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  • How to set up port forwarding and firewall settings for torrents using Transmsission on Mac OSX 10.5

    - by Liz
    I have picked up bits of advice here and there on the internet and got someway through this tortuous exercise (after it took 18 hours to download the first torrent I tried yesterday - magnet-link for a film). Where I have got stuck is with configuring the firewall on the Netgear Router but I am not sure if I have caused the problem myself by something else I have done configuring the Mac System Preferences for Security or Networking. I have been following the sections of these instructions that seem to apply, although they are written for a different OSX version (don't know which one, but the screen shots do not match what I see) and I am not wanting to set up my Mac as a server and attending to the parts that apply to port forwarding for Netgear rather than LinkSys: http://homepage.mac.com/car1son/static_port_fwd_intro.html I have been trying to follow these instructions: Instructions for DG834, DG834G, DG824M, FR114W, FM114P, FR114P, FR328S, FVL328, FVS328, FVS338, FVX538, FWAG114, FWG114P, or FVS318v3 These routers do port forwarding by assigning port numbers to a "service" associated with the application you want to run. "Rules" are set for particular services. Rules block or allow access, based on various conditions such as the time of day and the name of the service. To Create a New Inbound or Outbound Rule 1. Submit the router's address in an Internet browser. (The default is 192.168.0.1). 2. Enter the router's username and password. 3. From the main menu, click Security > Rules. 4. Click Add for inbound or outbound traffic, as appropriate to the application you are planning to run. 5. Select the Service. The services the router knows about are listed in the drop down. If the service you want is not listed, add it as described in the next section. 6. Select the Action, for example ALLOW always. 7. For Send to LAN Server, enter the IP address of the local server. Note that this is also the IP address the computers on your LAN will access. 8. For WAN User choose Any, or limit access to particular IP addresses. 9. For Log selection it is reasonable to turn logs on, especially at the beginning when you are unsure of the result of the changes you are making. Later, you may want to set logs to "Never" for performance reasons. 10. Click Apply. As noted in user manual for some models: * Consider using the Dynamic DNS feature on the Advanced menu, so that external users can find your network when the DHCP lease is renewed by your ISP. * If your own LAN server uses DHCP, and your IPs change on rebooting, consider using the Reserved IP Address feature in the LAN IP menu. To Add a Service for These Routers 1. Click Security > Services > Add Custom Service. 2. Enter any name you choose for the service. 3. Select whether the service is to use TCP or UDP. If you are unsure, select both. 4. Enter the lowest port number used by the service. 5. Enter the highest port number used. If the service uses only one port number, enter the same number. 6. Click Apply. There is no "Security - Rules" submenu in the Netgear page, so I have been trying to access "Security - Firewall Rules". I can access everthing else in the Netgear settings as Admin but I cannot get the "Firewall Rules" section to open up. (I am not 100% sure I will know exactly what to do if and when I do get it opened up!) I haven't managed to find though searching the internet any instructions that would seem to apply specifically to what I am trying to achieve, so would be very grateful if someone could either point me in the right direction or give me some advice directly. Best wishes, Liz

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  • WPF Templates error - "Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw

    - by jasonk
    I've just started experimenting with WPF templates vs. styles and I'm not sure what I'm doing wrong. The goal below is to alternate the colors of the options in the menu. The code works fine with just the , but when I copy and paste/rename it for the second segment of "MenuChoiceOdd" I get the following error: Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw an exception. Sample of the code: <Window x:Class="WpfApplication1.Template_Testing" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="Template_Testing" Height="300" Width="300"> <Grid> <Grid.Resources> <ControlTemplate x:Key="MenuChoiceEven"> <Border BorderThickness="1" BorderBrush="#FF4A5D80"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="0" Width="Auto" FontSize="14" Foreground="SlateGray" TextAlignment="Left" AllowDrop="True" Text="{Binding Path=Content, RelativeSource={RelativeSource TemplatedParent}}"> <TextBlock.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="#FFC2CCDB" Offset="1" /> </LinearGradientBrush> </TextBlock.Background> </TextBlock> </Border> </ControlTemplate> <ControlTemplate x:Key="MenuChoiceOdd"> <Border BorderThickness="1" BorderBrush="#FF4A5D80"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="0" Width="Auto" FontSize="14" Foreground="SlateGray" TextAlignment="Left" AllowDrop="True" Text="{Binding Path=Content, RelativeSource={RelativeSource TemplatedParent}}"> <TextBlock.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="##FFCBCBCB" Offset="1" /> </LinearGradientBrush> </TextBlock.Background> </TextBlock> </Border> </ControlTemplate> </Grid.Resources> <Border BorderBrush="SlateGray" BorderThickness="2" Margin="10" CornerRadius="10" Background="LightSteelBlue" Width="200"> <StackPanel Margin="4"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="2,2,2,0" Name="MenuHeaderTextBlock" Text="TextBlock" Width="Auto" FontSize="16" Foreground="PaleGoldenrod" TextAlignment="Left" Padding="10" FontWeight="Bold"><TextBlock.Background><LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"><GradientStop Color="LightSlateGray" Offset="0" /><GradientStop Color="DarkSlateGray" Offset="1" /></LinearGradientBrush></TextBlock.Background></TextBlock> <StackPanel Height="Auto" HorizontalAlignment="Stretch" Margin="2,0,2,0" Name="MenuChoicesStackPanel" VerticalAlignment="Top" Width="Auto"> <Button Template="{StaticResource MenuChoiceEven}" Content="Test Even menu element" /> <Button Template="{StaticResource MenuChoiceOdd}" Content="Test odd menu element" /> </StackPanel> </StackPanel> </Border> </Grid> </Window> What am I doing wrong?

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  • camera preview portrait problem in android application

    - by sujitjitu
    Hi this is my code for simple camera application in android .i have copied it from unlocking android e-book . Everything is working fine in emulator but when i am installing it in device the camera preview is working only in landscape mode. I have tried many thing but could not find any solution. Please see the code below and if you have any solution for it than it will be helpful to me. this is the code....... public class SimpleCamera extends Activity implements SurfaceHolder.Callback { private Camera camera; private boolean isPreviewRunning = false; private SimpleDateFormat timeStampFormat = new SimpleDateFormat("yyyyMMddHHmmssSS"); private SurfaceView surfaceView; private SurfaceHolder surfaceHolder; private Uri targetResource = Media.EXTERNAL_CONTENT_URI; public void onCreate(Bundle icicle) { super.onCreate(icicle); Window window = getWindow(); window.addFlags(WindowManager.LayoutParams.FLAG_KEEP_SCREEN_ON); window.addFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN); getWindow().setFormat(PixelFormat.TRANSLUCENT); setContentView(R.layout.main); surfaceView = (SurfaceView)findViewById(R.id.surface); surfaceHolder = surfaceView.getHolder(); surfaceHolder.getSurface(); // Surface.setOrientation(Display.DEFAULT_DISPLAY,Surface.ROTATION_180); //didn't work at all surfaceHolder.addCallback(this); surfaceHolder.setType(SurfaceHolder.SURFACE_TYPE_PUSH_BUFFERS); } public boolean onCreateOptionsMenu(android.view.Menu menu) { MenuItem item = menu.add(0, 0, 0, "View Pictures"); item.setOnMenuItemClickListener(new MenuItem.OnMenuItemClickListener() { public boolean onMenuItemClick(MenuItem item) { Intent intent = new Intent(Intent.ACTION_VIEW, targetResource); startActivity(intent); return true; } }); return true; } protected void onRestoreInstanceState(Bundle savedInstanceState) { super.onRestoreInstanceState(savedInstanceState); } Camera.PictureCallback mPictureCallbackRaw = new Camera.PictureCallback() { public void onPictureTaken(byte[] data, Camera c) { camera.startPreview(); } }; Camera.ShutterCallback mShutterCallback = new Camera.ShutterCallback() { public void onShutter() { } }; public boolean onKeyDown(int keyCode, KeyEvent event) { ImageCaptureCallback camDemo = null; if(keyCode == KeyEvent.KEYCODE_DPAD_CENTER) { try { String filename = timeStampFormat.format(new Date()); ContentValues values = new ContentValues(); values.put(Media.TITLE, filename); values.put(Media.DESCRIPTION, "Image from Android Emulator"); Uri uri = getContentResolver().insert(Media.EXTERNAL_CONTENT_URI, values); camDemo = new ImageCaptureCallback( getContentResolver().openOutputStream(uri)); } catch(Exception ex ){ } } if (keyCode == KeyEvent.KEYCODE_BACK) { return super.onKeyDown(keyCode, event); } if (keyCode == KeyEvent.KEYCODE_DPAD_CENTER) { camera.takePicture(mShutterCallback, mPictureCallbackRaw, camDemo); return true; } return false; } protected void onResume() { Log.e(getClass().getSimpleName(), "onResume"); super.onResume(); } protected void onSaveInstanceState(Bundle outState) { super.onSaveInstanceState(outState); } protected void onStop() { super.onStop(); } public void surfaceChanged(SurfaceHolder holder, int format, int w, int h) { if (isPreviewRunning) { camera.stopPreview(); } Camera.Parameters p = camera.getParameters(); p.setPreviewSize(w,h); //p.set("rotation","90"); // it didn't work //P.setRotation(90); // only work in 2.0 or later SDK but i am using 1.5 camera.setParameters(p); try { camera.setPreviewDisplay(holder); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } camera.startPreview(); isPreviewRunning = true; } public void surfaceCreated(SurfaceHolder holder) { camera = Camera.open(); } public void surfaceDestroyed(SurfaceHolder holder) { camera.stopPreview(); isPreviewRunning = false; camera.release(); } } any help will be appreciated..

