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• How to configure ldap on ubuntu 10.04 server

  - by user3215

  I am following the link to configure ldap on ubuntu 10.04 server but could not. when I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: john[email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Anybody could help me?

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• Convert a Julian Date to Regular Calendar Date

  - by Mark Acosta

  How do I convert a 7-digit julian date into a format like MM/dd/yyy?

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• From escaped html -> to regular html? - Python

  - by RadiantHex

  Hi folks, I used BeautifulSoup to handle XML files that I have collected through a REST API. The responses contain HTML code, but BeautifulSoup escapes all the HTML tags so it can be displayed nicely. Unfortunately I need the HTML code. How would I go on about transforming the escaped HTML into proper markup? Help would be very much appreciated!

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• Select From MySQL PHP

  - by Liju

  Sir, I have one Database Table named "table1" with 8 column, that is Date, Time, Name, t1, t2, t3, t4, t5. I want to update the same table like the following... my existing table:- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 10/11/2010 09:00 bob 10/11/2010 10:00 bob 10/11/2010 13:00 bob 10/11/2010 10:00 john 10/11/2010 12:00 john 10/11/2010 14:00 john 12/11/2010 08:00 bob 12/11/2010 09:00 bob 12/11/2010 10:00 bob 12/11/2010 13:00 bob 12/11/2010 10:00 john 12/11/2010 12:00 john 12/11/2010 14:00 john 12/11/2010 16:00 john I want to update this as follows :- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 08:00 09:00 10:00 13:00 10/11/2010 10:00 john 10:00 12:00 14:00 12/11/2010 08:00 bob 08:00 09:00 10:00 13:00 12/11/2010 10:00 john 10:00 12:00 14:00 16:00 is it posible to update like this please help me.. Liju

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• Limit user input to allowable comma delimited words with regular expression using javascript

  - by Marc

  I want to force the user to enter any combination of the following words. the words need to be comma delimited and no comma at the beginning or end of the string the user should only be able to enter one of each word. Examples admin basic,ectech admin,ectech,advanced basic,advanced,admin,ectech my attempt ^((basic|advanced)|admin|ectech)((,basic|,advanced)|,admin|,ectech){0,2}$ Thanks Marc

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• XSLT: Regular Expression function does not work?

  - by Fedor Steeman

  Ok, this one has been driving me up the wall... I have a xslt function that is supposed to split out the Zip-code part from a Zip+City string depending on the country. I cannot get it to work! This is what I got so far: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exslt="http://exslt.org/functions" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:function name="exslt:GetZip" as="xs:string"> <xsl:param name="zipandcity" as="xs:string"/> <xsl:param name="countrycode" as="xs:string"/> <xsl:choose> <xsl:when test="$countrycode='DK'"> <xsl:analyze-string select="$zipandcity" regex="(\d{4}) ([A-Za-zÆØÅæøå]{3,24})"> <xsl:matching-substring> <xsl:value-of select="regex-group(1)"/> </xsl:matching-substring> <xsl:non-matching-substring> <xsl:text>fail</xsl:text> </xsl:non-matching-substring> </xsl:analyze-string> </xsl:when> <xsl:otherwise> <xsl:text>error</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:function> I am running it on a source XML where the following values are passed to the function: zipandcity: "DK-2640 København SV" countrycode: "DK" ...will output 'fail'! I think there is something I am misunderstanding here...

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• Unable to convert from Julian INT date to regular TSQL Datetime

  - by Bluehiro

  Help me Stackoverflow, I'm close to going all "HULK SMASH" on my keyboard over this issue. I have researched carefully but I'm obviously not getting something right. I am working with a Julian dates referenced from a proprietary tool (Platinum SQL?), though I'm working in SQL 2005. I can convert their "special" version of Julian into datetime when I run a select statement. Unfortunately it will not insert into a datetime column, I get the following error when I try: The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value. So I can't setup datetime criteria for running a report off of the Stored Procedure. Original Value: 733416 Equivalent Calendar Value: 01-09-2009 Below is my code... I'm so close but I can't quite see what's wrong, I need my convert statement to actually convert the Julian value (733416) into a compatible TSQL DATETIME value. SELECT org_id, CASE WHEN date_applied = 0 THEN '00-00-00' ELSE convert(char(50),dateadd(day,date_applied-729960,convert(datetime, '07-25-99')),101) END AS date_applied, CASE WHEN date_posted = 0 THEN '00-00-00' ELSE convert(char(50),dateadd(day,date_posted-729960,convert(datetime, '07-25-99')),101) END AS date_posted from general_vw

