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  • Oracle Merge vs Select then Insert or Update

    - by DRTauli
    What is faster? the Merge statement MERGE INTO table USING dual ON (rowid = 'some_id') WHEN MATCHED THEN UPDATE SET colname = 'some_val' WHEN NOT MATCHED THEN INSERT (rowid, colname) VALUES ('some_id', 'some_val') or querying a select statement then using an update or insert statement. SELECT * FROM table where rowid = 'some_id' if rowCount == 0 INSERT INTO table (rowid,colname) VALUES ('some_id','some_val') else UPDATE table SET colname='some_val' WHERE rowid='some_id'

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  • ORACLE and TRIGGERS (inserted, updated, deleted)

    - by vandalo
    Hello, I would like to use a trigger on table which will be fired every time a row is inserted, updated, deleted. I wrote something like this: CREATE or REPLACE TRIGGER test001 AFTER INSERT OR DELETE OR UPDATE ON tabletest001 REFERENCING OLD AS old_buffer NEW AS new_buffer FOR EACH ROW WHEN (new_buffer.field1 = 'HBP00') and it works. Since I would like to do the same things if the row is inserted, updated or deleted I would like to know what's happening in the trigger. I think I can manage to find if the row in inserted or updated (I can check the old_buffer with the new_buffer). How can I know if the row has been deleted? Alberto

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  • Oracle database on trigger fail rollback

    - by GigaPr
    Hi I want to create a trigger that execute on update of a table. in particular on update of a table i want to update another table via a trigger but if the trigger fails (REFERENTIAL INTEGRITY-- ENTITY INTEGRITY) i do not want to execute the update anymore. Any suggestion on how to perform this? Is it better to use a trigger or do it anagrammatically via a stored procedure? Thanks

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  • Why do I get Bind Variable "DeliveryDate_Variable" is NOT DECLARED(Completely New TO Oracle)

    - by GigaPr
    Hi, I have the following script in Oacle I do not understand why i get Bind Variable "DeliveryDate_Variable" is NOT DECLARED Everything looks ok to me VARIABLE RollingStockTypeId_Variable NUMBER := 1; VARIABLE DeliveryDate_Variable DATE := (to_date('2010/8/25:12:00:00AM', 'yyyy/mm/dd:hh:mi:ssam')); SELECT DISTINCT rs.Id, rs.SerialNumber, rsc.Name AS Category, (SELECT COUNT(Id) from ROLLINGSTOCKS WHERE ROLLINGSTOCKCATEGORYID = rsc.id) as "Number Owened", (SELECT COUNT(rs.Id) FROM ROLLINGSTOCKS rs WHERE rs.ID NOT IN( select RollingStockId from ROLLINGSTOCK_ORDER WHERE :DeliveryDate_Variable BETWEEN DEPARTUREDATE AND DELIVERYDATE) AND rs.RollingStockCategoryId IN (Select Id from RollingStockCategories Where RollingStockTypeId = :RollingStockTypeId_Variable) AND rs.RollingStockCategoryId = rsc.Id) AS "Number Available" FROM ROLLINGSTOCKS rs JOIN RollingStockCategories rsc ON rsc.Id = rs.RollingStockCategoryId WHERE rs.ID NOT IN( select RollingStockId from ROLLINGSTOCK_ORDER WHERE :DeliveryDate_Variable BETWEEN DEPARTUREDATE AND DELIVERYDATE ) AND rs.RollingStockCategoryId IN ( Select Id from RollingStockCategories Where RollingStockTypeId = :RollingStockTypeId_Variable ) ORDER BY rsc.Name

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  • Oracle - Count distict values of a column

    - by Luciana Borela
    Hi I have this table: Reason|Area_Code|Id x dig 1 x dig 2 y dig 3 h util 4 x dig 5 I'm trying a sql that returns: Reason|Amount of distinct Reason|Area_code x 3 dig y 1 dig h 1 util I will use this result to plot a chart. I don´t have any ideia on how this SQL can be. Could you help me?

