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  • how to sort an existing table in greasemonkey ?

    - by user570512
    i'm writing a greasemonkey user.js for a page with a table in it. (table is 100 rows by 18 columns.) now what i want to do is to make it sortable on column. and also have it run in both chrome and firefox. all searches for answers sofar resulted in suggestions to use jquery/dojo or something alike. can i be done without any external code? after all it's just a matter of replacing the row's in a different order, right? or is that a silly thing to say? the thing is that i'm already using dojo for some query needs but since i want it to run in both firefox and chrome, i just copy paste the whole dojo thing in my script.. also, most of the solutions i found sofar seem to be more for use when building a table. not for altering an existing one. any help is appreciated.

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  • Is there a sorted_vector class, which supports insert() etc.?

    - by Frank
    Often, it is more efficient to use a sorted std::vector instead of a std::set. Does anyone know a library class sorted_vector, which basically has a similar interface to std::set, but inserts elements into the sorted vector (so that there are no duplicates), uses binary search to find elements, etc.? I know it's not hard to write, but probably better not to waste time and use an existing implementation anyway.

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  • How to make compareTo sort a list alphabetically?

    - by Alex
    Hi How do I change my code so that it lists the elements in alphabetical order from a to z. Right now it's ordering from z to a. I can't figure it out and am stuck :-/ String sName1 = ((Address)o).getSurname().toLowerCase(); String sName2 = (this.surname).toLowerCase(); int result = (sName1).compareTo(sName2); return result; Thanks :)

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  • Sort Array in PHP

    - by DonCroce
    I have a script which gets some values from a DB. The structure of the vars is as the following: $dump["likes"] = 1234; $likes["data"][$i]["name"] = "ABCDEFG"; for($i=0;$i<=$max;$i++){ $data[$i]["likes"] = $dump["likes"]; $data[$i]["name"] = $likes["data"][$i]["name"]; } //Print Here Sorted array (highest value in "like" first) I just need a way to find out in which entry the biggest "likes" are :) So far i have tried array_multisort, but it showed me "inconsistent size" or some error... Thanks for all your help!

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  • How to find the insertion point in an array using binary search?

    - by ????
    The basic idea of binary search in an array is simple, but it might return an "approximate" index if the search fails to find the exact item. (we might sometimes get back an index for which the value is larger or smaller than the searched value). For looking for the exact insertion point, it seems that after we got the approximate location, we might need to "scan" to left or right for the exact insertion location, so that, say, in Ruby, we can do arr.insert(exact_index, value) I have the following solution, but the handling for the part when begin_index >= end_index is a bit messy. I wonder if a more elegant solution can be used? (this solution doesn't care to scan for multiple matches if an exact match is found, so the index returned for an exact match may point to any index that correspond to the value... but I think if they are all integers, we can always search for a - 1 after we know an exact match is found, to find the left boundary, or search for a + 1 for the right boundary.) My solution: DEBUGGING = true def binary_search_helper(arr, a, begin_index, end_index) middle_index = (begin_index + end_index) / 2 puts "a = #{a}, arr[middle_index] = #{arr[middle_index]}, " + "begin_index = #{begin_index}, end_index = #{end_index}, " + "middle_index = #{middle_index}" if DEBUGGING if arr[middle_index] == a return middle_index elsif begin_index >= end_index index = [begin_index, end_index].min return index if a < arr[index] && index >= 0 #careful because -1 means end of array index = [begin_index, end_index].max return index if a < arr[index] && index >= 0 return index + 1 elsif a > arr[middle_index] return binary_search_helper(arr, a, middle_index + 1, end_index) else return binary_search_helper(arr, a, begin_index, middle_index - 1) end end # for [1,3,5,7,9], searching for 6 will return index for 7 for insertion # if exact match is found, then return that index def binary_search(arr, a) puts "\nSearching for #{a} in #{arr}" if DEBUGGING return 0 if arr.empty? result = binary_search_helper(arr, a, 0, arr.length - 1) puts "the result is #{result}, the index for value #{arr[result].inspect}" if DEBUGGING return result end arr = [1,3,5,7,9] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [] b = 60 arr.insert(binary_search(arr, b), b) p arr and result: Searching for 6 in [1, 3, 5, 7, 9] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 6, arr[middle_index] = 5, begin_index = 3, end_index = 2, middle_index = 2 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9] Searching for 6 in [1, 3, 5, 7, 9, 11] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 6, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 3, middle_index = 3 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9, 11] Searching for 60 in [1, 3, 5, 7, 9] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 60, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 60, arr[middle_index] = 9, begin_index = 4, end_index = 4, middle_index = 4 the result is 5, the index for value nil [1, 3, 5, 7, 9, 60] Searching for 60 in [1, 3, 5, 7, 9, 11] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 60, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 60, arr[middle_index] = 11, begin_index = 5, end_index = 5, middle_index = 5 the result is 6, the index for value nil [1, 3, 5, 7, 9, 11, 60] Searching for -60 in [1, 3, 5, 7, 9] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 9, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9] Searching for -60 in [1, 3, 5, 7, 9, 11] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 11, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9, 11] Searching for -60 in [1] a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 0, the index for value 1 [-60, 1] Searching for 60 in [1] a = 60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 1, the index for value nil [1, 60] Searching for 60 in [] [60]

