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  • c printing string syntax

    - by user535256
    Hello guys, Just stuck on c syntax regarding strings. Say I have a string like (name[5]="peter";) in c say if I just wanted to print the last character of string or check the last character of the string, which in this case would be 'r' how can I do this? The way I was thinking does not seem to work name[5]="peter"; if(name[5]=="r") printf("last character of name is r"); Question: is there some sort of function to do this that can check one character of array, is a certain value, like name[5] is 'r' in string peter or likewise name[1] is 'n' Also how do I use printf to print that certain char, having problems using printf("last character of name is %s",name[5]) ??? Thanks

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  • printing reverse in singly link list using pointers

    - by theoneabhinav
    i have been trying this code. i think the logic is ok but the program terminates abruptly when the display_rev function is called here is code of display_rev void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } } here is my whole code #include<stdio.h> #include<stdlib.h> #include<ctype.h> #include<string.h> //Declarations=============================================================== typedef struct //employee record { int emp_id; char name[150]; char mob_no[11]; float salary; int proj[5]; struct emp_node *next; } emp_node; emp_node* add_rec(emp_node*); emp_node* create_db(emp_node*); emp_node* search_db(emp_node*, int); emp_node* delete_rec(emp_node*, int); void read_name(emp_node*); void read_mob(emp_node*); void display_db(emp_node*); void display_rec(emp_node*); void display_rev(emp_node*); void modify_rec(emp_node*); void swtch(emp_node*); //=========================================================================== int main() { char ans; emp_node *head = NULL; head = create_db(head); display_db(head); do { swtch(head); printf("\n\n\tDo you want to continue (y/n) : "); getchar(); scanf("%c", &ans); } while (ans == 'y' || ans == 'Y'); return 0; } //Definitions================================================================ emp_node* create_db(emp_node *head) //database creation { int i = 1, no; emp_node *p; printf("Enter number of employees:"); scanf("%d", &no); printf("\n\n"); head = (emp_node *) malloc(sizeof(emp_node)); head = add_rec(head); head->next = NULL; p = head; while (i < no) { p->next = (emp_node *) malloc(sizeof(emp_node)); p = p->next; p = add_rec(p); p->next = NULL; i++; } return head; } emp_node* add_rec(emp_node *p) //new record { int j; printf("\n\tEmployee ID : "); scanf("%d", &(p->emp_id)); printf("\n\tFirst Name:"); read_name(p); printf("\n\tMobile No.:"); read_mob(p); printf("\n\tSalary :"); scanf("%f", &(p->salary)); printf( "\n\tEnter \"1\" for the projects employee is working on, otherwise enter \"0\": \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1 && p->proj[j] != 0) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } printf("\n\n\n"); return p; } void read_name(emp_node *p) //validation for name { int j, len; scanf("%s", p->name); len = strlen(p->name); for (j = 0; j < len; j++) { if (!isalpha(p->name[j])) { printf( "\n\n\tInvalid name!!Can contain only characters. Please Re-enter.\n"); printf("\n\tName : "); read_name(p); } } } void read_mob(emp_node *p) //validation for mobile no. { int j; scanf("%s", p->mob_no); while (strlen(p->mob_no) != 10) { printf("\n\nInvalid Mobile No!!Please Re-enter"); printf("\n\n\tMobile No.:"); read_mob(p); } for (j = 0; j < 10; j++) { if (!