Search Results

Search found 33297 results on 1332 pages for 'java java ee'.

Page 319/1332 | < Previous Page | 315 316 317 318 319 320 321 322 323 324 325 326  | Next Page >

  • Java Swing Forms Catching Data

    - by RhigoHR
    Hi everybody, I have a form in swing with a lot of textfields receiving data, then, the idea is when a click on a botton, the app catch all the data from the textfields. Do you know a good practice for this?, or is it necessary to catch textfield by textfield to get the data?.. Thx for your time.

    Read the article

  • Negative look ahead java

    - by venu
    I need an expression to capture a string like this "A"[A string that is NOT atleast 5 and atmost 6 digits]"B", In other words capture anything that is NOT the following A[0-9][0-9][0-9][0-9][0-9]B A[0-9][0-9][0-9][0-9][0-9][0-9]B I have tried the negative look ahead regex = "a((?![0-9]{5,6}).)*d" ; But it fails to capture all scenarios. Please help venu

    Read the article

  • best way to create UI java apps ?

    - by fwfwfw
    I've come across Netbeans but is there any tools out there that lets you build things event driven ? I'm looking for a feature like being able to drag and drop UI components, and add methods to buttons directly by double clicking it (kinda like visualbasic) and viewing the source.

    Read the article

  • My Java regex isn't capturing the group

    - by Geo
    I'm trying to match the username with a regex. Please don't suggest a split. USERNAME=geo Here's my code: String input = "USERNAME=geo"; Pattern pat = Pattern.compile("USERNAME=(\\w+)"); Matcher mat = pat.matcher(input); if(mat.find()) { System.out.println(mat.group()); } why doesn't it find geo in the group? I noticed that if I use the .group(1), it finds the username. However the group method contains USERNAME=geo. Why?

    Read the article

  • Reflection for Class of generic parameter in Java?

    - by hatboysam
    Imagine the following scenario: class MyClass extends OtherClass<String>{ String myName; //Whatever } class OtherClass<T> { T myfield; } And I am analyzing MyClass using reflection specifically (MyClass.class).getDeclaredFields(), in this case I will get the following fields (and Types, using getType() of the Field): myName --> String myField --> T I want to get the actual Type for T, which is known at runtime due to the explicit "String" in the extends notation, how do I go about getting the non-genetic type of myField?

    Read the article

  • Using Java method to display HTML code

    - by javArc
    Hey folks, ok so this is my problem, I need to display HTML code in a jsp, which wouldn't be a problem, except a requirement for this project is that we place all the code in a public class file and have seperate methods for each chunk(header, sidebar footer, etc). Now here's where i'm confused: "Your method should take the PrintWriter as a parameter to print out each line of HTML, and should have a return type of void" What does that mean? How do I pass the PrintWriter into a method? Does this make sense to anyone?

    Read the article

  • how to convert BigInteger to String in java

    - by Bipul
    i converted a string to BigInteger as follows: Scanner sc=new Scanner(System.in); System.out.println("enter the message"); String msg=sc.next(); byte[] bytemsg=msg.getBytes(); BigInteger m=new BigInteger(bytemsg); now i want my string back.i m using m.toString() method but not getting desired result. why??? what is bug in it and what is its remedy.

    Read the article

  • 2 bucks for !! java basic question

    - by Max
    How can I get a specific value from an object? I'm trying to get a value of an instance for eg. ListOfPpl newListOfPpl = new ListOfPpl(id, name, age); Object item = newListOfPpl; How can I get a value of name from an Object item?? Even if it is easy or does not interest you can anyone help me?? Edited: I was trying to build a binary tree contains the node of ListOfPpl, and need to sort it in the lexicographic. Here's my code for insertion on the node. Any clue?? public void insert(Object item){ Node current = root; Node follow = null; if(!isEmpty()){ root = new Node(item, null, null); return; }boolean left = false, right = false; while(current != null){ follow = current; left = false; right = false; //I need to compare and sort it if(item.compareTo(current.getFighter()) < 0){ current = current.getLeft(); left = true; }else { current = current.getRight(); right = true; } }if(left) follow.setLeft(new Node(item, null, null)); else follow.setRight(new Node(item, null, null)); }

    Read the article

  • Deferred printing in Java

    - by Bober02
    I have a specific issue with general console printing and I was wondering whether anyone has a solution for it. I am trying to print a dataTable which would look like sth like this: Table ---------------------- Name |Surname | ---------------------- Mike |Mikhailowish| Rafaello|Mirena | and so on. In order to print the border of the bar I need to know what the maximum length of each column value is. I don't want to go through the whole database to find that out and then again to print it. I would rather like to do sth like: System.out.printLater(s); //herejust leave a pointer to a StringBuilder you will build ... s.append("--------"); ... System.out.printAllDeferred(); I understand the above is probably in 99.99999% chances impossible, but perhaps you guys have a clever way of achieving the above?

