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  • Facebook Authentication Error when using apps.facebook.com as URL

    - by Adi Mathur
    I am trying to login on my website using Facebook Authentication and it works fine . How ever when i access the Application by using https://apps.facebook.com/myApp then i get an error The state does not match. You may be a victim of CSRF Here is the code that i am using from facebook , I think there is a problem in $my_url <?php $app_id = "YOUR_APP_ID"; $app_secret = "YOUR_APP_SECRET"; $my_url = "https://www.example.com/login.php"; session_start(); $code = $_REQUEST["code"]; if(empty($code)) { $_SESSION['state'] = md5(uniqid(rand(), TRUE)); //CSRF protection $dialog_url = "https://www.facebook.com/dialog/oauth?client_id=" . $app_id . "&redirect_uri=" . urlencode($my_url) . "&state=" . $_SESSION['state']; echo("<script> top.location.href='" . $dialog_url . "'</script>"); } if($_REQUEST['state'] == $_SESSION['state']) { $token_url = "https://graph.facebook.com/oauth/access_token?" . "client_id=" . $app_id . "&redirect_uri=" . urlencode($my_url) . "&client_secret=" . $app_secret . "&code=" . $code; $response = file_get_contents($token_url); $params = null; parse_str($response, $params); $graph_url = "https://graph.facebook.com/me?access_token=" . $params['access_token']; $user = json_decode(file_get_contents($graph_url)); echo("Hello " . $user->name); } else { echo("The state does not match. You may be a victim of CSRF."); } ?>

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  • silverlight authentication

    - by user291400
    Good day! I have an silverlight site (silverlight navigation application) and I want clients to log in on my site. I want to give them different rights of viewing pages. A WCF service gives me true or false when I enter a login and a password. Then, if it returns true, I want to remember the logged user. How can I do it? Using cookies or global variable or something else?

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  • Automatic authentication in PHPMyAdmin

    - by Konstantin
    Hello! I have a local phpMyAdmin (installed via apt-get) adn I'm tired of entering login and password every time I try to open it. Database contains no sensitive info, just test tables, and is visible only from 127.0.0.1 I want phpMyAdmin already be logged in as root user with password 1234 (for example) when I open it. How do I do that? P.S. Saving password in a browser is not what I want.

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  • Twitter authentication without authorization

    - by user325377
    I wish to get the tweeter usename of a visitor to my site. I do not wish to post statuses or access any other information. I'd be happy to use OAuth, possibly with a 'Sign in with Twitter' button, but this then takes the user to a page which requests authorization for the application, that I wish to avoid. Is there a way to get the username without authorization? Thanks, Daniel

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  • Pass authentication between php and Ruby On Rails application

    - by Li
    Hi, I have a simple Ruby on rails application that I want to integrate with an existing php website. I only want that users who's been authenticated by the php application would have access to my Ruby on Rails application (it should appear to the user as the same website, in the same domain, though it can be a different sub-domain if I chose to) What's the best way to do that? Thanks for the help, Li

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  • .htaccess authentication from a php script to prevent a browser dialog box

    - by digitalbart
    Using php I authenticate a user, then behind the scenes,they are then again authenticated a second time with a single .htaccess username & password. This would be the same for all users, but I would not want them to have to enter a username and password again and they would now be allowed to enter the password protected directory. I prefer not to use http://username@password:somedomain.com. Any thoughts?

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  • How Google is managing authentication between multiple domains?

    - by vaibhav
    I think everyone here would be knowing that, if I am logged in any of the google's website(i.e www.orkut.com), I don't need to authenticate again for www.gmail.com. How google is managing this. I think, it would be a cookie stored on user's browser. But, if it is a cookie, how different domains are able to read this cookie. What do you say.

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  • Where to Perform Authentication in REST API Server?

    - by David V
    I am working on a set of REST APIs that needs to be secured so that only authenticated calls will be performed. There will be multiple web apps to service these APIs. Is there a best-practice approach as to where the authentication should occur? I have thought of two possible places. Have each web app perform the authentication by using a shared authentication service. This seems to be in line with tools like Spring Security, which is configured at the web app level. Protect each web app with a "gateway" for security. In this approach, the web app never receives unauthenticated calls. This seems to be the approach of Apache HTTP Server Authentication. With this approach, would you use Apache or nginx to protect it, or something else in between Apache/nginx and your web app? For additional reference, the authentication is similar to services like AWS that have a non-secret identifier combined with a shared secret key. I am also considering using HMAC. Also, we are writing the web services in Java using Spring. Update: To clarify, each request needs to be authenticated with the identifier and secret key. This is similar to how AWS REST requests work.

