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  • Formatting made easy - Silverlight 4

    - by PeterTweed
    One of the simplest tasks in business apps is displaying different types of data to be read in the format that the user expects them.  In Silverlight versions until Silverlight 4 this has meant using a Converter to format data during binding.  This involves writing code for the formatting of the data to bind, instead of simply defining the formatting to use for the data in question where you bind the data to the control.   In Silverlight 4 we find the addition of the StringFormat markup extension that allows us to do exactly this.  Of course the nice thing is the ability to use the common formatting conventions available in C# through the String.Format function.   This post will show you how to use three of the common formatting conventions - currency, a defined number of decimal places for a number and a date format.   Steps:   1. Create a new Silverlight 4 application   2. In the body of the MainPage.xaml.cs file replace the MainPage class with the following code:       public partial class MainPage : UserControl     {         public MainPage()         {             InitializeComponent();             this.Loaded += new RoutedEventHandler(MainPage_Loaded);         }           void MainPage_Loaded(object sender, RoutedEventArgs e)         {             info i = new info() { PriceValue = new Decimal(9.2567), DoubleValue = 1.2345678, DateValue = DateTime.Now };             this.DataContext = i;         }     }         public class info     {         public decimal PriceValue { get; set; }         public double DoubleValue { get; set; }         public DateTime DateValue { get; set; }     }   This code defines a class called info with different data types for the three properties.  A new instance of the class is created and bound to the DataContext of the page.   3.  In the MainPage.xaml file copy the following XAML into the LayoutRoot grid:           <Grid.RowDefinitions>             <RowDefinition Height="60*" />             <RowDefinition Height="28*" />             <RowDefinition Height="28*" />             <RowDefinition Height="30*" />             <RowDefinition Height="154*" />         </Grid.RowDefinitions>         <Grid.ColumnDefinitions>             <ColumnDefinition Width="86*" />             <ColumnDefinition Width="314*" />         </Grid.ColumnDefinitions>         <TextBlock Grid.Row="1" Height="23" HorizontalAlignment="Left" Margin="32,0,0,0" Name="textBlock1" Text="Price Value:" VerticalAlignment="Top" />         <TextBlock Grid.Row="2" Height="23" HorizontalAlignment="Left" Margin="32,0,0,0" Name="textBlock2" Text="Decimal Value:" VerticalAlignment="Top" />         <TextBlock Grid.Row="3" Height="23" HorizontalAlignment="Left" Margin="32,0,0,0" Name="textBlock3" Text="Date Value:" VerticalAlignment="Top" />         <TextBlock Grid.Column="1" Grid.Row="1" Height="23" HorizontalAlignment="Left" Name="textBlock4" Text="{Binding PriceValue, StringFormat='C'}" VerticalAlignment="Top" Margin="6,0,0,0" />         <TextBlock Grid.Column="1" Grid.Row="2" Height="23" HorizontalAlignment="Left" Margin="6,0,0,0" Name="textBlock5" Text="{Binding DoubleValue, StringFormat='N3'}" VerticalAlignment="Top" />         <TextBlock Grid.Column="1" Grid.Row="3" Height="23" HorizontalAlignment="Left" Margin="6,0,0,0" Name="textBlock6" Text="{Binding DateValue, StringFormat='yyyy MMM dd'}" VerticalAlignment="Top" />   This XAML defines three textblocks that use the StringFormat markup extension.  The three examples use the C for currency, N3 for a number with 3 decimal places and yyy MM dd for a date that displays year 3 letter month and 2 number date.   4. Run the application and see the data displayed with the correct formatting. It's that easy!

