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  • Creating circular generic references

    - by M. Jessup
    I am writing an application to do some distributed calculations in a peer to peer network. In defining the network I have two class the P2PNetwork and P2PClient. I want these to be generic and so have the definitions of: P2PNetwork<T extends P2PClient<? extends P2PNetwork<T>>> P2PClient<T extends P2PNetwork<? extends T>> with P2PClient defining a method of setNetwork(T network). What I am hoping to describe with this code is: A P2PNetwork is constituted of clients of a certain type A P2PClient may only belong to a network whose clients consist of the same type as this client (the circular-reference) This seems correct to me but if I try to create a non-generic version such as MyP2PClient<MyP2PNetwork<? extends MyP2PClient>> myClient; and other variants I receive numerous errors from the compiler. So my questions are as follows: Is a generic circular reference even possible (I have never seen anything explicitly forbidding it)? Is the above generic definition a correct definition of such a circular relationship? If it is valid, is it the "correct" way to describe such a relationship (i.e. is there another valid definition, which is stylistically preferred)? How would I properly define a non-generic instance of a Client and Server given the proper generic definition?

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  • Extending Controller

    - by MakDotGNU
    Hi, I'm very new to Kohana and I'm trying to make a project in kohana 2.x, in my previous projects i had created a Base controller which used to extends Controller. and all other controller to Base_Controller. in Kohana I'm facing the problem. here is my structure. class Base_Controller extends Template_Controller class Home_Controller extends Base_Controller both these Controllers are in application/controller folder Fatal error: Class 'Base_Controller' not found in /home/myadav/public_html/innteract/innteract/controllers/home.php on line 2

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  • Extending the IndexController with a BaseController in Zend

    - by BillA
    I'm trying to extend my controllers with a global base controller as such: class BaseController extends Zend_Controller_Action { // common controller actions public function listAction() { // do stuff } } class IndexController extends BaseController { // index controller specific actions } class LoginController extends BaseController { // login controller specific actions } But I get this error: PHP Fatal error: Class 'BaseController' not found in /var/www/Zend/project/application/controllers/IndexController.php on line 3 Any ideas on how to get Zend to "see" this controller?

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  • Java multi Generic collection parameters complie error

    - by Geln Yang
    Hi, So strange!Please have a look the code first: public class A { } public class B extends A { } public class C extends A { } public class TestMain { public <T extends A> void test(T a, T b) { } public <T extends A> void test(List<T> a, List<T> b) { } public static void main(String[] args) { new TestMain().test(new B(), new C()); new TestMain().test(new ArrayList<B>(), new ArrayList<C>()); } } The statement "new TestMain().test(new ArrayList(), new ArrayList())" get a "Bound mismatch" compile error, while "new TestMain().test(new B(), new C())" is compiled ok. Bound mismatch: The generic method test(T, T) of type TestMain is not applicable for the arguments (ArrayList, ArrayList). The inferred type ArrayList is not a valid substitute for the bounded parameter It seems the type of the second generic List parameter is limited by the Type of the first.Is it a feature or a bug of the compile program? ps, jdk:1.6,IDE:Eclipse 3.5.1

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  • Why i can not acces the protected properties in my web application

    - by GigaPr
    Hi i have a web application which has a Base class in which i define all the properties common to the web pages. The base class extends System.Web.UI.Page Furthermore i have a Base User control class where are defined all the properties common to the user controls. the Base User Control extends System.Web.UI.UserControl all the properties in both base classes are protected. All the web pages extends the base class . All the controls extends the base user control class. The problem is i can not access the properties defined in the base class from the user controls and I can not extend two classes in the base user controls The question is how can i access the properties defined in the Base class from within the user controls? I hope i have been clear Thanks

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  • Returning the same type the function was passed

