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  • Maximum number of characters using keystrokes A, Ctrl+A, Ctrl+C and Ctrl+V

    - by munda
    This is an interview question from google. I am not able to solve it by myself. Can somebody shed some light? Write a program to print the sequence of keystrokes such that it generates the maximum number of character 'A's. You are allowed to use only 4 keys: A, Ctrl+A, Ctrl+C and Ctrl+V. Only N keystrokes are allowed. All Ctrl+ characters are considered as one keystroke, so Ctrl+A is one keystroke. For example, the sequence A, Ctrl+A, Ctrl+C, Ctrl+V generates two A's in 4 keystrokes. Ctrl+A is Select All Ctrl+C is Copy Ctrl+V is Paste I did some mathematics. For any N, using x numbers of A's , one Ctrl+A, one Ctrl+C and y Ctrl+V, we can generate max ((N-1)/2)2 number of A's. For some N M, it is better to use as many Ctrl+A's, Ctrl+C and Ctrl+V sequences as it doubles the number of A's. The sequence Ctrl+A, Ctrl+V, Ctrl+C will not overwrite the existing selection. It will append the copied selection to selected one.

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  • Returning the element number of the longest string in an array

    - by JohnRoberts
    I'm trying to get the longestS method to take the user-inputted array of strings, then return the element number of the longest string in that array. I got it to the point where I was able to return the number of chars in the longest string, but I don't believe that will work for what I need. My problem is that I keep getting incompatible type errors when trying to figure this out. I don't understand the whole data type thing with strings yet. It's confusing me how I go about return a number of the array yet the array is of strings. The main method is fine, I got stuck on the ???? part. { public static void main(String [] args) { Scanner inp = new Scanner( System.in ); String [] responseArr= new String[4]; for (int i=0; i<4; i++) { System.out.println("Enter string "+(i+1)); responseArr[i] = inp.nextLine(); } int highest=longestS(responseArr); } public static int longestS(String[] values) { int largest=0 for( int i = 1; i < values.length; i++ ) { if ( ????? ) } return largest; } }

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  • cakephp phone number validation

    - by hellosheikh
    i am new to cakephp 2.x so i dont know how to do this .. i want to login the user from his email address and phone number..what my intention is if the number in database is this "12345" and the user is trying to login through this number "+12345" he can be login into the system.. i have written a code but i dont know how can i use this or to adjust my code within the auth component as the auth component is autometically logging the user .. here is my controller public function beforeFilter() { parent::beforeFilter(); $this->Auth->authenticate = array( 'Authenticate.Cookie' => array( 'fields' => array( 'username' => 'email', 'password' => 'password' ), 'userModel' => 'User', 'scope' => array('User.active' => 1) ), 'Authenticate.MultiColumn' => array( 'fields' => array( 'username' => 'email', 'password' => 'password' ), 'columns' => array('email', 'mobileNo'), 'userModel' => 'User', ) ); } public function login() { if ($this->Auth->login() || $this->Auth->loggedIn()) { $this->redirect('/users/dashboard'); }else{ $this->layout='logindefault'; $this->set('title_for_layout', 'Account Login'); /*$this->Auth->logout(); $cookie = $this->Cookie->read('Auth.User'); */ if ($this->request->is('post')) { if ($this->Auth->login() || $this->Auth->loggedIn()) { if ($this->Session->check('Auth.User')){ $this->_setCookie($this->Auth->user('idUser')); $this->redirect('/users/dashboard'); } }else { $this->Session->setFlash('Incorrect Email/Password Combination'); } }} } here is the code which i am trying to add .. $mobileNo='+123456789'; if (strpos($mobileNo,'+') !== false) { $mobileNo=str_replace("+", "",$mobileNo); } ?

