Search Results

Search found 7702 results on 309 pages for 'django validation'.

Page 32/309 | < Previous Page | 28 29 30 31 32 33 34 35 36 37 38 39  | Next Page >

• Django: How to create a model dynamically just for testing

  - by muhuk

  I have a Django app that requires a settings attribute in the form of: RELATED_MODELS = ('appname1.modelname1.attribute1', 'appname1.modelname2.attribute2', 'appname2.modelname3.attribute3', ...) Then hooks their post_save signal to update some other fixed model depending on the attributeN defined. I would like to test this behaviour and tests should work even if this app is the only one in the project (except for its own dependencies, no other wrapper app need to be installed). How can I create and attach/register/activate mock models just for the test database? (or is it possible at all?) Solutions that allow me to use test fixtures would be great.

  Read the article

• django-haystack ordering - How do I handle this?

  - by Bartek

  Hi there, I'm using django-haystack for a search page on my site. I'm basically done, but not quite happy with the ordering and not quite sure how haystack decides how to order everything. I know I can over-ride the SearchQuerySet by using order_by but that over-rides it entirely. Let's say I want to force the search to order by in stock (BooleanField), so that the products that are in stock show up on top, but then do everything else as it normally would. How do I do that? I tried doing order_by('-in_stock', 'content') figure content was what it used by default but it produces very different results from if I just leave it to do its own ordering. Thanks for any input on this matter!

  Read the article

• Django queries Especial Caracters

  - by Jorge Machado

  Hi, I Working on location from google maps and using django to. My question is: I have a String in request.GET['descricao'] lets say it contains "Via rapida". In my database i have store = "Via Rápida" i'm doing : local = Local.objects.filter(name__icontains=request.GET['descricao']) with that i can get everthing fine like "Via Rapida" but the result that have "Via rápida" never get match in the query (ASCI caracter may be ?) what must i do given a string "Via rapida" match "via rápida" and "via rapida" ? Regular Expressions ? how ? Thanks

  Read the article

• user model password field default password field in django

  - by imran-glt

  Hi, I've created a custom user model in my application. This user model is working fine, but there are a couple of problems I have with it. 1) The change password link in the my register.html page doesn't work? 2) The default password box on the add/edit page for a user is a little unfriendly. Ideally, what I'd like is the two password fields from the change password form on the add/edit user form in the admin, which will automatically turn convert the entered password into a valid encrypted password in Django. This would make the admin system MUCH friendlier and much more suited to my needs, as a fair number of user accounts will be created and maintained manually in this app, and the person responsible for doing so will likely be scared off at the sight of that admin field, or just type a clear text password and wonder why it doesn't work. Is this possible / How do I do this?

  Read the article

• Can this be done with the ORM? - Django

  - by RadiantHex

  Hi folks, I have a few item listed in a database, ordered through Reddit's algorithm. This is it: def reddit_ranking(post): t = time.mktime(post.created_on.timetuple()) - 1134000000 x = post.score if x>0: y=1 elif x==0: y=-0 else: y=-1 if x<0: z=1 else: z=x return (log(z) + y * t/45000) I'm wondering if there is any clever way of using Django's ORM, in order to UPDATE the models in bulk. Without doing this: items = Item.objects.filter(created_on__gte=datetime.now()-timedelta(days=7)) for item in items: item.reddit_rank = reddit_rank(item) item.save() I know about the F() object, but I can't figure out if this function can be performed inside the ORM. Any ideas? Help would be very much appreciated!

  Read the article

• Porting Django's templates engine to C

  - by sandra

  Hi folks, I recently wrote a simple and tiny embedded HTTP server for my C++ app (QT) and I played a little bit with Ry's http-parser and loved it. This guy is crazy. So I told to myself: "Hey! Why not port the django template engine to C?" That'd be awesome! I know, it won't be an easy task (not at all, I know) but I'd really love to implement this. So I came here for inspiration, ideas, opinions... I'd really love to have some pointers on the subject, ideas, what is already done, which major problems I'll encounter (and how to solve them) - How not to reinvent the wheel... anyway, you got the idea :) Thanks a million times! P.S. Simple code snippets, and links to tools and libs are very welcome! P.P.S. I'm already aware of grantlee, I took a look into its sources. Well... that's C++ and its specific to Qt.

