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• Determine outer boundries of polygon from lat/lng point array

  - by DustinDavis

  I have a large array of lat/lng points. Could be up to 20k points. I'm plotting them using KML. What I want to do is to take only the outter most points and use them to draw a polygon instead. I already know how to draw a polygon in kml, I just need to figure out how to select only the outer most points of the group. Any ideas? I'd like to have at least 5 points to the polygon but no more than 25 points total. So far i've come up with checking for top most and bottom most points (basically crearing a square) using < & logic. The points will be in america & canada only if that matters. Thanks for any help.

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• Why does this jQuery dropdown menu display subcategory selections only for certain top-level categories?

  - by chunkymonkey

  I'm trying to implement a dropdown menu based on a jQuery plugin from Filament Group: http://jsfiddle.net/chunkymonkey/Pr8k4/ What I am having difficulty fixing is a bug where certain categories can be expanded to show their subcategories while others show nothing when opened up. For example: Alternative Rock can be expanded to show its multiple subcategories . . . BUT . . . World Music, which has equally many subcategories, shows no subcategories when expanded. I would be very grateful if anyone could help me figure out what's causing this. Thanks. UPDATE: Just noticed this problem may be Chrome-specific(??). I just tested it in IE8 and Firefox and it seems to work correctly in both.

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• Refreshing <div> and load data from php

  - by forgatn

  I have on my page and there is a tag where is some and values filled from mySQL DB. I need some JavaScript I think. When I select one option, I want to display in this propriate DATAs which are in DB. without refreshing whole page. Can you tell me how to do it, if you know that please?:) <div id="country1" class="tabcontent"> <label>Choose protocol</label> <SELECT name="cisloprot"> <?php $con = mysql_connect("localhost", "root", "123456"); $sql = "SELECT kod FROM prot GROUP BY kod"; $rs = mysql_query($sql,$con); while ($r = mysql_fetch_array($rs)) { echo "<OPTION VALUE=".$r['kod'].">".$r['kod']."</OPTION>"; } ?> </SELECT> </div>

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• solving markup validation errors

  - by pradeep

  http://validator.w3.org/check?uri=http%3A%2F%2Fratingscorner.com%2Fproduct_rating.php%3Falias%3DRashtreeya-Vidyalaya-College-of-Engineering-Mysore-Road-Bangalore%26product%3Dcolleges&charset=%28detect+automatically%29&doctype=Inline&group=0&ss=1&st=1&outline=1&No200=1&verbose=1 hi guys, i solved mots of my css errors . there are few errors which i am unable to fix. can some one please help me on it. 1.Warning Line 440, Column 1121: cannot generate system identifier for general entity "p" and similar errors 2.Error Line 113, Column 52: document type does not allow element "input" here; missing one of "p", "h1", "h2", "h3", "h4", "h5", "h6", "div", "pre", "address", "fieldset", "ins", "del" start-tag 3.Error Line 441, Column 37752: document type does not allow element "tfoot" here Error Line 440, Column 80: EntityRef: expecting ';'

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• How to authenticate users against a Windows AD?

  - by Potinos

  I've a JSF-Hibernate web application. I need to authenticate users against a Windows AD and the web application should only allow logins from members of group X, otherwise it should redirect to an error page. How can I configure this? Also, I would like to display the name of the logged-in user on all pages, not the name of the Windows user of the server machine. I have tried the System.property("user.name") for this, but this only returns the name of the Windows user of the server name.

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• Sum two rows in one - My Sql

  - by user303832

  I have found some similar posts, but I didn't find them useful. But I didn't know how to group them. I would like to Sum 'No' and 'Not Set' to one row, and to lose 'Not Set' row. So : 'No' = 'No' + 'Not Set' I have something like this : TEST TestCount Month 'Yes' 123 March 'No' 432 March 'Not Set' 645 March 'Yes' 13 April 'No' 42 April 'Not Set' 45 April 'Yes' 133 May 'No' 41 May 'Not Set' 35 May .... And I would like something like this : TEST TestCount Month 'Yes' 423 March 'No' 410 March 'Yes' 154 April 'No' 192 April 'Yes' 130 May 'No' 149 May .... Can anybody help me with this, tnx in advance

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• Xcode File management. What is best practice?

