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  • Simulate Photoshop's saturation changes in Imagemagick

    - by Ambirex
    In Photoshop you can adjust the hue, saturation and lightness of an image with three sliders. ImageMagick you can modulate the brightness, saturation, and hue. Minimizing the saturation correctly produces a black and white image in both programs. Maxing out the saturation appears close, but ImageMagick appears to soften some of the blown out edges while Photoshop will expose more the the compression artifacts. How can I accurately reproduce Photoshop's saturation changes from within ImageMagick, or other command line tool.

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  • How do I convert RGB into HSV in Cocoa Touch?

    - by Evelyn
    I want to set the background color of a label using HSV instead of RGB. How do I implement this into code? Code: //.m file #import "IBAppDelegate.h" @implementation IBAppDelegate @synthesize label; { self.label.backgroundColor = [UIColor colorWithRed:1.0f green:0.8f blue:0.0f alpha:1.0f]; }

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  • CMYK + CMYK = ? CMYK / 2 = ?

    - by Pete
    Suppose there are two colors defined in CMYK: color1 = 30, 40, 50, 60 color2 = 50, 60, 70, 80 If they were to be printed what values would the resulting color have? color_new = min(cyan1 + cyan2, 100), min(magenta1 + magenta2, 100), min(yellow1 + yellow2, 100), min(black1 + black2, 100)? Suppose there is a color defined in CMYK: color = 40, 30, 30, 100 It is possible to print a color at partial intensity, i.e. as a tint. What values would have a 50% tint of that color? color_new = cyan / 2, magenta / 2, yellow / 2, black / 2? I'm asking this to better understand the "tintTransform" function in PDF Reference 1.7, 4.5.5 Special Color Spaces, DeviceN Color Spaces Update: To better clarify: I'm not entirely concerned with human perception or how the CMYK dyies react to the paper. If someone specifies 90% tint which, when printed, looks like full intensity colorant, that's ok. In other words, if I asking how to compute 50% of cmyk(40, 30, 30, 100) I'm asking how to compute the new values, regardless of whether the result looks half-dark or not. Update 2: I'm confused now. I checked this in InDesign and Acrobat. For example Pantone 3005 has CMYK 100, 34, 0, 2, and its 25% tint has CMYK 25, 8.5, 0, 0.5. Does it mean I can "monkey around in a linear way"?

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  • Java anonymous class efficiency implications

    - by Po
    Is there any difference in efficiency (e.g. execution time, code size, etc.) between these two ways of doing things? Below are contrived examples that create objects and do nothing, but my actual scenarios may be creating new Threads, Listeners, etc. Assume the following pieces of code happen in a loop so that it might make a difference. Using anonymous objects: void doSomething() { for (/* Assume some loop */) { final Object obj1, obj2; // some free variables IWorker anonymousWorker = new IWorker() { doWork() { // do things that refer to obj1 and obj2 } }; } } Defining a class first: void doSomething() { for (/* Assume some loop */) { Object obj1, obj2; IWorker worker = new Worker(obj1, obj2); } } static class Worker implements IWorker { private Object obj1, obj2; public CustomObject(Object obj1, Object obj2) {/* blah blah */} @Override public void doWork() {} }; Thank you :)

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  • How can I use the HSL colorspace in Java?

    - by Eric
    I've had a look at the ColorSpace class, and found the constant TYPE_HLS (which presumably is just HSL in a different order). Can I use this constant to create a Color from hue, saturation, and luminosity? If not, are there any Java classes for this, or do I need to write my own?

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  • Batch file to map a drive when the folder name contains spaces

    - by Santiago
    I am trying to map a drive using a batch file. I have tried: net use m: \Server01\myfolder /USER:mynetwork\Administrator "Mypassword" /persistent:yes It works fine. The problem comes when I try to map a folder with spaces on its name: net use m: \Server01\my folder /USER:mynetwork\Administrator "Mypassword" /persistent:yes I have tried using quotes, using myfold~1 but nothing works. An easy way would be renaming the folder but I have it mapped in more than 300 workstations so is not a very good idea. PLEASE HELP!!!

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  • more efficient way to pickle a string

    - by gatoatigrado
    The pickle module seems to use string escape characters when pickling; this becomes inefficient e.g. on numpy arrays. Consider the following z = numpy.zeros(1000, numpy.uint8) len(z.dumps()) len(cPickle.dumps(z.dumps())) The lengths are 1133 characters and 4249 characters respectively. z.dumps() reveals something like "\x00\x00" (actual zeros in string), but pickle seems to be using the string's repr() function, yielding "'\x00\x00'" (zeros being ascii zeros). i.e. ("0" in z.dumps() == False) and ("0" in cPickle.dumps(z.dumps()) == True)

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  • Function for creating color wheels

    - by lbrandy
    This is something I've pseudo-solved many times and never quite found a solution that's stuck with me. The problem is to come up with a way to generate N colors that are as distinguishable as possible where N is a parameter.

