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  • The weirdest css issue I have ever seen

    - by jasondavis
    Below I have 2 css codes for a div, please note that the first one does not even have a div on the page or ANYTHING with it's name on it. I can also rename it to anything. Now where the weird part comes in. The second bit of code below has a width of 520px, the only way that the div on the page will be 520px is if I leave the css code thats above that one, the 1st one with no existing div on the page HAS to be on the page for the second css code to work, At first I thought it has to be a browser caching issue, so I clear my cache and that does nothing, I then try 2 other browsers and they all have the same result. I add the 1st bit of code into the page and the second bit works, I take the first bit away and the second bit does not work. AM i overlooking something here? .commentwrappsdfsde2{width:950px;margin:0 0;padding:0;} .commentwrapper{width:520px;margin-right:auto;margin-left:auto;} Here is the whole page code <style> <!-- css for user photos--> div.imageSub img.female { border-top: 1px solid #FF3399; } div.imageSub img.male { border-top: 1px solid #3399FF; } div.imageSub img { z-index: 1; margin: 0; display: block; } div.imageSub div { position: relative; margin: -15px 0 0; padding: 5px; height: 5px; line-height: 4px; text-align: center; overflow: hidden; font-family:Trebuchet MS,Helvetica,sans-serif; font-size:12px; font-weight: bold; } div.imageSub div.blackbg { z-index: 2; background-color: #000; -ms-filter: "progid:DXImageTransform.Microsoft.Alpha(Opacity=70)"; filter: alpha(opacity=70); opacity: 0.5; } div.imageSub div.label { z-index: 3; color: white; } <!-- end photo block--> /* Comments */ .commentwrappsdfsde2{width:950px;margin:0 0;padding:0;} .commentwrapper{width:520px;margin-right:auto;margin-left:auto;} #comments ol.commentlist li { list-style-type:none; padding:20px; background:none; } #comments ol.commentlist li.thread-even { background:#f6f6f6; border-top:1px solid #e3e3e3; border-bottom:1px solid #e3e3e3; } #comments ul.children li ul.children,#comments .commentlist{padding:0;} </style> <div class="commentwrapper"> <div id="comments"> <ol class="commentlist"> <li class="comment thread-even " > Comment 1 </li> </ol> </div> </div>

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  • css sticky footer without scrolbar

    - by massinissa
    How to do to avoid having the scroller with a sticky footer to the bottom of the page (not bottom of window)? When I remove height=100% from content and sidebar, I'm no more getting the scroller. However, when doing so, my content and sidebar do not fill all the space down to the footer. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>Untitled 13</title> <style media="all" type="text/css"> * { margin: 0; padding: 0; } html, body, #wrap, form { height: 100%; } #wrap, #footer { width: 750px; margin: 0 auto; } #wrap { background: #cff; } html, body { color: #000; background: #a7a09a; } body > #wrap { height: 100%; min-height: 100%; } form { /*height: auto;*/ min-height: 100%; } #main { background: #000; height:100%; min-height:100%; height: auto !important; */ } #content { height:100%; float: left; padding: 10px; float: left; width: 570px; background: #9c9; } #sidebar { height:100%; float: left; width: 140px; background: #c99; padding: 10px; } #footer { position: relative; margin-top: -100px; height: 100px; clear: both; background: #cc9; bottom: 0; } .clearfix:after { content: "."; display: block; height: 0; clear: both; visibility: hidden; } .clearfix { display: inline-block; } * html .clearfix { height: 1%; } .clearfix { display: block; } #header { /*padding: 5px 10px;*/ background: #ddd; } </style> </head> <body> <form id="form1" runat="server"> <div id="wrap"> <div id="main" class="clearfix"> <div id="header"> <h1>header</h1> </div> <div id="sidebar"> <h2>sidebar</h2> </div> <div id="content"> <h2>main content</h2> </div> </div> </div> <div id="footer"> <h2>footer</h2> </div> </form> </body> </html>

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  • What precautions should you take when a senior employee leaves?

    - by Mahin
    EDIT : I agree one should check the reasons, why a senior level employee is leaving. But I am interested in knowing the official/management/technical/legal steps one should take after its decided that he is leaving, so that the life after him is smooth. What are the steps management should take when a senior programmer/team lead leaves your company. Some of them which I have thought about are : 1) If He used to manage hosting and domains stuff, change passwords of domain control panels and hosting panels. 2) If your published web sites have maintenance account and he is aware of credentials of that account then change this details also. 3) Suspend mail account for some time and forward all eMails of that account to some ex-employee account. After some time close that account. What are the other things one should check. I am expecting the answer to be a general check list one should follow. It should include both technical scenarios and management scenarios. Notable Suggestions so far : Effectively transfer the responsibilities of that employee to another one without causing any potential delay in your work. Protect your source code. If possible Make them to sign something to say that they don't have copies of source code.. You can also consider NDA here. Use the Notice Period to train his replacement. Now any new code to the project will be done by replacement with the help of Guy who is leaving. Ask him to create a document of things he thinks you should know. Make sure he checks everything in now and then any checkout will only be done by the replacement. Emails, copy off his email account to a pst.file (this assumes Outlook), Make this file available to his replacement. the employee should probably be given a chance to scrub the email. if you are going to keep his account open for whatever reason, check that no rules are created that forward incoming emails to an alternate address. Copy the hard drive of his computer to a network location and have someone senior go through and see if there are any files (drafts of performance reviews or other sensitive issues ) on it that someone else might need. Clearance from Accounts,Finance,Security,Library etc departments.Obtain all company property, laptops, keys, etc. If there is no reason not to, you should reward a departing person for their many years of service. Write them letters of recommendation (even if they already have a new job lined up).Say goodbye, and keep the door open. Make sure any outside clients know that the departing employee is not their main contact anymore. Never neglect the exit interview/debriefing. Confirm the last day of employment so that there is no misunderstanding Inform H/R if the employee is on H1B status, there is paperwork required to notify the government when an H1B employee leaves. Depending on how senior / what position, you might spend some time convincing him not to take the rest of the engineering staff with him. Make sure he spends his last days on a good note, because if he is not leaving on a good note, he can easily pollute the mind of his colleagues. Best Regards, Mahin Gupta EDIT : Now offered a bounty on it to get more detailed responses and practical suggestions.

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  • UIButtons in UIScrollView stop it scrolling, how to fix?

