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• How to hold a queue of messages and have a group of working threads without polling?

  - by Mark

  I have a workflow that I want to looks something like this: / Worker 1 \ =Request Channel= - [Holding Queue|||] - Worker 2 - =Response Channel= \ Worker 3 / That is: Requests come in and they enter a FIFO queue Identical workers then pick up tasks from the queue At any given time any worker may work only one task When a worker is free and the holding queue is non-empty the worker should immediately pick up another task When tasks are complete, a worker places the result on the Response Channel I know there are QueueChannels in Spring Integration, but these channels require polling (which seems suboptimal). In particular, if a worker can be busy, I'd like the worker to be busy. Also, I've considered avoiding the queue altogether and simply letting tasks round-robin to all workers, but it's preferable to have a single waiting line as some tasks may be accomplished faster than others. Furthermore, I'd like insight into how many jobs are remaining (which I can get from the queue) and the ability to cancel all or particular jobs. How can I implement this message queuing/work distribution pattern while avoiding a polling? Edit: It appears I'm looking for the Message Dispatcher pattern -- how can I implement this using Spring/Spring Integration?

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• where can i get the spring framework 3.0 distribution?

  - by mlo55

  has anyone been able to download the spring framework 3.0.0.M4 release from the spring source site... (or can you provide an alternative download page)? http://www.springsource.org/download am I missing something..., the site is giving me the runaround... when i get to the "Spring Community Downloads" page and choose spring from the LHS menu... I get no download link... ta in advance...

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• What features EJB3 bring and also how does EJB3 stack up with Spring Framework ?

  - by Rachel

  I have never worked on ejb, when I started programming Spring was already arrived and all my projects have been with Spring only, recently I had one interview and they wanted knowledge of EJB3.0 and so I want to know how does EJB3.0 stack up with Spring Framework and why many projects now a day are with Spring Framework and not with EJB3.0, do not quote me here as I can be wrong I would really appreciate if difference and benefits of using one over another could be explained from practical perspective.

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• How to populate Java (web) application with initial data using Spring/JPA/Hibernate

  - by Tuukka Mustonen

  I want to setup my database with initial data programmatically. I want to populate my database for development runs, not for testing runs (it's easy). The product is built on top of Spring and JPA/Hibernate. Developer checks out the project Developer runs command/script to setup database with initial data Developer starts application (server) and begins developing/testing then: Developer runs command/script to flush the database and set it up with new initial data because database structures or the initial data bundle were changed What I want is to setup my environment by required parts in order to call my DAOs and insert new objects into database. I do not want to create initial data sets in raw SQL, XML, take dumps of database or whatever. I want to programmatically create objects and persist them in database as I would in normal application logic. One way to accomplish this would be to start up my application normally and run a special servlet that does the initialization. But is that really the way to go? I would love to execute the initial data setup as Maven task and I don't know how to do that if I take the servlet approach. There is somewhat similar question. I took a quick glance at the suggested DBUnit and Unitils. But they seem to be heavily focused in setting up testing environments, which is not what I want here. DBUnit does initial data population, but only using xml/csv fixtures, which is not what I'm after here. Then, Maven has SQL plugin, but I don't want to handle raw SQL. Maven also has Hibernate plugin, but it seems to help only in Hibernate configuration and table schema creation (not in populating db with data). How to do this?