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  • Best style for Python programs: what do you suggest?

    - by Noctis Skytower
    A friend of mine wanted help learning to program, so he gave me all the programs that he wrote for his previous classes. The last program that he wrote was an encryption program, and after rewriting all his programs in Python, this is how his encryption program turned out (after adding my own requirements). #! /usr/bin/env python ################################################################################ """\ CLASS INFORMATION ----------------- Program Name: Program 11 Programmer: Stephen Chappell Instructor: Stephen Chappell for CS 999-0, Python Due Date: 17 May 2010 DOCUMENTATION ------------- This is a simple encryption program that can encode and decode messages.""" ################################################################################ import sys KEY_FILE = 'Key.txt' BACKUP = '''\ !"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNO\ PQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~ _@/6-UC'GzaV0%5Mo9g+yNh8b">Bi=<Lx [sQn#^R.D2Xc(\ Jm!4e${lAEWud&t7]H\`}pvPw)FY,Z~?qK|3SOfk*:1;jTrI''' ################################################################################ def main(): "Run the program: loads key, runs processing loop, and saves key." encode_map, decode_map = load_key(KEY_FILE) try: run_interface_loop(encode_map, decode_map) except SystemExit: pass save_key(KEY_FILE, encode_map) def run_interface_loop(encode_map, decode_map): "Shows the menu and runs the appropriate command." print('This program handles encryption via a customizable key.') while True: print('''\ MENU ==== (1) Encode (2) Decode (3) Custom (4) Finish''') switch = get_character('Select: ', tuple('1234')) FUNC[switch](encode_map, decode_map) def get_character(prompt, choices): "Gets a valid menu option and returns it." while True: sys.stdout.write(prompt) sys.stdout.flush() line = sys.stdin.readline()[:-1] if not line: sys.exit() if line in choices: return line print(repr(line), 'is not a valid choice.') ################################################################################ def load_key(filename): "Gets the key file data and returns encoding/decoding dictionaries." plain, cypher = open_file(filename) return dict(zip(plain, cypher)), dict(zip(cypher, plain)) def open_file(filename): "Load the keys and tries to create it when not available." while True: try: with open(filename) as file: plain, cypher = file.read().split('\n') return plain, cypher except: with open(filename, 'w') as file: file.write(BACKUP) def save_key(filename, encode_map): "Dumps the map into two buffers and saves them to the key file." plain = cypher = str() for p, c in encode_map.items(): plain += p cypher += c with open(filename, 'w') as file: file.write(plain + '\n' + cypher) ################################################################################ def encode(encode_map, decode_map): "Encodes message for the user." print('Enter your message to encode (EOF when finished).') message = get_message() for char in message: sys.stdout.write(encode_map[char] if char in encode_map else char) def decode(encode_map, decode_map): "Decodes message for the user." print('Enter your message to decode (EOF when finished).') message = get_message() for char in message: sys.stdout.write(decode_map[char] if char in decode_map else char) def custom(encode_map, decode_map): "Allows user to edit the encoding/decoding dictionaries." plain, cypher = get_new_mapping() for p, c in zip(plain, cypher): encode_map[p] = c decode_map[c] = p ################################################################################ def get_message(): "Gets and returns text entered by the user (until EOF)." buffer = [] while True: line = sys.stdin.readline() if line: buffer.append(line) else: return ''.join(buffer) def get_new_mapping(): "Prompts for strings to edit encoding/decoding maps." while True: plain = get_unique_chars('What do you want to encode from?') cypher = get_unique_chars('What do you want to encode to?') if len(plain) == len(cypher): return plain, cypher print('Both lines should have the same length.') def get_unique_chars(prompt): "Gets strings that only contain unique characters." print(prompt) while True: line = input() if len(line) == len(set(line)): return line print('There were duplicate characters: please try again.') ################################################################################ # This map is used for dispatching commands in the interface loop. FUNC = {'1': encode, '2': decode, '3': custom, '4': lambda a, b: sys.exit()} ################################################################################ if __name__ == '__main__': main() For all those Python programmers out there, your help is being requested. How should the formatting (not necessarily the coding by altered to fit Python's style guide? My friend does not need to be learning things that are not correct. If you have suggestions on the code, feel free to post them to this wiki as well.

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  • drupal_get_form is not passing along node array

    - by ElectronicBlacksmith
    I have not been able to get drupal_get_form to pass on the node data. Code snippets are below. The drupal_get_form documentation (api.drupal.org) states that it will pass on the extra parameters. I am basing the node data not being passed because (apparently) $node['language'] is not defined in hook_form which causes $form['qqq'] not to be created and thus the preview button shows up. My goal here is that the preview button show up using path "node/add/author" but doesn't show up for "milan/author/add". Any alternative methods for achieving this goal would be helpful but the question I want answered is in the preceding paragraph. Everything I've read indicates that it should work. This menu item $items['milan/author/add'] = array( 'title' = 'Add Author', 'page callback' = 'get_author_form', 'access arguments' = array('access content'), 'file' = 'author.pages.inc', ); calls this code function get_author_form() { //return node_form(NULL,NULL); //return drupal_get_form('author_form'); return author_ajax_form('author'); } function author_ajax_form($type) { global $user; module_load_include('inc', 'node', 'node.pages'); $types = node_get_types(); $type = isset($type) ? str_replace('-', '_', $type) : NULL; // If a node type has been specified, validate its existence. if (isset($types[$type]) && node_access('create', $type)) { // Initialize settings: $node = array('uid' = $user-uid, 'name' = (isset($user-name) ? $user-name : ''), 'type' = $type, 'language' = 'bbb','bbb' = 'TRUE'); $output = drupal_get_form($type .'_node_form', $node); } return $output; } And here is the hook_form and hook_form_alter code function author_form_author_node_form_alter(&$form, &$form_state) { $form['author']=NULL; $form['taxonomy']=NULL; $form['options']=NULL; $form['menu']=NULL; $form['comment_settings']=NULL; $form['files']=NULL; $form['revision_information']=NULL; $form['attachments']=NULL; if($form["qqq"]) { $form['buttons']['preview']=NULL; } } function author_form(&$node) { return make_author_form(&$node); } function make_author_form(&$node) { global $user; $type = node_get_types('type', $node); $node = author_make_title($node); drupal_set_breadcrumb(array(l(t('Home'), NULL), l(t($node-title), 'node/' . $node-nid))); $form['authorset'] = array( '#type' = 'fieldset', '#title' = t('Author'), '#weight' = -50, '#collapsible' = FALSE, '#collapsed' = FALSE, ); $form['author_id'] = array( '#access' = user_access('create pd_recluse entries'), '#type' = 'hidden', '#default_value' = $node-author_id, '#weight' = -20 ); $form['authorset']['last_name'] = array( '#type' = 'textfield', '#title' = t('Last Name'), '#maxlength' = 60, '#default_value' = $node-last_name ); $form['authorset']['first_name'] = array( '#type' = 'textfield', '#title' = t('First Name'), '#maxlength' = 60, '#default_value' = $node-first_name ); $form['authorset']['middle_name'] = array( '#type' = 'textfield', '#title' = t('Middle Name'), '#maxlength' = 60, '#default_value' = $node-middle_name ); $form['authorset']['suffix_name'] = array( '#type' = 'textfield', '#title' = t('Suffix Name'), '#maxlength' = 14, '#default_value' = $node-suffix_name ); $form['authorset']['body_filter']['body'] = array( '#access' = user_access('create pd_recluse entries'), '#type' = 'textarea', '#title' = 'Describe Author', '#default_value' = $node-body, '#required' = FALSE, '#weight' = -19 ); $form['status'] = array( '#type' = 'hidden', '#default_value' = '1' ); $form['promote'] = array( '#type' = 'hidden', '#default_value' = '1' ); $form['name'] = array( '#type' = 'hidden', '#default_value' = $user-name ); $form['format'] = array( '#type' = 'hidden', '#default_value' = '1' ); // NOTE in node_example there is some addition code here not needed for this simple node-type $thepath='milan/author'; if($_REQUEST["theletter"]) { $thepath .= "/" . $_REQUEST["theletter"]; } if($node['language']) { $thepath='milan/authorajaxclose'; $form['qqq'] = array( '#type' = 'hidden', '#default_value' = '1' ); } $form['#redirect'] = $thepath; return $form; } That menu path coincides with this theme (PHPTemplate)