    - by Mark McFarlane
    Hi all, I have a problem with adding a set of UIButtons to a UIScrollView. With the buttons added it seems that the scroll command is not being passed to the scroll view as the buttons cover the whole surface. I've read various posts on this but still can't figure it out. I'm pretty new to iPhone programming so there's probably something obvious I've missed. I've tried things like canCancelContentTouches and delaysContentTouches to TRUE and FALSE. Here is the code I use to add the buttons to the scrollview. The scrollview was created in IB and is passed in to the function: -(void)drawCharacters:(NSMutableArray *)chars:(UIScrollView *)target_view { //NSLog(@"CLEARING PREVIOUS BUTTONS"); //clear previous buttons for parts/kanji if(target_view == viewParts){ for (UIButton *btn in parts_buttons) { [btn removeFromSuperview]; } [parts_buttons removeAllObjects]; } else if(target_view == viewKanji){ for (UIButton *btn in kanji_buttons) { [btn removeFromSuperview]; } [kanji_buttons removeAllObjects]; } //display options int chars_per_line = 9; //change this to change the number of chars displayed on each line if(target_view == viewKanji){ chars_per_line = 8; } int char_gap = 0; //change this to change the margin between chars int char_dimensions = (320/chars_per_line)-(char_gap*2); //set starting x, y coords int x = 0, y = 0; //increment y coord y += char_gap; //NSLog(@"ABOUT TO DRAW FIRST BUTTON"); for(NSMutableArray *char_arr in chars){ //increment x coord x += char_gap; //draw at x and y UIButton *myButton = [UIButton buttonWithType:UIButtonTypeCustom]; myButton.frame = CGRectMake(x, y, char_dimensions, char_dimensions); // position in the parent view and set the size of the button [myButton setTitle:[char_arr objectAtIndex:0] forState:UIControlStateNormal]; [myButton setTitleColor:[UIColor darkGrayColor] forState:UIControlStateNormal]; [myButton setTitleColor:[UIColor colorWithRed:0.8 green:0.8 blue:0.8 alpha:1.0] forState:UIControlStateDisabled]; myButton.titleLabel.font = [UIFont boldSystemFontOfSize:22]; if(target_view == viewKanji){ myButton.titleLabel.font = [UIFont boldSystemFontOfSize:30]; } // add targets and actions if(target_view == viewParts){ [myButton addTarget:self action:@selector(partSelected:) forControlEvents:UIControlEventTouchUpInside]; } else if(target_view == viewKanji){ [myButton addTarget:self action:@selector(kanjiSelected:) forControlEvents:UIControlEventTouchUpInside]; [myButton setTag:(int)[char_arr objectAtIndex:1]]; } //if the part isnt in the current list of kanji, disable and dim it if(target_view == viewParts){ if([kanji count] > 0){ [myButton setEnabled:NO]; } bool do_break = NO; for(NSMutableArray *arr in kanji){ //NSLog([NSString stringWithFormat:@"CHECKING PARTS AGAINST %d KANJI", [kanji count]]); for(NSString *str in [[arr objectAtIndex:2] componentsSeparatedByString:@" "]){ if(([myButton.titleLabel.text isEqualToString:str])){ //NSLog(@"--------------MATCH!!!-----------------"); [myButton setEnabled:YES]; for(NSString *str1 in parts_selected){ if(([myButton.titleLabel.text isEqualToString:str1])){ [myButton setEnabled:NO]; break; } } do_break = YES; break; } if(do_break) break; } if(do_break) break; } } // add to a view [target_view addSubview:myButton]; //update coords of next button x += char_dimensions+ char_gap; if (x > (320-char_dimensions)) { x = 0; y += char_dimensions + (char_gap*2); } //add button to global array to be removed from view next update if(target_view == viewParts){ [parts_buttons addObject:myButton]; } else if(target_view == viewKanji){ [kanji_buttons addObject:myButton]; } } //NSLog(@"FINISHED DRAWING ALL BUTTONS"); } Any help on this would be greatly appreciated. I just need to fix this to finish my app.

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  • Xcode/iPhone Development 6 months in - Annoyances

    - by clearbrian
    Hi I've been iPhone programming for 6 months and come from a PC/Java/Eclipse background and still have a few annoyances with Xcode/iPhone programming I wonder are there any shortcuts to. Is there any way to prevent multiple windows opening all the time in XCode? a) When you click on the Errors/Warnings in the bottom right of the status bar build errors are shown in separate window. Any way to get these to show in the main editor? b) Anyway to get debugger to appear in main editor. I have a big screen iMac and it's still window hell on Macs. When you come from Alt-Tab the Mac is a nightmare. 2) Anyway to get a toolbar item on the main editor to: a) Open Console (I know CMD-thingy-R) b) Open Break points (you have to open Debugger first then breakpoints) I know there's keyboard shortcuts but I have only left hand free others on the trackball so any keys on right hand side of keyboard are too far. I know you can add Finder toolbar scripts (just wondering if anyway to extend Xcode). Are there utilities to extend Xcode? Scripts/Automator/Any Services I can setup to help. Can you automate Xcode like you can with Windows/ActiveX/VBA 3) Limit lookups using CMD + double click. If I double click on a variable to find its definition using CMD + double click it shows every occurrence of all variables with that name. (annoying it you name all you maps mapView) Anyway to get it to limit to the current class or at least order so current class is first. 4) Find doesn't seem to loop backwards if result all above cursor position I'm in a class and I hit CMD + F for find. Find box appears. I enter some text hit return. It says I have x matches but only back arrow is highlight in Find But when I hit < it does nothing. I need to scroll to the top and redo the search. If the text is both forwards and backwards then both < are highlighted and it works. is this a bug or a 'feature' Missing Eclipse features I have been looking at the User Script menu but was wondering how powerful they are? 5) any scripts around to generate source from members such as description: @property @synthesize if I add a new member, run a script will generate @property/@syntesize and release in dealloc 7) any good sites for scripts? SCM Im having problems with SCM and Folders on HD under project Classes directory. You get a library e.g. JSON. It usually comes as a folder. You copy it to the /Classes for your project. /Classes/JSON I create a Group for the Library in Xcode under Classes group. Classes JSON I drag the files from the folder into xcode into the JSON Group. I add them to the SCM and icon changes from ? to A but if I try and commit them it say folder /JSON is not under SCM. Can you drag a folder into Xcode so that it AND its files get included in SCM? Anyway to stop Xcode Help from being on top all the time. I keep feeling like punching it and telling it to get out of the way! :) I dont mind it open just not in the way once I've finished. Yes I know I can Ctrl-W Sites: the main site I use to learn Obj-C are : stackoverflow.com Google code Search - tonnes of full apps on here http://www.iphonedevsdk.com/forum/iphone-sdk-development/ Apple Developers Forums (anyway to get RSS feed to these or is that blasphemy :) ) Safari - 100s of IT book though prob too many to keep up :) any others? Any site that gives simple examples for Obj-C/ UIKit The docs just show the methods but actual examples (Google code search has helped a lot here)

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  • Panning Image Using Javascript in ASP.Net Page Overflows Div

    - by Bob Mc
    I have an ASP.Net page that contains a <div> with an <img> tag within. The image is large so the <div> is set with a size of 500x500 pixels with overflow set to scroll. I'm attempting to add image panning using a click and drag on the image. However, every time I begin dragging the image escapes the boundary of the element and consumes the entire page. Here is example code that illustrates the problem: <%@ Page Language="VB" AutoEventWireup="false" CodeFile="Default.aspx.vb" Inherits="_Default" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body> <form id="form1" runat="server"> <div> <div id="divInnerDiv" style="overflow:scroll; width:500px; height:500px; cursor:move;"> <img id="imgTheImage" src="Page0001.jpg" border="0" /> </div> <script type="text/javascript"> document.onmousemove = mouseMove; document.onmouseup = mouseUp; var dragObject = null; var mouseOffset = null; function mouseCoords(ev){ if(ev.pageX || ev.pageY){ return {x:ev.pageX, y:ev.pageY}; } return { x:ev.clientX + document.body.scrollLeft - document.body.clientLeft, y:ev.clientY + document.body.scrollTop - document.body.clientTop }; } function getMouseOffset(target, ev){ ev = ev || window.event; var docPos = getPosition(target); var mousePos = mouseCoords(ev); return {x:mousePos.x - docPos.x, y:mousePos.y - docPos.y}; } function getPosition(e){ var left = 0; var top = 0; while (e.offsetParent){ left += e.offsetLeft; top += e.offsetTop; e = e.offsetParent; } left += e.offsetLeft; top += e.offsetTop; return {x:left, y:top}; } function mouseMove(ev) { ev = ev || window.event; var mousePos = mouseCoords(ev); if(dragObject){ dragObject.style.position = 'absolute'; dragObject.style.top = mousePos.y - mouseOffset.y; dragObject.style.left = mousePos.x - mouseOffset.x; return false; } } function mouseUp(){ dragObject = null; } function makeDraggable(item){ if(!item) return; item.onmousedown = function(ev){ dragObject = this; mouseOffset = getMouseOffset(this, ev); return false; } } makeDraggable(document.getElementById("imgTheImage")); </script> </div> </form> </body> </html> Also note that this HTML works fine in a non-ASP.Net page. Is there something in the ASP.Net Javascript that is causing this issue? Does anyone have a suggestion for panning a JPEG within a <div> block that will work in ASP.Net? I have tried using the jQueryUI library but the result is the same.