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  • What is the best way to embed controls in a list/grid

    - by Brad
    I have a table of about 450 rows that I would like to display in a graphical list for users to view or modify the line items. The users would be selection options from comboboxes and selecting check boxes etc. I have found a listview class that extends the basic listview to allow for embeding objects but it seems kind of slugish when I load all the rows into it. I have used a datagridview in the past for comboboxes and checkboxes, but there was a lot of time invested in getting that up and running...not a big fav of mine. I am looking for sugestions how I can do this with minimal overhead. thanks c#, vs2008, .net 2.0, system.windows.forms

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  • C# Executing timed commands with varying times

    - by Gio Borje
    I have a timer control and a grid with a List of coordinates for the grid. I was wondering how I could use the timer control or any other control in order to execute code in the interval, coordinate.Time as it varies for each coordinate. Also, thread.sleep(time) is not an option for me. foreach (Coordinate coordinate in this.Macro) { coordinate.Time; coordinate.Initial; coordinate.Final; ... executecode @ coordinate.Time. }

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  • Solution for distributing MANY simple network tasks?

    - by EmpireJones
    I would like to create some sort of a distributed setup for running a ton of small/simple REST web queries in a production environment. For each 5-10 related queries which are executed from a node, I will generate a very small amount of derived data, which will need to be stored in a standard relational database (such as PostgreSQL). What platforms are built for this type of problem set? The nature, data sizes, and quantities seem to contradict the mindset of Hadoop. There are also more grid based architectures such as Condor and Sun Grid Engine, which I have seen mentioned. I'm not sure if these platforms have any recovery from errors though (checking if a job succeeds). What I would really like is a FIFO type queue that I could add jobs to, with the end result of my database getting updated. Any suggestions on the best tool for the job?

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  • Positioning Photos in a Grid (HTML)

    - by Daniel O'Connor
    Hey Everyone, I've been trying to code this page for a while, but my biggest problem is that I can't seem to get the photos perfectly positioned. For some reason, there is a small bottom padding in each <td>which is messing things up. Here is the table code: <table> <tr> <td rowspan="2" style="height:353px;"><img src="danoconnor/img/photography/farm.jpg" height="353" width="470" alt="Farm" /></td> <td><img src="danoconnor/img/photography/paragliding.jpg" height="190" width="254" alt="Paraglider" /></td> <td rowspan="2"><img src="danoconnor/img/photography/cristo.jpg" height="353" width="230" alt="Cristo Redentor" /></td> </tr> <tr> <td><img src="danoconnor/img/photography/u2.jpg" height="154" width="254" alt="U2 at Fordham University" /></td> </tr> </table> My question is: how can I make the photogrid look like this? Thanks!

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  • How to expose a control collection to a property grid at design time

    - by Stefano Delendati
    I have a custom control that with a property that is a collection of custom object. This custom object hava a reference to some component/controls. When at design time I tray to add an item to the collection and select the object, VS tells me that the control is not serializable. This is the code (simplified version - but not to much): public class ViewRefObj { public control view { get; set; } public ViewRefObj() { } } private List<ViewRefObj> _controls=new List<ViewRefObj>(); public List<ViewRefObj> Views { get { return _controls; } }

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  • access: creating a grid for a report

    - by every_answer_gets_a_point
    i will be printing the access report. the report will not be printed a regular white people. it will be printed on top of a paper with checkboxes and fields on it. i need those checkboxes and fields to be printed on according to the access data. are there any libraries for access that make this easier? is there a feature that will help to print on specific coordinates?

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  • Show only div of the product hovering in category grid with jQuery