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  • fonts mac vs pc

    - by Kieran
    Hi all hope your having a good day/evening. Simple question, but maybe not so simple to answer. I have an unordered list, which i am using as a menu. The list items are floated right and sized due to an anchor tag inside them with a roll over. The last element is given a specific size to suck up any extra space. See the code snippits bellow. css ul.mainNav { width: 970px; display:block; background:black; clear:both; overflow:hidden;} ul.mainNav li { float: left; height:29px;} ul.mainNav li a { display: block; padding:7px 19px; color:#ffffff; background-color:#000; font-weight:bold; text-decoration:none; font-size:13px; } ul.mainNav li a:hover, ul.mainNav li a.selected { background-color:#ffff00; color:#000; } ul.mainNav li a.last{ text-align:center; padding: 7px 19px; width:58px;} html <ul class="mainNav" id="mainNav"> <li><a href="/Default.aspx">home</a></li> <li><a href="/About/">about</a></li> <li><a href="/News/">news</a></li> <li><a href="/Enter/Registration.aspx">enter SOYA 2010</a></li> <li><a href="/Categories/Film.aspx">categories</a></li> <li><a href="/Mentors/janChapman.aspx">mentors</a></li> <li><a href="/PastWinners/">past winners</a></li> <li><a href="/Awards/">awards nights</a></li> <li><a href="/Support/" class="last">contact</a></li> </ul> It is containted in a <div style="margin:0 auto;">...</div> to center on the menu on screen Now my problem is: On PC; firefox/ Safari /IE /Chrome are all displaying correctly. Take the same code to a Mac; Safari/ firefox are displaying the menu to be too short and the only thing i can point to is that the fonts may be smaller in widths. The width is currently set to 970px. My question is: How can i get it to display at the same widths without specifying exact widths for each list item? Any help would be appreciated. If my structure is wrong or it is just a mac thing that i will never solve(hope not). Cheers, KJ

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  • Differing styles in Python program: what do you suggest?

    - by Noctis Skytower
    A friend of mine wanted help learning to program, so he gave me all the programs that he wrote for his previous classes. The last program that he wrote was an encryption program, and after rewriting all his programs in Python, this is how his encryption program turned out (after adding my own requirements). #! /usr/bin/env python ################################################################################ """\ CLASS INFORMATION ----------------- Program Name: Program 11 Programmer: Stephen Chappell Instructor: Stephen Chappell for CS 999-0, Python Due Date: 17 May 2010 DOCUMENTATION ------------- This is a simple encryption program that can encode and decode messages.""" ################################################################################ import sys KEY_FILE = 'Key.txt' BACKUP = '''\ !"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNO\ PQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~ _@/6-UC'GzaV0%5Mo9g+yNh8b">Bi=<Lx [sQn#^R.D2Xc(\ Jm!4e${lAEWud&t7]H\`}pvPw)FY,Z~?qK|3SOfk*:1;jTrI''' ################################################################################ def main(): "Run the program: loads key, runs processing loop, and saves key." encode_map, decode_map = load_key(KEY_FILE) try: run_interface_loop(encode_map, decode_map) except SystemExit: pass save_key(KEY_FILE, encode_map) def run_interface_loop(encode_map, decode_map): "Shows the menu and runs the appropriate command." print('This program handles encryption via a customizable key.') while True: print('''\ MENU ==== (1) Encode (2) Decode (3) Custom (4) Finish''') switch = get_character('Select: ', tuple('1234')) FUNC[switch](encode_map, decode_map) def get_character(prompt, choices): "Gets a valid menu option and returns it." while True: sys.stdout.write(prompt) sys.stdout.flush() line = sys.stdin.readline()[:-1] if not line: sys.exit() if line in choices: return line print(repr(line), 'is not a valid choice.') ################################################################################ def load_key(filename): "Gets the key file data and returns encoding/decoding dictionaries." plain, cypher = open_file(filename) return dict(zip(plain, cypher)), dict(zip(cypher, plain)) def open_file(filename): "Load the keys and tries to create it when not available." while True: try: with open(filename) as file: plain, cypher = file.read().split('\n') return plain, cypher except: with open(filename, 'w') as file: file.write(BACKUP) def save_key(filename, encode_map): "Dumps the map into two buffers and saves them to the key file." plain = cypher = str() for p, c in encode_map.items(): plain += p cypher += c with open(filename, 'w') as file: file.write(plain + '\n' + cypher) ################################################################################ def encode(encode_map, decode_map): "Encodes message for the user." print('Enter your message to encode (EOF when finished).') message = get_message() for char in message: sys.stdout.write(encode_map[char] if char in encode_map else char) def decode(encode_map, decode_map): "Decodes message for the user." print('Enter your message to decode (EOF when finished).') message = get_message() for char in message: sys.stdout.write(decode_map[char] if char in decode_map else char) def custom(encode_map, decode_map): "Allows user to edit the encoding/decoding dictionaries." plain, cypher = get_new_mapping() for p, c in zip(plain, cypher): encode_map[p] = c decode_map[c] = p ################################################################################ def get_message(): "Gets and returns text entered by the user (until EOF)." buffer = [] while True: line = sys.stdin.readline() if line: buffer.append(line) else: return ''.join(buffer) def get_new_mapping(): "Prompts for strings to edit encoding/decoding maps." while True: plain = get_unique_chars('What do you want to encode from?') cypher = get_unique_chars('What do you want to encode to?') if len(plain) == len(cypher): return plain, cypher print('Both lines should have the same length.') def get_unique_chars(prompt): "Gets strings that only contain unique characters." print(prompt) while True: line = input() if len(line) == len(set(line)): return line print('There were duplicate characters: please try again.') ################################################################################ # This map is used for dispatching commands in the interface loop. FUNC = {'1': encode, '2': decode, '3': custom, '4': lambda a, b: sys.exit()} ################################################################################ if __name__ == '__main__': main() For all those Python programmers out there, your help is being requested. How should the formatting (not necessarily the coding by altered to fit Python's style guide? My friend does not need to be learning things that are not correct. If you have suggestions on the code, feel free to post them to this wiki as well.

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  • Update to Easy Slider 1.7 made all my JQuery code stop working.

