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Search found 1652 results on 67 pages for 'zend decorators'.

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  • ZendX Jquery Decorator

    - by iJD
    How use partial decorator in Jquery Element I use this code for Form Element: $title = new Zend_Form_Element_Text('title'); $title->setRequired(true) ->setAttrib('class', 'inputbox') ->setLabel('Title'); $title->viewScript = 'RegElement.phtml'; $title->setDecorators( array( array('ViewScript', array('class' => 'RegElement')) ) ); But when i use Jquery Element i dont know how implement it: $datePicker = new ZendX_JQuery_Form_Element_DatePicker( "datePicker1", array("label" => "Date:") ); $datePicker->viewScript = 'RegElement.phtml'; $datePicker->setDecorators( array( array('ViewScript', array('class' => 'RegElement')) ) ); //views/scripts/RegElement.phtml <li class="row <?php echo $this->class ?>"> <div class="cont-error"> <?php echo $this->formErrors($this->element->getMessages()); ?> </div> <div class="rowfields"> <?php echo $this->formLabel($this->element->getName(), $this->element->getLabel()) ?> <?php echo $this->{$this->element->helper}( $this->element->getName(), $this->element->getValue(), $this->element->getAttribs() ) ?> </div> <div class="hint"><?php echo $this->element->getDescription() ?></div> </li> And display this error: Warning: Exception caught by form: Cannot render jQuery form element without at least one decorator implementing the 'ZendX_JQuery_Form_Decorator_UiWidgetElementMarker' interface. I need display datePicker with same format. but idk how implement this interface. thx for your help.

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  • How to use Zend_Cache Identifier ?

    - by ArneRie
    Hi Folks, i think iam getting crazy, iam trying to implement Zend_Cache to cache my database query. I know how it works and how to configure. But i cant find a good way to set the Identifier for the cache entrys. I have an method wich search for records in my database (based on an array with search values). /** * Find Record(s) * Returns one record, or array with objects * * @param array $search Search columns => value * @param integer $limit Limit results * @return array One record , or array with objects */ public function find(array $search, $limit = null) { $identifier = 'NoIdea'; if (!($data = $this->_cache->load($identifier))) { // fetch // save to cache with $identifier.. } But what kind of identifier can use in this situation?

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  • Need to remove /index/ form URLs in my Zend_Navigation XML config

    - by jwhat
    I'm using Zend_Navigation to create my nav. I want the URL to be domain.com/me and not domain.com/index/me. What is wrong with my config XML: <?xml version="1.0" encoding="UTF-8"?> <config> <nav> <home> <label>Home</label> <controller>index</controller> <action>index</action> <pages> <me> <label>Me</label> <module>default</module> <controller>index</controller> <action>me</action> <resource>user</resource> <privilege>logout</privilege> </me> </pages> </home> </nav> </config>

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  • Extending / changing how Zend_Search_Lucene searches

    - by Grant Collins
    Hi, I am currently using Zend_Search_Lucene to index and search a number of documents currently at around a 1000 or so. What I would like to do is change how the engine scores hits on a document, from the current default. Zend_Search_Lucene scores on the frequency of number of hits within a document, so a document that has 10 matches of the word PHP will score higher than a document with only 3 matches of PHP. What I am trying to do is pass a number of key words and score depending on the hits of those keywords. e.g. I pass 5 key words say,PHP, MySQL, Javascript, HTML and CSS that I search against the index. One document has 3 matches to those key words and one document has all 4 matches, the 4 matches scores the highest. The number of instances of those words in the document do not concern me. Now I've had a quick look at Zend_Search_Lucene_Search_Similarity however I have to confess that I am not sure (or that bright) to know how to use this to achieve what I am after. Is what I want to do possible using Lucene or is there a better solution out there?

