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  • expecting tASSOC in a Rails file

    - by steven_noble
    I'm sure I've done something stupid here, but I just can't see it. I call the breadcrumb method in the application view. app/helpers/breadcrumbs_helper.rb says: module BreadcrumbsHelper def breadcrumb @crumb_list = [] drominay_crumb_builder project_crumb_builder content_tag(:div, :id => "breadcrumbs", @crumb_list.map { |list_item| crumb_builder(list_item) }) end def crumb_builder(list_item) if list_item == @crumb_list.last content_tag(:span, list_item['body'], :class => list_item['crumb']) else body = ["list_item['body']", "&nbsp;&#x2192;&nbsp;"].join link_to(body, list_item['url'], :class => list_item['crumb']) end end def drominay_crumb_builder list_item = Hash.new list_item['body'] = "Drominay" list_item['url'] = "root" @crumb_list << list_item end def project_crumb_builder end end Why oh why am I getting this "expecting tASSOC" error? (And what is a tASSOC anyway?) steven-nobles-imac-200:drominay steven$ script/server => Booting Mongrel (use 'script/server webrick' to force WEBrick) => Rails 2.2.2 application starting on http://0.0.0.0:3000 => Call with -d to detach => Ctrl-C to shutdown server ** Starting Mongrel listening at 0.0.0.0:3000 ** Starting Rails with development environment... Exiting /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require': /Users/steven/Drominay/app/helpers/breadcrumbs_helper.rb:7: syntax error, unexpected ')', expecting tASSOC (SyntaxError) /Users/steven/Drominay/app/helpers/breadcrumbs_helper.rb:29: syntax error, unexpected $end, expecting kEND from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:153:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:521:in `new_constants_in' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:153:in `require' from /Users/steven/Drominay/app/helpers/application_helper.rb:5 from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:382:in `load_without_new_constant_marking' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:382:in `load_file' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:521:in `new_constants_in' ... 56 levels... from /Users/steven/.gem/ruby/1.8/gems/rails-2.2.2/lib/commands/server.rb:49 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from script/server:3

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  • Hibernate: Found: float, expected: double precision

    - by Frederic Morin
    I have a problem with the mapping of Oracle Float double precision datatype to Java Double datatype. The hibernate schema validator seems to fail when the Java Double datatype is used. org.hibernate.HibernateException: Wrong column type in DB.TABLE for column amount. Found: float, expected: double precision The only way to avoid this is to disable schema validation and hope the schema is in sync with the app about to run. I must fix this before it goes out to production. App's evironment: - Grails 1.2.1 - Hibernate-core 3.3.1.GA - Oracle 10g

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  • MySQL Error 1452 - Cannot add or update a child row: a foreign key constraint fails

    - by dscher
    I've looked at other people's questions on this topic but can't seem to find where my error is coming from. Any help would be greatly appreciated. I'm including as much as I can think of that might help find the problem: CREATE TABLE stocks ( id INT AUTO_INCREMENT NOT NULL, user_id INT(11) UNSIGNED NOT NULL, ticker VARCHAR(20) NOT NULL, name VARCHAR(20), rating INT(11), position ENUM("strong buy", "buy", "sell", "strong sell", "neutral"), next_look DATE, privacy ENUM("public", "private"), PRIMARY KEY(id), FOREIGN KEY (user_id) REFERENCES users(id) ON DELETE CASCADE ) ENGINE=InnoDB DEFAULT CHARSET=utf8; CREATE TABLE IF NOT EXISTS `stocks_tags` ( `stock_id` INT NOT NULL, `tag_id` INT NOT NULL, PRIMARY KEY (`stock_id`,`tag_id`), KEY `fk_stock_tag` (`tag_id`), KEY `fk_tag_stock` (`stock_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; ALTER TABLE `stocks_tags` ADD CONSTRAINT `fk_stock_tag` FOREIGN KEY (`tag_id`) REFERENCES `tags` (`id`) ON DELETE CASCADE ON UPDATE CASCADE, ADD CONSTRAINT `fk_tag_stock` FOREIGN KEY (`stock_id`) REFERENCES `stocks` (`id`) ON DELETE CASCADE ON UPDATE CASCADE; CREATE TABLE tags( id INT AUTO_INCREMENT NOT NULL PRIMARY KEY, tags VARCHAR(30), UNIQUE(tags) ) ENGINE=INNODB DEFAULT CHARSET=utf8; And the error I'm getting: Database_Exception [ 1452 ]: Cannot add or update a child row: a foreign key constraint fails (`ddmachine`.`stocks_tags`, CONSTRAINT `fk_stock_tag` FOREIGN KEY (`tag_id`) REFERENCES `tags` (`id`) ON DELETE CASCADE ON UPDATE CASCADE) [ INSERT INTO `stocks_tags` (`stock_id`, `tag_id`) VALUES (19, 'cash') ] I did see that someone else had a similar problem based on their enum columns but don't think that's it.

