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  • Clicking on viewlist link in email alert sent for postlist redirecting to http://url/blogs/Lists /Po

    - by Sarita Mishra
    Hi, We have a Blogs site and post list. Users subscribes to the list and get email alert whenever any change made to the post list. In the email alert sent contains the heading giveb below : Modify my alert settings| View The ‘Colour of Energy’ – now on ...| View Posts View The ‘Colour of Energy’ – now on ... is the link for the post for which user has get the email alert. It is redirecting to the URL ://url/blogs/Lists /Posts/Dispform.aspx?ID=x, which is giving Page cannot be found error. It should redierct to ://url/blogs/Lists /Posts/Post.aspx?ID=x. I want to change the hyperlink URL to the above one. Please suggest as how to proceed with that.

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  • how to diff / align Python lists using arbitrary matching function?

    - by James Tauber
    I'd like to align two lists in a similar way to what difflib.Differ would do except I want to be able to define a match function for comparing items, not just use string equality, and preferably a match function that can return a number between 0.0 and 1.0, not just a boolean. So, for example, say I had the two lists: L1 = [('A', 1), ('B', 3), ('C', 7)] L2 = ['A', 'b', 'C'] and I want to be able to write a match function like this: def match(item1, item2): if item1[0] == item2: return 1.0 elif item1[0].lower() == item2.lower(): return 0.5 else: return 0 and then do: d = Differ(match_func=match) d.compare(L1, L2) and have it diff using the match function. Like difflib, I'd rather the algorithm gave more intuitive Ratcliff-Obershelp type results rather than a purely minimal Levenshtein distance.

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  • In Python, are there builtin functions for elementwise boolean operators over boolean lists?

    - by bshanks
    For example, if you have n lists of bools of the same length, then elementwise boolean AND should return another list of that length that has True in those positions where all the input lists have True, and False everywhere else. It's pretty easy to write, i just would prefer to use a builtin if one exists (for the sake of standardization/readability). Here's an implementation of elementwise AND: def eAnd(*args): return [all(tuple) for tuple in zip(*args)] example usage: >>> eAnd([True, False, True, False, True], [True, True, False, False, True], [True, True, False, False, True]) [True, False, False, False, True] thx

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  • indexing for faster search of lists in a file??

    - by kaushik
    i have a file having around 1 lakh lists and have a another file with again a list of around an average of 50.. I want to compare 2nd item of list in second file with the 2nd element of 1st file and repeat this for each of the 50 lists in 2nd file and get the result of all the matching element. I have written the code for all this,but this is taking a lot of time as it need to check the whole the 1lakh list some 50 times..i want to improve the speed... please tell me how can i do this.... i cant not post my code as it is part of big code and will be difficult to infer anything from that... please tell what can be done to improve the speed?? thank u,

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  • Generate all the ways to intersperse a list of lists, keeping each list in order.

    - by dreeves
    Given a list of lists like this [[1,2,3],[a,b,c,d],[x,y]] generate all permutations of the flattened list, [1,2,3,a,b,c,d,x,y], such that the elements of each sublist occur in the same order. For example, this one is okay [a,1,b,2,x,y,3,c,d] but this one is not [y,1,2,3,a,b,c,x,d] because y must occur after x, that being how x and y are ordered in the original sublist. I believe the number of such lists is determined by the multinomial coefficient. I.e., if there are k sublists, n_i is the length of the ith sublist, and n is the sum of the n_i's then the number of such permutations is n!/(n_i! * ... * n_k!). The question is how to generate those sublists. Pseudocode is great. An actual implementation in your language of choice is even better!

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  • How to compare two lists with duplicated items in one list?

    - by eladc
    I need to compare list_a against many others. my problem starts when there's a duplicated item in the other lists (two k's in other_b). my goal is to filter out all the lists with the same items (up to three matching items). list_a = ['j','k','a','7'] other_b = ['k', 'j', 'k', 'q'] other_c = ['k','k','9','k'] >>>filter(lambda x: not x in list_a,other_b) ['q'] I need a way that would return ['k', 'q'], because 'k' appears only once in list_a. comparing list_a and other_c with set() isn't good for my purpose since it will return only one element: k. while I need ['k','9','k'] I hope I was clear enough. Thank you

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  • Are there any Pandora/Slacker like applications to create stations/play lists from personal mp3 library?