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  • Is there a way to sort digits within a cell?

    - by Iszi
    I'd like to know if there's an Excel Function, or a formula, that can be used to sort digits within a cell. For example, if the value of A1 is 6193254807 and B1 has our formula with parameters set to sort ascending then B1 should equal 0123456789 (leading zero included). Of course, if the parameters were set so that it would sort descending then B1 should equal 9876543210. Is there a way to do this, without wandering into VBScript, or macros, or something similarly exotic?

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  • How best to merge/sort/page through tons of JSON arrays?

    - by Joshiatto
    Here's the scenario: Say you have millions of JSON documents stored as text files. Each JSON document is an array of "activity" objects, each of which contain a "created_datetime" attribute. What is the best way to merge/sort/filter/page through these activities via a web UI? For example, say we want to take a few thousand of the documents, merge them into a gigantic array, sort the array by the "created_datetime" attribute descending and then page through it 10 activities at a time. Also keep in mind that roughly 25% of these JSON documents are updated every day, and updates have to make it into the view within 5 minutes. My first thought is to parse all of the documents into an RDBMS table and then it would just be a simple query such as "select top 10 name, created_datetime from Activity where user_id=12345 order by created_datetime desc". Some have suggested I use NoSQL techniques such as hadoop or map/reduce instead. How exactly would this work? For more background, see: Why is NoSQL better for this scenario?

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  • Linux Mint 12 sort en version finale : Gnome 3 avec extensions, MATE et DuckDuckGo comme nouveau moteur de recherche par défaut

    Linux Mint 12 sort en version finale Gnome 3 avec extensions ou MATE, DuckDuckGo est son nouveau moteur de recherche par défaut La distro. du moment Mint vient de sortir officiellement en version 12 « Lisa». L'annonce officielle vient confirmer la disponibilité de cette édition sur plusieurs sites miroirs depuis quelques jours. Mint sort en effet dès qu'elle est prête, et n'a pas de calendrier précis comme pour l'Ubuntu dont elle dérive. Avant toute considération technique, ce lancement est marqué par un partenariat stratégique. Le m...

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  • lambda vs. operator.attrgetter('xxx') as sort key function in Python

    - by Paul McGuire
    I am looking at some code that has a lot of sort calls using comparison functions, and it seems like it should be using key functions. If you were to change seq.sort(lambda x,y: cmp(x.xxx, y.xxx)), which is preferable: seq.sort(key=operator.attrgetter('xxx')) or: seq.sort(key=lambda a:a.xxx) I would also be interested in comments on the merits of making changes to existing code that works.

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  • How to sort by a field that has an alternative value if null in lucene?

