Search Results

Search found 1162 results on 47 pages for 'shane grant'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 31/47 | < Previous Page | 27 28 29 30 31 32 33 34 35 36 37 38  | Next Page >

  • Necessary rights to be able to add a column with ALTER TABLE ADD column_name

    - by Sorin Comanescu
    Hi, Could somebody point out the necessary rights to do something like ALTER TABLE myTable ADD myColumn int NOT NULL CONSTRAINT [Constraint_name] DEFAULT ((0)) ? I assumed grant alter on myTable to [user] was enough but I'm getting the error message The UPDATE permission was denied on the object 'myTable', database 'x', schema 'dbo'. Could UPDATE rights be needed because of the DEFAULT constraint? Thanks.

    Read the article

  • Service MSFTESQL not found.

    - by hrishi
    While installating MS-CRM:I got sql server errors:- 1Service MSFTESQL not found. The specified service does not exists as an installed service -----but i can see the service is running automatically and help file says "verify that you have local administrator permissions for the computer on which sql server is running. And if necessary grant the needed permissions." how to achive this.

    Read the article

  • Problems writing a query to join two tables

    - by Psyche
    Hello, I'm working on a script which purpose is to grant site users access to different sections of the site menu. For this I have created two tables, "menu" and "rights": menu - id - section_name rights - id - menu_id (references column id from menu table) - user_id (references column id from users table) How can a query be written in order to get all menu sections and mark the ones where a given user has access. I'm using PHP and Postgres. Thank you.

    Read the article

  • File paths on Silverlight applications

    - by jose
    I have two silverlight applications. One produces XML files (models) that are used for the other to read. The XML files are uploaded to a specific (abosulte for now) folder. So, I need a solution to grant access by these two applications, a Models folder. Right now I'm using absolute paths and developing in ASP.NET Dev server. What would be the best way to accomplish this, thinking on IIS approach? Regards,

    Read the article

  • Rails multi level model security

    - by rballz
    I have the need to do the following in Rails to mirror a desktop application: a User and an Office 'owns' a record, if you don't own the record on a user or office level you're kicked into the public realm. user gets read,write,delete to the model record office gets read/write/delete to the model record other or public gets read/write/delete to the model record e.g. UserA owns a model record with read/write/delete OfficeA owns a model with read/write other/public gets read I was wondering if a plugin/gem existed to grant this functionality?

    Read the article

  • How to hide folder in SSRS Report Builder?

    - by tnafoo
    When I click File - Open on Report Builder, I can see a list of folders under Report Server Home root folder. But I don't want end-user to see any of the folders under root unless I grant them access. I tried hiding and removing permission on the folders but they are still visible in the root folder.

    Read the article

  • SQl server 2008 permission and encryption

    - by paranjai
    i have made columns in some of the tables encrypted in sql server 2008. Now as i am a db owner i have the access to encode and decode the data using the symmetric key and certificate. But some other users have only currently datareader and datawriter rights ,and when they execute any SP referring the logic which uses the key and certificate "User does has not right on the certificate to execute". What rights / exact permission should i grant them just to solve this problem

    Read the article

  • How to get only one row for each distinct value in the column ?

    - by Chavdar
    Hi Everybody, I have a question about Access.If for example I have a table with the following data : NAME | ADDRESS John Taylor | 33 Dundas Ave. John Taylor | 55 Shane Ave. John Taylor | 786 Edward St. Ted Charles | 785 Bloor St. Ted Charles | 90 New York Ave. I want to get one record for each person no matter of the address.For example : NAME | ADDRESS John Taylor | 33 Dundas Ave. Ted Charles | 90 New York Ave. Can this be done with queries only ? I tried using DISTINCT, but when I am selecting both columns, the combination is allways unique so I get all the rows. Thank you !

