Search Results

Search found 34274 results on 1371 pages for 'mysql table'.

Page 31/1371 | < Previous Page | 27 28 29 30 31 32 33 34 35 36 37 38  | Next Page >

  • How to create sql insert query dynamically in mysql

    - by nectar
    I am creating an application where I am generating pins dynamically based on user's input and storing them into mySql database. $sql = "INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES for($i=0;$i<$npin;$i++) { ('$pin[$i]','$ownerid', 'Free', '1'); } ;"; how can I do that?

    Read the article

  • MySQL - Order results by relevancy, LEFT JOINS and more

    - by XaviEsteve
    Hi guys, I am trying to get some results ordered by total votes (where client votes count 2 points and other people votes are 1 point). tab_names: +-----------+ | Name | id | +------+----+ | John | 1 | | Paul | 2 | +------+----+ tab_votes: +--------+-----------+ | idname | ip | +--------+-----------+ | 2 | 127.0.0.1 | | 2 | 127.0.0.1 | | 2 | 82.23.5.1 | | 1 | 127.0.0.1 | +--------+-----------+ This is the MySQL query I've got but doesn't work: SELECT * COUNT(v.idname) AS totalvotes, (SELECT COUNT(v.ip) FROM tab_votes WHERE v.ip LIKE '$ip') AS uservotes FROM tab_names n LEFT JOIN tab_votes v ON n.id = v.idname GROUP BY n.name ORDER BY uservotes DESC, totalvotes DESC LIMIT 40

    Read the article

  • MySQL - Using an alias in a subquery with WHERE clause

    - by gaoshan88
    I have a feeling I am completely borking this MySQL query but I'll ask anyway. I am wondering why I get the warning Unknown column 'FOO', and how I can get this query to work properly, in 'where clause' when I run the following: SELECT sample_id as FOO FROM tbl_test WHERE sample_id = 521 AND sample_id IN ( Select sample_id FROM tbl_test WHERE sample_id = FOO GROUP BY sample_id )

    Read the article

  • mySQL - One large query vs Ajax indivdual queries

    - by Mark
    Hi guys, I guess no one will have a definative answer to this but considered predictions would be appriciated. I am in the process of developing a mySQL database for a web application and my question is: Is it more efficient to make a single query that returns a single row using AJAX or To request 100 - 700 rows when the user will likely only ever use the results of two or three? Really I am asking what is heavier for the server 2-3 requests with one result or 1 request with 100 - 700 results? Thanks, Mark

    Read the article

  • Timeout error occurred trying to start MySQL Daemon. CentOS 5

    - by epema
    I ran into troubles with MySQL on my CentOS. I had some problems and backed up my database and removed mysql with all dependencies. After that I ran reinstalled: yum groupinstall "MySQL Database" Installed without errors. Running the mysql daemon: service mysqld start Timeout error occurred trying to start MySQL Daemon. Starting MySQL: [FAILED] I also ran # /usr/bin/mysql_install_db --user=mysql Installing MySQL system tables... 120112 1:49:44 [ERROR] Error message file '/usr/share/mysql/english/errmsg.sys' had only 480 error messages, but it should contain at least 481 error messages. Check that the above file is the right version for this program! 120112 1:49:44 [ERROR] Aborting Installation of system tables failed! Examine the logs in /var/lib/mysql for more information. You can try to start the mysqld daemon with: /usr/libexec/mysqld --skip-grant & and use the command line tool /usr/bin/mysql to connect to the mysql database and look at the grant tables: shell> /usr/bin/mysql -u root mysql mysql> show tables Try 'mysqld --help' if you have problems with paths. Using --log gives you a log in /var/lib/mysql that may be helpful. The latest information about MySQL is available on the web at http://www.mysql.com Please consult the MySQL manual section: 'Problems running mysql_install_db', and the manual section that describes problems on your OS. Another information source is the MySQL email archive. Please check all of the above before mailing us! And if you do mail us, you MUST use the /usr/bin/mysqlbug script! Checking the logs: less /var/log/mysqld.log Log file is empty. I don't even know how to debug it and not sure what to do. Any recommendations? Thank you

    Read the article

  • Best way to check for NULL value in MySql query

    - by PHP-Prabhu
    Can any one please let me know the best way to use IF statement in mysql query to show if the "email" field is NULL then it should show as "no email"... Postcode Telephone Email ---------------------------------------------------------- BS20 0QN 1275373088 no email BS20 0QN 1275373088 no email PO9 4HG 023 92474208 [email protected] SO43 7DS 07801 715200 [email protected] ----------------------------------------------------------

    Read the article

  • MySQL 5.1.41 leading zero is deleted

    - by iggnition
    Hello, I have a MySQL database where i want to store phonenumbers among other things. The fieldtype is INT(10) When I try to insert a number starting with a 0, like 0504042858 it's stored like 504042858. This only happens with zeros when the number start with any other number it's stored correctly. What am I doing wrong?