    - by citizenmatt
    Hi folks. I want to sort my lucene(.net) search results by a date field (date1), but if date1 is not set, I'd like to use date2. The traditional sort method is to sort by date1, and then sort the values that are the same by date 2. This would mean that whenever I did fall back to date2, these values would be at the top (or bottom) of the result set. I'd like to interleave the date2 values with the date1 values. In other words, I want to sort on (date1 != null ? date1 : date2). Is this possible in lucene? I reckon I could do this in the index creation phase (just put the relevant date value in a new field) but I don't have enough control of the indexing process to be able to do this, so would like a sorting solution. Any ideas? Thanks Matt

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  • FLEX: I lose current datagrid selection if I sort differently the items of its dataProvider.

    - by Patrick
    hi, when I sort differently my datagrid items, I lose the current selection. This is the code. I'm using savedSelectedItems array to restore the selectedItems but it doesn't work. How can I save the current selection. private function sortItems(option:String):void { //save selectedItems savedSelectedItems = tagsList.selectedItems; if (option == "tag") sort.fields = [new SortField("tag",true)]; if (option == "popularity") sort.fields = [new SortField("popularity",true)]; fullTagsDataModel.tagsData.sort = sort; fullTagsDataModel.tagsData.refresh(); tagsList.selectedItems = savedSelectedItems; } ... <!-- tags list --> <dataGrid:CheckBoxList id="tagsList" width="100%" height="100%" initialize="tagsList.dataProvider=fullTagsDataModel.tagsData" labelField="tag" itemRenderer="com.CheckBoxListAndDataGrid.CheckBoxRenderer" allowMultipleSelection="true" click="savedSelectedItems = tagsList.selectedItems" />