  - by ian1971

  I've been using Xcode for a while now. One thing that always bugs me is the way it handles files. I like to have my files all in nested folders rather than one big physical folder, but when you create a group in Xcode by default it does not create a folder just a virtual folder within the project. I can see that virtual folders are great for linking code in arbitrary places into your project but once you get beyond a few classes I find the one big folder approach really painful. And then if you try to fix it later it takes ages and is easy to break your build. Is it possible to change this behaviour so that by default it creates a physical folder? Or am I doing it wrong and trying to cling to some other way of working? How do other people work with files in Xcode?

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• Grid forms in Rails

  - by KandadaBoggu

  I am trying to create a grid form for a survey question. value1 value2 value3 option 1 x option 2 x option 3 x Each cell in the grid is a radio button and the radio buttons in a row belong to one radio button group. My models: class Question # title has_many :answers end class Answer # name, position, atype(row/col) end I am struggling to come up with a Rails approach for creating such a form. To complicate the issue user can save the semi-completed form and complete it at a later time. What is the best approach for this problem?

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• Broken count(*) after adding LEFT JOIN

  - by Iain Urquhart

  Since adding the LEFT JOIN to the query below, the count(*) has been returning some strange values, it seems to have added the total rows returned in the query to the 'level': SELECT `n`.*, exp_channel_titles.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n` LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`), `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` I'm totally stumped... Thank you!

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• Can I batch based on a Property (not just Items)?

  - by Josh Buedel

  I have a property group, like so: <PropertyGroup> <Platform>Win32;x64</Platform> </PropertyGroup> And I want to batch in an Exec task, like so: <Exec Command='devenv MySolution.sln /Build "Release|%(Platform)"' /> But of course, as written I get an error: error MSB4095: The item metadata %(Platform) is being referenced without an item name. Specify the item name by using %(itemname.Platform). Can I batch tasks on properties that are lists? I suppose I could hack it by creating a placeholder ItemGroup with metadata and batch on that.

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• How do I find the previous/default value of a radio button in JS?

  - by royrules22

  I'm not sure if this is even possible, but I figured I'd ask before clubbing togehter an ugly solution. What I have is a group of radio buttons and I want to trigger a function if the radio button value is changed. For example say there are three buttons X Y and Z with Y default selected. If a user clicks on an unselected button (i.e. X or Z) then the function gets triggered but if he/she clicks on Y (which is already selected) nothing happens. Naturally the best solution would be to fire the function on an onchange event but IE6 doesn't fire onchange until the focus is no longer on the element which is not satisfactory. So is there a way to know what the previous value of the radio button was or at least what its default value is? I could easily create an array of default values and check against that but I'm trying to reduce the overhead. Please no jQuery suggestions ;)

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• Fetch last item in a category that fits specific criteria

  - by Franz

  Let's assume I have a database with two tables: categories and articles. Every article belongs to a category. Now, let's assume I want to fetch the latest article of each category that fits a specific criteria (read: the article does). If it weren't for that extra criteria, I could just add a column called last_article_id or something similar to the categories table - even though that wouldn't be properly normalized. How can I do this though? I assume there's something using GROUP BY and HAVING?

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• Serialized task distribution: use thread or epoll?

  - by hpsmouse

  Now I'm in such a situation that there is a group of predefined tasks for multiple clients to do(any client can take any task). When a client connects to the server, server choose a task from the uncompleted tasks and send it to the client. It takes a while for the client to finish the task and send the result back to the server. Since a task should be sent to only one client, server should process requests in a serialized way. Now I have two plans to do it: create a thread for each client connection and all the threads take turns accessing the task pool, or use epoll listening on all the connection and process for each event of clients. Which one is better for the job? Or is there any other ideas? The server will be run on a multi-core machine.

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• Create a link to delete membership in web2py

  - by user1741325

  I'm trying to do something really simple but it's taking me ages to figure out how to do it properly. I want to have a button that simply deletes a member from a group. So in my view I have <div id="del-role">{{=A('Delete Role',_class="btn btn-danger", callback=URL('test'),delete='#del-role')}}</div> However, when I click the button, the only thing I get is a Javascript prompt asking whether I'm sure I want to delete the specified object, yes/no. That's fine but, what I'd really like to do is just auth.del_membership('role') What needs to go in my controller? I do not want any page redirection, I just want to auth.del_membership(role) This seemingly simple thing is taking me forever to understand. Thanks!