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• How to let Tomcat publish WSDL for the WS it provides (CXF 2.2, Spring 3, Tomcat6)

  - by Zwei Steinen

  Hi, I am trying to implement a simple web service provider using Tomcat6, CXF 2.2, Spring 3, and actually the service itself runs fine (I can call web methods using the original WSDL and SoapUI). However, Tomcat returns a blank page on "?wsdl" requests. Also, when I try to manipulate the (would-be) published WSDL by adding a publishedEndpointURL property to the jaxws:endpoint element, Tomcat will issue a XML parse exception (something like property publishedEndpointURL is not allowed in element jaxws:endpoint) <jaxws:endpoint id="service" implementor="org.sample.ServiceImpl" implementorClass="org.sample.ServiceImpl" address="/service" publishedEndpointURL="http://localhost:8080/MyService/service"> I used "contract first" style. EDIT: What I did so far: Setup tomcat6 with Spring3 Generate CXF implementation class by using maven Provide web.xml (only relevant part shown) <listener> <listener-class>org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <servlet> <servlet-name>cxf</servlet-name> <servlet-class> org.apache.cxf.transport.servlet.CXFServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>cxf</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> Provide applicationContext.xml (only relevant part is shown) Package generated stuff into war and deploy

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• Problem with Remember Me Service in Spring Security

  - by Gearóid

  Hi, I'm trying to implement a "remember me" functionality in my website using Spring. The cookie and entry in the persistent_logins table are getting created correctly. Additionally, I can see that the correct user is being restored as the username is displayed at the top of the page. However, once I try to access any information for this user when they return after they were "remembered", I get a NullPointerException. It looks as though the user isn't being set in the session again. My applicationContext-security.xml contains the following: <remember-me data-source-ref="dataSource" user-service-ref="userService"/> ... <authentication-provider user-service-ref="userService" /> <jdbc-user-service id="userService" data-source-ref="dataSource" role-prefix="ROLE_" users-by-username-query="select email as username, password, 1 as ENABLED from user where email=?" authorities-by-username-query="select user.id as id, upper(role.name) as authority from user, role, users_roles where users_roles.user_fk=id and users_roles.role_fk=role.name and user.email=?"/> I thought it may have had something to do with users-by-username query but surely login wouldn't work correctly if this query was incorrect? Any help on this would be greatly appreciated. Thanks, gearoid.

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• Lazy-loading with Spring HibernateDaoSupport ?

  - by umanga

  Greetings I am developing a non-webapplication using Spring+Hibernate. My question is how the HibernateDaoSupport handles lazy-loading , because after a call do DAO , the Session is closed. Take a look at following psuedo-code: DAO is like: CommonDao extends HibernateDaoSupport{ Family getFamilyById(String id); SubFamily getSubFamily(String familyid,String subfamilyid); } Domain model is like: Family{ private List<SubFamily> subfamiles; public List<SubFamily> getSubFamiles(); } SubFamily{ private Family family; public Family getFamily(); } In the application I get DAO from app-context and want to following operations.Is this possible to do with lazy-loading because AFAIK after every method (getFamilyById() , getSubFamily() ) the session is closed. CommonDAO dao=//get bean from application context; Family famA=dao.getFamilyById(familyid); // //Do some stuff List<SubFamily> childrenA=fam.getSubFamiles(); SubFamily asubfamily=dao.getSubFamily(id,subfamilyid); // //Do some other stuff Family famB=asubfamily.getFamily();

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• Spring scheduler shutdown error

