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  • How can I transfer a user state of a win7 machine that won't boot?

    - by askvictor
    I have a windows 7 machine that won't boot completely, even in safe mode. I want to re-image the machine using a generic software image, but would like to keep the user data (including settings etc) that are on there ala Windows Easy Transfer. I can mount the hard disk on another machine - can I use Easy Transfer to transfer the user state of an account on the non-booted OS? Or do I need explore USMT?

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  • Sql Query - Selecting rows where user can be both friend and user

    - by Gublooo
    Hey Sorry the title is not very clear. This is a follow up to my earlier question where one of the members helped me with a query. I have a following friends Table Friend friend_id - primary key user_id user_id_friend status The way the table is populated is - when I send a friend request to John - my userID appears in user_id and Johns userID appears in user_id_friend. Now another scenario is say Mike sends me a friend request - in this case mike's userID will appear in user_id and my userID will appear in user_id_friend So to find all my friends - I need to run a query to find where my userID appears in both user_id column as well as user_id_friend column What I am trying to do now is - when I search for user say John - I want all users Johns listed on my site to show up along with the status of whether they are my friend or not and if they are not - then show a "Add Friend" button. Based on the previous post - I got this query which does part of the job - My example user_id is 1: SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id = u.user_id and f.user_id_friend = 1 where u.name like '%' So this only shows users with whom I am friends where they have sent me request ie my userID appears in user_id_friend. Although I am friends with others (where my userID appears in user_id column) - this query will return that as null To get those I need another query like this SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id_friend = u.user_id and f.user_id = 1 where u.name like '%' So how do I combine these queries to return 1 set of users and what my friendship status with them is. I hope my question is clear Thanks

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  • Why do I get Detached Entity exception when upgrading Spring Boot 1.1.4 to 1.1.5

