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  • VB.net/Excel- "Backwards" tab index For Each iteration with textboxes.

    - by MSD
    Hi there, I have a form with 3 textboxes and 1 button. textbox1 has tab index 0, and it's text = 1 textbox2 has tab index 1, and it's text = 2 textbox3 has tab index 2, and it's text = 3 I want to iterate thru the textboxes and place their values into cells so that... range("A1").value = txtbox1.text (ie: A1 = "1") range("A2").value = txtbox2.text (ie: A2 = "2") range("A3").value = txtbox3.text (ie: A3 = "3") but what I am getting is... range("A1").value = txtbox1.text (ie: A1 = "3") range("A2").value = txtbox2.text (ie: A2 = "2") range("A3").value = txtbox3.text (ie: A3 = "1") I have tried reversing the tab index for the text boxes, but it doesn't change the "backwards iteration". Is there something I can do to change this so that the loop runs from lowest tab index to highest? Thanks! Public Class Form1 Private Sub Button1_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim objExcel As New Microsoft.Office.Interop.Excel.Application 'Declaring the object. objExcel.Visible = True 'Setting Excel to visible. Dim cntrl As Control With objExcel .Workbooks.Add() 'Adding a workbook. .Range("A1").Select() 'Selecting cell A1. End With 'Form contains 3 text boxes, with one number in each (1,2,3), and one button to fire the code in this sub. For Each cntrl In Me.Controls 'For every control on the form... If TypeOf (cntrl) Is TextBox Then 'If the control is a textbox, then... With objExcel .ActiveCell.Value = cntrl.Text 'place the control's text in the active cell and... .ActiveCell.Offset(1, 0).Activate() 'offset down one row. End With End If 'If the control is not a textbox (if it's the button), do nothing. Next 'Go to the next control. objExcel = Nothing 'Release the object. GC.Collect() 'Clean up. End Sub End Class

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  • Asp.Net Cookie sharing

    - by SH
    This is C#.Net code: How to share Cookie between 2 HttpWebRequest calls? Details: I am posting a form in first request, this form contains some setting variables which are used by the system. lets say there is a input field in the form which sets the size of grid pages to be displayed in other pages. Once i have updated the setings in previous request, i go to send a request to another page which shows off asp.net gridview/grid. The grid might contaian several pages and the page size should be the one which i set in previous request. But when i do this via HttpWebReeust it does not happen. When i do it via browser, loading the setting page in the browser and then going to the grid view page... i see the page size is updated. I want to achieve this via code. Sicne i am scraping this grid. i have to set page size or visit the gird pages one by one via code. Or is it possible to set a cookie on 2nd request which is used to set in first request? It will be great if i go this way. any solution?

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  • saveall not saving associated data

    - by junior29101
    I'm having a problem trying to save (update) some associated data. I've read about a million google returns, but nothing seems to be the solution. I'm at my wit's end and hope some kind soul here can help. I'm using 1.3.0-RC4, my database is in InnoDB. Course has many course_tees CourseTee belongs to course My controller function is pretty simple (I've made it as simple as possible): if(!empty($this-data)) $this-Course-saveAll($this-data); I've tried a lot of different variations of that $this-data['Course'], save($this-data), etc without luck. It saves the Course info, but not the CourseTee stuff. I don't get an error message. Since I don't know how many tees any given course will have, I generate the form inputs dynamically in a loop. $form-input('CourseTee.'.$i.'.teeName', array('error' = false, 'label' = false, 'value'=$data['course_tees'][$i]['teeName'])) The course inputs are simpler: $form-input('Course.hcp'.$j, array('error' = false, 'label' = false, 'class' = 'form_small_w', 'value'=$data['Course']['hcp'.$j])) And this is how my data is formatted: Array ( [Course] = Array ( [id] = 1028476 ... ) [CourseTee] = Array ( [0] = Array ( [key] = 636 [courseid] = 1028476 ... ) [1] = Array ( [key] = 637 [courseid] = 1028476 ... ) ... ) )

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  • Why does this sql statement keep saying it is a boolean and not a paramter? (php/Mysql)

    - by ggfan
    In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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  • <input type="file"> reads only file name not full path

    - by Deep
    I am using Glassfish Server.I have seen the apache file upload to solve it...but i want to implement it in glassfish server. image.html <form action="" method="post" enctype="multipart/form-data"> Select a file: <input type="file" name="first" id="first"/> <br /> <input type="button" name="button" value="upload" id="button" /> <p id="test"></p> <img src='Unknown.png' id="profile_img" height="200px" width="150px"/> </form> test.js $(document).ready(function() { var filepath= $("#first"); $('#button').click(function() { $.ajax({ type: "post", url: "imageservlet", data: "user="+filepath.val(), success: function(msg) { $("#profile_img").attr('src',msg); $("#test").html(msg) .fadeIn("fast"); } }); }); }); imageservlet.java String user=request.getParameter("user"); out.print(user); the output is file name not full path.

