XSLT: Get node where one certain value is present
- by Kim Andersen
Hi there
I have the following XML:
<data>
<page id="1118">
<itms>
<values>
<value>1104</value>
</values>
</itms>
</page>
<page id="1177">
<itms>
<values>
<value>1273</value>
<value>1215</value>
</values>
</itms>
</page>
</data>
I need to get the @id from the < page , where a certain value is present in one of the < value -tags. The id that need to be in the < value is kept in this: $itm/@id.
This means that if my $itm/@id is equal to 1273, I need to get 1177 returned. I'm not quite sure how to achieve this.
Actually I could have XML that looks like this as well:
<data>
<page id="1118">
<itms>
<values>
<value>1104</value>
</values>
</itms>
</page>
<page id="1177">
<itms>
<values>
<value>1273</value>
<value>1215</value>
</values>
</itms>
</page>
<page id="1352">
<itms>
<values>
<value>1242</value>
<value>1273</value>
</values>
</itms>
</page>
</data>
If that's the case, I need the latest id, so this means that if the $itm/@id matches values in more < page 's, then I need to grab the value from the latest page. I the above case that would be 1352.
Hope this makes sense to you guys. And by the way, I work with Umbraco CMS if that does any difference.
Best Regards,
Kim