    - by mmeany
    On updating Spring Boot from 1.1.4 to 1.1.5 a simple web application started generating detached entity exceptions. Specifically, a post authentication inteceptor that bumped number of visits was causing the problem. A quick check of loaded dependencies showed that Spring Data has been updated from 1.6.1 to 1.6.2 and a further check of the change log shows a couple of issues relating to optimistic locking, version fields and JPA issues that have been fixed. Well I am using a version field and it starts out as Null following recommendation to not set in the specification. I have produced a very simple test scenario where I get detached entity exceptions if the version field starts as null or zero. If I create an entity with version 1 however then I do not get these exceptions. Is this expected behaviour or is there still something amiss? Below is the test scenario I have for this condition. In the scenario the service layer that has been annotated @Transactional. Each test case makes multiple calls to the service layer - the tests are working with detached entities as this is the scenario I am working with in the full blown application. The test case comprises four tests: Test 1 - versionNullCausesAnExceptionOnUpdate() In this test the version field in the detached object is Null. This is how I would usually create the object prior to passing to the service. This test fails with a Detached Entity exception. I would have expected this test to pass. If there is a flaw in the test then the rest of the scenario is probably moot. Test 2 - versionZeroCausesExceptionOnUpdate() In this test I have set the version to value Long(0L). This is an edge case test and included because I found reference to Zero values being used for version field in the Spring Data change log. This test fails with a Detached Entity exception. Of interest simply because the following two tests pass leaving this as an anomaly. Test 3 - versionOneDoesNotCausesExceptionOnUpdate() In this test the version field is set to value Long(1L). Not something I would usually do, but considering the notes in the Spring Data change log I decided to give it a go. This test passes. Would not usually set the version field, but this looks like a work-around until I figure out why the first test is failing. Test 4 - versionOneDoesNotCausesExceptionWithMultipleUpdates() Encouraged by the result of test 3 I pushed the scenario a step further and perform multiple updates on the entity that started life with a version of Long(1L). This test passes. Reinforcement that this may be a useable work-around. The entity: package com.mvmlabs.domain; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.Table; import javax.persistence.Version; @Entity @Table(name="user_details") public class User { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; @Version private Long version; @Column(nullable = false, unique = true) private String username; @Column(nullable = false) private Integer numberOfVisits; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public Long getVersion() { return version; } public void setVersion(Long version) { this.version = version; } public Integer getNumberOfVisits() { return numberOfVisits == null ? 0 : numberOfVisits; } public void setNumberOfVisits(Integer numberOfVisits) { this.numberOfVisits = numberOfVisits; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } The repository: package com.mvmlabs.dao; import org.springframework.data.repository.CrudRepository; import com.mvmlabs.domain.User; public interface UserDao extends CrudRepository<User, Long>{ } The service interface: package com.mvmlabs.service; import com.mvmlabs.domain.User; public interface UserService { User save(User user); User loadUser(Long id); User registerVisit(User user); } The service implementation: package com.mvmlabs.service; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.stereotype.Service; import org.springframework.transaction.annotation.Propagation; import org.springframework.transaction.annotation.Transactional; import org.springframework.transaction.support.TransactionSynchronizationManager; import com.mvmlabs.dao.UserDao; import com.mvmlabs.domain.User; @Service @Transactional(propagation=Propagation.REQUIRED, readOnly=false) public class UserServiceJpaImpl implements UserService { @Autowired private UserDao userDao; @Transactional(readOnly=true) @Override public User loadUser(Long id) { return userDao.findOne(id); } @Override public User registerVisit(User user) { user.setNumberOfVisits(user.getNumberOfVisits() + 1); return userDao.save(user); } @Override public User save(User user) { return userDao.save(user); } } The application class: package com.mvmlabs; import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.EnableAutoConfiguration; import org.springframework.context.annotation.ComponentScan; import org.springframework.context.annotation.Configuration; @Configuration @ComponentScan @EnableAutoConfiguration public class Application { public static void main(String[] args) { SpringApplication.run(Application.class, args); } } The POM: <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mvmlabs</groupId> <artifactId>jpa-issue</artifactId> <version>0.0.1-SNAPSHOT</version> <packaging>jar</packaging> <name>spring-boot-jpa-issue</name> <description>JPA Issue between spring boot 1.1.4 and 1.1.5</description> <parent> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-parent</artifactId> <version>1.1.5.RELEASE</version> <relativePath /> <!-- lookup parent from repository --> </parent> <dependencies> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-data-jpa</artifactId> </dependency> <dependency> <groupId>org.hsqldb</groupId> <artifactId>hsqldb</artifactId> <scope>runtime</scope> </dependency> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-test</artifactId> <scope>test</scope> </dependency> </dependencies> <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> <start-class>com.mvmlabs.Application</start-class> <java.version>1.7</java.version> </properties> <build> <plugins> <plugin> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-maven-plugin</artifactId> </plugin> </plugins> </build> </project> The application properties: spring.jpa.hibernate.ddl-auto: create spring.jpa.hibernate.naming_strategy: org.hibernate.cfg.ImprovedNamingStrategy spring.jpa.database: HSQL spring.jpa.show-sql: true spring.datasource.url=jdbc:hsqldb:file:./target/testdb spring.datasource.username=sa spring.datasource.password= spring.datasource.driverClassName=org.hsqldb.jdbcDriver The test case: package com.mvmlabs; import org.junit.Assert; import org.junit.Test; import org.junit.runner.RunWith; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.boot.test.SpringApplicationConfiguration; import org.springframework.test.context.junit4.SpringJUnit4ClassRunner; import com.mvmlabs.domain.User; import com.mvmlabs.service.UserService; @RunWith(SpringJUnit4ClassRunner.class) @SpringApplicationConfiguration(classes = Application.class) public class ApplicationTests { @Autowired UserService userService; @Test public void versionNullCausesAnExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version Null"); user.setNumberOfVisits(0); user.setVersion(null); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(1L), user.getVersion()); } @Test public void versionZeroCausesExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version Zero"); user.setNumberOfVisits(0); user.setVersion(0L); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(1L), user.getVersion()); } @Test public void versionOneDoesNotCausesExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version One"); user.setNumberOfVisits(0); user.setVersion(1L); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(2L), user.getVersion()); } @Test public void versionOneDoesNotCausesExceptionWithMultipleUpdates() throws Exception { User user = new User(); user.setUsername("Version One Multiple"); user.setNumberOfVisits(0); user.setVersion(1L); user = userService.save(user); user = userService.registerVisit(user); user = userService.registerVisit(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(3), user.getNumberOfVisits()); Assert.assertEquals(new Long(4L), user.getVersion()); } } The first two tests fail with detached entity exception. The last two tests pass as expected. Now change Spring Boot version to 1.1.4 and rerun, all tests pass. Are my expectations wrong? Edit: This code saved to GitHub at https://github.com/mmeany/spring-boot-detached-entity-issue

