Search Results

Search found 38423 results on 1537 pages for 'try finally'.

Page 32/1537 | < Previous Page | 28 29 30 31 32 33 34 35 36 37 38 39  | Next Page >

  • Android software for the system administrator on the move

    - by GruffTech
    My company has over service through Verizon, and AT&T Service in the area is "shoddy" at its best, so I haven't been able to join the "iPhone party" like so many of my fellow system administrators have been able to. That being said, this week finally a phone I like has hit Verizon, the HTC Incredible. (I've been waiting for the Desire or Nexus One, but after seeing spec sheets and reviews, HTC Incredible comes out ahead anyway). So (finally) I'm looking for Android Apps that are "gotta-haves" for system administrators. I've found the bottom three. If there are others you prefer over these let me know. RDP Program - RemoteRDP SSH Client - ConnectBot Nagios - NagMonDroid Reply with your favorite Android App and why!

    Read the article

  • gnu coreutils split verbose flushed?

    - by 130490868091234
    When using the GNU coreutils split command with verbose mode, how can I make the lines that appear in the STDOUT be flushed with respect to the time when the file has finally been created? Fore example, running it like this: ~/coreutils/bin/split --verbose -d -u -l 10000000 1>out & tail -f out creating file `x00' creating file `x01' creating file `x02' [...] I would have expected the line creating file 'x00' to have appeared in file out after the file has been completely written, but instead, it seems like nothing is written into out until the whole file has been finally processed. Is there a way to change this behavior?

    Read the article

  • tkinter frame does not show on startup

    - by Jzz
    this is my first question on SO, so correct me please if I make a fool of myself. I have this fairly complicated python / Tkinter application (python 2.7). On startup, the __init__ loads several frames, and loads a database. When that is finished, I want to set the application to a default state (there are 2 program states, 'calculate' and 'config'). Setting the state of the application means that the appropriate frame is displayed (using grid). When the program is running, the user can select a program state in the menu. Problem is, the frame is not displayed on startup. I get an empty application (menu bar and status bar are displayed). When I select a program state in the menu, the frame displays as it should. Question: What am I doing wrong? Should I update idletasks? I tried, but no result. Anything else? Background: I use the following to switch program states: def set_program_state(self, state): '''sets the program state''' #try cleaning all the frames: try: self.config_frame.grid_forget() except: pass try: self.tidal_calculations_frame.grid_forget() except: pass try: self.tidal_grapth_frame.grid_forget() except: pass if state == "calculate": print "Switching to calculation mode" self.tidal_calculations_frame.grid() #frame is preloaded self.tidal_calculations_frame.fill_data(routes=self.routing_data.routes, deviations=self.misc_data.deviations, ship_types=self.misc_data.ship_types) self.tidal_grapth_frame.grid() self.program_state = "calculate" elif state == "config": print "Switching to config mode" self.config_frame = GUI_helper.config_screen_frame(self, self.user) #load frame first (contents depend on type of user) self.config_frame.grid() self.program_state = "config" I understand that this is kind of messy to read, so I simplified things for testing, using this: def set_program_state(self, state): '''sets the program state''' #try cleaning all the frames: try: self.testlabel_1.grid_forget() except: pass try: self.testlabel_2.grid_forget() except: pass if state == "calculate": print "switching to test1" self.testlabel_1 = tk.Label(self, text="calculate", borderwidth=1, relief=tk.RAISED) self.testlabel_1.grid(row=0, sticky=tk.W+tk.E) elif state == "config": print "switching to test1" self.testlabel_2 = tk.Label(self, text="config", borderwidth=1, relief=tk.RAISED) self.testlabel_2.grid(row=0, sticky=tk.W+tk.E) But the result is the same. The frame (or label in this test) is not displayed at startup, but when the user selects the state (calling the same function) the frame is displayed. UPDATE the sample code in the comments (thanks for that!) pointed me in another direction. Further testing revealed (what I think) the cause of the problem. Disabling the display of the status bar made the program work as expected. Turns out, I used pack to display the statusbar and grid to display the frames. And they are in the same container, so problems arise. I fixed that by using only pack inside the main container. But the same problem is still there. This is what I use for the statusbar: self.status = GUI_helper.StatusBar(self.parent) self.status.pack(side=tk.BOTTOM, fill=tk.X) And if I comment out the last line (pack), the config frame loads on startup, as per this line: self.set_program_state("config") But if I let the status bar pack inside the main window, the config frame does not show. Where it does show when the user asks for it (with the same command as above).