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  • table design for storing large number of rows

    - by hyperboreean
    I am trying to store in a postgresql database some unique identifiers along with the site they have been seen on. I can't really decide which of the following 3 option to choose in order to be faster and easy maintainable. The table would have to provide the following information: the unique identifier which unfortunately it's text the sites on which that unique identifier has been seen The amount of data that would have to hold is rather large: there are around 22 millions unique identifiers that I know of. So I thought about the following designs of the table: id - integer identifier - text seen_on_site - an integer, foreign key to a sites table This approach would require around 22 mil multiplied by the number of sites. id - integer identifier - text seen_on_site_1 - boolean seen_on_site_2 - boolean ............ seen_on_site_n - boolean Hopefully the number of sites won't go past 10. This would require only the number of unique identifiers that I know of, that is around 20 millions, but it would make it hard to work with it from an ORM perspective. one table that would store only unique identifiers, like in: id - integer unique_identifier - text, one table that would store only sites, like in: id - integer site - text and one many to many relation, like: id - integer, unique_id - integer (fk to the table storing identifiers) site_id - integer (fk to sites table) another approach would be to have a table that stores unique identifiers for each site So, which one seems like a better approach to take on the long run?

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  • Jquery number of clicks record

    - by Maxime
    Hi, I am working on this page where I'm using a Jquery Mp3 Player (Jplayer) with its playlist. What I want to do is very simple in theory: I want to record the number of clicks for every playlist element. When someone enters the page, his number of clicks are at 0 for every element. The visitor can click a few times on element #1, then go to element #2 (which will be at 0), then come back to element #1 and the number of clicks must be saved. We don't need to save it for next visits. Jplayer has this function that loads each time a new playlist element is being loaded: function playListChange( index ) In which every element has its own ID dynamically updated: myPlayList[index].song_id Here's my code: function playListChange( index ) { var id = myPlayList[index].song_id; if(!o) { var o = {}; } if(!o[id]) { o[id] = 0; } alert(o[id]); … $("#mydiv").click { o[id] = o[id]+1; } … But o[id] is reset every time and the alert always show 0. Why? Thanks for any reply.

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  • [java] Returning the element number of the longest string in an array

    - by JohnRoberts
    Hoookay, so. I'm trying to get the longestS method to take the user-inputted array of strings, then return the element number of the longest string in that array. I got it to the point where I was able to return the number of chars in the longest string, but I don't believe that will work for what I need. My problem is that I keep getting incompatible type errors when trying to figure this out. I don't understand the whole data type thing with strings yet. It's confusing me how I go about return a number of the array yet the array is of strings. The main method is fine, I got stuck on the ???? part. { public static void main(String [] args) { Scanner inp = new Scanner( System.in ); String [] responseArr= new String[4]; for (int i=0; i<4; i++) { System.out.println("Enter string "+(i+1)); responseArr[i] = inp.nextLine(); } int highest=longestS(responseArr); } public static int longestS(String[] values) { int largest=0 for( int i = 1; i < values.length; i++ ) { if ( ????? ) } return largest; } }

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  • Find the number of congruent triangles?

    - by avd
    Say I have a square from (0,0) to (z,z). Given a triangle within this square which has integer coordinates for all its vertices. Find out the number of triangles within this square which are congruent to this triangle and have integer coordinates. My algorithm is as follows-- 1) Find out the minimum bounding rectangle(MBR) for the given triangle. 2) Find out the number of congruent triangles, y within that MBR, obtained after reflection, rotation of the given triangle. y can be either 2,4 or 8. 3) Now find out how many such MBR's can be drawn within the given big square, say x; (This is similar to finding number of squares on a chess board) 4) x*y is the required answer. Am I counting some triangles more than once or I am missing something by this algorithm? It is a problem on online judge? It gives me wrong answer. I have thought a lot about it, but I am not able to figure it out.

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  • VisualSVN How to roll back the revision number ?

    - by Ita
    The company I work in has suffered a major server failure. During this failure the SVN Repository was lost. But there is still hope ! We have an old backup of the repository which I've managed to successfully restore using VisualSVN. The problem I'm facing now is that I can't update / commit pre-failure checkedout folders. The reason for this problem is that for instance: a local folder has a revision number of 2361, while the repository itself holds a revision number of 2290, which is older. Is there a way to deal with this issue ? Can I some how change the revision numbers on either the local copy or the server copy? A few points: I'm using TortoiseSVN 1.6.6. I can checkout folders from the repo and the connection is active. I've picked one of my folders and used the Relocate option on it. This helped me see that there is something wrong with the revision number I've experimented a bit with the merge option but this lead me now where special. (I'm open for suggestions ) Thank you for your time, Ita

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  • Find out number of fraction digits in currency in iOS