    Read the article

  • Swapping switch-case in extra fle/data structure (Java)

    - by poeschlorn
    Hi guys, it may be a nooby question, but I've never needed it before: I have several strings and I want to compare them to given ones... At first glance it would lead to a switch/case construction in what every available entry is checked. Is there a more elegant way to swap those strings as key/value datas? greets, poeschlorn

    Read the article

  • Adapting pseudocode to java implementation for finding the longest word in a trie

    - by user1766888
    Referring to this question I asked: How to find the longest word in a trie? I'm having trouble implementing the pseudocode given in the answer. findLongest(trie): //first do a BFS and find the "last node" queue <- [] queue.add(trie.root) last <- nil map <- empty map while (not queue.empty()): curr <- queue.pop() for each son of curr: queue.add(son) map.put(son,curr) //marking curr as the parent of son last <- curr //in here, last indicate the leaf of the longest word //Now, go up the trie and find the actual path/string curr <- last str = "" while (curr != nil): str = curr + str //we go from end to start curr = map.get(curr) return str This is what I have for my method public static String longestWord (DTN d) { Queue<DTN> holding = new ArrayQueue<DTN>(); holding.add(d); DTN last = null; Map<DTN,DTN> test = new ArrayMap<DTN,DTN>(); DTN curr; while (!holding.isEmpty()) { curr = holding.remove(); for (Map.Entry<String, DTN> e : curr.children.entries()) { holding.add(curr.children.get(e)); test.put(curr.children.get(e), curr); } last = curr; } curr = last; String str = ""; while (curr != null) { str = curr + str; curr = test.get(curr); } return str; } I'm getting a NullPointerException at: for (Map.Entry<String, DTN> e : curr.children.entries()) How can I find and fix the cause of the NullPointerException of the method so that it returns the longest word in a trie?

    Read the article

  • Using enums in Java across multiple classes

    - by Richard Mar.
    I have the following class: public class Card { public enum Suit { SPACES, HEARTS, DIAMONDS, CLUBS }; public Card(Suit nsuit, int nrank) { suit = nsuit; rank = nrank; } private Suit suit; private int rank; } I want to instantiate it in another class, but that class doesn't understand the Suit enum. Where should I put the enum to make it publicly visible?

    Read the article

  • Memory increases with Java UDP Server

    - by Trevor
    I have a simple UDP server that creates a new thread for processing incoming data. While testing it by sending about 100 packets/second I notice that it's memory usage continues to increase. Is there any leak evident from my code below? Here is the code for the server. public class UDPServer { public static void main(String[] args) { UDPServer server = new UDPServer(15001); server.start(); } private int port; public UDPServer(int port) { this.port = port; } public void start() { try { DatagramSocket ss = new DatagramSocket(this.port); while(true) { byte[] data = new byte[1412]; DatagramPacket receivePacket = new DatagramPacket(data, data.length); ss.receive(receivePacket); new DataHandler(receivePacket.getData()).start(); } } catch (IOException e) { e.printStackTrace(); } } } Here is the code for the new thread that processes the data. For now, the run() method doesn't do anything. public class DataHandler extends Thread { private byte[] data; public DataHandler(byte[] data) { this.data = data; } @Override public void run() { System.out.println("run"); } }

    Read the article

  • java beginner- in which folder should I place a "database.properties" file

    - by Arvind
    I read some tutorials on how to read data from a database.properties file- which basically stored key-value pairs. What i want to know is, in which folder should I place this file? Is it in the root (ie "src") or within a package... And how do I access this file, if it is placed in "src"- my code will be within a package (and the package's directory will be under src)- so how do I access the properties file, which is in "src", from a class within a package?

    Read the article

  • Java - How to pass a Generic parameter as Class<T> to a constructor

    - by Joe Almore
    I have a problem here that still cannot solve, the thing is I have this abstract class: public abstract class AbstractBean<T> { private Class<T> entityClass; public AbstractBean(Class<T> entityClass) { this.entityClass = entityClass; }... Now I have another class that inherits this abstract: @Stateless @LocalBean public class BasicUserBean<T extends BasicUser> extends AbstractBean<T> { private Class<T> user; public BasicUserBean() { super(user); // Error: cannot reference user before supertype contructor has been called. } My question is how can I make this to work?, I am trying to make the class BasicUserBean inheritable, so if I have class PersonBean which inherits BasicUserBean then I could set in the Generic the entity Person which also inherits the entity BasicUser. And it will end up being: @Stateless @LocalBean public class PersonBean extends BasicUserBean<Person> { public PersonBean() { super(Person.class); } ... I just want to inherit the basic functionality from BasicUserBean to all descendants, so I do not have to repeat the same code among all descendants. Thanks!.

    Read the article

  • Help using recursion in Java

    - by Mercer
    I have a class Group. In the class I have two fields, idGroup IdGroupGroup. Groups may be part of other groups. My class Group is defined in a HashMap<Integer,Integer>; the key is IdGroupGroup and value is idGroup. I want to search the map for a particular idGroup; can I use recursion to do this?