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  • Zend_Filter_StripTags ignoring allowed tags and attributes

    - by Jhorra
    I'm trying to use the following code and it still strips out all the tags. Am I doing something wrong? I'm using the newest V1.10 $allowed_tags = array('img', 'object', 'param', 'embed', 'a', 'href', 'p', 'br', 'em', 'strong', 'li', 'ol', 'span'); $allowed_attributes = array('style', 'src', 'alt', 'href', 'width', 'height', 'value', 'name', 'type', 'embed', 'quality', 'pluginspage'); Zend_Loader::loadClass('Zend_Filter_StripTags'); $html_filter = new Zend_Filter_StripTags($allowed_tags, $allowed_attributes); $post = $html_filter->filter($this->_request->getPost('post'));

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  • Zend_Db Enum Values [Closed]

    - by scopus
    I find this solution $metadata = $result->getTable()->info('metadata'); echo $metadata['Continent']['DATA_TYPE']; Hi, I want to get enum values in Zend_Db. My Code: $select = $this->select(); $result = $select->fetchAll(); print_r($result->getTable()); Output: Example Object ( [_name] => country [query] => Zend_Db_Table_Select Object ( [_info:protected] => Array ( [schema] => [name] => country [cols] => Array ( [0] => Code [1] => Continent ) [primary] => Array ( [1] => Code ) [metadata] => Array ( [Continent] => Array ( [SCHEMA_NAME] => [TABLE_NAME] => country [COLUMN_NAME] => Continent [COLUMN_POSITION] => 3 [DATA_TYPE] => enum('Asia','Europe','North America','Africa','Oceania','Antarctica','South America') [DEFAULT] => Asia [NULLABLE] => [LENGTH] => [SCALE] => [PRECISION] => [UNSIGNED] => [PRIMARY] => [PRIMARY_POSITION] => [IDENTITY] => ) I see enum values in data_type but i don't get this values. How can get data_type?

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  • How to allow all except part 1 and part 2 ?

    - by Stackfan
    This allows me to get easyly dynamic input variables instead of putting a static prefix like /en/etcetcetc, but the problem is all controllers are blocked. Everything goes to index/index. Question: How can i tell this rule allow evertying as it is now, but do not track if it contains http://site.com/donotcatch/me and http://site.com/iamnotbelongstodynamic1/blabla protected function _initRoutes() { ... $dynamic1 = new Zend_Controller_Router_Route( '/:variable0/:variable1', array( 'controller' => 'index', 'action' => 'index'), array( 'variable0' => '^[a-zA-Z0-9_]*$', 'variable1' => '^[a-zA-Z0-9_]*$', ) ); Follow up: Normally, i always belive yes we can, so, we can do that like this where dynamic1 does not the inter-fare with my other static controllers: // http://site/yeswecan/blabla // variable0 = yeswecan // variable1 = blabla $dynamic1 = new Zend_Controller_Router_Route( '/:variable0/:variable1', array( 'controller' => 'index', 'action' => 'index'), array( 'variable0' => '^[a-zA-Z]*$', 'variable1' => '^[a-z0-9_]*$', ) ); // http://site/ajax/whatever... // solves it $dynamic2 = new Zend_Controller_Router_Route( '/ajax/:variable0', array( 'controller' => 'ajax', 'action' => '' ), array( 'variable0' => '^[a-zA-Z0-9_]*$', ) ); // http://site/order/whatever... // solves it $dynamic3 = new Zend_Controller_Router_Route( '/order/:variable0', array( 'controller' => 'order', 'action' => ''), array( 'variable0' => '^[a-zA-Z0-9_]*$', ) ); Note: Still the controllers are getting failed for example http://site/ajax/whatever always goes to /ajax/index where i wanted to send it as /ajax/user-inserted-value How can i fix the $dynamic2 and $dynamic3 by keeping $dynamic1 ??

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  • How does Zend_Db_Table_Select work?

    - by jwhat
    I'm trying to figure out how to use Zend_Db_Table_Abstract correctly. I want to return just the name column from my query. Can you please explain what's wrong with the following code? class Model_DbTable_Foo extends Zend_Db_Table_Abstract { protected $_name = 'foo'; public function getFooById($id) { $select = $this->select(true)->columns('name')->where('id=' . $id); $row = $this->fetchRow($select); print_r($row->toArray()); } }

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  • ZendFramework Headscript Helper - Make scripts unique

    - by tokam
    How can I ensure that the headScript and headStyle helper include css files only once when added? The reason I am asking is that I would like to display some contents in a lightbox and all Flashmassages.E.g. notifications like profile successfully edited. To display flashmessages in the lightbox i would like to check at the top of my layout script if they are set, in case they are i would like to attach the required javascript library using the headScript helper. The problem is that I have no control about the scripts which were already added at this point. Maybe at a page where the library is needed for an other use case, it has already been added with addScript. How can I ensure all scripts are added only once to my helper? I already checked that these helpers extend Zend_View_Helper_Placeholder_Container_Standalone which uses an ArrayObject internally to hold the data and provides getters & setter to the array object. Maybe a solution here would be to check each time when adding a script file if it already exists using the ArrayObject?