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  • SQL Oracle Combining Multiple Results Rows

    - by Stuav
    I have the below query Select case upper(device_model) when 'IPHONE' then 'iOS - iPhone' when 'IPAD' then 'iOS - iPad' when 'IPOD TOUCH' then 'iOS - iPod Touch' Else 'Android' End As Device_Model, count(create_dtime) as Installs_Oct17_Oct30 From Player Where Create_Dtime >= To_Date('2012-Oct-17','yyyy-mon-dd') And Create_Dtime <= To_Date('2012-Oct-30','yyyy-mon-dd') Group By Device_Model Order By Device_Model This spits out multiple rows of results that read "Android"....I would like there to be only 4 results rows, one for each case....so it comes out like this: Device_Model Installs_Oct17_Oct30 Android 987 iOS - iPad 12003 iOS - iPhone 8563 iOS- iPod Touch 3482

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  • Oracle - Count distinct values of a column

    - by Luciana Borela
    Hi I have this table: Reason|Area_Code|Id x dig 1 x dig 2 y dig 3 h util 4 x dig 5 I'm trying for a SQL that returns: Reason|Amount of distinct Reason|Area_code x 3 dig y 1 dig h 1 util I will use this result to plot a chart. I don´t have any idea on how this SQL can be done. Could you help me?

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  • Remove a character from a given position on Oracle

    - by alex
    Is there anyway to remove a character from a given position? Let's say my word is: PANCAKES And I want to remove the 2nd letter (in this case, 'A'), so i want PNCAKES as my return. Translate doesnt work for this. Replace doesnt work for this. Regex is damn complicated... Ideas?

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  • Oracle query with LOWER

    - by Nickolodeon
    Hi. Why this returns 0 rows SELECT GARTUSERID, USER_CODE, UNITID, RANKCODE, RANKID, FIO, LOGINNAME, START_DATE, EXPIR_DATE, NOTE, POSITION, ISCHGPASSWORD, IS_EXPIRDATE, IS_BLOCKED, ROW_ID FROM ACONTROL.GARTUSERS WHERE LOWER(LOGINNAME)=LOWER(:LOGIN) AND ROW_ID=:MD5PSWD and this returns 1 row (as I wanted for the first query)? SELECT GARTUSERID, USER_CODE, UNITID, RANKCODE, RANKID, FIO, LOGINNAME, START_DATE, EXPIR_DATE, NOTE, POSITION, ISCHGPASSWORD, IS_EXPIRDATE, IS_BLOCKED, ROW_ID FROM ACONTROL.GARTUSERS WHERE LOGINNAME=:LOGIN AND ROW_ID=:MD5PSWD

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  • Concatenate and group multiple rows in Oracle

    - by user1693347
    Suppose I have a table like this: NAME GROUP name1 groupA name2 groupB name5 groupC name4 groupA name3 groupC I'd like to have a result like this: GROUP NAMES groupA name1,name4 groupB name2 groupC name3,name5 If there were only one column in the table, I could concatenate the records by doing the following, but with grouping in the context, I really don't have much idea. Any suggestion is welcome, thanks in advance! Concatatenating one column table: SELECT names FROM (SELECT SYS_CONNECT_BY_PATH(names,' ') names, level FROM name_table START WITH names = (SELECT names FROM name_table WHERE rownum = 1) CONNECT BY PRIOR names < names ORDER BY level DESC) WHERE rownum = 1

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  • Basics of Join Factorization