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  • Solr error; Anybody know what this means?

    - by Camran
    I am installing solr on my VPS (Ubuntu 9.10) via PuTTY. First, I thought about installing Solr with Tomcat, but then after installing tomcat, I changed my mind and went for the Jetty which comes with Solr. Now that I have setup everything on my Server, and try to start the "start.jar" file, I get some errors... Here is some text from the log file: 2010-05-29 00:22:42.074::INFO: jetty-6.1.3 2010-05-29 00:22:42.134::INFO: Extract jar:file:/var/www/webapps/solr.war!/ to /var/www/work/Jetty_0_0_0_0_8983_solr.war__solr__k1kf17/webapp May 29, 2010 12:22:42 AM org.apache.solr.core.SolrResourceLoader locateSolrHome INFO: JNDI not configured for solr (NoInitialContextEx) May 29, 2010 12:22:42 AM org.apache.solr.core.SolrResourceLoader locateSolrHome INFO: solr home defaulted to 'solr/' (could not find system property or JNDI) May 29, 2010 12:22:42 AM org.apache.solr.core.SolrResourceLoader <init> INFO: Solr home set to 'solr/' May 29, 2010 12:22:42 AM org.apache.solr.servlet.SolrDispatchFilter init INFO: SolrDispatchFilter.init() May 29, 2010 12:22:42 AM org.apache.solr.core.SolrResourceLoader locateSolrHome INFO: JNDI not configured for solr (NoInitialContextEx) May 29, 2010 12:22:42 AM org.apache.solr.core.SolrResourceLoader locateSolrHome INFO: solr home defaulted to 'solr/' (could not find system property or JNDI) May 29, 2010 12:22:42 AM org.apache.solr.core.CoreContainer$Initializer initialize INFO: looking for solr.xml: /var/www/solr/solr.xml May 29, 2010 12:22:42 AM org.apache.solr.core.SolrResourceLoader <init> INFO: Solr home set to 'solr/' Anybody know what this is? Thanks

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  • Can not delete row from MySQL