    - by Ken Bloom
    I have the following code implementation of Breadth-First search. trait State{ def successors:Seq[State] def isSuccess:Boolean = false def admissableHeuristic:Double } def breadthFirstSearch(initial:State):Option[List[State]] = { val open= new scala.collection.mutable.Queue[List[State]] val closed = new scala.collection.mutable.HashSet[State] open.enqueue(initial::Nil) while (!open.isEmpty){ val path:List[State]=open.dequeue() if(path.head.isSuccess) return Some(path.reverse) closed += path.head for (x <- path.head.successors) if (!closed.contains(x)) open.enqueue(x::path) } return None } If I define a subtype of State for my particular problem class CannibalsState extends State { //... } What's the best way to make breadthFirstSearch return the same subtype as it was passed? Supposing I change this so that there are 3 different state classes for my particular problem and they share a common supertype: abstract class CannibalsState extends State { //... } class LeftSideOfRiver extends CannibalsState { //... } class InTransit extends CannibalsState { //... } class RightSideOfRiver extends CannibalsState { //... } How can I make the types work out so that breadthFirstSearch infers that the correct return type is CannibalsState when it's passed an instance of LeftSideOfRiver? Can this be done with an abstract type member, or must it be done with generics?

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  • Combining multiple classes gives me errors

    - by Martti Laine
    Hello I'm creating a website with structure like this: class main { } class mysql extends main { } class user extends main { } class etc extends main { } The idea is for these classes to use functions from each other. This doesn't work. How can I call a function from mysql in user? Martti Laine

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  • Combination of JFreeChart with JXLayer with JHotDraw

    - by Yan Cheng CHEOK
    Recently, I had use JXLayer, to overlay two moving yellow message boxes, on the top of JFreeChart http://yccheok.blogspot.com/2010/02/investment-flow-chart.html I was wondering, had anyone experience using JXLayer + JHotdraw, to overlay all sorts of figures (Re-sizable text box, straight line, circle...), on the top of JFreeChart. I just would like to add drawing capability, without changing the JFreeChart source code. So that, JStock's user may draw trending lines, annotation text on their favorite stock charting. The code skeleton is as follow : // this.chartPanel is JFreeChartPanel final org.jdesktop.jxlayer.JXLayer<ChartPanel> layer = new org.jdesktop.jxlayer.JXLayer<ChartPanel>(this.chartPanel); this.myUI = new MyUI<ChartPanel>(this); layer.setUI(this.myUI); public class MyUI<V extends javax.swing.JComponent> extends AbstractLayerUI<V> { @Override protected void paintLayer(Graphics2D g2, JXLayer<? extends V> layer) { // Previous, I am using my own hand-coded, to draw the yellow box // // Now, How can I make use of JHotDraw at here, to draw various type of // figures? } @Override protected void processMouseEvent(MouseEvent e, JXLayer<? extends V> layer) { // How can I make use of JHotDraw at here? } @Override protected void processMouseMotionEvent(MouseEvent e, JXLayer<? extends V> layer) { // How can I make use of JHotDraw at here? } } As you see, I already got Graphics2D g2 from paintLayer method. How is it possible that I can pass the Graphics2D object to JHotDraw, and let JHotDraw handles all the drawing. My experience in using JHotDraw are with org.jhotdraw.draw.DefaultDrawingView org.jhotdraw.draw.DefaultDrawingEditor I am able to use them to draw various figures, by clicking on the toolbar and click on drawing area. How is it possible I can use DefaultDrawingView and DefaultDrawingEditor within MyUI's paintLayer? Also, shall I let MyUI handles the mouse event, or JHotDraw? Sorry, I start getting confused.

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  • How to combine multiple uiBinder-based widgets?

    - by jprusakova
    I need to insert a [number of] uiBinder-based widgets into another one, at a particular spot. The inserted widget has a somewhat complicated layout, so I am trying to define it in HTML. referencePanel.add(...) fails with NoSuchElement exception. reference.getElement().toSource returns "undefined". Any suggestions on how to do that? public class AppUIDemo extends Composite { @UiTemplate("AppUIDemo.ui.xml") interface AppUIDemoUiBinder extends UiBinder<Widget, AppUIDemo> { } @UiTemplate("ReferenceUI.ui.xml") interface ReferenceUIUiBinder extends UiBinder<Widget, ReferenceUI> { } private static AppUIDemoUiBinder uiBinder = GWT .create(AppUIDemoUiBinder.class); private static ReferenceUIUiBinder refUIBinder = GWT .create(ReferenceUIUiBinder.class); @UiField HTMLPanel referencePanel; public AppUIDemo() { initWidget(uiBinder.createAndBindUi(this)); ReferenceUI reference = new ReferenceUI(refUIBinder); referencePanel.add(reference, reference.getElement().getId()); } } public class ReferenceUI extends Composite { interface ReferenceUIUiBinder extends UiBinder<Widget,ReferenceUI> { } private static ReferenceUIUiBinder uiBinder = GWT .create(ReferenceUIUiBinder.class); public ReferenceUI() { initWidget(uiBinder.createAndBindUi(this)); } public CreditReferenceUI(final UiBinder<Widget, CreditReferenceUI> binder) { initWidget(binder.createAndBindUi(this)); } }