(48 <= p->mob_no[j] && p->mob_no[j] <= 57)) { printf( "\n\nInvalid Mobile No!!Can contain only digits. Please Re-enter."); printf("\n\n\tMobile No.:"); read_mob(p); } } } void display_db(emp_node *head) //displaying whole database { emp_node *p; p = head; printf("\n\n\t\t****** EMPLOYEE DATABASE ******\n"); printf( "\n=============================================================================="); printf("\n Id.\t Name\t\t Mobile No\t Salary\t Projects\n"); while (p != NULL) { display_rec(p); p = p->next; printf("\n\n\n"); } printf( "\n=============================================================================="); } void swtch(emp_node *head) //function for menu and switch case { int cho, x; emp_node *p; printf("\n\n\t\t****** MENU ******"); printf( "\n\n\t1. insert Record\n\t2. Search Record\n\t3. Modify Record\n\t4. Delete Record\n\t5. Display Reverse\n\t6. Exit"); printf("\n\tWhich operation do you want to perform? "); scanf("%d", &cho); switch (cho) { case 1: p=head; while(p->next != NULL) p=p->next; p->next = (emp_node *) malloc(sizeof(emp_node)); p=p->next; p = add_rec(p); p->next = NULL; display_db(head); break; case 2: printf("\n\n\tEnter employee ID whose record is to be Searched :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else display_rec(p); break; case 3: printf("\n\n\tEnter employee ID whose record is to be modified :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else modify_rec(p); display_db(head); break; case 4: printf("\n\n\tEnter employee ID whose record is to be deleted :"); scanf("%d", &x); head = delete_rec(head, x); display_db(head); break; case 5: display_rev(head); case 6: exit(0); default: printf("Invalid Choice!! Please try again."); } } emp_node* search_db(emp_node *head, int id) //search database { emp_node *p = head; while (p != NULL) { if (p->emp_id == id) return p; p = p->next; } return NULL; } void display_rec(emp_node *p) //display a single record { int j; printf("\n %d", p->emp_id); printf("\t %10s", p->name); printf("\t %10s", p->mob_no); printf("\t %05.2f", p->salary); printf("\t "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } } void modify_rec(emp_node *p) //modifying a record { int j, cho; char ch1, edt; do { printf( "\n\t1. Name\n\t2. Email Address\n\t3. Mobile No.\n\t4. Salary\n\t5. Date of birth\n\t6. Projects\n"); printf("Enter your choice : "); scanf("%d", &cho); switch (cho) { case 1: printf("\n\tPrevious name:%s", p->name); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Name:"); read_name(p); } break; case 2: printf("\n\tPrevious Mobile No. : %s", p->mob_no); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Mobile No. :"); read_mob(p); } break; case 3: printf("\n\tPrevious salary is : %f", p->salary); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New salary:"); scanf("%f", &(p->salary)); } break; case 4: printf("the employee is currently working on project no. "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf( "\n\tEnter \"1\" for the projects employee is working on : \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } } break; default: printf("\n\nInvalid Choice!! Please Try again."); } printf("\n\nDo you want to edit any other fields ?(y/n)"); getchar(); scanf("%c", &edt); } while (edt == 'y' || edt == 'Y'); } emp_node* delete_rec(emp_node *head, int id) //physical deletion of record { emp_node *p = head, *q; if (head->emp_id == id) { head = head->next; free(p); return head; } else { q = p->next; while (q->emp_id != id) { p = p->next; q = q->next; } if (q->next == NULL) p->next = NULL; else p->next = q->next; free(q); return head; } } void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } }

