I want tell the VC++ Compiler to compile all code. Can it be done?
- by KGB
I am using VS2005 VC++ for unmanaged C++. I have VSTS and am trying to use the code coverage tool to accomplish two things with regards to unit tests:
See how much of my referenced code under test is getting executed
See how many methods of my code under test (if any) are not unit tested at all
Setting up the VSTS code coverage tool (see the link text) and accomplishing task #1 was straightforward. However #2 has been a surprising challenge for me. Here is my test code.
class CodeCoverageTarget
{
public:
std::string ThisMethodRuns() {
return "Running";
}
std::string ThisMethodDoesNotRun() {
return "Not Running";
}
};
#include <iostream>
#include "CodeCoverageTarget.h"
using namespace std;
int main()
{
CodeCoverageTarget cct;
cout<<cct.ThisMethodRuns()<<endl;
}
When both methods are defined within the class as above the compiler automatically eliminates the ThisMethodDoesNotRun() from the obj file. If I move it's definition outside the class then it is included in the obj file and the code coverage tool shows it has not been exercised at all. Under most circumstances I want the compiler to do this elimination for me but for the code coverage tool it defeats a significant portion of the value (e.g. finding untested methods). I have tried a number of things to tell the compiler to stop being smart for me and compile everything but I am stumped. It would be nice if the code coverage tool compensated for this (I suppose by scanning the source and matching it up with the linker output) but I didn't find anything to suggest it has a special mode to be turned on. Am I totally missing something simple here or is this not possible with the VC++ compiler + VSTS code coverage tool?
Thanks in advance,
KGB