    Read the article

  • Eclipse CDT on Snow Leopard cannot find binaries

    - by ejel
    After upgraded to Snow Leopard, I can no longer run Eclipse CDT project on my computer. While the build process completes without any error, Eclipse does not recognize the binary file it created. When try to point to the binary file in Run Configuration.. dialog, it cannot find any binary in the project. Though executing the file from Terminal works fine. According to a post at on Eclipse forum, this might be a problem that Mach-O parser does not recognize 64-bit binaries. Does anyone know what are the solutions or workarounds to the problem so that I can run/debug my C++ projects on Snow Leopard. UPDATED The solution suggested by Shane, though allowing the binary created to be recognized, does introduce another problem. Since system libraries in Snow Leopard are all 64 bits, it is no longer possible to link the code created with -arch i386 with these libraries, and hence not a feasible solution yet.

    Read the article

  • Performance problem Loading Dataset inside a virtual.

    - by ShaneH
    Host Configuration: HP EliteBook 8530w 4G Ram Win7 Ultimate 64Bit RC SQL Server 2005 64bit Developer Edition Virtual: Windows Virtual PC 1G Ram allocated Integration Services installed Windows XP 64bit Up to date service packs and .Net framework through 3.5 SP1 Sharing the Gigabit network adapter of the Host I have a simple .Net console application which loads a dataset of approximately 37K rows. Running the application on the host executes in approximately 4 seconds. Running inside the virtual takes 729 seconds. The size of the application grows to about 65Mb when the dataset is finished loading, no calculated columns or event handlers are attached. [edit] I changed the virtual to use a loopback adapter to communicate with the host and performance is now on par with running on hardware. Any ideas as to why it would going over the network adapter be almost 200x longer? TraceRt shows that the connection is only one hop. Thanks, Shane Holder

    Read the article

  • xml to xsd to c# class - C# 3.0, .net 3.5

    - by uno
    Following this articlelink text one of the comments from 'zanoni' said he did it this way Using .NET 3.5: [XmlRoot] public class EmailConfiguration { [XmlElement] public string DataBoxID { get; set; } [XmlElement] public DefaultSendToAddressCollectionClass DefaultSendToAddressCollection { get; set; } } public class DefaultSendToAddressCollectionClass { [XmlElement] public string[] EmailAddress { get; set; } } How would I get my class to be as what he described? I ran the xsd tool and it is in the fashion as what shane posted in the above link [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] [System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] public partial class EmailConfiguration : object, System.ComponentModel.INotifyPropertyChanged { private string dataBoxIDField; private EmailConfigurationDefaultSendToAddressCollection[] defaultSendToAddressCollectionField; /// <remarks/> [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] public string DataBoxID { get { return this.dataBoxIDField; } set { this.dataBoxIDField = value; this.RaisePropertyChanged("DataBoxID"); } }

    Read the article

  • Multiple data centers and HTTP traffic: DNS Round Robin is the ONLY way to assure instant fail-over?

    - by vmiazzo
    Hi, Multiple A records pointing to the same domain seem to be used almost exclusively to implement DNS Round Robin as a cheap load balancing technique. The usual warning against DNS RR is that it is not good for high availability. When 1 IP goes down clients will continue to use it for minutes. A load balancer is often suggested as a better choice. Both claims are not completely true: When the traffic is HTTP then, most of the HTML browsers are able to automatically try the next A record if the previous is down, without a new DNS look-up. Read here chapter 3.1 and here. When multiple data centers are involved then, DNS RR is the only option to distribute traffic across them. So, is it true that, with multiple data centers and HTTP traffic, the use of DNS RR is the ONLY way to assure instant fail-over when one data center goes down? Thanks, Valentino Edit: Off course each data center has a local Load Balancer with hot spare. It's OK to sacrifice session affinity for an instant fail-over. AFAIK the only way for a DNS to suggest a data center instead of another is to reply with just the IP (or IPs) associated to that data center. If the data center becomes unreachable then all those IP are also unreachables. This means that, even if smart HTML browsers are able to instantly try another A record , all the attempts will fail until the local cache entry expires and a new DNS lookup is done, fetching the new working IPs (I assume DNS automatically suggests to a new data center when one fail). So, "smart DNS" cannot assure instant fail-over. Conversely a DNS round-robin permits it. When one data center fail, the smart HTML browsers (most of them) instantly try the other cached A records jumping to another (working) data center. So, DNS round-robin doesn't assure session affinity or the lowest RTT but seems to be the only way to assure instant fail-over when the clients are "smart" HTML browsers. Edit 2: Some people suggest TCP Anycast as a definitive solution. In this paper (chapter 6) is explained that Anycast fail-over is related to BGP convergence. For this reason Anycast can employ from 15 minutes to 20 seconds to complete. 20 seconds are possible on networks where the topology was optimized for this. Probably just CDN operators can grant such fast fail-overs. Edit 3:* I did some DNS look-ups and traceroutes (maybe some expert can double check) and: The only CDN using TCP Anycast seems to be CacheFly, other operators like CDN networks and BitGravity use CacheFly. Seems that their edges cannot be used as reverse proxies. Therefore, they cannot be used to grant instant failover. Akamai and LimeLight seems to use geo-aware DNS. But! They return multiple A records. From traceroutes seems that the returned IPs are on the same data center. So, I'm puzzled on how they can offer a 100% SLA when one data center goes down.