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  • New Skool Crosstabbing

    - by Tim Dexter
    A while back I spoke about having to go back to BIP's original crosstabbing solution to achieve a certain layout. Hok Min has provided a 'man' page for the new crosstab/pivot builder for 10.1.3.4.1 users. This will make the documentation drop but for now, get it here! The old, hand method is still available but this new approach, is more efficient and flexible. That said you may need to get into the crosstab code to tweak it where the crosstab dialog can not help. I had to do this, this week but more on that later. The following explains how the crosstab wizard builds the crosstab and what the fields inside the resulting template structure are there for. To create the crosstab a new XDO command "<?crosstab:...?>" has been created. XDO Command: <?crosstab: ctvarname; data-element; rows; columns; measures; aggregation?> Parameter Description Example Ctvarname Crosstab variable name. This is automatically generated by the Add-in. C123 data-element This is the XML data element that contains the data. "//ROW" Rows This contains a list of XML elements for row headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the row header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "Region{,o=a,t=t}, District{,o=a,t=t}" In the example, the first row header is "Region". It is sort by "Region", order is ascending, and type is text. The second row header is "District". It is sort by "District", order is ascending, and type is text. Columns This contains a list of XML elements for columns headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the column header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" In the example, the first column header is "ProductsBrand". It is sort by "ProductsBrand", order is ascending, and type is text. The second column header is "PeriodYear". It is sort by "District", order is ascending, and type is text. Measures This contains a list of XML elements for measures. "Revenue, PrevRevenue" Aggregation The aggregation function name. Currently, we only support "sum". "sum" Using the Oracle BI Publisher Template Builder for Word add-in, we are able to construct the following Pivot Table: The generated XDO command for this Pivot Table is as follow: <?crosstab:c547; "//ROW";"Region{,o=a,t=t}, District{,o=a,t=t}"; "ProductsBrand{,o=a,t=t},PeriodYear{,o=a,t=t}"; "Revenue, PrevRevenue";"sum"?> Running the command on the give XML data files generates this XML file "cttree.xml". Each XPath in the "cttree.xml" is described in the following table. Element XPath Count Description C0 /cttree/C0 1 This contains elements which are related to column. C1 /cttree/C0/C1 4 The first level column "ProductsBrand". There are four distinct values. They are shown in the label H element. CS /cttree/C0/C1/CS 4 The column-span value. It is used to format the crosstab table. H /cttree/C0/C1/H 4 The column header label. There are four distinct values "Enterprise", "Magicolor", "McCloskey" and "Valspar". T1 /cttree/C0/C1/T1 4 The sum for measure 1, which is Revenue. T2 /cttree/C0/C1/T2 4 The sum for measure 2, which is PrevRevenue. C2 /cttree/C0/C1/C2 8 The first level column "PeriodYear", which is the second group-by key. There are two distinct values "2001" and "2002". H /cttree/C0/C1/C2/H 8 The column header label. There are two distinct values "2001" and "2002". Since it is under C1, therefore the total number of entries is 4 x 2 => 8. T1 /cttree/C0/C1/C2/T1 8 The sum for measure 1 "Revenue". T2 /cttree/C0/C1/C2/T2 8 The sum for measure 2 "PrevRevenue". M0 /cttree/M0 1 This contains elements which are related to measures. M1 /cttree/M0/M1 1 This contains summary for measure 1. H /cttree/M0/M1/H 1 The measure 1 label, which is "Revenue". T /cttree/M0/M1/T 1 The sum of measure 1 for the entire xpath from "//ROW". M2 /cttree/M0/M2 1 This contains summary for measure 2. H /cttree/M0/M2/H 1 The measure 2 label, which is "PrevRevenue". T /cttree/M0/M2/T 1 The sum of measure 2 for the entire xpath from "//ROW". R0 /cttree/R0 1 This contains elements which are related to row. R1 /cttree/R0/R1 4 The first level row "Region". There are four distinct values, they are shown in the label H element. H /cttree/R0/R1/H 4 This is row header label for "Region". There are four distinct values "CENTRAL REGION", "EASTERN REGION", "SOUTHERN REGION" and "WESTERN REGION". RS /cttree/R0/R1/RS 4 The row-span value. It is used to format the crosstab table. T1 /cttree/R0/R1/T1 4 The sum of measure 1 "Revenue" for each distinct "Region" value. T2 /cttree/R0/R1/T2 4 The sum of measure 1 "Revenue" for each distinct "Region" value. R1C1 /cttree/R0/R1/R1C1 16 This contains elements from combining R1 and C1. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand". Therefore, the combination is 4 X 4 è 16. T1 /cttree/R0/R1/R1C1/T1 16 The sum of measure 1 "Revenue" for each combination of "Region" and "ProductsBrand". T2 /cttree/R0/R1/R1C1/T2 16 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "ProductsBrand". R1C2 /cttree/R0/R1/R1C1/R1C2 32 This contains elements from combining R1, C1 and C2. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand", and two distinct values of "PeriodYear". Therefore, the combination is 4 X 4 X 2 è 32. T1 /cttree/R0/R1/R1C1/R1C2/T1 32 The sum of measure 1 "Revenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". T2 /cttree/R0/R1/R1C1/R1C2/T2 32 The sum of measure 2 "PrevRevenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". R2 /cttree/R0/R1/R2 18 This contains elements from combining R1 "Region" and R2 "District". Since the list of values in R2 has dependency on R1, therefore the number of entries is not just a simple multiplication. H /cttree/R0/R1/R2/H 18 The row header label for R2 "District". R1N /cttree/R0/R1/R2/R1N 18 The R2 position number within R1. This is used to check if it is the last row, and draw table border accordingly. T1 /cttree/R0/R1/R2/T1 18 The sum of measure 1 "Revenue" for each combination "Region" and "District". T2 /cttree/R0/R1/R2/T2 18 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "District". R2C1 /cttree/R0/R1/R2/R2C1 72 This contains elements from combining R1, R2 and C1. T1 /cttree/R0/R1/R2/R2C1/T1 72 The sum of measure 1 "Revenue" for each combination of "Region", "District" and "ProductsBrand". T2 /cttree/R0/R1/R2/R2C1/T2 72 The sum of measure 2 "PrevRevenue" for each combination of "Region", "District" and "ProductsBrand". R2C2 /cttree/R0/R1/R2/R2C1/R2C2 144 This contains elements from combining R1, R2, C1 and C2, which gives the finest level of details. M1 /cttree/R0/R1/R2/R2C1/R2C2/M1 144 The sum of measure 1 "Revenue". M2 /cttree/R0/R1/R2/R2C1/R2C2/M2 144 The sum of measure 2 "PrevRevenue". Lots to read and digest I know! Customization One new feature I discovered this week is the ability to show one column and sort by another. I had a data set that was extracting month abbreviations, we wanted to show the months across the top and some row headers to the side. As you may know XSL is not great with dates, especially recognising month names. It just wants to sort them alphabetically, so Apr comes before Jan, etc. A way around this is to generate a month number alongside the month and use that to sort. We can do that in the crosstab, sadly its not exposed in the UI yet but its doable. Go back up and take a look a the initial crosstab command. especially the Rows and Columns entries. In there you will find the sort criteria. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" Notice those leading commas inside the curly braces? Because there is no field preceding them it means that the crosstab should sort on the column before the brace ie PeriodYear. But you can insert another column in the data set to sort by. To get my sort working how I needed. <?crosstab:c794;"current-group()";"_Fund_Type_._Fund_Type_Display_{_Fund_Type_._Fund_Type_Sort_,o=a,t=n}";"_Fiscal_Period__Amount__._Amt_Fm_Disp_Abbr_{_Fiscal_Period__Amount__._Amt_Fiscal_Month_Sort_,o=a,t=n}";"_Execution_Facts_._Amt_";"sum"?> Excuse the horribly verbose XML tags, good ol BIEE :0) The emboldened columns are not in the crosstab but are in the data set. I just opened up the field, dropped them in and changed the type(t) value to be 'n', for number, instead of the default 'a' and my crosstab started sorting how I wanted it. If you find other tips and tricks, please share in the comments.