    - by Anders H
    I'm pretty novice as a JQuery user goes. I've got some experience implementing different plugins but would be lost trying to customize my own. I can't share the exact site details with you due to a NDA, so I hope someone can give me a little help. I've got a project due today (Just HTML/CSS/JQuery). It has a lightbox, show/hide login menu and a slider is Easy Slider 1.5. Everything was working together, until I attempted to update to Easy Slider 1.7 (see link on same page, I'm too new to post more than 1 link). When I did so, JQuery stopped working for all the plugins. I've attempted to revert back to the original state, by undoing my work (didn't do much), ad JQuery remains broken. Firebug Error Console shared no errors. I can't find anything in the code no matter how hard I look at it. Can anyone help me troubleshoot this JQuery problem? Delivery is supposed to be tonight for the project. EDIT: Generic header info: <!-- Global Style Sheet --> <link rel="stylesheet" href="style.css" media="screen" type="text/css" /> <!-- Cufon --> <script src="cufon/cufon.js" type="text/javascript"></script> <script src="cufon/gotham_325-gotham_350.font.js" type="text/javascript"></script> <!-- jQuery Javascript --> <script type="text/javascript" language="javascript" src="js/jquery-1.3.2.min.js"></script> <script type="text/javascript" language="javascript" src="js/jquery-ui-1.7.1.custom.min.js"></script> <script type="text/javascript" language="javascript" src="js/jquery.colorbox.js"></script> <script type="text/javascript" language="javascript" src="js/global.js"></script> <script type="text/javascript" language="javascript" src="js/home.js"></script> <script type="text/javascript"> $(document).ready(function() { $(".signin").click(function(e) { e.preventDefault(); $("fieldset#signin_menu").toggle(); $(".signin").toggleClass("menu-open"); }); $("fieldset#signin_menu").mouseup(function() { return false }); $(document).mouseup(function(e) { if($(e.target).parent("a.signin").length==0) { $(".signin").removeClass("menu-open"); $("fieldset#signin_menu").hide(); } }); }); </script> <script src="javascripts/jquery.tipsy.js" type="text/javascript"></script> <script type='text/javascript'> $(function() { $('#forgot_username_link').tipsy({gravity: 'w'}); }); </script> <script type="text/javascript" language="javascript" src="js/easySlider1.5.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("#slider").easySlider(); }); </script> <script type="text/javascript"> $(document).ready(function(){ $(".regbox").colorbox({iframe:true, innerWidth:270, innerHeight:270}); }); </script>

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  • WPF Issues with Control Layout

    - by Brett Powell
    I am making an application that connects to our billing software using its API, and I am running into a few issues getting the layout working properly. I want to make it so that when one of the expanders is minimized, the other window fills the gap, and when it is expanded again the other expander goes back to where it was. Right now when the arrow is clicked on one, there is just an empty gap. I used a DockPanel as the parent which I assumed would automatically do this, but it isn't working. Second question, is there a way to make these areas resizable? I don't want to try and get too frisky with allowing the user to undock the menus (don't even know if that is possible with just straight WPF) but it would be nice if they could change the width/height of them. Also, just a newbie question to C#, but what is the equivalent of a C++ header file? It looks like you just use .cs files, but I am not sure. I want to extract all of my functions that pull the data from the billing software and put them into a different file to clean up the code. Here is my XAML... <Window x:Class="WpfApplication3.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="Billing Management" Height="550" Width="754" xmlns:shared="http://schemas.actiprosoftware.com/winfx/xaml/shared" WindowStartupLocation="CenterScreen" WindowStyle="ThreeDBorderWindow"> <Grid> <Grid.RowDefinitions> <RowDefinition Height="22" /> <RowDefinition /> </Grid.RowDefinitions> <Menu Height="22" Name="menu1" Margin="0" HorizontalAlignment="Stretch" VerticalAlignment="Top" HorizontalContentAlignment="Left" IsEnabled="True" IsMainMenu="True"> <MenuItem Header="_File"> <MenuItem Header="_Open" /> <MenuItem Header="_Close" /> <Separator/> <MenuItem Header="_Exit" /> </MenuItem> </Menu> <TabControl Name="tabControl1" HorizontalContentAlignment="Stretch" VerticalContentAlignment="Stretch" BorderThickness="1" Padding="0" TabStripPlacement="Bottom" UseLayoutRounding="False" FlowDirection="LeftToRight" Grid.Row="1"> <TabItem Header="Main" Name="tabItem1" Margin="0"> <DockPanel Name="dockPanel1" LastChildFill="True"> <ListBox Height="100" Name="listBox3" DockPanel.Dock="Top" /> <ListBox Name="listBox4" Width="200" DockPanel.Dock="Right" /> <DockPanel Height="Auto" Name="dockPanel2" Width="Auto" VerticalAlignment="Stretch" LastChildFill="True"> <shared:AnimatedExpander Header="Staff Online" Width="200" Name="expanderStaffOnline" IsExpanded="True" Height="194" BorderThickness="0" DockPanel.Dock="Top" VerticalContentAlignment="Stretch"> <ListBox Name="listboxStaffOnline" Width="Auto" Height="Auto" Margin="0" VerticalAlignment="Stretch" Loaded="listboxStaffOnline_Loaded" /> </shared:AnimatedExpander> <shared:AnimatedExpander Header="Test Menu 2" Height="Auto" Name="animatedExpander1" BorderThickness="1" Margin="0,0,0,0" IsExpanded="True" VerticalContentAlignment="Stretch"> <ListBox Height="Auto" HorizontalAlignment="Stretch" Name="listBox6" VerticalAlignment="Stretch" Margin="0" BorderThickness="1" /> </shared:AnimatedExpander> </DockPanel> <ListBox Height="100" Name="listboxAdminLogs" DockPanel.Dock="Bottom" Loaded="listboxAdminLogs_Loaded" /> <ListBox Name="listBox5" /> </DockPanel> </TabItem> <TabItem Header="Support" Name="tabItem2" Margin="0"> </TabItem> <TabItem Header="Clients" /> <TabItem Header="Billing" /> <TabItem Header="Orders" /> </TabControl> </Grid> </Window>

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  • tkinter frame does not show on startup

    - by Jzz
    this is my first question on SO, so correct me please if I make a fool of myself. I have this fairly complicated python / Tkinter application (python 2.7). On startup, the __init__ loads several frames, and loads a database. When that is finished, I want to set the application to a default state (there are 2 program states, 'calculate' and 'config'). Setting the state of the application means that the appropriate frame is displayed (using grid). When the program is running, the user can select a program state in the menu. Problem is, the frame is not displayed on startup. I get an empty application (menu bar and status bar are displayed). When I select a program state in the menu, the frame displays as it should. Question: What am I doing wrong? Should I update idletasks? I tried, but no result. Anything else? Background: I use the following to switch program states: def set_program_state(self, state): '''sets the program state''' #try cleaning all the frames: try: self.config_frame.grid_forget() except: pass try: self.tidal_calculations_frame.grid_forget() except: pass try: self.tidal_grapth_frame.grid_forget() except: pass if state == "calculate": print "Switching to calculation mode" self.tidal_calculations_frame.grid() #frame is preloaded self.tidal_calculations_frame.fill_data(routes=self.routing_data.routes, deviations=self.misc_data.deviations, ship_types=self.misc_data.ship_types) self.tidal_grapth_frame.grid() self.program_state = "calculate" elif state == "config": print "Switching to config mode" self.config_frame = GUI_helper.config_screen_frame(self, self.user) #load frame first (contents depend on type of user) self.config_frame.grid() self.program_state = "config" I understand that this is kind of messy to read, so I simplified things for testing, using this: def set_program_state(self, state): '''sets the program state''' #try cleaning all the frames: try: self.testlabel_1.grid_forget() except: pass try: self.testlabel_2.grid_forget() except: pass if state == "calculate": print "switching to test1" self.testlabel_1 = tk.Label(self, text="calculate", borderwidth=1, relief=tk.RAISED) self.testlabel_1.grid(row=0, sticky=tk.W+tk.E) elif state == "config": print "switching to test1" self.testlabel_2 = tk.Label(self, text="config", borderwidth=1, relief=tk.RAISED) self.testlabel_2.grid(row=0, sticky=tk.W+tk.E) But the result is the same. The frame (or label in this test) is not displayed at startup, but when the user selects the state (calling the same function) the frame is displayed. UPDATE the sample code in the comments (thanks for that!) pointed me in another direction. Further testing revealed (what I think) the cause of the problem. Disabling the display of the status bar made the program work as expected. Turns out, I used pack to display the statusbar and grid to display the frames. And they are in the same container, so problems arise. I fixed that by using only pack inside the main container. But the same problem is still there. This is what I use for the statusbar: self.status = GUI_helper.StatusBar(self.parent) self.status.pack(side=tk.BOTTOM, fill=tk.X) And if I comment out the last line (pack), the config frame loads on startup, as per this line: self.set_program_state("config") But if I let the status bar pack inside the main window, the config frame does not show. Where it does show when the user asks for it (with the same command as above).

