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  • Unable to access MySQL from MyPHPAdmin after setting root password in EasyPHP{WAMP}

    - by Codex
    Am a new starter with WAMP and trying to play around my way using the EasyPHP setup. After successful setup on intial launch of MySQL, the page prompted me to set up ROOT password for security reasons. On setting the password, am no longer able to access MySQL. The error is : Error MySQL said: Documentation 1045 - Access denied for user 'root'@'localhost' (using password: NO) Looked up on the net and tried the following options in the config.inc.php from the phpmyadmin foler: 1] Set the authetication to "http" so that it prompts to enter the username and password /* Authentication type */ $cfg['Servers'][$i]['auth_type'] = 'http'; 2] Set up the correct password in the config file $cfg['Servers'][$i]['password'] = 'myPwd'; None of them worked. Can anyone suggest a workaround to access MySQL? Am not fussed about not being able to use the root account but would like to CRUD on the database using other username. Thanks in advance.

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  • .NET Active Directory Password Expiration on Windows 2008

    - by Brent Pabst
    Searched SO and Everywhere else, including the .net developers guide to directory services programming book - no luck. I am trying to create a simple password reset web page that allows the user to change their password. The change password portion of the code is working fine. For the users I would also like to display when their current password will expire next. Using the sample code from the book mentioned above I was able to get all of the code setup however, the attribute that is returned is always equal to Long.MinValue and hence cannot be inverted to a positive number, plus this means it did not find the proper domain setting. Does anyone have sample code or references for getting the password expiration in a Windows 2008 or R2 domain environment where password policies can be different for each user?

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  • Can IIS admin change password of Windows Service account

    - by sweta Jha
    We have a service account defined for anonymous access which is used for several web sites hosted on the web server. This account has access to several network resources like report server, file servers and so on. While deploying a new web site, we used the same service account for anonymous access. IIS takes the username/password for the account and then a dialog opens for confirm password. Accidently, we gave a wrong password in both the text boxes, the new site with wrong password is working fine but all other previously hosted sites which were using the service account, started giving the unautorized access error. Is it possible that when we entered wrong password for the new web site, the password of the account got reset and all sites stopped functioning?

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  • How does this C# asp.net random password code work?

    - by quakkels
    Hello all, I'm new to .NET and C# and I'm trying to figure out how this code works: public static string CreateRandomPassword(int PasswordLength) { String _allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ23456789"; Byte[] randomBytes = new Byte[PasswordLength]; RNGCryptoServiceProvider rng = new RNGCryptoServiceProvider(); rng.GetBytes(randomBytes); char[] chars = new char[PasswordLength]; int allowedCharCount = _allowedChars.Length; for(int i = 0;i<PasswordLength;i++) { /// /// I don't understand how this line works: /// chars[i] = _allowedChars[(int)randomBytes[i] % allowedCharCount]; } return new string(chars); } I think I've got a pretty good handle on most of this. I haven't been able to understand the following line: chars[i] = _allowedChars[(int)randomBytes[i] % allowedCharCount]; I understand that the code generates random binary numbers and uses those random numbers in the for loop to select a character from the _allowedChars string. What I don't get is why this code uses the modulous operator (%) to get the _allowedChars index value. Thanks for any help

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  • How to read a password encrypted key with java?

    - by Denis
    Hi, This is very simple question. I have private key stored in file in PKCS8 DER format and protected by password. What is the easiest way to read it? Here is the code I use to load unencrypted one: InputStream in = new FileInputStream(privateKeyFilename); byte[] privateKeydata = new byte[in.available()]; in.read(privateKeydata); in.close(); KeyFactory privateKeyFactory = KeyFactory.getInstance("RSA"); PKCS8EncodedKeySpec encodedKeySpec = new PKCS8EncodedKeySpec(privateKeydata); PrivateKey privateKey = privateKeyFactory.generatePrivate(encodedKeySpec); Please, Help!!!

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  • Design an api using rails and change the forgot password functionality

    - by ragupathi
    I have been using rails for developing web applications and now i need to do design an api for iphone application and since i used respond to json it also produces json but i use devise for authentication in my web application and when i send email and password along with the api it gives out {"user":{"authentication_token":"Lsusyd27ewgasga63","email":"[email protected]"}} and there is forgot password functionality in the iphone app but in the web application when clicking on forgot password button it sends an email to the users email, whereby the user has to go to his mail and click on the link sent and it will take to the change password path and after changing it the user will be login but in this iphone app i want to send the password to the user mail and the user can use that password and login. How can i do this? Also do i have to create new controllers for api or the web application controller is enough if it respond as json? please help me.

