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  • PHP TTF/OTF Reader

    - by Abs
    Hello all, Is anyone aware of a font reader class where I can pass in a font file (ttf or otf) and I can find out the font name, the model, artist etc. The meta data really. Thanks all for any help

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  • Basic PHP logic problem

    - by Joe Smalley
    $this->totplpremium is 2400 $this->minpremiumq is 800 So why would this ever return true?! if ($this->totplpremium < $this->minpremiumq){ The figures are definitely correct and I am definitely using the 'less than' symbol. I can't work it out.

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  • What are the PHP "encryption" functions?

    - by Rob
    Looking for built in encryption functions, not to hide the string from the clever programmer, but instead just to obfuscate it a bit. Looking for functions such as str_rot13 and base64_encode, but I can't seem to locate any. Surely there are more?

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  • cURL command to PHP's libcurl?

    - by Daddy Warbox
    curl -is -F 'J:A-login=BTDT::Action::Login' -F 'J:A:F-address-login=EMAILADDRESS' -F 'J:A:F-password-login=PASSWORD' http://hiveminder.com/splash | grep -o 'JIFTY_SID_HIVEMINDER=[0-9a-f]\+' In continuation off of this question.

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  • PHP: Return string between two characters

    - by Nic Hubbard
    I am wanting to use "keywords" within a large string. These keywords start and end using *my_keyword* and are user defined. How, within a large string, can I search and find what is between the two * characters and return each instance? The reason it might change it, that parts of the keywords can be user defined, such as *page_date_Y* which might show the year in which the page was created. So, again, I just need to do a search and return what is between those * characters. Is this possible, or is there a better way of doing this if I don't know the "keyword" length or what i might be?

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  • php cURL problem

    - by dfilkovi
    I have a problem logging onto a page and then using it with cURL. I login, get PHPSESSID and cookie, and then try to do an action but page returns 'not logged in'. But if I manually log in and copy/paste that PHPSESSID into curl cookies .txt file, everything works fine. So why doesn't it work with PHPSESSID from cURL?

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  • give preference to print array values in php

    - by Bharanikumar
    Hi , I have country table, i fetch all values and moved into array , these value i like to populate into combo/dropdown list , here i want to do some magic things, that is , for my site most of the users coming from uk,us,Australia,Romain and few, So i like to populate by my preference , is there any array will do this magic work, else is it possible mysql query , So final question is , Populate country name into combo based on my prefernce , Thanks

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  • PHP - Search array in array

    - by Anonymous2011
    I have tried googling for the past one hour straight now and tried many ways to search for an array, in an array. My objective is, to find a keyword in the URL, and the keywords are in a txt file. This is what i have so far - but doesn't work. $file = "keywords.txt"; $open = fopen($file,'r'); $data = fread($open,filesize($file)); $data = explode(" ",$data); $url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; $url = parse_url($url); //parse the URL into an array foreach($data as $d) { if(strstr($d,$url)) { echo "yes"; } } This works WITHOUT the text file, or array - but that's not what i want. I'd appreciate it if anyone can assist me.

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  • Delete an (exact) element from an array in php

    - by Holian
    Hi Masters! For example i have an array like this: $test= array("0" => "412", "1" => "2"); I would like to delete the element if its = 2 $delete=2; for($j=0;$j<$dbj;$j++) { if (in_array($delete, $test)) { unset($test[$j]); } } print_r($test); But with this, unfortunatelly the array will empty... How can i delete an exact element from the array? Thank you

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  • PHP: question about passing parameters in URL's

    - by user248959
    Hi, i have this two lines: var_dump($parametros_post_signin); $this->redirect('prueba/aux?email='.$parametros_post_signin['signin']); the first one prints this: array 'signin' => array 'email_address' => string '' (length=0) 'password' => string '' (length=0) the second one takes to another action where i have this code: var_dump($request->getParameter('email')); that prints this: string 'password' (length=8) I expected it to print something like this: string '' (length=0) What should i do to the get value of the 'email_address' field ? Regards Javi

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  • Reformat a date in PHP

    - by Kreker
    I have a date/time string like this: 180510_112440 in this format ddmmyy_hhmmss I need a snippet for having a string formatted like this way: 2010-05-18 11:24:40 Thanks for help.