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  • Tab Index on div

    - by Mithun P
    Please see the form HTML code below <form method="post" action="register"> <div class="email"> Email <input type="text" tabindex="1" id="email" value="" name="email"> </div> </div> <div class="agreement"> <div tabindex="2" class="terms_radio"> <div onclick="changeTerm(this);" class="radio" id="terms_radio_wrapper" style="background-position: left 0pt;"> <input type="radio" id="terms" value="1" name="terms"><label for="terms">I have read and understood the ZapAV</label> </div> </div> </div> <div class="form_submit"> <input type="button" tabindex="3" value="Cancel" name="cancel"> <input type="submit" tabindex="4" value="Submit" name="submit"> </div> </form> Here I syled teh agreement check box insuch a way that radio input is completly hidden and background image is applied to the wrapper div, and onclick of the wrapper div will toggle the backgroud image as well as the checked status of teh radio input. I need to set the tabindex index on the 'terms_radio' DIV, simply tabindex="2" attribute on div is not working, Is it possible to bring the dotted border on the label for the radio input up on pressing the TAB when the cursor is at email input field?

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  • Filling a region draws it off canvas

    - by Xanyx
    Hi Using the following code in Delphi 2007: procedure TfrmTest.PaintBox1Paint(Sender: TObject); const Rect_Size = 10; begin PaintBox1.Canvas.Brush.Color := clYellow; PaintBox1.Canvas.FillRect(Rect(0, 0, PaintBox1.width, PaintBox1.height)); PaintBox1.Canvas.Brush.Color := clRed; DrawARect(PaintBox1.Canvas, 0, 0, Rect_Size, Rect_Size); end; procedure TfrmTest.DrawARect(ACanvas: TCanvas; iLeft, iTop, iWidth, iHeight: Integer); var rgnMain: HRGN; begin rgnMain := CreateRectRgn(iLeft, iTop, iLeft + iWidth, iTop + iHeight); try SelectClipRgn(ACanvas.handle, rgnMain); ACanvas.FillRect(ACanvas.ClipRect); SelectClipRgn(ACanvas.handle, 0); finally DeleteObject(rgnMain); end; end; I get this: (Yellow area shows boundaries of PaintBox1). HMMM, NOT ALLOWED TO POST IMAGE Please go to: http://www.freeimagehosting.net/uploads/62cf687d29.jpg (Linked image shows a form with a yellow box [PaintBox1] in the center. However my red rectange [rgnMain] has been drawn at pos 0,0 on the form) My expectation was that the red rectangle would be at the top left of the PaintBox1 canvas, not the form's canvas. Why is it not? Can regions only be used with controls that have a Windows handle? Thanks

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  • jQuery dynamic validation

    - by kpomka
    Hi there Im trying to do a few things with jQuery validation plugin and seems stuck on one place. Here is some code: <script type="text/javascript"> $(document).ready(function(){ $('#myform').validate(); $('#email').rules('add', {required: true, messages: {required: 'email is required'}} ); $('#phone').rules('add', {required: true, messages: {required: 'phone is required'}} ); $('#validate').click(function(){ $('#result').text($('#myform').validate().form()); return false; }); }); </script> <form id="myform"> <div>email:<input type="text" id="email" /></div> <div>phone:<input type="text" id="phone" /></div> <div id="result"></div> <input id="valdate" type="image" src="images/submit.png" /> </form> As a result i keep getting a wrong error message. If i click on submit button 'phone is required' is shown near email input and 'email is required' isnt shown at all. Whats wrong with this code ?

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  • Django ModelForm Imagefield Upload