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  • adv. styling list with css

    - by Ayrton
    Hi I need to style a regular html list like the following picture: as you see each each list item has a padding on the sides and a top&bottom border. When hovered the border has a width of 100% of the <ul> item. Now the problem actually is: when you give each <li> element a top & bottom border I have a border of 2 px between each element (bottom border from the first element and the top border from the second element), I don't want that however I do not know any solution for this. my html: <div id="tab_top" class="tab"> <div class="bottom"> <div class="cont"> <ul> <li><a href="#">Here’s a Sample Post <span class="ct">32</span></a></li> <li><a href="#">Here’s a Sample Post <span class="ct">32</span></a></li> <li><a href="#">Here’s a Sample Post <span class="ct">32</span></a></li> <li><a href="#">Here’s a Sample Post <span class="ct">32</span></a></li> <li><a href="#">Here’s a Sample Post <span class="ct">32</span></a></li> <li><a href="#">Here’s a Sample Post <span class="ct">32</span></a></li> <li><a href="#">Here’s a Sample Post <span class="ct">32</span></a></li> </ul> </div> </div> </div> my css: #tabs .tab div.cont ul li a{line-height:30px; height:30px; color:#3ca097; display:block; padding-left:11px; padding-right:13px; width:259px;} #tabs .tab div.cont ul li a span.ct{float:right;background:url(images/count_comments.gif) no-repeat left top; height:13px; padding-left:16px; margin-top:10px; line-height:12px;} #tabs .tab div.cont ul li a:hover{color:#fff; background-color:#6fd2c8; border-top:1px solid #7db9b2; border-bottom:1px solid #7db9b2; height:28px; line-height:28px;} #tabs .tab div.cont ul li a:hover span.ct{background-position:left bottom; color:#23665f; margin-top:9px;} I would be pleased if you can help me Yours truthfully

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  • XSLT: look for a word and it's context

    - by farhad
    Hello! I need to search a word and it's context into an xml. For example <line>hello world, my name is farhad and i'm having trouble with xslt</line> looking for 'and', context of 3 words: <line>hello world, my <span class="context">name is farhad <span class="word">and</span> i'm having</span> trouble with xslt</line> How can i do? I wrote some xslt to find the word, but i can't go back 3 words to set span. This is my xslt: <xsl:variable name="delimiters">[,.;!?\s"()]+</xsl:variable> <xsl:template match="/"> <xsl:apply-templates select="//line"/> </xsl:template> <xsl:template match="line"> <line> <xsl:for-each select="tokenize(.,'\s')"> <xsl:choose> <!-- se l'ultimo carattere è di punteggiatura, prendo la sottostringa senza la punteggiatura --> <xsl:when test="compare(replace(.,$delimiters,'$1'),'red') = 0"> <span class="word"> <xsl:value-of select="."/> </span> </xsl:when> <xsl:otherwise> <xsl:value-of select="."/> <xsl:choose> <xsl:when test="position()=last()"> <xsl:text></xsl:text> </xsl:when> <xsl:otherwise> <xsl:text> </xsl:text> </xsl:otherwise> </xsl:choose> </xsl:otherwise> </xsl:choose> </xsl:for-each> </line><xsl:text> </xsl:text> </xsl:template> This is an example xml: http://pastebin.com/eAVM9CDQ . I have to search for context also on preceding tags, for example: <line>hello world,</line> <line>my name</line> <line>is farhad </line> <line>and i'm having</line> <line>trouble with xslt</line> so, looking for 'and', context of 3 words: <line>hello world,</line> <line>my <span class="context">name</line> <line>is farhad </line> <line><span class="word">and</span> i'm having</span></line> <line>trouble with xslt</line> with problems of overlapping, but now it's not a problem (i think i know how manage it). How can i search a word and its context? Thank you very much.

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  • HTML: Place an image on top of another one

    - by Dimitris Baltas
    Inside a div, there is a picture that should have 10px margin in all directions from the DIV's border. On the left bottom corner of the picture there is an about-image. The picture is only displayed when its loaded in the DOM through jquery. The problem is that the existence of the about-image dislocates the picture downwards as many pixels as the height of the about-image. I am looking for the cleanest possible alternative to keep the picture inside the DIV and still display the about-image on top of it. Setting the picture as background will not work since i need the picture to load at once. Any improvement on the #about css would be greatly appreciated. Below is a full html page that reproduces the issue <html> <head> <title>Troubleshooting :: align the main picture inside the DIV</title> <style type="text/css"> html, body { background-color: #000000; } #about { z-index:2; position:relative; top:82%; left:3%; } #pic { width:100%; height:96%; } #main-content-image { height:100%; margin-right:10px; margin-left:10px; margin-top:10px; margin-bottom:10px; } #main-content { height:490px; border-width: 1px; border-style: solid; border-color: #777777; } #main-content-image.loading { background: url(http://farros.gr/images/ajax-loader2.gif) no-repeat center center; } a { text-decoration: none; text-decoration: none; color: #868686; outline:none; } .hide { display:none; } </style> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> <script type="text/javascript"> <!-- $(document).ready(function(){ $(function () { var img = new Image(); $(img).load(function () { $(this).hide(); $(this).width('100%'); $(this).height('96%'); $('#main-content-image').removeClass('loading').append(this); $(this).fadeIn(); }).error(function () { // notify the user that the image could not be loaded }).attr('src', 'http://farros.gr/images/bg.jpg'); }); }); </script> </head> <body> <div id="main-content"> <div id="main-content-image" class="loading"> <a href="#"><img id="about" src='http://farros.gr/images/about.png' alt='Haris Farros'/></a> </div> </div> </body> </html>

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  • Improving the performance of XSL

    - by Rachel
    In the below XSL for the variable "insert-data", I have an input param with the structure, <insert-data> <data compareIndex="4" nodeName="d1e1"> <a/> </data> <data compareIndex="5" nodeName="d1e1"> <b/> </data> <data compareIndex="7" nodeName="d1e2"> <a/> </data> <data compareIndex="9" nodeName="d1e2"> <b/> </data> </insert-data> where "nodeName" is the id of a node and "compareIndex" is the position of the text content relative to the node having id "$nodeName". I am using the below XSL to select all the text nodes(generate-id) that satisfy the above condition and construct a data xml. The below implementation works perfectly but the time taken for the execution is in min. Is there a better way of implementing or is there any in-efficient operation being used. From my observation the code where the preceding text length is calculated consumes the major time. Please share your thoughts to improve the performance of the XSL. I am using Java SAXON XSL transformer. <xsl:variable name="insert-data" as="element()*"> <xsl:for-each select="$insert-file/insert-data/data"> <xsl:sort select="xsd:integer(@index)"/> <xsl:variable name="compareIndex" select="xsd:integer(@compareIndex)" /> <xsl:variable name="nodeName" select="@nodeName" /> <xsl:variable name="nodeContent" as="node()"> <xsl:copy-of select="node()"/> </xsl:variable> <xsl:for-each select="$main-root/*//text()[ancestor::*[@id = $nodeName]]"> <xsl:variable name="preTextLength" as="xsd:integer" select="sum((preceding::text())[. ancestor::*[@id = $nodeName]]/string-length(.))" /> <xsl:variable name="currentTextLength" as="xsd:integer" select="string-length(.)" /> <xsl:variable name="sum" select="$preTextLength + $currentTextLength" as="xsd:integer"></xsl:variable> <xsl:variable name="split-index" select="$compareIndex - $preTextLength" as="xsd:integer"></xsl:variable> <xsl:if test="($sum ge $compareIndex) and ($compareIndex gt $preTextLength)"> <data split-index="{$split-index}" text-id="{generate-id(.)}"> <xsl:copy-of select="$nodeContent"/> </data> </xsl:if> </xsl:for-each> </xsl:for-each> </xsl:variable>