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  • Problem with Autowiring & No unique bean

    - by mada
    I have 2 classes (B,C) extends class A. @Service public class A extends AbstratClass<Modele>{ @Autowired A(MyClass br) { super(br); } @Service public class B extends A{ @Autowired B (MyClass br) { super(br); } @Service public class C extends A{ @Autowired C (MyClass br) { super(br); } But i have this message: No unique bean of type [A] ] is defined: expected single matching bean but found 2: [A, B, moveModeleMarshaller] I really cant get why i have this message & how to resolve even after reading Spring documentation. Thanks in advance.

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  • JAVA Inheritance Generics and Casting.

    - by James Moore
    Hello, I have two classes which both extends Example. public class ClassA extends Example { public ClassA() { super("a", "class"); } .... } public class ClassB extends Example { public ClassB() { super("b", "class"); } .... } public class Example () { public String get(String x, String y) { return "Hello"; } } So thats all very well. So suppose we have another class called ExampleManager. With example manager I want to use a generic type and consequently return that generic type. e.g. public class ExampleManager<T extends Example> { public T getExample() { return new T("example","example"); // So what exactly goes here? } } So where I am returning my generic type how do i get this to actually work correctly and cast Example as either classA or classB? Many Thanks

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  • Scala newbie vproducer/consumer attempt running out of memory

    - by Nick
    I am trying to create a producer/consumer type Scala app. The LoopControl just sends a message to the MessageReceiver continually. The MessageReceiver then delegates work to the MessageCreatorActor (whose work is to check a map for an object, and if not found create one and start it up). Each MessageActor created by this MessageCreatorActor is associated with an Id. Eventually this is where I want to do business logic. But I run out of memory after 15 minutes. Its finding the cached actors,but quickly runs out of memory. Any help is appreciated. Or any one has any good code on producers consumers doing real stuff (not just adding numbers), please post. import scala.actors.Actor import java.util.HashMap import scala.actors.Actor._ case object LoopControl case object MessageReceiver case object MessageActor case object MessageActorCreator class MessageReceiver(msg: String) extends Actor { var messageActorMap = new HashMap[String, MessageActor] val messageCreatorActor = new MessageActorCreator(null, null) def act() { messageCreatorActor.start loop { react { case MessageActor(messageId) => if (msg.length() > 0) { var messageActor = messageActorMap.get(messageId); if(messageActor == null) { messageCreatorActor ! MessageActorCreator(messageId, messageActorMap) }else { messageActor ! MessageActor } } } } } } case class MessageActorCreator(msg:String, messageActorMap: HashMap[String, MessageActor]) extends Actor { def act() { loop { react { case MessageActorCreator(messageId, messageActorMap) => if(messageId != null ) { var messageActor = new MessageActor(messageId); messageActorMap.put(messageId, messageActor) println(messageActorMap) messageActor.start messageActor ! MessageActor } } } } } class LoopControl(messageReceiver:MessageReceiver) extends Actor { var count : Int = 0; def act() { while (true) { messageReceiver ! MessageActor ("00-122-0X95-FEC0" + count) //Thread.sleep(100) count = count +1; if(count > 5) { count = 0; } } } } case class MessageActor(msg: String) extends Actor { def act() { loop { react { case MessageActor => println() println("MessageActor: Got something-> " + msg) } } } } object messages extends Application { val messageReceiver = new MessageReceiver("bootstrap") val loopControl = new LoopControl(messageReceiver) messageReceiver.start loopControl.start }