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  • Struts2 Hibernate Login with User table and group table

    - by J2ME NewBiew
    My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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  • Couldn't drop privileges: User is missing UID (see mail_uid setting)

    - by drecute
    I'm hoping I can use some help. I'm configuring dovecot_ldap, but I can't seem to be able to get dovecot to authenticate the ldap user. Below is my config and log info: hosts = 192.168.128.45:3268 dn = cn=Administrator,cn=Users,dc=company,dc=example,dc=com dnpass = "passwd" auth_bind = yes ldap_version = 3 base = dc=company, dc=example, dc=com user_attrs = sAMAccountName=home=/var/vmail/example.com/%$,uid=1001,gid=1001 user_filter = (&(sAMAccountName=%Ln)) pass_filter = (&(ObjectClass=person)(sAMAccountName=%u)) dovecot.conf # 2.0.19: /etc/dovecot/dovecot.conf # OS: Linux 3.2.0-33-generic x86_64 Ubuntu 12.04 LTS auth_mechanisms = plain login auth_realms = example.com auth_verbose = yes disable_plaintext_auth = no mail_access_groups = mail mail_location = mbox:~/mail:INBOX=/var/mail/%u mail_privileged_group = mail passdb { driver = pam } passdb { driver = passwd } passdb { args = /etc/dovecot/dovecot-ldap.conf.ext driver = ldap } passdb { args = scheme=CRYPT username_format=%u /etc/dovecot/users driver = passwd-file } protocols = " imap pop3" service auth { unix_listener /var/spool/postfix/private/auth { group = postfix mode = 0660 user = postfix } } service imap-login { inet_listener imap { port = 143 } inet_listener imaps { port = 993 ssl = yes } } ssl_cert = </etc/ssl/certs/dovecot.pem ssl_key = </etc/ssl/private/dovecot.pem userdb { driver = passwd } userdb { args = /etc/dovecot/dovecot-ldap.conf.ext driver = ldap } userdb { args = username_format=%u /etc/dovecot/users driver = passwd-file } protocol imap { imap_client_workarounds = tb-extra-mailbox-sep imap_logout_format = bytes=%i/%o mail_plugins = } mail.log Nov 29 10:51:44 mail dovecot: auth-worker: pam(charyorde,10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:44 mail dovecot: auth-worker: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:44 mail dovecot: auth: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:44 mail dovecot: imap-login: Login: user=<charyorde>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, mpid=1892, TLS Nov 29 10:51:44 mail dovecot: imap(charyorde): Error: user charyorde: Couldn't drop privileges: User is missing UID (see mail_uid setting) Nov 29 10:51:44 mail dovecot: imap(charyorde): Error: Internal error occurred. Refer to server log for more information. Nov 29 10:51:46 mail dovecot: auth-worker: pam(charyorde,10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:46 mail dovecot: auth-worker: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:46 mail dovecot: auth: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:46 mail dovecot: imap-login: Login: user=<charyorde>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, mpid=1894, TLS Nov 29 10:51:46 mail dovecot: imap(charyorde): Error: user charyorde: Couldn't drop privileges: User is missing UID (see mail_uid setting) Nov 29 10:51:46 mail dovecot: imap(charyorde): Error: Internal error occurred. Refer to server log for more information. Nov 29 10:51:48 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:48 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:51:48 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:51:48 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:51:54 mail postfix/smtpd[1880]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1879]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1886]: proxymap stream disconnect Nov 29 10:51:54 mail postfix/smtpd[1887]: proxymap stream disconnect Nov 29 10:51:54 mail postfix/smtpd[1886]: auto_clnt_close: disconnect private/tlsmgr stream Nov 29 10:51:54 mail postfix/smtpd[1887]: auto_clnt_close: disconnect private/tlsmgr stream Nov 29 10:51:54 mail postfix/smtpd[1887]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1886]: idle timeout -- exiting Nov 29 10:51:56 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:56 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:51:56 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:51:56 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:52:04 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:52:06 mail dovecot: imap-login: Disconnected (auth failed, 3 attempts): user=<[email protected]>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, TLS Thank you for looking into this.