    Read the article

  • Hash Tables - Java

    - by Antony
    Am about to do a homework, and i need to store quite a lot of information (Dictionary) in a data structure of my choice. I heard people in my classroom saying hash-tables are the way to go. How come?

    Read the article

  • Exception and Inheritance in JAVA

    - by user1759950
    Suppose we have this problem public class Father{ public void method1(){...} } public class Child1 extends Father{ public void method1() throws Exception{ super.method1(); ... } } Child1 extends Father and override method1 but given implementation Child1.method1 now throws a exception, this wont compile as override method can't throw new exceptions. What is the best solution? Propagate the required exception to the Father.. to me this is against encapsulation, inheritance and general OOP ( the father potentially throw and exception that will never happen ) Use a RuntimeException instead? This solution wont propagate the Exception to the father but I read In Oracle docs and others sources states class of exceptions should be used when "Client code cannot do anything" this is not that case, this exception will b useful to recover blablabla ( why is wrong to use RuntimeException instead? ) Other.. thanks, Federico

    Read the article

  • java switch case question

    - by hkvega
    public String sizeOfSupermarket() { String size; switch (this.numberOfProducts) { case (this.numberOfProducts > 5000): size = "Large"; break; case (this.numberOfProducts > 2000 && this.numberOfProducts < 5000): size = "Medium"; break; case (this.numberOfProducts < 2000): size = "Small"; break; } return size; } the above is wrong, how to write the compare statement in case statement?

    Read the article

  • How do I make java wait for boolean to run funciton

    - by TWeeKeD
    I'm sure this is pretty simple but I can't figure out and it sucks I'm up on suck on (what should be) an easy step. ok. I have a method that runs one function that give a response. this method actually handles the uploading of the file so o it takes a second to give a response. I need this response in the following method. sendPicMsg needs to complete and then forward it's response to sendMessage. Please help. b1.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { if(!uploadMsgPic.equalsIgnoreCase("")){ Log.v("response","Pic in storage"); sendPicMsg(); sendMessage(); }else{ sendMessage(); } 1st Method public void sendPicMsg(){ Log.v("response", "sendPicMsg Loaded"); if(!uploadMsgPic.equalsIgnoreCase("")){ final SharedPreferences preferences = this.getActivity().getSharedPreferences("MyPreferences", getActivity().MODE_PRIVATE); AsyncHttpClient client3 = new AsyncHttpClient(); RequestParams params3 = new RequestParams(); File file = new File(uploadMsgPic); try { File f = new File(uploadMsgPic.replace(".", "1.")); f.createNewFile(); //Convert bitmap to byte array Bitmap bitmap = decodeFile(file,400); ByteArrayOutputStream bos = new ByteArrayOutputStream(); bitmap.compress(CompressFormat.PNG, 0 /*ignored for PNG*/, bos); byte[] bitmapdata = bos.toByteArray(); //write the bytes in file FileOutputStream fos = new FileOutputStream(f); fos.write(bitmapdata); params3.put("file", f); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } params3.put("email", preferences.getString("loggedin_user", "")); params3.put("webversion", "1"); client3.post("http://peekatu.com/apiweb/msgPic_upload.php",params3, new AsyncHttpResponseHandler() { @Override public void onSuccess(String response) { Log.v("response", "Upload Complete"); refreshChat(); //responseString = response; Log.v("response","msgPic has been uploaded"+response); //parseChatMessages(response); response=picurl; uploadMsgPic = ""; if(picurl!=null){ Log.v("response","picurl is set"); } if(picurl==null){ Log.v("response", "picurl no ready"); }; } }); sendMessage(); } } 2nd Method public void sendMessage(){ final SharedPreferences preferences = this.getActivity().getSharedPreferences("MyPreferences", getActivity().MODE_PRIVATE); if(preferences.getString("Username", "").length()<=0){ editText1.setText(""); Toast.makeText(this.getActivity(), "Please Login to send messages.", 2); return; } AsyncHttpClient client = new AsyncHttpClient(); RequestParams params = new RequestParams(); if(type.equalsIgnoreCase("3")){ params.put("toid",user); params.put("action", "sendprivate"); }else{ params.put("room", preferences.getString("selected_room", "Adult Lobby")); params.put("action", "insert"); } Log.v("response", "Sending message "+editText1.getText().toString()); params.put("message",editText1.getText().toString() ); params.put("media", picurl); params.put("email", preferences.getString("loggedin_user", "")); params.put("webversion", "1"); client.post("http://peekatu.com/apiweb/messagetest.php",params, new AsyncHttpResponseHandler() { @Override public void onSuccess(String response) { refreshChat(); //responseString = response; Log.v("response", response); //parseChatMessages(response); if(picurl!=null) Log.v("response", picurl); } }); editText1.setText(""); lv.setSelection(adapter.getCount() - 1); }

    Read the article

< Previous Page | 315 316 317 318 319 320 321 322 323 324 325 326  | Next Page >