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  • Do I need to echo html inside included php file

    - by UmeRonaldo
    I just learned how to include php .Here's the index or main php file <!DOCTYPE HTML> <html> <head> </head> <body> <?php include 'header.php'; ?> </body> </html> now in header.php file which way is better to print html Way 1 directly use html without php <header> <h1>Header</h1> </header> Way 2 Using php and echo <?php echo ' <header> <h1>Header</h1> </header> ' ?> Another quick question. Will it work if I use .html for the base or index file ?? sorry for my bad english

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  • jQuery, Ajax & PHP submit multiple forms dilemma

    - by user557563
    This is a very simple form that I have found on the web (as I am a jQuery beginner). <!-- this is my jquery --> <script> $(document).ready(function(){ $("form#submit_wall").submit(function() { var message_wall = $('#message_wall').attr('value'); var id = $('#id').attr('value'); $.ajax({ type: "POST", url: "index.php?leht=pildid", data:"message_wall="+ message_wall + "&id="+ id, cache: false, success: function(){ $("ul#wall").prepend(""+message_wall+"", ""+id+""); $("ul#wall li:first").fadeIn(); alert("Thank you for your comment!"); } }); return false; }); }); </script> <!-- this is my HTML+PHP --> some PHP ... while($row_pilt = mysql_fetch_assoc($select_pilt)){ print <form id="submit_wall"> <label for="message_wall">Share your message on the Wall</label> <input type="text" id="message_wall" /> <input type="hidden" id="id" value="'.(int)$row_pilt['id'].'"> <button type="submit">Post to wall</button> </form> and down below is my PHP script that writes to mySQL. It is a pretty straight forward script. However, it is getting little complicated when I submit it. Since I have more than one form on my page (per WHILE PHP LOOP), thus when I submit - only the FIRST form gets submitted. Furthermore, any other subsequent forms that I submit - data is being copied from the first form. Is there any jQuery functions that clear the data? - or is there a better solution. Thanks, Nick

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  • What is the last entry in an unfilled array (C++)?

    - by jwaffe
    I put C++ because I'm just starting in C# and I'm not sure if there's a difference. if you declare an array char arr[10] and fill in values for arr[0] through arr[8], what value will be put in arr[9]? a space ' '? An endline '\n'? '\0'? Or is it nothing at all? I'm asking this because I've always used tactics like this char word[20]; for(count = 0 ; count < 20 ; count++) { cout << word[count]; } to print the entire contents of an array, and I was wondering if I could simplify it (e.g., if the last entry was '\0') by using something like this char word[20]; while(word[count] != '\0') { cout << word[count]; } that way, I wouldn't have to remember how many pieces of data were entered into an array if all the spaces weren't filled up. If you know an even faster way, let me know. I tend to make a bunch of mistakes on arrays.

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  • Is there a better way to detab (expand tabs) using Perl?

    - by Uri
    I wanted to detab my source files. (Please, no flame about WHY I wanted to detab my sources. That's not the point :-) I couldn't find a utility to do that. Eclipse didn't do it for me, so I implemented my own. I couldn't fit it into a one liner (-e) program. I came with the following, which did the job just fine. while( <> ) { while( /\t/ ) { s/^(([^\t]{4})*)\t/$1 /; s/^((([^\t]{4})*)[^\t]{1})\t/$1 /; s/^((([^\t]{4})*)[^\t]{2})\t/$1 /; s/^((([^\t]{4})*)[^\t]{3})\t/$1 /; } print; } However, it makes me wonder if Perl - the champion language of processing text - is the right tool. The code doesn't seem very elegant. If I had to detab source that assume tab=8 spaces, the code would look even worse. Specifically because I can think of a deterministic state machine with only 4 states to do the job. I have a feeling that a more elegant solution exists. Am I missing a Perl idiom? In the spirit of TIMTOWTDI I'm curious about the other ways to do it. u.

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  • CodeGolf: Find the Unique Paths

    - by st0le
    Here's a pretty simple idea, in this pastebin I've posted some pair of numbers. These represent Nodes of a directed graph. The input to stdin will be of the form, (they'll be numbers, i'll be using an example here) c d q r a b b c d e p q so x y means x is connected to y (not viceversa) There are 2 paths in that example. a->b->c->d->e and p->q->r. You need to print all the unique paths from that graph The output should be of the format a->b->c->d->e p->q->r Notes You can assume the numbers are chosen such that one path doesn't intersect the other (one node belongs to one path) The pairs are in random order. They are more than 1 paths, they can be of different lengths. All numbers are less than 1000. If you need more details, please leave a comment. I'll amend as required. Shameless-Plug For those who enjoy Codegolf, please Commit at Area51 for its very own site:) (for those who don't enjoy it, please support it as well, so we'll stay out of your way...)