    Read the article

  • Why can't I reinstall MySQL?

    - by Johannes Nielsen
    I've been looking all around the Internet for an answer but didn't find anything. I hope you can help me now. I have a server with MySQL. From one day to another, MySQL didn't let me enter with my root password anymore (accsess denied for user 'root'@'localhost' using password: 'YES'). So I tried two ways to reset the password: No.1: I typed: shell> /etc/init.d/mysqld stop To stop MySQL. Then I restarted it skipping the grant-tables: shell> mysqld_safe --skip-grant-tables So I was able to log in as root and change the password using: mysql> UPDATE mysql.user SET Password = PASSWORD('MyNewPassword') WHERE User = 'root'; FLUSH PRIVILEGES; I restarted MySQL and tried to log in as root with my new password - didn't work. So I tried the solution that's described here: http://dev.mysql.com/doc/refman/5.0/en/resetting-permissions.html (I don't want to post it here because this post is already pretty long). Didn't work either. Actually it made it worse, because since that day, every time I try to start MySQL, it doesn't even ask me for my password, but I get: shell> ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (111) Well, I've looked up what it means and found that my mysqld.sock is missing. I tried to create it using touch but MySQL can't start with that socket. Now I'm trying to reinstall MySQL but everytime I type in shell> apt-get --purge remove mysql-server mysql-common mysql-client In that or any other order or every one of those three alone, I get: shell> Reading package lists... Done shell> Building dependency tree shell> Reading state information... Done shell> Package mysql-client is not installed, so not removed shell> Package mysql-server is not installed, so not removed shell> You might want to run 'apt-get -f install' to correct these: shell> The following packages have unmet dependencies: shell> libmysqlclient18 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> libmysqlclient18:i386 : Depends: mysql-common:i386 (>= 5.5.28-0ubuntu0.12.04.2) shell> mysql-client-5.5 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> mysql-server-5.5 : PreDepends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> psa-firewall : Depends: plesk-core (>= 11.0.9) but it is not installable shell> Depends: mysql-server but it is not going to be installed shell> psa-spamassassin : Depends: plesk-core (>= 11.0.9) but it is not installable shell> psa-vpn : Depends: plesk-core (>= 11.0.9) but it is not installable shell> Depends: plesk-base (>= 11.0.9) but it is not installable shell> Depends: mysql-server but it is not going to be installed shell> E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). So I said to my self "let's just remove those files with depenencies, too" (that psa-stuff since plesk is virtual and can't be uninstalled)... Guess what happened: shell> Reading package lists... Done shell> Building dependency tree shell> Reading state information... Done shell> Package mysql-client is not installed, so not removed shell> Package mysql-server is not installed, so not removed shell> You might want to run 'apt-get -f install' to correct these: shell> The following packages have unmet dependencies: shell> libmysqlclient18 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> libmysqlclient18:i386 : Depends: mysql-common:i386 (>= 5.5.28-0ubuntu0.12.04.2) shell> mysql-client-5.5 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> mysql-server-5.5 : PreDepends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). Of course I tried apt-get -f install, too many times even. What am I doing wrong? No matter, which other packages I include into apt-get --purge remove, I always get new dependencies. Do I have to delete every MySQL-related directory and file manually? Hope there's someone out there who can help me! Cheers! EDIT: After trying apt-get purge mysql-server mysql-common mysql-client libmysqlclient18 libmysqlclient18:i386 mysql-client-5.5 mysql-server-5.5 psa-firewall psa-spamassassin psa-vpn Reading package lists... Done Building dependency tree Reading state information... Done Package mysql-client is not installed, so not removed Package mysql-server is not installed, so not removed You might want to run 'apt-get -f install' to correct these: The following packages have unmet dependencies: libdbd-mysql-perl : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed libmyodbc : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed libqt4-sql-mysql:i386 : Depends: libmysqlclient18:i386 (>= 5.5.13-1) but it is not going to be installed php5-mysql : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed ruby-mysql : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). So I tried to remove all these and got: Building dependency tree Reading state information... Done Package mysql-client is not installed, so not removed Package mysql-server is not installed, so not removed You might want to run 'apt-get -f install' to correct these:qlclient18:i386 mysql The following packages have unmet dependencies: libmysql-ruby1.8 : Depends: ruby-mysql but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). And actually I think removing that file, too solved my problem :-S Next time I'll try everything before asking :D Thank you Eric for keeping me couraged to just go on removing :D