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  • Super strange PHP error

    - by Industrial
    Hi everyone, When trying memcache:get, I'll get the following error message back: Message: Memcache::get() [memcache.get]: Server localhost (tcp 11211) failed with: Failed reading line from stream (0) I run a Windows 32bit test environment (XP) and here's how my code looks: function getMulti(array $keys) { $items = $this->memcache->get($keys); return $items; } My memcache servers are two local computers in the LAN that my dev. environment is connected to. Sure, I can turn the error logging off or just put an @ before the get function call, but that doesnt solve this issue. What can I do? Thanks a lot!

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  • PHP & MySQL query value question.

    - by space
    How can I use the first query's id value $row['id'] again after I run a second query inside the while loop statement? To show you what I mean here is a sample code below of what I'm trying to do. I hope I explained it right. Here is the code. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id = 4"); if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); } while($row = mysqli_fetch_assoc($dbc)) { echo '<div>User: ' . $row['id'] . '</div>'; echo '<div>Link To User' . $row['id'] . '</div>'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc2 = mysqli_query($mysqli,"SELECT COUNT(cid) as num FROM comments WHERE comments_id = $row[id]"); if (!$dbc2) { // There was an error...do something about it here... print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc2)){ $num = $row['num']; } } echo '<div>User ' . $row['id'] . ' Comments# ' . $num . '</div>'; }

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  • php and SQL_CALC_FOUND_ROWS

    - by Lizard
    I am trying to add the SQL_CALC_FOUND_ROWS into a query (Please note this isn't for pagination) please note I am trying to add this to a cakePHP query the code I currently have is below: return $this->find('all', array( 'conditions' => $conditions, 'fields'=>array('SQL_CALC_FOUND_ROWS','Category.*','COUNT(`Entity`.`id`) as `entity_count`'), 'joins' => array('LEFT JOIN `entities` AS Entity ON `Entity`.`category_id` = `Category`.`id`'), 'group' => '`Category`.`id`', 'order' => $sort, 'limit'=>$params['limit'], 'offset'=>$params['start'], 'contain' => array('Domain' => array('fields' => array('title'))) )); Note the 'fields'=>array('SQL_CALC_FOUND_ROWS',' this obviously doesn't work as It tries to apply the SQL_CALC_FOUND_ROWS to the table e.g. SELECTCategory.SQL_CALC_FOUND_ROWS, Is there anyway of doing this? Any help would be greatly appreciated, thanks.

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • SFTP not supported error with PHP & cURL

    - by Bad Programmer
    I followed the advice from this Stack Overflow question thread, but I keep hitting a snag. I am receiving the following error message: Unsupported protocol: sftp Here is my code: $ch = curl_init(); if(!$ch) { $error = curl_error($ch); die("cURL session could not be initiated. ERROR: $error.""); } $fp = fopen($docname, 'r'); if(!$fp) { $error = curl_error($ch); die("$docname could not be read."); } curl_setopt($ch, CURLOPT_URL, "sftp://$user_name:$user_pass@$server:22/$docname"); curl_setopt($ch, CURLOPT_UPLOAD, 1); curl_setopt($ch, CURLOPT_PROTOCOLS, CURLPROTO_SFTP); curl_setopt($ch, CURLOPT_INFILE, $fp); curl_setopt($ch, CURLOPT_INFILESIZE, filesize($docname)); //this is where I get the failure $exec = curl_exec ($ch); if(!$exec) { $error = curl_error($ch); die("File $docname could not be uploaded. ERROR: $error."); } curl_close ($ch); I used the curl_version() function to see my curl information, and found that sftp doesn't seem to be in the array of supported protocols: [version_number] => 462597 [age] => 2 [features] => 1597 [ssl_version_number] => 0 [version] => 7.15.5 [host] => x86_64-redhat-linux-gnu [ssl_version] => OpenSSL/0.9.8b [libz_version] => 1.2.3 [protocols] => Array ( [0] => tftp [1] => ftp [2] => telnet [3] => dict [4] => ldap [5] => http [6] => file [7] => https [8] => ftps ) Is this a matter of my version of cURL being outdated, or is the SFTP protocol simply not supported at all? Any advice is greatly appreciated.