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  • Problem with sending out variable to serial port using api JAVA

    - by sjaakensjon
    We are developing a java program for school. But we are experiencing problems with sending out a variable created by 3 sliders. The idea is that we have 3 sliders. One slider for every color. Red green and blue. The variable has to have a value between 0 and 255. Everytime the value of the slider changes is has to send a variable for the channel, that value is 1, 2 ,3. And after that it has to send the value of the slider through the serial port. Could you please help us out by creating an example program? Below is our code so far. Thanks in advance. Sjaak package main; import javax.swing.*; import javax.swing.event.*; import java.awt.*; import app.Com; import app.Parameters; public class menu{ JSlider sliderblauw; JLabel hoeveelblauw; JLabel blauw; JLabel rood; JSlider sliderrood; JLabel hoeveelrood; JLabel groen; JLabel hoeveelgroen; JSlider slidergroen; public menu(){ Frame venster = new JFrame("Color control"); JPanel blauwinstel = new JPanel(); ((JFrame) venster).setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); venster.setSize(500, 500); venster.setVisible(true); sliderblauw = new JSlider(JSlider.VERTICAL, 0, 255, 0); sliderblauw.addChangeListener(new veranderingblauw()); hoeveelblauw = new JLabel ("0"); blauwinstel.add(sliderblauw); blauwinstel.add(hoeveelblauw); venster.add(blauwinstel, BorderLayout.WEST); sliderblauw.setMajorTickSpacing(10); sliderblauw.setPaintTicks(true); JPanel roodinstel = new JPanel(); sliderrood = new JSlider(JSlider.VERTICAL, 0, 255, 0); sliderrood.addChangeListener(new veranderingrood()); hoeveelrood = new JLabel ("0"); roodinstel.add(sliderrood); roodinstel.add(hoeveelrood); venster.add(roodinstel, BorderLayout.EAST); sliderrood.setMajorTickSpacing(10); sliderrood.setPaintTicks(true); JPanel groeninstel = new JPanel(); slidergroen = new JSlider(JSlider.VERTICAL, 0, 255, 0); slidergroen.addChangeListener(new veranderinggroen()); hoeveelgroen = new JLabel ("0"); groeninstel.add(slidergroen); groeninstel.add(hoeveelgroen); venster.add(groeninstel, BorderLayout.CENTER); slidergroen.setMajorTickSpacing(10); slidergroen.setPaintTicks(true); } public class veranderingblauw implements ChangeListener{ public void stateChanged(ChangeEvent ce){ int value = sliderblauw.getValue(); String waarde_blauw = Integer.toString(value); hoeveelblauw.setText(waarde_blauw); }} public class veranderingrood implements ChangeListener{ public void stateChanged(ChangeEvent ce){ int value = sliderrood.getValue(); String waarde_rood = Integer.toString(value); hoeveelrood.setText(waarde_rood); }} public class veranderinggroen implements ChangeListener{ public void stateChanged(ChangeEvent ce){ int value = slidergroen.getValue(); String waarde_groen = Integer.toString(value); hoeveelgroen.setText(waarde_groen); }} public static void main( String[] args) { new menu(); } }

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  • Content div not filling up the remaining space

    - by Sameer Shariff
    Basically #content is not obeying the height: auto attribute. What am i doing wrong? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title id="title" runat="server">AMIDS: Advanced Management Information Data Store</title> <style type="text/css"> #container { background-color: White; height: 100%; min-height: 100%; min-width: 600px; width: 100%; } #header { height: 50px; overflow: hidden; width: 100%; } #headerLeft { background-image: url('/Amids/App_Themes/Default/Images/HeaderLeft.jpg'); float: left; height: 50px; width: 5px; } #headerCenter { background-image: url('/Amids/App_Themes/Default/Images/HeaderCenter.jpg'); float: left; height: 50px; width: 99.2%; } #headerRight { background-image: url('/Amids/App_Themes/Default/Images/HeaderRight.jpg'); float: left; height: 50px; width: 5px; } #menu { background-image: url('/Amids/App_Themes/Default/Images/Menu.jpg'); height: 20px; width: 100%; } #content { background-color: Pink; height: auto; width: 100%; } #footer { height: 40px; overflow: hidden; width: 100%; } #footerLeft { background-image: url('/Amids/App_Themes/Default/Images/FooterLeft.jpg'); float: left; height: 40px; width: 5px; } #footerCenter { background-image: url('/Amids/App_Themes/Default/Images/FooterCenter.jpg'); float: left; height: 40px; width: 99.2%; } #footerRight { background-image: url('/Amids/App_Themes/Default/Images/FooterRight.jpg'); float: left; height: 40px; width: 5px; } * html #container { height: 100%; } * { margin: 0; padding: 0; } html, body, form { border: none; height: 100%; } </style> </head> <body> <form id="form" runat="server"> <div id="container"> <div id="header"> <div id="headerLeft"></div> <div id="headerCenter"></div> <div id="headerRight"></div> </div> <div id="menu"></div> <div id="content"></div> <div id="footer"> <div id="footerLeft"></div> <div id="footerCenter"></div> <div id="footerRight"></div> </div> </div> </form> </body> </html> Any ideas anyone?

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  • How to properly use the .each() command in jQuery

    - by sadmicrowave
    I have a script that checks the class (integer) of a , runs a switch statement to change that integer value to text and appends the text to another in the same listitem tag. I use the .each() function because each listitem starts with class=_[user ID] -- each user can have up to 5 entries.. Enough explaining -- heres the code: <HTML> <li class='_44074'><div class='_12' style='width:380px;'><div style='width:60px; float:left;'>1st</div><div class='verify-type' style='float:left; width:160px;'></div><div style='float:left; width:120px;'>04/26/10 07:29 AM</div></div></li> <li class='_44074'><div class='_6' style='width:380px;'><div style='width:60px; float:left;'>2nd</div><div class='verify-type' style='float:left; width:160px;'></div><div style='float:left; width:120px;'>04/23/10 03:29 PM</div></div></li> <li class='_44074'><div class='_12' style='width:380px;'><div style='width:60px; float:left;'>3rd</div><div class='verify-type' style='float:left; width:160px;'></div><div style='float:left; width:120px;'>04/23/10 03:18 PM</div></div></li> <li class='_44074'><div class='_2' style='width:380px;'><div style='width:60px; float:left;'>4th</div><div class='verify-type' style='float:left; width:160px;'></div><div style='float:left; width:120px;'>04/23/10 02:28 PM</div></div></li> </HTML> when I use the .each() function to scan through each of the listitems begining with the entered user id it only finds the first value (in this case _12) and applies that to all the entries; instead of finding _12, _6, _12, _2 it finds _12, _12, _12, _12...here is the java: $("div#history-menu div#history-text li." + valueid).each(function(){ valueid = $("div#center-box input").val(); checkedvalue=""; checkedvalue = $("div#history-menu div#history-text li." + valueid + " div").attr('class'); switch(checkedvalue){ case '_2':lcCheckedMessage = "Shoes"; break; case '_4':lcCheckedMessage = "Shoe Straps"; break; case '_6':lcCheckedMessage = "Shoes & Shoe Straps"; break; case '_8':lcCheckedMessage = "Wrist Straps"; break; case '_10':lcCheckedMessage = "Shoes & Wrist Strap"; break; case '_12':lcCheckedMessage = "Shoe Straps & Wrist Strap"; break; }; $("div#history-menu div#history-text li." + valueid + " ." + checkedvalue + " .verify-type").text(lcCheckedMessage); });

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  • not able to style a ul inside a nav tag