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  • How to migrate user settings and data to new machine?

    - by torbengb
    I'm new to Ubuntu and recently started using it on my PC. I'm going to replace that PC with a new machine. I want to transfer my data and settings to the nettop. What aspects should I consider? Obviously I want to move my data over. What things am I missing if I only copy the entire home folder? This is a home pc (not corporate) so user rights and other security issues are not a concern, except that the files should be accessible on the new machine! Please take into account that the new machine is a nettop that doesn't have an optical drive and doesn't allow me to hook the old SATA disk into it, so any data transfer must be handled via home network (I can have both the old and the new machine turned on and connected to the home LAN) and I have an USB thumbdrive with limited capacity (2GB). This sounds like it might limit the general applicability, but it would in fact make it more general. I'll make this a wiki topic because there could be several "right" answers. Update: Or so I thought. I don't see a choice for that.

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  • How do I set up an sftp user to login with a password to an EC2 ubuntu server ?

    - by Doron
    Hello, I have an Ubuntu Server running on an EC2 instance. To login to that server I use a certificate file without any password. I've installed and configured vsftpd and created a user (let's call him "testuser") for which I've set a /bin/false ssh terminal so it will only be able to connect via sftp and upload/access files on his home directory. However - when I try to connect to the server from my computer, running sftp testuser@my-ec2-server I get Permission denied (publickey). Connection closed messages so I can't log in. How can I remove the certificate requirement for this user only (meaning, the "ubuntu" user will still have to use the certificate file to login via ssh), so normal sftp clients will be able to connect using a username and a password ? Thank you. PS Using Ubuntu Server 10.10 official AMI from canonical, 64bit on a micro instance.

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  • "log on as a batch job" user rights removed by what GPO?

    - by LarsH
    I am not much of a server administrator, but get my feet wet when I have to. Right now I'm running some COTS software on a Windows 2008 Server machine. The software installer creates a few user accounts for running its processes, and then gives those users the right to "log on as a batch job". Every so often (e.g. yesterday at 2:52pm and this morning at 7:50am), those rights disappear. The software then stops working. I can verify that the user rights are gone by using secedit /export /cfg e:\temp\uraExp.inf /areas USER_RIGHTS and I have a script that does this every 30 seconds and logs the results with a timestamp, so I know when the rights disappear. What I see from the export is that in the "good" state, i.e. after I install the software and it's working correctly, the line for SeBatchLogonRight from the secedit export includes the user accounts created by the software. But every few hours (sometimes more), those user accounts are removed from that line. The same thing can be seen by using the GUI tool Local Security Policy > Security Settings > Local Policies > User Rights Assignment > Log on as a batch job: in the "good" state, that policy includes the needed user accounts, and in the bad state, the policy does not. Based on the above-mentioned logging script and the timestamps at which the user rights are being removed, I can see clearly that some GPOs are causing the change. The GPO Operational log shows GPOs being processed at exactly the right times. E.g.: Starting Registry Extension Processing. List of applicable GPOs: (Changes were detected.) Local Group Policy I have run GPOs on demand using gpupdate /force, and was able to verify that this caused the User Rights to be removed. We have looked over local group policies till our eyes are crossed, trying to figure out which one might be stripping these User Rights to "log on as a batch job." We have not configured any local group policies on this machine, that we know of; so is there a default local group policy that might typically do such a thing? Are there typical domain policies that would do this? I have been working with our IT staff colleagues to troubleshoot the problem, but none of them are really GPO experts... They wear many hats, and they do what they need to do in order to keep most things running. Any suggestions would be greatly appreciated!

