrer , it works fine but there is error on every page - Curl error: $url = somesite.com function doMagic($url) { $curl = curl_init(); $header[0] = "Accept: text/xml,application/xml,application/xhtml+xml,"; $header[0] .= "text/html;q=0.9,text/plain;q=0.8,image/png,*/*;q=0.5"; $header[] = "Cache-Control: max-age=0"; $header[] = "Connection: keep-alive"; $header[] = "Keep-Alive: 300"; $header[] = "Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7"; $header[] = "Accept-Language: en-us,en;q=0.5"; $header[] = "Pragma: "; curl_setopt($curl, CURLOPT_URL, $url); curl_setopt($curl, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:7.0.1) Gecko/20100101 Firefox/7.0.12011-10-16 20:23:00"); curl_setopt($curl, CURLOPT_HTTPHEADER, $header); curl_setopt($curl, CURLOPT_REFERER, "http://www.facebook.com"); curl_setopt($curl, CURLOPT_ENCODING, "gzip,deflate"); curl_setopt($curl, CURLOPT_AUTOREFERER, true); curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl, CURLOPT_TIMEOUT, 30); curl_setopt($curl, CURLOPT_FOLLOWLOCATION,true); $html = curl_exec($curl); echo 'Curl error: '. curl_error($curl); curl_close($curl); return $html; } $text = doMagic($url); print("$text"); what i'm doing wrong?

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  • Scanner error that I can't figure out: NoSuchElementException

    - by iaacp
    It's crashing on the third line inside the do-while loop, and doesn't wait for my input: input = kb.nextInt(); Stack trace: Exception in thread "main" java.util.NoSuchElementException at java.util.Scanner.throwFor(Unknown Source) at java.util.Scanner.next(Unknown Source) at java.util.Scanner.nextInt(Unknown Source) at java.util.Scanner.nextInt(Unknown Source) at main.MainDriver.main(MainDriver.java:50) Relevant code: do { displayFullMenu(); System.out.print("Selection: "); input = kb.nextInt(); switch (input) { //Create new survey case 1: currentSurvey = new Survey(); break; //Display current survey case 2: currentSurvey.display(); break; //Save current survey case 3: saveSurvey(currentSurvey); break; //Load a survey case 4: currentSurvey = loadSurvey(); break; //Modify a survey case 5: currentSurvey.modify(); break; /*******************Test Functions*******************/ //Create new test case 6: currentSurvey = new Test(); break; //Display current test case 7: currentSurvey.display(); break; //Save current test case 8: saveSurvey(currentSurvey); break; //Load a test case 9: currentSurvey = loadTest(); break; //Modify a test case 10: currentSurvey.modify(); default: System.out.println("Invalid choice. Please make a valid choice: "); input = kb.nextInt(); System.out.println(); } } while (input != 99); kb.close(); It crashes after I choose option 9. It saves the file correctly, then goes back to the top of the loop, and crashes at the previously mentioned line. I want it to ask for more input. What gives?

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  • python global variable not working in apache

    - by Suhail
    I am facing issue with the global variable, when i run in the django development server it works fine, but in apache it doesn't work here is the code below: red= "/foodfolio3/test/" def showAddRecipe(request): #global objc if "userid" in request.session: objc["ErrorMsgURL"]= "" try: urlList= request.POST URL= str(urlList['url']) URL= URL.strip('http://') URL= "http://" + URL recipe= __addRecipeUrl__(URL) if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'): #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" print "here global_context =", objc arurl= HttpResponseRedirect("/foodfolio3/add/import/") arurl['ErrorMsgURL']= objc["ErrorMsgURL"] #return HttpResponseRedirect("/foodfolio3/add/import/") #return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) return (arurl) else: objc["recipe"] = recipe return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) except: objc["recipe"] = "" return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/" return HttpResponseRedirect("/foodfolio3/login") def showAddRecipeUrl(request): if "userid" in request.session: return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/import/" return HttpResponseRedirect("/foodfolio3/login") def showLogin(request): obj = {} obj["error_message"] = "" obj["registered"] = "" if request.method == "POST": if (red == "/foodfolio3/test"): next= '/foodfolio3/recipes' else: next= red try: username = request.POST['username'] password = request.POST['password'] user = authenticate(username=username, password=password) except: user = authenticate(request=request) if user is not None: if user.is_active: login(request, user) request.session["userid"] = user.id # Redirect to a success page. return HttpResponseRedirect(next) this code works fine in django development server, but in apache, the url is getting redirected to '/foodfolio3/recipes'

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  • passing data from a servlet to javascript code in an Ajax application ?

    - by A.S al-shammari
    I have a simple jsp/servlet application and I want to add AJAX feature to this app. I use JQuery , but it doesn't matter what javascript framework I use. This is my code: <script type="text/javascript"> function callbackFunction(data){ $('#content').html(data); } $('document').ready(function(){ $('#x').click(function() { $.post('/ajax_2/servlet',callbackFunction) }); }); </script> <body> <a href="#" id="x">Increase it</a> <div id="content"></div> </body> </html> Servlet HttpSession session = request.getSession(); Integer myInteger = (Integer)session.getAttribute("myInteger"); if(myInteger == null) myInteger = new Integer(0); else myInteger = new Integer(myInteger+1); session.setAttribute("myInteger", myInteger); response.getWriter().println(myInteger); The Question: I use out.print to transfer data from a servlet to javascript code (ajax code) , but If I have a complex structure such as Vector of Object or something like this , what is the best way to transfer the data? what about an XML file , JSON ? Is there any special jsp/servlets library to transfer data from a servlet to ajax application ? How can I parse this data in callbackFunction ?