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • Trying to understand the Zend_Auth OpenId

    - by Will Olbrys
    I'm using a slightly modified version of the Zend_Auth_OpenId classes to get openid logins from google apps. The results are very positive, as I seem to be getting successful results from Google. I cannot get successful results passed to Zend_Auth, though. For example, Zend_Auth_Adapter_OpenId on line 241: if (!$consumer->login($id, $this->_returnTo, $this->_root, $this->_extensions, $this->_response)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", $consumer->getError())); } The consumer calls login() which in turn calls the private method _checkId() in Zend_OpenId_Consumer. _checkId() always ends in redirecting to the openid server. How is this ever supposed to return a valid Zend_Auth_Result object? I'm pretty close to giving up and trying to implement another OpenId library, but I'm so close to just making this work. I must be missing something so obvious! Maybe I don't understand how openid works exactly, but if someone could help me understand I would really appreciate it.

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  • Using Zend_Db and multiple tables

    - by Yacoby
    I have a normalized database that stores locations of files on the internet. A file may have multiple locations spread across different sites. I am storing the urls in two parts (Site.UrlStart, FileLocation.UrlEnd). The UrlEnd is the part unique to that file (for the site). Simplified Db structure: I am using Zend_Db as my ORM (If it is that), with classes for the tables inheriting from Zend_Db_Table_Abstract. The issue is that retrieving the location data (e.g. the url) requires the use of multiple tables and as far as I can make out and I would either have to use both table classes (thereby exposing my table structure) or scatter sql all over my application, neither of which sound appealing. The only solution I can see is to create a façade that acts like Zend_Db_Table_Abstract (Maybe inherits from it?) and hides the fact that the data is actually on two tables. My questions are as follows: Am I going in the right direction in creating a façade class (Are there other alternatives)? Should the facade class inherit from Zend_Db_Table_Abstract?

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  • Zend_Registry - Do you need getInstance() ?

    - by Jesse
    Hey I'm wondering when accessing Zend_Registry in an application if you need to include getInstance() and if so, why? for example Zend_Registry::getInstance()-get('db'); vs. Zend_Registry::get('db'); they both seem to work with the later being less verbose. I vaguely understand that Zend_Registry is a singleton, which I think means there can only be one instance of it? so why would you need getInstance()?

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  • having problems using Zend_Db_Table_Abstract::createRow()

    - by Gootik
    Hey, I have built a model that extends Zend_Db_Table_Abstract and I can't figure out why I can't use createRow(); here is my code: class Model_User extends Zend_Db_Table_Abstract { public function createUser() { $row = $this->createRow(); $row->name = 'test'; $row->save(); } } and in a controller I use: $userModel = new Model_User(); $userModel->createUser(); which when run displays an error An error occurred Application error here is my setup in application.ini resources.db.adapter = "pdo_mysql" resources.db.params.host = "localhost" resources.db.params.username = "root" resources.db.params.password = "pass" resources.db.params.dbname = "app_db" resources.db.isDefaultTableAdapter = true I am sure that my user/pass/dbname is correct. I would appreciate it if you point me in the right direction.

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  • [ZF] How to use Zend_Db without SQL Queries?

    - by rasouza
    The last time I worked with Zend_Db I recall I used to write SQL Queries manually. I've been searching for some ORM application, but, since I read something like Zend_Db is also capable of doing so, I started to try it, but I can't find neither a good tutorial explain it or a good documentation. I read something lake Gateway pattern and ModelMapper class but I can't figure it out. Can someone shine my path? :P

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  • Where do I put inline script in head with Zend Framework?

    - by Joel
    I'm reading the manual here: http://zendframework.com/manual/en/zend.view.helpers.html but I'm still confused. I have a script in my head that I'm converting to the layout/view for the Zend MVC: <script type="text/javascript"> var embedCode = '<object data="http://example.com" type="application/x-shockwave-flash" height="385" width="475"><param name="src" value="http://example.com" /><param name="allowfullscreen" value="true" /></object>' </script> I first tried to add it is an external file like this (in layout): $this->headScript()->appendFile('js/embeddedVideo.js')->appendScript($onloadScript); <head> <?php echo $this->headScript(); ?> </head> Didn't really work, but anyway, I'm wanting to just add the script and not add it as an external file. How do I do that? Thanks!