    - by Hong Su
    We continue our series on optimizer transformations with a post that describes the Join Factorization transformation. The Join Factorization transformation was introduced in Oracle 11g Release 2 and applies to UNION ALL queries. Union all queries are commonly used in database applications, especially in data integration applications. In many scenarios the branches in a UNION All query share a common processing, i.e, refer to the same tables. In the current Oracle execution strategy, each branch of a UNION ALL query is evaluated independently, which leads to repetitive processing, including data access and join. The join factorization transformation offers an opportunity to share the common computations across the UNION ALL branches. Currently, join factorization only factorizes common references to base tables only, i.e, not views. Consider a simple example of query Q1. Q1:    select t1.c1, t2.c2    from t1, t2, t3    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2   union all    select t1.c1, t2.c2    from t1, t2, t4    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3; Table t1 appears in both the branches. As does the filter predicates on t1 (t1.c1 > 1) and the join predicates involving t1 (t1.c1 = t2.c1). Nevertheless, without any transformation, the scan (and the filtering) on t1 has to be done twice, once per branch. Such a query may benefit from join factorization which can transform Q1 into Q2 as follows: Q2:    select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                   from t2, t3                    where t2.c2 = t3.c2 and t2.c2 = 2                                  union all                   select t2.c1 item_1, t2.c2 item_2                   from t2, t4                    where t2.c3 = t4.c3) VW_JF_1    where t1.c1 = VW_JF_1.item_1 and t1.c1 > 1; In Q2, t1 is "factorized" and thus the table scan and the filtering on t1 is done only once (it's shared). If t1 is large, then avoiding one extra scan of t1 can lead to a huge performance improvement. Another benefit of join factorization is that it can open up more join orders. Let's look at query Q3. Q3:    select *    from t5, (select t1.c1, t2.c2                  from t1, t2, t3                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2                 union all                  select t1.c1, t2.c2                  from t1, t2, t4                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3) V;   where t5.c1 = V.c1 In Q3, view V is same as Q1. Before join factorization, t1, t2 and t3 must be joined first before they can be joined with t5. But if join factorization factorizes t1 from view V, t1 can then be joined with t5. This opens up new join orders. That being said, join factorization imposes certain join orders. For example, in Q2, t2 and t3 appear in the first branch of the UNION ALL query in view VW_JF_1. T2 must be joined with t3 before it can be joined with t1 which is outside of the VW_JF_1 view. The imposed join order may not necessarily be the best join order. For this reason, join factorization is performed under cost-based transformation framework; this means that we cost the plans with and without join factorization and choose the cheapest plan. Note that if the branches in UNION ALL have DISTINCT clauses, join factorization is not valid. For example, Q4 is NOT semantically equivalent to Q5.   Q4:     select distinct t1.*      from t1, t2      where t1.c1 = t2.c1  union all      select distinct t1.*      from t1, t2      where t1.c1 = t2.c1 Q5:    select distinct t1.*     from t1, (select t2.c1 item_1                   from t2                union all                   select t2.c1 item_1                  from t2) VW_JF_1     where t1.c1 = VW_JF_1.item_1 Q4 might return more rows than Q5. Q5's results are guaranteed to be duplicate free because of the DISTINCT key word at the top level while Q4's results might contain duplicates.   The examples given so far involve inner joins only. Join factorization is also supported in outer join, anti join and semi join. But only the right tables of outer join, anti join and semi joins can be factorized. It is not semantically correct to factorize the left table of outer join, anti join or semi join. For example, Q6 is NOT semantically equivalent to Q7. Q6:     select t1.c1, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t2.c2 (+) = 2  union all    select t1.c1, t2.c2    from t1, t2      where t1.c1 = t2.c1(+) and t2.c2 (+) = 3 Q7:     select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                  from t2                  where t2.c2 = 2                union all                  select t2.c1 item_1, t2.c2 item_2                  from t2                                                                                                    where t2.c2 = 3) VW_JF_1       where t1.c1 = VW_JF_1.item_1(+)                                                                  However, the right side of an outer join can be factorized. For example, join factorization can transform Q8 to Q9 by factorizing t2, which is the right table of an outer join. Q8:    select t1.c2, t2.c2    from t1, t2      where t1.c1 = t2.c1 (+) and t1.c1 = 1 union all    select t1.c2, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t1.c1 = 2 Q9:   select VW_JF_1.item_2, t2.c2   from t2,             (select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 1           union all            select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 2) VW_JF_1   where VW_JF_1.item_1 = t2.c1(+) All of the examples in this blog show factorizing a single table from two branches. This is just for ease of illustration. Join factorization can factorize multiple tables and from more than two UNION ALL branches.  SummaryJoin factorization is a cost-based transformation. It can factorize common computations from branches in a UNION ALL query which can lead to huge performance improvement. 