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  • Need Associated ID Added to a While Loop (php)

    - by user319361
    Been trying to get my head around while loops for the last few days but the code seems very inefficient for what Im trying to achieve. I'm assuming I'm overcomplicating this though nothing I've tried seems to work. Each topic in my forum can have related topic IDs stored in a seperate table. A post ID is also stored in this table, as that specific post references why they are considered related. DB Table contains only: topic_id, related_id, post_id // Get related IDs and post IDs for current topic being viewed $result = $db->query('SELECT related_id, post_id FROM related_topics WHERE topic_id='.$id.''); // If related topics found, put both of the IDs into arrays if ($db->num_rows($result)) { while($cur_related = mysql_fetch_array($result)){ $reltopicarray[] = $cur_related['related_id']; $relpost[] = $cur_related['post_id']; } // If the first array isnt empty, get some additional info about each related ID from another table if(!empty($reltopicarray)) { $pieces = $reltopicarray; $glued = "\"".implode('", "', $pieces)."\""; $fetchtopics = $db->query('SELECT id, subject, author, image, etc FROM topics WHERE id IN('.$glued.')'); } // Print each related topic while($related = mysql_fetch_array($fetchtopics)){ ?> <a href="view.php?id=<?php echo $related['id']; ?>"><?php echo $related['subject']; ?></a> by <?php echo $related['author']; ?> // Id like to show the Post ID below (from the array in the first while loop) // The below link doesnt work as Im outside the while loop by this point. <br /><a href="view.php?post_id=<?php echo $cur_related['post_id']; ?>">View Relationship</a> <?php } ?> The above currently works, however I'm trying to also display the post_id link below each related topic link, as shown above. Would be greatful if someone can lend a hand. Thanks :)

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  • Glob() filesearch, question

    - by Peter
    Hi, a little question. I have this code, which is works perfect for files, but If am trying search on a directory name, the result is blank. How I can fix that? <?php function listdirs($dir,$search) { static $alldirs = array(); $dirs = glob($dir."*"); foreach ($dirs as $d){ if(is_file($d)){ $filename = pathinfo($d); if(eregi($search,$filename['filename'])){ print "<a href=http://someurl.com/" . $d .">". $d . "</a><br/>"; } }else{ listdirs($d."/",$search); } } } $path = "somedir/"; $search= "test"; listdirs($path,$search); ?> somedir/test/ result: blank (I want: /somedir/test/) somedir/test/test.txt result: OK I want to search also in the directory names, how I can do that?

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  • Can't seem to sign AWS Cloud Front URL properly

    - by Joe Corkery
    Hi everybody, I found a lot of detailed examples online on how to sign an Amazon CloudFront URL for private content. Unfortunately, whenever I implement these examples my URL doesn't seem to work. The resource path is correct because I can download the file when it is set for world read, but the URL doesn't work when set just for authorized users. The PHP code I am using is below. If anybody has any insights as to what I might be doing wrong (I'm guessing it is something obvious that I am just not seeing right now), it would be greatly appreciated. function urlCloudFront($resource) { $AWS_CF_KEY = 'APKA...'; $priv_key = file_get_contents(path_to_pem_file); $pkeyid = openssl_get_privatekey($priv_key); $expires = strtotime("+ 3 hours"); $policy_str = '{"Statement":[{"Resource":"'.$resource.'","Condition":{"DateLessThan":{"AWS:EpochTime":'.$expires.'}}}]}'; $policy_str = trim( preg_replace( '/\s+/', '', $policy_str ) ); $res = openssl_sign($policy_str, $signature, $pkeyid, OPENSSL_ALGO_SHA1); $signature_base64 = (base64_encode($signature)); $repl = array('+' => '-','=' => '_','/' => '~'); $signature_base64 = strtr($signature_base64,$repl); $url = $resource . '?Expires=' .$expires. '&Signature=' . $signature_base64 . '&Key-Pair-Id='. $AWS_CF_KEY; print '<p><A href="' .$url. '">Download VIDA (CloudFrount)</A>'; } urlCloudFront("http://mydistcloud.cloudfront.net/mydir/myfile.tar.gz"); Thanks.

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  • How do I return an array from a method?

    - by dwwilson66
    I'm trying to create a deck of cards for my homework. Code is posted below. I need to create four sets of cards (the four suits) and am create a multidimensional array. When I print the results instead of trying to pass the array, I can see that the data in the array is as expected. However, when I try to pass the array card, I get an error cannot find symbol. I've got this modeled after texbook and Java tutorial examples, and I need some help figuring out what I'm missing. I've over-documented to give an idea of how I'm thinking this SHOULD work...please let me know where I've gone horribly wrong in my understanding. import java.util.*; import java.lang.*; // public class CardGame { public static int[][] main(String[] args) { int[][] startDeck = deckOfCards(); /* cast new deck as int[][], calling method deckOfCards System.out.println(" /// from array: " + Arrays.deepToString(startDeck)); } public static int[][] deckOfCards() /* method to return a multi-dimensional array */ { int rank; int suit; for(rank=1;rank<14;rank++) /* cards 1 - 13 .... */ { for(suit=1;suit<5;suit++) /* suits 1 - 4 .... */ { int[][] card = new int[][] /* define a new card... */ { {rank,suit} /* with rank/suit from for... loops */ }; System.out.println(" /// from array: " + Arrays.deepToString(card)); } } return card; /* Error: cannot find symbol } }

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