  - by Alex

  During development a SPRING based scheduler in a tomcat container, I always get this logoutput at undeploy webapp or shutdown server: Apr 28, 2010 4:21:33 PM org.apache.catalina.core.StandardService stop INFO: Stopping service Catalina Apr 28, 2010 4:21:33 PM org.apache.catalina.loader.WebappClassLoader clearReferencesThreads SEVERE: A web application appears to have started a thread named [org.springframework.scheduling.quartz.SchedulerFactoryBean#0_Worker-1] but has failed to stop it. This is very likely to create a memory leak. Apr 28, 2010 4:21:33 PM org.apache.catalina.loader.WebappClassLoader clearReferencesThreads SEVERE: A web application appears to have started a thread named [org.springframework.scheduling.quartz.SchedulerFactoryBean#0_Worker-2] but has failed to stop it. This is very likely to create a memory leak. Apr 28, 2010 4:21:33 PM org.apache.catalina.loader.WebappClassLoader clearReferencesThreads SEVERE: A web application appears to have started a thread named [org.springframework.scheduling.quartz.SchedulerFactoryBean#0_Worker-3] but has failed to stop it. This is very likely to create a memory leak. Apr 28, 2010 4:21:33 PM org.apache.catalina.loader.WebappClassLoader clearReferencesThreads SEVERE: A web application appears to have started a thread named [org.springframework.scheduling.quartz.SchedulerFactoryBean#0_Worker-4] but has failed to stop it. This is very likely to create a memory leak. Apr 28, 2010 4:21:33 PM org.apache.catalina.loader.WebappClassLoader clearReferencesThreads SEVERE: A web application appears to have started a thread named [org.springframework.scheduling.quartz.SchedulerFactoryBean#0_Worker-5] but has failed to stop it. This is very likely to create a memory leak. . . . SEVERE: A web application created a ThreadLocal with key of type [org.springframework.core.NamedThreadLocal] (value [Prototype beans currently in creation]) and a value of type [null] (value [null]) but failed to remove it when the web application was stopped. To prevent a memory leak, the ThreadLocal has been forcibly removed. Apr 28, 2010 4:21:34 PM org.apache.coyote.http11.Http11Protocol destroy INFO: Stopping Coyote HTTP/1.1 on http-8606 How can I fix this?

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• Spring MVC parameter validation

  - by Don

  Hi, I've defined a controller, validator and command class for a Spring 2.5 MVC application like this: public class ResourceController extends AbstractCommandController { private MessageRetriever messageRetriever; protected ModelAndView handle(HttpServletRequest request, HttpServletResponse response, Object command, BindException errors) throws Exception { ResourceCommand resourceCommand = (ResourceCommand) command; // I NEED TO CHECK HERE IF COMMAND IS VALID? } public static class ResourceCommand { private String module; private String site; private String lang; // GETTERS AND SETTERS OMITTED } public static class ResourceValidator implements Validator { public boolean supports(Class clazz) { return ResourceCommand.class.isAssignableFrom(clazz); } public void validate(Object obj, Errors errors) { ValidationUtils.rejectIfEmptyOrWhitespace(errors, "module", "MODULE_REQUIRED"); ValidationUtils.rejectIfEmptyOrWhitespace(errors, "site", "SITE_REQUIRED"); ValidationUtils.rejectIfEmptyOrWhitespace(errors, "lang", "LANG_REQUIRED"); } } } I have wired these all together in the application context: <bean id="resourceController" class="com.amadeus.jcp.ui.framework.localization.ResourceController"> <property name="commandClass" value="com.amadeus.jcp.ui.framework.localization.ResourceController.ResourceCommand"/> <property name="validator"> <bean class="com.amadeus.jcp.ui.framework.localization.ResourceController.ResourceValidator"/> </property> </bean> However, I can't figure out how to actually check whether the command is valid or not - I assume the framework calls the validator, but how do I get access to the result? Incidentally, I'm using Java 1.4, so can't use any solutions that require annotations or other Java 1.5 features. Thanks, Don

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• Spring-hibernate mapping problem

  - by James

  I have a spring-hibernate application which is failing to map an object properly: basically I have 2 domain objects, a Post and a User. The semantics are that every Post has 1 corresponding User. The Post domain object looks roughly as follows: class Post { private int pId; private String attribute; ... private User user; //getters and setters here } As you can see, Post contains a reference to User. When I load a Post object, I want to corresponding User object to be loaded (lazily - only when its needed). My mapping looks as follows: <class name="com...Post" table="post"> <id name="pId" column="PostId" /> <property name="attribute" column="Attribute" type="java.lang.String" /> <one-to-one name="User" fetch="join" class="com...User"></one-to-one> </class> And of course I have a basic mapping for User set up. As far as my table schema is concerned, I have a table called post with a foreign UserId which links to the user table. I thought this setup should work, BUT when I load a page that forces the lazy loading of the User object, I notice the following Hiberate query being generated: Select ... from post this_ left outer join user user2_ on this.PostId=user2_.UserId ... Obviously this is wrong: it should be joining UserId from post with UserId from user, but instead its incorrectly joining PostId from post (its primary key) with UserId from user. Any ideas? Thanks!