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  • Codeigniter: A nice straight forward tutorial on how to build a reset password/forgotten password?

    - by Psychonetics
    I've built a full sign up system with user account activation, login, validation, captcha etc. To complete this I now need to implement a forgot password/reset password feature.. I have created one function that generates a random password 8 characters, another method that takes that random password word and applies sha1 and hashing. Also one that takes that hashed password and stores it in a table in the database. I will keep these methods to one side as they might come in handy later on but for now I would like to know if anyone can point me to a nice tutorial for creating a password reset feature for my website. Thanks in advance

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  • How do you do masked password entry on windows using character overwriting?

    - by Erick
    Currently I am using this implementation to hide user input during password entry: void setEcho(bool enable) { HANDLE hStdin = GetStdHandle(STD_INPUT_HANDLE); DWORD mode; GetConsoleMode(hStdin, &mode); if(enable) { mode |= ENABLE_ECHO_INPUT; } else { mode &= ~ENABLE_ECHO_INPUT; } SetConsoleMode(hStdin, mode); } The user needs to be able to have positive feed back that text entry is being made. What techniques are available in a Win32 environment using C++?

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  • Access denied for user 'root@localhost' (using password:NO)

    - by Nasser Hajloo
    I'm new to mysql, I'm trying to run Wordpress inmy windows desktop and it need Mysql. I install everything with Web Platform Installer which provided by microsoft. I never seta root password for mysql and in final step of installing wordpressit askfor root password of mysql. What is the default password for root (if there is one) and how to change it? I try mysql -u root password '123' but it show me Access denied for user 'root@localhost' (using password:NO) after this I try mysql -u root -p but it ask for a password which I don't have Thank you in advance

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  • Error comparing hash to hashed mysql password (output values are equal)

    - by Charlie
    Im trying to compare a hashed password value in a mysql database with the hashed value of an inputted password from a login form. However, when I compare the two values it says they aren't equal. I removed the salt to simply, and then tested what the outputs were and got the same values $password1 = $_POST['password']; $hash = hash('sha256', $password1); ...connect to database, etc... $query = "SELECT * FROM users WHERE username = '$username1'"; $result = mysql_query($query); $userData = mysql_fetch_array($result); if($hash != $userData['password']) //incorrect password { echo $hash."|".$userData['password']; die(); } ...other code... Sample output: 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361| 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361 Any thoughts?

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  • rails 3.1 partial_updates doesn't seem to work with password

    - by user1306769
    i have a user model with a password attribute, which gets saved as password_digest. What i want to do is have the edit user page and the edit password page separated, so that the admin doesn't need to input the password everytime he needs to change something else. For this i have made an extra action / view. My problem is that when i update the user info, i get password validation errors even though i have no password field in the form. Which leads me to the conclusion that partial_updates isn't working with the password attribute (as i have already tested in the console that it is enabled, and it is) Is this me doing something wrong, or should i approach this differently?

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  • Can't validate mine, sudo nor root in Debian "Jessie" Gnome anymore?

    - by Janar
    I'm Debian beginner & GUI guy in a bit of trouble? Can't login as sudo/gksu/root/su nor as (main/super)user after removed user password via Gnome-user-settings. History of actions (Probably irrelevant though) Installed Debian "Jessie" GNU/Linux with xFce GUI (en-US) as only OS. HardWare is ThinkPad w510. Skipped root user password in setup, to get sudo for superuser easily. Logged in (as always had) with Gnome (3.4.x), not once with xFCE. (installed Xfce. Installed xFce only to achieve more control (easier management) over packages this way, to set-up gnome much more by mine likes. Added more jessie repros (same ones as in Wheesy stable by default but for Jessie as, Jessie only had repros for security updates by default). Installed lots of gtk(3) & gnome(3) based soft; (- restarted again after this) Installed propietary graphics card driver for mine nvidia quadro. (- restarted once again after that one) Installed more stuff related to mine work/school/devel. The actual problem Had a plan to restart again, but wanted to set up auto-login first, instead set user password to none (don't ask why / perhaps caused by being awake for a looooong time), noticed it, and set also to auto-login, but couldn't undo mine previous mistake to create new password for me. As mine password is set to none I would have expected that simply return in pass prompt for emty password field would do, but it won't authenticate. I tried Alt+F2 "gksu gedit" as well as: sudo wget "https://www.some-page.eu/file.ext" and "su" in terminals, none has applied (quite logical actually - as I'm sudoer and highest ranked super user, besides only user in computer). Current stand Everything worked & still works nice after this accident, besides this password prompts part. To spoked to log-out nor restart. Synaptic package-manager is still open with root rights (only one, that has left open prior to the issue and not closed since, just in case). Goggled for help and read some manuals/faqs/how-tos - mostly lead to sudoers file management, but not found one specifically for mine issue - so still not any smarter. Really hope, that I don't have to redo OS inst all over again, by just one stupid mistake. Thanks for your reply :-)