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  • FileInput Help/Advice

    - by user559142
    I have a fileinput class. It has a string parameter in the constructor to load the filename supplied. However it just exits if the file doesn't exist. I would like it to output a message if the file doesn't exist - but not sure how.... Here is the class: public class FileInput extends Input { /** * Construct <code>FileInput</code> object given a file name. */ public FileInput(final String fileName) { try { scanner = new Scanner(new FileInputStream(fileName)); } catch (FileNotFoundException e) { System.err.println("File " + fileName + " could not be found."); System.exit(1); } } /** * Construct <code>FileInput</code> object given a file name. */ public FileInput(final FileInputStream fileStream) { super(fileStream); } } And its implementation: private void loadFamilyTree() { out.print("Enter file name: "); String fileName = in.nextLine(); FileInput input = new FileInput(fileName); family.load(input); input.close(); }

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  • Android SDK and Java

    - by Soonts
    Android SDK Manager complains "WARNING: Java not found in your path". Instead of using the information from Windows registry, the software tries to search Java in the default installation folders, and fails (I don't install software in program files because I don't like space characters in my paths). Of course I know how to modify the %PATH% environment variable. The question is — which Java does it need? After installing the latest JDK, I’ve got 4 distinct versions of java.exe file, in the following 4 folders: system32, jre6\bin, jdk1.6.0_26\bin, and jdk1.6.0_26\jre\bin. Size ranges from 145184 to 171808. All of them print version “1.6.0_26” when launched with the “-version” argument. The one in system32 has .exe version “6.0.250.6”, the rest of them is “6.0.260.3”. All 4 files are different (I’ve calculated the MD5 checksums). Q1. Which folder should I add to %PATH% to make the Android SDK happy? Q2. Why does Oracle build that many variants of java.exe of the same version for the same platform? Thanks in advance! P.S. I'm using Windows 7 SP1 x64 home premium, and downloaded the 64-bit version of JDK, jdk-6u26-windows-x64.exe.

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  • Very weird jquery/json problem...

    - by Scarface
    Hey guys I have finally located the cause of this problem...I just have no idea how to fix it and why it is happening. I have a jquery getjson function and it returns 0 results every 2-5 clicks on new topics or refreshes. For some reason if I change my query to sort results by ASC it always returns results and much quicker, but this poses a problem since I need results by DESC. If anyone has any ideas, I would greatly appreciate it because I am dumbfounded at this point. Here is my query but I need it by DESC SELECT time, user, message FROM comments WHERE topic_id='$topic_id' ORDER BY time ASC LIMIT 10 $.getJSON(files+"comments.php?action=view&load=initial&topic_id="+topic_id+"&t=" + (new Date()), function(json) { if(json.length) { for(i=0; i < json.length; i++) { $('#comment-list').prepend(prepare(json[i])); $('#list-' + count).fadeIn(1500); } } }); I return results like so while($row = mysql_fetch_array($res)){ $data[] = $row; } $out = json_encode($data); print $out;

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  • What's up with this reversing bit order function?

    - by MattyW
    I'm rather ashamed to admit that I don't know as much about bits and bit manipulation as I probably should. I tried to fix that this weekend by writing some 'reverse the order of bits' and 'count the ON bits' functions. I took an example from here but when I implemented it as below, I found I had to be looping while < 29. If I loop while < 32 (as in the example) Then when I try to print the integer (using a printBits function i've written) I seem to be missing the first 3 bits. This makes no sense to me, can someone help me out? int reverse(int n) { int r = 0; int i = 0; for(i = 0; i < 29; i++) { r = (r << 1) + (n & 1); n >>=1; } return r; }

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  • How is this function being made use of?