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  • Printing contents of a div

    - by Hulk
    The contents of the following div re derived dynamically. i.e, A table is added dynamically to this div with some button .My question is how to print the content of this div(window.print) and not other things in the page <div id="newdiv" name="newdiv"></div> Thanks..............

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  • Printing array with delimiters in Perl

    - by Mark B
    I have an array in Perl I want to print with space delimiters between each element, except every 10th element which should be newline delimited. There aren't any spaces in the elements if that matters. I've written a function to do it with for and a counter, but I wondered if there's a better/shorter/canonical Perl way, perhaps a special join syntax or similar. My function to illustrate: sub PrintArrayWithNewlines { my $counter = 0; my $newlineIndex = shift @_; foreach my $item (@_) { ++$counter; print "$item"; if($counter == $newlineIndex) { $counter = 0; print "\n"; } else { print " "; } } }

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  • Printing to STDOUT and log file while removing ANSI color codes

    - by Arrieta
    I have the following functions for colorizing my screen messages: def error(string): return '\033[31;1m' + string + '\033[0m' def standout(string): return '\033[34;1m' + string + '\033[0m' I use them as follows: print error('There was a problem with the program') print "This is normal " + standout("and this stands out") I want to log the output to a file (in addition to STDOUT) WITHOUT the ANSI color codes, hopefully without having to add a second "logging" line to each print statement. The reason is that if you simply python program.py > out then the file out will have the ANSI color codes, which look terrible if you open in a plain text editor. Any advice?

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  • Super class variables not printing through sub class

    - by Abhishek Singh
    Can u tell me why this code is not displaying any result on the console. class employee { protected String name; protected double salary; protected String dob; public employee(String name, double salary, String dob) { this.name = name; this.salary = salary; this.dob = dob; } public employee(String name, double salary) { this.name = name; this.salary = salary; } } public class Manage extends employee { String dept1; public Manage(String name, double salary, String dob, String dept1) { super(name, salary, dob); this.dept1 = dept1; } public Manage(String name, double salary, String dept1) { super(name, salary); this.dept1 = dept1; } public static void main(String args[]) { employee e = new employee("Vikas", 122345); employee e2 = new employee("Vikas", 122345, "12-2-1991"); Manage m = (Manage) new Manage("Vikas", 122345, "Sales"); Manage m2 = new Manage("Vikas", 122345, "12-2-1991", "sales"); m.display(); m2.display(); } public void display() { System.out.println("Name " + name); System.out.println("Salary " + salary); System.out.println("Birth " + dob); System.out.println("Department " + dept1); } }

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  • problem in printing fonts

    - by user1400
    hello i have a application on php that i show a report in the table , i want to print this page i can see my page fine in print preview , but when i send thuis page to printer ,the fonts are small and diffrent fonts that i set in css file this is my css file @page { size: A4 landscape; margin-top:2cm; margin-bottom:1cm; margin-left:1cm; margin-right:1cm; } table.print{ text-align:right; border:#999 1px solid; } table.print td.e1{ border-top:#999 1px solid; padding:5px 2px; text-align: right; font-size: 20pt; font-family:"stencil"; } table.print td.e2{ border-top:#999 1px solid; padding:5px 2px; text-align: right; font-size: 120%; font-family:"tahoma"; } thanks

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  • Automatic printing through IE6

    - by Richard
    We have a requirement to auto print dockets from a webpage. We are developing a stock control application using ASP.NET, MVC2 using IE6 Scenerio is as follows: Once the user has completed the order, a docket should be automatically printed. At the moment, I am using Javascript command "window.print();" method however the print dialog button is displayed. Is there a way to stop the print dialog button from showing and the docket will be automatically printed?

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  • printing uid of a file on linux system

    - by neo730
    i am learning c programming. I am trying to make my own program similar to ls command but with less options.what i am doing is taking input directory/file name as argument and then gets all directory entry with dirent struct(if it is directory) . After it i use stat() to take all information of the file but here is my problem when i use write() to print these value its fine but when i want to print these with printf() i get warninng : format ‘%ld’ expects type ‘long int’, but argument 2 has type ‘__uid_t’. I don't know what should use at place of %ld and also for other special data types.

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  • printing long compilation lines with MS NMAKE

    - by Elazar Leibovich
    I have a legacy MS NMAKE Makefile I need to fix a few bugs in. There are some very long command lines I wish to debug that are being executed using the NMAKE trick of "inline files": dep: cmd @<<tmpfilename cmd_args.. << When changing the line to dep: echo cmd @<<tmpfilename cmd_args.. << NMAKE complains that the line is too long. Is there any other trick I can apply in order to view the command line NMAKE is actually executing?