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  • Hekaton – SQL Server’s in-memory database engine

    - by Christian
    Microsoft have just gone public at the PASS Summit in Seattle about a new SQL Server engine that they’re working on which is optimized for high-memory servers – an in-memory OLTP database engine which is built-in to SQL Server rather than a separate entity.  This means that you can move just the performance critical parts of your database to Hekaton. The new engine really pushes the performance boundaries by eliminating as many instructions as possible: Main memory optimized tables which are decoupled from on-disk structures; Everything is lock and latch free; More work is pushed to compile time so your T-SQL code is compiled natively into low-level code. We’re already working with a customer on an early adoption program so expect to hear from us on what we learn about implementing it!   Christian Bolton - MCA, MCM, MVP Technical Director http://coeo.com - SQL Server Consulting & Managed Services

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  • SQL SERVER – Find Most Active Database in SQL Server – DMV dm_io_virtual_file_stats

    - by pinaldave
    Few days ago, I wrote about SQL SERVER – Find Current Location of Data and Log File of All the Database. There was very interesting conversation in comments by blog readers. Blog reader and SQL Expert Sreedhar has very interesting DMV presented which lists the most active database in SQL Server. For quick reference he has included the size of the disk in KB, MB and GB as well. SELECT DB_NAME(mf.database_id) AS databaseName, name AS File_LogicalName, CASE WHEN type_desc = 'LOG' THEN 'Log File' WHEN type_desc = 'ROWS' THEN 'Data File' ELSE type_desc END AS File_type_desc ,mf.physical_name ,num_of_reads ,num_of_bytes_read ,io_stall_read_ms ,num_of_writes ,num_of_bytes_written ,io_stall_write_ms ,io_stall ,size_on_disk_bytes ,size_on_disk_bytes/ 1024 AS size_on_disk_KB ,size_on_disk_bytes/ 1024 / 1024 AS size_on_disk_MB ,size_on_disk_bytes/ 1024 / 1024 / 1024 AS size_on_disk_GB FROM sys.dm_io_virtual_file_stats(NULL, NULL) AS divfs JOIN sys.master_files AS mf ON mf.database_id = divfs.database_id AND mf.FILE_ID = divfs.FILE_ID ORDER BY num_of_Reads DESC If you like to read and practice with DMVs, I suggest to read the blog of my very good friend Glenn Berry. He is one DMV expert. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Anthony Lye Shows New Pharmaceutical Sales Solution: Turn the Screen Around

    - by charles.knapp
    Tomorrow, March 31, watch as senior vice president of CRM, Anthony Lye, and director of life sciences product strategy, Piers Evans, provide the first public look at Oracle's new Pharmaceutical Sales solution, powered by Oracle CRM On Demand 17 - Life Sciences Edition. You will see a next generation approach to sell more and report less. Register now for this informative global webcast on March 31, 9 AM PDT/4 PM GMT.

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  • SOA &amp; E2.0 Partner Community Forum XIII registration is open