    Read the article

  • AJAX Issue, Works in all browsers except IE

    - by Nik
    Alright, this code works in Chrome and FF, but not IE (which is to be expected). Does anyone see anything wrong with this code that would render it useless in IE? var waittime=400; chatmsg = document.getElementById("chatmsg"); room = document.getElementById("roomid").value; sessid = document.getElementById("sessid").value; chatmsg.focus() document.getElementById("chatwindow").innerHTML = "loading..."; document.getElementById("userwindow").innerHTML = "Loading User List..."; var xmlhttp = false; var xmlhttp2 = false; var xmlhttp3 = false; function ajax_read() { if(window.XMLHttpRequest){ xmlhttp=new XMLHttpRequest(); if(xmlhttp.overrideMimeType){ xmlhttp.overrideMimeType('text/xml'); } } else if(window.ActiveXObject){ try{ xmlhttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try{ xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ } } } if(!xmlhttp) { alert('Giving up :( Cannot create an XMLHTTP instance'); return false; } xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState==4) { document.getElementById("chatwindow").innerHTML = xmlhttp.responseText; setTimeout("ajax_read()", waittime); } } xmlhttp.open('GET','methods.php?method=r&room=' + room +'',true); xmlhttp.send(null); } function user_read() { if(window.XMLHttpRequest){ xmlhttp3=new XMLHttpRequest(); if(xmlhttp3.overrideMimeType){ xmlhttp3.overrideMimeType('text/xml'); } } else if(window.ActiveXObject){ try{ xmlhttp3=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try{ xmlhttp3=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ } } } if(!xmlhttp3) { alert('Giving up :( Cannot create an XMLHTTP instance'); return false; } xmlhttp3.onreadystatechange = function() { if (xmlhttp3.readyState==4) { document.getElementById("userwindow").innerHTML = xmlhttp3.responseText; setTimeout("user_read()", 10000); } } xmlhttp3.open('GET','methods.php?method=u&room=' + room +'',true); xmlhttp3.send(null); } function ajax_write(url){ if(window.XMLHttpRequest){ xmlhttp2=new XMLHttpRequest(); if(xmlhttp2.overrideMimeType){ xmlhttp2.overrideMimeType('text/xml'); } } else if(window.ActiveXObject){ try{ xmlhttp2=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try{ xmlhttp2=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ } } } if(!xmlhttp2) { alert('Giving up :( Cannot create an XMLHTTP instance'); return false; } xmlhttp2.open('GET',url,true); xmlhttp2.send(null); } function submit_msg(){ nick = document.getElementById("chatnick").value; msg = document.getElementById("chatmsg").value; document.getElementById("chatmsg").value = ""; ajax_write("methods.php?method=w&m=" + msg + "&n=" + nick + "&room=" + room + "&sessid=" + sessid + ""); } function keyup(arg1) { if (arg1 == 13) submit_msg(); } var intUpdate = setTimeout("ajax_read()", waittime); var intUpdate = setTimeout("user_read()", 0);

    Read the article

  • Delphi7 - How can i copy a file that is being written to

    - by Simon
    I have an application that logs information to a daily text file every second on a master PC. A Slave PC on the network using the same application would like to copy this text file to its local drive. I can see there is going to be file access issues. These files should be no larger than 30-40MB each. the network will be 100MB ethernet. I can see there is potential for the copying process to take longer than 1 second meaning the logging PC will need to open the file for writing while it is being read. What is the best method for the file writing(logging) and file copying procedures? I know there is the standard Windows CopyFile() procedure, however this has given me file access problems. There is also TFileStream using the fmShareDenyNone flag, but this also very occasionally gives me an access problem too (like 1 per week). What is this the best way of accomplishing this task? My current File Logging: procedure FSWriteline(Filename,Header,s : String); var LogFile : TFileStream; line : String; begin if not FileExists(filename) then begin LogFile := TFileStream.Create(FileName, fmCreate or fmShareDenyNone); try LogFile.Seek(0,soFromEnd); line := Header + #13#10; LogFile.Write(line[1],Length(line)); line := s + #13#10; LogFile.Write(line[1],Length(line)); finally logfile.Free; end; end else begin line := s + #13#10; Logfile:=tfilestream.Create(Filename,fmOpenWrite or fmShareDenyNone); try logfile.Seek(0,soFromEnd); Logfile.Write(line[1], length(line)); finally Logfile.free; end; end; end; My file copy procedure: procedure DoCopy(infile, Outfile : String); begin ForceDirectories(ExtractFilePath(outfile)); //ensure folder exists if FileAge(inFile) = FileAge(OutFile) then Exit; //they are the same modified time try { Open existing destination } fo := TFileStream.Create(Outfile, fmOpenReadWrite or fmShareDenyNone); fo.Position := 0; except { otherwise Create destination } fo := TFileStream.Create(OutFile, fmCreate or fmShareDenyNone); end; try { open source } fi := TFileStream.Create(InFile, fmOpenRead or fmShareDenyNone); try cnt:= 0; fi.Position := cnt; max := fi.Size; {start copying } Repeat dod := BLOCKSIZE; // Block size if cnt+dod>max then dod := max-cnt; if dod>0 then did := fo.CopyFrom(fi, dod); cnt:=cnt+did; Percent := Round(Cnt/Max*100); until (dod=0) finally fi.free; end; finally fo.free; end; end;