    - by user1831677
    I am trying to make a nav menu for my website and have been using http://www.onextrapixel.com/2011/06/03/how-to-create-a-horizontal-dropdown-menu-with-html-css-and-jquery/ as a guide. It has worked fine but as soon as I try to add ( id="coolMenu" ) to the nav tag it stops working. I took it away from the ul tag and added it to the nav tag and it no longer works. It does not display anything at all. What am in doing wrong? Thanks. html code below: <nav id="coolMenu"> <ul> <li><a href="#">Lorem</a></li> <li><a href="#">Mauricii</a></li> <li> <a href="#">Periher</a> <ul class="noJS"> <li><a href="#">Hellenico</a></li> <li><a href="#">Genere</a></li> <li><a href="#">Indulgentia</a></li> </ul> </li> <li><a href="#">Tyrio</a></li> <li><a href="#">Quicumque</a></li> </ul> </nav> css below: /* Structure ------------------------------------------*/ #coolMenu, #coolMenu ul { list-style: none; } #coolMenu { float: left; } #coolMenu > li { float: left; } #coolMenu li a { display: block; height: 2em; line-height: 2em; padding: 0 1.5em; text-decoration: none; } #coolMenu ul { position: absolute; display: none; z-index: 999; } #coolMenu ul li a { width: 80px; } #coolMenu li:hover ul.noJS { display: block; } /* Main menu ------------------------------------------*/ #coolMenu { font-family: Arial; font-size: 12px; background: #2f8be8; } #coolMenu > li > a { color: #fff; font-weight: bold; } #coolMenu > li:hover > a { background: #f09d28; color: #000; } /* Submenu ------------------------------------------*/ #coolMenu ul { background: #f09d28; } #coolMenu ul li a { color: #000; } #coolMenu ul li:hover a { background: #ffc97c; }

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  • Two forms are being called from one view.One encodes the russian text the doesn't.

    - by Daniel
    The menu I want to show to the users changes depending on their rights After user authentication I redirect to my menu action which calls its view access/menu.html.erb <% if admin? %> <%form_for(:user, :url => {:controller => 'admin_users',:name => session[:username]}) do |admin|%> <ul><h2>Administrator: <%=session[:username]%></h2></ul> <%= render(:partial =>'admin_form',:locals => {:admin => admin})%> <%end%> <%else%> <%form_for(:user, :url => {:controller => 'students',:name => session[:username]}) do |student|%> <ul><h2>???????: <%=session[:surname].to_s + " " + session[:name].to_s%></h2></ul> <%= render(:partial =>'student_form',:locals => {:student => student})%> <%end%> <%end%> And the forms look: _student_form: <table> <ul> <li><%=link_to '?????',{:controller => 'students'}%></li> </ul> <ul> <li><%=link_to '?????? ?????????',{:controller => 'students'}%></li> </ul> <ul> <li><%=link_to '???????? ?????? ????',{:controller => 'students'}%></li> </ul> <ul> <li><%=link_to '???????? ??????',{:controller => 'students'}%></li> </ul> <ul> <td>&nbsp;</td> </ul> </table> _admin_form: <table> <ul> <li><%=link_to '?????????? ????????????????',{:controller => 'AdminUsers',:role_id => 1}%></li> </ul> <ul> <li><%=link_to '?????????? ????????',{:controller => 'AdminUsers',:role_id => 2}%></li> </ul> <ul> <li><%=link_to '?????????? ??????????',{:controller => 'AdminUsers',:role_id => 3}%></li> </ul> <ul> <li><%=link_to '?????????? ???????????',:controller => 'subjects'%></li> </ul> <ul> <td>&nbsp;</td> </ul> </table> If a log in as a student I get: But if I log in as an administrator I get How can this be posible??

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  • create previous next button for iframe pages

    - by Resu
    This topic may have lots of code out there, BUT I seem to be looking for a variation that isn't based on history, is it possible... So I have this code... <script type="text/javascript"> var pages=new Array(); pages[0]="listItem1.html"; pages[1]="listItem2.html"; pages[2]="listItem3.html"; pages[3]="listItem4.html"; pages[4]="listItem5.html"; var i=0; var end=pages.length; end--; function changeSrc(operation) { if (operation=="next") { if (i==end) { document.getElementById('the_iframe').src=pages[end]; i=0;} else { document.getElementById('the_iframe').src=pages[i]; i++;}} if (operation=="back") { if (i==0) { document.getElementById('the_iframe').src=pages[0]; i=end;} else { document.getElementById('the_iframe').src=pages[i]; i--;}}} </script> </head> <body> <ul id="menu" role="group"> <li><a href="listItem1.html" target="ifrm" role="treeitem">Welcome</a> <ul> <li><a href="listItem2.html" target="ifrm" role="treeitem">Ease of Access Center</a></li> </ul> </li> <li><a href="listItem3.html" target="ifrm">Getting Started</a> <ul> <li><a href="listItem4.html" target="ifrm">Considerations</a></li> <li><a href="listItem5.html" target="ifrm">Changing Perspective</a></li> </ul> </li> </ul> <iframe id="the_iframe" scrolling="no" src="listItem1.htm" name="ifrm" style="width:540px;></iframe> <input type="button" onClick="changeSrc('back');" value="Back" /> <input type="button" onClick="changeSrc('next');" value="Next" /> and if I click on the next or prev button, it does move somewhere,but... let's say my iframe is showing listItem2, then I click on listItem4 in the menu (there is a tree menu involved), then I want to go to listItem3 and I hit the back button...instead of going to listItem3, it goes to listItem2 (or someplace that is not back a page from 4 to 3). It appears that the buttons are navigating based on history?...but I just want a straight forward or backward movement...I don't want my buttons to have this browser-type functionality...If I'm on listItem4 and hit the next button, I want it to go to listItem5. Many Thanks For Any Help!

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  • error_expected_primary expression before in. In functions

    - by user2975402
    Here is my code. I try to fix it and I always obtain the same error: expected primary expression before 'int'. in line 47, 55, 63, 80, 86. And I've already tried this program in small pieces before and it works. It doesn't marked that error. ` #include using namespace std; int add (int a, int b) { int r; r=a+b; return (r); } int ssub (int a, int b) { int r; r=a-b; return (r); } int mult(int a, int b) { int r; r=a*b; return (r); } int menu(int a, int b){ int r; char x; cout <<"What do you want to do: \na.Adding \n s. Substract \n m. Multiply. \n. e. Exit"<<endl; cin>>x; switch (x){ case 'a': cout << "Give a value for a"<<endl; cin>>a; cout <<"Give a value for b"<<endl; cin>>b; add (int a, int b); //aquí y en otras líneas me sale: expected primary expression before int. break; case 's': cout << "Give a value for a"<<endl; cin>>a; cout <<"Give a value for b"<<endl; cin>>b; ssub (int a, int b); break; case 'm': cout << "Give a value for a"<<endl; cin>>a; cout <<"Give a value for b"<<endl; cin>>b; mult (int a, int b); break; case 'e': x='e'; break; default: cout<<"Wrong choice. Run the program again and choose another letter"<<endl; break; } return r; } cout<<"The result is " << menu (int a, int b)<<endl; int main() { menu (int a, int b); return 0; } `

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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  • WPF Combobox: Autocomplete