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  • Download a file with DefaultHTTPClient and preemptive authentication

    - by Nils
    After I had a lot of problems with preemptive authentication , I got it finally working. Now the next problem. I want to get a file with it, but I don't know how. I thought the file data might be in the variable response, but it isn't. Any ideas how this might work? I'm trying it since days without success :( - Basically I'm trying to download an jpeg file, which is on a server protected by prem. auth. // BASIC AUTH /* * ==================================================================== * * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements. See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. * ==================================================================== * * This software consists of voluntary contributions made by many * individuals on behalf of the Apache Software Foundation. For more * information on the Apache Software Foundation, please see * <http://www.apache.org/>. */ //http://svn.apache.org/repos/asf/httpcomponents/httpclient/branches/4.0.x/httpclient/src/examples/org/apache/http/examples/client/ClientPreemptiveBasicAuthentication.java httpclient = new DefaultHttpClient(); httpclient.getCredentialsProvider().setCredentials( new AuthScope(host, port), new UsernamePasswordCredentials(username, password)); // Generate BASIC scheme object and stick it to the local // execution context BasicHttpContext localcontext = new BasicHttpContext(); BasicScheme basicAuth = new BasicScheme(); localcontext.setAttribute("preemptive-auth", basicAuth); //first request interceptor httpclient.addRequestInterceptor(new PreemptiveAuth(), 0); HttpHost targetHost = new HttpHost(host, port, "http"); //HttpGet httpget = new HttpGet("/"); HttpGet httpget = new HttpGet(http.url); System.out.println("executing request" + httpget.getRequestLine()); /// !!! HttpResponse response = httpclient.execute(targetHost, httpget, localcontext); HttpEntity entity = response.getEntity(); System.out.println("----------------------------------------"); System.out.println("+"+response.getStatusLine()+"+"); ...

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  • Apache HttpClient Digest authentication

    - by Milan Jovic
    Hi, Basically what I need to do is to perform digest authentication. First thing I tried is the official example available here. But when I try to execute it(with some small changes, Post instead of the the Get method) I get a org.apache.http.auth.MalformedChallengeException: missing nonce in challange at org.apache.http.impl.auth.DigestScheme.processChallenge(DigestScheme.java:132) When this failed I tried using: DefaultHttpClient client = new DefaultHttpClient(); client.getCredentialsProvider().setCredentials(new AuthScope(null, -1, null), new UsernamePasswordCredentials("<username>", "<password>")); HttpPost post = new HttpPost(URI.create("http://<someaddress>")); List<NameValuePair> nvps = new ArrayList<NameValuePair>(); nvps.add(new BasicNameValuePair("domain", "<username>")); post.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8)); DigestScheme digestAuth = new DigestScheme(); digestAuth.overrideParamter("algorithm", "MD5"); digestAuth.overrideParamter("realm", "http://<someaddress>"); digestAuth.overrideParamter("nonce", Long.toString(new Random().nextLong(), 36)); digestAuth.overrideParamter("qop", "auth"); digestAuth.overrideParamter("nc", "0"); digestAuth.overrideParamter("cnonce", DigestScheme.createCnonce()); Header auth = digestAuth.authenticate(new UsernamePasswordCredentials("<username>", "<password>"), post); System.out.println(auth.getName()); System.out.println(auth.getValue()); post.setHeader(auth); HttpResponse ret = client.execute(post); ByteArrayOutputStream v2 = new ByteArrayOutputStream(); ret.getEntity().writeTo(v2); System.out.println("----------------------------------------"); System.out.println(v2.toString()); System.out.println("----------------------------------------"); System.out.println(ret.getStatusLine().getReasonPhrase()); System.out.println(ret.getStatusLine().getStatusCode()); At first I have only overridden "realm" and "nonce" DigestScheme parameters. But it turned out that PHP script running on the server requires all other params, but no matter if I specify them or not DigestScheme doesn't generate them when I call its authenticate() method. I've been struggling with this for two days, and no luck. Based on everything I think that the cause of the problem is the PHP script. It looks to me that it doesn't send a challenge when app tries to access it unauthorized. Any ideas anyone?