  Read the article

• Django: ordering by backward related field property

  - by Silver Light

  Hello! I have two models related one-to-many: a Post and a Comment: class Post(models.Model): title = models.CharField(max_length=200); content = models.TextField(); class Comment(models.Model): post = models.ForeignKey('Post'); body = models.TextField(); date_added = models.DateTimeField(); I want to get a list of posts, ordered by the date of the latest comment. If I would write a custom SQL query it would look like this: SELECT `posts`.`*`, MAX(`comments`.`date_added`) AS `date_of_lat_comment` FROM `posts`, `comments` WHERE `posts`.`id` = `comments`.`post_id` GROUP BY `posts`.`id` ORDER BY `date_of_lat_comment` DESC How can I do same thing using django ORM?

  Read the article

• How to limit choice field options based on another choice field in django admin

  - by umnik700

  I have the following models: class Category(models.Model): name = models.CharField(max_length=40) class Item(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) class Demo(models.Model): name = models.CharField(max_length=40) category = models.ForeignKey(Category) item = models.ForeignKey(Item) In the admin interface when creating a new Demo, after user picks category from the dropdown, I would like to limit the number of choices in the "items" drop-down. If user selects another category then the item choices should update accordingly. I would like to limit item choices right on the client, before it even hits the form validation on the server. This is for usability, because the list of items could be 1000+ being able to narrow it down by category would help to make it more manageable. Is there a "django-way" of doing it or is custom JavaScript the only option here?

  Read the article

• Edit the opposite side of a many to many relationship with django generic form

  - by Ed

  I have two models: class Actor(models.Model): name = models.CharField(max_length=30, unique = True) event = models.ManyToManyField(Event, blank=True, null=True) class Event(models.Model): name = models.CharField(max_length=30, unique = True) long_description = models.TextField(blank=True, null=True) In a previous question: http://stackoverflow.com/questions/2503243/django-form-linking-2-models-by-many-to-many-field, I created an EventForm with a save function: class EventForm(forms.ModelForm): class Meta: model = Event def save(self, commit=True): instance = forms.ModelForm.save(self) instance.actors_set.clear() for actor in self.cleaned_data['actors']: instance.actors_set.add(actors) return instance This allowed me to add m2m links from the other side of the defined m2m connection. Now I want to edit the entry. I've been using a generic function: def generic_edit(request, modelname, object_id): modelname = modelname.lower() form_class = form_dict[modelname] return update_object(request, form_class = form_class, object_id = object_id, template_name = 'createdit.html' ) but this pulls in all the info except the many-to-many selections saved to this object. I think I need to do something similar to this: http://stackoverflow.com/questions/1700202/editing-both-sides-of-m2m-in-admin-page, but I haven't figured it out. How do I use the generic update_object to edit the other side of many-to-many link?

  Read the article

• Evaluating Django Chained QuerySets Locally

  - by jnadro52

  Hello All: I am hoping someone can help me out with a quick question I have regarding chaining Django querysets. I am noticing a slow down because I am evaluating many data points in the database to create data trends. I was wondering if there was a way to have the chained filters evaluated locally instead of hitting the database. Here is a (crude) example: pastries = Bakery.objects.filter(productType='pastry') # <--- will obviously always hit DB, when evaluated cannoli = pastries.filter(specificType='cannoli') # <--- can this be evaluated locally instead of hitting the DB when evaluated, as long as pastries was evaluated? I have checked the docs and I do not see anything specifying this, so I guess it's not possible, but I wanted to check with the 'braintrust' first ;-). BTW - I know that I can do this myself by implementing some methods to loop through these datapoints and evaluate the criteria, but there are so many datapoints that my deadline does not permit me manually implementing this. Thanks in advance.

  Read the article

• How do I find the "concrete class" of a django model baseclass

  - by Mr Shark

  I'm trying to find the actual class of a django-model object, when using model-inheritance. Some code to describe the problem: class Base(models.model): def basemethod(self): ... class Child_1(Base): pass class Child_2(Base): pass If I create various objects of the two Child classes and the create a queryset containing them all: Child_1().save() Child_2().save() (o1, o2) = Base.objects.all() I want to determine if the object is of type Child_1 or Child_2 in basemethod, I can get to the child object via o1.child_1 and o2.child_2 but that reconquers knowledge about the childclasses in the baseclass. I have come up with the following code: def concrete_instance(self): instance = None for subclass in self._meta.get_all_related_objects(): acc_name = subclass.get_accessor_name() try: instance = self.__getattribute__(acc_name) return instance except Exception, e: pass But it feels brittle and I'm not sure of what happens when if I inherit in more levels.

  Read the article

• ImportError and Django driving me crazy

  - by John Peebles

  OK, I have the following directory structure (it's a django project): - project -- app and within the app folder, there is a scraper.py file which needs to reference a class defined within models.py I'm trying to do the following: import urllib2 import os import sys import time import datetime import re import BeautifulSoup sys.path.append('/home/userspace/Development/') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from project.app.models import ClassName and this code just isn't working. I get an error of: Traceback (most recent call last): File "scraper.py", line 14, in from project.app.models import ClassName ImportError: No module named project.app.models This code above used to work, but broke somewhere along the line and I'm extremely confused as to why I'm having problems. On SnowLeopard using python2.5.

