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  • num_rows is 0 when it should be >0 for php mysqli code

    - by jpporterVA
    My num_rows is coming back as 0, and I've tried calling it several ways, but I'm stuck. Here is my code: $conn = new mysqli($dbserver, "dbuser", "dbpass", $dbname); // get the data $sql = 'SELECT AT.activityName, AT.createdOn FROM userActivity UA, users U, activityType AT WHERE U.userId = UA.userId and AT.activityType = UA.activityType and U.username = ? order by AT.createdOn'; $stmt = $conn->stmt_init(); $stmt->prepare($sql); $stmt->bind_param('s', $requestedUsername); $stmt->bind_result($activityName, $createdOn); $stmt->execute(); // display the data $numrows = $stmt->num_rows; $result=array("user activity report for: " . $requestedUsername . " with " . $numrows . " rows:"); $result[]="Created On --- Activity Name"; while ($stmt->fetch()) { $msg = " " . $createdOn . " --- " . $activityName . " "; $result[] = $msg; } $stmt->close(); There are multiple rows found, and the fetch loop process them just fine. Any suggestions on what will enable me to get the number of rows returned in the query? Suggestions are much appreciated. Thanks in advance.

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  • Login system and sessions (php)

    - by Jonathan
    I've created a login page and registration page and now I want to use that to password protect pages and have pages which show information specific to that user. Would storing the user ID of the user logged in in a Session variable be a safe and correct way of doing this? How easy would it be for a user to change the session variable to a different ID and access another user's information, and not having to type the users login details in?

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  • Php random row help...

    - by Skillman
    I've created some code that will return a random row, (well, all the rows in a random order) But i'm assuming its VERY uneffiecent and is gonna be a problem in a big database... Anyone know of a better way? Here is my current code: $count3 = 1; $count4 = 1; //Civilian stuff... $query = ("SELECT * FROM `*Table Name*` ORDER BY `Id` ASC"); $result = mysql_query($query); while($row = mysql_fetch_array($result)) { $count = $count + 1; $civilianid = $row['Id']; $arrayofids[$count] = $civilianid; //echo $arrayofids[$count]; } while($alldone != true) { $randomnum = (rand()%$count) + 1; //echo $randomnum . "<br>"; //echo $arrayofids[$randomnum] . "<br>"; $currentuserid = $arrayofids[$randomnum]; $count3 += 1; while($count4 < $count3) { $count4 += 1; $currentarrayid = $listdone[$count4]; //echo "<b>" . $currentarrayid . ":" . $currentuserid . "</b> "; if ($currentarrayid == $currentuserid){ $found = true; //echo " '" .$found. "' "; } } if ($found == true) { //Reset array/variables... $count4 = 1; $found = false; } else { $listdone[$count3] = $currentuserid; //echo "<u>" . $count3 .";". $listdone[$count3] . "</u> "; $query = ("SELECT * FROM `*Tablesname*` WHERE Id = '$currentuserid'"); $result = mysql_query($query); $row = mysql_fetch_array($result); $username = $row['Username']; echo $username . "<br>"; $count4 = 1; $amountdone += 1; if ($amountdone == $count) { //$count $alldone = true; } } } Basically it will loop until its gets an id (randomly) that hasnt been chosen yet. -So the last username could take hours :P Is this 'bad' code? :P :(

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  • PHP: Auto Updating subscriptions?

    - by Duncan Palmer
    Hey guys I am currently making a website and I am hopefully going to start a premium service for it. What I am currently looking into right now is how to make an "auto updating" shop which removes 1 day from how many days left the user has left on their premium status. so for example if the users purchases 30 days of premium, each day that 30 with negate 1 so.. 30, 29, 28, 27.. etc and then if the days gets to 0 in will remove premium status. The only way I can think of keeping track of this right now is by manually monitoring each persons premium status but that wouldnt be very practical. What would the best way for me to do this? (hopefully "automatically") Thanks.

