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  • MySQL: difference of two result sets

    - by Zombies
    How can I get the set difference of two result sets? Say I have a result set (just one column in each): result1: 'a' 'b' 'c' result2: 'b' 'c' I want to minus what is in result1 by result2: result1 - result2 such that it equals: difference of result1 - result2: 'a'

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  • Is there anything wrong with having a few private methods exposing IQueryable<T> and all public meth

    - by Nate Bross
    I'm wondering if there is a better way to approach this problem. The objective is to reuse code. Let’s say that I have a Linq-To-SQL datacontext and I've written a "repository style" class that wraps up a lot of the methods I need and exposes IQueryables. (so far, no problem). Now, I'm building a service layer to sit on top of this repository, many of the service methods will be 1<-1 with repository methods, but some will not. I think a code sample will illustrate this better than words. public class ServiceLayer { MyClassDataContext context; IMyRepository rpo; public ServiceLayer(MyClassDataContext ctx) { context = ctx; rpo = new MyRepository(context); } private IQueryable<MyClass> ReadAllMyClass() { // pretend there is some complex business logic here // and maybe some filtering of the current users access to "all" // that I don't want to repeat in all of the public methods that access // MyClass objects. return rpo.ReadAllMyClass(); } public IEnumerable<MyClass> GetAllMyClass() { // call private IQueryable so we can do attional "in-database" processing return this.ReadAllMyClass(); } public IEnumerable<MyClass> GetActiveMyClass() { // call private IQueryable so we can do attional "in-database" processing // in this case a .Where() clause return this.ReadAllMyClass().Where(mc => mc.IsActive.Equals(true)); } #region "Something my class MAY need to do in the future" private IQueryable<MyOtherTable> ReadAllMyOtherTable() { // there could be additional constrains which define // "all" for the current user return context.MyOtherTable; } public IEnumerable<MyOtherTable> GetAllMyOtherTable() { return this.ReadAllMyOtherTable(); } public IEnumerable<MyOtherTable> GetInactiveOtherTable() { return this.ReadAllMyOtherTable.Where(ot => ot.IsActive.Equals(false)); } #endregion } This particular case is not the best illustration, since I could just call the repository directly in the GetActiveMyClass method, but let’s presume that my private IQueryable does some extra processing and business logic that I don't want to replicate in both of my public methods. Is that a bad way to attack an issue like this? I don't see it being so complex that it really warrants building a third class to sit between the repository and the service class, but I'd like to get your thoughts. For the sake of argument, lets presume two additional things. This service is going to be exposed through WCF and that each of these public IEnumerable methods will be calling a .Select(m => m.ToViewModel()) on each returned collection which will convert it to a POCO for serialization. The service will eventually need to expose some context.SomeOtherTable which wont be wrapped into the repository.

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  • Left outer join in LINQ is showing exception

    - by stackuser3
    The folloqing is the excpetion I am getting The null value cannot be assigned to a member with type System.Int32 which is a non-nullable value type. below is my LINQ Statement where QuestionId is the primary key in my table var questionViewsData = from questionViews in objDc.SC_QuestionsViews join questions in objDc.SC_Questions on questionViews.QuestionId equals questions.QuestionId into qs from questions in qs.DefaultIfEmpty() where questionViews.CreatedDate.Date == new DateTime(2010, 4,27) select new { Selected =(questions == null ?-1:questions.QuestionId), QuestioinTitle = questions.Title, VotesCount = questions.VotesCount }; Let me know how to resolve this

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  • Mutable objects and hashCode

    - by robert
    Have the following class: public class Member { private int x; private long y; private double d; public Member(int x, long y, double d) { this.x = x; this.y = y; this.d = d; } @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + x; result = (int) (prime * result + y); result = (int) (prime * result + Double.doubleToLongBits(d)); return result; } @Override public boolean equals(Object obj) { if (this == obj) { return true; } if (obj instanceof Member) { Member other = (Member) obj; return other.x == x && other.y == y && Double.compare(d, other.d) == 0; } return false; } public static void main(String[] args) { Set<Member> test = new HashSet<Member>(); Member b = new Member(1, 2, 3); test.add(b); System.out.println(b.hashCode()); b.x = 0; System.out.println(b.hashCode()); Member first = test.iterator().next(); System.out.println(test.contains(first)); System.out.println(b.equals(first)); System.out.println(test.add(first)); } } It produces the following results: 30814 29853 false true true Because the hashCode depends of the state of the object it can no longer by retrieved properly, so the check for containment fails. The HashSet in no longer working properly. A solution would be to make Member immutable, but is that the only solution? Should all classes added to HashSets be immutable? Is there any other way to handle the situation? Regards.