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  • Problem with Twitter basic authentication using AJAX

    - by jelford
    I'm developing a javascript App that needs, as part of its functionality, for users to be able to update their Twitter status. The App is designed to work on mobiles, and as such I don't really want to be sending users all the way over to the Twitter site to sign in; they should just be able to pass their credentials to the app, and I'll handle all the signin. So I'm trying to use the Basic Auth with the restful API. My code looks like: function postTweet(input){ $.ajax( { type: "POST", url: "http://twitter.com/statuses/update.json", data: {status: input}, dataType: "json", error: function() { alert("Some error occured"); }, success: function() { alert("Success!"); }, beforeSend: function(request) { request.setRequestHeader("Authorization", "Basic BASE64OFMYCREDENTIALS");} } ) ; } So, as far as I'm aware, this should perform the authentication from the XMLHttpRequest header, and then post the status. However, whenever I call this code, I get a "401 Unauthorized" error from Twitter. Below are the request & response headers from firebug: Request: OPTIONS /statuses/update.json HTTP/1.1 Host: twitter.com User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-GB; rv:1.9.2) Gecko/20100115 Firefox/3.6 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-gb,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Origin: null Access-Control-Request-Method: POST Access-Control-Request-Headers: authorization Response: HTTP/1.1 401 Unauthorized Date: Sat, 13 Mar 2010 11:08:58 GMT Server: hi Status: 401 Unauthorized WWW-Authenticate: Basic realm="Twitter API" X-Runtime: 0.00204 Content-Type: application/json; charset=utf-8 Cache-Control: no-cache, max-age=300 Set-Cookie: guest_id=1268478538488; path=/ _twitter_sess=BAh7CDoPY3JlYXRlZF9hdGwrCPlyNlcnAToHaWQiJWUyN2YzYjc3OTk2NGQ3%250ANzJkYTA4MjYzOWJmYTQyYmUyIgpmbGFzaElDOidBY3Rpb25Db250cm9sbGVy%250AOjpGbGFzaDo6Rmxhc2hIYXNoewAGOgpAdXNlZHsA--d687808459872da0aa6a89cab35fd347300b4d07; domain=.twitter.com; path=/ Expires: Sat, 13 Mar 2010 11:13:58 GMT Vary: Accept-Encoding Content-Encoding: gzip Content-Length: 88 Connection: close Any help with this would be much appreciated, Thanks, jelford ps. I should mention I'm using JQuery, incase it's not clear.

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  • 401 error when consuming a Web service with HTTP Basic authentication using CXF