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  • Help to solve "Robbery Problem"

    - by peiska
    Hello, Can anybody help me with this problem in C or Java? The problem is taken from here: http://acm.pku.edu.cn/JudgeOnline/problem?id=1104 Inspector Robstop is very angry. Last night, a bank has been robbed and the robber has not been caught. And this happened already for the third time this year, even though he did everything in his power to stop the robber: as quickly as possible, all roads leading out of the city were blocked, making it impossible for the robber to escape. Then, the inspector asked all the people in the city to watch out for the robber, but the only messages he got were of the form "We don't see him." But this time, he has had enough! Inspector Robstop decides to analyze how the robber could have escaped. To do that, he asks you to write a program which takes all the information the inspector could get about the robber in order to find out where the robber has been at which time. Coincidentally, the city in which the bank was robbed has a rectangular shape. The roads leaving the city are blocked for a certain period of time t, and during that time, several observations of the form "The robber isn't in the rectangle Ri at time ti" are reported. Assuming that the robber can move at most one unit per time step, your program must try to find the exact position of the robber at each time step. Input The input contains the description of several robberies. The first line of each description consists of three numbers W, H, t (1 <= W,H,t <= 100) where W is the width, H the height of the city and t is the time during which the city is locked. The next contains a single integer n (0 <= n <= 100), the number of messages the inspector received. The next n lines (one for each of the messages) consist of five integers ti, Li, Ti, Ri, Bi each. The integer ti is the time at which the observation has been made (1 <= ti <= t), and Li, Ti, Ri, Bi are the left, top, right and bottom respectively of the (rectangular) area which has been observed. (1 <= Li <= Ri <= W, 1 <= Ti <= Bi <= H; the point (1, 1) is the upper left hand corner, and (W, H) is the lower right hand corner of the city.) The messages mean that the robber was not in the given rectangle at time ti. The input is terminated by a test case starting with W = H = t = 0. This case should not be processed. Output For each robbery, first output the line "Robbery #k:", where k is the number of the robbery. Then, there are three possibilities: If it is impossible that the robber is still in the city considering the messages, output the line "The robber has escaped." In all other cases, assume that the robber really is in the city. Output one line of the form "Time step : The robber has been at x,y." for each time step, in which the exact location can be deduced. (x and y are the column resp. row of the robber in time step .) Output these lines ordered by time . If nothing can be deduced, output the line "Nothing known." and hope that the inspector will not get even more angry. Output a blank line after each processed case.

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  • WCF: Configuring Known Types

    - by jerbersoft
    I want to know as to how to configure known types in WCF. For example, I have a Person class and an Employee class. The Employee class is a sublass of the Person class. Both class are marked with a [DataContract] attribute. I dont want to hardcode the known type of a class, like putting a [ServiceKnownType(typeof(Employee))] at the Person class so that WCF will know that Employee is a subclass of Person. Now, I added to the host's App.config the following XML configuration: <?xml version="1.0" encoding="utf-8" ?> <configuration> <system.runtime.serialization> <dataContractSerializer> <declaredTypes> <add type="Person, WCFWithNoLibrary, Version=1.0.0.0,Culture=neutral,PublicKeyToken=null"> <knownType type="Employee, WCFWithNoLibrary, Version=1.0.0.0,Culture=neutral, PublicKeyToken=null" /> </add> </declaredTypes> </dataContractSerializer> </system.runtime.serialization> <system.serviceModel> ....... </system.serviceModel> </configuration> I compiled it, run the host, added a service reference at the client and added some code and run the client. But an error occured: The formatter threw an exception while trying to deserialize the message: There was an error while trying to deserialize parameter http://www.herbertsabanal.net:person. The InnerException message was 'Error in line 1 position 247. Element 'http://www.herbertsabanal.net:person' contains data of the 'http://www.herbertsabanal.net/Data:Employee' data contract. The deserializer has no knowledge of any type that maps to this contract. Add the type corresponding to 'Employee' to the list of known types - for example, by using the KnownTypeAttribute attribute or by adding it to the list of known types passed to DataContractSerializer.'. Please see InnerException for more details. Below are the data contracts: [DataContract(Namespace="http://www.herbertsabanal.net/Data", Name="Person")] class Person { string _name; int _age; [DataMember(Name="Name", Order=0)] public string Name { get { return _name; } set { _name = value; } } [DataMember(Name="Age", Order=1)] public int Age { get { return _age; } set { _age = value; } } } [DataContract(Namespace="http://www.herbertsabanal.net/Data", Name="Employee")] class Employee : Person { string _id; [DataMember] public string ID { get { return _id; } set { _id = value; } } } Btw, I didn't use class libraries (WCF class libraries or non-WCF class libraries) for my service. I just plain coded it in the host project. I guess there must be a problem at the config file (please see config file above). Or I must be missing something. Any help would be pretty much appreciated.

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  • How to manage a MotionEvent going from one View to another?

    - by Darren
    I have a SurfaceView that takes up part of the screen, and some buttons along the bottom. When a button is pressed and the user drags, I want to be able to drag a picture (based on the button) onto the SurfaceView and have it drawn there. I want to be able to use clickListeners and the like, and not just have a giant SurfaceView with me writing code to detect where the user pressed and if it's a button, etc. I have somewhat of a solution, but it seems a bit of a hack to me. What is the best way to accomplish this using the framework intelligently? Part of my XML: <RelativeLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@drawable/background"> <!-- Place buttons along the bottom --> <RelativeLayout android:id="@+id/bottom_bar" android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="40dip" android:layout_alignParentBottom="true" android:background="@null"> <ImageButton android:id="@+id/btn_1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_centerVertical="true" android:background="@null" android:src="@drawable/btn_1"> </ImageButton> <!-- More buttons here... --> </RelativeLayout> <!-- Place the SurfaceView in a frame so we can stack on top of it --> <FrameLayout android:layout_width="fill_parent" android:layout_height="0px" android:layout_weight="1" android:layout_above="@id/bottom_bar"> <com.project.question.MySurfaceView android:id="@+id/my_view" android:layout_width="fill_parent" android:layout_height="fill_parent" /> </FrameLayout> And the relevant Java code in MySurfaceView, which extends SurfaceView. mTouchX and Y are used in the onDraw method to draw the image: @Override public boolean onTouchEvent(MotionEvent event){ mTouchX = (int) event.getX(); mTouchY = (int) event.getY(); return true; } public void onButtonTouchEvent(MotionEvent event){ event.setLocation(event.getX(), event.getY() + mScreenHeight); onTouchEvent(event); } Finally, the activity: @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); requestWindowFeature(Window.FEATURE_NO_TITLE); setContentView(R.layout.my_surface); mView = (MySurfaceView) findViewById(R.id.my_view); mSurfaceHeight = mView.getHeight(); mBtn = (ImageButton) findViewById(R.id.btn_1); mBtn.setOnTouchListener(mTouchListener); } OnTouchListener mTouchListener = new OnTouchListener() { public boolean onTouch(View v, MotionEvent event) { int [] location = new int[2]; v.getLocationOnScreen(location); event.setLocation(event.getX() + location[0], event.getY()); mView.onButtonTouchEvent(event); return true; } }; Strangely, one has to add to the x-coordinate in the activity, then add to the y coordinate in the View. Otherwise, it doesn't show up in the correct position. If you add nothing, something drawn using mTouchX and mTouchY will show up in the upper left corner of the SurfaceView. Any direction would be greatly appreciated. If I'm going about this completely the wrong way, that would be good information too.