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  • Constraint Validation

    - by tanuja
    I am using javax.validation.Validator and relevant classes for annotation based validation. Configuration<?> configuration = Validation.byDefaultProvider().configure(); ValidatorFactory factory = configuration.buildValidatorFactory(); Validator validator = factory.getValidator(); Set<ConstraintViolation<ValidatableObject>> constraintViolations = validator.validate(o); for (ConstraintViolation<ValidatableObject> value : constraintViolations) { List< Class< ? extends ConstraintValidator< ? extends Annotation,?>>> list = value.getConstraintDescriptor().getConstraintValidatorClasses(); } I get a compilation error stating: Type mismatch: cannot convert from List< Class< ? extends ConstraintValidator< capture#4-of ?,? to List< Class< ? extends ConstraintValidator< ? extends Annotation,? What am I missing?

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  • Is there any way to achieve multiple inheritance in php?

    - by Starx
    Lets say I have a parent class class parent { } ..... This parent has three sub class class child1 { } class child2 { } class child3 { } and these child classes have further smaller parts like class child1subpar1 { } class child1subpar2 { public function foo() { echo "hi"; } } class child2subpar1 { } class child2subpar2 { } Now, how to sum this whole up like class child1 extends child1subpar1, child1subpar2 { } class child2 extends child2subpar1, childsubpar1 { } class parent extends child1,child2,child3 { } I need to execute the methods in its inherited classes and do something like this $objparent = new parent; $objparent - foo();

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  • java thread - run() and start() methods

    - by JavaUser
    Please explain the output of the below code: If I call th1.run() ,the output is EXTENDS RUN RUNNABLE RUN If I call th1.start() , the output is : RUNNABLE RUN EXTENDS RUN Why this inconsistency . Please explain. class ThreadExample extends Thread{ public void run(){ System.out.println("EXTENDS RUN"); } } class ThreadExampleRunnable implements Runnable { public void run(){ System.out.println("RUNNABLE RUN "); } } class ThreadExampleMain{ public static void main(String[] args){ ThreadExample th1 = new ThreadExample(); //th1.start(); th1.run(); ThreadExampleRunnable th2 = new ThreadExampleRunnable(); th2.run(); } }

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  • Java - Syntax Question: What is <? super T>

    - by aloh
    I'm having trouble understanding the following syntax: public class SortedList< T extends Comparable< ? super T> > extends LinkedList< T > I see that class SortedList extends LinkedList. I just don't know what T extends Comparable< ? super T> means. My understanding of it so far is that type T must be a type that implements Comparable...but what is "< ? super T "?

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  • help with generating models from database for many to many in doctrine

    - by ajsie
    im using doctrine and i have set up some test tables to be generated into models: I want a many-to-many relationship models (3 tables converted into 3 models) (things are simplified to make the point clear) mysql tables: user: id INT // primary key name VARCHAR group: id INT // primary key name VARCHAR user_group: user_id INT // primary and foreign key to user.id group_id INT // primary and foreign key to group.id i thought that it would generate these models (from the documentation): // User.php class User extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('id'); $this->hasColumn('name); } public function setUp() { $this->hasMany('Group as Groups', array( 'refClass' => 'UserGroup', 'local' => 'user_id', 'foreign' => 'group_id' ) ); } } // Group.php class Group extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('id'); $this->hasColumn('name); } public function setUp() { $this->hasMany('User as Users', array( 'refClass' => 'UserGroup', 'local' => 'group_id', 'foreign' => 'user_id' ) ); } } // UserGroup.php class UserGroup extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('user_id') ); $this->hasColumn('group_id') ); } } but it generated this: // User.php abstract class BaseUser extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('id'); $this->hasColumn('name'); } public function setUp() { $this->hasMany('UserGroup', array( 'local' => 'id', 'foreign' => 'user_id')); } } // Group.php abstract class BaseGroup extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('id'); $this->hasColumn('name'); } public function setUp() { $this->hasMany('UserGroup', array( 'local' => 'id', 'foreign' => 'group_id')); } } // UserGroup.php abstract class BaseUserGroup extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('user_id'); $this->hasColumn('group_id'); } public function setUp() { $this->hasOne('User', array( 'local' => 'user_id', 'foreign' => 'id')); $this->hasOne('Group', array( 'local' => 'group_id', 'foreign' => 'id')); } } as you can see, there is no 'refClass' in the 'User' and 'Group' models pointing to the 'UserGroup'. the 'UserGroup' table in this case is just another table from Doctrine's perspective not a reference table. I've checked my table definitions in mysql. They are correct. user_group has 2 columns (primary keys and foreign keys), each one pointing to the primary key in either User or Group. But i want the standard many-to-many relationship models in Doctrine models. I'd appreciate some help. I have struggled to figure it out for a half day now. What is wrong? Thanks!