    - by seanhodges
    I'm trying to consume a remote Web service that uses HTTP basic authentication, using Apache CXF, within a JUnit test. The error I am getting is: javax.xml.ws.WebServiceException: Failed to access the WSDL at: http://localhost:8080/services/MyService?wsdl. It failed with: Server returned HTTP response code: 401 for URL: http://localhost:8080/services/MyService?wsdl. at com.sun.xml.internal.ws.wsdl.parser.RuntimeWSDLParser.tryWithMex(RuntimeWSDLParser.java:151) at com.sun.xml.internal.ws.wsdl.parser.RuntimeWSDLParser.parse(RuntimeWSDLParser.java:133) at com.sun.xml.internal.ws.client.WSServiceDelegate.parseWSDL(WSServiceDelegate.java:254) at com.sun.xml.internal.ws.client.WSServiceDelegate.<init>(WSServiceDelegate.java:217) at com.sun.xml.internal.ws.client.WSServiceDelegate.<init>(WSServiceDelegate.java:165) at com.sun.xml.internal.ws.spi.ProviderImpl.createServiceDelegate(ProviderImpl.java:93) at javax.xml.ws.Service.<init>(Service.java:76) at com.wave2.marketplace.importer.impl.adportal.ws.MyServiceService.<init>(MyServiceService.java:37) at com.wave2.marketplace.importer.impl.adportal.MyWSTest.testConsumingTheWS(MyWSTest.java:22) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at junit.framework.TestCase.runTest(TestCase.java:168) at junit.framework.TestCase.runBare(TestCase.java:134) at junit.framework.TestResult$1.protect(TestResult.java:110) at junit.framework.TestResult.runProtected(TestResult.java:128) at junit.framework.TestResult.run(TestResult.java:113) at junit.framework.TestCase.run(TestCase.java:124) at junit.framework.TestSuite.runTest(TestSuite.java:232) at junit.framework.TestSuite.run(TestSuite.java:227) at org.junit.internal.runners.JUnit38ClassRunner.run(JUnit38ClassRunner.java:83) at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:46) at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197) Caused by: java.io.IOException: Server returned HTTP response code: 401 for URL: http://localhost:8080/services/MyService?wsdl at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1269) at java.net.URL.openStream(URL.java:1029) at com.sun.xml.internal.ws.wsdl.parser.RuntimeWSDLParser.createReader(RuntimeWSDLParser.java:793) at com.sun.xml.internal.ws.wsdl.parser.RuntimeWSDLParser.resolveWSDL(RuntimeWSDLParser.java:251) at com.sun.xml.internal.ws.wsdl.parser.RuntimeWSDLParser.parse(RuntimeWSDLParser.java:118) ... 26 more Having read this StackOverflow post, I have attempted to add the auth credentials to my request context, as follows: @Test public void testConsumingTheWS() throws Exception { URL wsdl = new URL("http://localhost:8080/services/MyService?wsdl"); MyServiceService provider = new MyServiceService(wsdl); // <-- Error occurs here MyService service = provider.getMyService(); BindingProvider binding = (BindingProvider)service; binding.getRequestContext().put(BindingProvider.USERNAME_PROPERTY, "username"); binding.getRequestContext().put(BindingProvider.PASSWORD_PROPERTY, "password"); Ping out = service.getPing(); assertNotNull(out); } However, as my in-line comment indicates, the error is occurring before the BindingProvider code is reached, so the error remains the same. I did have a read of this article and its follow-up, but so far I've had trouble determining how to go about adding the interceptor code without the use of Spring (this is for a JUnit test). How might I go about authenticating against this Web service?

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  • HTTP Authentication with Web References

    - by Thor
    I have a web reference created from the WSDL, but I'm not allowed to call the function unless I pass in the username / password; the original code for the XML toolkit was: Set client = CreateObject("MSSOAP.SOAPClient30") URL = "http://" & host & "/_common/webservices/Trend?wsdl" client.mssoapinit (URL) client.ConnectorProperty("WinHTTPAuthScheme") = 1 client.ConnectorProperty("AuthUser") = user client.ConnectorProperty("AuthPassword") = passwd On Error GoTo err Dim result1() As String result1 = client.getTrendData(expression, startDate, endDate, limitFromStart, maxRecords How do I add the AuthUser/AuthPassword to my new code? New code: ALCServer.TrendClient tc = new WindowsFormsApplication1.ALCServer.TrendClient(); foreach(string s in tc.getTrendData(textBox2.Text, "5/25/2009", "5/28/2009", false, 500)) textBox1.Text+= s;

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  • Cocoa Basic HTTP Authentication : Advice Needed..