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  • downloading security related problem in php

    - by pareek-rohit
    hi i have to upload a video.but i want to gives permission only authenticate user to download .but i have a problem in that.because if any body type the video detail in browser.(ex http://sitename/folder_name/videoname) then browser download that video.but i don't want this .please suggest me how can i resolve this problem.either i should generate the video name randomly or make a temporary folder in which video reside only for specific time,after this video will be delete. Or if any other ideas you have please let me know Thanks in advance

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  • PHP Datediff days involved

    - by user3549835
    I need to know how many days are involved in a date diff. \For example: <? $start = new DateTime('2014-06-29 14:00:00'); $ende = new DateTime('2014-07-02 05:45:00'); $diff = $start->diff($ende); echo $diff->format('%R'); echo $diff->days; ?> The above code echos +2 My desired result would be 4, because the 29th, 30th, 1st and 2nd of July are "touched". I have no idea to achieve that with the given functions. Coding a day-subtraction seems to bean open door for errors.

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  • Merge array in a different way in PHP

    - by user2984974
    I have these two arrays: $array1 = array( '0' => 'apple', '1' => '' , '2' => 'cucumber' ); $array2 = array( '0' => '', '1' => 'bmw', '2' => 'chrysler' ); if I do this to merge these arrays: $result_arr = array_merge($array1, $array2); print_r( count ( array_filter($result_arr) ) ); the output would be 4. However, I need to get the number 3. So, when there are two things on the same position (same key) count it only once. Is it possible to merge/count elements in arrays like that?

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  • PHP : If...Else...Query

    - by Rachel
    I am executing this statement under while (($data=fgetcsv($this->fin,5000,";"))!==FALSE) Now what I want in else loop is to throw exception only for data value which did not satisfy the if condition. Right now am displaying the complete row as I am not sure how to throw exception only for data which does not satisfy the value. Code if ((strtotime($data[11]) &&strtotime($data[12])&&strtotime($data[16]))!==FALSE && ctype_digit($data[0]) && ctype_alnum($data[1]) && ctype_digit($data[2]) && ctype_alnum($data[3]) && ctype_alnum($data[4]) && ctype_alnum($data[5]) && ctype_alnum($data[6]) && ctype_alnum($data[7]) && ctype_alnum($data[8]) && $this->_is_valid($data[9]) && ctype_digit($data[10]) && ctype_digit($data[13]) && $this->_is_valid($data[14])) { //Some Logic } else { throw new Exception ("Data {$data[0], $data[1], $data[2], $data[3], $data[4], $data[5], $data[6], $data[7], $data[8], $data[9], $data[10], $data[11], $data[12], $data[13], $data[14], $data[16]} is not in valid format"); } Guidance would be highly appreciated as to how can I throw exception only for data which did not satisfy the if value.

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  • PHP/MySQL Interview - How would you have answered?

    - by martincarlin87
    I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

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  • Add a + sign to a +ve number in PHP

    - by user318466
    I need to design a function to return -ve numbers unchanged but should add a + sign at the start of the number if its alreay no present. Example: Input Output ---------------- +1 +1 1 +1 -1 -1 It will get only numeric input. function formatNum($num) { # something here..perhaps a regex? } This function is going to be called several times in echo/print so the quicker the better.

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • PHP Multiple form tokens

    - by Juddling
    I understand the idea of generating a form token and storing it in a session, and also putting it as a hidden input in my forms. But how could I make this work if I have pages with multiple forms, is it still safe to use the same token for each form? And I still feel weary about bots and stuff on my website, can these form tokens really safely replace CAPTCHAs?

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • How to echo an array in PHP?