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  • How to retrieve an url parameter in the Zend Framework ?

    - by ismaelsow
    Hello guys ! I'am trying to retrieve an parameter passed in a url using the zend framework. But of course, it is not working ! My code looks like this : Generating the url : <?php echo $this->url(array('controller' => 'poll', 'action' => 'showresults', 'poll_id' => $poll['_id']), null, true) ?> Retrieving the "poll_id" parameter in showresultsAction() : $request = new Zend_Controller_Request_Http(); $poll_id = $request->getParam('poll_id'); The problem is that $poll_id is NULL. When I do a var_dump of $request-getParams(), it is also NULL. I have glanced trough the Zend Framework doc, but it was not very usefull. Any idea ? Thanks !

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  • Apache refusing to change DocumentRoot

    - by mingos
    I've installed Zend Server CE 5.1.0 on Windows 7 Ultimate 64 bit in its default location, meaning the path to my htdocs is C:\Program Files (x86)\Zend\Apache2\htdocs. Not something that I would like to type each time I check out a project from SVN in Eclipse or something. I'd like to set the DocumentRoot to a different folder, namely D:\www. What I've done I edited conf/httpd.conf, with the significant lines being: DocumentRoot "D:\www" <Directory "D:\www"> Options Indexes FollowSymLinks AllowOverride All Order allow,deny Allow from all </Directory> Include conf/extra/httpd-vhosts.conf I edited conf/extra/httpd-vhosts.conf to add a virtual host: NameVirtualHost *:80 <VirtualHost *:80> DocumentRoot D:\www ServerName localhost ServerAlias localhost SetEnv APPLICATION_ENV development SetEnv APPLICATION_DOMAIN localhost </VirtualHost> <VirtualHost *:80> DocumentRoot D:\www\UmbraCMS ServerName umbracms.local ServerAlias umbracms.local SetEnv APPLICATION_ENV development SetEnv APPLICATION_DOMAIN umbracms.local </VirtualHost> I edited C:\Windows\System32\drivers\etc\hosts to add this line: 127.0.0.1 umbracms.local And I also added a PHP project to D:\www\UmbraCMS. And restarted Apache. Actually, I restarted the computer, too, just in case. What's supposed to happen After typing http://umbracms.local/ in the browser's address bar, I want to see my PHP project launch, obviously. What's actually happening No matter whether whether I type http://umbracms.local/ or http://localhost/, I'm taken to the test zend page, located in C:\Program Files (x86)\Zend\Apache2\htdocs\index.html, as if neither DocumentRoot was changed nor name-based virtual hosting worked. Interestingly, when I put another project in C:\Program Files (x86)\Zend\Apache2\htdocs\bugraid\ and then, in the browser, typed http://localhost/bugraid, the project actually opened, or at least tried to, as it completely ignored the project's .htaccess file. Extra considerations Zend Server's Apache version is 2.2.16, PHP version is 5.3.0 I've installed MySQL CE 5.5.13 separately, and it works, both from command line and via MySQL Workbench. I have XAMPP installed, but none of its components are started up. It's got its own install of Apache 2.2.17 and MySQL 5.5.1. PHP version is 5.3.5 (I think). Question Have you had a similar situation before? What else might need taking care of in order to have Zend Server's Apache use D:\www as document root for my PHP projects?

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  • Compiling Gearman extension for PHP on OS-X Snow Leopard with Zend Server Community Edition

    - by GrumpyCanuck
    I was wondering if anyone else has figured out how to solve this problem. Whether I install the extension via PECL or compile it by hand, I get the same error: PHP Warning: PHP Startup: Unable to load dynamic library '/usr/local/zend/lib/php_extensions/gearman.so' - dlopen(/usr/local/zend/lib/php_extensions/gearman.so, 9): no suitable image found. Did find: /usr/local/zend/lib/php_extensions/gearman.so: mach-o, but wrong architecture in Unknown on line 0 I have no idea how to fix this problem and I can only bang my head into my desk so many times.

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