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  • Javascript: find array by name

    - by Kin
    Hi, I have some js arrays and I want to find the arrays by name. for example: arr1 = [1,2,3]; arr2 = [3,4,5]; And access them like this: var intNum = 2; var arrName = 'arr' + intNum; arrName[0]; // equals 3 Is this possible? Thanks, Kevin

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  • Counting comma seperated values in php,how to?

    - by Jay
    Hey folks, I have a variable holding values separated by a comma (Implode), I'm trying to get the total count of the values in that variable however, count() is just returning 1. I've tried converting the comma separated values to a properly formatted array which still spits out1. So heres the quick snippet where the sarray session equals to value1,value2,value3: $schools = $_SESSION['sarray']; $result = count($schools); Any help would be appreciated.

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  • How to use Groovy Set for unique elements?

    - by Guy
    As simple as this must be I still can't understand where am I wrong: class A { boolean equals(o) { true } } def s = [new A(), new A()] as Set assert s.size() == 1 // Assertion failed: actually gives 2 Which method should I override in order to get uniqueness?

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  • Object value not getting updated in the database using hibernate

    - by user1662917
    I am using Spring,hibernate,jsf with jquery in my application. I am inserting a Question object in the database through the hibernate save query . The question object contains id ,question,answertype and reference to a form object using form_id. Now I want to alter the values of Question object stored in the database by altering the value stored in the list of Question objects at the specified index position. If I alter the value in the list the value in the database is not getting altered by update query . Could you please advise. Question.java package com.otv.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.ManyToOne; import javax.persistence.Table; import org.apache.commons.lang.builder.ToStringBuilder; @Entity @Table(name = "questions") public class Question implements Serializable { @Id @GeneratedValue @Column(name = "id", unique = true, nullable = false) private int id; @Column(name = "question", nullable = false) private String text; @Column(name = "answertype", nullable = false) private String answertype; @ManyToOne(fetch = FetchType.EAGER) @JoinColumn(name = "form_id") private Form form; // @JoinColumn(name = "form_id") // private int formId; public Question() { } public Question(String text, String answertype) { this.text = text; this.answertype = answertype; } public int getId() { return id; } public void setId(int id) { this.id = id; } public String getQuestion() { return text; } public void setQuestion(String question) { this.text = question; } public String getAnswertype() { return answertype; } public void setAnswertype(String answertype) { this.answertype = answertype; } @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + ((answertype == null) ? 0 : answertype.hashCode()); result = prime * result + id; result = prime * result + ((text == null) ? 0 : text.hashCode()); return result; } @Override public boolean equals(Object obj) { if (this == obj) return true; if (obj == null) return false; if (getClass() != obj.getClass()) return false; Question other = (Question) obj; if (answertype == null) { if (other.answertype != null) return false; } else if (!answertype.equals(other.answertype)) return false; if (id != other.id) return false; if (text == null) { if (other.text != null) return false; } else if (!text.equals(other.text)) return false; return true; } public void setForm(Form form) { this.form = form; } @Override public String toString() { return ToStringBuilder.reflectionToString(this); } } Form.java package com.otv.model; import java.io.Serializable; import java.util.ArrayList; import java.util.List; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.OneToMany; import javax.persistence.Table; import org.apache.commons.lang.builder.ToStringBuilder; @Entity @Table(name = "FORM") public class Form implements Serializable { @Id @GeneratedValue @Column(name = "id", unique = true, nullable = false) private int id; @Column(name = "name", nullable = false) private String name; @Column(name = "description", nullable = false) private String description; @OneToMany(mappedBy = "form", fetch = FetchType.EAGER, cascade = CascadeType.ALL) List<Question> questions = new ArrayList<Question>(); public Form(String name) { super(); this.name = name; } public Form() { super(); } public int getId() { return id; } public void setId(int id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } public String getDescription() { return description; } public void setDescription(String description) { this.description = description; } public List<Question> getQuestions() { return questions; } public void setQuestions(List<Question> formQuestions) { this.questions = formQuestions; } public void addQuestion(Question question) { questions.add(question); question.setForm(this); } public void removeQuestion(Question question) { questions.remove(question); question.setForm(this); } @Override public String toString() { return ToStringBuilder.reflectionToString(this); } public void replaceQuestion(int index, Question question) { Question prevQuestion = questions.get(index); // prevQuestion.setQuestion(question.getQuestion()); // prevQuestion.setAnswertype(question.getAnswertype()); question.setId(prevQuestion.getId()); question.setForm(this); questions.set(index, question); } } QuestionDAO.java package com.otv.user.dao; import java.util.List; import org.hibernate.SessionFactory; import com.otv.model.Question; public class QuestionDAO implements IQuestionDAO { private SessionFactory sessionFactory; public SessionFactory getSessionFactory() { return sessionFactory; } public void setSessionFactory(SessionFactory sessionFactory) { this.sessionFactory = sessionFactory; } public void addQuestion(Question question) { getSessionFactory().getCurrentSession().save(question); } public void deleteQuestion(Question question) { getSessionFactory().getCurrentSession().delete(question); } public void updateQuestion(Question question) { getSessionFactory().getCurrentSession().update(question); } public Question getQuestionById(int id) { List list = getSessionFactory().getCurrentSession().createQuery("from Questions where id=?") .setParameter(0, id).list(); return (Question) list.get(0); } }