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• using JMock to write unit test for a simple spring JDBC DAO

  - by Quincy

  I'm writing an unit test for spring jdbc dao. The method to test is: public long getALong() { return simpleJdbcTemplate.queryForObject("sql query here", new RowMapper<Long>() { public Long mapRow(ResultSet resultSet, int i) throws SQLException { return resultSet.getLong("a_long"); } }); } Here is what I have in the test: public void testGetALong() throws Exception { final Long result = 1000L; context.checking(new Expectations() {{ oneOf(simpleJdbcTemplate).queryForObject("sql_query", new RowMapper<Long>() { public Long mapRow(ResultSet resultSet, int i) throws SQLException { return resultSet.getLong("a_long"); } }); will(returnValue(result)); }}); Long seq = dao.getALong(); context.assertIsSatisfied(); assertEquals(seq, result); } Naturally, the test doesn't work (otherwise, I wouldn't be asking this question here). The problem is the rowmapper in the test is different from the rowmapper in the DAO. So the expectation is not met. I tried to put with around the sql query and with(any(RowMapper.class)) for the rowmapper. It wouldn't work either, complains about "not all parameters were given explicit matchers: either all parameters must be specified by matchers or all must be specified by values, you cannot mix matchers and values"

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• What is the correct way to configure a spring TextEncryptor for use on Heroku

  - by Ollie Edwards

  I have a spring TextEncryptor defined like this <bean id="textEncryptor" class="org.springframework.security.crypto.encrypt.Encryptors" factory-method="text"> <constructor-arg value="${security.encryptPassword}" /> <constructor-arg value="${security.encryptSalt}" /> </bean> Which is fed these properties security.encryptPassword=47582920264f212c566d5e5a6d security.encryptSalt=39783e315e6a207e733d6f4141 Which works fine on my local environment. When I deploy to Heroku I get java.lang.IllegalArgumentException: Unable to initialize due to invalid secret key at org.springframework.security.crypto.encrypt.CipherUtils.initCipher(CipherUtils.java:110) at org.springframework.security.crypto.encrypt.AesBytesEncryptor.encrypt(AesBytesEncryptor.java:65) at org.springframework.security.crypto.encrypt.HexEncodingTextEncryptor.encrypt(HexEncodingTextEncryptor.java:36) ... Caused by: java.security.InvalidKeyException: Illegal key size at javax.crypto.Cipher.checkCryptoPerm(Cipher.java:972) at javax.crypto.Cipher.implInit(Cipher.java:738) at javax.crypto.Cipher.chooseProvider(Cipher.java:797) at javax.crypto.Cipher.init(Cipher.java:1276) at javax.crypto.Cipher.init(Cipher.java:1215) at org.springframework.security.crypto.encrypt.CipherUtils.initCipher(CipherUtils.java:105) ... 53 more So I tried some smaller keys but I always get the same problem. What is the correct key size to use on Heroku?

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• Problem with Spring @Configuration class