    - by Randy K
    I'm interested in having playlists created automatically much in the same way that Pandora and Slacker Radio "create" radio channels. I understand that iTunes has the Genius feature, but this requires that the files have been encoded with iTunes, which is not the case with my music, among other reasons I'm not considering iTunes. I'm running an Windows environment, but would consider Linux options as it would give me a reason to learn more about Linux. In the end the music files and play lists will end up on my Android phone and tablets. Working with Amazon's Cloud Player would be nice, but not required.

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  • How do I allow end user 'blocked sender lists' to work even if the server manages spam filtering?

    - by Myrddin Emrys
    Client filtering in Outlook 2010 is disabled when the server is managing spam filtering. Unfortunately I have a few high profile users that prefer to spam-block mailing lists rather than unsubscribe, so even though the email is not really spam they are upset that it is coming into their mailbox. As seen here, I am not the first person to wrestle with this issue, and the suggested fix there (setting New-FseExtendedOption –Name CFAllowBlockedSenders –Value true) also failed to work for me. Can anyone provide another possible fix? Thank you kindly.

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  • Is it possible to have tab completion of drop-down lists in web pages in Firefox?

    - by Nick Booker
    Does anyone know of a Firefox plugin that would enable tab-completion (or some other key sequence like Alt-L) of items in drop-down lists in web forms? e.g. ou<TAB>in<TAB>s<TAB> for 'OurCompany - Internal Support' Vimperator's hints mode makes it very ergonomic to focus the drop-down list with a key sequence like f13 but the keyboard interface to the drop-down list still sucks. I very frequently have to pick items from a very long list with very long common prefixes among the entries (e.g. 30-40 starting with OurCompany -), which renders both the built-in keyboard interface and the mouse pretty slow and unergonomic. I basically want readline support for filling webforms!

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  • Should I skip authorization, with CanCan, of an action that instantiates a resource?

    - by irkenInvader
    I am writing a web app to pick random lists of cards from larger, complete sets of cards. I have a Card model and a CardSet model. Both models have a full RESTful set of 7 actions (:index, :new, :show, etc). The CardSetsController has an extra action for creating random sets: :random. # app/models/card_set.rb class CardSet < ActiveRecord::Base belongs_to :creator, :class_name => "User" has_many :memberships has_many :cards, :through => :memberships # app/models/card.rb class Card < ActiveRecord::Base belongs_to :creator, :class_name => "User" has_many :memberships has_many :card_sets, :through => :memberships I have added Devise for authentication and CanCan for authorizations. I have users with an 'editor' role. Editors are allowed to create new CardSets. Guest users (Users who have not logged in) can only use the :index and :show actions. These authorizations are working as designed. Editors can currently use both the :random and the :new actions without any problems. Guest users, as expected, cannot. # app/controllers/card_sets_controller.rb class CardSetsController < ApplicationController before_filter :authenticate_user!, :except => [:show, :index] load_and_authorize_resource I want to allow guest users to use the :random action, but not the :new action. In other words, they can see new random sets, but not save them. The "Save" button on the :random action's view is hidden (as designed) from the guest users. The problem is, the first thing the :random action does is build a new instance of the CardSet model to fill out the view. When cancan tries to load_and_authorize_resource a new CardSet, it throws a CanCan::AccessDenied exception. Therefore, the view never loads and the guest user is served a "You need to sign in or sign up before continuing" message. # app/controllers/card_sets_controllers.rb def random @card_set = CardSet.new( :name => "New Set of 10", :set_type => "Set of 10" ) I realize that I can tell load_and_authorize_resource to skip the :random action by passing :except => :random to the call, but that just feels "wrong" for some reason. What's the "right" way to do this? Should I create the new random set without instantiating a new CardSet? Should I go ahead and add the exception?

