Why is n given the initial value of 1 in this loop?
- by notypist
From Kochan's "Programming in C":
Input:
printf ("TABLE OF TRIANGULAR NUMBERS\n\n");
printf (" n Sum from 1 to n\n");
printf ("--- ---------------\n");
triangularNumber = 0;
for(n=1; n<=10; ++n){
triangularNumber += n;
? printf (" %i", n);
}
Output (only partly pasted):
TABLE OF TRIANGULAR NUMBERS
n = 1
Sum from 1 to n = 1
n = 2
Sum from 1 to n = 2
Question:
I understand the purpose of this, but here's what I can't get my head around: If within the loop we assign an initial value of "1" to "n", then we check if n<=10, and if that's true (which it should be with the initial value), we then add "1" to n. Shouldn't (and I know it shouldn't, just don't understand why) the initial value displayed in our table be n=2 ?
Thanks in advance for your patience and effort!