    - by thejaz
    I use NSNumberFormatter to format currencies in a localized way, and it works fine. But I want to override this and give the user the option to override the number of digits after the decimal separator. How can I find out the number of digits the NSNumberFormatter will use for a certain currency? I have looked in the NSLocale object, but none of the keys tell me this. NSString * const NSLocaleIdentifier; NSString * const NSLocaleLanguageCode; NSString * const NSLocaleCountryCode; NSString * const NSLocaleScriptCode; NSString * const NSLocaleVariantCode; NSString * const NSLocaleExemplarCharacterSet; NSString * const NSLocaleCalendar; NSString * const NSLocaleCollationIdentifier; NSString * const NSLocaleUsesMetricSystem; NSString * const NSLocaleMeasurementSystem; NSString * const NSLocaleDecimalSeparator; NSString * const NSLocaleGroupingSeparator; NSString * const NSLocaleCurrencySymbol; NSString * const NSLocaleCurrencyCode; NSString * const NSLocaleCollatorIdentifier; NSString * const NSLocaleQuotationBeginDelimiterKey; NSString * const NSLocaleQuotationEndDelimiterKey; NSString * const NSLocaleAlternateQuotationBeginDelimiterKey; NSString * const NSLocaleAlternateQuotationEndDelimiterKey; How can I find out the correct number of decimals for a currency like the NSNumberFormatter seems to know?

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  • Apache POI rows number

    - by sys_debug
    I am using Apache POI java and want to get the total number of rows which are not empty. I successfully processed a whole row with all its columns. Now I am assuming that I get an excel sheet with multiple rows and not a single row...so how to go about that? I was thinking of getting total number of rows (int n) and then loop until i<=n but not sure. Suggestions are most welcome :) Note: Apache POI version is 3.8. I am not dealing with Xlsx format...only xls. Yes I tried this code but got 20 in return....which is not possible given I have only 5 rows FileInputStream fileInputStream = new FileInputStream("COD.xls"); HSSFWorkbook workbook = new HSSFWorkbook(fileInputStream); HSSFSheet worksheet = workbook.getSheet("COD"); HSSFRow row1 = worksheet.getRow(3); Iterator rows = worksheet.rowIterator(); int noOfRows = 0; while( rows.hasNext() ) { HSSFRow row = (HSSFRow) rows.next(); noOfRows++; } System.out.println("Number of Rows: " + noOfRows);

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  • Extracting a number from a 1-word string

    - by Kyle
    In this program I am trying to make, I have an expression (such as "I=23mm", or "H=4V") and I am trying to extract the 23 (or the 4) out of it, so that I can turn it into an integer. The problem I keep running into is that since the expression I am trying to take the numbers out of is 1 word, I cannot use split() or anything. One example I saw but wouldnt work was - I="I=2.7A" [int(s) for s in I.split() if s.isdigit()] This wouldnt work because it only takes the numbers are are delimited by spaces. If there was a number in the word int078vert, it wouldnt extract it. Also, mine doesnt have spaces to delimit. I tried one that looked like this, re.findall("\d+.\d+", "Amps= 1.4 I") but it didnt work either, because the number that is being passed is not always 2 digits. It could be something like 5, or something like 13.6. What code do I need to write so that if I pass a string, such as I="I=2.4A" or I="A=3V" So that I can extract only the number out of this string? (and do operations on it)? There are no spaces or other constant chars that I can delimit by.

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  • Retrieve POST data without knowing exact number of fields

    - by James
    Hi all! I'm creating an online poll from scratch which will be held in a database. I'm working on getting a system set up so someone can create a new poll. I will be having the user fill out a simple HTML form with the Questions and Answers (there may be several answers). The user will be able to add multiple questions and multiple answers for each question. As the total number of questions and answers will be decided by the user, I need to create some clever PHP to cater for this - however many there are. When dealing with a static number of questions, it's simple. But I'm having trouble thinking of a way to get all the POST data into individual PHP variables so I can process them. I was thinking of using a foreach loop, anyone got any ideas? Sorry for the long winded description! If anyone needs anything clarified, I'd be happy to do so. My problem is that I can't get my head around how to deal with the POST values when I don't know exactly which element of the array will contain what. If things were static with a set number of questions and answers, I'd know $_POST[0] was Question1, etc Thank you! =)

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  • Linq Return node level of hierarchical xml

