AlertDialog in if-stetement doesn't show()
- by Steffen Kern
I have the following code:
public void button_login(View view) {
// Instantiate an AlertDialog.Builder with its constructor
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) { /* User clicked OK button */ }
});
// Preserve EditText values.
EditText ET_username = (EditText) findViewById(R.id.username);
EditText ET_password = (EditText) findViewById(R.id.password);
String str_username = ET_username.toString();
String str_password = ET_password.toString();
// Intercept missing username and password.
if(str_username.length() == 0) {
builder.setMessage(R.string.hint_username_empty);
AlertDialog dialog = builder.create();
dialog.show();
}
}
I have an activity that includes the two EditText-Views and a button. When I click the button the shown method will be called.
My problem:
The AlertDialog doesnt show up!
When I put the create and show at beginning like this:
// Instantiate an AlertDialog.Builder with its constructor
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) { /* User clicked OK button */ }
});
builder.setMessage(R.string.hint_username_empty);
AlertDialog dialog = builder.create();
dialog.show();
// Preserve EditText values.
EditText ET_username = (EditText) findViewById(R.id.username);
EditText ET_password = (EditText) findViewById(R.id.password);
String str_username = ET_username.toString();
String str_password = ET_password.toString();
// Intercept missing username and password.
if(str_username.length() == 0) {
}
}
Then the Dialog shows up.
Any ideas why the dialog doesnt show up in the first place?
Greetz,
Steffen