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  • error with linq join

    - by Luca Romagnoli
    I have this linq query: var segreterie = from s in db.USR_Utenti join h in db.USR_Accounts on new {s.ID, settings.GruppoSegreteria} equals new {h.USR_UtentiReference,h.ID_Gruppo} select s; that has this problem: The type of one of the expressions in the join clause is incorrect. Type inference failed in the call to 'Join'. how can i do to solve it?

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  • Remove Item From Object SubList (LINQ)

    - by X3074861X
    I have an object that looks like this : public class Consortium { public string Id { get; set; } [JsonConverter(typeof(EnumDescriptionConverter))] public SourceType Type { get; set; } public List<UserLibrary> Branches { get; set; } } Each Consortium has a list of UserLibrary's associated with it, and that class looks like this : public class UserLibrary { public string LibraryId { get; set; } public string RetailerId {get; set;} public string UserId { get; set; } public string Name { get; set; } public DateTime CreatedAt { get; set; } } I have a method which will allow the user to remove a library from one of their consortium (note: There may be many branches associated to the consortium). However, I'm only being supplied a LibraryId, so I'm forced to traverse their list of Consortium, find which one contains the given id, then iterate over the branches and remove the one that matches the id. Here is how I'm currently accomplishing this : // Get the current list of consortiums var user = _mediator.Send(new GetUserProfileCommand { UserProfileId = _principle.UserProfileId }); var userConsortia = user.SavedConsortia; // the consortium to remove the library from var branchToRemove = _libraryService.GetLibrary(id); var consortRemove = new UserConsortium(); foreach (var userConsortium in userConsortia) { if (userConsortium.Branches.FirstOrDefault(c => string.Equals(c.LibraryId, id, StringComparison.OrdinalIgnoreCase)) != null) { consortRemove = userConsortium; } } // if the consortium id is null, something is f* if (consortRemove.Id == null) { return new JsonDotNetResult(HttpStatusCode.BadRequest); } // first remove the consortia userConsortia.Remove(consortRemove); // remove the branch from the consortium consortRemove.Branches.RemoveAll(ul => string.Equals(ul.LibraryId, id, StringComparison.OrdinalIgnoreCase)); // add it back in without the branch userConsortia.Add(consortRemove); Question : Is there a LINQ expression I'm missing here that can help me consolidate this logic, or is there a better way of doing this?

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  • why use the "!!!"?

    - by lazyanno
    as follow codes: var a = {}; if(!!!a[tabType]){ a[tabType] = []; a[tabType].push([self,boxObj]); }else{ a[tabType].push([self,boxObj]); } i think !!!a[tabType] equals !a[tabType] why use the "!!!" not "!" ? thank you!

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  • [C#] How to do a search from a list with non-prefix keywords

    - by aNui
    First of all, sorry if my english or my post got any mistakes. I am programming a program to search the name from the list and I need to find them if the keyword is not in front of the names (that's what I mean non-prefix) e.g. if I my list is the music instruments and I type "guit" to the search textbox. It should find the names "Guitar, Guitarrón, Acoustic Guitar, Bass Guitar, ..." or something like this Longdo Dictionary's search suggestion. here is my simple and stupid algorithm (that's all I can do) const int SEARCHROWLIMIT = 30; private string[] DoSearch(string Input, string[] ListToSearch) { List<string> FoundNames = new List<string>(); int max = 0; bool over = false; for (int k = 0; !over; k++) { foreach (string item in ListToSearch) { max = (max > item.Length) ? max : item.Length; if (k > item.Length) continue; if (k >= max) { over = true; break; } if (!Input.Equals("Search") && item.Substring(k, item.Length - k).StartsWith(Input, StringComparison.OrdinalIgnoreCase)) { bool exist = false; int i = 0; while (!exist && i < FoundNames.Count) { if (item.Equals(FoundNames[i])) { exist = true; break; } i++; } if (!exist && FoundNames.Count < SEARCHROWLIMIT) FoundNames.Add(item); else if (FoundNames.Count >= SEARCHROWLIMIT) over = true; } } } return FoundNames.ToArray(); } I think this algorithm is too slow for a large number of names and after several trial-and-error, I decided to add SEARCHROWLIMIT to breaks the operation And I also think there're some readymade methods that can do that. And another problem is I need to search music instruments by a category like strings, percussions, ... and by the country of origins. So I need to search them with filter by type and country. please help me. P.S. Me and my friends are just student from Thailand and developing the project to compete in Microsoft Imagine Cup 2010 and please become fan on our facebook page [KRATIB][3]. And we're so sorry we don't have much information in English but you can talk to us in English.