    - by Ryan
    In a treeview you can retrieve the level of an item. I am trying to accomplish the same thing with the given input being an object. The XML data I will use for this example would be something like the following <?xml version="1.0" encoding="utf-8" ?> <Testing> <Numbers> <Number val="1"> <Number val="1.1"> <Number val="1.1.1"> <Number val="1.1.2" /> <Number val="1.1.3" /> <Number val="1.1.4" /> </Number> </Number> <Number val="1.2" /> <Number val="1.3" /> <Number val="1.4" /> </Number> <Number val="2" /> <Number val="3" /> <Number val="4" /> </Numbers> <Numbers> <Number val="5" /> <Number val="6" /> <Number val="7" /> <Number val="8" /> </Numbers> </Testing> This one is kicking my butt!

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  • Return node level of hierarchical xml

    - by Ryan
    In a treeview you can retrieve the level of an item. I am trying to accomplish the same thing with the given input being an object. The XML data I will use for this example would be something like the following <?xml version="1.0" encoding="utf-8" ?> <Testing> <Numbers> <Number val="1"> <Number val="1.1"> <Number val="1.1.1"> <Number val="1.1.2" /> <Number val="1.1.3" /> <Number val="1.1.4" /> </Number> </Number> <Number val="1.2" /> <Number val="1.3" /> <Number val="1.4" /> </Number> <Number val="2" /> <Number val="3" /> <Number val="4" /> </Numbers> <Numbers> <Number val="5" /> <Number val="6" /> <Number val="7" /> <Number val="8" /> </Numbers> </Testing> This one is kicking my butt!

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  • Finding an odd perfect number

    - by Coin Bird
    I wrote these two methods to determine if a number is perfect. My prof wants me to combine them to find out if there is an odd perfect number. I know there isn't one(that is known), but I need to actually write the code to prove that. The issue is with my main method. I tested the two test methods. I tried debugging and it gets stuck on the number 5, though I can't figure out why. Here is my code: public class Lab6 { public static void main (String[]args) { int testNum = 3; while (testNum != sum_of_divisors(testNum) && testNum%2 != 0) testNum++; } public static int sum_of_divisors(int numDiv) { int count = 1; int totalDivisors = 0; while (count < numDiv) if (numDiv%count == 0) { totalDivisors = totalDivisors + count; count++; } else count++; return totalDivisors; } public static boolean is_perfect(int numPerfect) { int count = 1; int totalPerfect = 0; while (totalPerfect < numPerfect) { totalPerfect = totalPerfect + count; count++; } if (numPerfect == totalPerfect) return true; else return false; } }

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  • how to record mic input and pipe the output to another program

    - by acrs
    Hi everyone Im trying to follow a tutorial on generating truly random bits How To Generate Truly Random Bits This is the command from the tutorial but it does not work rec -c 1 -d /dev/dsp -r 8000 -t wav -s w - | ./noise-filter >bits I know i can record my mic input using rec -c 1 no.wav this is the command i tried using rec -c 1 -r 8000 -t wav -s noise.wav | ./noise-filter >bits but i get root@xxc:~/cc# rec -c 1 -r 8000 -t wav -s noise.wav - | ./noise-filter >bits rec WARN formats: can't set sample rate 8000; using 48000 rec FAIL sox: Input files must have the same sample-rate I have complied noise-filter noise-filter I think the tutorial is using an older version of SOX and REC I'm using sox: SoX v14.3.2 on Ubuntu 12.04 server Can someone please help me ?

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  • Identifying the version of ATI Catalyst drivers

    - by Snark
    I have bought a new video card based on the ATI Radeon HD 5670 chipset. I couldn't make it work with the latest ATI Catalyst drivers found on their website, only the drivers found on the CD delivered with the card worked. How can I know the version of Catalyst that is installed on my PC (running Windows 7 64-bits)? The ATI Catalyst Control Center returns the following information: Driver Packaging Version 8.673-091110a-092263C Provider ATI Technologies Inc. 2D Driver Version 8.01.01.973 2D Driver File Path /REGISTRY/MACHINE/SYSTEM/ControlSet001/Control/CLASS/{4D36E968-E325-11CE-BFC1-08002BE10318}/0000 Direct3D Version 8.14.10.0708 OpenGL Version 6.14.10.9120 Catalyst™ Control Center Version 2009.1110.2225.40230 I do not recognize anything pointing to a "marketing version". The website says the current version of Catalyst is 10.2.