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  • Arrays- Square root of an Array and printing the result JAVA

    - by roger34
    Hello, The title says it all, really. I'm trying to get an array of (9) numbers squared then printed but I keep coming back with only one result - the number of numbers in the array squared- obviously not what I want. Thanks for any help. Ok, here is my terrible code so far. Trying to pass it to a method as well. public static void main ( String args[] ) { double[] nums = {126, 12.939, 795, 320.16, 110, 34.7676, 7773, 67, 567, 323}; System.out.println ("Square root is " +square); square(nums); } public static double square (double [] array) { double result; for( double i = 0; i < array.length ; i++ ) result = Math.sqrt(array[i]); return result; } }

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  • What's the difference between logging and printing to the console

    - by Ankur
    This is kind of a philosophical question. Basically people often ask if I am logging - and since I am not a full time programmer, but someone who programs often but is actually more of a requirements analyst, I don't know all the best practices. I use Java a lot so I often do things like System.out.println() What's the difference in theory between the two? Ultimately aren't I also logging? Esp, if I prefix my comments with something like "ERROR:" or "WARN:" ?

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  • Nicely printing/showing a binary tree in Haskell

    - by nicole
    I have a tree data type: data Tree a b = Branch b (Tree a b) (Tree a b) | Leaf a ...and I need to make it an instance of Show, without using deriving. I have found that nicely displaying a little branch with two leaves is easy: instance (Show a, Show b) => Show (Tree a b) where show (Leaf x) = show x show (Branch val l r) = " " ++ show val ++ "\n" ++ show l ++ " " ++ show r But how can I extend a nice structure to a tree of arbitrary size? It seems like determining the spacing would require me to know just how many leaves will be at the very bottom (or maybe just how many leaves there are in total) so that I can allocate all the space I need there and just work 'up.' I would probably need to call a size function. I can see this being workable, but is that making it harder than it is?

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  • macro function for printing

    - by seven
    Hi, if for example i have : define PRINT(x) fprintf(stderr, x); and in code i append it : PRINT(("print this")) output is : [print this] if i append it : PRINT(("print %s", "this")) output is : [this] could someone explain me why it receives just the "this" argument and not the whole string ?

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  • Printing with fixed spaces

    - by eriks
    I want to print two strings (say "ABC" and "DEF") with 5 space characters before "ABC" and that the second string will start 7 characters after the beginning of the first string.

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  • Printing a field with additional dots in haskell

    - by Frank Kluyt
    I'm writing a function called printField. This function takes an int and a string as arguments and then then prints a field like this "Derp..." with this: printField 7 "Derp". When the field consists of digits the output should be "...3456". The function I wrote looks like this: printField :: Int -> String -> String printField x y = if isDigit y then concat(replicate n ".") ++ y else y ++ concat(replicate n ".") where n = x - length y This obviously isn't working. The error I get from GHC is: Couldn't match type `[Char]' with `Char' Expected type: Char Actual type: String In the first argument of `isDigit', namely `y' In the expression: isDigit y In the expression: if isDigit y then concat (replicate n ".") ++ y else y ++ concat (replicate n ".") I can't get it to work :(. Can anyone help me out? Please keep in mind that I'm new to Haskell and functional programming in general.

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  • Problem in printing array of char pointer passing from Python

    - by Yan Cheng CHEOK
    My following C code works quite well, till my Python code trying to pass an array of char pointer to it. The output I obtain is The file_name is python-file Another 3 string is not being printed out. Anything I had missed out? C Code #include <iostream> #include "c_interface.h" int foo(const char* file_name, const char** names) { std::cout << "The file_name is " << file_name << std::endl; while (*names) { std::cout << "The name is " << *names << std::endl; names++; } return 0; } /* int main() { const char *c[] = {"123gh", "456443432", "789", 0}; foo("hello", c); getchar(); } */ Python Code #!c:/Python27/python.exe -u from ctypes import * name0 = "NAME0" name1 = "NAME1" name2 = "NAME2" names = ((c_char_p * 1024) * 4)() names[0].value = name0 names[1].value = name1 names[2].value = name2 names[3].value = 0 libc = CDLL("foo.dll") libc.foo("python-file", names)