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• MySQL COUNT() multiple columns

  - by liam

  Hello, I'm trying to fetch the most popular tags from all videos in my database (ignoring blank tags). I also need the 'flv' for each tag. I have this working as I want if each video has one tag: SELECT tag_1, flv, COUNT(tag_1) AS tagcount FROM videos WHERE NOT tag_1='' GROUP BY tag_1 ORDER BY tagcount DESC LIMIT 0, 10 However in my database, each video is allowed three tags - tag_1, tag_2 and tag_3. Is there a way to get the most popular tags reading from multiple columns? The record structure is: +-----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | flv | varchar(150) | YES | | NULL | | | tag_1 | varchar(75) | YES | | NULL | | | tag_2 | varchar(75) | YES | | NULL | | | tag_3 | varchar(75) | YES | | NULL | | +-----------------+--------------+------+-----+---------+----------------+

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• MySQL: Records inserted by hour, for the last 24 hours

  - by Andrew M

  I'm trying to list the number of records per hour inserted into a database for the last 24 hours. Each row displays the records inserted that hour, as well as how many hours ago it was. Here's my query now: SELECT COUNT(*), FLOOR( TIME_TO_SEC( TIMEDIFF( NOW(), time)) / 3600 ) FROM `records` WHERE time > DATE_SUB(NOW(), INTERVAL 24 HOUR) GROUP BY HOUR(time) ORDER BY time ASC right now it returns: 28 23 62 23 14 20 1 4 28 3 19 1 That shows two rows from 23 hours ago, when it should only show one per hour. I think it has something to do with using NOW() instead of getting the time at the start of the hour, which I'm unsure on how to get. There must be a simpler way of doing this.

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• setting minDate in datepicker in Rails

  - by Sakshi Jain

  I need to apply minDate attribute to the datepicker in Rails App. In _admin_controls.html.erb <%= f.input :end_date, wrapper: :append do %> <div id="datepicker" class="datepicker input-group edit-left"> <%= f.text_field :end_date, :class => "datetime form-control" %> application.js contains jQuery(document).on('focus', 'input.datetime', function() { opts = {format: 'M dd, yyyy', autoclose: true}; jQuery(this).datepicker(opts); jQuery(".datepicker").css("z-index",10000); }); What should be the javascript to do so only for _admin_controls.html.erb?

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• Google App Engine datastore-primary key

  - by megala

  Hi, I've created a table in the Google App Engine Datastore. It contains the following FIELDS(GROUPNAME,GROUPID,GROUPDESC). How do I set GROUPID as the primary key? My code is as follows: @Entity @Table(name="group" , schema="PUBLIC") public class Creategroup { @Basic private String groupname; @Basic private String groupid; @Basic private String groupdesc; public void setGroupname(String groupname) { this.groupname = groupname; } public String getGroupname() { return groupname; } public void setGroupid(String groupid) { this.groupid = groupid; } public String getGroupid() { return groupid; } public void setGroupdesc(String groupdesc) { this.groupdesc = groupdesc; } public String getGroupdesc() { return groupdesc; } public Creategroup(String groupname, String groupid, String groupdesc ) { // TODO Auto-generated constructor stub this.groupname = groupname; this.groupid = groupid; this.groupdesc = groupdesc; } }

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• Drupal: Views: grouping relationship in block list

  - by Ronn

  I have a question about views, specifically about grouping a relationship. I have a "partner" node that has many "docs", I want to list the name of the "partner" along with its corresponding "docs" below. I have the relationship set up correctly(I think) but can't figure out how or where to group it correctly. I get this: partner name 1 - doc name 1 partner name 1 - doc name 2 partner name 1 - doc name 3 partner name 2 - doc name 4 partner name 2 - doc name 5 partner name 3 - doc name 6 but would like this: partner name 1 - doc name 1 - doc name 2 - doc name 3 partner name 2 - doc name 4 - doc name 5 - doc name 6

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• Select all items of union but not the last one!