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  • Why is my /dev/random so slow when using dd?

    - by Mikey
    I am trying to semi-securely erase a bunch of hard drives. The following is working at 20-50Mb/s dd if=/dev/zero of=/dev/sda But dd if=/dev/random of=/dev/sda seems not to work. Also when I type dd if=/dev/random of=stdout It only gives me a few bytes regardless of what I pass it for bs= and count= Am I using /dev/random wrong? What other info should I look for to move this troubleshooting forward? Is there some other way to do this with a script or something like makeMyLifeEasy | dd if=stdin of=/dev/sda Or something like that...

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  • Generate random number histogram using java

    - by Chewart
    Histogram -------------------------------------------------------- 1 ****(4) 2 ******(6) 3 ***********(11) 4 *****************(17) 5 **************************(26) 6 *************************(25) 7 *******(7) 8 ***(3) 9 (0) 10 *(1) -------------------------------------------------------- basically above is what my prgram needs to do.. im missing something somewhere any help would be great :) import java.util.Random; public class Histogram { /*This is a program to generate random number histogram between 1 and 100 and generate a table */ public static void main(String args[]) { int [] randarray = new int [80]; Random random = new Random(); System.out.println("Histogram"); System.out.println("---------"); int i ; for ( i = 0; i<randarray.length;i++) { int temp = random.nextInt(100); //random numbers up to number value 100 randarray[i] = temp; } int [] histo = new int [10]; for ( i = 0; i<10; i++) { /* %03d\t, this generates the random numbers to three decimal places so the numbers are generated with a full number or number with 00's or one 0*/ if (randarray[i] <= 10) { histo[i] = histo[i] + 1; //System.out.println("*"); } else if ( randarray[i] <= 20){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 30){ histo[i] = histo[i] + 1; } else if ( randarray[i] <= 40){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 50){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=60){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=70){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=80){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=90){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=100){ histo[i] = histo[i] + 1; } switch (randarray[i]) { case 1: System.out.print("0-10 | "); break; case 2: System.out.print("11-20 | "); break; case 3: System.out.print("21-30 | "); break; case 4: System.out.print("31-40 | "); break; case 5: System.out.print("41-50 | "); break; case 6: System.out.print("51-60 | "); break; case 7: System.out.print("61-70 | "); break; case 8: System.out.print("71-80 | "); break; case 9: System.out.print("81-90 | "); break; case 10: System.out.print("91-100 | "); } for (int i = 0; i < 80; i++) { randomNumber = random.nextInt(100) index = (randomNumber - 1) / 2; histo[index]++; } } } }

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  • how to make a javascript number keypad popup

    - by user2434653
    i have a website with 3 pages. each page has a form with two input fields. i am trying to make a popup number-keypad that will populate what ever input field called it. below is that base code i keep coming back to. <html> <head><title>test</title></head> <body> <script> function num(id) { return document.getElementById(id); } </script> <form action="/unitPage" method="POST" style=" text-align:center;"> Prefix: <input id="num" name"prefix" type="text" onfocus="num('keypad').style.display='inline-block';"/> Number: <input id="num" name"number" type="text" pattern="[0-9]{6}" onfocus="num('keypad').style.display='inline-block';"/> </form> <div id="keypad" style="display:none; background:#AAA; vertical-align:top;"> <input type="button" value="7" onclick="num('num').value+=7;"/> <input type="button" value="8" onclick="num('num').value+=8;"/> <input type="button" value="9" onclick="num('num').value+=9;"/><br/> <input type="button" value="4" onclick="num('num').value+=4;"/> <input type="button" value="5" onclick="num('num').value+=5;"/> <input type="button" value="6" onclick="num('num').value+=6;"/><br/> <input type="button" value="1" onclick="num('num').value+=1;"/> <input type="button" value="2" onclick="num('num').value+=2;"/> <input type="button" value="3" onclick="num('num').value+=3;"/><br/> <input type="button" value="X" onclick="num('keypad').style.display='none'"/> <input type="button" value="0" onclick="num('num').value+=0;"/> <input type="button" value="&larr;" onclick="num('num').value=num('num').value.substr(0,num('num').value.length-1);"/> </div> </body> </html> is there a way of making one number key pad that i call from any page or do i need to make the above for each input? thanks