    Read the article

  • php and mysql listing databases and looping through results

    - by Jacksta
    Beginner help needed :) I am doign an example form a php book which lists tables in databases. I am getting an error on line 36: $db_list .= "$table_list"; <?php //connect to database $connection = mysql_connect("localhost", "admin_cantsayno", "cantsayno") or die(mysql_error()); //list databases $dbs = @mysql_list_dbs($connection) or die(mysql_error()); //start first bullet list $db_list = "<ul>"; $db_num = 0; //loop through results of functions while ($db_num < mysql_num_rows($dbs)) { //get database names and make each a list point $db_names[$db_num] = mysql_tablename($dbs, $db_num); $db_list .= "<li>$db_names[$db_num]"; //get table names and make another list $tables = @mysql_list_tables($db_names[$db_num]) or die(mysql_error()); $table_list = "<ul>"; $table_num = 0; //loop through results of function while ($table_num < mysql_num_rows($tables)){ //get table names and make each bullet point $table_names[$table_num] = mysql_tablename($tables, $table_num); $table_list .= "<li>$table_names[$table_num]"; $table_num++; } //close inner bullet list and increment number to continue $table_list .= "</ul>" $db_list .= "$table_list"; $db_num++; } //close outer bullet list $db_list .= "</ul>"; ?> <html> <head> <title>MySQL Tables</title> </head> <body> <p><strong>Data bases and tables on local host</strong></p> <? echo "$db_list"; ?> </body>

    Read the article

  • Mysql timestamp query

    - by Hulk
    In mysql a result of a query is say select timestamp from newbie; | 2010-03-12 14:50:46 | | 2010-03-12 14:50:46 | | 2010-03-12 14:50:51 | | 2010-03-12 14:50:52 | | 2010-03-12 14:50:54 | | 2010-03-12 14:51:04 | | 2010-03-12 14:51:07 | | 2010-03-12 14:51:08 | Is there a way to subquery the above and sum up the i.e, the final result should be the delta of each row in hh:mm:ss format

    Read the article

  • MySQL - Structure for Permissions to Objects

    - by Kerry
    What would be an ideal structure for users permissions of objects. I've seen many related posts for general permissions, or what sections a user can access, which consists of a users, userGroups and userGroupRelations or something of that nature. In my system there are many different objects that can get created, and each one has to be able to be turned on or off. For instance, take a password manager that has groups and sub groups. Group 1 Group 2 Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Each group can contain a set of passwords. A user can be given read, write, edit and delete permissions to any group. More groups can get created at any point in time. If someone has permission to a group, I should be able to make him have permissions to all sub groups OR restrict it to just that group. My current thought is to have a users table, and then a permissions table with columns like: permission_id (int) PRIMARY_KEY user_id (int) INDEX object_id (int) INDEX type (varchar) INDEX read (bool) write (bool) edit (bool) delete (bool) This has worked in the past, but the new system I'm building needs to be able to scale rapidly, and I am unsure if this is the best structure. It also makes the idea of having someone with all subgroup permissions of a group more difficult. So, as a question, should I use the above structure? Or can someone point me in the direction of a better one?

    Read the article

  • Search number entries on a mysql database with COUNT

    - by skiria
    I have a mysql database which allocate: iid, name, description, url, namecategory, idcategory, nametopic, idtopic How can i know the number of entries that has categoryid=1 and topicid=1? I've try $result = mysql_query("SELECT COUNT(id) FROM videos WHERE categoryid=1 AND topicid=1") But it hasn't worked!

    Read the article

  • Mysql change column details

    - by Ankur
    I am trying to redefine the number of varchars a column can have (in a MySQL db). I am doing alter table obj_details IMG_SRC IMG_SRC varchar(180); I want to change the number of characters that can be used in the column IMG_SRC to 180 (it is currently 100). But I get an error saying that I should check the syntax near IMG_SRC IMG_SRC varchar(180).