    - by Jürgen Kress
    INVITATION TO THE ORACLE SOA AND E2.0 PARTNER COMMUNITY FORUM Do you want to learn about how to sell the value of Fusion Middleware by combining SOA and E2.0 Solutions? We would like to invite you to become updated and trained at our SOA and E2.0 Partner Community Forum March on 15th and 16th 2011 in Utrecht, The Netherlands. Keynote: Andrew Sutherland and Andrew Gilboy The Oracle SOA and E2.0 Partner Community Forum is a wonderful opportunity to: learn how to sell the value of Fusion Middleware bij combining SOA and E2.0 solutions meet with Oracle SOA and E2.0 Product management exchange knowledge learn from successful SOA, BPM, WebCenter and UCM implementations understand Oracle's Fusion Applications Strategy network within the Oracle SOA Partner Community and the Oracle E2.0 Partner Community During this highly informative event you can learn about partner success stories, participate in an array of break out sessions, exchange information with other partners and enjoy a vibrant panel discussion. Additionally to the SOA and E2.0 Partner Community Forum, you can participate in technical hands on workshops on March 17th and 18th. The goal of these workshops is to prepare you for customer implementations. Places are limited, so don't delay and register now by clicking here. Registration takes a few minutes and is free of charge, except in case of cancellation or no show (cancellation fee € 150). For more information, please visit our website. Best regards Jürgen Kress & Hans Blaas SOA & E2.0 Partner Adoption EMEA Agenda March 15th 2011 Welcome & Introduction Keynote Oracle Middleware Strategy and information on Application Grid and Exalogic Andrew Sutherland, SVP Middleware Sales EMEA, Oracle Keynote Managing Online Customer, Partner and Employee Engagement with Oracle E2.0 Solutions Andrew Gilboy, VP E2.0 Sales EMEA, Oracle Partner SOA/BPM Reference Case Partner WebCenter/UCM Reference Case SOA Suite PS3 David Shaffer, VP Product Management, Oracle Why Specialization is important for Partners Nick Kritikos, Hans Blaas & Jürgen Kress, Alliances & Channels, Oracle   Agenda March 16th 2011 Welcome & Introduction Day II Breakout round 1 - SOA Suite 11g PS3 & OSB - Importance of ADF & JDeveloper - SOA Security IDM - WebCenter PS3, Whats new - E2.0 Sales Plays Breakout round 2 - WebCenter PS3, Whats new - Application Management Enterprise manager and Amberpoint - ADF/WebCenter 11g integration with BPM Suite 11g - Importance of ADF & JDeveloper - JCAPS & OC4J migration opportunities for service business Breakout round 3 - BPM 11g: Whats new - Universal Content management 11g - SOA Security Management - E2.0 Surrounding Products: ATG, Documaker, Primavera - Middleware Industry Value Propositions & Sales Play Fusion Application SOA & E2.0 Summary & Closing For registration and additional information, please visit our website. For more information on SOA Specialization and the SOA Partner Community please feel free to register at www.oracle.com/goto/emea/soa (OPN account required) Blog Twitter LinkedIn Mix Forum Wiki Website Technorati Tags: SOA Community,SOA,SOA Partner Community Forum,SOA Community Forum,OPN,Jürgen Kress

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  • Now It’s Personal (Although It Should Always Be): Campus Recruitment

    - by user769227
    One of the things that I think is important and I want our Campus Recruitment Team here at Oracle to be known for is outstanding customer service. When I say customer service, I mean both students and hiring managers should feel they have had a great experience in our campus hiring process. I think one of the keys to providing outstanding customer service is being able to provide as best as we can a personalised experience where the students who are interviewing with us feel like individuals in our process and not just part a ‘campus drive’. In the campus world this can be challenging at times especially in countries where there is high volume hiring. It can be tricky to create a personal experience when you are hiring for a large number of open graduate roles at one time. I think Campus Recruitment is one of the areas in the recruitment industry that is just waiting for a change. We have all seen the proliferation of Social Media in Recruitment over the past 4-6 years. Every Recruiter has a LinkedIn account or uses Twitter or G+ or FB, etc… and some individuals and organisations do it really well. Even in Campus Hiring there is great Social Media initiatives where companies reach out to students and talk to them. However one thing that has not really changed (and this is a generalisation) is the campus hiring interview process. Do these words inspire enthusiasm to you: “Group Interview, Assessment Centre, On-Campus Drive, Off-Campus Drive, etc...” I don’t know about you but to me these words don’t really sound very personal or individual to students. It almost conjures up images of a factory production line or those long queues you see where the person behind the counter says ‘take a number’. Campus Recruitment has come a long way don’t get me wrong – companies can share data with and talk to students in so many different ways now it really has become a much more transparent and open process. There are some times such as at IIT’s in India where it really is a bit old school in terms of interviewing with students running from company to company interviewing on campus over the course of a few days but I want students talking to Oracle to have as great an experience as possible (the outcome of getting a job or not is separate to the customer experience). As students, what are your thoughts? Do you feel like ‘just a number’ when you are interviewing or is there ways that companies can make the process more personalised. Let us know your thoughts. If you are interviewing with Oracle and have questions, want to talk to us or want to know what it is like working here – email us and we will help where we can. If you can’t reach your local Recruiter in your region email me at [email protected] and I will put you in touch with the appropriate person.