  Read the article

• Django database caching

  - by hekevintran

  I have a Django form that uses an integer field to lookup a model object by its primary key. The form has a save() method that uses the model object referred to by the integer field. The model's manager's get() method is called twice, once in the clean method and once in the save() method: class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is the first call to get MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): id_a = self.cleaned_data['id_a'] # here is the second call to get my_model_object = MyModel.objects.get(id=id_a) # do other stuff I wasn't sure whether this hits the database two times or one time so I returned the object itself in the clean method so that I could avoid a second get() call. Does calling get() hit the database two times? Or is the object cached in the thread? class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is my workaround return MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): # looking up the cleaned value returns the model object my_model_object = self.cleaned_data['id_a'] # do other stuff

  Read the article

• In django models, how to make all table names not have the app label?

  - by Luigi

  I have a database that was already being used by other applications before i began writing a web interface with django for it. The table names follow simple naming standards, so the django model Customer should map to the table "customer" in the db. At the same time I'm adding new tables/models. Since I find it cumbersome to use app_customer every time i have to write a query (django's ORM is definitely not enough for them) in the other applications and I don't want to rename the existing tables, what is the best way to make all models in my django app use tables without applabel_, besides adding a Meta class with db_table= to each model? Is there any reason why I shouldn't do this? I have only one web app that needs to access this db, everything else doesn't use django models.

  Read the article

• how to change display text in django admin foreignkey dropdown

  - by FurtiveFelon

  Hi all, I have a task list, with ability to assign users. So i have foreignkey to User model in the database. However, the default display is username in the dropdown menu, i would like to display full name (first last) instead of the username. If the foreignkey is pointing to one of my own classes, i can just change the str function in the model, but User is a django authentication model, so i can't easily change it directly right? Anyone have any idea how to accomplish this? Thanks a lot!

  Read the article

• Incremement Page Hit Count in Django

  - by Andrew C

  I have a table with an IntegerField (hit_count), and when a page is visited (ie. http://site/page/3) I want record id 3 'hit_count' column in the database to increment by 1. The query should be like: update table set hit_count = hit_count + 1 where id=3 Can I do this with the standard Django Model conventions? Or should I just write the query by hand? I'm starting a new project, so I am trying to avoid hacks. We'll see how long this lasts! Thanks!

  Read the article

• Django: cannot pass variable to included template?

  - by duy

  Hi, I got a problem where I want to use template including in Django. Here is the real example: I got 3 file: home.html (will get the context variable passed from Views), base.html (the skeleton template file) and the header.html (included by base.html). If if put the code below directly in base.html without including the header.html, the {{title}} variable passing from home is correctly called. But if I include the header.html in base.html, the {{title}} variable's value cannot be called. <title>{% block title %}{% endblock %} | {{ SITE_INFO_TITLE }}</title> Is there any solution to this problem? Thanks.

  Read the article

• Django gives "I/O operation on closed file" error when reading from a saved ImageField

  - by Rob Osborne

  I have a model with two image fields, a source image and a thumbnail. When I update the new source image, save it and then try to read the source image to crop/scale it to a thumbnail I get an "I/O operation on closed file" error from PIL. If I update the source image, don't save the source image, and then try to read the source image to crop/scale, I get an "attempting to read from closed file" error from PIL. In both cases the source image is actually saved and available in later request/response loops. If I don't crop/scale in a single request/response loop but instead upload on one page and then crop/scale in another page this all works fine. This seems to be a cached buffer being reused some how, either by PIL or by the Django file storage. Any ideas on how to make an ImageField readable after saving?

  Read the article

• I get a 400 Bad Request error while using django-piston

  - by Cheezo

  Hello, I am trying to use Piston to provide REST support to Django. I have implemented my handlers as per the documentation provided . The problem is that i can "read" and "delete" my resource but i cannot "create" or "update". Each time i hit the relevant api i get a 400 Bad request Error. I have extended the Resource class for csrf by using this commonly available code snippet: class CsrfExemptResource(Resource): """A Custom Resource that is csrf exempt""" def init(self, handler, authentication=None): super(CsrfExemptResource, self).init(handler, authentication) self.csrf_exempt = getattr(self.handler, 'csrf_exempt', True) My class (code snippet) looks like this: user_resource = CsrfExemptResource(User) class User(BaseHandler): allowed_methods = ('GET', 'POST', 'PUT', 'DELETE') @require_extended def create(self, request): email = request.GET['email'] password = request.GET['password'] phoneNumber = request.GET['phoneNumber'] firstName = request.GET['firstName'] lastName = request.GET['lastName'] self.createNewUser(self, email,password,phoneNumber,firstName,lastName) return rc.CREATED Please let me know how can i get the create method to work using the POST operation?