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  • Clipplanes, vertex shaders and hardware vertex processing in Direct3D 9

    - by Igor
    Hi, I have an issue with clipplanes in my application that I can reproduce in a sample from DirectX SDK (February 2010). I added a clipplane to the HLSLwithoutEffects sample: ... D3DXPLANE g_Plane( 0.0f, 1.0f, 0.0f, 0.0f ); ... void SetupClipPlane(const D3DXMATRIXA16 & view, const D3DXMATRIXA16 & proj) { D3DXMATRIXA16 m = view * proj; D3DXMatrixInverse( &m, NULL, &m ); D3DXMatrixTranspose( &m, &m ); D3DXPLANE plane; D3DXPlaneNormalize( &plane, &g_Plane ); D3DXPLANE clipSpacePlane; D3DXPlaneTransform( &clipSpacePlane, &plane, &m ); DXUTGetD3D9Device()->SetClipPlane( 0, clipSpacePlane ); } void CALLBACK OnFrameMove( double fTime, float fElapsedTime, void* pUserContext ) { // Update the camera's position based on user input g_Camera.FrameMove( fElapsedTime ); // Set up the vertex shader constants D3DXMATRIXA16 mWorldViewProj; D3DXMATRIXA16 mWorld; D3DXMATRIXA16 mView; D3DXMATRIXA16 mProj; mWorld = *g_Camera.GetWorldMatrix(); mView = *g_Camera.GetViewMatrix(); mProj = *g_Camera.GetProjMatrix(); mWorldViewProj = mWorld * mView * mProj; g_pConstantTable->SetMatrix( DXUTGetD3D9Device(), "mWorldViewProj", &mWorldViewProj ); g_pConstantTable->SetFloat( DXUTGetD3D9Device(), "fTime", ( float )fTime ); SetupClipPlane( mView, mProj ); } void CALLBACK OnFrameRender( IDirect3DDevice9* pd3dDevice, double fTime, float fElapsedTime, void* pUserContext ) { // If the settings dialog is being shown, then // render it instead of rendering the app's scene if( g_SettingsDlg.IsActive() ) { g_SettingsDlg.OnRender( fElapsedTime ); return; } HRESULT hr; // Clear the render target and the zbuffer V( pd3dDevice->Clear( 0, NULL, D3DCLEAR_TARGET | D3DCLEAR_ZBUFFER, D3DCOLOR_ARGB( 0, 45, 50, 170 ), 1.0f, 0 ) ); // Render the scene if( SUCCEEDED( pd3dDevice->BeginScene() ) ) { pd3dDevice->SetVertexDeclaration( g_pVertexDeclaration ); pd3dDevice->SetVertexShader( g_pVertexShader ); pd3dDevice->SetStreamSource( 0, g_pVB, 0, sizeof( D3DXVECTOR2 ) ); pd3dDevice->SetIndices( g_pIB ); pd3dDevice->SetRenderState( D3DRS_CLIPPLANEENABLE, D3DCLIPPLANE0 ); V( pd3dDevice->DrawIndexedPrimitive( D3DPT_TRIANGLELIST, 0, 0, g_dwNumVertices, 0, g_dwNumIndices / 3 ) ); pd3dDevice->SetRenderState( D3DRS_CLIPPLANEENABLE, 0 ); RenderText(); V( g_HUD.OnRender( fElapsedTime ) ); V( pd3dDevice->EndScene() ); } } When I rotate the camera I have different visual results when using hardware and software vertex processing. In software vertex processing mode or when using the reference device the clipping plane works fine as expected. In hardware mode it seems to rotate with the camera. If I remove the call to RenderText(); from OnFrameRender then hardware rendering also works fine. Further debugging reveals that the problem is in ID3DXFont::DrawText. I have this issue in Windows Vista and Windows 7 but not in Windows XP. I tested the code with the latest NVidia and ATI drivers in all three OSes on different PCs. Is it a DirectX issue? Or incorrect usage of clipplanes? Thanks Igor

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  • python: what are efficient techniques to deal with deeply nested data in a flexible manner?

    - by AlexandreS
    My question is not about a specific code snippet but more general, so please bear with me: How should I organize the data I'm analyzing, and which tools should I use to manage it? I'm using python and numpy to analyse data. Because the python documentation indicates that dictionaries are very optimized in python, and also due to the fact that the data itself is very structured, I stored it in a deeply nested dictionary. Here is a skeleton of the dictionary: the position in the hierarchy defines the nature of the element, and each new line defines the contents of a key in the precedent level: [AS091209M02] [AS091209M01] [AS090901M06] ... [100113] [100211] [100128] [100121] [R16] [R17] [R03] [R15] [R05] [R04] [R07] ... [1263399103] ... [ImageSize] [FilePath] [Trials] [Depth] [Frames] [Responses] ... [N01] [N04] ... [Sequential] [Randomized] [Ch1] [Ch2] Edit: To explain a bit better my data set: [individual] ex: [AS091209M02] [imaging session (date string)] ex: [100113] [Region imaged] ex: [R16] [timestamp of file] ex [1263399103] [properties of file] ex: [Responses] [regions of interest in image ] ex [N01] [format of data] ex [Sequential] [channel of acquisition: this key indexes an array of values] ex [Ch1] The type of operations I perform is for instance to compute properties of the arrays (listed under Ch1, Ch2), pick up arrays to make a new collection, for instance analyze responses of N01 from region 16 (R16) of a given individual at different time points, etc. This structure works well for me and is very fast, as promised. I can analyze the full data set pretty quickly (and the dictionary is far too small to fill up my computer's ram : half a gig). My problem comes from the cumbersome manner in which I need to program the operations of the dictionary. I often have stretches of code that go like this: for mk in dic.keys(): for rgk in dic[mk].keys(): for nk in dic[mk][rgk].keys(): for ik in dic[mk][rgk][nk].keys(): for ek in dic[mk][rgk][nk][ik].keys(): #do something which is ugly, cumbersome, non reusable, and brittle (need to recode it for any variant of the dictionary). I tried using recursive functions, but apart from the simplest applications, I ran into some very nasty bugs and bizarre behaviors that caused a big waste of time (it does not help that I don't manage to debug with pdb in ipython when I'm dealing with deeply nested recursive functions). In the end the only recursive function I use regularly is the following: def dicExplorer(dic, depth = -1, stp = 0): '''prints the hierarchy of a dictionary. if depth not specified, will explore all the dictionary ''' if depth - stp == 0: return try : list_keys = dic.keys() except AttributeError: return stp += 1 for key in list_keys: else: print '+%s> [\'%s\']' %(stp * '---', key) dicExplorer(dic[key], depth, stp) I know I'm doing this wrong, because my code is long, noodly and non-reusable. I need to either use better techniques to flexibly manipulate the dictionaries, or to put the data in some database format (sqlite?). My problem is that since I'm (badly) self-taught in regards to programming, I lack practical experience and background knowledge to appreciate the options available. I'm ready to learn new tools (SQL, object oriented programming), whatever it takes to get the job done, but I am reluctant to invest my time and efforts into something that will be a dead end for my needs. So what are your suggestions to tackle this issue, and be able to code my tools in a more brief, flexible and re-usable manner?