    Read the article

  • What to do when ServerSocket throws IOException and keeping server running

    - by s5804
    Basically I want to create a rock solid server. while (keepRunning.get()) { try { Socket clientSocket = serverSocket.accept(); ... spawn a new thread to handle the client ... } catch (IOException e) { e.printStackTrace(); // NOW WHAT? } } In the IOException block, what to do? Is the Server socket at fault so it need to be recreated? For example wait a few seconds and then serverSocket = ServerSocketFactory.getDefault().createServerSocket(MY_PORT); However if the server socket is still OK, then it is a pity to close it and kill all previously accepted connections that are still communicating. EDIT: After some answers, here my attempt to deal with the IOException. Would the implementation be guaranteeing keeping the server up and only re-create server socket when only necessary? while (keepRunning.get()) { try { Socket clientSocket = serverSocket.accept(); ... spawn a new thread to handle the client ... bindExceptionCounter = 0; } catch (IOException e) { e.printStackTrace(); recreateServerSocket(); } } private void recreateServerSocket() { while (keepRunning) { try { logger.info("Try to re-create Server Socket"); ServerSocket socket = ServerSocketFactory.getDefault().createServerSocket(RateTableServer.RATE_EVENT_SERVER_PORT); // No exception thrown, then use the new socket. serverSocket = socket; break; } catch (BindException e) { logger.info("BindException indicates that the server socket is still good.", e); bindExceptionCounter++; if (bindExceptionCounter < 5) { break; } } catch (IOException e) { logger.warn("Problem to re-create Server Socket", e); e.printStackTrace(); try { Thread.sleep(30000); } catch (InterruptedException ie) { logger.warn(ie); } } } }

    Read the article

  • Releasing Excel after using Interop

    - by figus
    Hi everyone I've read many post looking for my answer, but all are similar to this: http://stackoverflow.com/questions/1610743/reading-excel-files-in-vb-net-leaves-excel-process-hanging My problem is that I don't quit the app... The idea is this: If a User has Excel Open, if he has the file I'm interested in open... get that Excel instance and do whatever I want to do... But I don't to close his File after I'm done... I want him to keep working on it, the problem is that when he closes Excel... The process keeps running... and running... and running after the user closes Excel with the X button... this is how I try to do it This piece is used to know if he has Excel open, and in the For I check for the file name I'm interested in. Try oApp = GetObject(, "Excel.Application") libroAbierto = True For Each libro As Microsoft.Office.Interop.Excel.Workbook In oApp.Workbooks If libro.Name = EquipoASeccionIdSeccion.Text & ".xlsm" Then Exit Try End If Next libroAbierto = False Catch ex As Exception oApp = New Microsoft.Office.Interop.Excel.Application End Try here would be my code... if he hasn't Excel open, I create a new instance, open the file and everything else. My code ends with this: If Not libroAbierto Then libroSeccion.Close(SaveChanges:=True) oApp.Quit() Else oApp.UserControl = True libroSeccion.Save() End If System.Runtime.InteropServices.Marshal.FinalReleaseComObject(libroOriginal) System.Runtime.InteropServices.Marshal.FinalReleaseComObject(libroSeccion) System.Runtime.InteropServices.Marshal.FinalReleaseComObject(origen) System.Runtime.InteropServices.Marshal.FinalReleaseComObject(copiada) System.Runtime.InteropServices.Marshal.FinalReleaseComObject(oApp) libroOriginal = Nothing libroSeccion = Nothing oApp = Nothing origen = Nothing copiada = Nothing nuevosGuardados = True So you can see that, if I opened the file, I call oApp.Quit() and everything else and the Excel Process ends after a few seconds (maybe 5 aprox.) BUT if I mean the user to keep the file open (not calling Quit()), Excel process keeps running after the user closes Excel with the X button. Is there any way to do what I try to do?? Control a open instance of excel and releasing everything so when the user closes it with the X button, the Excel Process dies normally??? Thanks!!!