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  • Global User Experience Research: Mobile

    - by ultan o'broin
    A shout out to the usableapps.oracle.com blog article Going Native to Understand Mobile Workers. Oracle is a global company and with all that revenue coming from outside the US, international usability research is essential. So read up about how the Applications User Experience team went about this important user-centered ethnographic research. Personalization is king in the mobile space. Going native is a great way to uncover exactly what users want as they work and use their mobile devices, but you need to do it worldwide!

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  • Disk I/O error copying a Exchange 2007 database

    - by Scottio
    Hi all, A short time ago due to disk space I moved our Exchange database onto an external drive, the drive was new and the database was being backed up daily. I've now discovered the database is corrupt, I've run the Exchange utils to fix the database and this works but it corrupts again as soon as I try to move it. I need to get it off the disk, any suggestions? I'm also trying to restore the last good database but I'd like try to get the database off this disk, any suggestions? PS I know putting the db on an external disk was a bad move, I had no where else to put it :-( Thanks

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  • Anthony Lye: How Pharmaceutical Reps Can Sell More & Report Less

    - by charles.knapp
    On March 31, watch as senior vice president of CRM, Anthony Lye, and director of life sciences product strategy, Piers Evans, provide the first public look at Oracle's new Pharmaceutical Sales solution, powered by Oracle CRM On Demand - Life Sciences Edition. You will see a next generation approach to: • Increase sales effectiveness • Equip reps worldwide • Get the best value Register now for this informative GLOBAL webcast on March 31, 9 AM PDT/4 PM GMT.

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  • LLBLGen Pro feature highlights: grouping model elements