    Read the article

  • SQL Server Split() Function

    - by HighAltitudeCoder
    Title goes here   Ever wanted a dbo.Split() function, but not had the time to debug it completely?  Let me guess - you are probably working on a stored procedure with 50 or more parameters; two or three of them are parameters of differing types, while the other 47 or so all of the same type (id1, id2, id3, id4, id5...).  Worse, you've found several other similar stored procedures with the ONLY DIFFERENCE being the number of like parameters taped to the end of the parameter list. If this is the situation you find yourself in now, you may be wondering, "why am I working with three different copies of what is basically the same stored procedure, and why am I having to maintain changes in three different places?  Can't I have one stored procedure that accomplishes the job of all three? My answer to you: YES!  Here is the Split() function I've created.    /******************************************************************************                                       Split.sql   ******************************************************************************/ /******************************************************************************   Split a delimited string into sub-components and return them as a table.   Parameter 1: Input string which is to be split into parts. Parameter 2: Delimiter which determines the split points in input string. Works with space or spaces as delimiter. Split() is apostrophe-safe.   SYNTAX: SELECT * FROM Split('Dvorak,Debussy,Chopin,Holst', ',') SELECT * FROM Split('Denver|Seattle|San Diego|New York', '|') SELECT * FROM Split('Denver is the super-awesomest city of them all.', ' ')   ******************************************************************************/ USE AdventureWorks GO   IF EXISTS       (SELECT *       FROM sysobjects       WHERE xtype = 'TF'       AND name = 'Split'       ) BEGIN       DROP FUNCTION Split END GO   CREATE FUNCTION Split (       @InputString                  VARCHAR(8000),       @Delimiter                    VARCHAR(50) )   RETURNS @Items TABLE (       Item                          VARCHAR(8000) )   AS BEGIN       IF @Delimiter = ' '       BEGIN             SET @Delimiter = ','             SET @InputString = REPLACE(@InputString, ' ', @Delimiter)       END         IF (@Delimiter IS NULL OR @Delimiter = '')             SET @Delimiter = ','   --INSERT INTO @Items VALUES (@Delimiter) -- Diagnostic --INSERT INTO @Items VALUES (@InputString) -- Diagnostic         DECLARE @Item                 VARCHAR(8000)       DECLARE @ItemList       VARCHAR(8000)       DECLARE @DelimIndex     INT         SET @ItemList = @InputString       SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)       WHILE (@DelimIndex != 0)       BEGIN             SET @Item = SUBSTRING(@ItemList, 0, @DelimIndex)             INSERT INTO @Items VALUES (@Item)               -- Set @ItemList = @ItemList minus one less item             SET @ItemList = SUBSTRING(@ItemList, @DelimIndex+1, LEN(@ItemList)-@DelimIndex)             SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)       END -- End WHILE         IF @Item IS NOT NULL -- At least one delimiter was encountered in @InputString       BEGIN             SET @Item = @ItemList             INSERT INTO @Items VALUES (@Item)       END         -- No delimiters were encountered in @InputString, so just return @InputString       ELSE INSERT INTO @Items VALUES (@InputString)         RETURN   END -- End Function GO   ---- Set Permissions --GRANT SELECT ON Split TO UserRole1 --GRANT SELECT ON