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  • Unicode generated by toEscapedUnicode method is without spaces

    - by vishvesha
    For this word ????????????? the Unicode is== \u0938\u0941\u0916\u091A\u0948\u0928\u093E\u0928\u0940 \u0930\u0940\u091D\u0941\u092E\u0932 \u091C\u093F\u0935\u0924\u0930\u093E\u092E and look it has spaces before \u0930 and \u091C But when I am trying in my code String tempString=Strings.toEscapedUnicode(strString); This method to convert to Unicode gives a result without spaces: \u0938\u0941\u0916\u091A\u0948\u0928\u093E\u0928\u0940\u0930\u0940\u091D\u0941\u092E\u0932\u091C\u093F\u0935\u0924\u0930\u093E\u092E and that's why they are not matching. My 'toEscapeUnicode' method generates Unicode without spaces. I want the spaces, so how to do it?

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  • remove the spaces...

    - by tekknolagi
    !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

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  • The volume "filesystem root" has only 0 bytes disk space remaining?

    - by radek
    I installed 11.10 ~two weeks ago and run into some strange troubles recently. Installation was on brand new laptop with clear 128GB SSD. I opted for encrypting home directory. Apart from that I accepted defaults during the installation. There is no other OS on my laptop. I had circa 40GB in use when (for the third time) I got to see this very unpleasant window: Twice situation was pretty bad and whole system slowed down considerably. After reboot I could not login to graphical interface (with an error message informing about insufficient space) and had to remove some files from command line first. Third time I still managed to quickly delete some files and it helped. My laptop is mainly work environment: so no torrents, games, just two movies. Only media filling space are ~20GB of pictures, and bunch of pdfs. Working mostly on PostgreSQL & PostGIS, GeoServer and QGIS recently. Although I had lots of opportunities to test and practice my backups I would be extremely grateful if somebody could point me to any potential solutions to this problem. My laptop has been bought just before I installed Ubuntu, and it came without OS. Could that be hardware issue? Or is the encrypted home causing me headaches? Thanks for help! Update: As suggested by @maniat1k, here is current output of fdisk -l: WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders, total 312581808 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sda1 1 312581807 156290903+ ee GPT

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  • Platform for Efficiency: Boeing Defense, Space & Security integrates supply chain processes using Oracle Business Process Management solutions. by Fred Sandsmark

    - by JuergenKress
    Like most companies, aerospace giant Boeing has its jargon - words and phrases that uniquely define its products and processes. Take the word platform. It is used at Boeing to mean a family of aircraft - the F/A-18 fighter, for example, or the 777 jetliner. Boeing Defense, Space & Security since August 2009, employees in the Global Services & Support (GS&S) division of Boeing Defense, Space & Security have been talking about a different sort of platform: a supply chain technology platform, based on Oracle Business Process Management (Oracle BPM) solutions and Oracle SOA Suite. That platform, built with the assistance of Oracle Diamond Partner Capgemini, is serving as a jumping-off point for Boeing's GS&S staff to deploy radically improved business processes supported by Oracle Fusion Applications to build a high-visibility, end-to-end supply chain. This business process-driven technology platform has ambitious goals: to help GS&S respond more quickly and accurately to its customers' needs, to make business processes at all GS&S sites more consistent and less expensive, and to create a foundation for further improvement and efficiency. Read the full article here. Want to publish your BPM11g success story - request for a partner/customer reference? BPM Center of Excellent & First 100 Days of BPM documents to our SOA Community Workspace MWD_bpm_si_Centre_of_Excellence_0811.pdf First 100 Days of BPM whitepaper.pdf Please visit our SOA Community Workspace (SOA Community membership required). SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit  www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Mix Forum Technorati Tags: BPM,BPM reference,BPM Capgemini,BPM first 100 days,BPM center of Excellence,SOA Community,Oracle SOA,Oracle BPM,Community,OPN,Jürgen Kress

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  • Why the clip space in OpenGL has 4 dimensions?

    - by user827992
    I will use this as a generic reference, but the more i browser online docs and books, the less i understand about this. const float vertexPositions[] = { 0.75f, 0.75f, 0.0f, 1.0f, 0.75f, -0.75f, 0.0f, 1.0f, -0.75f, -0.75f, 0.0f, 1.0f, }; in this online book there is an example about how to draw the first and classic hello world for OpenGL about making a triangle. The vertex structure for the triangle is declared as stated in the code above. The book, as all the other sources about this, stress the point that the Clip Space is a 4D structure that is used to basically decide what will be rasterized and rendered to the screen. Here I have my questions: i can't imagine something in 4D, i don't think that a human can do that, what is a 4D for this Clip space ? the most human-readable doc that i have read speaks about a camera, which is just an abstraction over the clipping concept, and i get that, the problem is, why not using the concept of a camera in the first place which is a more familiar 3D structure? The only problem with the concept of a camera is that you need to define the prospective in other way and so you basically have to add another statement about what kind of camera you wish to have. How i'm supposed to read this 0.75f, 0.75f, 0.0f, 1.0f ? All i get is that they are all float values and i get the meaning of the first 3 values, what does it mean the last one?

