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• determine from where the function being called in php

  - by Avinash

  I have one function on my code. say its xyz(). This function is being called from different files of my project. Is there any way than I can get from where the function is being called. I want below infromation: File name from where its called. Line number of that file. if call is from inside the function then that function name. Class name Class method name. I know about use of magic constants like FILE and all that. but i don't want to pass all that in function call. like below: xyz('msg',__FILE__,__CLASS__); is there any way that i have to pass just my error related data only. and it will find the above details from where the function is called. let me know if anything is not clear.

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• PHP scope question

  - by Dan

  Hi, I'm trying to look through an array of records (staff members), in this loop, I call a function which returns another array of records (appointments for each staff member). foreach($staffmembers as $staffmember) { $staffmember['appointments'] = get_staffmember_appointments_for_day($staffmember); // print_r($staffmember['appointments'] works fine } This is working OK, however, later on in the script, I need to loop through the records again, this time making use of the appointment arrays, however they are unavailable. foreach ($staffmembers as $staffmember) { //do some other stuff //print_r($staffmember['appointments'] no longer does anything } Normally, I would perform the function from the first loop, within the second, however this loop is already nested within two others, which would cause the same sql query to be run 168 times. Can anyone suggest a workaround? Any advice would be greatly appreciated. Thanks

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• PHP use function return value as array

  - by Richard Knop

  Why is it that this works: $cacheMatchesNotPlayed = $cache->load('externalData'); $cacheMatchesNotPlayed = $cacheMatchesNotPlayed['matchesNotPlayed']; But this doesn't work: $cacheMatchesNotPlayed = $cache->load('externalData')['matchesNotPlayed']; Is there some reason for it? The second bit is easier to write.

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• PHP Upload file enhance security

  - by mandril

  Hey.. my question is how to prevent someone upload a virus or some malicious code with the extension you pretend for example i have a pdf file uploader, anyone can upload a binary with pdf camouflage there are lots of programs to do that.

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• help with converting javascript function to php

  - by Haroldo

  My javascript isnt so great, but i found a brilliant looking function here I'm not sure what to do with this bit: var ranges = [], rstart, rend; full function: function getRanges(array) { var ranges = [], rstart, rend; for (var i = 0; i < array.length; i++) { rstart = array[i]; rend = rstart; while (array[i + 1] - array[i] == 1) { rend = array[i + 1]; // increment the index if the numbers sequential i++; } ranges.push(rstart == rend ? rstart+'' : rstart + '-' + rend); } return ranges; } getRanges([2,3,4,5,10,18,19,20]); // returns ["2-5", "10", "18-20"] getRanges([1,2,3,5,7,9,10,11,12,14 ]); // returns ["1-3", "5", "7", "9-12", "14"] getRanges([1,2,3,4,5,6,7,8,9,10]) // returns ["1-10"]

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• rename uploaded images ascending php

  - by robertdd

  how i rename uploaded images like this: 001.jpg, 002.jpg, 003.jpg? thanks!

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• Boolean expression in PHP?

  - by user198729

  case 1: echo false . 'test'; output: test case 2: echo true . 'test'; output: 1test Why true cast to 1 but false nothing?

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• Prevent PHP sesison hijack, are these good ideas?

  - by matthew Rhodes

  I'm doing a simple shopping cart for a small site. I plan to store cart items as well as logged in user_id in session variables. to make things a little more secure, I thought I'd do this: sha1() the user_id before storing it in the session. Also sha1() and store the http_user_agent var with some salt, and check this along with the user_id. I know there is more one can do, but I thought this at least helps quite a bit right? and is easy for me to implement.

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• Refining Search Results [PHP/MySQL]

  - by Dae

  I'm creating a set of search panes that allow users to tweak their results set after submitting a query. We pull commonly occurring values in certain fields from the results and display them in order of their popularity - you've all seen this sort of thing on eBay. So, if a lot of rows in our results were created in 2009, we'll be able to click "2009" and see only rows created in that year. What in your opinion is the most efficient way of applying these filters? My working solution was to discard entries from the results that didn't match the extra arguments, like: while($row = mysql_fetch_assoc($query)) { foreach($_GET as $key => $val) { if($val !== $row[$key]) { continue 2; } } // Output... } This method should hopefully only query the database once in effect, as adding filters doesn't change the query - MySQL can cache and reuse one data set. On the downside it makes pagination a bit of a headache. The obvious alternative would be to build any additional criteria into the initial query, something like: $sql = "SELECT * FROM tbl MATCH (title, description) AGAINST ('$search_term')"; foreach($_GET as $key => $var) { $sql .= " AND ".$key." = ".$var; } Are there good reasons to do this instead? Or are there better options altogether? Maybe a temporary table? Any thoughts much appreciated!