Split TO UserRole2 --GO   The syntax is basically as follows: SELECT <fields> FROM Table 1 JOIN Table 2 ON ... JOIN Table 3 ON ... WHERE LOGICAL CONDITION A AND LOGICAL CONDITION B AND LOGICAL CONDITION C AND TABLE2.Id IN (SELECT * FROM Split(@IdList, ',')) @IdList is a parameter passed into the stored procedure, and the comma (',') is the delimiter you have chosen to split the parameter list on. You can also use it like this: SELECT <fields> FROM Table 1 JOIN Table 2 ON ... JOIN Table 3 ON ... WHERE LOGICAL CONDITION A AND LOGICAL CONDITION B AND LOGICAL CONDITION C HAVING COUNT(SELECT * FROM Split(@IdList, ',') Similarly, it can be used in other aggregate functions at run-time: SELECT MIN(SELECT * FROM Split(@IdList, ','), <fields> FROM Table 1 JOIN Table 2 ON ... JOIN Table 3 ON ... WHERE LOGICAL CONDITION A AND LOGICAL CONDITION B AND LOGICAL CONDITION C GROUP BY <fields> Now that I've (hopefully effectively) explained the benefits to using this function and implementing it in one or more of your database objects, let me warn you of a caveat that you are likely to encounter.  You may have a team member who waits until the right moment to ask you a pointed question: "Doesn't this function just do the same thing as using the IN function?  Why didn't you just use that instead?  In other words, why bother with this function?" What's happening is, one or more team members has failed to understand the reason for implementing this kind of function in the first place.  (Note: this is THE MOST IMPORTANT ASPECT OF THIS POST). Allow me to outline a few pros to implementing this function, so you may effectively parry this question.  Touche. 1) Code consolidation.  You don't have to maintain what is basically the same code and logic, but with varying numbers of the same parameter in several SQL objects.  I'm not going to go into the cons related to using this function, because the afore mentioned team member is probably more than adept at pointing these out.  Remember, the real positive contribution is ou are decreasing the liklihood that your team fails to update all (x) duplicate copies of what are basically the same stored procedure, and so on...  This is the classic downside to duplicate code.  It is a virus, and you should kill it. You might be better off rejecting your team member's question, and responding with your own: "Would you rather maintain the same logic in multiple different stored procedures, and hope that the team doesn't forget to always update all of them at the same time?".  In his head, he might be thinking "yes, I would like to maintain several different copies of the same stored procedure", although you probably will not get such a direct response.  2) Added flexibility - you can use the Split function elsewhere, and for splitting your data in different ways.  Plus, you can use any kind of delimiter you wish.  How can you know today the ways in which you might want to examine your data tomorrow?  Segue to my next point. 3) Because the function takes a delimiter parameter, you can split the data in any number of ways.  This greatly increases the utility of such a function and enables your team to work with the data in a variety of different ways in the future.  You can split on a single char, symbol, word, or group of words.  You can split on spaces.  (The list goes on... test it out). Finally, you can dynamically define the behavior of a stored procedure (or other SQL object) at run time, through the use of this function.  Rather than have several objects that accomplish almost the same thing, why not have only one instead?