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  • SPSiteDataQuery Returns Only One List Type At A Time

    - by Brian Jackett
    The SPSiteDataQuery class in SharePoint 2007 is very powerful, but it has a few limitations.  One of these limitations that I ran into this morning (and caused hours of frustration) is that you can only return results from one list type at a time.  For example, if you are trying to query items from an out of the box custom list (list type = 100) and document library (list type = 101) you will only get items from the custom list (SPSiteDataQuery defaults to list type = 100.)  In my situation I was attempting to query multiple lists (created from custom list templates 10001 and 10002) each with their own content types. Solution     Since I am only able to return results from one list type at a time, I was forced to run my query twice with each time setting the ServerTemplate (translates to ListTemplateId if you are defining custom list templates) before executing the query.  Below is a snippet of the code to accomplish this. SPSiteDataQuery spDataQuery = new SPSiteDataQuery(); spDataQuery.Lists = "<Lists ServerTemplate='10001' />"; // ... set rest of properties for spDataQuery   var results = SPContext.Current.Web.GetSiteData(spDataQuery).AsEnumerable();   // only change to SPSiteDataQuery is Lists property for ServerTemplate attribute spDataQuery.Lists = "<Lists ServerTemplate='10002' />";   // re-execute query and concatenate results to existing entity results = results.Concat(SPContext.Current.Web.GetSiteData(spDataQuery).AsEnumerable());   Conclusion     Overall this isn’t an elegant solution, but it’s a workaround for a limitation with the SPSiteDataQuery.  I am now able to return data from multiple lists spread across various list templates.  I’d like to thank those who commented on this MSDN page that finally pointed out the limitation to me.  Also a thanks out to Mark Rackley for “name dropping” me in his latest article (which I humbly insist I don’t belong in such company)  as well as encouraging me to write up a quick post on this issue above despite my busy schedule.  Hopefully this post saves some of you from the frustrations I experienced this morning using the SPSiteDataQuery.  Until next time, Happy SharePoint’ing all.         -Frog Out   Links MSDN Article for SPSiteDataQuery http://msdn.microsoft.com/en-us/library/microsoft.sharepoint.spsitedataquery.lists.aspx

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  • Searching within Gmail's nested labels [closed]

    - by Penang
    Consider this setup in my gmail inbox I have 3 lists mailing-lists/first-list mailing-lists/second-list mailing-lists/third-list if I want to search for all unread messages in any sublabel of mailing-lists, is there a better way to search than "is:unread label:mailing-list/first-list OR label:mailing-list/second-list OR label:mailing-list/third-list" something like "is:unread label:mailing-list/*" is what I'm looking for

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  • Roundcube "Server Error (OK!)": Lists no messages but can get messages according to the log file

    - by thonixx
    In my server setup there are three virtual machines. One windows machine, an Ubuntu Server 11.10 and a Debian Squeeze mailserver. On the Ubuntu system I have Roundcube installed and I want to connect to the virtual mail server. What's the problem After login into Roundcube it says "Server Error (OK!)" and lists no messages. More information On the Ubuntu server there is no error in any log file (even Roundcubes log files). In the imap log file there you can see Roundcube is able to fetch all imap messages (I can see them in the imap log file created by Roundcube). And on the side of the mail server there are no error messages too. The test connection at the end of the configuration of Roundcube works too, there is a "success" notification. Even the basic login at Roundcube login dialog works without any error message. Roundcube log file you can look here for the log file: http://fixee.org/paste/wxg36eh/ So does anyone know what's wrong with Roundcube?

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  • reconstructing a tree from its preorder and postorder lists.