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• Extract parameter value from url using regular expressions

  - by Oscar Reyes

  This should be very simple ( when you know the answer ). From this question I want to give it a try to the posted solution. And my question is: How to get the parameter value of a given url using javascript regexp? I have: http://www.youtube.com/watch?v=Ahg6qcgoay4 I need: Ahg6qcgoay4 I tried: http://www.youtube.com/watch\\?v=(w{11}) But: I suck...

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• Using regular expressions to remove relative path slashes

  - by Adam Carlile

  Hey Guys I am trying to remove all the relative image path slashes from a chunk of HTML that contains several other elements. For example <img src="../../../../images/upload/1/test.jpg /> would need to become <img src="http://s3.amazonaws.com/website/images/upload/1/test.jpg" /> I was thinking of writing this as a rails helper, and just passing the entire block into the method, and make using Nokogiri or Hpricot to parse the HTML instead, but I don't really know. Any help would be great Cheers Adam

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• Ninject : ninject.web - How to apply on a regular ASP.Net Web (!MVC)

  - by No Body

  What I am looking is something similar to the below (http://github.com/ninject/ninject.web.mvc): README.markdown This extension allows integration between the Ninject core and ASP.NET MVC projects. To use it, just make your HttpApplication (typically in Global.asax.cs) extend NinjectHttpApplication: public class YourWebApplication : NinjectHttpApplication { public override void OnApplicationStarted() { // This is only needed in MVC1 RegisterAllControllersIn("Some.Assembly.Name"); } public override IKernel CreateKernel() { return new StandardKernel(new SomeModule(), new SomeOtherModule(), ...); // OR, to automatically load modules: var kernel = new StandardKernel(); kernel.AutoLoadModules("~/bin"); return kernel; } } Once you do this, your controllers will be activated via Ninject, meaning you can expose dependencies on their constructors (or properties, or methods) to request injections.

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• java Regular expression matching html

  - by user121196

  I want to match and capture the enclosing content of the <pre></pre> tag tried the following, not working, what's wrong? String p="<pre>.*</pre>"; Matcher m=Pattern.compile(p,Pattern.MULTILINE|Pattern.CASE_INSENSITIVE).matcher(input); if(m.find()){ String g=m.group(0); System.out.println("g is "+g); }

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• Rewriting An URL With Regular Expression Substitution in Routes

  - by Sean M

  In my Pylons app, some content is located at URLs that look like http://mysite/data/31415. Users can go to that URL directly, or search for "31415" via the search page. My constraints, however, mean that http://mysite/data/000031415 should go to the same page as the above, as should searches for "0000000000031415." Can I strip leading zeroes from that string in Routes itself, or do I need to do that substitution in the controller file? If it's possible to do it in routing.py, I'd rather do it there - but I can't quite figure it out from the documentation that I'm reading.

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• Verifying regular expression for malware removal

  - by Legend

  Unfortunately, one of my web servers was compromised recently. I have two questions. Is there a way I can scan the downloaded directory for backdoors? Is there anything I can do to ensure that at least known vulnerabilities do not exist anymore? Secondly, the malware put up the following in all index.* files on my webserver: <script>/*GNU GPL*/ try{window.onload = function(){var Hva23p3hnyirlpv7 = document.createElement('script');Hva23p3hnyirlpv7.setAttribute('type', 'text/javascript');Hva23p3hnyirlpv7.setAttribute('id', 'myscript1');Hva23p3hnyirlpv7.setAttribute('src',.... CODE DELETED FOR SAFETY.... );}} catch(e) {}</script> Obviously, this snippet seems to download some rogue file onto the user's machine. I downloaded an entire backup of the web server and am currently trying to remove this snippet from all file. For this I am doing: find ./ -name "index.*" -exec sed -i 's/<script>\/\*GNU GPL\*.*Hva23p3hnyirlpv7.*<\/script>//g' {} \; Just wanted to verify if this does the trick. I verified it with a few files but I want to be sure that this doesn't delete some valid code. Anyone suggests any other modifications?