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  • .animate question/help

    - by Josh
    So, I've built this navigation bar so far and I'm curious if it's even possible to achieve what I'm thinking. Currently, when you hover over each of the links they drop down (padding is increased). Now, what I'm curious in doing is if you hover over say "test1", test2-4 also drop with it but in the padding that has been created from the drop down, "test1" information shows up. Allowing the user to click or read whatever information is in there. Also, if the user would like to, they can move their mouse to test2 and everything would animate (opacity, this I can do I think) to whatever is in the test2 field, test3 doing the same and so on. I haven't had much success with this, I've created a completely separate panel before, but that didn't exactly work or I wasn't doing it correctly. Here is what I've been working on, ANY help would be appreciated! Thanks! <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <script type="text/javascript" src="jquery.js"></script> <script type="text/javascript"> $(function() { $("#nav li > a").hover(function() { $(this).stop().animate({paddingTop: "100px"}, 100); }, function() { $(this).stop().animate({paddingTop: "10px"}, 200); }); }); </script> <style type="text/css"> #nav { position: absolute; top: 0; left: 60px; padding: 0; margin: 0; list-style: none; } #nav li { display: inline; } #nav li a { float: left; display: block; color: #555; text-decoration: none; padding: 10px 30px; background-color: #d1d1d1; border-top: none; } </style> </head> <body> <div id="wrap"> <ul id="nav"> <li><a href="">test1</a></li> <li><a href="">test2</a></li> <li><a href="">test3</a></li> <li><a href="">test4</a></li> </ul> </div> </body> </html>

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  • Animated background image in a hidden <div> doesn't load or loads not animated

    - by Guanche
    Hello, I have spent the whole day trying to make a script which on "submit" hides the form and shows hidden with animated progress bar. The problem is that Internet Explorer doesn't show animated gif images in hidden divs. The images are static. I visited many websites and found a script which uses: document.getElementById(id).style.backgroundImage = 'url(/images/load.gif)'; Finally, my script works in Internet Explorer, Firefox, Opera but... Google Chrome doesn't display the image at all. I see only div text. After many tests I discovered the following: the only way to see the background image in Google Chrome is to include the same image somewhere in the page (outside of hidden div) with 1px dimensions: <img src="/images/load.gif" width="1" heigh="1" /> This did the trick but... after this dirty solution Microsoft Explorer for some reason shows the image as static again. So, my question is: is there any way how to force Gogle Chrome to show the image? Thanks. This is my script: <script language="JavaScript" type="text/javascript"> function ver (id, elementId){ if (document.getElementById('espera').style.visibility == "visible") { return false; }else{ var esplit = document.forms[0]['userfile'].value.split("."); ext = esplit[esplit.length-1]; if (document.forms[0]['userfile'].value == '') { alert('Please select a file'); return false; }else{ if ((ext.toLowerCase() == 'jpg')) { document.getElementById(id).style.position = 'absolute'; document.getElementById(id).style.display = 'inline'; document.getElementById(id).style.visibility = "visible"; document.getElementById(id).style.backgroundImage = 'url(/images/load.gif)'; document.getElementById(id).style.height = "100px"; document.getElementById(id).style.backgroundColor = '#f3f3f3'; document.getElementById(id).style.backgroundRepeat = "no-repeat"; document.getElementById(id).style.backgroundPosition = "50% 50%"; var element; if (document.all) element = document.all[elementId]; else if (document.getElementById) element = document.getElementById(elementId); if (element && element.style) element.style.display = 'none'; return true; }else{ alert('This is not a jpg file'); return false; } } } } </script> <div id="frmDiv"> <form enctype="multipart/form-data" action="/upload.php" method="post" name="upload3" onsubmit="return ver('espera','frmDiv');"> <input type="hidden" name="max_file_size" value="4194304" /> <table border="0" cellspacing="1" cellpadding="2" width="100%"> <tr bgcolor="#f5f5f5"> <td>File (jpg)</td> <td> <input type="file" name="userfile" class="upf" /></td></tr> <tr bgcolor="#f5f5f5"> <td>&nbsp;</td> <td> <input class="upf2" type="submit" name="add" value="Upload" /> </td></tr></table></form> </div> <div id="espera" style="display:none;text-align:center;float:left;width:753px;">&nbsp;<br />&nbsp;<br />&nbsp;<br />&nbsp;<br /> &nbsp;<br />Please wait...<br />&nbsp; </div>

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  • How can I get Firefox to update background-color on a:hover *before* a javascript routine is run?

    - by Rob
    I'm having a Firefox-specific issue with a script I wrote to create 3d layouts. The correct behavior is that the script pulls the background-color from an element and then uses that color to draw on the canvas. When a user mouses over a link and the background-color changes to the :hover rule, the color being drawn changes on the canvas changes as well. When the user mouses out, the color should revert back to non-hover color. This works as expected in Webkit browsers and Opera, but it seems like Firefox doesn't update the background-color in CSS immediately after a mouseout event occurs, so the current background-color doesn't get drawn if a mouseout occurs and it isn't followed up by another event that calls the draw() routine. It works just fine in Opera, Chrome, and Safari. How can I get Firefox to cooperate? I'm including the code that I believe is most relevant to my problem. Any advice on how I fix this problem and get a consistent effect would be very helpful. function drawFace(coord, mid, popColor,gs,x1,x2,side) { /*Gradients in our case run either up/down or left right. We have two algorithms depending on whether or not it's a sideways facing piece. Rather than parse the "rgb(r,g,b)" string(popColor) retrieved from elsewhere, it is simply offset with the gs variable to give the illusion that it starts at a darker color.*/ var canvas = document.getElementById('depth'); //This is for excanvas.js var G_vmlCanvasManager; if (G_vmlCanvasManager != undefined) { // ie IE G_vmlCanvasManager.initElement(canvas); } //Init canvas if (canvas.getContext) { var ctx = canvas.getContext('2d'); if (side) var lineargradient=ctx.createLinearGradient(coord[x1][0]+gs,mid[1],mid[0],mid[1]); else var lineargradient=ctx.createLinearGradient(coord[0][0],coord[2][1]+gs,coord[0][0],mid[1]); lineargradient.addColorStop(0,popColor); lineargradient.addColorStop(1,'black'); ctx.fillStyle=lineargradient; ctx.beginPath(); //Draw from one corner to the midpoint, then to the other corner, //and apply a stroke and a fill. ctx.moveTo(coord[x1][0],coord[x1][1]); ctx.lineTo(mid[0],mid[1]); ctx.lineTo(coord[x2][0],coord[x2][1]); ctx.stroke(); ctx.fill(); } } function draw(e) { var arr = new Array() var i = 0; var mid = new Array(2); $(".pop").each(function() { mid[0]=Math.round($(document).width()/2); mid[1]=Math.round($(document).height()/2); arr[arr.length++]=new getElemProperties(this,mid); i++; }); arr.sort(sortByDistance); clearCanvas(); for (a=0;a<i;a++) { /*In the following conditional statements, we're testing to see which direction faces should be drawn, based on a 1-point perspective drawn from the midpoint. In the first statement, we're testing to see if the lower-left hand corner coord[3] is higher on the screen than the midpoint. If so, we set it's gradient starting position to start at a point in space 60pixels higher(-60) than the actual side, and we also declare which corners make up our face, in this case the lower two corners, coord[3], and coord[2].*/ if (arr[a].bottomFace) drawFace(arr[a].coord,mid,arr[a].popColor,-60,3,2); if (arr[a].topFace) drawFace(arr[a].coord,mid,arr[a].popColor,60,0,1); if (arr[a].leftFace) drawFace(arr[a].coord,mid,arr[a].popColor,60,0,3,true); if (arr[a].rightFace) drawFace(arr[a].coord,mid,arr[a].popColor,-60,1,2,true); } } $("a.pop").bind("mouseenter mouseleave focusin focusout",draw); If you need to see the effect in action, or if you want the full javascript code, you can check it out here: http://www.robnixondesigns.com/strangematter/

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  • XSL to show highest number of copies in catalog.xml file