    - by Wei Xu
    I am pretty new to Django and I met a problem in handling image upload using ModelForm. My model is as following: class Project(models.Model): name = models.CharField(max_length=100) description = models.CharField(max_length=2000) startDate = models.DateField(auto_now_add=True) photo = models.ImageField(upload_to="projectimg/", null=True, blank=True) And the modelform is as following: class AddProjectForm(ModelForm): class Meta: model = Project widgets = { 'description': Textarea(attrs={'cols': 80, 'rows': 50}), } fields = ['name', 'description', 'photo'] And the View function is: def addProject(request, template_name): if request.method == 'POST': addprojectform = AddProjectForm(request.POST,request.FILES) print addprojectform if addprojectform.is_valid(): newproject = addprojectform.save(commit=False) print newproject print request.FILES newproject.photo = request.FILES['photo'] newproject.save() print newproject.photo else: addprojectform = AddProjectForm() newProposalNum = projectProposal.objects.filter(solved=False).count() return render(request, template_name, {'addprojectform':addprojectform, 'newProposalNum':newProposalNum}) the template is: <form class="bs-example form-horizontal" method="post" action="">{% csrf_token %} <h2>Project Name</h2><br> {{ addprojectform.name }}<br> <h2>Project Description</h2> {{ addprojectform.description }}<br> <h2>Image Upload</h2><br> {{ addprojectform.photo }}<br> <input type="submit" class="btn btn-success" value="Add Project"> </form> Can anyone help me or could you give an example of image uploading? Thank you!

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  • Very Urgent :How to start a new session if a user click on the new tab in IE or mozilla on websphere

    - by ha22109
    Hi, I have one "user search" portlet on the home page of one application running on websphere portal server.Which display the matching user records as per the search criteria filled in the search form.I have requirement to have a "back to search input" link on the results page which onclick should show the filled form on the input jsp. The issue which i am facing is if i open the application in two diff tab of same IE browser and start giving some search criteria and submit and same time search for some other input from other IE tab (in the same browser)and then go back to previous tab and click on "back to search input" link then instead of showing me the first input it will show me the imput which i entered in the next IE tab. I am setting and getting the bean(form bean) through portlet session.but in the two diff tab of same IE it will be the sae user session (and may be the same portlet session..) Please tell me solution for this. The one thing to be notice here is i can access this "user search" application even without doing login also.so it must be taking the default portlet session in this case. what wil happen once i login and then search,will it going to overwrite the portlet session and http session or howz is that?

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  • How can I spot subtle Lisp syntax mistakes?

    - by Marius Andersen
    I'm a newbie playing around with Lisp (actually, Emacs Lisp). It's a lot of fun, except when I seem to run into the same syntax mistakes again and again. For instance, here's something I've encountered several times. I have some cond form, like (cond ((foo bar) (qux quux)) ((or corge (grault warg)) (fred) (t xyzzy))) and the default clause, which returns xyzzy, is never carried out, because it's actually nested inside the previous clause: (cond ((foo bar) (qux quux)) ((or corge (grault warg)) (fred)) (t xyzzy)) It's difficult for me to see such errors when the difference in indentation is only one space. Does this get easier with time? I also have problems when there's a large distance between the (mal-)indented line and the line it should be indented against. let forms with a lot of complex bindings, for example, or an unless form with a long conditional: (defun test () (unless (foo bar (qux quux) (or corge (grault warg) (fred)))) xyzzy) It turns out xyzzy was never inside the unless form at all: (defun test () (unless (foo bar (qux quux) (or corge (grault warg) (fred))) xyzzy)) I auto-indent habitually and use parenthesis highlighting to avoid counting parentheses. For the most part it works like a breeze, but occasionally, I discover my syntax mistakes only by debugging. What can I do?

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  • ThickBox - update inside without redirect

    - by Alex Maslakov
    ASP.NET MVC and jQuery ThickBox. I show some content in ThickBox. It includes file upload form The view multi-media.apsx (it's strange, the this editor doesn't allow start the line with "<" in the code) form action="/upload/multi-media" method="post" enctype="multipart/form-data" label for="file"File name: input type="file" name="file" id="file" / input type="submit" value="Upload" / <% if (Model.Count > 0) { foreach (FileInfo mediaFile in Model) { <img width="100px" height="100px" src="<%: ResolveUrl("~/audio.png") %>" border="0" alt="<%: mediaFile.Name %>" / //................ After file upload I redirect to /upload/multi-media action and content shows in normal window, not in ThickBox. [ActionName("multi-media"), HttpPost] public ActionResult MultiMedia(HttpPostedFileBase file) { if (file.ContentLength > 0) { file.SaveAs(GenerateNewFileName(fullFileName)); return View("multi-media", model); } } How can I stay into ThickBox after file upload? I need show content in ThickBox all the time, even after the file upload.