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  • How to properly name record creation(insertion) datetime field ?

    - by alpav
    If I create a table with datetime default getdate() field that is intended to keep date&time of record insertion, which name is better to use for that field ? I like to use Created and I've seen people use DateCreated or CreateDate. Other possible candidates that I can think of are: CreatedDate, CreateTime, TimeCreated, CreateDateTime, DateTimeCreated, RecordCreated, Inserted, InsertedDate, ... From my point of view anything with Date inside name looks bad because it can be confused with date part in case if I have 2 fields: CreateDate,CreateTime, so I wonder if there are any specific recommendations/standards in that area based on real reasons, not just style, mood or consistency. Of course, if there are 100 existing tables and this is table 101 then I would use same naming convention as used in those 100 tables for the sake of consistency, but this question is about first table in first database in first server in first application.

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  • What is better, a STL list or a STL Map for 20 entries, considering order of insertion is as importa

    - by Abhijeet
    I have the following scenario.The implementation is required for a real time application. 1)I need to store at max 20 entries in a container(STL Map, STL List etc). 2)If a new entry comes and 20 entries are already present i have to overwrite the oldest entry with the new entry. Considering point 2, i feel if the container is full (Max 20 entries) 'list' is the best bet as i can always remove the first entry in the list and add the new one at last (push_back). However, search won't be as efficient. For only 20 entries, does it really make a big difference in terms of searching efficiency if i use a list in place of a map? Also considering the cost of insertion in map i feel i should go for a list? Could you please tell what is a better bet for me ?

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  • Data structure in c for fast look-up/insertion/removal of integers (from a known finite domain)

    - by MrDatabase
    I'm writing a mobile phone based game in c. I'm interested in a data structure that supports fast (amortized O(1) if possible) insertion, look-up, and removal. The data structure will store integers from the domain [0, n] where n is known ahead of time (it's a constant) and n is relatively small (on the order of 100000). So far I've considered an array of integers where the "ith" bit is set iff the "ith" integer is contained in the set (so a[0] is integers 0 through 31, a[1] is integers 32 through 63 etc). Is there an easier way to do this in c?

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  • What are the rules for Javascript's automatic semicolon insertion?

    - by T.R.
    Well, first I should probably ask if this is browser dependent. I've read that if an invalid token is found, but the section of code is valid until that invalid token, a semicolon is inserted before the token if it is preceded by a line break. However, the common example cited for bugs caused by semicolon insertion is: return _a+b; which doesn't seem to follow this rule, since _a would be a valid token. On the other hand, breaking up call chains works as expected: $('#myButton') .click(function(){alert("Hello!")}); Does anyone have a more in-depth description of the rules?