    Read the article

  • VB.NET 2008, Windows 7 and saving files

    - by James Brauman
    Hello, We have to learn VB.NET for the semester, my experience lies mainly with C# - not that this should make a difference to this particular problem. I've used just about the most simple way to save a file using the .NET framework, but Windows 7 won't let me save the file anywhere (or anywhere that I have found yet). Here is the code I am using to save a text file. Dim dialog As FolderBrowserDialog = New FolderBrowserDialog() Dim saveLocation As String = dialog.SelectedPath ... Build up output string ... Try ' Try to write the file. My.Computer.FileSystem.WriteAllText(saveLocation, output, False) Catch PermissionEx As UnauthorizedAccessException ' We do not have permissions to save in this folder. MessageBox.Show("Do not have permissions to save file to the folder specified. Please try saving somewhere different.", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error) Catch Ex As Exception ' Catch any exceptions that occured when trying to write the file. MessageBox.Show("Writing the file was not successful.", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error) End Try The problem is that this using this code throws an UnauthorizedAccessException no matter where I try to save the file. I've tried running the .exe file as administrator, and the IDE as administrator. Is this just Windows 7 being overprotective? And if so, what can I do to solve this problem? The requirements state that I be able to save a file! Thanks.

    Read the article

  • How do I delete the 32k errored document?

    - by Ramkumar
    I am having some documents. If I try to open the document then it shows error like "field is too large 32k or view's column & selection formulas are too large" Whenever I try to delete the document, I am getting the same error. I am not able to delete. Okay we can try to get the document via backend, But there, I can not get the document handle. Whatever I try to search then the document collection count is 0. Important:- I am using Notes 6.5.2. Thanks in Advance,

    Read the article

  • VB .NET error handling, pass error to caller

    - by user1375452
    this is my very first project on vb.net and i am now struggling to migrate a vba working add in to a vb.net COM Add-in. I think i'm sort of getting the hang, but error handling has me stymied. This is a test i've been using to understand the try-catch and how to pass exception to caller Public Sub test() Dim ActWkSh As Excel.Worksheet Dim ActRng As Excel.Range Dim ActCll As Excel.Range Dim sVar01 As String Dim iVar01 As Integer Dim sVar02 As String Dim iVar02 As Integer Dim objVar01 As Object ActWkSh = Me.Application.ActiveSheet ActRng = Me.Application.Selection ActCll = Me.Application.ActiveCell iVar01 = iVar02 = 1 sVar01 = CStr(ActCll.Value) sVar02 = CStr(ActCll.Offset(1, 0).Value) Try objVar01 = GetValuesV(sVar01, sVar02) 'DO SOMETHING HERE Catch ex As Exception MsgBox("ERRORE: " + ex.Message) 'LOG ERROR SOMEWHERE Finally MsgBox("DONE!") End Try End Sub Private Function GetValuesV(ByVal QryStr As Object, ByVal qryConn As String) As Object Dim cnn As Object Dim rs As Object Try cnn = CreateObject("ADODB.Connection") cnn.Open(qryConn) rs = CreateObject("ADODB.recordset") rs = cnn.Execute(QryStr) If rs.EOF = False Then GetValuesV = rs.GetRows Else Throw New System.Exception("Query Return Empty Set") End If Catch ex As Exception Throw ex Finally rs.Close() cnn.Close() End Try End Function i'd like to have the error message up to test, but MsgBox("ERRORE: " + ex.Message) pops out something unexpected (Object variable or With block variable not set) What am i doing wrong here?? Thanks D

    Read the article

  • Correct way to close database connection in event of exception.

    - by lowlyintern
    /I have some code of of the following form. Does this mean the connection is left open if there is an exception? Note, I am using a Microsoft SQL compact edition database./ try { SqlCeConnection conn = new SqlCeConnection(ConnectionString); conn.Open(); using (SqlCeCommand cmd = new SqlCeCommand("SELECT stuff FROM SomeTable", conn)) { // do some stuff } conn.Close(); } catch (Exception ex) { ExceptionManager.HandleException(ex); } /*Surely a better way would be to declare a connection object before the try, establish a connection inside the try block and close it in a finally block? */ SqlCeConnection conn = null; try { conn = new SqlCeConnection(ConnectionString); conn.Open(); using (SqlCeCommand cmd = new SqlCeCommand("SELECT stuff FROM SomeTable", conn)) { // do some stuff } } catch (Exception ex) { ExceptionManager.HandleException(ex); } finally { if( conn != null ) conn.Close(); }