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  • PHP system() help

    - by sea_1987
    Hello, I have this shell script #!/bin/sh ############################################################# # Example startup script for the SecureTrading Xpay4 client # # Install Xpay4 into /usr/local/xpay4 # # To run this script automatically at startup, place the # # following line at the end of the bootup script. # # eg. for RedHat linux: /etc/rc.d/rc.local # # # # /usr/local/xpay4/xpay4.sh # ############################################################# # Configuration options # Path to java executable JAVAPATH=/System/Library/Frameworks/JavaVM.framework/Versions/1.6.0/Home ########## Do not alter anything below this line ########## echo "Starting Xpay4. Please ensure the Xpay4 client is not already running" $JAVAPATH/java -jar /usr/local/xpay4/Xpay4.jar /usr/local/xpay4/xpay4.ini & And I am trying to run it using, system("/x/sh/shell.sh"); I am doing this when a user navigates to a certain page on my site, however I am getting just a white blank screen is there a way to error check with system(), I am currently using error_reporting(E_ALL | E_STRCIT) and that is applied site wide

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  • Saving PHP Table as CSV

    - by user2403705
    I have been looking everywhere for a way to do this. There are a lot of people that have asked the questions but when I try myself i cant seem to get it to work. Often I get the format correct but it inputs the information into a new page instead of saving it. I did manage to get one to work for google chrome but when i ran it in internet explorer it didnt work. I have a table being created from a MYSQL query and i would like the table to be able to be saved as a CSV. Could anyone help me out?

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  • If statement in MySQL query with PHP

    - by user1104854
    Is it possible to use an if statement in a MySQL query in a similar what I'm showing? I want to grab some information for upcoming events(not ones with previous dates). ini_set('date.timezone', 'America/New_York'); $timestamp = date('m/d/Y'); $sql = "select eventID,eventTitle,eventDate from events where eventLocationID = $locationID ORDER BY eventDate DESC IF(eventDate > $timestamp) "; I really want to avoid doing post-query if statements that will only print if it's after today's date because I run it through a pagination function, and I'd really prefer to avoid tinkering with that.

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  • num_rows is 0 when it should be >0 for php mysqli code

    - by jpporterVA
    My num_rows is coming back as 0, and I've tried calling it several ways, but I'm stuck. Here is my code: $conn = new mysqli($dbserver, "dbuser", "dbpass", $dbname); // get the data $sql = 'SELECT AT.activityName, AT.createdOn FROM userActivity UA, users U, activityType AT WHERE U.userId = UA.userId and AT.activityType = UA.activityType and U.username = ? order by AT.createdOn'; $stmt = $conn->stmt_init(); $stmt->prepare($sql); $stmt->bind_param('s', $requestedUsername); $stmt->bind_result($activityName, $createdOn); $stmt->execute(); // display the data $numrows = $stmt->num_rows; $result=array("user activity report for: " . $requestedUsername . " with " . $numrows . " rows:"); $result[]="Created On --- Activity Name"; while ($stmt->fetch()) { $msg = " " . $createdOn . " --- " . $activityName . " "; $result[] = $msg; } $stmt->close(); There are multiple rows found, and the fetch loop process them just fine. Any suggestions on what will enable me to get the number of rows returned in the query? Suggestions are much appreciated. Thanks in advance.

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  • Php read directory file

    - by kwek-kwek
    I have a script that goes through a directory that has 3 images $imglist=''; $img_folder = "path to my image"; //use the directory class $imgs = dir($img_folder); //read all files from the directory, checks if are images and ads them to a list while ($file = $imgs->read()) { if (eregi("gif", $file) || eregi("jpg", $file) || eregi("png", $file)) $imglist .= "$file "; } closedir($imgs->handle); //put all images into an array $imglist = explode(" ", $imglist); //display image foreach($imglist as $image) { echo '<img src="'.$img_folder.$image.'">'; } but the problem that I am having is it display a 4th img with no image.. yet I only have 3 image in that folder.

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