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  • PAM with KRB5 to Active Directory - How to prevent update of AD password?

    - by Ex Umbris
    I have a working Fedora 9 system that's set up to authenticate users via PAM - krb5 - Active Directory. I'm migrating this to Fedora 14, and everything works, but it's working too well :-) On Fedora 9, if a Linux user updated their password, it did not propagate to their Active Directory account. On Fedora 14, it is changing their A/D password. The problem is I don't want A/D to be updated. Here's my password-auth-ac: auth required pam_env.so auth sufficient pam_unix.so nullok try_first_pass auth requisite pam_succeed_if.so uid >= 500 quiet auth sufficient pam_krb5.so use_first_pass auth required pam_deny.so account required pam_unix.so account sufficient pam_localuser.so account sufficient pam_succeed_if.so uid < 500 quiet account [default=bad success=ok user_unknown=ignore] pam_krb5.so account required pam_permit.so password requisite pam_cracklib.so try_first_pass retry=3 type= password sufficient pam_unix.so sha512 shadow nullok try_first_pass use_authtok password sufficient pam_krb5.so use_authtok password required pam_deny.so session optional pam_keyinit.so revoke session required pam_limits.so -session optional pam_systemd.so session [success=1 default=ignore] pam_succeed_if.so service in crond quiet use_uid session required pam_unix.so session optional pam_krb5.so I tried removing the line password sufficient pam_krb5.so use_authtok But then when attempting to change the Linux password, if they provide their A/D password for the authentication prompt, they get the error: passwd: Authentication token manipulation error What I want to achieve is: Allow authentication with either the A/D or Linux password (the Linux password is a fall-back for certain sysadmin users in case A/D is unavailable for some reason). This is working now. Allow users to change their Linux passwords without affecting their A/D passwords. Is this possible?

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  • Implementing "Generator" support in a custom language

    - by Roger Alsing
    I've got a bit of fettish for language design and I'm currently playing around with my own hobby language. (http://rogeralsing.com/2010/04/14/playing-with-plastic/) One thing that really makes my mind bleed is "generators" and the "yield" keyword. I know C# uses AST transformation to transform enumerator methods into statemachines. But how does it work in other languages? Is there any way to get generator support in a language w/o AST transformation? e.g. Does languages like Python or Ruby resort to AST transformations to solve this to? (The question is how generators are implemented under the hood in different languages, not how to write a generator in one of them)

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  • Create a color generator in matplotlib

    - by Brendan
    I have a series of lines that each need to be plotted with a separate colour. Each line is actually made up of several data sets (positive, negative regions etc.) and so I'd like to be able to create a generator that will feed one colour at a time across a spectrum, for example the gist_rainbow map shown here. I have found the following works but it seems very complicated and more importantly difficult to remember, from pylab import * NUM_COLORS = 22 mp = cm.datad['gist_rainbow'] get_color = matplotlib.colors.LinearSegmentedColormap.from_list(mp, colors=['r', 'b'], N=NUM_COLORS) ... # Then in a for loop this_color = get_color(float(i)/NUM_COLORS) Moreover, it does not cover the range of colours in the gist_rainbow map, I have to redefine a map. Maybe a generator is not the best way to do this, if so what is the accepted way?

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  • Navigation properties not set when using ADO.NET Mocking Context Generator

    - by olenak
    I am using ADO.NET Mocking Context Generator plugin for my Entity Framework model. I have not started on using mocks yet, just trying to fix generated entity and context classes to make application run as before without exceptions. I've already fixed T4 template to support SaveChanges method. Now I've got another problem: when I try to access any navigation property it is set to null. All the primitive fields inherited from DB table are set and correct. So what I am doing is the following using (var context = MyContext()) { var order = context.Orders.Where(p => p.Id == 7); var product = order.Products; } in this case product is set to null. But that was not a case while using default code generator, it used to return real product object. Thanks ahead for any suggestions!