    Read the article

  • Enable Soap for PHP 5.5.x on CentOS 6.5

    - by Chris Mancini
    Unfortunately I have to support soap on my server for the Fedex webservice. I recompiled PHP enabling support and it works via CLI but not PHP-fpm. They both point to the same ini file and both show the module loaded, but only CLI shows the configuration values. Output of php -i | grep -i soap Configuration File (php.ini) Path => /usr/local/etc Loaded Configuration File => /usr/local/etc/php.ini Configure Command => './configure' '--prefix=/usr/local' '--with-config-file-path=/usr/local/etc' '--with-config-file-scan-dir=/usr/local/etc/php_user/' '--enable-fpm' '--enable-ftp' '--enable-libxml' '--enable-mbstring' '--enable-pdo' '--enable-soap' '--enable-sockets=shared' '--enable-zip' '--with-curl' '--with-fpm-group=nginx' '--with-fpm-user=nginx' '--with-freetype-dir=/usr/lib64/' '--with-gd' '--with-jpeg-dir=/usr/lib64/' '--with-libdir=lib64' '--with-mcrypt' '--with-openssl' '--with-pdo-mysql' '--with-pear' '--with-readline' '--with-tidy' '--with-xsl' '--with-zlib' '--without-pdo-sqlite' '--without-sqlite3' soap Soap Client => enabled Soap Server => enabled soap.wsdl_cache => 1 => 1 soap.wsdl_cache_dir => /tmp => /tmp soap.wsdl_cache_enabled => 1 => 1 soap.wsdl_cache_limit => 5 => 5 soap.wsdl_cache_ttl => 86400 => 86400 Output from php-fpm phpinfo(): Configuration File (php.ini) Path /usr/local/etc Loaded Configuration File /usr/local/etc/php.ini SOAP Brad Lafountain, Shane Caraveo, Dmitry Stogov Please help, I have tried so many things...

    Read the article

  • What would cause an IIS6 website to be unavailable remotely randomly for a few minutes at a time?

    - by jskunkle
    Website is served by iis6 on windows server 2003. Never saw this problem once for months in beta. We made the new site live yesterday - its getting more traffic than in beta but not that much - resource utilization on the server and speed are fine. Today the site has been unavailable remotely a few (4?) times for a few minutes at a time. If you visit any page on the site - nothing is ever returned and eventually the request times out. While this is happening - I can connect to the server via remote desktop and the site loads fine from the live url when running a browser on the server locally. Other websites on the server continiue to function fine the entire time (using the same instance of iis, different app pools). Other computers on the same network can't access the website either. Other than not serving content - the server seems to behave normally - scheduled jobs in our custom job system continue to run, etc. We've looked at the iis logs quickly and we don't see any traffic out of the ordinary - no traffic spikes, etc. Any ideas? Thanks, Shane

    Read the article

  • apache name virtual host - two domains and SSL

    - by Tom
    I'm trying to setup Apache(2.2.3) to run two websites with SSL using both different domains and IP addresses. Both websites run fine on port 80 but when I tried to enable SSL for website2 I get a ssl_error_bad_cert_domain error; website2 picks up the SSL cert for website1. Here is my setup in httpd.conf: # Website1 NameVirtualHost 192.168.10.1:80 <VirtualHost 192.168.10.1:80> DocumentRoot /var/www/html ServerName www.website1.org </VirtualHost> NameVirtualHost 192.168.10.1:443 <VirtualHost 192.168.10.1:443> SSLEngine On SSLCertificateFile conf/ssl/website1.cer SSLCertificateKeyFile conf/ssl/website1.key </VirtualHost> # Website2 NameVirtualHost 192.168.10.2:80 <VirtualHost 192.168.10.2:80> DocumentRoot /var/www/html/chart ServerName www.website2.org </VirtualHost> NameVirtualHost 192.168.10.2:443 <VirtualHost 192.168.10.2:443> SSLEngine On SSLCertificateFile conf/ssl/website2.cer SSLCertificateKeyFile conf/ssl/website2.key </VirtualHost> Update: In answer to Shane (this wouldn't fit in comment box) here is the output from apachectl -S: VirtualHost configuration: 192.168.10.2:80 is a NameVirtualHost default server www.website2.org (/etc/httpd/conf/httpd.conf:1033) port 80 namevhost www.website2.org (/etc/httpd/conf/httpd.conf:1033) 192.168.10.2:443 is a NameVirtualHost default server bogus_host_without_reverse_dns (/etc/httpd/conf/httpd.conf:1040) port 443 namevhost bogus_host_without_reverse_dns (/etc/httpd/conf/httpd.conf:1040) 192.168.10.1:80 is a NameVirtualHost default server www.website1.org (/etc/httpd/conf/httpd.conf:1017) port 80 namevhost www.website1.org (/etc/httpd/conf/httpd.conf:1017) 192.168.10.1:443 is a NameVirtualHost default server bogus_host_without_reverse_dns (/etc/httpd/conf/httpd.conf:1024) port 443 namevhost bogus_host_without_reverse_dns (/etc/httpd/conf/httpd.conf:1024) wildcard NameVirtualHosts and _default_ servers: _default_:443 192.168.10.1 (/etc/httpd/conf.d/ssl.conf:81) Syntax OK