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• SED - Regular Expression over multiple lines

  - by herrherr

  Hi there, I'm stuck with this for several hours now and cycled through a wealth of different tools to get the job done. Without success. It would be fantastic, if someone could help me out with this. Here is the problem: I have a very large CSV file (400mb+) that is not formatted correctly. Right now it looks something like this: Alan Smithee ist ein Anagramm von „The [...] „Alan Smythee“, und „Adam Smithee“." ,Alan Smithee Die Aussagenlogik ist der Bereich der Logik, der sich mit [...] ihrer Teilaussagen bestimmen. ,Aussagenlogik As you can probably see the words ",Alan Smithee" and ",Aussagenlogik" should actually be on the same line as the foregoing sentence. Then it would look something like this: Alan Smithee ist ein Anagramm von „The Smitheeeee [...] „Alan Smythee“, und „Adam Smithee“.,Alan Smithee Die Aussagenlogik ist der Bereich der Logik, der sich mit [...] ihrer Teilaussagen bestimmen.,Aussagenlogik Please note that the end of the sentence can contain quotes or not. In the end they should be replaced too. Here is what I came up with so far: sed -n '1h;1!H;${;g;s/\."?.*,//g;p;}' out.csv > out1.csv This should actually get the job done of matching the expression over multiple lines. Unfortunately it doesn't :) The expression is looking for the dot at the end of the sentence and the optional quotes plus a newline character that I'm trying to match with .*. Help much appreciated. And it doesn't really matter what tool gets the job done (awk, perl, sed, tr, etc.). Thanks, Chris

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• Regular expression that contains in it...

  - by Fabiano PS

  I need my regexp to match, all the highlighted words, in order, following: Fri/Feb/10 - *Nesta* manh\303\203\302\243,* @*anestesya *entrou* \303\240s 08:18AM Fri/Feb/10 - *Nesta* tarde,* @*pernas *saiu* \303\240s 08:18AM I was trying something like: /[?=Nesta.?=@.?=(entrou|saiu)]/ So I don't care what is in between as long as it has: ' Nesta ' AND ' @' AND ' entrou ' OR ' saiu '

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• Regular Expression Fill-Down

  - by richardtallent

  I have a plain text file something like this: Ford\tTaurus F-150 F-250 Toyota\tCamry Corsica In other words, a two-level hierarchy where the first child is on the same line as the parent, but subsequent children on lines following, distinguished from being a parent by a two-space prefix (\t above represents a literal tab in the text). I need to convert to this using RegEx: Ford\tTaurus Ford\tF-150 Ford\tF-250 Toyota\tCamry Toyota\tCorsica So, I need to capture the parent (text between \r\n and \t not starting with \s\s), and apply that in the middle of any \r\n\s\s found until the next parent. I have a feeling this can be done with some sort of nested groups, but I think I need more caffeine or something, can't seem to work out the pattern. (Using .NET with IgnoreWhitespace off and Multiline off)

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• Java Regular Expressions

  - by david robers

  Hi All, Im struggling to understand the regex documentation. How would I find the strings that contain exactly one C in the following text: ABCCAMNL YOOBABCCA XNABCCA ZDXUABCCA TAQABCC ISABCCA REABCCA CABCAMONPT Edit: private void matchIt(String regex, ArrayList<String> d) { Pattern p = Pattern.compile("[\\w^C]"); Matcher m = p.matcher(regex); for (int i = 0; i < d.size(); i++) { p.matcher(d.get(i)); if(m.find()){ out.println(d.get(i)); } } } i have the above function and it only outputs: ABCCAMNL YOOBABCCA Why is that?