    - by Dane
    On Magento, I'm trying to get avalable attributes per product in a new div (show/ hide onmouseover) as soon as I hover a product. Unfortunately, my jQuery code opens every div with the same name. I think, I need to do it with jQuery(this) but I tried it in a 1000 different ways, and it won't work. Maybe, somebody here can help me with a better code. jQuery(function() { jQuery('.slideDiv').hide().data('over', false); jQuery('#hover').hover(function() { jQuery('.slideDiv').fadeIn(); }, function() { // Check if mouse did not go over .dialog before hiding it again var timeOut = setTimeout(function() { if (!jQuery('.slideDiv').data('over')) { jQuery('.slideDiv').fadeOut(); clearTimeout(timeOut); } }, 100); }); // Set data for filtering on mouse events for #hover-here jQuery('.slideDiv').hover(function() { jQuery(this).data('over', true); }, function() { jQuery(this).fadeOut().data('over', false); }); }); The PHP just prints the attributes needed. <a href="#" id="hover">Custom Attributes</a> <div class="slideDiv"> <?php $attrs = $_product->getTypeInstance(true)->getConfigurableAttributesAsArray($_product); foreach($attrs as $attr) { if(0 == strcmp("shoe_size", $attr['attribute_code'])) { $options = $attr['values']; print "Größen:<br />"; foreach($options as $option) { print "{$option['store_label']}<br />"; } } } ?> </div> I added the script to [new link] http://jsfiddle.net/xsxfr/47/ so you can see there, that it is not working like this right now :(.

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  • Handling row selection from a simple grid using jquery and asp.net mvc

    - by Jonn
    Using a simple table and jquery, how would you manually handle selection using jquery? So far, I've managed to add a gridrowselected class on the tr when the click event is called so that I'll know which row is currently selected. But I don't know how to pass the selected data back to the controller (or at least an index I placed on the row). I tried something like this $(function() { $('#ProjectList .gridrow').click(function() { // Get row's index var projectId = $(this).find('input[name$=ProjectId]').val(); // Remove the input if it already exists var parentForm = $(this).parents('form'); parentForm.remove('input[name="selectedRows"][value="' + projectId + '"]'); // If it is selected, create the form. If it's not selected then the input just gets removed (the user must have clicked on it and deselected the row) if ($(this).hasClass('gridrow-selected') === true) { parentForm.append($('<input>', { type: "hidden", name: "selectedRows", value: projectId })); } }); }); which I'm expecting to create a hidden input so that when I post, selectedRows gets passed onto the controller. But all it does is create the input, but the data still doesn't get passed to the controller.

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  • Unable to bind in asp.net grid Template Column

    - by OneSmartGuy
    I am having trouble accessing the data field. I receive the error: Databinding methods such as Eval(), XPath(), and Bind() can only be used in the context of a databound control. I can get the value but using <%# getOpenJobs((string)Eval("ParentPart")) % but I need to use it in the if to display a certian picture if it passes the condition. Is there a better way to do this or am i just missing something simple? <telerik:GridTemplateColumn UniqueName="hasOpenJobs" HeaderText=""> <ItemTemplate> <% if (getOpenJobs((string)Eval("ParentPart")) > 1) { %> <img src="../images/job-icon.gif" alt="Open Jobs" /> <%} %> </ItemTemplate> </telerik:GridTemplateColumn>

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  • ListView GridView and Grid

    - by urema
    Hi, If you have a ListView with its view set as a GridView, which itself contains columns for each month say.....how do I set a template up for the ItemTemplate of the ListView so that each Item will be three rows high, and be inline with the ListView.View's columns? For example different employee recruits over a year.... each month across the top and each employee on the left side, though sub-columned on the employee are three rows "Name", "Address" and "Job Type" say. I know you have to use the IsSharedSizeScope attached property. January February ... Employee1 Name E1 Address E1 Street Job Type Cleaner Employee2 Name ... Address ... Job Type ... Thanks greatly in advance, U.

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  • read contents of a sql table into a data grid view

    - by syedsaleemss
    Im using c# .net windows application form. i have created a database named "resources" in SQL server 2005. In that i have a table named "resourcetable" which has two columns. now i need to read the data in the table into a datagridview. I can do this by using the connection string and querry by giving the table name. But my problem is i have a button and if i click on that button, an open dialog box should open and i should be able to select a database amomng many databases and in that selected database i have to select one table amomg many tables. i.e select a table ofa particular database. and the contents of that table are to be displayed in a datagridview.