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  • Space Invaders-type game: Keeping the enemies aligned with each other as they turn around?

    - by CorundumGames
    OK, so here's the lowdown of the problem I'm trying to solve. I'm developing a game in PyGame that's a cross between Space Invaders and Columns. I'm trying to make the motion of the enemies similar to that of the aliens in Space Invaders; that is, they're all clustered in a grid, and if even one hits the side of the screen, the entire formation moves down and turns around. However, the motion of these aliens is continuous (as continuous as a monitor can be, anyway), not on a discrete grid like in the original. The enemies are instances of an Enemy class, and in turn they're held by a 2D array in a enemysquadron module (which, if you don't use Python, is in this case essentially a singleton due to the way Python modules work). Inside the Enemy class I have a class-scope velocity vector that is reversed every time an Enemy object touches the edge of the screen. This won't do, though, because as time goes on the enemies just become disorganized and jumbled (i.e. not in a grid as planned). I haven't implemented the Enemies going downward yet, so let's not worry about that right now. Any tips?

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  • How do you blend multiple colors in HSV (polar) color-space?

    - by Toxikman
    In RGB color space, you can do a weighted multiple-color blend by just doing: Start with R = G = B = 0. Then we perform a blend at index i using a set of colors C, and a set of normalized weights w like so: R += w[i] * C[i].r G += w[i] * C[i].g B += w[i] * C[i].b But I'd like to interpolate the colors in the HSV color-space instead, so that saturation and brightness are uniform across the interpolation. I know I can blend saturation and brightness in the same way as above, but the HUE component is an angle around a continuous circle, since HSV is essentially a polar coordinate system. Blending only two HSV colors makes sense to me, you just find the shortest arc around the circle and interpolate between the two hues. But when you attempt to blend more than 2 colors, it becomes a bit of a puzzle. You have to handle anomalous cases, like 4 equally-weighted colors with a hue at 0, 90, 180, and 270 degrees. They basically cancel each other out, so any hue will do. Any ideas would be greatly appreciated.

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  • How can a 1Gb Java heap on a 64bit machine use 3Gb of VIRT space?

    - by Graeme Moss
    I run the same process on a 32bit machine as on a 64bit machine with the same memory VM settings (-Xms1024m -Xmx1024m) and similar VM version (1.6.0_05 vs 1.6.0_16). However the virtual space used by the 64bit machine (as shown in top under "VIRT") is almost three times as big as that in 32bit! I know 64bit VMs will use a little more memory for the larger references, but how can it be three times as big? Am I reading VIRT in top incorrectly? Full data shown below, showing top and then the result of jmap -heap, first for 64bit, then for 32bit. Note the VIRT for 64bit is 3319m for 32bit is 1220m. * 64bit * PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 22534 agent 20 0 3319m 163m 14m S 4.7 2.0 0:04.28 java $ jmap -heap 22534 Attaching to process ID 22534, please wait... Debugger attached successfully. Server compiler detected. JVM version is 10.0-b19 using thread-local object allocation. Parallel GC with 4 thread(s) Heap Configuration: MinHeapFreeRatio = 40 MaxHeapFreeRatio = 70 MaxHeapSize = 1073741824 (1024.0MB) NewSize = 2686976 (2.5625MB) MaxNewSize = -65536 (-0.0625MB) OldSize = 5439488 (5.1875MB) NewRatio = 2 SurvivorRatio = 8 PermSize = 21757952 (20.75MB) MaxPermSize = 88080384 (84.0MB) Heap Usage: PS Young Generation Eden Space: capacity = 268500992 (256.0625MB) used = 247066968 (235.62142181396484MB) free = 21434024 (20.441078186035156MB) 92.01715277089181% used From Space: capacity = 44695552 (42.625MB) used = 0 (0.0MB) free = 44695552 (42.625MB) 0.0% used To Space: capacity = 44695552 (42.625MB) used = 0 (0.0MB) free = 44695552 (42.625MB) 0.0% used PS Old Generation capacity = 715849728 (682.6875MB) used = 0 (0.0MB) free = 715849728 (682.6875MB) 0.0% used PS Perm Generation capacity = 21757952 (20.75MB) used = 16153928 (15.405586242675781MB) free = 5604024 (5.344413757324219MB) 74.24378912132907% used * 32bit * PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 30168 agent 20 0 1220m 175m 12m S 0.0 2.2 0:13.43 java $ jmap -heap 30168 Attaching to process ID 30168, please wait... Debugger attached successfully. Server compiler detected. JVM version is 14.2-b01 using thread-local object allocation. Parallel GC with 8 thread(s) Heap Configuration: MinHeapFreeRatio = 40 MaxHeapFreeRatio = 70 MaxHeapSize = 1073741824 (1024.0MB) NewSize = 1048576 (1.0MB) MaxNewSize = 4294901760 (4095.9375MB) OldSize = 4194304 (4.0MB) NewRatio = 8 SurvivorRatio = 8 PermSize = 16777216 (16.0MB) MaxPermSize = 67108864 (64.0MB) Heap Usage: PS Young Generation Eden Space: capacity = 89522176 (85.375MB) used = 80626352 (76.89128112792969MB) free = 8895824 (8.483718872070312MB) 90.0629940005033% used From Space: capacity = 14876672 (14.1875MB) used = 14876216 (14.187065124511719MB) free = 456 (4.3487548828125E-4MB) 99.99693479832048% used To Space: capacity = 14876672 (14.1875MB) used = 0 (0.0MB) free = 14876672 (14.1875MB) 0.0% used PS Old Generation capacity = 954466304 (910.25MB) used = 10598496 (10.107513427734375MB) free = 943867808 (900.1424865722656MB) 1.1104107034039412% used PS Perm Generation capacity = 16777216 (16.0MB) used = 11366448 (10.839889526367188MB) free = 5410768 (5.1601104736328125MB) 67.74930953979492% used