    - by Kay
    Hello all, I am just studying a few classes given to me by my lecturer and I can't understand how the function heapRebuild is being made used of! It doesn't change any global variables and it doesn't print out anything ad it doesn't return anything - so should this even work? It shouldn't, should it? If you were told to make use of heapRebuild to make a new function removeMac would you edit heapRebuild? public class MaxHeap<T extends Comparable<T>> implements Heap<T>{ private T[] heap; private int lastIndex; public T removeMax(){ T rootItem = heap[0]; heap[0] = heap[lastIndex-1]; lastIndex--; heapRebuild(heap, 0, lastIndex); return rootItem; } protected void heapRebuild(T[ ] items, int root, int size){ int child = 2*root+1; if( child < size){ int rightChild = child+1; if ((rightChild < size) && (items[rightChild].compareTo(items[child]) > 0)){ child = rightChild; } if (items[root].compareTo(items[child]) < 0){ T temp = items[root]; items[root] = items[child]; items[child] = temp; heapRebuild(items, child, size);} } } }

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  • This program isn't asking for the predetermined 5 numbers from the array?

    - by user1801781
    Okay, so this question is difficult to state. I'm a beginner at C++, and I rarely run into problems with these simple assignments, but something is majorly wrong here and I cannot identify it. I've been trying for hours. This program is supposed to read 5 numbers from an array that the user enters, and then print the largest one. (I know it's easier to just write a for-loop, but our professor wanted us to call a function). The only problem is that instead of asking for 5 numbers, it asks for 2. It works other than that, I JUST NEED IT TO ASK FOR 5 NUMBERS. haha. Your input would be greatly appreciated. I aspire to be a programmer one day, so don't be afraid to go harsh on me. #include <iostream> using namespace std; int largest_number(int score[], int max) { for (int i=1; i<5; i++) { cin >> score[i]; if(score[i] > max) max=score[i]; return (max); } } int main () { int score[5], max, z; cout << "Enter 5 numbers: " <<endl; cin >> score[0]; max = score[0]; z = largest_number(score, max); cout << "The largest number is: " << z <<endl; system("pause"); return 0; }

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  • Perl Linux::Inotify2 - can't respond to events anymore

    - by alcy
    I am getting some really weird behavior when using Linux::Inotify2 module for watching a directory for any newly created files. I had made a test script to see how it worked, and once that was done, I went on to incorporating its usage in the other scripts, in which it didn't work. Then, when I tried my earlier test script again to find some information, strangely that stopped working as well. It hasn't worked since then. There were no package/distro upgrades during that time. The problem is that it has stopped responding to events. Here's the test script: #!/usr/bin/perl use strict; use warnings; use Linux::Inotify2; my $inotify = new Linux::Inotify2 or die "unable to create new inotify object: $!"; my $dir = "/my/dir"; $inotify->watch($dir, IN_CREATE, sub { my $e = shift; print $e->fullname; }) or die " Can't watch $!"; 1 while $inotify->poll; A strace on the running script kills the script. Otherwise when strace is used when starting the script, then it does seem to read the new events, but there's no response to those events. Any suggestions for debugging this further ?

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  • How can I write output to a new external file with Perl?

    - by Structure
    Maybe I am searching with the wrong keywords or this is a very basic question but I cannot find the answer to my question. I am having trouble writing the result of my whois command to a new external file. My code is below. It takes $readfilename, which is a file name which has a list of IPs, and $writefilename, which is the destination file for output. Both are user-specified. For my tests, $readfilename contains three IP addresses on three separate lines so there should be three separate whois results in the user specified output file. if ($readfilename) { open (my $inputfile, "<", $readfilename) || die "\n Cannot open the specified file. Please double check your file name and path.\n\n"; open (my $outputfile, ">", $writefilename) || die "\n Could not create write file.\n\n"; while (<$inputfile>) { my $iplookupresult = `whois $_`; print $outputfile $iplookupresult; } close $outputfile; close $inputfile; } I can execute this script and end up with a new external file, but over half of the file has binary garbage data (running on CentOS) and only one (or a portion of one) of the whois lookups is readable. I have no idea how half of my file is ending up binary... but my approach must be incorrect. Is there a better way to achieve the same result?