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  • Reversing a number in c++

    - by Marcel Bujnowski
    I created a program to show the sum and show the reversed number a person has typed. The sum function works but the revers function is not. Can anyone give me any tips on how to fix it. I created a program to show the sum and show the reversed number a person has typed. The sum function works but the revers function is not. Can anyone give me any tips on how to fix it. #include<iostream> #include<iomanip> using namespace std; void printSum(int n, bool reverse); int sm(int n); int reverseInt(int n); void printAddTable(int n); int main() { int reverse; int sum=0; int n; cout<<"Enter N value:"<<endl; cin>>n; if(n>0) { reverse = true; printSum( n, reverse); // calls the printSum Method } else { //cout<<"enter positive Number only:"<<endl; } sum = sm(n); //err // calls the sum Method reverse = reverseInt(n); // calls the reverseInt Method cout<<"The reverse value is:"<<reverse; printAddTable(n); // calls the printAddTable Method //getch() } //end of main() void printSum(int n, bool reverse) { int sum=0; // print sum of reverse numbers for(int i=n; i>=1; i--) { sum=sum+i; cout<<i<< " "<<"+"<<" "; } cout<<sum; } int sm(int n) {int sum =0; for(int i=1; i<=n; i++) { sum = sum + i ; cout << endl; cout<<i<<" "<<"+"<<" "<<endl; // print n positive integers cout << endl; } cout<< "Are " <<n<< " positive integers"<<endl; cout<< "Sum is "<<sum <<endl; return sum; } int reverseInt(int n) { int reminder=0; int sum =0; while(n<=0) { reminder = n/10; sum = (sum * 10) + reminder; // it returns the reverse number n = n % 10; } return sum; } void printAddTable(int n) { for(int i=1; i<=n; i++) { cout<<i<<endl; for(int j=1; j<=n; j++) // print n X n add table { cout<<i+j<<endl; } } } {

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  • Tab Sweep - Java EE wins, Prime Faces JSF, NetBeans, Jelastic for GlassFish, BeanValidation, Ewok and more...

    - by alexismp
    Recent Tips and News on Java, Java EE 6, GlassFish & more : • PrimeFaces 3.2 Final Released (primefaces.org) • Java EE wins over Spring (Bill Burke) • Customizing Components in JSF 2.0 (Mr. Bool) • Key to the Java EE 6 Platform: NetBeans IDE 7.1.x (OTN) • How to use GlassFish’s Connection Pool in Jelastic (jelastic.com) • Bean Validation 1.1 early draft 1 is out - time for feedback (Emmanuel) • Code artifacts published for Bean Validation 1.1 early draft 1 (Emmanuel) • Aprendendo Java EE 6 com GlassFish 3 e NetBeans 7.1 (Marcello) • JavaEE6 and the Ewoks (Murat)

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  • How to know the number of pins on my laptop's ram?

    - by Rajat Saxena
    I am thinking about upgrading my laptop's ram.How can I get to know the number of pins on my ram without opening my laptop? I ran this command sudo dmidecode --type memory and got following info: Handle 0x0019, DMI type 17, 27 bytes Memory Device Array Handle: 0x0017 Error Information Handle: 0x001A Total Width: 64 bits Data Width: 64 bits Size: 1024 MB Form Factor: SODIMM Set: None Locator: DIMM0 Bank Locator: BANK 0 Type: DDR2 Type Detail: Synchronous Speed: 667 MHz Manufacturer: AD00000000000000 Serial Number: 04008104 Asset Tag: Unknown Part Number: 040404040404040404040404040404040404 Can anyone help?

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  • SEO: Firefox addon/plugin to see Google results with a position number?

    - by Marco Demaio
    Do you know a Firefox addon that adds postion number to Google/Yahoo results. When I do SEO report for www.some-site.com by keyphrase "some-keyphrase" I usually show results in blocks of 100 results per page. Then uisng browser find box I search for "some-site.com", if found in page I see its position, but I have to count by hand the number of results before (or after) it to know the exact position number. It would be handful a simple addon that adds a number positioning before each result like: 1. Result blah blah Snippet... url 2. Result blah blah Snippet... url etc.

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