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• CSV file read fail (PHP )

  - by user1020069

  I am trying to read a csv file (delimited by commas) but unfortunately, it isn't responding as it ought to. I am not so sure what I am doing wrong here, but I'll paste out the contents of the code and the CSV file both : $row = 0; if($handle = fopen("SampleQuizData.csv","r") !== FALSE) { // WORKS UNTIL HERE, SO FILE IS BEING READ while(!feof(handle)){ $line = fgetcsv($handle, 1024, ",") ; echo $line[2]; // DOES NOT WORK } } And the CSV file is (the emails and names have been changed here to protect the identities of the users) parijat,something,[email protected] matthew,durp, [email protected] steve,vai,[email protected] rajni,kanth,[email protected]

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• PDF Viewer for my web - PHP

  - by hjaffer2001

  I am searching for pdf viewer for my web(Open Source). Searched for months and months. Is there any open source to view pdf in my web (without adobe). On the other hand, the documents should be secured. I have done a synopsis with the following urls;(but no use) http://embedit.in/ http://www.vuzit.com/ http://www.ajaxdocumentviewer.com/ http://flexpaper.devaldi.com http://www.icepdf.org/ https://docs.google.com/viewer http://www.snowbound.com/ http://www.mygazines.com http://www.issuu.com/business www.box.net http://viewer.zoho.com/ I want both download and print option for my pdf viewer.

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• PHP sql with foreach loop variable problem

  - by anthony

  This is really getting frustrating. I have a text file that I'm reading for a list of part numbers that goes into an array. I'm using the following foreach function to search a database for matching numbers. $file = file('parts_array.txt'); foreach ($file as $newPart) { $sql = "SELECT products_sku FROM products WHERE products_sku='" . $newPart . "'"; $rs = mysql_query($sql); $num_rows = mysql_num_rows($rs); echo $num_rows; echo "<br />"; } The problem is I'm getting 0 rows returned from mysql_num_rows. I can type the sql statement without the variable and it works perfectly. I can even echo out the sql statement from this script, copy and paste the statement from the browser and it works. But, for some reason I'm not getting any records when I'm using the variable. I've used variables in sql statements tons of times, but this really has me stumped.

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• Creating phone number format standard php

  - by Webnet

  I found this resource when looking to commonly format user's phone numbers.... http://www.eyesis.ca/projects/formatphone.html I was wondering if someone else might have a better solution.

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• curl cookie problem in PHP

  - by safaali

  hi as my client needs, I developed a code to login via cURl. login to www.web1.com and store cookies in cookie.txt go to www.web2.com and browse a page using that cookie.txt no problem with www.web2.com so when i want to do this with www.web3.com, the problem appears. the www.web3.com uses session and cookies itself and I have to gather and use them. it means I should have tow series of cookies, first those from www.web1.com , and second those from www.web3.com , then request the www.web3.com/somepage how I can do that?

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• My IF statement is changing variables in PHP

  - by user1902509

  I am fairly new to the whole programming thing, so forgive me if this is a stupid question. It seems odd that I haven't run into it before. I am trying to make an order form for a cake. You fill out the form, submit it, and it will then display the order in a new window, where you then hit "submit," and upload it to the Database. I have a series of If Statements to check for errors in the form before submitting it. Here is a simplified version of the code. Writing means any writing you want on the cake, Name is your name, and cake is what type of cake you want (the default is "None"). try { $name = trim($params->name); $cake = trim($params->cake); $writing = trim($params->writing); if (strlen($name) < 3){ throw new Exception("Please enter Your name."); } if ($cake = "None") { throw new Exception("Please select a Cake" } if ($cake = "Caramel Apple Pie" or $cake = "Pumpkin Pie" or $cake = "Eggnog Pie" and strlen($writing) > 1) { throw new Exception("We are sorry, but you can't write on any of our specialty pies."); } } catch(Exception $x) { $error = $x->getmessage(); } So what is happening is that when I go and hit submit the first time, the correct cake type comes up, but when you submit it the second time, the error comes up saying that I have "None" selected. All the other values are there and remain the same. I think the problem is that the first "IF" statement (Where it says "If($cake = "None")) is automatically changing $cake to "None" because I have tried commenting just that statement out, and it will then change the cake to be "Caramel Apple Pie," which is in the top of the next IF statement. Anyone know why it is doing this? And how to fix it?

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• Partial PHP code refresh

  - by Tom

  Is it possible to refresh only the part of the page? How? the part: if (checkExpiry($member->expires)==true) { print timeLeft($leftts); } else { print "expired"; } I have table which is showing name, email, time until membership ends and I need to refresh 'time until membership ends' every second.