    - by NomeN
    Consider the situation where you have two lists of nodes of which all you know is that one is a representation of a preorder traversal of some tree and the other a representation of a postorder traversal of the same tree. I believe it is possible to reconstruct the tree exactly from these two lists, and I think I have an algorithm to do it, but have not proven it. As this will be a part of a masters project I need to be absolutely certain that it is possible and correct (Mathematically proven). However it will not be the focus of the project, so I was wondering if there is a source out there (i.e. paper or book) I could quote for the proof. (Maybe in TAOCP? anybody know the section possibly?) In short, I need a proven algorithm in a quotable resource that reconstructs a tree from its pre and post order traversals. Note: The tree in question will probably not be binary, or balanced, or anything that would make it too easy. Note2: Using only the preorder or the postorder list would be even better, but I do not think it is possible. Note3: A node can have any amount of children. Note4: I only care about the order of siblings. Left or right does not matter when there is only one child.

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  • Count all lists of adjacent nodes stored in an array.

    - by Ben Brodie
    There are many naive approaches to this problem, but I'm looking for a good solution. Here is the problem (will be implemented in Java): You have a function foo(int a, int b) that returns true if 'a' is "adjacent" to 'b' and false if 'a' is not adjacent to 'b'. You have an array such as this [1,4,5,9,3,2,6,15,89,11,24], but in reality has a very long length, like 120, and will be repeated over and over (its a genetic algorithm fitness function) which is why efficiency is important. I want a function that returns the length of each possible 'list' of adjacencies in the array, but not including the 'lists' which simply subsets of a larger list. For example, if foo(1,4) - true, foo(4,5) - true, foo(5,9)- false, foo(9,3) & foo(3,2) & foo(2,6), foo(6,15) - true, then there are 'lists' (1,4,5) and (9,3,2,6), so length 3 and 4. I don't want it to return (3,2,6), though, because this is simply a subset of 9,3,2,6. Thanks.

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  • How to move list items from two lists (from different areas) to one specific list by clicking the li

    - by pschorr
    I've been having some issues setting up a list of items and moving them between each other. Is it possible to have multiple lists, with a link inside each item to move it to a specified list? i.e. List of actions with a plus next to the action, click the plus and move to a specified box? Furthermore, would it be possible to then load a lightbox (code would have to be inline I'd guess) from that page and move those names to the specific list as well? Example Images Thanks much! More broad view of my efforts so far... The initial issue being that I could not use listboxes due to their being rendered natively inside each individual browser. Through listboxes I was able to set this up, but with a trigger via the code below (found on stackoverflow). While it gave me partial functionality it did not get the target I was looking for. document.getElementById('moveTrigger').onclick = function() { var listTwo = document.getElementById('secondList'); var options = document.getElementById('firstList').getElementsByTagName('option'); while(options.length != 0) { listTwo.appendChild(options[0]); } } I then moved onto jqueryui's sortable and it's ability to connect multiple, and most important, style-able lists and to be dragged between each other. This works for the side by side tables, but it does not offer the usability I was looking for overall. So, I've come to where I'm unsure as to where to move forward. While I can get around PHP, I wouldn't know where to start with this one personally. I'm open to any and all options! Thanks much!

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  • OpenSource Projects - Is there a site which lists projecs that need more developers?

    - by Jamie
    Morning/Afternoon/Evening all, Do any of you know of a website which lists opensource projects which are in need of more help? Let me elaborate, I would like to work on another open source project (I already work on a couple), however, it would be nice to have a site which lists lots of OS projects, their aims, deadlines, workload, how many more developers they are in need of etc. Of course, I could just pick a topic i'm interested in, find an OS project and then work on it, however, it would be nice to see a diversified list of projects. Primarily because some little known awesome projects get little attention and big projects such as jQuery forks, adium, gimp etc. etc. get a lot of attention because they are well known (and of course because they are great)and thus get a lot of developers working on them. It would be nice to see some little known projects getting more attention and thus hopefully drawing some people to work on them. Currently there are many websites hosting os projects, such as github, sourceforge, google code etc. A website to centralise all of this into one place and categorise it would be awesome. Let me know your thoughts please. I'm not looking for an answer per se, so I will mark it is as a community wiki. Your thoughts would be great.

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  • Why can't I refresh the list of packages?