    Read the article

  • Initialising vals which might throw an exception

    - by Paul Butcher
    I need to initialise a set of vals, where the code to initialise them might throw an exception. I'd love to write: try { val x = ... generate x value ... val y = ... generate y value ... } catch { ... exception handling ... } ... use x and y ... But this (obviously) doesn't work because x and y aren't in scope outside of the try. It's easy to solve the problem by using mutable variables: var x: Whatever = _ var y: Whatever = _ try { x = ... generate x value ... y = ... generate y value ... } catch { ... exception handling ... } ... use x and y ... But that's not exactly very nice. It's also easy to solve the problem by duplicating the exception handling: val x = try { ... generate x value ... } catch { ... exception handling ... } val y = try { ... generate y value ... } catch { ... exception handling ... } ... use x and y ... But that involves duplicating the exception handling. There must be a "nice" way, but it's eluding me.

    Read the article

  • Exception Handling in MVP Passive View

    - by ilmatte
    Hello, I'm wondering what's the preferred way to manage exceptions in an MVP implemented with a Passive View. There's a discussion in my company about putting try/catch blocks in the presenter or only in the view. In my opinion the logical top level caller is the presenter (even if the actual one is the view). Moreover I can test the presenter and not the view. This is the reason why I prefer to define a method in the view interface: IView.ShowError(error) and invoke it from the catch blocks in the presenter: try { } catch (Exception exception) { ...log exception... view.ShowError("An error occurred") } In this way the developers of future views can safely forget to implement exception handling but the IView interface force them to implement a ShowError method. The drawback is that if I want to feel completely safe I need to add redundant try/catch blocks in the view. The other way would be to add try catch blocks only in the views and not introducing the showerror method in the view interface. What do you suggest?

    Read the article

  • Dual AJAX Requests at different times

    - by Nik
    Alright, I'm trying to make an AJAX Chat system that polls the chat database every 400ms. That part is working, the part of which isn't is the Active User List. When I try to combine the two requests, the first two requests are made, then the whole thing snowballs and the usually timed (12 second) Active User List request starts updating every 1ms and the first request NEVER happens again. Displayed is the entire AJAX code for both requests: var waittime=400;chatmsg=document.getElementById("chatmsg"); room = document.getElementById("roomid").value; chatmsg.focus() document.getElementById("chatwindow").innerHTML = "loading..."; document.getElementById("userwindow").innerHTML = "Loading User List..."; var xmlhttp = false; var xmlhttp2 = false; var xmlhttp3 = false; function ajax_read(url) { if(window.XMLHttpRequest){ xmlhttp=new XMLHttpRequest(); if(xmlhttp.overrideMimeType){ xmlhttp.overrideMimeType('text/xml'); } } else if(window.ActiveXObject){ try{ xmlhttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try{ xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ } } } if(!xmlhttp) { alert('Giving up :( Cannot create an XMLHTTP instance'); return false; } xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState==4) { document.getElementById("chatwindow").innerHTML = xmlhttp.responseText; setTimeout("ajax_read('methods.php?method=r&room=" + room +"')", waittime); } } xmlhttp.open('GET',url,true); xmlhttp.send(null); } function user_read(url) { if(window.XMLHttpRequest){ xmlhttp3=new XMLHttpRequest(); if(xmlhttp3.overrideMimeType){ xmlhttp3.overrideMimeType('text/xml'); } } else if(window.ActiveXObject){ try{ xmlhttp3=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try{ xmlhttp3=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ } } } if(!xmlhttp3) { alert('Giving up :( Cannot create an XMLHTTP instance'); return false; } xmlhttp3.onreadystatechange = function() { if (xmlhttp3.readyState==4) { document.getElementById("userwindow").innerHTML = xmlhttp3.responseText; setTimeout("ajax_read('methods.php?method=u&room=" + room +"')", 12000); } } xmlhttp3.open('GET',url,true); xmlhttp3.send(null); } function ajax_write(url){ if(window.XMLHttpRequest){ xmlhttp2=new XMLHttpRequest(); if(xmlhttp2.overrideMimeType){ xmlhttp2.overrideMimeType('text/xml'); } } else if(window.ActiveXObject){ try{ xmlhttp2=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try{ xmlhttp2=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e){ } } } if(!xmlhttp2) { alert('Giving up :( Cannot create an XMLHTTP instance'); return false; } xmlhttp2.open('GET',url,true); xmlhttp2.send(null); } function submit_msg(){ nick = document.getElementById("chatnick").value; msg = document.getElementById("chatmsg").value; document.getElementById("chatmsg").value = ""; ajax_write("methods.php?method=w&m=" + msg + "&n=" + nick + "&room=" + room + ""); } function keyup(arg1) { if (arg1 == 13) submit_msg(); } var intUpdate = setTimeout("ajax_read('methods.php')", waittime); var intUpdate = setTimeout("user_read('methods.php')", waittime);

    Read the article

  • How do I run a sudo command in Emacs?