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  • Inheritance inside a template - public members become invisible?

    - by Juliano
    I'm trying to use inheritance among classes defined inside a class template (inner classes). However, the compiler (GCC) is refusing to give me access to public members in the base class. Example code: template <int D> struct Space { struct Plane { Plane(Space& b); virtual int& at(int y, int z) = 0; Space& space; /* <= this member is public */ }; struct PlaneX: public Plane { /* using Plane::space; */ PlaneX(Space& b, int x); int& at(int y, int z); const int cx; }; int& at(int x, int y, int z); }; template <int D> int& Space<D>::PlaneX::at(int y, int z) { return space.at(cx, y, z); /* <= but it fails here */ }; Space<4> sp4; The compiler says: file.cpp: In member function ‘int& Space::PlaneX::at(int, int)’: file.cpp:21: error: ‘space’ was not declared in this scope If using Plane::space; is added to the definition of class PlaneX, or if the base class member is accessed through the this pointer, or if class Space is changed to a non-template class, then the compiler is fine with it. I don't know if this is either some obscure restriction of C++, or a bug in GCC (GCC versions 4.4.1 and 4.4.3 tested). Does anyone have an idea?

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  • How do you add more space to a Fedora (LVM) partition?

    - by Trevor Boyd Smith
    In a nutshell, i have a VM that ran out of space. I increased the size of the VM's harddrive to be 4 times bigger but the OS partition is still only using 1x the space. I need to change the LVM partition to take up the extra 4x space but I don't know how to extend the LVM partition. (NOTE: To make the screenshots given below I had to boot from a live-cd for gnome-partition-manager (aka gparted). Very unfortunately gparted is only able to "detect LVM" and can't do any LVM operations.) Here is what "gparted" shows. Please notice that the "resize" option is not available: The Problem: I can't find good directions<1 on how to grow the LVM partition via GUI or command-line! How do you grow a LVM partition that was created by the default Fedora install? If you are giving command line directions. Please explain what each line of commands does.

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  • Thunderbird gives " Not enough disk space " alert, after trying to download more emails ( Win 7, 64 bit )

    - by James C
    So, today I have installed Mozilla Thunderbird 24.2.0 on my Windows 7 (64 bit) machine. It was downloading emails, until it hit an error. An alert showed up saying : "There is not enough disk space to download new messages. Try deleting old mail, emptying the Trash folder, and compacting your mail folders, and then try again." Now, disk space is not a problem, there is enough free space left ( almost 50 % of the drive ). How to stop the alert and continue downloading ?

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  • Why does compressing and decompressing my SSD hard drive free up space?

    - by Paperflyer
    I bought an SSD (SandForce 2), created a tiny 25GB partition on it for Windows and installed Windows 7 64-bit. In order to free disk space, I enabled compression on the drive using the Properties entry in the context menu for the drive in Explorer. Prior to compressing I had around 5GB of free space. After compression I had 4GB, so compression was not working for me. I figured this might have happened because of the built-in data compression of the SSD. I decompressed the files again - after decompression, it left me with 7GB of free space! Better yet, after restarting, I had 10GB. What is happening here?

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