    - by Drew
    Howdy all, I've got a table, which won't delete a row. Specifically, when I try to delete any row with a GEO_SHAPE_ID over 150000000 it simply does not disappear from the DB. I have tried: SQLyog to erase it. DELETE FROM TABLE WHERE GEO_SHAPE_ID = 150000042 (0 rows affected). UNLOCK TABLES then 2. As far as I am aware, bigint is a valid candidate for auto_increment. Anyone know what could be up? You gotta help us, Doc. We’ve tried nothin’ and we’re all out of ideas! DJS. PS. Here is the table construct and some sample data just for giggles. CREATE TABLE `GEO_SHAPE` ( `GEO_SHAPE_ID` bigint(11) NOT NULL auto_increment, `RADIUS` float default '0', `LATITUDE` float default '0', `LONGITUDE` float default '0', `SHAPE_TYPE` enum('Custom','Region') default NULL, `PARENT_ID` int(11) default NULL, `SHAPE_POLYGON` polygon default NULL, `SHAPE_TITLE` varchar(45) default NULL, `SHAPE_ABBREVIATION` varchar(45) default NULL, PRIMARY KEY (`GEO_SHAPE_ID`) ) ENGINE=MyISAM AUTO_INCREMENT=150000056 DEFAULT CHARSET=latin1 CHECKSUM=1 DELAY_KEY_WRITE=1 ROW_FORMAT=DYNAMIC; SET FOREIGN_KEY_CHECKS = 0; LOCK TABLES `GEO_SHAPE` WRITE; INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (57, NULL, NULL, NULL, 'Region', 10, NULL, 'Washington', 'WA'); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (58, NULL, NULL, NULL, 'Region', 10, NULL, 'West Virginia', 'WV'); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (59, NULL, NULL, NULL, 'Region', 10, NULL, 'Wisconsin', 'WI'); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000042, 10, -33.8833, 151.217, 'Custom', NULL, NULL, 'Sydney%2C%20New%20South%20Wales%20%2810km%20r', NULL); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000043, 10, -33.8833, 151.167, 'Custom', NULL, NULL, 'Annandale%2C%20New%20South%20Wales%20%2810km%', NULL); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000048, 10, -27.5, 153.017, 'Custom', NULL, NULL, 'Brisbane%2C%20Queensland%20%2810km%20radius%2', NULL); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000045, 10, 43.1002, -75.2956, 'Custom', NULL, NULL, 'New%20York%20Mills%2C%20New%20York%20%2810km%', NULL); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000046, 10, 40.1117, -78.9258, 'Custom', NULL, NULL, 'Region1', NULL); UNLOCK TABLES; SET FOREIGN_KEY_CHECKS = 1;

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  • sql query for 3 tables

    - by greffe
    i have 3 tables (A,B,C) Table A - ID Name 1 Sam 2 Manuel 3 Jane Table B ID Tab_A_ID Name 1 1 Meer 2 1 Kutti 3 2 Mikaro Table C ID Tab_B_ID Price 1 1 255.11 2 1 30.52 3 3 125.22 I need a query that shall pick up the top price for TableA-Name from TableC. So only 1 top price for 1 nae record. e.g.- Sam - 255.11 Manuel - 125.22 How can i get this?

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  • Undo Table Partitioning - SQL Server 2008

    - by Binder
    I have a table 'X' and did the following CREATE PARTITION FUNCTION PF1(INT) AS RANGE LEFT FOR VALUES (1, 2, 3, 4) CREATE PARTITION SCHEME PS1 AS PARTITION PF1 ALL TO ([PRIMARY]) CREATE CLUSTERED INDEX CIDX_X ON X(col1) ON PS1(col1) this 3 steps created 4 logical partitions of the data I had. My question is, how do i revert this partitioning to its original state ?

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  • Javascript data store solution using PhoneGap

    - by nickcartwright
    Hiya, Does anyone have any experience of storing data in JavaScript across all mobile platforms using PhoneGap? My ideal solution would be to use something like SQLite, but unfortunately SQLite isn't supported across all the platforms PhoneGap supports. I tried to ask this question a little while ago, but it got quite a few negative marks. If you think this is a bad / pointless question I would love to know as it will hopefully help me to understand the problem! Cheers, Nick.

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  • how to rethrow same exception in sql server

    - by Shantanu Gupta
    I want to rethrow same exception in sql server that has been occured in my try block. I am able to throw same message but i want to throw same error. BEGIN TRANSACTION BEGIN TRY INSERT INTO Tags.tblDomain (DomainName, SubDomainId, DomainCode, Description) VALUES(@DomainName, @SubDomainId, @DomainCode, @Description) COMMIT TRANSACTION END TRY BEGIN CATCH declare @severity int; declare @state int; select @severity=error_severity(), @state=error_state(); RAISERROR(@@Error,@ErrorSeverity,@state); ROLLBACK TRANSACTION END CATCH RAISERROR(@@Error, @ErrorSeverity, @state); This line will show error, but i want functionality something like that. This raises error with error number 50000, but i want erron number to be thrown that i am passing @@error, I want to capture this error no at frontend i.e. catch (SqlException ex) { if ex.number==2627 MessageBox.show("Duplicate value cannot be inserted"); } I want this functionality. which can't be achieved using raiseerror. I dont want to give custom error message at back end.