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• sort associative array PHP

  - by jim smith

  Here's my array, how do I sort it by saleref? Array ( [xml] => Array ( [sale] => Array ( [0] => Array ( [saleref] => 12345 [saleline] => 1 [product] => producta [date] => 19/ 3/10 [manifest] => 0 [qty] => 1 [nextday] => [order_status] => ) [1] => Array ( [saleref] => 12344 [saleline] => 1 [product] => productb [date] => 18/ 3/10 [manifest] => 11892 [qty] => 1 [nextday] => [order_status] => )

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• PHP Path issue running backticks/exec()

  - by Lee

  Hey all I'm trying to run a java jar file from the command line and within the the execution it gives a path. Withing this path their are spaces and this is causing the issue. ie $f = `java -jar /OCR/ocr.jar /Folder/Sub Folder/filetoocr.pdf /ocr/output.txt`; echo "<pre>$output</pre>"; If you can see the space in between the Sub Folder name causes the issue. By command line it would be (which works) java -jar /OCR/ocr.jar /Folder/Sub\ Folder/filetoocr.pdf /ocr/output.txt any suggestions how I can resolve this ?? Hope you can advise

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• PHP Check if <ul> has ended IF it exists

  - by Krewe

  I have my blog generate a preview by taking the first 300 characters and cut off the last whole word. My problem is, when I have a list near the top of the blog it is sometimes included in the preview, however the end list tag usually never is. So how can I check the $preview variable for a starting list tag, and if it is found, check for an ending tag and if it's not there add one. All the code for my preview. $preview = wordwrap($content, 300); $preview = explode("\n", $preview); $preview = $preview[0] . "...";

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• Getting the title of a page in PHP

  - by Francesc

  Hi. When I want to get the title of a remote webiste, I use this script: function get_remotetitle($urlpage) { $file = @fopen(($urlpage),"r"); $text = fread($file,16384); if (preg_match('/<title>(.*?)<\/title>/is',$text,$found)) { $title = $found[1]; } else { $title = 'Title N/A'; } return $title; } But when I parase a webiste title with accents, I get "?". But if I look in PHPMyAdmin, I see the accents correctly. What's happening?

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• Escaping quotes twice in PHP

  - by Genadinik

  Hello, I have a complicated form where I first have to take some _GET parameters and obviously I have to do a mysql_real_escape_string() on them since I look stuff up in the database with them. Them problem for me is after the initial db lookup. When the user submits a form, I send them along as a _POST request and obviously have to do this mysql_real_escape_string call again just in case someone tries to hack my site with a faked form submission. Then the problem I have is the arguments are escaped twice and my queries begin to look strange like this: select field1 , field2 , from my_table where some_id = \'.$lookup_id.\' ... So the system seems to be adding \' and it is messing me up :) Also, in my other forms I have not seen such behavior. Any ideas on what may be causing this? One weird thing is that I tried to send unescaped parameters to the post, and the same problem happens. That is a clue, but not a sufficient one for me. :( Thanks, Alex

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• PHP: imagepng is creating inordinately large files

  - by Rafael

  I'm using a simple thumbnailing script I wrote and it's pretty standard: $imgbuffer = imagecreatetruecolor($thumbwidth, $thumbheight); switch($type) { case 1: $image = imagecreatefromgif($img); break; case 2: $image = imagecreatefromjpeg($img); break; case 3: $image = imagecreatefrompng($img); break; case 6: $image = imagecreatefrombmp($img); break; case 15: $image = imagecreatefromwbmp($img); break; default: return log_error("Tried to create thumbnail from $img: not a valid image"); } imagecopyresampled($imgbuffer, $image, 0, 0, 0, 0, $thumbwidth, $thumbheight, $width, $height); $output = imagepng($imgbuffer, "$album/thumbs/$imgname.png", 9); 9 is the lowest quality setting, yet from a 400 x 600 JPEG image (at 56kB) I'm getting a thumbnail 27 kB in size (140 x 140). Using imagejpeg (quality of 80) instead of imagepng it's about 4kB. How can this be, especially at the lowest quality setting for imagepng? I tried using imagecopy instead of imagecopyresampled, and imagecreate instead of the true color version. Unfortunately the images come out mangled somehow. Is there any way to get PNG thumbnails of a reasonably small file size (about 4 kB at 140 x 140)? Or do I have to use JPEG?

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• PHP: Manage roles with math?

  - by Mike

  I once saw an article about how to use a specific type of numbering system to manage roles. A user would be assigned a specific role number and depending on a calculation, the number could stand for multiple roles. Can anybody share this technique with me or share a link? Thanks!

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• php mysql search

  - by mckenzie

  Hello, My code contain SELECT * FROM newchap WHERE company LIKE '%$company%' OR Category LIKE '%$cat%' It works perfectly however, when the field $company contain empty, it return all result in MYSQL. How to prevent it?

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• Determining which PHP source files are not used.

  - by Unkwntech

  I have a large web app, and I think there are a bunch of old files that are no longer being used, is there an app which can tell me what these files are?

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