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  • Could not find generator mini_test:install

    - by David James
    I expected these generators to be available: $ rails g Usage: rails generate GENERATOR [args] [options] MiniTest: mini_test:controller mini_test:helper mini_test:install mini_test:mailer mini_test:model mini_test:scaffold So I ran: $ rails g mini_test:install But got this error: Could not find generator mini_test:install. As for my environment, here is the relevant portion of my Gemfile: group :test, :development do gem 'minitest-rails' end And the resulting portions of my Gemfile.lock: minitest (2.12.1) minitest-rails (0.0.7) minitest (~> 2.12) rails (~> 3.1) I am now in the process of debugging this. I would appreciate any tips. In any case, I will report back.

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  • Python configuration file generator

    - by Stan
    I want to use Python to make a configuration file generator. My roughly idea is feeding input with template files and some XML files with the real settings. Then use the program to generate the real configuration files. I got several questions: Is there any open source configuration generator program? (what could be the keyword), I wonder if there's anything can be added/modified in the design. Does Python have good XML parser module? Is it good idea to use XML file to save the original settings? I've been thinking to use Excel since it's more intuitive to maintain, but harder for program to parse. Not sure how people deal with this. Hope the community can give me some suggestions. Thanks a lot!

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  • Ubuntu 13.10 isn't remembering my passwords anymore, why?

    - by Nik Reiman
    Ubuntu's password management used to be working just fine for me, but around two weeks ago after running apt-get upgrade, I've noticed that now it keeps "forgetting" my passwords. For instance, I need to manually enter passwords to unlock my ssh keys to use git, which previously was done automatically on login. My workplace's 802.11x authentication also no longer works, I need to manually re-auth just to connect to internet. What's going on?

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  • Hash Sum mismatch on python-keyring

    - by Gearoid Murphy
    I came in to my workstation this morning to find an apt error notification relating to a hash sum mismatch on the python keyring password storage mechanism, given the sensitive nature of this package, this gives me some cause for concern. Has anyone else seen this error?, how can I ensure that my system has not been compromised? Failed to fetch http://gb.archive.ubuntu.com/ubuntu/pool/main/p/python-keyring/python-keyring_0.9.2-0ubuntu0.12.04.2_all.deb Hash Sum mismatch Xubuntu 11.04 AMD64

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  • How can * be a safe hashed password?