  - by easyrider

  Hi, i use class with @Configuration annotation to configure my spring application: @Configuration public class SpringConfiguration { @Value("${driver}") String driver; @Value("${url}") String url; @Value("${minIdle}") private int minIdle; // snipp .. @Bean(destroyMethod = "close") public DataSource dataSource() { DataSource dataSource = new DataSource(); dataSource.setDriverClassName(driver); dataSource.setUrl(url); dataSource.setUsername(user); dataSource.setPassword(password); dataSource.setMinIdle(minIdle); return dataSource; } and properties file in CLASSPATH driver=org.postgresql.Driver url=jdbc:postgresql:servicerepodb minIdle=1 I would like to get my DataSource configured object in my DAO class: ApplicationContext ctx = new AnnotationConfigApplicationContext(SpringConfiguration.class); DataSource dataSource = ctx.getBean(DataSource.class); But i get the error: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'springConfiguration': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: private int de.hska.repo.configuration.SpringConfiguration.minIdle; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert value of type 'java.lang.String' to required type 'int'; nested exception is **java.lang.NumberFormatException: For input string: "${minIdle}"** Caused by: java.lang.NumberFormatException: For input string: **"${minIdle}"** at java.lang.NumberFormatException.forInputString(**Unknown Source**) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.valueOf(Unknown Source) It worked with String properties (driver, url), but ${minIdle} (of type int) can't be resolved! Please help. Thanx in advance!

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• Application design in Spring MVC

  - by Ravi

  Hello All, I'm new to Spring MVC and trying out a simple project.It will contain a simple adding, viewing, updating and deleting user work flows. It will have login page and once authenticated the user will be taken to a welcome screen which will have links to add, view, update and delete users. Clicking on any of the links will take to individual pages where the user can do the specific tasks. What I'm doing here is, I'm using a MultiActionController to group together all requests related to User work flow. So the request from "Add User" link will handled by the addUser method in the UserController which will redirect the user to the "Add User" page, and the user can then fill in the details and save the new user. Now here is where I'm getting confused. Where should I put the save process of the new user, should I put that in new mehtod inside UserController, or use the same "addUser" method. What is the best way to handle this kind of scenario. I hope I was able to clear my question.

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• executing stored procedure from Spring-Hibernate using Annotations

  - by HanuAthena

  I'm trying to execute a simple stored procedure with Spring/Hibernate using Annotations. Here are my code snippets: DAO class: public class UserDAO extends HibernateDaoSupport { public List selectUsers(final String eid){ return (List) getHibernateTemplate().execute(new HibernateCallback() { public Object doInHibernate(Session session) throws HibernateException, SQLException { Query q = session.getNamedQuery("SP_APPL_USER"); System.out.println(q); q.setString("eid", eid); return q.list(); } }); } } my entity class: @Entity @Table(name = "APPL_USER") @Inheritance(strategy = InheritanceType.SINGLE_TABLE) @DiscriminatorFormula(value = "SUBSCRIBER_IND") @DiscriminatorValue("N") @NamedQuery(name = "req.all", query = "select n from Requestor n") @org.hibernate.annotations.NamedNativeQuery(name = "SP_APPL_USER", query = "call SP_APPL_USER(?, :eid)", callable = true, readOnly = true, resultClass = Requestor.class) public class Requestor { @Id @Column(name = "EMPL_ID") public String getEmpid() { return empid; } public void setEmpid(String empid) { this.empid = empid; } @Column(name = "EMPL_FRST_NM") public String getFirstname() { return firstname; } ... } public class Test { public static void main(String[] args) { ApplicationContext ctx = new ClassPathXmlApplicationContext( "applicationContext.xml"); APFUser user = (APFUser)ctx.getBean("apfUser"); List selectUsers = user.getUserDAO().selectUsers("EMP456"); System.out.println(selectUsers); } } and the stored procedure: create or replace PROCEDURE SP_APPL_USER (p_cursor out sys_refcursor, eid in varchar2) as empId varchar2(8); fname varchar2(50); lname varchar2(50); begin empId := null; fname := null; lname := null; open p_cursor for select l.EMPL_ID, l.EMPL_FRST_NM, l.EMPL_LST_NM into empId, fname, lname from APPL_USER l where l.EMPL_ID = eid; end; If i enter invalid EID, its returning empty list which is OK. But when record is there, following exception is thrown: Exception in thread "main" org.springframework.jdbc.BadSqlGrammarException: Hibernate operation: could not execute query; bad SQL grammar [call SP_APPL_USER(?, ?)]; nested exception is java.sql.SQLException: Invalid column name Do I need to modify the entity(Requestor.class) ? How will the REFCURSOR be converted to the List? The stored procedure is expected to return more than one record.