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  • Android layout issue - table/grid/linear

    - by phpmysqlguy
    I am trying to wrap my head around some basic layout issues in android. Here is what I want as my final goal: As you can see, various fields set up like that. The fields get filled in based on XML data. There could be 1 set of fields, or there could be more. I tried a tablelayout, but couldn't get it set up right even when layout_span for Field 7. It worked ok, but when I tried to change the widths of Field 1 thru 5, the spanned row below it didn't conform to the changes (not like an HTML table would). The fields in each group need to lineup if there are more than one (see red lines in image). Can someone point me in the right direction on how I should approach this? Thanks

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  • multiline column in data grid view. using c#

    - by syedsaleemss
    Im using c# .net windows form application. i have a datagrid view. It has two columns.I need to make all the cells on the second column as to have multiple line. i.e a multiline column. I will edit something in a cell and press enter key. the cursor should reach the next line in the same cell. It should not go to the next cell. What should i do?

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  • Navigate through .Net Grid

    - by SH
    is there a way to navigate through gird found on this page by passing parameters in query string? http://pubrec3.hillsclerk.com/oncore/search.aspx?bd=01/01/2008&ed=12/31/2008&bt=O&lb=1000000&ub=1000000000&d=5/6/2010&pt=-1&dt=D,%20MTG&st=consideration Or any code suggestion? All example could i need in C#.

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  • ASP.NET Grid with CSS in Rows and Columns

    - by user1089173
    I have the following code List<Department> depts = new List<Department>(); Department.Add(new Department() { DNo = 1, DName = "Accounting", DFloor="6" }); Department.Add(new Department() { DNo = 2, DName = "FInance", DFloor="3" }); I want to bind this data to a GridView, so that it outputs the following. Observe the classes on each th and tr. How can I achieve this in ASP.NET? <thead> <tr> <th class="DNo">DNo</th> <th class="DName">DName</th> <th class= "DFloor">DFloor</th> </tr> </thead> <tr> <td class="DNo">1</td> <td class="DName">Accounting</td> <td class="DFloor">6</td> </tr> <tr> <td class="DNo">2</td> <td class="DName">FInance</td> <td class="DFloor">3</td> </tr>

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  • Not working for single click..Jquery Grid

    - by kumar
    $("#table_id").click(function(e) { var row = jQuery(e.target || e.srcElement).parent(); $("#table_id").bind('click', loaddata); name= row.attr("id"); }); loaddata is the funcation I am calling on click on each row.. but this cilck event is working for double click.. I mean when you double click its working fyn.. but i need it to work for single click on the row.. is that anything I am doing wrong here? thanks

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  • Insert and remove Template textbox column in grid view

    - by user1545215
    class TextColumn : ITemplate { private string controlId; private string cssClass; public TextColumn(string id, string cssClass = "inputFromTo") { controlId = id; this.cssClass = cssClass; } public void InstantiateIn(Control container) { TextBox txt = new TextBox(); txt.ID = controlId; txt.CssClass = cssClass; container.Visible = true; container.Controls.Add(txt); } } /******************* Add column code snippet ***************/ TemplateField dentry = new TemplateField(); TemplateField dexit = new TemplateField(); TemplateField dslack = new TemplateField(); dentry.ItemTemplate = new TextColumn("txtHH" + nameCount + "DEntry"); dexit.ItemTemplate = new TextColumn("txtHH" + nameCount + "DExit"); dslack.ItemTemplate = new TextColumn("txtHH" + nameCount + "DSlack"); gvOfcBlowingReport.Columns.Insert(startPoint, dentry); gvOfcBlowingReport.Columns.Insert(startPoint + 1, dexit); gvOfcBlowingReport.Columns.Insert(startPoint + 2, dslack); /***************** Remove column code snippet ************/ gvOfcBlowingReport.Columns.RemoveAt(startPoint - 1); gvOfcBlowingReport.Columns.RemoveAt(startPoint - 2); gvOfcBlowingReport.Columns.RemoveAt(startPoint - 3); // after executing this code all the columns vanish. Anyone know how to remove this text box template column?

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