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• Greek characters, Regular Expressions, and C#

  - by craigmoliver

  I'm building a CMS for a scientific journal and that uses a lot of Greek characters. I need to validate a field to include a specific character set and Greek characters. Here's what I have now: [^a-zA-Z0-9-()/\s] How do I get this to include Greek characters in addition to alphanumeric, '(', ')', '-', and '_'? I'm using C#, by the way.

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• VBScript Regular Expressions to check IP address validity with some adtional characters

  - by yael

  How to create VB Irregular expression syntax to check the VPparam (IP address validity) When the last octatat of the IP address is a range between ip's (x-y) and between each IP we can put the "," separator in order to add another IP example of VBparam VBparam=172.17.202.1-20 VBparam=172.17.202.1-10,192.9.200.1-100 VBparam=172.17.202.1-10,192.9.200.1-100,180.1.1.1-20 THX yael

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• VBScript Regular Expressions to check IP address validity with some adtional characters

  - by yael

  How to create VB script Irregular expression syntax to check the VPparam (IP address validity) When the last octatat of the IP address is a range between ip's (x-y) and between each IP we can put the "," separator in order to add another IP example of VBparam VBparam=172.17.202.1-20 VBparam=172.17.202.1-10,192.9.200.1-100 VBparam=172.17.202.1-10,192.9.200.1-100,180.1.1.1-20 THX yael

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• Convert regular date and time to Julian date and vice versa

  - by zbz.lvlv

  I am currently working on a program that will calculate sunrise and sunset times. How do I convert yyyymmddhhmmss to Julian date? I need the date to be very precise. It'll great if there can be an example for such conversions. Calendar cNow = Calendar.getInstance(); Calendar cJan1 = Calendar.getInstance(); double julianJan1_2014_12_00_00 = 2456659; cJan1.set(2014, 0, 0, 12, 0); Date dJan1 = cJan1.getTime(); Date dNow = cNow.getTime(); long lJan1 = dJan1.getTime(); long lNow = dNow.getTime(); double diffDay = (lNow - lJan1) / 1000 / 60 / 60 / 24; double julianDate = diffDay + julianJan1_2014_12_00_00; The code I currently have.

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• Regular expressions .net

  - by Tony

  I have the following function that I am using to remove the characters \04 and nulls from my xmlString but I can't find what do I need to change to avoid removing the \ from my ending tags. This is what I get when I run this function <ARR>20080625<ARR><DEP>20110606<DEP><PCIID>626783<PCIID><NOPAX>1<NOPAX><TG><TG><HASPREV>FALSE<HASPREV><HASSUCC>FALSE<HASSUCC> Can anybody help me find out what do I need to change in my expression to keep the ending tag as </tag> Private Function CleanInput(ByVal inputXML As String) As String ' Note - This will perform better if you compile the Regex and use a reference to it. ' That assumes it will still be memory-resident the next time it is invoked. ' Replace invalid characters with empty strings. Return Regex.Replace(inputXML, "[^><\w\.@-]", "") End Function

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• How to match filetype with regular expression?

  - by Sanarothe

  Hi. I'm stuck trying to get a regex to match a filetype in a sorting script. Dir.foreach(savedirs[0]) do |x| puts "Matching " + x + " against filetypes." case x when x.match(/^.*\.exe$/i) then puts x when x.match(/\.jpe?g$/) then FileUtils.move(x, sortpath[".exe"], :verbose => true) when x =~ /\.jpg$/ then FileUtils.move(x, sortpath[".jpg"]) end end I can't get any of these to match on in windows. All I need is to confirm that a given filename matches against compatible filetypes.

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• Javascript Regular Expressions - Replace non-numeric characters

  - by user271619

  This works: var.replace(/[^0-9]+/g, ''); That simple snippet will replace anything that is not a number with nothing. But decimals are real too. So, I'm trying to figure out how to include a period. I'm sure it's really simple, but my tests aren't working.

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• php regular express

  - by kelly

  I have one string format like {blah\blah{\blah\blah...{\bl....}}}{blah...}blah... How can I get the content to the array in the first level, like array( "{blah\blah{\blah\blah...{\bl....}}}", "{blah...}"). Thanks in advance.

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