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  • Generics in return types of static methods and inheritance

    - by Axel
    Generics in return types of static methods do not seem to get along well with inheritance. Please take a look at the following code: class ClassInfo<C> { public ClassInfo(Class<C> clazz) { this(clazz,null); } public ClassInfo(Class<C> clazz, ClassInfo<? super C> superClassInfo) { } } class A { public static ClassInfo<A> getClassInfo() { return new ClassInfo<A>(A.class); } } class B extends A { // Error: The return type is incompatible with A.getClassInfo() public static ClassInfo<B> getClassInfo() { return new ClassInfo<B>(B.class, A.getClassInfo()); } } I tried to circumvent this by changing the return type for A.getClassInfo(), and now the error pops up at another location: class ClassInfo<C> { public ClassInfo(Class<C> clazz) { this(clazz,null); } public ClassInfo(Class<C> clazz, ClassInfo<? super C> superClassInfo) { } } class A { public static ClassInfo<? extends A> getClassInfo() { return new ClassInfo<A>(A.class); } } class B extends A { public static ClassInfo<? extends B> getClassInfo() { // Error: The constructor ClassInfo<B>(Class<B>, ClassInfo<capture#1-of ? extends A>) is undefined return new ClassInfo<B>(B.class, A.getClassInfo()); } } What is the reason for this strict checking on static methods? And how can I get along? Changing the method name seems awkward.

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  • what would be the output?

    - by Abhishek Jain
    Please explain me below situation What would be the output? interface A{} class B implements A{} class C extends B{} Class D extends C{} class E extends D{ public static void main(String args[]){ C c = new C(); B b = c; A a = (E)c; A a = (B)c; C c = (C)(B)c; } }

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  • Problem persisting inheritance tree

    - by alaiseca
    I have a problem trying to map an inheritance tree. A simplified version of my model is like this: @MappedSuperclass @Embeddable public class BaseEmbedded implements Serializable { @Column(name="BE_FIELD") private String beField; // Getters and setters follow } @MappedSuperclass @Embeddable public class DerivedEmbedded extends BaseEmbedded { @Column(name="DE_FIELD") private String deField; // Getters and setters follow } @MappedSuperclass public abstract class BaseClass implements Serializable { @Embedded protected BaseEmbedded embedded; public BaseClass() { this.embedded = new BaseEmbedded(); } // Getters and setters follow } @Entity @Table(name="MYTABLE") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="TYPE", discriminatorType=DiscriminatorType.STRING) public class DerivedClass extends BaseClass { @Id @Column(name="ID", nullable=false) private Long id; @Column(name="TYPE", nullable=false, insertable=false, updatable=false) private String type; public DerivedClass() { this.embedded = new DerivedClass(); } // Getters and setters follow } @Entity @DiscriminatorValue("A") public class DerivedClassA extends DerivedClass { @Embeddable public static NestedClassA extends DerivedEmbedded { @Column(name="FIELD_CLASS_A") private String fieldClassA; } public DerivedClassA() { this.embedded = new NestedClassA(); } // Getters and setters follow } @Entity @DiscriminatorValue("B") public class DerivedClassB extends DerivedClass { @Embeddable public static NestedClassB extends DerivedEmbedded { @Column(name="FIELD_CLASS_B") private String fieldClassB; } public DerivedClassB() { this.embedded = new NestedClassB(); } // Getters and setters follow } At Java level, this model is working fine, and I believe is the appropriate one. My problem comes up when it's time to persist an object. At runtime, I can create an object which could be an instance of DerivedClass, DerivedClassA or DerivedClassB. As you can see, each one of the derived classes introduces a new field which only makes sense for that specific derived class. All the classes share the same physical table in the database. If I persist an object of type DerivedClass, I expect fields BE_FIELD, DE_FIELD, ID and TYPE to be persisted with their values and the remaining fields to be null. If I persist an object of type DerivedClass A, I expect those same fields plus the FIELD_CLASS_A field to be persisted with their values and field FIELD_CLASS_B to be null. Something equivalent for an object of type DerivedClassB. Since the @Embedded annotation is at the BaseClass only, Hibernate is only persisting the fields up to that level in the tree. I don't know how to tell Hibernate that I want to persist up to the appropriate level in the tree, depending on the actual type of the embedded property. I cannot have another @Embedded property in the subclasses since this would duplicate data that is already present in the superclass and would also break the Java model. I cannot declare the embedded property to be of a more specific type either, since it's only at runtime when the actual object is created and I don't have a single branch in the hierarchy. Is it possible to solve my problem? Or should I resignate myself to accept that there is no way to persist the Java model as it is? Any help will be greatly appreciated.