    - by Inaimathi
    I tried using shell-command, but it just does something like this: Sudo password: incorrect, try again. Sudo password: incorrect, try again. Sudo password: incorrect, try again. Failed three attempts. without actually asking for a password. I don't want to have to start up Emacs using sudo emacs, but I guess that's an option if nothing else will work.

    Read the article

  • non blocking client server chat application in java using nio

    - by Amith
    I built a simple chat application using nio channels. I am very much new to networking as well as threads. This application is for communicating with server (Server / Client chat application). My problem is that multiple clients are not supported by the server. How do I solve this problem? What's the bug in my code? public class Clientcore extends Thread { SelectionKey selkey=null; Selector sckt_manager=null; public void coreClient() { System.out.println("please enter the text"); BufferedReader stdin=new BufferedReader(new InputStreamReader(System.in)); SocketChannel sc = null; try { sc = SocketChannel.open(); sc.configureBlocking(false); sc.connect(new InetSocketAddress(8888)); int i=0; while (!sc.finishConnect()) { } for(int ii=0;ii>-22;ii++) { System.out.println("Enter the text"); String HELLO_REQUEST =stdin.readLine().toString(); if(HELLO_REQUEST.equalsIgnoreCase("end")) { break; } System.out.println("Sending a request to HelloServer"); ByteBuffer buffer = ByteBuffer.wrap(HELLO_REQUEST.getBytes()); sc.write(buffer); } } catch (IOException e) { e.printStackTrace(); } finally { if (sc != null) { try { sc.close(); } catch (Exception e) { e.printStackTrace(); } } } } public void run() { try { coreClient(); } catch(Exception ej) { ej.printStackTrace(); }}} public class ServerCore extends Thread { SelectionKey selkey=null; Selector sckt_manager=null; public void run() { try { coreServer(); } catch(Exception ej) { ej.printStackTrace(); } } private void coreServer() { try { ServerSocketChannel ssc = ServerSocketChannel.open(); try { ssc.socket().bind(new InetSocketAddress(8888)); while (true) { sckt_manager=SelectorProvider.provider().openSelector(); ssc.configureBlocking(false); SocketChannel sc = ssc.accept(); register_server(ssc,SelectionKey.OP_ACCEPT); if (sc == null) { } else { System.out.println("Received an incoming connection from " + sc.socket().getRemoteSocketAddress()); printRequest(sc); System.err.println("testing 1"); String HELLO_REPLY = "Sample Display"; ByteBuffer buffer = ByteBuffer.wrap(HELLO_REPLY.getBytes()); System.err.println("testing 2"); sc.write(buffer); System.err.println("testing 3"); sc.close(); }}} catch (IOException e) { e.printStackTrace(); } finally { if (ssc != null) { try { ssc.close(); } catch (IOException e) { e.printStackTrace(); } } } } catch(Exception E) { System.out.println("Ex in servCORE "+E); } } private static void printRequest(SocketChannel sc) throws IOException { ReadableByteChannel rbc = Channels.newChannel(sc.socket().getInputStream()); WritableByteChannel wbc = Channels.newChannel(System.out); ByteBuffer b = ByteBuffer.allocate(1024); // read 1024 bytes while (rbc.read(b) != -1) { b.flip(); while (b.hasRemaining()) { wbc.write(b); System.out.println(); } b.clear(); } } public void register_server(ServerSocketChannel ssc,int selectionkey_ops)throws Exception { ssc.register(sckt_manager,selectionkey_ops); }} public class HelloClient { public void coreClientChat() { Clientcore t=new Clientcore(); new Thread(t).start(); } public static void main(String[] args)throws Exception { HelloClient cl= new HelloClient(); cl.coreClientChat(); }} public class HelloServer { public void coreServerChat() { ServerCore t=new ServerCore(); new Thread(t).start(); } public static void main(String[] args) { HelloServer st= new HelloServer(); st.coreServerChat(); }}

    Read the article

  • Strange Java Socket Behavior (Connects, but Doesn't Send)