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• Sending multi-part email from Google App Engine using Spring's JavaMailSender fails

  - by hleinone

  It works without the multi-part (modified from the example in Spring documentation): final MimeMessagePreparator preparator = new MimeMessagePreparator() { public void prepare(final MimeMessage mimeMessage) throws Exception { final MimeMessageHelper message = new MimeMessageHelper( mimeMessage); message.setTo(toAddress); message.setFrom(fromAddress); message.setSubject(subject); final String htmlText = FreeMarkerTemplateUtils .processTemplateIntoString(configuration .getTemplate(htmlTemplate), model); message.setText(htmlText, true); } }; mailSender.send(preparator); But once I change it to: final MimeMessagePreparator preparator = new MimeMessagePreparator() { public void prepare(final MimeMessage mimeMessage) throws Exception { final MimeMessageHelper message = new MimeMessageHelper( mimeMessage, true); ... message.setText(plainText, htmlText); } }; mailSender.send(preparator); I get: Failed message 1: javax.mail.MessagingException: Converting attachment data failed at com.google.appengine.api.mail.stdimpl.GMTransport.sendMessage(GMTransport.java:231) at org.springframework.mail.javamail.JavaMailSenderImpl.doSend(JavaMailSenderImpl.java:402) ... This is especially difficult since the GMTransport is proprietary Google class and no sources are available, which would make it a bit easier to debug. Anyone have any ideas what to try next? My bean config, for helping you to help me: <bean id="mailSender" class="org.springframework.mail.javamail.JavaMailSenderImpl" p:username="${mail.username}" p:password="${mail.password}" p:protocol="gm" />

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• Spring - Transaction Readonly

  - by AAK

  Hello Gurus! Just wanted your expert opinions on declarative transaction management for Spring. Here is my setup - A. DAO Layer is Plain old JDBC using jdbcTemplete (No hibernate etc) B. Service Layer is POJO with declarative trasnactions as follows - save*, readonly=false, rollback for Throwable Things work fine with above setup. However when I say get*, readonly=true I see errors in my log file saying - Database connection cannot be marked as readonly. This happens for all get* methods in Service Layer. Now my questions - A. Do I have to say get* as readonly? All my get* methods are pure read DB operations. I do not wish to run them in any transaction context. How serious is the above error? B. When I remove the get* confiiguration, I do not see the errors, morever all my simple get* operations are performed without transactions. Is this the way to go? C. Why would anyone want to have transactional methods where readonly = true? Is there any practical significance of this configuration? Thank you! As always your resposes are much appreciated!

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• Problem with Spring security's logout

  - by uther-lightbringer

  Hello, I've got a problem logging out in Spring framework. First when I want j_spring_security_logout to handle it for me i get 404 j_spring_security_logout not found: sample-security.xml: <http> <intercept-url pattern="/messageList.htm*" access="ROLE_USER,ROLE_GUEST" /> <intercept-url pattern="/messagePost.htm*" access="ROLE_USER" /> <intercept-url pattern="/messageDelete.htm*" access="ROLE_ADMIN" /> <form-login login-page="/login.jsp" default-target-url="/messageList.htm" authentication-failure-url="/login.jsp?error=true" /> <logout/> </http> Sample url link to logout in JSP page: <a href="<c:url value="/j_spring_security_logout" />">Logout</a> When i try to use a custom JSP page i.e. I use login form for this purpose then I get better result at least it gets to login page, but another problem is that you dont't get logged off as you can diretcly type url that should be guarded buy you get past it anyway. Slightly modified from previous listings: <http> <intercept-url pattern="/messageList.htm*" access="ROLE_USER,ROLE_GUEST" /> <intercept-url pattern="/messagePost.htm*" access="ROLE_USER" /> <intercept-url pattern="/messageDelete.htm*" access="ROLE_ADMIN" /> <form-login login-page="/login.jsp" default-target-url="/messageList.htm" authentication-failure-url="/login.jsp?error=true" /> <logout logout-success-url="/login.jsp" /> </http> <a href="<c:url value="/login.jsp" />">Logout</a> Thank you for help