  - by 100r

  I have few texboxes, dropdown lists, etc.. They have their css classes. I want to select all elements of specific class(es) but NOT the last element from group of all classes. <asp:TextBox ID="TextBox1" runat="server" CssClass="class1" ></asp:TextBox> <asp:TextBox ID="TextBox2" runat="server" CssClass="class2" ></asp:TextBox> <asp:TextBox ID="TextBox3" runat="server" CssClass="class2" ></asp:TextBox> I want to select only TextBox1 and TextBox2, not TextBox3! selector should be something like this $("(.class1,.class1):not(:last)") or something like $(".class1,.class1").filter(":not(:last)") but of course none of it is working :) any sugestions? tnx in advance!

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• If a Matlab function returns a variable number of values, how can I get all of them as a cellarray,

  - by kaleidomedallion

  I am writing a function to remove some values from a cellarray, like so: function left = remove(cells, item); left = cells{cellfun(@(i) ~isequal(item, i), cells)}; But when I run this, left has only the first value, as the call to cells{} with a logical array returns all of the matching cells as separate values. How do I group these separate return values into a single cellarray? Also, perhaps there is already a way to remove a given item from a cellarray? I could not find it in the documentation.

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• MySQL how to display data from two tables.

  - by gew

  I'm trying to display the username of the person who has submitted the most articles but I don't know how to do it using MySQL & PHP, can someone help me? Here is the MySQL code. CREATE TABLE users ( user_id INT UNSIGNED NOT NULL AUTO_INCREMENT, username VARCHAR(255) DEFAULT NULL, pass CHAR(40) NOT NULL, PRIMARY KEY (user_id) ); CREATE TABLE users_articles ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, user_id INT UNSIGNED mNOT NULL, title TEXT NOT NULL, acontent LONGTEXT NOT NULL, PRIMARY KEY (id) ); Here is the code I have so far. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT COUNT(*) as coun, user_id FROM users_articles GROUP BY user_id ORDER BY coun DESC LIMIT 1");

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• Trying to create fields based on a case statement

  - by dido

  I'm having some trouble with the query below. I am trying to determine if the "category" field is A, B or C and then creating a field based on the category. That field would sum up payments field. But I'm running into error saying "incorrect syntax near keyword As". I am creating this in a SQL View. Using SQL Server 2008 SELECT r.id, r.category CASE WHEN r.category = 'A' then SUM(r.payment) As A_payments WHEN r.category = 'B' then SUM(r.payment) As B_payments WHEN r.category = 'C' then SUM(r.payment) As C_payments END FROM r_invoiceTable As r GROUP BY r.id, r.category I have data where all of the above cases should be executed because the data that I have has A,B and C Sample Data- r_invoiceTable Id --- Category ---- Payment 222 A ---- 50 444 A ---- 30 111 B ---- 90 777 C ---- 20 555 C ---- 40 Desired Output A_payments = 80, B_payments = 90, C_payments = 60

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• Presentation to under privileged students about what programming is. How? Any ideas.

  - by Quigrim

  Next week I have to give a presentation to a group of under privileged college students about the possibilities of a career in software development. These students have no exposure to programming what-so-ever. I have a good idea of how to tackle the non-technical, general portion of the presentation. However, notwithstanding my decade of experience, I am finding myself at somewhat of a loss how to convey the concept of programming in a meaningful way in under 20 minutes. Do I demonstrate actual simple code, or do I stick with concepts? I need to be able to scratch the surface of the vastness of the programming realm, to create just enough of a handle to those students, to peak the interest of those who might have the aptitude for it. Any ideas that are concise and clear would be greatly appreciated. Also, if anybody knows of online resources that addresses this topic, please share. Looking forward to some great input from this community. Thank you.

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• Query to find all bars that sell three different beers at the same price

  - by Eternal Learner

  Query to find "All bars that sell three different beers at the same price?" My Tables are Sells(bar,beer,price) - bar - foreign Key.. Bars(name,addr) - name primary key. I thought of something like this but that dosent seem to work ... Select A.bar As bar , B.bar as bar From Sells AS A, Sells AS B Where A.bar = B.bar and A.beer <> B.beer Group By(A.beer) Having Count(Distinct A.beer) >= 2 Is this the correct SQL query ?

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