    - by Donald Campbell
    I have a fairly complex project that boils down to a simple Client / Server communicating through object streams. Everything works flawlessly for two consecutive connections (I connect once, work, disconnect, then connect again, work, and disconnect). The client connects, does its business, and then closes. The server successfully closes both the object output stream and the socket, with no IO errors. When I try to connect a third time, the connection appears to go through (the ServerSocket.accept() method goes through and an ObjectOutputStream is successfully created). No data is passed, however. The inputStream.readUnshared() method simply blocks. I have taken the following memory precautions: When it comes time to close the sockets, all running threads are stopped, and all objects are nulled out. After every writeUnshared() method call, the ObjectOutputBuffer is flushed and reset. Has anyone encountered a similar problem, or does anyone have any suggestions? I'm afraid my project is rather large, and so copying code is problematic. The project boils down to this: SERVER MAIN ServerSocket serverSocket = new ServerSocket(port); while (true) { new WorkThread(serverSocket.accept()).start(); } WORK THREAD (SERVER) public void run() { ObjectInputBuffer inputBuffer = new ObjectInputBuffer(new BufferedInputStream(socket.getInputStream())); while (running) { try { Object myObject = inputBuffer.readUnshared(); // do work is not specified in this sample doWork(myObject); } catch (IOException e) { running = false; } } try { inputBuffer.close(); socket.close(); } catch (Exception e) { System.out.println("Could not close."); } } CLIENT public Client() { Object myObject; Socket mySocket = new Socket(address, port); try { ObjectOutputBuffer output = new ObjectOutputBuffer(new BufferedOutputStream(mySocket.getOutputStream())); output.reset(); output.flush(); } catch (Exception e) { System.out.println("Could not get an input."); mySocket.close(); return; } // get object data is not specified in this sample. it simply returns a serializable object myObject = getObjectData(); while (myObject != null) { try { output.writeUnshared(myObject); output.reset(); output.flush(); } catch (Exception e) { e.printStackTrace(); break; } // catch } // while try { output.close(); socket.close(); } catch (Exception e) { System.out.println("Could not close."); } } Thank you to everyone who may be able to help!

    Read the article

  • I've caught an exception!! Now what?

    - by Jonesy
    Hi folks, I've started using try catch blocks (bit late i know!) but now im not sure what to do with the exception once i've caught it. What do people usually do here? -- Jonesy Try connection.Open() Dim sqlCmd As New SqlCommand("do some SQL", connection) Dim sqlDa As New SqlDataAdapter(sqlCmd) sqlDa.Fill(dt) Catch ex As SQLException ' ahhhh what to do now!!!? Finally connection.Close() End Try

    Read the article

  • Question about Transact SQL syntax

    - by Yousui
    Hi guys, The following code works like a charm: BEGIN TRY BEGIN TRANSACTION COMMIT TRANSACTION END TRY BEGIN CATCH IF @@TRANCOUNT > 0 ROLLBACK; DECLARE @ErrorMessage NVARCHAR(4000), @ErrorSeverity int; SELECT @ErrorMessage = ERROR_MESSAGE(), @ErrorSeverity = ERROR_SEVERITY(); RAISERROR(@ErrorMessage, @ErrorSeverity, 1); END CATCH But this code gives an error: BEGIN TRY BEGIN TRANSACTION COMMIT TRANSACTION END TRY BEGIN CATCH IF @@TRANCOUNT > 0 ROLLBACK; RAISERROR(ERROR_MESSAGE(), ERROR_SEVERITY(), 1); END CATCH Why?

    Read the article

  • How to stop live network traffic displayed in terminal?

    - by Jakobud
    For our network we are working on building a new firewall box and we just installed Smoothwall on it to test it out. When I start up the box, before the login prompt even appears, all of the live IP traffic is appearing in the terminal (source/destination IPs, MACs, Ports, etc). I wait for the boot sequence to finish, but all I see is this IP traffic. The login prompt never comes up. I finally get sick of waiting and press CTRL + C and it says "Entering Run Level 3" and then I get a login prompt finally. Once I login, the IP traffic continues to fly through the terminal even as I'm trying to type commands. How do I turn this stuff off? Is this the default setting for Smoothwall to have all this IP traffic going by on the screen? It essentially renders using the terminal to being useless.

    Read the article

  • Must JDBC Resultsets and Statements be closed separately although the Connection is closed afterwards?

    - by Mulmoth
    It is said to be a good habit to close all JDBC resources after usage. But if I have the following code, is it necessary to close the Resultset and the Statement? Connection conn = null; PreparedStatement stmt = null; ResultSet rs = null; try { conn = // Retrieve connection stmt = conn.prepareStatement(// Some SQL); rs = stmt.executeQuery(); } catch { // Error Handling } finally { try { if (rs != null) rs.close(); } catch (Exception e) {}; try { if (stmt != null) stmt.close(); } catch (Exception e) {}; try { if (conn != null) conn.close(); } catch (Exception e) {}; } The question is if the closing of the connection does the job or if it leaves some resources in use.