    - by SANJAY RAO
    In this the catalog.xml file. I have two books who have the same inventory (i.e. 20). I want to write an XSL file that will display the highest number of copies of a book in a catalog. If there are two or more books of the same inventory then they have to be displayed. <catalog> <Book> <sku>12345</sku> <title>Beauty Secrets</title> <condition>New</condition> <current_inventory>20</current_inventory> <price>99.99</price> </Book> <Book> <sku>54321</sku> <title>Picturescapes</title> <current_inventory>20</current_inventory> <condition>New</condition> <price>50.00</price> </Book> <Book> <sku>33333</sku> <title>Tourist Perspectives</title> <condition>New</condition> <current_inventory>0</current_inventory> <price>75.00</price> </Book> <Book> <sku>10001</sku> <title>Fire in the Sky</title> <condition>Used</condition> <current_inventory>0</current_inventory> <price>10.00</price> </Book> </catalog> Below is my catalog3.xsl file which is able to display only one out of the two books: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:variable name="max"/> <xsl:template match="/"> <html> <body> <h2>Titles of Books for which Most Copies are Available</h2> <table border="2"> <tr bgcolor="#9acd32"> <th>Title</th> <th>No of Copies</th> </tr> <xsl:apply-templates/> </table> </body> </html> </xsl:template> <xsl:template match="catalog"> <xsl:for-each select="Book"> <xsl:sort select="current_inventory" data-type="number" order="descending"/> <tr> <xsl:if test="position()= 1"> <p><xsl:value-of select="$max = "/></p> <td><xsl:value-of select="title"/></td> <td><xsl:value-of select="current_inventory"/></td> </xsl:if> </tr> </xsl:for-each> </xsl:template> </xsl:stylesheet> Could anybody correct me to achieve my goal of displaying all the copies having the same maximum inventory in the catalog. Thanks.

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  • Toggle KML Layers, Infowindow isnt working

    - by user1653126
    I have this code, i am trying to toggle some kml layers. The problem is that when i click the marker it isn't showing the infowindow. Maybe someone can show me my error. Thanks. Here is the CODE <!DOCTYPE html> <html> <head> <meta name="viewport" content="initial-scale=1.0, user-scalable=no" /> <style type="text/css"> html { height: 100% } body { height: 100%; margin: 0; padding: 0 } #map_canvas { height: 100% } </style> <script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?key=IzaSyAvj6XNNPO8YPFbkVR8KcTl5LK1ByRHG1E&sensor=false"> </script> <script type="text/javascript"> var map; // lets define some vars to make things easier later var kml = { a: { name: "Productores", url: "https://maps.google.hn/maps/ms?authuser=0&vps=2&hl=es&ie=UTF8&msa=0&output=kml&msid=200984447026903306654.0004c934a224eca7c3ad4" } // keep adding more if you like }; // initialize our goo function initializeMap() { var options = { center: new google.maps.LatLng(13.324182,-87.080071), zoom: 8, mapTypeId: google.maps.MapTypeId.TERRAIN } map = new google.maps.Map(document.getElementById("map_canvas"), options); createTogglers(); }; google.maps.event.addDomListener(window, 'load', initializeMap); // the important function... kml[id].xxxxx refers back to the top function toggleKML(checked, id) { if (checked) { var layer = new google.maps.KmlLayer(kml[id].url, { preserveViewport: true, suppressInfoWindows: true }); // store kml as obj kml[id].obj = layer; kml[id].obj.setMap(map); } else { kml[id].obj.setMap(null); delete kml[id].obj; } }; // create the controls dynamically because it's easier, really function createTogglers() { var html = "<form><ul>"; for (var prop in kml) { html += "<li id=\"selector-" + prop + "\"><input type='checkbox' id='" + prop + "'" + " onclick='highlight(this,\"selector-" + prop + "\"); toggleKML(this.checked, this.id)' \/>" + kml[prop].name + "<\/li>"; } html += "<li class='control'><a href='#' onclick='removeAll();return false;'>" + "Remove all layers<\/a><\/li>" + "<\/ul><\/form>"; document.getElementById("toggle_box").innerHTML = html; }; function removeAll() { for (var prop in kml) { if (kml[prop].obj) { kml[prop].obj.setMap(null); delete kml[prop].obj; } } }; // Append Class on Select function highlight(box, listitem) { var selected = 'selected'; var normal = 'normal'; document.getElementById(listitem).className = (box.checked ? selected: normal); }; </script> <style type="text/css"> .selected { font-weight: bold; } </style> </head> <body> <div id="map_canvas" style="width: 50%; height: 200px;"></div> <div id="toggle_box" style="position: absolute; top: 200px; right: 1000px; padding: 20px; background: #fff; z-index: 5; "></div> </body> </html>

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  • How do I explain this to potential employers?

    - by ReferencelessBob
    Backstory: TL;DR: I've gained a lot of experience working for 5 years at one startup company, but it eventually failed. The company is gone and the owner MIA. When I left sixth-form college I didn't want to start a degree straight away, so when I met this guy who knew a guy who was setting up a publishing company and needed a 'Techie' I thought why not. It was a very small operation, he sent mailings to schools, waited for orders to start arriving, then ordered a short run of the textbooks to be printed, stuck them in an envelope posted them out. I was initially going to help him set up a computerized system for recording orders and payments, printing labels, really basic stuff and I threw it together in Access in a couple of weeks. He also wanted to start taking orders online, so I set up a website and a paypal business account. While I was doing this, I was also helping to do the day-to-day running of things, taking phone orders, posting products, banking cheques, ordering textbooks, designing mailings, filing end of year accounts, hiring extra staff, putting stamps on envelopes. I learned so much about things I didn't even know I needed to learn about. Things were pretty good, when I started we sold about £10,000 worth of textbooks and by my 4th year there we sold £250,000 worth of text books. Things were looking good, but we had a problem. Our best selling product had peaked and sales started to fall sharply, we introduced add on products through the website to boost sales which helped for a while, but we had simply saturated the market. Our plan was to enter the US with our star product and follow the same, slightly modified, plan as before. We setup a 1-866 number and had the calls forwarded to our UK offices. We contracted a fulfillment company, shipped over a few thousand textbooks, had a mailing printed and mailed, then sat by the phones and waited. Needless to say, it didn't work. We tried a few other things, at home and in the US, but nothing helped. We expanded in the good times, moving into bigger offices, taking on staff to do administrative and dispatch work, but now cashflow was becoming a problem and things got tougher. We did the only thing we could and scaled things right back, the offices went, the admin staff went, I stopped taking a wage and started working from home. Nothing helped. The business was wound up about about 2 years ago. In the end it turned out that the owner had built up considerable debt at the start of business and had not paid them off during good years, which left him in a difficult position when cashflow had started to dry up. I haven't been able to contact the owner since I found out. It took me a while to get back on my feet after that, but I'm now at University and doing a Computer Science degree. How do I show the experience I have without having to get into all the gory details of what happened?

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  • Spring Custom Filter Problem?

    - by mr.lost
    greetings all,iam using spring security 3 and i want to perform some logic(saving some data in the session) when the user is visiting the site and he's remembered so i extended the GenericFilterBean class and performed the logic in the doFilter method then complete the filter chain by calling the chain.doFilter method,and then inserted that filter after the remember me filter in the security.xml file? but there's a problem is the filter is executed on each page even if the user is remembered or not is there's something wrong with the filter implementation or the position of the filter? and i have a simple question,is the filter chain by default is executed on each page? and when making a custom filter should i add it to the web.xml too? the filter class: package projects.internal; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.Authentication; import org.springframework.security.core.context.SecurityContextHolder; import org.springframework.web.filter.GenericFilterBean; import projects.ProjectManager; public class rememberMeFilter extends GenericFilterBean { private ProjectManager projectManager; @Autowired public rememberMeFilter(ProjectManager projectManager) { this.projectManager = projectManager; } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { System.out.println("In The Filter"); Authentication auth = (Authentication) SecurityContextHolder .getContext().getAuthentication(); HttpServletResponse response = ((HttpServletResponse) res); HttpServletRequest request = ((HttpServletRequest) req); // if the user is not remembered,do nothing if (auth == null) { chain.doFilter(request, response); } else { // the user is remembered save some data in the session System.out.println("User Is Remembered"); chain.doFilter(request, response); } } } the security.xml file: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" > <remember-me data-source-ref="dataSource"/> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/forgot_password" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <custom-filter after="REMEMBER_ME_FILTER" ref="rememberMeFilter" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login" authentication-failure-url="/p/login?login_error=1" default-target-url="/p/dashboard" authentication-success-handler-ref="myAuthenticationHandler" always-use-default-target="false" /> <logout/> </http> <beans:bean id="myAuthenticationHandler" class="projects.internal.myAuthenticationHandler" /> <beans:bean id="rememberMeFilter" class="projects.internal.rememberMeFilter" > </beans:bean> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder hash="md5" /> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> </authentication-manager> </beans:beans> any help?