  Read the article

• Correct redirect after posting comment - django comments framework

  - by Sachin

  I am using django comments framework for allowing users to comment on my site, but there is a problem with the url to which user is redirected after posting the comment. If I render my comment form as {% with comment.content_object.get_absolute_url as next %} {% render_comment_form for comment.content_object %} {% endwith %} Then the url to which it is redirected after the comment is posted is <comment.content_object.get_absolute_url/?c=<comment.id> For example I posted a comment on a post with url /post/256/a-new-post/ then the url to which I am redirected after posting the comment is /post/256/a-new-post/?c=99 where assume 99 is the id comment just posted. Instead what I want is something like this /post/256/a-new-post/#c99. Secondly when I do comment.get_absolute_url() I do not get the proper url instead I get a url like /comments/cr/58/14/#c99 and this link is broken. How can I get the correct url as mentioned in the documentation. Am i doing something wrong. Any help is appreciated.

  Read the article

• Django adminsite customize search_fields query

  - by dArignac

  Howdy! In the django admin you can set the search_fields for the ModelAdmin to be able to search over the properties given there. My model class has a property that is not a real model property, means it is not within the database table. The property relates to another database table that is not tied to the current model through relations. But I want to be able to search over it, so I have to somehow customize the query the admin site creates to do the filtering when the search field was filled - is this possible and if, how? I can query the database table of my custom property and it then returns the ids of the model classes fitting the search. This then, as I said, has to flow into the admin site search query. Thanks!

  Read the article

• replace values in form.data when form fails validation

  - by John

  Hi I have a form field which requires a json object as its value when it is rendered. When the form is submitted it returns a comma seperated string of ids as its value (not a json string). however if the form does not validate i want to turn this string of ids back into a json string so it will display properly (is uses jquery to render the json object correctly). how would i do this? I was thinking of overwriting the form.clean method but when I tried to change self.data['fieldname'] I got the error 'This QueryDict instance is immutable' and when i tried to change self.cleaned_data['fieldname'] it didn't make a difference to the value of the field. Thanks

  Read the article

• Django User "per project" group assignation

  - by Ben G

  Hi, Here's my problem : my site has users, which can create projects, and access other user's projects. Each project can assign different rights to users. So, i could have Project A : user "John" is in group "manager" , and Project "B" user "John" is in group "worker". How could I use the Django User authentication model to do that ? From a SQL point a view, what i would like is to be able to add "project_id" in the primary key for the "auth_user_groups" table. I don't think profile is of any help here. Any advice ? UPDATE : "worker" and "manager" are just two examples of the permission group (or "roles") that my application defines. There will be more in the future. Eg : i will probably also have "admin", "reporting", etc...

  Read the article

• Django paging object has issues with Postgresql QuerySets

  - by pivotal

  I have some django code that runs fine on a SQLite database or on a MySQL database, but it runs into problems with Postgres, and it's making me crazy that no one has has this issue before. I think it may also be related to the way querysets are evaluated by the pager. In a view I have: def index(request, page=1): latest_posts = Post.objects.all().order_by('-pub_date') paginator = Paginator(latest_posts, 5) try: posts = paginator.page(page) except (EmptyPage, InvalidPage): posts = paginator.page(paginator.num_pages) return render_to_response('blog/index.html', {'posts' : posts}) And inside the template: {% for post in posts.object_list %} {# some rendering jazz #} {% endfor %} This works fine with SQLite, but Postgres gives me: Caught TypeError while rendering: 'NoneType' object is not callable To further complicate things, when I switch the Queryset call to: latest_posts = Post.objects.all() Everything works great. I've tried re-reading the documentation, but found nothing, although I admit I'm a bit clouded by frustration at this point. What am I missing? Thanks in advance.

  Read the article

• Not work variables in django templates

  - by ??????? ???????

  My context dictionary not sending to my templates. I have function from django.shortcuts import render_to_response def home(request): return render_to_response('home.html',{'test':'test'}) and i have simple template such as: <html> <body> my test == {{test}} </body> </html> When i open my site in browser, i have "my test == ". settings.py is default. I dont use something custom. What the problem? Server is apache with wsgi module.

  Read the article

< Previous Page | 28 29 30 31 32 33 34 35 36 37 38 39  | Next Page >