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  • Stream buffering issue

    - by Kolyunya
    The mod_rewrite documentation states that it is a strict requirement to disable in(out)put buffering in a rewrite program. Keeping that in mind I've written a simple program (I do know that it lacks the EOF check but this is not an issue and it saves one condition check per loop): #include <stdio.h> #include <stdlib.h> int main ( void ) { setvbuf(stdin,NULL,_IOLBF,4200); setvbuf(stdout,NULL,_IOLBF,4200); int character; while ( 42 ) { character = getchar(); if ( character == '-' ) { character = '_'; } putchar(character); } return 42 - 42; } After making some measurements I was shocked - it was over 9,000 times slower than the demo Perl script provided by the documentation: #!/usr/bin/perl $| = 1; # Turn off I/O buffering while (<STDIN>) { s/-/_/g; # Replace dashes with underscores print $_; } Now I have two related questions: Question 1. I believe that the streams may be line buffered since Apache sends a new line after each path. Am I correct? Switching my program to setvbuf(stdin,NULL,_IOLBF,4200); setvbuf(stdout,NULL,_IOLBF,4200); makes it twice as fast as Perl one. This should not hit Apache's performance, should it? Question 2. How can one write a program in C which will use unbuffered streams (like Perl one) and will perform as fast as Perl one?

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  • problem using fprintf

    - by shiran bar
    I'm trying to print to a text file numerous variables yet it doesn't work. I checked and verified that i write it in the correct syntax. I also checked the return value and it's positive therefore i know it did write to the file, however when i open the file it's empty. I would be happy for some help. This is the code: I initiate DynsaleDayPtr in the main: FILE* DynsaleDayPtr = CreateTextFiles("sale_day.txt"); Create function: FILE* CreateTextFiles (char* fileName) { FILE* saleFilePtr=NULL; if((saleFilePtr=fopen(fileName,"a+"))==NULL) printf("File couldn't be opened\n"); return saleFilePtr; } The call to the function TextAddSale is done from a function that is called in the main: TextAddSale(DynSaleDayPtr,dynNumOfRecords); Bool TextAddSale (FILE* DynsaleDayPtr, int* dynNumOfRecords) { char id[6]; char name [50]; char priceChar[20]; char* tmp = NULL; int price=-1; DynamicRecord * newRec=NULL; scanf("%s%s%s",id,name,priceChar); newRec = (DynamicRecord *)malloc(sizeof(DynamicRecord)); if (newRec == NULL) return False; tmp = (char*)malloc(strlen(name)+1); if (tmp == NULL) { free (newRec); return False; } strcpy(tmp,name); newRec->productName = tmp; strcpy(newRec->productId, id); newRec->productPrice=atoi (priceChar); if (fprintf(DynsaleDayPtr,"%d %s %s %d", strlen(newRec->productName), newRec->productId, newRec->productName, newRec->productPrice)>0) { *dynNumOfRecords=(*dynNumOfRecords)+1; return True; } } thanks!

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  • Python - creating a list with 2 characteristics bug

    - by user2733911
    The goal is to create a list of 99 elements. All elements must be 1s or 0s. The first element must be a 1. There must be 7 1s in total. import random import math import time # constants determined through testing generation_constant = 0.96 def generate_candidate(): coin_vector = [] coin_vector.append(1) for i in range(0, 99): random_value = random.random() if (random_value > generation_constant): coin_vector.append(1) else: coin_vector.append(0) return coin_vector def validate_candidate(vector): vector_sum = sum(vector) sum_test = False if (vector_sum == 7): sum_test = True first_slot = vector[0] first_test = False if (first_slot == 1): first_test = True return (sum_test and first_test) vector1 = generate_candidate() while (validate_candidate(vector1) == False): vector1 = generate_candidate() print vector1, sum(vector1), validate_candidate(vector1) Most of the time, the output is correct, saying something like [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0] 7 True but sometimes, the output is: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 2 False What exactly am I doing wrong?

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  • Need Multiple Sudoku Solutions