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  • How do I synchronize GUI-Elements?

    - by anonymous2500
    Hello, I have a little problem with my java-program. I wanna use Observer, to synchronize two GUIs. But I can't synchronize the JComponent / JButton elements. For example: I have a GUI-Class which implements the Observer-Class: public class GUI extends JFrame implements Observer I have a second "GUI"-Class which extends the JButton-Class and makes changes on a specific Button-Element. public class Karte extends JButton{ ... this.setEnabled(false); ... How do I synchronize this Button via Observable? I have already tried to use "extends Observable" in this class, but the "setEnabled()" method is explicit for the JButton-Class, which is not Observable! Can someone help? Thanks.

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  • Interface with generic parameters- can't get it to compile

    - by user997112
    I have an interface like so: public interface MyInterface<E extends Something1> { public void meth1(MyClass1<E> x); } and I have a subclass whose superclass implements the above interface: public class MyClass2<E extends Something1> extends Superclass{ public MyClass2(){ } public void meth1(MyClass1 x) { // TODO Auto-generated method stub } } superclass: public abstract class Superclass<E extends Something1> implements MyInterface{ MyClass1<E> x; protected E y; public Superclass(){ } } the problem is that the parameter for meth1() is supposed to be generic. If I do MyClass1 it doesn't like it and the only way I can get it to compile is by leaving out generic parameters- which feels wrong. What's going wrong?

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  • Refactoring huge if ( ... instanceof ...)

    - by Chris
    I'm currently trying to refactor a part of a project that looks like this: Many classes B extends A; C extends A; D extends C; E extends B; F extends A; ... And somewhere in the code: if (x instanceof B){ B n = (B) x; ... }else if (x instanceof C){ C n = (C) x; ... }else if (x instanceof D){ D n = (D) x; ... }else if (x instanceof E){ E n = (E) x; ... }else if (x instanceof G){ G n = (G) x; ... }... Above if-construct currently sits in a function with a CC of 19. Now my question is: Can I split this if-construct up in mutliple functions and let Java's OO do the magic? Or are there any catches I have to look out for? My idea: private void oopMagic(C obj){ ... Do the stuff from the if(x instanceof C) here} private void oopMagic(D obj){ ... Do the stuff from the if(x instanceof D) here} private void oopMagic(E obj){ ... Do the stuff from the if(x instanceof E) here} .... and instead of the huge if: oopMagic(x);

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  • A strange error in java generic.

    - by ???
    This is ok: Class<? extends String> stringClass = "a".getClass(); But this gets error: <T> void f(T obj) { Class<? extends T> objClass = obj.getClass(); } I know I can cast it like: <T> void f(T obj) { @SuppressWarnings("unchecked") Class<? extends T> objClass = (Class<? extends T>) obj.getClass(); } But why the previous error? Will the next release of Java 7 will support such usage?

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