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  • How should I change my Graph structure (very slow insertion)?

    - by Nazgulled
    Hi, This program I'm doing is about a social network, which means there are users and their profiles. The profiles structure is UserProfile. Now, there are various possible Graph implementations and I don't think I'm using the best one. I have a Graph structure and inside, there's a pointer to a linked list of type Vertex. Each Vertex element has a value, a pointer to the next Vertex and a pointer to a linked list of type Edge. Each Edge element has a value (so I can define weights and whatever it's needed), a pointer to the next Edge and a pointer to the Vertex owner. I have a 2 sample files with data to process (in CSV style) and insert into the Graph. The first one is the user data (one user per line); the second one is the user relations (for the graph). The first file is quickly inserted into the graph cause I always insert at the head and there's like ~18000 users. The second file takes ages but I still insert the edges at the head. The file has about ~520000 lines of user relations and takes between 13-15mins to insert into the Graph. I made a quick test and reading the data is pretty quickly, instantaneously really. The problem is in the insertion. This problem exists because I have a Graph implemented with linked lists for the vertices. Every time I need to insert a relation, I need to lookup for 2 vertices, so I can link them together. This is the problem... Doing this for ~520000 relations, takes a while. How should I solve this? Solution 1) Some people recommended me to implement the Graph (the vertices part) as an array instead of a linked list. This way I have direct access to every vertex and the insertion is probably going to drop considerably. But, I don't like the idea of allocating an array with [18000] elements. How practically is this? My sample data has ~18000, but what if I need much less or much more? The linked list approach has that flexibility, I can have whatever size I want as long as there's memory for it. But the array doesn't, how am I going to handle such situation? What are your suggestions? Using linked lists is good for space complexity but bad for time complexity. And using an array is good for time complexity but bad for space complexity. Any thoughts about this solution? Solution 2) This project also demands that I have some sort of data structures that allows quick lookup based on a name index and an ID index. For this I decided to use Hash Tables. My tables are implemented with separate chaining as collision resolution and when a load factor of 0.70 is reach, I normally recreate the table. I base the next table size on this http://planetmath.org/encyclopedia/GoodHashTablePrimes.html. Currently, both Hash Tables hold a pointer to the UserProfile instead of duplication the user profile itself. That would be stupid, changing data would require 3 changes and it's really dumb to do it that way. So I just save the pointer to the UserProfile. The same user profile pointer is also saved as value in each Graph Vertex. So, I have 3 data structures, one Graph and two Hash Tables and every single one of them point to the same exact UserProfile. The Graph structure will serve the purpose of finding the shortest path and stuff like that while the Hash Tables serve as quick index by name and ID. What I'm thinking to solve my Graph problem is to, instead of having the Hash Tables value point to the UserProfile, I point it to the corresponding Vertex. It's still a pointer, no more and no less space is used, I just change what I point to. Like this, I can easily and quickly lookup for each Vertex I need and link them together. This will insert the ~520000 relations pretty quickly. I thought of this solution because I already have the Hash Tables and I need to have them, then, why not take advantage of them for indexing the Graph vertices instead of the user profile? It's basically the same thing, I can still access the UserProfile pretty quickly, just go to the Vertex and then to the UserProfile. But, do you see any cons on this second solution against the first one? Or only pros that overpower the pros and cons on the first solution? Other Solution) If you have any other solution, I'm all ears. But please explain the pros and cons of that solution over the previous 2. I really don't have much time to be wasting with this right now, I need to move on with this project, so, if I'm doing to do such a change, I need to understand exactly what to change and if that's really the way to go. Hopefully no one fell asleep reading this and closed the browser, sorry for the big testament. But I really need to decide what to do about this and I really need to make a change. P.S: When answering my proposed solutions, please enumerate them as I did so I know exactly what are you talking about and don't confuse my self more than I already am.

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