    Read the article

  • Set Positions returns E_NOTIMPL

    - by Manish
    Hi, I want to write only a specific portion of a .avi file in the output .avi file .For this I follow Source Filter -Avi mux-File Writer.I try to use IMediaSeeking on the Mux to set the specific start and stop times using Set Positions but it returns E_NOTIMPL. I also try to query the graph builder for IMediaSeeking and try to set the start and stop positions with no success.Can someone help?

    Read the article

  • Functioning Socket read no longer works when called in AsyncTask

    - by bibismcbryde
    I'm making an app that sends a string to a server over a socket and then reads the output after the server has processed that data. It worked perfectly when it was my foreground task, but I have since used AsyncTask to show a process dialog while the socket communication runs in the background, and things start breaking after I read the output from the server and then try to close the socket. private class Progressor extends AsyncTask<String, Void, Void> { ProgressDialog dialog; protected void onPreExecute() { dialog = ProgressDialog.show(ClearTalkInputActivity.this, "Loading..", "Analyzing Text", true, false); } protected Void doInBackground(String... strings) { String language = strings[0].toLowerCase(); String the_text = strings[1]; Socket socket = null; DataOutputStream dos = null; DataInputStream dis = null; try { socket = new Socket(my_ip, port); dos = new DataOutputStream(socket.getOutputStream()); dis = new DataInputStream(socket.getInputStream()); dos.writeUTF(language+"****"+the_text); String in = ""; while (in.indexOf("</content>") < 0) { in += dis.readUTF(); } socket.close(); save_str(OUTPUT_KEY, in); } catch (UnknownHostException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { if (socket != null) { try { socket.close(); } catch (IOException e) { e.printStackTrace(); } } } if (dos != null) { try { dos.close(); } catch (IOException e) { e.printStackTrace(); } } if (dis != null) { try { dis.close(); } catch (IOException e) { e.printStackTrace(); } } return null; } protected void onPostExecute() { if (dialog.isShowing()) dialog.dismiss(); startActivity(new Intent (output_intent)); } }

    Read the article

  • Segmentation fault, shared library

    - by user1306184
    I get Segmentation Fault when I try to run my program. Can someone please help me find out what Im doing wrong? Compiling with this: g++ sms_out.cpp -o sms_out g++ -c -fPIC SMSDispatch.cpp g++ -shared SMSDispatch.o -o libSMSDispatch.so It should be a shared library and dynamic linking. I get Segmentation Fault when I try to run sms_out. //sms_out.cpp #include <iostream> #include<cstdlib> #include<fstream> #include<sstream> #include<string> #include "SMSDispatch.h" using namespace std; string sms = ""; void sendSMS(string sms) { SMSDispatch* sPtr=0; sPtr->sendSMS(sms); } int main(int argc, char *argv[]) { if(argv[1]) { string input = argv[1]; string test = "--author"; if(input == test) { cout << "s149113" << endl; return 0; } } string line = ""; string file = "sms_out.txt"; ifstream myfile(file.c_str()); while(getline(myfile, line)) { string idnr, landcode, number, error; istringstream linestream(line); unsigned short errorcode; //Split the sentence getline(linestream, idnr, '\t'); getline(linestream, landcode, ':'); getline(linestream, number, '\t'); getline(linestream, error); if(idnr == "") break; //Make string to int try { errorcode = atoi(error.c_str() ); } catch (exception &) { } //Put together landcode and tlfnumber string nr = landcode + number; string txt = "Thank you for your vote!"; if(errorcode == 100) txt = "Invalid question, please try again"; else if(errorcode == 110) txt = "Sorry, only one vote pr. number"; else if(errorcode == 200) txt = "Invalid alternative, please try again"; else if(errorcode == 300) txt = "Missing a statement after other, please try again"; else if(errorcode == 999) txt = "An error occurred, please try again"; sms += "{\"ID\":" + idnr + ",\"nr\":" + nr + ",\"txt\":" + "\"" + txt + "\"" + "}\n"; } cout << sms << endl; sendSMS(sms); } //SMSDispatch.h #include <string> #ifndef SMSDISPATCH_H #define SMSDISPATCH_H using namespace std; class SMSDispatch{ public: virtual void sendSMS(string json); }; #endif //SMSDispatch.cpp #include <iostream> #include <fstream> #include "SMSDispatch.h" using namespace std; /*virtual*/void SMSDispatch::sendSMS(string json) { ofstream myfile; myfile.open ("sms_out.log"); myfile << json; myfile.close(); } int main() { }

    Read the article

< Previous Page | 28 29 30 31 32 33 34 35 36 37 38 39  | Next Page >