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  • Beginner Android Dev question navigating through intents, getting errors not sure how to fix it. I've tried rearranging and everything even tabbing.

    - by user554786
    /*I created this Sign-In page. I start by declaring variables for username/password & buttons. If user enters "test" as username & "test" as password and hits the login button, its supposed to go to the DrinksTwitter.class activity, else throw error message I created. To me the code and login makes perfect sense. I'm not sure why it wont go to the next activity I want it to go to */ package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); // Check Login String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); if(username.equals("test") && password.equals("test")){ final Intent i = new Intent(Screen2.this, DrinksTwitter.class); btnLogin.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(i); } // lblResult.setText("Login successful."); else { /* ERROR- Syntax error on token "else", { expected */ lblResult.setText("Invalid username or password."); } } }); final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); } }); /* ERROR- Syntax error, insert "}" to complete Statement*/ } }

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  • avoid NullPointerException at the first cycle

    - by user1508419
    I have this piece of code: EventSnapshot snapshotEvent = new EventSnapshot(); EventSnapshot currentEvent = new EventSnapshot(); do { ... currentEvent.setContent(in_stats); ... if(!snapshotEvent.equals(currentEvent)) snapshotEvent.setContent(in_stats); } while(true); At the first cycle I get a NullPointerException because obviously the object snapshotEvent is empty. At the second cycle this doesn't happen.how can avoid this problem?

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  • Censoring selected words (replacing them with ****) using a single replaceAll?

    - by aioobe
    I'd like to censor some words in a string by replacing each character in the word with a "*". Basically I would want to do String s = "lorem ipsum dolor sit"; s = s.replaceAll("ipsum|sit", $0.length() number of *)); so that the resulting s equals "lorem ***** dolor ***". I know how to do this with repeated replaceAll invokations, but I'm wondering, is this possible to do with a single replaceAll?

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  • When To Use IEquatable And Why

    - by ChloeRadshaw
    I just dont understand this - What does IEuqtable buy you exactly?? The only reason I can see it being useful is when creating a generic type and forcing users to implement and write a good equals method. What am I missing

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  • ordering by a property on a joined table linq to sql

    - by Gazeth
    I have the following linq query from o in context.Opportunities join i in context.Interactions on o.OpportunityID equals i.OpportunityID into ints from i in ints.DefaultIfEmpty() orderby i.StatusID descending, o.StatusID descending select o Now i want to then do a distinct on the opportunities table but doing so removes my orderby. I know that you can do Distinct().OrderBy but how do i get a reference to the interactions table that was joined when I'm only selecting the opportunity entity?

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  • Java lang object

    - by Neeraj
    why java Object class has two methods hashcode() and equals()? One of them looks redundant and its percolated to the bottom most derived class?

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  • concurrentmodificationexception hashmap in java

    - by chetan
    I write following code but when this run it generate concurrentmodificationexception if( attendancePolicy.getType().equals( AttendanceConstants.EMPLOYEE_ATTENDANCE_POLICY ) ) { synchronized( attendancePolicy.getListEmployee() ) { for( EmployeeAttendancePolicy employeeAttendancePolicy : attendancePolicy.getListEmployee() ) { employeeInfo = employeeInfoSessionBeanLocal.findEmployeeInfoEntityByEmployeeInfoId( employeeAttendancePolicy.getEmployeeId() ); if( employeeInfo != null ) { employeeAttendancePolicy.setEmpName( employeeInfo.getFirstName() + " " + employeeInfo.getMiddleName() + " " + employeeInfo.getLastName() ); company = companySessionBeanLocal.findCompanyById( employeeInfo.getCompanyId() ); employeeAttendancePolicy.setCompanyName( company.getName() ); department = departmentSessionBeanLocal.findDepartmentEntityByDepartmentId( employeeInfo.getDepartmentId() ); employeeAttendancePolicy.setDepartmentName( department.getName() ); } else { attendancePolicy.getListEmployee().remove( employeeAttendancePolicy ); } } } }

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