    - by user1567909
    I'm trying to output multiple sudoku solutions in my program. For example, when You enter this as input: 8..6..9.5.............2.31...7318.6.24.....73...........279.1..5...8..36..3...... .'s denote blank spaces. Numbers represent already-filled spaces. The output should be a sudoku solution like so: 814637925325149687796825314957318462241956873638274591462793158579481236183562749 However, I want to output multiple solutions. This would be all the solutions that should be printed: 814637925325149687796825314957318462241956873638274591462793158579481236183562749 814637925325941687796825314957318462241569873638472591462793158579184236183256749 834671925125839647796425318957318462241956873368247591682793154579184236413562789 834671925125839647796524318957318462241956873368247591682793154519482736473165289 834671925125839647796524318957318462241965873368247591682793154519482736473156289 But my program only prints out one solution. Below is my recursive solution to solving a sudoku solution bool sodoku::testTheNumber(sodoku *arr[9][9], int row, int column) { if(column == 9) { column = 0; row++; if(row == 9) return true; } if(arr[row][column]->number != 0) { return testTheNumber(arr, row, column+1); } for(int k = 1; k < 10; k++) { if(k == 10) { arr[row][column]->number = 0; return false; } if(rowIsValid(arr, k, row) && columnIsValid(arr, k, column) && boxIsValid(arr, k, row, column)) { arr[row][column]->number = k; if(testTheNumber(arr, row, column+1)==true) { return true; } arr[row][column]->number = 0; } } return false; } Could anyone help me come up with a way to print out multiple solutions? Thanks.

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  • Template specialization to use default type if class member typedef does not exist

    - by Frank
    Hi Everyone, I'm trying to write code that uses a member typedef of a template argument, but want to supply a default type if the template argument does not have that typedef. A simplified example I've tried is this: struct DefaultType { DefaultType() { printf("Default "); } }; struct NonDefaultType { NonDefaultType() { printf("NonDefault "); } }; struct A {}; struct B { typedef NonDefaultType Type; }; template<typename T, typename Enable = void> struct Get_Type { typedef DefaultType Type; }; template<typename T> struct Get_Type< T, typename T::Type > { typedef typename T::Type Type; }; int main() { Get_Type::Type test1; Get_Type::Type test2; } I would expect this to print "Default NonDefault", but instead it prints "Default Default". My expectation is that the second line in main() should match the specialized version of Get_Type, because B::Type exists. However, this does not happen. Can anyone explain what's going on here and how to fix it, or another way to accomplish the same goal? Thank you.

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  • Applying jQuery attr value to new DOM elements (result of AJAX query)

    - by Daniel
    Hello everyone, I have a div on a page whose contents is replaced by an AJAX request when the user selects an option from a select list. When the page loads, I issue a command to disable the autocomplete feature for all of the pages text input elements: //Stop that pesky browser autocomplete $('input[type=text]').attr("autocomplete", "off"); However, when new elements appear in the div after an AJAX call, this line of code does not reference them because they were not part of the original DOM (when the page was loaded). I have tried appending the autocomplete line to the end of the post function: //AJAX Post request that changes the fields in the address div for each different country $("div#address select#country").live("change", function() { $.post("<?php print($_SERVER['PHP_SELF']); ?>", { country: $(this).val() }, function(data) { $('div#address').html(data); }, "text"); $('div#address input[type=text]').attr("autocomplete", "off"); }); But for some reason it does not work and the autocomplete pops up when text is entered into any of the address fields. As far as I am aware I cannot use .live() to select the input elements because changing an attribute is not classed as an event. So can anyone advise me how to modify the attributes of a newly created DOM element?

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  • Doubt in switch case

    - by user302593
    Hi.. When i executes the following program it get the user input for account details and then print it correctly...But it cannot read the opt value(y/n)..it automatically calls again..i want to exit the program when i press n value... please help to solve this problem.. char opt; do { //Getting user input printf("\n Enter the Account Number:\n "); scanf("%d",&gAccNo_i); printf("\n Enter the Account Holder's Name:\n "); scanf("%s",gCustName_c); printf("\n Enter the Balance Amount:\n "); scanf("%f",&gBlncAmt_f); //Printing the inputted data. printf("\n Account Number : %d",gAccNo_i); printf("\n Customer Name : %s",gCustName_c); printf("\n Balance Amount : %f",gBlncAmt_f); printf("\n Do u want to wish to continue?(y/n)"); scanf("%c",&opt); }while(opt!='n');

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  • Compression Program in C