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  • ETL Tools and Build Tools

    - by Ngu Soon Hui
    I have familiarities with software automated build tools ( such as Automated Build Studio). Now I am looking at ETL tools. The one thing crosses my mind is that, I can do anything I can do in ETL tools by using a software build tool. ETL tools are tailored for data loading and manipulation for which a lot of scripts are needed in order to do the job. Software build tool, on the other hand, is versatile enough to do any jobs, including writing scripts to extract, transform and load any data from any format into any format. Am I right?

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  • Optional one-to-one mapping in Hibernate

    - by hibernate
    How do I create an optional one-to-one mapping in the hibernate hbm file? For example, suppose that I have a User and a last_visited_page table. The user may or may not have a last_visited page. Here is my current one-to-one mapping in the hbm file: User Class: <one-to-one name="lastVisitedPage" class="LastVisitedPage" cascade="save-update"> LastVisitedPage Class: <one-to-one name="user" class="user" constrained="true" /> The above example does not allow the creation of a user who does not have a last visited page. A freshly created user has not visited any pages yet. How do I change the hbm mapping to make the userPrefs mapping optional?

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  • Comparing two Oracle schema, other users

    - by Igman
    Hello! I have been tasked with comparing two oracle schema with a large number of tables to find the structural differences in the schema. Up until know I have used the DB Diff tool in Oracle SQL Developer, and it has worked very well. The issue is that now I need to compare tables in a user that I cannot log into , but I can see it through the other users section in SQL developer. The issue is that whenever I try to use the diff tool to compare those objects to the other schema it does not work. Does anyone have any idea how to do this? It would save me a very large amount of work. I have some basic SQL knowledge if that is whats needed. Thanks.

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  • PHP postgres backup.

    - by russell kinch
    Hi. I am trying to make a Postgres PHP backup script. I have downloaded one for the command line which looks like this: #!/bin/bash find /home/russell/pg_bkp -type f -mtime +7 -exec rm {} \; time=`date +%Y-%m-%d`; # date in reverse so that lastest date appears last in the list of backup files. PGPASSWORD=****** pg_dump -i -h localhost -p 5432 -U postgres -F c -b -v -f "/home/russell/pg_bkp/$time.backup" ah3 How can I implement this in PHP? The extension that this creates is .backup. It works great and have used it many times. the data is perfect, but doing it from inside my website would be better. Thanks

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  • Legit? Two foreign keys referencing the same primary key.

    - by Ryan
    Hi All, I'm a web developer and have recently started a project with a company. Currently, I'm working with their DBA on getting the schema laid out for the site, and we've come to a disagreement regarding the design on a couple tables, and I'd like some opinions on the matter. Basically, we are working on a site that will implement a "friends" network. All users of the site will be contained in a table tblUsers with (PersonID int identity PK, etc). What I am wanting to do is to create a second table, tblNetwork, that will hold all of the relationships between users, with (NetworkID int identity PK, Owners_PersonID int FK, Friends_PersonID int FK, etc). Or conversely, remove the NetworkID, and have both the Owners_PersonID and Friends_PersonID shared as the Primary key. This is where the DBA has his problem. Saying that "he would only implement this kind of architecture in a data warehousing schema, and not for a website, and this is just another example of web developers trying to take the easy way out." Now obviously, his remark was a bit inflammatory, and that have helped motivate me to find an suitable answer, but more so, I'd just like to know how to do it right. I've been developing databases and programming for over 10 years, have worked with some top-notch minds, and have never heard this kind of argument. What the DBA is wanting to do is instead of storing both the Owners_PersonId and Friends_PersonId in the same table, is to create a third table tblFriends to store the Friends_PersonId, and have the tblNetwork have (NetworkID int identity PK, Owner_PersonID int FK, FriendsID int FK(from TBLFriends)). All that tblFriends would house would be (FriendsID int identity PK, Friends_PersonID(related back to Persons)). To me, creating the third table is just excessive in nature, and does nothing but create an alias for the Friends_PersonID, and cause me to have to add (what I view as unneeded) joins to all my queries, not to mention the extra cycles that will be necessary to perform the join on every query. Thanks for reading, appreciate comments. Ryan

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  • Retrieve sequence of data from different columns.