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  • XmlException - inserting attribute gives "unexpected token" exception

    - by Anders Svensson
    Hi, I have an XmlDocument object in C# that I transform, using XslTransform, to html. In the stylesheet I insert an id attribute in a span tag, taking the id from an element in the XmlDocument. Here is the template for the element: <xsl:template match="word"> <span> <xsl:attribute name="id"><xsl:value-of select="@id"></xsl:value-of></xsl:attribute> <xsl:apply-templates/> </span> </xsl:template> But then I want to process the result document as an xhtml document (using the XmlDocument dom). So I'm taking a selected element in the html, creating a range out of it, and try to load the element using XmlLoad(): wordElem.LoadXml(range.htmlText); But this gives me the following exception: "'598' is an unexpected token. The expected token is '"' or '''. Line 1, position 10." And if I move the cursor over the range.htmlText, I see the tags for the element, and the "id" shows without quotes, which confuses me (i.e.SPAN id=598 instead of SPAN id="598"). To confuse the matter further, if I insert a blank space or something like that in the value of the id in the stylesheet, it works fine, i.e.: <span> <xsl:attribute name="id"><xsl:text> </xsl:text> <xsl:value-of select="@id"></xsl:value-of></xsl:attribute> <xsl:apply-templates/> </span> (Notice the whitespace in the xsl:text element). Now if I move the cursor over the range.htmlText, I see an id with quotes as usual in attributes (and as it shows if I open the html file in notepad or something). What is going on here? Why can't I insert an attribute this way and have a result that is acceptable as xhtml for XmlDocument to read? I feel I am missing something fundamental, but all this surprises me, since I do this sort of transformations using xsl:attribute to insert attributes all the time for other types of xsl transformations. Why doesn't XmlDocument accept this value? By the way, it doesn't matter if it is an id attribute. i have tried with the "class" attribute, "style" etc, and also using literal values such as "style" and setting the value to "color:red" and so on. The compiler always complains it is an unvalid token, and does not include quotes for the value unless there is a whitespace or something else in there (linebreaks etc.). I hope I have provided enough information. Any help will be greatly appreciated. Basically, what I want to accomplish is set an id in a span element in html, select a word in a webbrowser control with this document loaded, and get the id attribute out of the selected element. I've accomplished everything, and can actually do what I want, but only if I use regex e.g. to get the attribute value, and I want to be able to use XmlDocument instead to simply get the value out of the attribute directly. I'm sure I'm missing something simple, but if so please tell me. Regards, Anders

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  • Internet Explorer percent based layout issue

    - by Tom
    Heya, My goal is to make a layout that is 200% width and height, with four containers of equal height and width (100% each), using no javascript as the bear minimum (or preferably no hacks). Right now I am using HTML5, and CSS display:table. It works fine in Safari 4, Firefox 3.5, and Chrome 5. I haven't tested it yet on older versions. Nonetheless, in IE7 and IE8 this layout fails completely. (I do use the Javascript HTML5 enabling script /cc../, so it should not be the use of new HTML5 tags) Here is what I have: <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <meta charset="UTF-8" /> <title>IE issue with layout</title> <style type="text/css" media="all"> /* styles */ @import url("reset.css"); /* Generall CSS */ .table { display:table; } .row { display:table-row; } .cell { display:table-cell; } /* Specific CSS */ html, body { //overflow:hidden; I later intend to limit the viewport } section#body { position:absolute; width:200%; height:200%; overflow:hidden; } section#body .row { width:200%; height:50%; overflow:hidden; } section#body .row .cell { width:50%; overflow:hidden; } section#body .row .cell section { display:block; width:100%; height:100%; overflow:hidden; } section#body #stage0 section header { text-align:center; height:20%; display:block; } section#body #stage0 section footer { display:block; height:80%; } </style> </head> <body> <section id="body" class="table"> <section class="row"> <section id="stage0" class="cell"> <section> <header> <form> <input type="text" name="q" /> <input type="submit" value="Search" /> </form> </header> <footer> <table id="scrollers"> </table> </footer> </section> </section> <section id="stage1" class="cell"> <section> content </section> </section> </section> <section class="row"> <section id="stage2" class="cell"> <section> content </section> </section> <section id="stage3" class="cell"> <section> content </section> </section> </section> </section> </body> </html> You can see it live here: http://www.tombarrasso.com/ie-issue/

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  • Custom Filter Problem?

    - by mr.lost
    greetings all,iam using spring security 3 and i want to perform some logic(saving some data in the session) when the user is visiting the site and he's remembered so i extended the GenericFilterBean class and performed the logic in the doFilter method then complete the filter chain by calling the chain.doFilter method,and then inserted that filter after the remember me filter in the security.xml file? but there's a problem is the filter is executed on each page even if the user is remembered or not is there's something wrong with the filter implementation or the position of the filter? and i have a simple question,is the filter chain by default is executed on each page? and when making a custom filter should i add it to the web.xml too? the filter class: package projects.internal; import java.io.IOException; import javax.servlet.FilterChain; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.security.core.Authentication; import org.springframework.security.core.context.SecurityContextHolder; import org.springframework.web.filter.GenericFilterBean; import projects.ProjectManager; public class rememberMeFilter extends GenericFilterBean { private ProjectManager projectManager; @Autowired public rememberMeFilter(ProjectManager projectManager) { this.projectManager = projectManager; } @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { System.out.println("In The Filter"); Authentication auth = (Authentication) SecurityContextHolder .getContext().getAuthentication(); HttpServletResponse response = ((HttpServletResponse) res); HttpServletRequest request = ((HttpServletRequest) req); // if the user is not remembered,do nothing if (auth == null) { chain.doFilter(request, response); } else { // the user is remembered save some data in the session System.out.println("User Is Remembered"); chain.doFilter(request, response); } } } the security.xml file: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <global-method-security pre-post-annotations="enabled"> </global-method-security> <http use-expressions="true" > <remember-me data-source-ref="dataSource"/> <intercept-url pattern="/" access="permitAll" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/scripts/**" filters="none" /> <intercept-url pattern="/styles/**" filters="none" /> <intercept-url pattern="/p/login" filters="none" /> <intercept-url pattern="/p/register" filters="none" /> <intercept-url pattern="/p/forgot_password" filters="none" /> <intercept-url pattern="/p/**" access="isAuthenticated()" /> <custom-filter after="REMEMBER_ME_FILTER" ref="rememberMeFilter" /> <form-login login-processing-url="/j_spring_security_check" login-page="/p/login" authentication-failure-url="/p/login?login_error=1" default-target-url="/p/dashboard" authentication-success-handler-ref="myAuthenticationHandler" always-use-default-target="false" /> <logout/> </http> <beans:bean id="myAuthenticationHandler" class="projects.internal.myAuthenticationHandler" /> <beans:bean id="rememberMeFilter" class="projects.internal.rememberMeFilter" > </beans:bean> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder hash="md5" /> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> </authentication-manager> </beans:beans> any help?

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