    - by Exception e
    phpass is a widely used hashing 'framework'. While evaluating phpass' HashPassword I came across this odd method fragment. function HashPassword($password) { // <snip> trying to generate a hash… # Returning '*' on error is safe here, but would _not_ be safe # in a crypt(3)-like function used _both_ for generating new # hashes and for validating passwords against existing hashes. return '*'; } This is the complete phpsalt class: # Portable PHP password hashing framework. # # Version 0.2 / genuine. # # Written by Solar Designer <solar at openwall.com> in 2004-2006 and placed in # the public domain. # # # class PasswordHash { var $itoa64; var $iteration_count_log2; var $portable_hashes; var $random_state; function PasswordHash($iteration_count_log2, $portable_hashes) { $this->itoa64 = './0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'; if ($iteration_count_log2 < 4 || $iteration_count_log2 > 31) $iteration_count_log2 = 8; $this->iteration_count_log2 = $iteration_count_log2; $this->portable_hashes = $portable_hashes; $this->random_state = microtime() . getmypid(); } function get_random_bytes($count) { $output = ''; if (is_readable('/dev/urandom') && ($fh = @fopen('/dev/urandom', 'rb'))) { $output = fread($fh, $count); fclose($fh); } if (strlen($output) < $count) { $output = ''; for ($i = 0; $i < $count; $i += 16) { $this->random_state = md5(microtime() . $this->random_state); $output .= pack('H*', md5($this->random_state)); } $output = substr($output, 0, $count); } return $output; } function encode64($input, $count) { $output = ''; $i = 0; do { $value = ord($input[$i++]); $output .= $this->itoa64[$value & 0x3f]; if ($i < $count) $value |= ord($input[$i]) << 8; $output .= $this->itoa64[($value >> 6) & 0x3f]; if ($i++ >= $count) break; if ($i < $count) $value |= ord($input[$i]) << 16; $output .= $this->itoa64[($value >> 12) & 0x3f]; if ($i++ >= $count) break; $output .= $this->itoa64[($value >> 18) & 0x3f]; } while ($i < $count); return $output; } function gensalt_private($input) { $output = '$P$'; $output .= $this->itoa64[min($this->iteration_count_log2 + ((PHP_VERSION >= '5') ? 5 : 3), 30)]; $output .= $this->encode64($input, 6); return $output; } function crypt_private($password, $setting) { $output = '*0'; if (substr($setting, 0, 2) == $output) $output = '*1'; if (substr($setting, 0, 3) != '$P$') return $output; $count_log2 = strpos($this->itoa64, $setting[3]); if ($count_log2 < 7 || $count_log2 > 30) return $output; $count = 1 << $count_log2; $salt = substr($setting, 4, 8); if (strlen($salt) != 8) return $output; # We're kind of forced to use MD5 here since it's the only # cryptographic primitive available in all versions of PHP # currently in use. To implement our own low-level crypto # in PHP would result in much worse performance and # consequently in lower iteration counts and hashes that are # quicker to crack (by non-PHP code). if (PHP_VERSION >= '5') { $hash = md5($salt . $password, TRUE); do { $hash = md5($hash . $password, TRUE); } while (--$count); } else { $hash = pack('H*', md5($salt . $password)); do { $hash = pack('H*', md5($hash . $password)); } while (--$count); } $output = substr($setting, 0, 12); $output .= $this->encode64($hash, 16); return $output; } function gensalt_extended($input) { $count_log2 = min($this->iteration_count_log2 + 8, 24); # This should be odd to not reveal weak DES keys, and the # maximum valid value is (2**24 - 1) which is odd anyway. $count = (1 << $count_log2) - 1; $output = '_'; $output .= $this->itoa64[$count & 0x3f]; $output .= $this->itoa64[($count >> 6) & 0x3f]; $output .= $this->itoa64[($count >> 12) & 0x3f]; $output .= $this->itoa64[($count >> 18) & 0x3f]; $output .= $this->encode64($input, 3); return $output; } function gensalt_blowfish($input) { # This one needs to use a different order of characters and a # different encoding scheme from the one in encode64() above. # We care because the last character in our encoded string will # only represent 2 bits. While two known implementations of # bcrypt will happily accept and correct a salt string which # has the 4 unused bits set to non-zero, we do not want to take # chances and we also do not want to waste an additional byte # of entropy. $itoa64 = './ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789'; $output = '$2a$'; $output .= chr(ord('0') + $this->iteration_count_log2 / 10); $output .= chr(ord('0') + $this->iteration_count_log2 % 10); $output .= '$'; $i = 0; do { $c1 = ord($input[$i++]); $output .= $itoa64[$c1 >> 2]; $c1 = ($c1 & 0x03) << 4; if ($i >= 16) { $output .= $itoa64[$c1]; break; } $c2 = ord($input[$i++]); $c1 |= $c2 >> 4; $output .= $itoa64[$c1]; $c1 = ($c2 & 0x0f) << 2; $c2 = ord($input[$i++]); $c1 |= $c2 >> 6; $output .= $itoa64[$c1]; $output .= $itoa64[$c2 & 0x3f]; } while (1); return $output; } function HashPassword($password) { $random = ''; if (CRYPT_BLOWFISH == 1 && !$this->portable_hashes) { $random = $this->get_random_bytes(16); $hash = crypt($password, $this->gensalt_blowfish($random)); if (strlen($hash) == 60) return $hash; } if (CRYPT_EXT_DES == 1 && !$this->portable_hashes) { if (strlen($random) < 3) $random = $this->get_random_bytes(3); $hash = crypt($password, $this->gensalt_extended($random)); if (strlen($hash) == 20) return $hash; } if (strlen($random) < 6) $random = $this->get_random_bytes(6); $hash = $this->crypt_private($password, $this->gensalt_private($random)); if (strlen($hash) == 34) return $hash; # Returning '*' on error is safe here, but would _not_ be safe # in a crypt(3)-like function used _both_ for generating new # hashes and for validating passwords against existing hashes. return '*'; } function CheckPassword($password, $stored_hash) { $hash = $this->crypt_private($password, $stored_hash); if ($hash[0] == '*') $hash = crypt($password, $stored_hash); return $hash == $stored_hash; } }

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