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• Spring MVC- several parts/views from a controller

  - by leeeroy

  i'm looking into using Spring MVC - how would I structure the fact that a page can be composed of several different views Consider a controller that's basically: public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List<Post> posts = repository.getNewPosts(); return new ModelAndView("posts", "posts", posts); } However, I decide that on every page, I'd also want a side "pane" that shows data based on some logic. That "pane" would just be a .jsp that gets included from the above "posts" view, and I could change my controller to: public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List<Post> posts = repository.getNewPosts(); List<Items> items= repository.getItems(); return new ModelAndView("model", "model", new MyCommonViewModel(posts,items)); } But then I'd have to change every controller to also do List<Items> items= repository.getItems(); , and change everything again the next time I come up with something new. This seems messy. How do I structure this ? `

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• Setting spring bean property value using ref-bean

  - by Apache Fan

  Hi, I am trying to set a property value using spring. <bean id="velocityPropsBean" class="com.test.CustomProperties" abstract="false" singleton="true" lazy-init="false" autowire="default" dependency-check="default"> <property name="properties"> <props> <prop key="resource.loader">file</prop> <prop key="file.resource.loader.cache">true</prop> <prop key="file.resource.loader.class">org.apache.velocity.runtime.resource.loader.FileResourceLoader</prop> <prop key="file.resource.loader.path">NEED TO INSERT VALUE AT STARTUP</prop> </props> </property> </bean> <bean id="velocityResourcePath" class="java.lang.String" factory-bean="velocityHelper" factory-method="getLoaderPath"/> Now what i need to do is insert the result from getLoaderPath into file.resource.loader.path. The value of getLoaderPath changes so it has to be loaded at server startup. Any thoughts how i can inset the velocityResourcePath value to the property?

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• spring - constructor injection and overriding parent definition of nested bean

  - by mdma

  I've read the Spring 3 reference on inheriting bean definitions, but I'm confused about what is possible and not possible. For example, a bean that takes a collaborator bean, configured with the value 12 <bean name="beanService12" class="SomeSevice"> <constructor-arg index="0"> <bean name="beanBaseNested" class="SomeCollaborator"> <constructor-arg index="0" value="12"/> </bean> </constructor-arg> </bean> I'd then like to be able to create similar beans, with slightly different configured collaborators. Can I do something like <bean name="beanService13" parent="beanService12"> <constructor-arg index="0"> <bean> <constructor-arg index="0" value="13"/> </bean> </constructor> </bean> I'm not sure this is possible and, if it were, it feels a bit clunky. Is there a nicer way to override small parts of a large nested bean definition? It seems the child bean has to know quite a lot about the parent, e.g. constructor index. I'd prefer not to change the structure - the parent beans use collaborators to perform their function, but I can add properties and use property injection if that helps. This is a repeated pattern, would creating a custom schema help? Thanks for any advice!