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  • jQuery: responding to click event of element added to document after page load

    - by morpheous
    I am writing a page which uses a lot of in situ editing and updating using jQuery for AJAX. I have come accross a problem which can best be summarised by the workflow described below: Clicking on 'element1' on the page results in a jQuery AJAX POST Data is received in json format The data received in json format The received data is used to update an existing element 'results' in the page The received data is actual an HTML form I want jQuery to be responsible for POSTing the form when the form button is clicked The problem arises at point 6 above. I have code in my main page which looks like this: $(document).ready(function(){ $('img#inserted_form_btn').click(function(){ $.ajax({'type: 'POST', 'url': 'www.example.com', function($data){ $(data.id).html($data.frm); }), 'dataType': 'json'} }); }); However, the event is not being triggered. I think this is because when the document is first loaded, the img#inserted_form_btn element does not exist on the page (it is inserted into the DOM as the result of an element being clicked on the page (not shown in the code above - to keep the question short) My question therefore is: how can I get jQuery to be able to respond to events occuring in elements that were added to the DOM AFTER the page has loaded?

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  • How to add or remove a value inside a table cell on selection / de-selection of checkbox of that row, trying to submit the value via Jquery?

    - by Raul
    Here is the table: <%= form_tag '', :id => "costs" do %> <table class="table table-bordered" id="service_cost"> <% @services.each do |service| %> <tbody> <tr> <td><%= check_box_tag :open_service, {}, false, :class => 'checkable' %></td> <td><%= service.phone %></td> <td><%= service.internet %></td> <td></td> <td></td> <td></td> <td></td> <td></td> <td><%= service.house_keeping %> </td> <td>0.0 </td> <td><%= service.laundry %></td> <td><%= text_field_tag "service_cost", service.total, :class => "input-small" %></td> </tr> <% end %> when the form gets submitted, the javascript gets into action: $("#costs").submit(function(){ formData=$("#costs").serializeArray(); processFormData(formData) return false; }); This ensures form submission on selecting the checkbox: $('.checkable').live('change', function() { $(this).parents('form:first').submit(); }); But, what I am looking for is adding or removing a cell value based on checkbox selection/de-selection and submitting it, kindly suggest a way to do it.

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  • One Exchange 2010 issue

    - by user64060
    Hi All, When end user use the outlook anywhere to connect company exchange 2010 server from outside, it will come out the Synchronization Log: **15:18:26 Microsoft Exchange offline address book 15:18:26 Not downloading Offline address book files. A server (URL) could not be located. 15:18:26 0X8004010F** Can help me to resolve this issue. I have tried many methods but can not resolve it! Thank you very much.

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  • C#: Passing data to forms UI using BeginInvoke

    - by Bi
    Hi I am a C# newbie and have a class that needs to pass row information to a grid in the windows form. What is the best way to do it? I have put in some example code for better understanding. Thanks. public class GUIController { private My_Main myWindow; public GUIController( My_Main window ) { myWindow = window; } public void UpdateProducts( List<myProduct> newList ) { object[] row = new object[3]; foreach (myProduct product in newList) { row[0] = product.Name; row[1] = product.Status; row[2] = product.Day; //HOW DO I USE BeginInvoke HERE? } } } And the form class below: public class My_Main : Form { //HOW DO I GO ABOUT USING THIS DELEGATE? public delegate void ProductDelegate( string[] row ); public static My_Main theWindow = null; static void Main( ) { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); theWindow = new My_Main(); Application.Run(theWindow); } private void My_Main_Load( object sender, EventArgs e ) { /// Create GUIController and pass the window object gui = new GUIController( this ); } public void PopulateGrid( string[] row ) { ProductsGrid.Rows.Add(row); ProductsGrid.Update(); } } Thanks!

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  • Codeigniter PHP - loading a view at an anchor point

    - by James Billings
    I have a form at the bottom of a long page, if a user fills out the form but it doesn't validate the page is reloaded in the typical codeigniter fashion: $this->load->view('template',$data); however because the form is way down at the bottom of the page I need the page to load down there like you do with HTML anchors. Does anyone know how to do this in codeigniter? I can't use the codeigniter redirect(); function because it loses the object and the validation errors are gone. Other frameworks I've used like Yii you can call the redirect function like: $this->redirect(); which solves the problem because you keep the object. I've tried using: $this->index() within the controller which works fine as a redirect but the validation errors are in another method which is where the current page is loaded from: $this->item($labs) but when I use this it get stuck in a loop Any ideas? I've seen this question a lot on the net but no clear answers. I'm researching using codeigniter "flash data" but think it's a bit overkill. cheers.

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  • How can I measure the time it takes a file to upload to a PHP script?