    Read the article

  • MySQL help, counting information on last records

    - by ee12csvt
    I need some advice I have two tables, one holds unique serial numbers of items (items) and the other holds status changes and other information for these items (details) The Tables are set up as follows Item itemID itemName itemDate details detID itemID modlvl status detDate All items have at least one record in the details table, but over time the status has changed or the modification level has changed (Both of these are identified by numbers which are held in other appropriate tables) and a new record is created each time the status/modlvl changes I want to display a table on my webpage using php that identifies the different mod levels of the items and shows a count of each of the current status of the items EDIT Hi Ronnis, This is an example of the data in the tables and what I want to achieve The current Mod Levels range from 1 to 3 Status representations are 1 In Use 2 In Store 3 Being repaired 4 In Transit 5 For Disposal 6 Disposed 7 Lost Item itemID OrigMod created 1000 1 2009-10-01 22:12:12 1001 1 2009-10-01 22:12:12 1002 1 2009-10-01 22:12:12 1003 1 2009-10-01 22:12:12 1004 1 2009-10-01 22:12:12 1005 1 2009-10-01 22:12:12 1006 1 2009-10-01 22:12:12 1007 1 2009-10-01 22:12:12 1008 1 2009-10-01 22:12:12 1009 1 2009-10-01 22:12:12 1010 1 2009-10-01 22:12:12 Details detID itemID modlvl detDate status 1 1000 1 2009-10-01 1 2 1001 1 2009-10-01 1 3 1002 1 2009-10-01 1 4 1003 1 2009-10-01 1 5 1004 1 2009-10-01 1 6 1005 1 2009-10-01 1 7 1006 1 2009-10-01 1 8 1007 1 2009-10-01 1 9 1008 1 2009-10-01 1 10 1009 1 2009-10-01 1 11 1010 1 2009-10-01 1 12 1001 1 2010-02-01 2 13 1001 1 2010-02-03 4 14 1001 1 2010-03-01 3 15 1000 1 2010-03-14 2 16 1001 2 2010-04-01 4 17 1006 1 2010-04-01 2 18 1001 2 2010-04-03 2 19 1006 1 2010-04-14 4 20 1006 1 2010-05-01 5 21 1002 1 2010-05-02 2 22 1003 1 2010-05-10 2 23 1010 1 2010-06-01 2 24 1006 1 2010-06-18 6 25 1010 1 2010-07-01 7 26 1007 1 2010-07-02 2 27 1007 1 2010-07-04 4 28 1003 1 2010-07-10 2 29 1007 1 2010-07-11 3 30 1007 2 2010-07-12 4 31 1007 2 2010-07-15 2 32 1001 2 2010-08-31 1 33 1001 2 2010-09-10 2 34 1001 2 2010-10-01 4 35 1008 1 2010-10-01 2 36 1001 2 2010-10-05 3 37 1008 1 2010-10-05 4 38 1008 1 2010-10-10 3 39 1001 3 2010-10-20 4 40 1001 3 2010-10-25 2 Using the tables above I want to get this result MoLvl Use Store Repd Transit Displ Dispd Lost Total 1 3 3 1 0 0 1 1 9 2 0 1 0 0 0 0 0 1 3 0 1 0 0 0 0 0 1 Total 3 5 1 0 0 1 1 11

    Read the article

  • MySQL: Check if first character is _not_ A-Z

    - by dbemerlin
    I have to create an SQL Query to get all rows starting with a specific character, except if the parameter passed to the (PHP) function is 0, in that case it should get every row that does not start with A - Z (like #0-9.,$ etc). What is the easiest and fastest way to get those rows? DB: MySQL 5.1 Column: title

    Read the article

  • mySQL query: How to insert with UNION?

    - by Industrial
    Hi everybody, I am kind of new to mySQL:s union functions, at least when doing inserts with them. I have gotten the following to work based upon a example found on the net: INSERT INTO tableOne(a, b) SELECT a, $var FROM tableOne WHERE b = $var2 UNION ALL SELECT $var,$var Ok, nothing strange about that. But what happens when I want to insert a third value into the database that has nothing to do with the logic of the Select being done? Like : INSERT INTO tableOne(a, b, c ) How could that be done?

    Read the article

  • Mysql syntax help

    - by Karthick
    Query: select t1.col1 from table1 t1 inner join with (nolock) table2 t2 on t1.col2 = t2.col1 Am trying to use nolock option for optimized query in mySQL db, but for some reason the above query does not work and the error i receive is You have an error in your SQL syntax; Any thoughts?

    Read the article

  • MySQL friends table

    - by asmo
    I have a MySQL DB in which I store data about each user. I would like to add a list of friends for each user. Should I create a table of friends for each user in the DB or is there a better way?

    Read the article

  • Concate String In MYSQL

    - by streetparade
    How can i concate this string in mysql desc=desc+$desct what i want is each time i insert a variable from PHP that the string is added to the string which was already in db and seperated with || the field desc should look like this desc 10||30||90||710 say i want to add the value 20 desc 10||30||90||710||20 then the desc field should look like this How can i implement this?

    Read the article

< Previous Page | 27 28 29 30 31 32 33 34 35 36 37 38  | Next Page >