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  • Degrading administrative privilege to standard with single admin user account

    - by Vivek S Panicker
    I recently met with a severe issue with user accounts. In my system, there is only administrator user named vivek. I added another user with name vivi and changed its privilege to administrator. After clicked on my username, vivek,and changed its privilege to standard. Since vivek is being the current user, I dropped with all administrator privileges. No password was set for the new administrator user vivi and hence it was disabled by default. I no longer access to any administrative activities. Later I corrected this by editing etc/group file. Isn't this a severe bug? Being the current administrator user, how could I degrade myself to a standard user and got out from administrator's seat? I did not get any warning messages indicating no other administrators exists to manage my system. I suggest this warning should be included there in user accounts when an administrator user changes his privilege without any enabled administrators. Your thoughts?

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  • PL-SQL - Two statements with begin and end, run fine seperately but not together?

    - by Twiss
    Hi all, Just wondering if anyone can help with this, I have two PLSQL statements for altering tables (adding extra fields) and they are as follows: -- Make GC_NAB field for Next Action By Dropdown begin if 'VARCHAR2' = 'NUMBER' and length('VARCHAR2')>0 and length('')>0 then execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NAB VARCHAR2(10, ))'; elsif ('VARCHAR2' = 'NUMBER' and length('VARCHAR2')>0 and length('')=0) or 'VARCHAR2' = 'VARCHAR2' then execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NAB VARCHAR2(10))'; else execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NAB VARCHAR2)'; end if; commit; end; -- Make GC_NABID field for Next Action By Dropdown begin if 'NUMBER' = 'NUMBER' and length('NUMBER')>0 and length('')>0 then execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NABID NUMBER(, ))'; elsif ('NUMBER' = 'NUMBER' and length('NUMBER')>0 and length('')=0) or 'NUMBER' = 'VARCHAR2' then execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NABID NUMBER())'; else execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NABID NUMBER)'; end if; commit; end; When I run these two queries seperately, no problems. However, when run together as shown above, Oracle gives me an error when it starts the second statement: Error report: ORA-06550: line 15, column 1: PLS-00103: Encountered the symbol "BEGIN" 06550. 00000 - "line %s, column %s:\n%s" *Cause: Usually a PL/SQL compilation error. *Action: I'm assuming that this means the first statement is not terminated properly... is there anything I should put inbetween the statements to make it work properly? Thanks in advance everyone!

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  • Using the @ in SQL Azure Connections

    - by BuckWoody
    The other day I was working with a client on an application they were changing to a hybrid architecture – some data on-premise and other data in SQL Azure and Windows Azure Blob storage. I had them make a couple of corrections - the first was that all communications to SQL Azure need to be encrypted. It’s a simple addition to the connection string, depending on the library you use. Which brought up another interesting point. They had been using something that looked like this, using the .NET provider: Server=tcp:[serverName].database.windows.net;Database=myDataBase; User ID=LoginName;Password=myPassword; Trusted_Connection=False;Encrypt=True; This includes most of the formatting needed for SQL Azure. It specifies TCP as the transport mechanism, the database name is included, Trusted_Connection is off, and encryption is on. But it needed one more change: Server=tcp:[serverName].database.windows.net;Database=myDataBase; User ID=[LoginName]@[serverName];Password=myPassword; Trusted_Connection=False;Encrypt=True; Notice the difference? It’s the User ID parameter. It includes the @ symbol and the name of the server – not the whole DNS name, just the server name itself. The developers were a bit surprised, since it had been working with the first format that just used the user name. Why did both work, and why is one better than the other? It has to do with the connection library you use. For most libraries, the user name is enough. But for some libraries (subject to change so I don’t list them here) the server name parameter isn’t sent in the way the load balancer understands, so you need to include the server name right in the login, so the system can parse it correctly. Keep in mind, the string limit for that is 128 characters – so take the @ symbol and the server name into consideration for user names. The user connection info is detailed here: http://msdn.microsoft.com/en-us/library/ee336268.aspx Upshot? Include the @servername on your connection string just to be safe. And plan for that extra space…  

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  • What Parallel computing APIs make good use of sockets?