    - by Gustav Bertram
    I am trying to measure the time a script takes to upload a file to a PHP script, inside the receiving script. Here's a short example: <form action="#" enctype="multipart/form-data" method="post"> Upload: <input type="file" name="datafile" size="40"> <input type="submit" value="Send"> </form> <?php $upload_time = time() - $_SERVER['REQUEST_TIME']; echo $upload_time . " seconds."; I've submitted 4MB, 25MB, 100MB and 1.4GB files. They took anything from a fraction of a second, to almost a minute, yet the script above always yielded 0 seconds. NOTE: I know that this is a duplicate question, but the accepted answer on the other question did not work for me (at least, initially): Detect how long it takes for a file to upload (PHP) I've tried it using PHP 5.3.3 with Apache 2.2.16 on Ubuntu 10.4. UPDATE: I've discovered that both the Apache header and Ajax solutions work. In fact, the solution on the duplicate question also works. The critical element to making these solutions work is to ensure that the following values in the php.ini are sufficiently high: memory_limit = 1000M upload_max_filesize = 1000M post_max_size = 1000M I am accepting the Apache header solution, since it only uses PHP.

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  • Input html tag not parsing properly in php

    - by Akaash
    I have a database with names that I would like displayed in the form of a table with checkboxes. Everything works until I try to place the html tag into my php code. When I put the input tag in it gives me the error: Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' I can't see where I would put a comma or semi colon. <form> <?php $name = $_POST['name']; $host = "mysql16.000webhost.com"; $user_name = "a1611480_akaash"; $pwd = "****"; $database_name = "a1611480_akaash"; $db = mysql_connect($host, $user_name, $pwd); mysql_select_db($database_name); $result = mysql_query("SELECT name FROM Sort"); $var = array(); while ($row = mysql_fetch_array($result)) { $var[] = $row['name']; } $unique = array_unique($var); foreach ($unique as $value) { echo "<p class = Body_text><label>$value</label> <input type="checkbox" name="name" value="$value" /> </p>\n"; } ?> </form>

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  • Handling large datasets with PHP/Drupal

    - by jo
    Hi all, I have a report page that deals with ~700k records from a database table. I can display this on a webpage using paging to break up the results. However, my export to PDF/CSV functions rely on processing the entire data set at once and I'm hitting my 256MB memory limit at around 250k rows. I don't feel comfortable increasing the memory limit and I haven't got the ability to use MySQL's save into outfile to just serve a pre-generated CSV. However, I can't really see a way of serving up large data sets with Drupal using something like: $form = array(); $table_headers = array(); $table_rows = array(); $data = db_query("a query to get the whole dataset"); while ($row = db_fetch_object($data)) { $table_rows[] = $row->some attribute; } $form['report'] = array('#value' => theme('table', $table_headers, $table_rows); return $form; Is there a way of getting around what is essentially appending to a giant array of arrays? At the moment I don't see how I can offer any meaningful report pages with Drupal due to this. Thanks

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  • Upload to a PHP Server, using Ajax ( XMLHttp POST)

    - by Krishnanunni
    Right now i'm using the below method to Upload a file to PHP <form enctype="multipart/form-data" action="http://sserver.com/fileupload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="30000000" /> <input type="hidden" name="filename" value="file_uploaded.gif" /> <input type="hidden" name="username" value="foobar"/> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> I read the $_POST and $_FILE in php to complete upload like this. $target = $_SERVER['DOCUMENT_ROOT']."/test/upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; echo $target; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } My questions is , can i change the above said code (HTML) to an Ajax XMLHttpRequest without changes in PHP.

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  • Disabling Text field with Javascript when value in drop down box is from mysql

    - by SteveJ313
    Hi I have a simple script in HTML, using a dropdown menu. When the value 1 is selected, the user can write in the text field, if value 2 is selected, it disables the text field. However, i changed the values of the dropdown menu, so that one value was from a mysql table(using PHP) and the other remained 'option value='1''. Yet now neither text field is disabled. Below is the code. `<script type="text/javascript"> function findselected() { if (document.form.selmenu.value == <?php echo $id; ?>) { document.form.txtField.disabled=true; // return false; // not sure this line is needed } else { document.form.txtField.disabled=false; // return false; // not sure this line is needed } } ` And the PHP section if(mysql_num_rows($SQL) == 1) { echo "<select name='selmenu' onChange='findselected()'>"; echo "<label>TCA_Subject</label>"; while ($row=mysql_fetch_array($SQL)) { echo "<option value='$id'>$thing</option>"; echo "<option value='2'>Choice 2</option>"; } } echo "<option value=$userid>'Choice 1'</option>"; ?> <option value='2'>Choice 2</option>"; </select> I have tried taking the second option value out of the loop, putting it into html, editing the variable in the javascript function. There is not a fault with the PHP as it is retrieving the right results and displaying it, yet the text field doesnt become disabled. Does anyone know of a possible solution? Thanks

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