    - by user279244
    Hi, I have implemented a Autocomplete enabled Combobox in WPF. It is like below... private void cbxSession_Loaded(object sender, RoutedEventArgs e) { cbxSession.ApplyTemplate(); TextBox textBox = cbxSession.Template.FindName("PART_EditableTextBox", cbxSession) as TextBox; textBox.IsReadOnly = false; if (textBox != null) { textBox.KeyUp += new KeyEventHandler(textBox_KeyUp); textBox.KeyUp += delegate { ///open the drop down and start filtering based on what the user types into the combobox cbxSession.IsDropDownOpen = true; cbxSession.Items.Filter += a => { if (a.ToString().ToUpper().Contains(textBox.Text.ToUpper())) return true; else return false; }; }; } } void textBox_KeyUp(object sender, KeyEventArgs e) { if ((e.Key == System.Windows.Input.Key.Up) || (e.Key == System.Windows.Input.Key.Down)) { e.Handled = true; } else if (e.Key == System.Windows.Input.Key.Enter) { e.Handled = true; cbxSession.IsDropDownOpen = false; } } void textBox_KeyDown(object sender, KeyEventArgs e) { cbxSession.SelectionChanged -= cbxSession_SelectionChanged; if (e.Key == System.Windows.Input.Key.Enter) { e.Handled = true; cbxSession.SelectionChanged += cbxSession_SelectionChanged; } if ((e.Key == System.Windows.Input.Key.Up) || (e.Key == System.Windows.Input.Key.Down)) { e.Handled = true; } } private void cbxSession_DropDownClosed(object sender, EventArgs e) { if (cbxSession.Text != "") { TextBox textBox = cbxSession.Template.FindName("PART_EditableTextBox", cbxSession) as TextBox; if (!cbxSession.Items.Contains(textBox.Text)) { textBox.Text = cbxSession.Text; } } } private void cbxSession_DropDownOpened(object sender, EventArgs e) { cbxSession.Items.Filter += a => { return true; }; } <ComboBox x:Name="cbxSession" Width="260" Canvas.Top="5" Canvas.Left="79" Height="25" Visibility="Visible" SelectionChanged="cbxSession_SelectionChanged" MaxDropDownHeight="200" IsTextSearchEnabled="False" IsEditable="True" IsReadOnly="True" Loaded="cbxSession_Loaded" DropDownClosed="cbxSession_DropDownClosed" StaysOpenOnEdit="True" DropDownOpened="cbxSession_DropDownOpened"> <ComboBox.ItemsPanel> <ItemsPanelTemplate> <VirtualizingStackPanel IsVirtualizing="True" IsItemsHost="True"/> </ItemsPanelTemplate> </ComboBox.ItemsPanel> </ComboBox> But, the problem I am facing is... When I try searching, the first character goes missing. And this happens only once. Secondly, When I am using Arrow buttons to the filtered items, the ComboboxSelectionChanged event is fired. Is there any way to make it fire only on the click of 'Enter'

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  • WCF REST on .Net 4.0

    - by AngelEyes
    A simple and straight forward article taken from: http://christopherdeweese.com/blog2/post/drop-the-soap-wcf-rest-and-pretty-uris-in-net-4 Drop the Soap: WCF, REST, and Pretty URIs in .NET 4 Years ago I was working in libraries when the Web 2.0 revolution began.  One of the things that caught my attention about early start-ups using the AJAX/REST/Web 2.0 model was how nice the URIs were for their applications.  Those were my first impressions of REST; pretty URIs.  Turns out there is a little more to it than that. REST is an architectural style that focuses on resources and structured ways to access those resources via the web.  REST evolved as an “anti-SOAP” movement, driven by developers who did not want to deal with all the complexity SOAP introduces (which is al lot when you don’t have frameworks hiding it all).  One of the biggest benefits to REST is that browsers can talk to rest services directly because REST works using URIs, QueryStrings, Cookies, SSL, and all those HTTP verbs that we don’t have to think about anymore. If you are familiar with ASP.NET MVC then you have been exposed to rest at some level.  MVC is relies heavily on routing to generate consistent and clean URIs.  REST for WCF gives you the same type of feel for your services.  Let’s dive in. WCF REST in .NET 3.5 SP1 and .NET 4 This post will cover WCF REST in .NET 4 which drew heavily from the REST Starter Kit and community feedback.  There is basic REST support in .NET 3.5 SP1 and you can also grab the REST Starter Kit to enable some of the features you’ll find in .NET 4. This post will cover REST in .NET 4 and Visual Studio 2010. Getting Started To get started we’ll create a basic WCF Rest Service Application using the new on-line templates option in VS 2010: When you first install a template you are prompted with this dialog: Dude Where’s my .Svc File? The WCF REST template shows us the new way we can simply build services.  Before we talk about what’s there, let’s look at what is not there: The .Svc File An Interface Contract Dozens of lines of configuration that you have to change to make your service work REST in .NET 4 is greatly simplified and leverages the Web Routing capabilities used in ASP.NET MVC and other parts of the web frameworks.  With REST in .NET 4 you use a global.asax to set the route to your service using the new ServiceRoute class.  From there, the WCF runtime handles dispatching service calls to the methods based on the Uri Templates. global.asax using System; using System.ServiceModel.Activation; using System.Web; using System.Web.Routing; namespace Blog.WcfRest.TimeService {     public class Global : HttpApplication     {         void Application_Start(object sender, EventArgs e)         {             RegisterRoutes();         }         private static void RegisterRoutes()         {             RouteTable.Routes.Add(new ServiceRoute("TimeService",                 new WebServiceHostFactory(), typeof(TimeService)));         }     } } The web.config contains some new structures to support a configuration free deployment.  Note that this is the default config generated with the template.  I did not make any changes to web.config. web.config <?xml version="1.0"?> <configuration>   <system.web>     <compilation debug="true" targetFramework="4.0" />   </system.web>   <system.webServer>     <modules runAllManagedModulesForAllRequests="true">       <add name="UrlRoutingModule" type="System.Web.Routing.UrlRoutingModule,            System.Web, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" />     </modules>   </system.webServer>   <system.serviceModel>     <serviceHostingEnvironment aspNetCompatibilityEnabled="true"/>     <standardEndpoints>       <webHttpEndpoint>         <!--             Configure the WCF REST service base address via the global.asax.cs file and the default endpoint             via the attributes on the <standardEndpoint> element below         -->         <standardEndpoint name="" helpEnabled="true" automaticFormatSelectionEnabled="true"/>       </webHttpEndpoint>     </standardEndpoints>   </system.serviceModel> </configuration> Building the Time Service We’ll create a simple “TimeService” that will return the current time.  Let’s start with the following code: using System; using System.ServiceModel; using System.ServiceModel.Activation; using System.ServiceModel.Web; namespace Blog.WcfRest.TimeService {     [ServiceContract]     [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)]     [ServiceBehavior(InstanceContextMode = InstanceContextMode.PerCall)]     public class TimeService     {         [WebGet(UriTemplate = "CurrentTime")]         public string CurrentTime()         {             return DateTime.Now.ToString();         }     } } The endpoint for this service will be http://[machinename]:[port]/TimeService.  To get the current time http://[machinename]:[port]/TimeService/CurrentTime will do the trick. The Results Are In Remember That Route In global.asax? Turns out it is pretty important.  When you set the route name, that defines the resource name starting after the host portion of the Uri. Help Pages in WCF 4 Another feature that came from the starter kit are the help pages.  To access the help pages simply append Help to the end of the service’s base Uri. Dropping the Soap Having dabbled with REST in the past and after using Soap for the last few years, the WCF 4 REST support is certainly refreshing.  I’m currently working on some REST implementations in .NET 3.5 and VS 2008 and am looking forward to working on REST in .NET 4 and VS 2010.

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  • SQL03070: This statement is not recognized in this context

    - by prash
    Recently I have started working with VS2010 and Fx4. There have been various challenges. We also introduced a new Database Project in our solution. And found this error. The reason for this error is: the project system expects the stored procedure as a create statement only.  The additional statements to drop if existing are not necessary within the project system.  Project deployment takes care of detecting if the sproc already exists and if it needs to be updated. To resolve this error you can simply remove the additional statements other then your create SP, Function etc. OR Exclude the file from build. Right Click on your file in Solution Explorer, Click Properties > Build Action > Not in Build

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  • SQL SERVER – T-SQL Script to Take Database Offline – Take Database Online

    - by pinaldave
    Blog reader Joyesh Mitra recently left a comment to one of my very old posts about SQL SERVER – 2005 Take Off Line or Detach Database, which I have written focusing on taking the database offline. However, I did not include how to bring the offline database to online in that post. The reason I did not write it was that I was thinking it was a very simple script that almost everyone knows. However, it seems to me that there is something I found advanced in this procedure that is not simple for other people. We all have different expertise and we all try to learn new things, so I do not see any reason as to not write about the script to take the database online. -- Create Test DB CREATE DATABASE [myDB] GO -- Take the Database Offline ALTER DATABASE [myDB] SET OFFLINE WITH ROLLBACK IMMEDIATE GO -- Take the Database Online ALTER DATABASE [myDB] SET ONLINE GO -- Clean up DROP DATABASE [myDB] GO Joyesh let me know if this answers your question. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, Readers Question, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

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  • Integrate Bing Search API into ASP.Net application