    - by Kaoukkos
    The following code $results = $facebook->api('/fql', array('q'=>'SELECT page_id, type FROM page_admin WHERE uid = me()')); print_r($results); returned me this array Array ( [data] => Array ( [0] => Array ( [page_id] => 204725966262837 [type] => WEBSITE ) [1] => Array ( [page_id] => 163703342377960 [type] => COMMUNITY ) ) ) My question is how can I just echo the content without this structure? I tried foreach ($results as $result) { echo $result->type; echo "<br>"; }

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  • Using PHP to Seperate Results of a txt file

    - by outbreak
    I am trying to display the last 10 lines of a File and from there take those results and break them down to 10 individual lines.. Currently the code I have found from examples is: $filearray = file("test.txt"); $lastfifteenlines = array_slice($filearray,-10); echo implode($lastfifteenlines, "\n") It display's the 10 items I need however it does not break them down onto individual lines the current results are: 1.0.0.11 1.0.0.12 1.0.0.13 1.0.0.14 1.0.0.15 I need that to instead display as: 1.0.0.11 1.0.0.12 1.0.0.13 1.0.0.14 1.0.0.15 Thanks in Advance for the Asistance!

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  • php string to array and split

    - by RussP
    Hi folks Looking for suggestions as to the best way to do this (I know there are many options): take a variable like this: $args = ('post_type=post&order_by=DESC&limit=10'); the create a function to convert that variable into parts like this: $post_type = post; $order_by = DESC; $limit= 10; Reason is I want a client to be able to use a string like the first to pass variables to a sql query in much the same way (but doesn't have to be exact) as you can do it in WordPress.

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  • php multidimensional array if loop

    - by user1091558
    I have a multidimensional array like this array[value][1][1] Now i would like to implement if loop like this if ($value = array[value][1][1]) { echo "It works"; } Now it works if i assign the values like [1][1],[2][1]. Is it possible to compare the whole array. I mean if the array looks like array[value][1][1],array[value][2][1],..........,array[value][n][1] It works should be echoed. I tried like this. if ($value = array[value][][]) { echo "It works"; } But its not working. Can anyone give me the correct syntax?

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  • php web based portal authentication through IP.

    - by user434885
    i have a web portal running which involves basic data entry. The issue being that this is highly sensitive data. And the credibility of the data entry personel is very low. Therefore i have implemented recording of IP when an entry is made. The Problem i am facing is if this if this person starts forwarding his IP from a proxy server then i am unable to track authenticity of the data. How do i detect if the IP forwarding is happening/ get the real ip address of the person.

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  • Error during data INSERT in php

    - by nectar
    here my code- $sql = "INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES "; for($i=0; $i0) { $sql .= ", "; } $sql .= "('$pin[$i]', '$ownerid', 'Free', '1')"; } $sql .= ";"; echo $sql; mysql_query($sql); if(mysql_affected_rows() 0) { echo "done"; } else { echo "Fail"; } output: ** INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES ('13837927', 'admin', 'Free', '1'), ('59576082', 'admin', 'Free', '1'); Fail why it is not inserting values when $sql query is right?

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  • If statement in MySQL query with PHP

    - by user1104854
    Is it possible to use an if statement in a MySQL query in a similar what I'm showing? I want to grab some information for upcoming events(not ones with previous dates). ini_set('date.timezone', 'America/New_York'); $timestamp = date('m/d/Y'); $sql = "select eventID,eventTitle,eventDate from events where eventLocationID = $locationID ORDER BY eventDate DESC IF(eventDate > $timestamp) "; I really want to avoid doing post-query if statements that will only print if it's after today's date because I run it through a pagination function, and I'd really prefer to avoid tinkering with that.

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  • PHP - displaying 1 random record for each week

    - by mike
    I want to display 1 random record from a database based on the week. I need to determine if it's a new, and if it is a new week, then select the record and display the new record. I'm thinking I can just use a single day of the week to generate the new record, either way will work. I'm really having a hard time conceptualizing how I'll store the record id and not select a new one when someone visits again the same day or refreshes the page. Any ideas? Let me know if I wasn't clear enough.

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