    - by Kristiaan
    Hello all, im looking to read the contents of a webpage that is secured with a user name and password. this is a mac OS X application NOT an iphone app so most of the things i have read on here or been suggested to read do not seem to work. Also i am a total beginner with Xcode and Obj C i was told to have a look at a website that provided sample code to http auth however so far i have had little luck in getting this working. below is the main code for the button press in my application, there is also another unit called Base64 below that has some code in i had to change to even get it compiling (no idea if what i changed is correct mind you). NSURL *url = [NSURL URLWithString:@"my URL"]; NSString *userName = @"UN"; NSString *password = @"PW"; NSError *myError = nil; // create a plaintext string in the format username:password NSMutableString *loginString = (NSMutableString*)[@"" stringByAppendingFormat:@"%@:%@", userName, password]; // employ the Base64 encoding above to encode the authentication tokens char *encodedLoginData = [base64 encode:[loginString dataUsingEncoding:NSUTF8StringEncoding]]; // create the contents of the header NSString *authHeader = [@"Basic " stringByAppendingFormat:@"%@", [NSString stringWithCString:encodedLoginData length:strlen(encodedLoginData)]]; //NSString *authHeader = [@"Basic " stringByAppendingFormat:@"%@", loginString];//[NSString stringWithString:loginString length:strlen(loginString)]]; NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL: url cachePolicy: NSURLRequestReloadIgnoringCacheData timeoutInterval: 3]; // add the header to the request. Here's the $$$!!! [request addValue:authHeader forHTTPHeaderField:@"Authorization"]; // perform the reqeust NSURLResponse *response; NSData *data = [NSURLConnection sendSynchronousRequest: request returningResponse: &response error: &myError]; //*error = myError; // POW, here's the content of the webserver's response. NSString *result = [NSString stringWithCString:[data bytes] length:[data length]]; [myTextView setString:result]; code from the BASE64 file #import "base64.h" static char *alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+-"; @implementation Base64 +(char *)encode:(NSData *)plainText { // create an adequately sized buffer for the output. every 3 bytes // become four basically with padding to the next largest integer // divisible by four. char * encodedText = malloc((((([plainText length] % 3) + [plainText length]) / 3) * 4) + 1); char* inputBuffer = malloc([plainText length]); inputBuffer = (char *)[plainText bytes]; int i; int j = 0; // encode, this expands every 3 bytes to 4 for(i = 0; i < [plainText length]; i += 3) { encodedText[j++] = alphabet[(inputBuffer[i] & 0xFC) >> 2]; encodedText[j++] = alphabet[((inputBuffer[i] & 0x03) << 4) | ((inputBuffer[i + 1] & 0xF0) >> 4)]; if(i + 1 >= [plainText length]) // padding encodedText[j++] = '='; else encodedText[j++] = alphabet[((inputBuffer[i + 1] & 0x0F) << 2) | ((inputBuffer[i + 2] & 0xC0) >> 6)]; if(i + 2 >= [plainText length]) // padding encodedText[j++] = '='; else encodedText[j++] = alphabet[inputBuffer[i + 2] & 0x3F]; } // terminate the string encodedText[j] = 0; return encodedText;//outputBuffer; } @end when executing the code it stops on the following line with a EXC_BAD_ACCESS ?!?!? NSString *authHeader = [@"Basic " stringByAppendingFormat:@"%@", [NSString stringWithCString:encodedLoginData length:strlen(encodedLoginData)]]; any help would be appreciated as i am a little clueless on this problem, not being very literate with Cocoa, objective c, xcode is only adding fuel to this fire for me.

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  • Rails Authentication

    - by Oluf Nielsen
    Hey, i need some help with rails, again! Last it was about Authlogic.. Well I'm gone a bit backward since.. I mean, Authlogic isn't a Authentcate system i like.. So now i wan't you guys to tell me what you think is the best! I going to use it to a project of mine. Where there has to be a few roles like Admin, User and Guest.. So might you guys can tell me what is good and what is bad..?

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  • IIS Windows Authentication not working in Internet Explorer via host name; works via IP

    - by jkohlhepp
    I'm trying to get a new Windows Server 2003 box working to host an ASP.NET application that uses Windows Authentication. Here's some info: IIS Anonymous Access is diabled IIS Integrated Windows Authentication is enabled I've tried it with and without Digest Authentication and it is the same result Both my machine and the server are in same active directory domain on the same intranet I'm using IE 6 My symptoms: In Firefox, via either IP or host name, a login box pops up, and if I enter my NT credentials, it works. In IE, via the server IP address, it works perfectly with no login box. In IE, via the server host name, it pops up a login box but even if I put in the correct credentials, it just pops up the box again. This is the problem. Why won't windows auth work in IE via host name but it will via IP address? Edit: Here's something else interesting. If I go into my Internet Explorer advanced settings and disable Windows Authentication, it seems to work just fine. And by work I mean that my test .NET app sees my NT ID as the current user.

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  • In Django, why is user.is_authenticated a method and not a member variable like is_staff

    - by luc
    Hello all, I've lost some time with a bug in my app due to user authentication. I think that it's a bit confusing but maybe someone can explain the reason and it will appear to me very logical. The user.is_staff is a member variable while user.is_authenticated is a method. However is_authenticated only returns True or False depending if the class is User or AnonymousUser (see http://docs.djangoproject.com/en/dev/topics/auth/) Is there a reason for that? Why user.is_authenticated is a method? Thanks in advance

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  • Security in API authentication