    - by Elysium
    This might be a duplicate, but I can't find a solution in other posts. Whenever I try to update I get this message: ERROR###ERROR###ERROR###ERROR###ERROR###ERROR###ERROR E:Encountered a section with no Package: header, E:Problem with MergeList /var/lib/apt/listspackages.medibuntu.org_dists_quantal_free_i18n_Translation-en, E:The package lists or status file could not be parsed or opened. I have tried runnig this in the terminal: sudo rm /var/lib/apt/lists/* -vf sudo apt-get update It doesn't work at all. I cant even open the software sources and "sudo apt-get check" gives me this message: Reading package lists... Error! E: Encountered a section with no Package: header E: Problem with MergeList /var/lib/apt/lists/packages.medibuntu.org_dists_quantal_free_i18n_Translation-en E: The package lists or status file could not be parsed or opened. UPDATE: solution for me was to remove the medibuntu-keyring through synaptic manager and removed mediubuntu from the software sources too manually. This seems to have solved the problem. The update manager doesnt give me any error messages anymore.

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  • using '.each' method: how do I get the indexes of multiple ordered lists to each begin at [0]?

    - by shecky
    I've got multiple divs, each with an ordered list (various lengths). I'm using jquery to add a class to each list item according to its index (for the purpose of columnizing portions of each list). What I have so far ... <script type="text/javascript"> /* Objective: columnize list items from a single ul or ol in a pre-determined number of columns 1. get the index of each list item 2. assign column class according to li's index */ $(document).ready(function() { $('ol li').each(function(index){ // assign class according to li's index ... index = li number -1: 1-6 = 0-5; 7-12 = 6-11, etc. if ( index <= 5 ) { $(this).addClass('column-1'); } if ( index > 5 && index < 12 ) { $(this).addClass('column-2'); } if ( index > 11 ) { $(this).addClass('column-3'); } // add another class to the first list item in each column $('ol li').filter(function(index) { return index != 0 && index % 6 == 0; }).addClass('reset'); }); // closes li .each func }); // closes doc.ready.func </script> ... succeeds if there's only one list; when there are additional lists, the last column class ('column-3') is added to all remaining list items on the page. In other words, the script is presently indexing continuously through all subsequent lists/list items, rather than being re-set to [0] for each ordered list. Can someone please show me the proper method/syntax to correct/amend this, so that the script addresses/indexes each ordered list anew? many thanks in advance. shecky p.s. the markup is pretty straight-up: <div class="tertiary"> <h1>header</h1> <ol> <li><a href="#" title="a link">a link</a></li> <li><a href="#" title="a link">a link</a></li> <li><a href="#" title="a link">a link</a></li> </ol> </div><!-- END div class="tertiary" -->

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  • How do I connect multiple sortable lists to each other in jQuery UI?

    - by Abs
    I'm new to jQuery, and I'm totally struggling with using jQuery UI's sortable. I'm trying to put together a page to facilitate grouping and ordering of items. My page has a list of groups, and each group contains a list of items. I want to allow users to be able to do the following: 1. Reorder the groups 2. Reorder the items within the groups 3. Move the items between the groups The first two requirements are no problem. I'm able to sort them just fine. The problem comes in with the third requirement. I just can't connect those lists to each other. Some code might help. Here's the markup. <ul id="groupsList" class="groupsList"> <li id="group1" class="group">Group 1 <ul id="groupItems1" class="itemsList"> <li id="item1-1" class="item">Item 1.1</li> <li id="item1-2" class="item">Item 1.2</li> </ul> </li> <li id="group2" class="group">Group 2 <ul id="groupItems2" class="itemsList"> <li id="item2-1" class="item">Item 2.1</li> <li id="item2-2" class="item">Item 2.2</li> </ul> </li> <li id="group3" class="group">Group 3 <ul id="groupItems3" class="itemsList"> <li id="item3-1" class="item">Item 3.1</li> <li id="item3-2" class="item">Item 3.2</li> </ul> </li> </ul> I was able to sort the lists by putting $('#groupsList').sortable({}); and $('.itemsList').sortable({}); in the document ready function. I tried using the connectWith option for sortable to make it work, but I failed spectacularly. What I'd like to do is have the every groupItemsX list connected to every groupItemsX list but itself. How should I do that?

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