    - by sreejukg
    Couple of months back, I wrote an article about how to integrate Bing Search engine (API 2.0) with ASP.Net website. You can refer the article here http://weblogs.asp.net/sreejukg/archive/2012/04/07/integrate-bing-api-for-search-inside-asp-net-web-application.aspx Things are changing rapidly in the tech world and Bing has also changed! The Bing Search API 2.0 will work until August 1, 2012, after that it will not return results. Shocked? Don’t worry the API has moved to Windows Azure market place and available for you to sign up and continue using it and there is a free version available based on your usage. In this article, I am going to explain how you can integrate the new Bing API that is available in the Windows Azure market place with your website. You can access the Windows Azure market place from the below link https://datamarket.azure.com/ There is lot of applications available for you to subscribe and use. Bing is one of them. You can find the new Bing Search API from the below link https://datamarket.azure.com/dataset/5BA839F1-12CE-4CCE-BF57-A49D98D29A44 To get access to Bing Search API, first you need to register an account with Windows Azure market place. Sign in to the Windows Azure market place site using your windows live account. Once you sign in with your windows live account, you need to register to Windows Azure Market place account. From the Windows Azure market place, you will see the sign in button it the top right of the page. Clicking on the sign in button will take you to the Windows live ID authentication page. You can enter a windows live ID here to login. Once logged in you will see the Registration page for the Windows Azure market place as follows. You can agree or disagree for the email address usage by Microsoft. I believe selecting the check box means you will get email about what is happening in Windows Azure market place. Click on continue button once you are done. In the next page, you should accept the terms of use, it is not optional, you must agree to terms and conditions. Scroll down to the page and select the I agree checkbox and click on Register Button. Now you are a registered member of Windows Azure market place. You can subscribe to data applications. In order to use BING API in your application, you must obtain your account Key, in the previous version of Bing you were required an API key, the current version uses Account Key instead. Once you logged in to the Windows Azure market place, you can see “My Account” in the top menu, from the Top menu; go to “My Account” Section. From the My Account section, you can manage your subscriptions and Account Keys. Account Keys will be used by your applications to access the subscriptions from the market place. Click on My Account link, you can see Account Keys in the left menu and then Add an account key or you can use the default Account key available. Creating account key is very simple process. Also you can remove the account keys you create if necessary. The next step is to subscribe to BING Search API. At this moment, Bing Offers 2 APIs for search. The available options are as follows. 1. Bing Search API - https://datamarket.azure.com/dataset/5ba839f1-12ce-4cce-bf57-a49d98d29a44 2. Bing Search API – Web Results only - https://datamarket.azure.com/dataset/8818f55e-2fe5-4ce3-a617-0b8ba8419f65 The difference is that the later will give you only web results where the other you can specify the source type such as image, video, web, news etc. Carefully choose the API based on your application requirements. In this article, I am going to use Web Results Only API, but the steps will be similar to both. Go to the API page https://datamarket.azure.com/dataset/8818f55e-2fe5-4ce3-a617-0b8ba8419f65, you can see the subscription options in the right side. And in the bottom of the page you can see the free option Since I am going to use the free options, just Click the Sign Up link for that. Just select I agree check box and click on the Sign Up button. You will get a recipt pagethat detail your subscription. Now you are ready Bing Search API – Web results. The next step is to integrate the API into your ASP.Net application. Now if you go to the Search API page (as well as in the Receipt page), you can see a .Net C# Class Library link, click on the link, you will get a code file named “BingSearchContainer.cs”. In the following sections I am going to demonstrate the use of Bing Search API from an ASP.Net application. Create an empty ASP.Net web application. In the solution explorer, the application will looks as follows. Now add the downloaded code file (“BingSearchContainer.cs”) to the project. Right click your project in solution explorer, Add -> existing item, then browse to the downloaded location, select the “BingSearchContainer.cs” file and add it to the project. To build the code file you need to add reference to the following library. System.Data.Services.Client You can find the library in the .Net tab, when you select Add -> Reference Try to build your project now; it should build without any errors. Add an ASP.Net page to the project. I have included a text box and a button, then a Grid View to the page. The idea is to Search the text entered and display the results in the gridview. The page will look in the Visual Studio Designer as follows. The markup of the page is as follows. In the button click event handler for the search button, I have used the following code. Now run your project and enter some text in the text box and click the Search button, you will see the results coming from Bing, cool. I entered the text “Microsoft” in the textbox and clicked on the button and I got the following results. Searching Specific Websites If you want to search a particular website, you pass the site url with site:<site url name> and if you have more sites, use pipe (|). e.g. The following search query site:microsoft.com | site:adobe.com design will search the word design and return the results from Microsoft.com and Adobe.com See the sample code that search only Microsoft.com for the text entered for the above sample. var webResults = bingContainer.Web("site:www.Microsoft.com " + txtSearch.Text, null, null, null, null, null, null); Paging the results returned by the API By default the BING API will return 100 results based on your query. The default code file that you downloaded from BING doesn’t include any option for this. You can modify the downloaded code to perform this paging. The BING API supports two parameters $top (for number of results to return) and $skip (for number of records to skip). So if you want 3rd page of results with page size = 10, you need to pass $top = 10 and $skip=20. Open the BingSearchContainer.cs in the editor. You can see the Web method in it as follows. public DataServiceQuery<WebResult> Web(String Query, String Market, String Adult, Double? Latitude, Double? Longitude, String WebFileType, String Options) {  In the method signature, I have added two more parameters public DataServiceQuery<WebResult> Web(String Query, String Market, String Adult, Double? Latitude, Double? Longitude, String WebFileType, String Options, int resultCount, int pageNo) { and in the method, you need to pass the parameters to the query variable. query = query.AddQueryOption("$top", resultCount); query = query.AddQueryOption("$skip", (pageNo -1)*resultCount); return query; Note that I didn’t perform any validation, but you need to check conditions such as resultCount and pageCount should be greater than or equal to 1. If the parameters are not valid, the Bing Search API will throw the error. The modified method is as follows. The changes are highlighted. Now see the following code in the SearchPage.aspx.cs file protected void btnSearch_Click(object sender, EventArgs e) {     var bingContainer = new Bing.BingSearchContainer(new Uri(https://api.datamarket.azure.com/Bing/SearchWeb/));     // replace this value with your account key     var accountKey = "your key";     // the next line configures the bingContainer to use your credentials.     bingContainer.Credentials = new NetworkCredential(accountKey, accountKey);     var webResults = bingContainer.Web("site:microsoft.com" +txtSearch.Text , null, null, null, null, null, null,3,2);     lstResults.DataSource = webResults;     lstResults.DataBind(); } The following code will return 3 results starting from second page (by skipping first 3 results). See the result page as follows. Bing provides complete integration to its offerings. When you develop search based applications, you can use the power of Bing to perform the search. Integrating Bing Search API to ASP.Net application is a simple process and without investing much time, you can develop a good search based application. Make sure you read the terms of use before designing the application and decide which API usage is suitable for you. Further readings BING API Migration Guide http://go.microsoft.com/fwlink/?LinkID=248077 Bing API FAQ http://go.microsoft.com/fwlink/?LinkID=252146 Bing API Schema Guide http://go.microsoft.com/fwlink/?LinkID=252151

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  • Microsoft’s 22tracks Music Service now Available in All Browsers

    - by Akemi Iwaya
    Are you tired of listening to the same old music and looking for something new to listen to? Then 22tracks from Microsoft is definitely worth a look! This online music service is available in your favorite browser, does not require an account to use, and lets you listen to music from multiple international sources! If you are curious about 22tracks, then the following excerpt and video sum up the service very nicely. From the blog post: The concept behind 22tracks is simple: 22 local top DJs from cities like Amsterdam, Brussels, London and Paris share their genre’s 22 hottest tracks of the moment. Each city boosts its own team of specialized DJs bringing you the newest tracks in their genre. When you get ready to select (or change to) another set of tracks, just click on the desired city at the top of the browser window, then click on the appropriate set from the drop-down list. 22tracks Homepage 22tracks and Internet Explorer team up to bring you a completely new online music experience [22tracks Blog] 22tracks about [YouTube] [via BetaNews and The Next Web]

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