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  • lua string printing

    - by anon
    In C, I have format strings, something like: char *msg = "wlll you marry me" fprintf(stderr, "%s, %s?", name, msg); Now, can I do something similar in lua with format strings? I.e. I want something functionally equivalent to: name .. ", " .. msg .. "?" but not so ugly, in lua. Okay, so I can do string.format("%s, %s?", name, msg), but can I go even a step further, something like perl style, where I can go: "%name, %msg?" Thanks!

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  • Printing a string and variable in MIPS

    - by Matt
    Here's the C representation of what I'm trying to do in MIPS assembly: printf ("x=%d\n", x); I know that I can do a syscall to easily print x= and I can also do a syscall to print the int x (which is stored in a register). However, that prints them like this (let's say x is 5): x= 5 How can I make them print on the same line?

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  • Printing a Project in NetBeans

    - by Infestor
    i have an exam and i would like to print my java (in netbeans project) files as fast as possible. i was wondering is there a way to print an entire project/project in netbeans with one click? or do you have a better suggestion? (i will be using windows xp and there is no nice editor like gedit installed)

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  • jquery not printing the image in IE 6

    - by pradeep
    if(count > 0){ for(var i= parseInt(start); i < parseInt(count); i++) { link ='<a href="/diabetes/ropimages/origpicdisplay.php?pid='+pid+'&rid='+i+'" target="_blank"><img src="/diabetes/ropimages/thumbpicdisplay.php?pid='+pid+'&rid='+i+'"/><a>&nbsp;&nbsp;'; if(i > start){ $("#content1").append(link);} else{ $("#content1").empty().html(link);} } } i use code like this. it does print images in FF but not in IE6 any solutions for this ?

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  • Reading strings and integers from .txt file and printing output as strings only

    - by screename71
    Hello, I'm new to C++, and I'm trying to write a short C++ program that reads lines of text from a file, with each line containing one integer key and one alphanumeric string value (no embedded whitespace). The number of lines is not known in advance, (i.e., keep reading lines until end of file is reached). The program needs to use the 'std::map' data structure to store integers and strings read from input (and to associate integers with strings). The program then needs to output string values (but not integer values) to standard output, 1 per line, sorted by integer key values (smallest to largest). So, for example, suppose I have a text file called "data.txt" which contains the following three lines: 10 dog -50 horse 0 cat -12 zebra 14 walrus The output should then be: horse zebra cat dog walrus I've pasted below the progress I've made so far on my C++ program: #include <fstream> #include <iostream> #include <map> using namespace std; using std::map; int main () { string name; signed int value; ifstream myfile ("data.txt"); while (! myfile.eof() ) { getline(myfile,name,'\n'); myfile >> value >> name; cout << name << endl; } return 0; myfile.close(); } Unfortunately, this produces the following incorrect output: horse cat zebra walrus If anyone has any tips, hints, suggestions, etc. on changes and revisions I need to make to the program to get it to work as needed, can you please let me know? Thanks!

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  • Printing out series of numbers in java

    - by Jay
    hi guys i am just doing some reading for myself to learn java and came across this problem and is currently stuck. i need to print out series of number based on the input given by the user. for example, if input = 5, the output should be as follows @1@22@333@4444@55555 import java.util.*; public class ex5{ public static void main(String[] args){ Scanner kb = new Scanner(System.in); System.out.println("Please type a #: "); int input = kb.nextInt(); for(int i=0;i<input;i++){ if(input==1){ System.out.print("@1"); } if(input==2){ System.out.print("@1@22"); } } } } this doesnt seem to be working because this is the output i get Please type a #: 2 @1@22@1@22 im not sure what to put inside the for loop right now and i dont think i am using the for loop here very well either... any help guys?

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