    Read the article

  • cisco asa + action drop issue

    - by ghp
    Have created a tunnel between 10.x.y.z network and 122.a.b.c ..the tunnel is up and active, but when I try the packet tracer output ..I get the ACTION as drop. I have also enabled same-security-traffic permit intra-interface. Can someone help me what does this drop mean? Result: input-interface: inside input-status: up input-line-status: up output-interface: outside output-status: up output-line-status: up Action: drop Drop-reason: (acl-drop) Flow is denied by configured rule Packet Tracer output @Shane Madden: please find below the packet tracer output. CASA5K-A# CASA5K-A# config t CASA5K-A(config)# packet-tracer input inside tcp 10.x.y.112 0 122.a.b.c 0 Phase: 1 Type: ROUTE-LOOKUP Subtype: input Result: ALLOW Config: Additional Information: in 0.0.0.0 0.0.0.0 outside Phase: 2 Type: ACCESS-LIST Subtype: Result: DROP Config: Implicit Rule Additional Information: Result: input-interface: inside input-status: up input-line-status: up output-interface: outside output-status: up output-line-status: up Action: drop Drop-reason: (acl-drop) Flow is denied by configured rule CASA5K-A(config)# ======================================================================== The access-group are as follows : access-group acl-inbound in interface outside access-group acl-outbound in interface inside and the access-list's are access-list acl-inbound extended permit tcp any any gt 1023 access-list acl-outbound extended permit ip object-group net-Source object net-dest

    Read the article

  • That’s a wrap! Almost, there’s still one last chance to attend a SQL in the City event in 2012

    - by Red and the Community
    The communities team are back from the SQL in the City multi-city US Tour and we are delighted to have met so many happy SQL Server professionals and Red Gate customers. We set out to run a series of back-to-back events in order to meet, talk to and delight as many SQL Server and Red Gate enthusiasts as possible in 5 different cities in 11 days. We did it! The attendees had a good time too and 99% of them would attend another SQL in the City event in 2013 – so it seems we left an impression. There were a range of topics on the event agenda, ranging from ‘The Whys & Hows of Continuous Integration’, ‘Database Maintenance Essentials’, ‘Red Gate tools – The Complete Lifecycle’, ‘Automated Deployment: Application And Database Releases Without The Headache’, ‘The Ten Commandments of SQL Server Monitoring’ and many more. Videos and slides from the events will be posted to the event website in November, after our last event of 2012. SQL in the City Seattle – November 5 Join us for free and hear from some of the very best names in the SQL Server world. SQL Server MVPs such as; Steve Jones, Grant Fritchey, Brent Ozar, Gail Shaw and more will be presenting at the Bell Harbor conference center for one day only. We’re even taking on board some of the recent attendee-suggestions of how we can improve the events (feedback from the 65% of attendees who came to our US tour events), first off we’re extending the drinks celebration in the evening! Rather than just a 30 minute drink and run, attendees will have up to 2 hours to enjoy free drinks, relax and network in a fantastic environment amongst some really smart like-minded professionals. If you’re interested in expanding your SQL Server knowledge, would like to learn more about Red Gate tools, get yourself registered for the last SQL in the City event of 2012. It’s free, fun and we’re very friendly! I look forward to seeing you in Seattle on Monday November 5. Cheers, Annabel.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 27 28 29 30 31 32 33 34 35 36 37 38  | Next Page >