    - by Carlos
    We are in the process of revamping our server side API, and we need to manage security. Our current model requires that a credentials object (containing user, password, and pin) be included in each method invocation. Our development team, however, has decided that we should have session objects instead (which is fine by me), but the new credentials are just a GUID. This is very different from what I've seen in other APIs in our industry, so I'm a bit concerned about how secure the new model will be. I asked them if they had analyzed both alternatives, and they said they haven't. Does anyone know if there're any clear advantages, disadvantages, risks, etc. of using a set of credentials versus just one element (complex as it may be)? PS: the communication channel would be secure in either case, and it's separate from this particular topic

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  • Custom User Management for Google App Engine Java

    - by Gopi
    I am using GAE Java for a multi-user application. There are multiple users with different roles. Each user can login, do some operations and logout. The business restricts me from using Google User Service and I need to implement my own for authentication and session management. Can anyone please share with me how should I go about implementing my own user management? I have read its very tricky to implement own user management. Any pointers in terms of best approaches/ design / existing frameworks if any ? I could see some similar posts but they are for python.

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  • Roles authentication with Rails 3 and Devise.

    - by Oluf Nielsen
    Hi, first happy new year, may you make the best applications in 2011! So to my question, i have used devise ever since i got over to Rails 3, that was around the first or second beta, and now i also needs some Roles. So i searched the net, and i searched! And what i found was that CanCan should be the best solution. But i'm unsure if CanCan can manage my needs, like i want a forum moderator who can edit/destroy the topic, but the user who created the topic should also be able to edit, so how can i do that? Cheers, Oluf.

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  • Trying and expand the contrib.auth.user model and add a "relatipnships" manage

    - by dotty
    I have the following model setup. from django.db import models from django.contrib.auth.models import User class SomeManager(models.Manager): def friends(self): # return friends bla bla bla class Relationship(models.Model): """(Relationship description)""" from_user = models.ForeignKey(User, related_name='from_user') to_user = models.ForeignKey(User, related_name='to_user') has_requested_friendship = models.BooleanField(default=True) is_friend = models.BooleanField(default=False) objects = SomeManager() relationships = models.ManyToManyField(User, through=Relationship, symmetrical=False) relationships.contribute_to_class(User, 'relationships') Here i take the User object and use contribute_to_class to add 'relationships' to the User object. The relationship show up, but if call User.relationships.friends it should run the friends() method, but its failing. Any ideas how i would do this? Thanks

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  • ldap-authentication without sambaSamAccount on linux smb/cifs server (e.g. samba)

    - by umlaeute
    i'm currently running samba-3.5.6 on a debian/wheezy host to act as the fileserver for our department's w32-clients. authentication is done via OpenLDAP, where each user-dn has an objectclass:sambaSamAccount that holds the smb-credentials and an objectclass:shadowAccount/posixAccount for "ordinary" authentication (e.g. pam, apache,...) now we would like to dump our department's user-db, and instead use authenticate against the user-db of our upstream-organisation. these user-accounts are managed in a novell-edirectory, which i can already use to authenticate using pam (e.g. for ssh-logins; on another host). our upstream organisation provides smb/cifs based access (via some novell service) to some directories, which i can access from my linux client via smbclient. what i currently don't manage to do is to use the upstream-ldap (the eDirectory) to authenticate our institution's samba: i configured my samba-server to auth against the upstream ldap server: passdb backend = ldapsam:ldaps://ldap.example.com but when i try to authenticate a user, i get: $ smbclient -U USER \\\\SMBSERVER\\test Enter USER's password: Domain=[WORKGROUP] OS=[Unix] Server=[Samba 3.6.6] tree connect failed: NT_STATUS_ACCESS_DENIED the logfiles show: [2012/10/02 09:53:47.692987, 0] passdb/secrets.c:350(fetch_ldap_pw) fetch_ldap_pw: neither ldap secret retrieved! [2012/10/02 09:53:47.693131, 0] lib/smbldap.c:1180(smbldap_connect_system) ldap_connect_system: Failed to retrieve password from secrets.tdb i see two problems i'm having: i don't have any administrator password for the upstream ldap (and most likely, they won't give me one). i only want to authenticate my users, write-access is not needed at all. can i go away with that? the upstream ldap does not have any samba-related attributes in the db. i was under the impression, that for samba to authenticate, those attributes are required, as smb/cifs uses some trivial hashing which is not compatible with the usual posixAccount hashes. is there a way for my department's samba server to authenticate against such an ldap server?

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