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• NUnit integration programmatically with spring

  - by harkon

  Hi! I have a component based architecture framework designed and I use NUnit for isolated testing - okay so far. Now I want to enable integration tests. Therefore the tests use real implementations of the existing components. Each element of the component has a life cycle (init, start and stop) and I created a NUnit component. In the start section the Console runner of the NUnit will be executed. Okay - now if I have a test fixture class in my dlls in the execution path the runner exectues them - fine! But: And this is crucial! Each to be tested implementation exists so far in the process and I want to use this instances for testing. If I use NUnit runner in the current way each instance will be created twice - and above all: I have a spring container and a implementation registry. Via this registry I can get access to all instances in the processes. But how do I give the test fixture access to the existing registry? Good: I can start the component architecture framework in the startup of the nunit runner - but this is not what I want. My guide is the apache Cactus framework (with JUnit and tomcat, JBoss etc.) Can someone help? Thanks a lot! Check: http://cone.codeplex.com

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• PropertyPlaceholderConfigurer vs Filters -- Spring Beans

  - by John

  Hi there. I've got a question regarding the difference between PropertyPlaceholderConfigurer (org.springframework.beans.factory.config.PropertyPlaceholderConfigurer) and normal filters defined in my pom.xml. I've been looking at examples, and it seems that even though filters are defined and marked to be active by default in the pom.xml they still make use of PropertyPlaceholderConfigurer in Spring's applicationContext.xml. This means that the pom.xml has a reference to a filter-LOCAL.properties while applicationContext.xml has a reference to application.properties and they both contain the same settings. Why is that? Is that how it is supposed to be done? I'm able to run the goal mvn jetty:run without the application.properties present, but if I add settings to the application.properties that differ from the filter-LOCAL.properties they don't seem to override. Here's an example of what I mean: pom.xml <profiles <profile <idLOCAL <activation <activeByDefaulttrue </activation <properties <envLOCAL </properties </profile </profiles applicationContext.xml <bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer" <property name="locations" <list <valueclasspath:application.properties </list </property <property name="ignoreResourceNotFound" value="true"/ </bean <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" <property name="driverClassName" value="${jdbc.driver}"/ <property name="url" value="${jdbc.url}"/ <property name="username" value="${jdbc.username}"/ <property name="password" value="${jdbc.password}"/ </bean an example of the content of application.properties and filters-LOCAL.properties jdbc.driver=org.postgresql.Driver jdbc.url=jdbc:postgresql://localhost/shoutbox_dev jdbc.username=tester jdbc.password=tester Can I remove the propertyConfigurer from the applicationContext, create a PROD filter and disregard the application.properties file, or will that give me issues when deploying to the production server?

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• Spring aop multiple pointcuts & advice but only the last one is working

  - by Jarle Hansen

  I have created two Spring AOP pointcuts that are completely separate and will be woven in for different parts of the system. The pointcuts are used in two different around advices, these around-advices will point to the same Java method. How the xml-file looks: <aop:config> <aop:pointcut expression="execution(......)" id="pointcutOne" /> <aop:pointcut expression="execution(.....)" id="pointcurTwo" /> <aop:aspect id="..." ref="springBean"> <aop:around pointcut-ref="pointcutOne" method="commonMethod" /> <aop:aroung pointcut-ref="pointcutTwo" method="commonMethod" /> </aop:aspect> </aop:config> The problem is that only the last pointcut works (if I change the order "pointcutOne" works because it is last). I have gotten it to work by creating one big pointcut, but I would like to have them separate. Any suggestions to why only one of the pointcuts works at a time?

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• Update database settings in properties file in Spring

  - by mvg

  Hi all, I am trying to create a Database Manager page which shows the database details on page load and updates the database settings when the user press submit I followed this tutorial and set the database settings in properties file. I managed to update the database settings in properties file programmatically. When I retrieved the database settings using the following code DriverManagerDataSource databaseSource = (DriverManagerDataSource)context.getBean("dataSource"); databaseSource.getUsername(); I managed to get the old value and unable to get the new value This is the mapping in applicationContext.xml file <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>classpath:/bundle/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> I checked the properties file and found it to be updated with the latest input. What am I missing? Thanks in advance P.S I am using JSF1.2 with Spring 3 Update Just making my requirement simple. I am creating a setparate dbsettings page, so that when user wishes to connect to different database he/she can just enter the details in dbsettings page and connect

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