    - by Ole Jak
    My program uses sockets, what Parallel computing APIs could I use that would help me without obligating me to go from sockets to anything else? When we are on a cluster with a special, non-socket infrastructure system this API would emulate something like sockets but using that infrastructure (so programs perform much faster than on sockets, but still use the sockets API).

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  • Simulating user activities on a GMail page

    - by Vitaliy
    I create a program that simulates me browsing to gmail, entering the user name and password and clicking the submit button. All this with C#. I would appreciate two kinds of answers: One that tells how to do this programaticaly. Since I may be interested in automating more sophisticated user activities. On that tells me about a program that already does that. Thanks!!

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  • How to detect user agent in WCF web service

    - by Kangkan
    How can I detect the user agent in a web service? My web service is implemented using a WCF webservice with basicHTTPBinding. It will be a post from some SOAP clients. I wish to know the user-agent from the clients. I shall like to see some sample code for this.

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  • Django: How to get current user in admin forms

    - by lazerscience
    In Django's ModelAdmin I need to display forms customized according to the permissions an user has. Is there a way of getting the current user object into the form class, so that i can customize the form in its __init__ method? I think saving the current request in a thread local would be a possibility but this would be my last resort think I'm thinking it is a bad design approach....

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  • Best practices for custom http user-agent strings?

    - by Noufal Ibrahim
    I'm developing an application that communicates with an internal web service using HTTP. Are there any "best practices" for custom user-agent strings so that I can put a nice one in my app? It's a Python library and the lower transport is Python's own httplib. Should the user-agent string say that or something else?

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  • How do you test the usability of your user interfaces

    - by Martin
    How do you test the usability of the user interfaces of your applications - be they web or desktop? Do you just throw it all together and then tweak it based on user experience once the application is live? Or do you pass it to a specific usability team for testing prior to release? We are a small software house, but I am interested in the best practices of how to measure usability. Any help appreciated.

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  • Django microblog showing a logged in user only his posts

    - by dana
    i have a miniblog application, with a class named New(refering to a new post), having a foreign key to an user(who has posted the entry). above i have a method that displays all the posts from all the users. I'd like to show to the logged in user, only his posts How can i do it? Thanks in advance! def paginate(request): paginator = New.objects.all() return render_to_response('news/newform.html', { 'object_list': paginator, }, context_instance=RequestContext(request))

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  • Writing user stories for internal technical tasks

    - by John Nolan
    I am attempting to manage my projects a little better so I am looking at attempting to apply some of (eventually all) the features of scrum. Looking at user stories specifically the high level format seems to be: As a User I can Feature Description or Artifact is Doing Something How would I write "Upgrade the Database"? Is it simply Upgrade the Database? I think I am being thrown off as there is no specific actor/customer and that the customer is the IT department.

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  • User accounts in Symfony?

    - by gruner
    I'm new to Symfony. Is my understanding correct that the User class is actually for controlling sessions? But is there built-in login and account creation? I'm not finding it. But if there's an admin backend generator, how can it function without user logins?

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  • problem in batch script read user input

    - by JCH
    hi, i use set /p below to read user input it seems to work outside the if block but the one inside if block doesn't work. When i run the script second time the user input in the if block prints the previous user input. test script: @echo off set cond=true echo %cond% if %cond%==true ( echo "cond is true" REM the below input doesn't work set /p name1="enter your name" echo name is: %name1% ) REM it works here set /p name2="enter your name" echo name is: %name2% thank you

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