    - by FransBouma
    (This post is part of a series of posts about features of the LLBLGen Pro system) When working with an entity model which has more than a few entities, it's often convenient to be able to group entities together if they belong to a semantic sub-model. For example, if your entity model has several entities which are about 'security', it would be practical to group them together under the 'security' moniker. This way, you could easily find them back, yet they can be left inside the complete entity model altogether so their relationships with entities outside the group are kept. In other situations your domain consists of semi-separate entity models which all target tables/views which are located in the same database. It then might be convenient to have a single project to manage the complete target database, yet have the entity models separate of each other and have them result in separate code bases. LLBLGen Pro can do both for you. This blog post will illustrate both situations. The feature is called group usage and is controllable through the project settings. This setting is supported on all supported O/R mapper frameworks. Situation one: grouping entities in a single model. This situation is common for entity models which are dense, so many relationships exist between all sub-models: you can't split them up easily into separate models (nor do you likely want to), however it's convenient to have them grouped together into groups inside the entity model at the project level. A typical example for this is the AdventureWorks example database for SQL Server. This database, which is a single catalog, has for each sub-group a schema, however most of these schemas are tightly connected with each other: adding all schemas together will give a model with entities which indirectly are related to all other entities. LLBLGen Pro's default setting for group usage is AsVisualGroupingMechanism which is what this situation is all about: we group the elements for visual purposes, it has no real meaning for the model nor the code generated. Let's reverse engineer AdventureWorks to an entity model. By default, LLBLGen Pro uses the target schema an element is in which is being reverse engineered, as the group it will be in. This is convenient if you already have categorized tables/views in schemas, like which is the case in AdventureWorks. Of course this can be switched off, or corrected on the fly. When reverse engineering, we'll walk through a wizard which will guide us with the selection of the elements which relational model data should be retrieved, which we can later on use to reverse engineer to an entity model. The first step after specifying which database server connect to is to select these elements. below we can see the AdventureWorks catalog as well as the different schemas it contains. We'll include all of them. After the wizard completes, we have all relational model data nicely in our catalog data, with schemas. So let's reverse engineer entities from the tables in these schemas. We select in the catalog explorer the schemas 'HumanResources', 'Person', 'Production', 'Purchasing' and 'Sales', then right-click one of them and from the context menu, we select Reverse engineer Tables to Entity Definitions.... This will bring up the dialog below. We check all checkboxes in one go by checking the checkbox at the top to mark them all to be added to the project. As you can see LLBLGen Pro has already filled in the group name based on the schema name, as this is the default and we didn't change the setting. If you want, you can select multiple rows at once and set the group name to something else using the controls on the dialog. We're fine with the group names chosen so we'll simply click Add to Project. This gives the following result:   (I collapsed the other groups to keep the picture small ;)). As you can see, the entities are now grouped. Just to see how dense this model is, I've expanded the relationships of Employee: As you can see, it has relationships with entities from three other groups than HumanResources. It's not doable to cut up this project into sub-models without duplicating the Employee entity in all those groups, so this model is better suited to be used as a single model resulting in a single code base, however it benefits greatly from having its entities grouped into separate groups at the project level, to make work done on the model easier. Now let's look at another situation, namely where we work with a single database while we want to have multiple models and for each model a separate code base. Situation two: grouping entities in separate models within the same project. To get rid of the entities to see the second situation in action, simply undo the reverse engineering action in the project. We still have the AdventureWorks relational model data in the catalog. To switch LLBLGen Pro to see each group in the project as a separate project, open the Project Settings, navigate to General and set Group usage to AsSeparateProjects. In the catalog explorer, select Person and Production, right-click them and select again Reverse engineer Tables to Entities.... Again check the checkbox at the top to mark all entities to be added and click Add to Project. We get two groups, as expected, however this time the groups are seen as separate projects. This means that the validation logic inside LLBLGen Pro will see it as an error if there's e.g. a relationship or an inheritance edge linking two groups together, as that would lead to a cyclic reference in the code bases. To see this variant of the grouping feature, seeing the groups as separate projects, in action, we'll generate code from the project with the two groups we just created: select from the main menu: Project -> Generate Source-code... (or press F7 ;)). In the dialog popping up, select the target .NET framework you want to use, the template preset, fill in a destination folder and click Start Generator (normal). This will start the code generator process. As expected the code generator has simply generated two code bases, one for Person and one for Production: The group name is used inside the namespace for the different elements. This allows you to add both code bases to a single solution and use them together in a different project without problems. Below is a snippet from the code file of a generated entity class. //... using System.Xml.Serialization; using AdventureWorks.Person; using AdventureWorks.Person.HelperClasses; using AdventureWorks.Person.FactoryClasses; using AdventureWorks.Person.RelationClasses; using SD.LLBLGen.Pro.ORMSupportClasses; namespace AdventureWorks.Person.EntityClasses { //... /// <summary>Entity class which represents the entity 'Address'.<br/><br/></summary> [Serializable] public partial class AddressEntity : CommonEntityBase //... The advantage of this is that you can have two code bases and work with them separately, yet have a single target database and maintain everything in a single location. If you decide to move to a single code base, you can do so with a change of one setting. It's also useful if you want to keep the groups as separate models (and code bases) yet want to add relationships to elements from another group using a copy of the entity: you can simply reverse engineer the target table to a new entity into a different group, effectively making a copy of the entity. As there's a single target database, changes made to that database are reflected in both models which makes maintenance easier than when you'd have a separate project for each group, with its own relational model data. Conclusion LLBLGen Pro offers a flexible way to work with entities in sub-models and control how the sub-models end up in the generated code.

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