    - by janetsmith
    Let's say I have a table containing following data: | id | t0 | t1 | t2 | | 1 | 4 | 5 | 6 | | 2 | 3 | 3 | 2 | | 3 | 6 | 4 | 5 | | 4 | 4 | 5 | 5 | I want to retrieve all the rows containing 4, 5, 6 (regardless the position of numbers in the tables), so row 1 & row 3 will be selected. How to do that with SQL query?

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  • Using MongoDB with Ruby On Rails and the Mongomapper plugin

    - by Micke
    Hello, i am currently trying to learn Ruby On Rails as i am a long-time PHP developer so i am building my own community like page. I have came pritty far and have made the user models and suchs using MySQL. But then i heard of MongoDB and looked in to it a little bit more and i find it kinda nice. So i have set it up and i am using mongomapper for the connection between rails and MongoDB. And i am now using it for the News page on the site. I also have a profile page for every User which includes their own guestbook so other users can come to their profile and write a little message to them. My thought now is to change the User models from using MySQL to start using MongoDB. I can start by showing how the models for each User is set up. The user model: class User < ActiveRecord::Base has_one :guestbook, :class_name => "User::Guestbook" The Guestbook model model: class User::Guestbook < ActiveRecord::Base belongs_to :user has_many :posts, :class_name => "User::Guestbook::Posts", :foreign_key => "user_id" And then the Guestbook posts model: class User::Guestbook::Posts < ActiveRecord::Base belongs_to :guestbook, :class_name => "User::Guestbook" I have divided it like this for my own convenience but now when i am going to try to migrate to MongoDB i dont know how to make the tables. I would like to have one table for each user and in that table a "column" for all the guestbook entries since MongoDB can have a EmbeddedDocument. I would like to do this so i just have one Table for each user and not like now when i have three tables just to be able to have a guestbook. So my thought is to have it like this: The user model: class User include MongoMapper::Document one :guestbook, :class_name => "User::Guestbook" The Guestbook model model: class User::Guestbook include MongoMapper::EmbeddedDocument belongs_to :user many :posts, :class_name => "User::Guestbook::Posts", :foreign_key => "user_id" And then the Guestbook posts model: class User::Guestbook::Posts include MongoMapper::EmbeddedDocument belongs_to :guestbook, :class_name => "User::Guestbook" But then i can think of one problem.. That when i just want to fetch the user information like a nickname and a birthdate then it will have to fetch all the users guestbook posts. And if each user has like a thousand posts in the guestbook it will get really much to fetch for the system. Or am i wrong? Do you think i should do it any other way? Thanks in advance and sorry if i am hard to understand but i am not so educated in the english language :)

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  • Oracle Trigger to persist value

    - by Jose Jose
    I have a column that I need to be able to guarantee never gets set to anything other than "N" - I thought a trigger would be the perfect solution for this, but I can't seem to figure out how to make it so that anytime the column gets set to something other than "N" I reset it back to "N" Any pointers? EDIT: I wouldn't want to do a constraint because the application that will potentially change it to Y is outside of my control and I don't want it to be getting errors when it sets it to Y, I just want to passively set it back to N without fanfare.

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  • MySql, InnoDB & Null Values

    - by pws5068
    Formerly I was using MyISAM storage engine for MySql and I had defined the combination of three fields to be unique. Now I have switched to InnoDB, which I assume caused this problem, and now NULL != NULL. So for the following table: ID (Auto) | Field_A | Field_B | Field_C I can insert (Field_A,Field_B,Field_C) Values(1,2,NULL) (1,2,NULL) (1,2,NULL) infinitely many times. How can I prevent this behavior?

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