    - by Delandilon
    I want to compress a series of characters. For example if i type Input : FFFFFBBBBBBBCCBBBAABBGGGGGSSS (27 x 8 bits = 216 bits) Output: F5B7C2B3A2B2G5S3 (14 x 8 bits = 112bits) So far this is what i have, i can count the number of Characters in the Array. But the most important task is to count them in the same sequence. I can't seem to figure that out :( Ive stared doing C just a few weeks back, i have knowledge on Array, pointers, ASCII value but in any case can't seem to count these characters in a sequence. Ive try a bit of everything. This approach is no good but it the closest i came to it. #include <stdio.h> #include <conio.h> int main() { int charcnt=0,dotcnt=0,commacnt=0,blankcnt=0,i, countA, countB; char str[125]; printf("*****String Manipulations*****\n\n"); printf("Enter a string\n\n"); scanf("%[^'\n']s",str); printf("\n\nEntered String is \" %s \" \n",str); for(i=0;str[i]!='\0';i++) { // COUNTING EXCEPTION CHARS if(str[i]==' ') blankcnt++; if(str[i]=='.') dotcnt++; if(str[i]==',') commacnt++; if (str[i]=='A' || str[i]=='a') countA++; if (str[i]=='B' || str[i]=='b') countA++; } //PRINT RESULT OF COUNT charcnt=i; printf("\n\nTotal Characters : %d",charcnt); printf("\nTotal Blanks : %d",blankcnt); printf("\nTotal Full stops : %d",dotcnt); printf("\nTotal Commas : %d\n\n",commacnt); printf("A%d\n", countA); }

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  • PHP PDO changes remote host to local hostname

    - by Wade Urry
    I'm trying to connect to a remote mysql server using PDO. However, regardless of the hostname or ip address i supply in the dsn, when the script is run it always reverts the address to the hostname of the local server where the webserver is running. Google suggests this could be something to do with SELinux and apaches ability to connect to remote databases, however i have SELinux disabled. Distro: Ubuntu 11.04 x64 Apache version: 2.2.17 PHP Version: PHP 5.3.5-1ubuntu7.11 with Suhosin-Patch (cli) Edit: Added code as requested. Though i dont believe this is an issue with my coding as it works fine on the local server, but doesnt allow remote connection. public function db_connect($driver, $dbhost, $dbname, $user, $pass) { $dsn = $driver . ':host=' . $dbhost . ';dbname=' . $dbname; try { $this->DB = new PDO($dsn, $user, $pass); } catch (PDOException $err) { print 'Database Connection Failed: ' . $err->getMessage(); die(); } } $remote_db = new DB('mysql', 'remote_server.domain.tld', 'database_name', 'user_name', 'password'); This is the error message i am receiving. Database Connection Failed: SQLSTATE[28000] [1045] Access denied for user 'user_name'@'local_server.domain.tld' (using password: YES)

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  • problem by displaying images stored in a MySQL database?

    - by user1400
    i have images in my blob field in database i use blow colde for displaying image but it does not show any pic , someone could tell me where is my wrong? this is my model: public function getListUser() { $select = $this->select() ->order('lastname DESC'); $adapter = new Zend_Paginator_Adapter_DbTableSelect ($select); return $adapter; } this my controller: $userModel = new Admin_Model_User(); $adapter = $userModel->getListUser(); $paginator = new Zend_Paginator ($adapter); $paginator->setItemCountPerPage(1); $page = $this->_request->getParam('page', 1); $paginator->setCurrentPageNumber($page); $this->view->paginator = $paginator; this my view code: <td style="width: 20%;"> <?php echo $this->lastname ?> </td> <td style="width: 20%;"><?php header("Content-type: image/gif"); print $this->image; ?></td>

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  • Identify words with ascending characters from text file

    - by user2914000
    I am having a fair amount of trouble trying to write a program that counts the amount of ascending words (words in which each character is larger than the previous character) in a text file. I have tried a few different methods to solve this but cannot seem to get it working. If anyone could help me revise the code to work properly it would be appreciated. The code will print about 5 of the words from the list of nearly 20000, but none considered are ascending (the file does have many ascending words) and it sometimes prints the same word twice. I am printing theWord to the console simply to see if the code works. import java.util.Scanner; import java.io.*; public class { public static void main (String [] args) throws FileNotFoundException{ String theWord; Scanner inputFile = new Scanner(new File("file.txt")); boolean ascending = true; int i = 1; while(inputFile.hasNextLine()){ theWord = inputFile.nextLine(); if(theWord.length() >= 2){ while(i < theWord.length() - 1){ if(theWord.charAt(i) <= theWord.charAt(i + 1)){ ascending = true; System.out.println("+ " + theWord); totalNum = totalNum + 1; } else{ ascending = false; System.out.println("= " + theWord); } i++; } } }

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  • java:25: '.class' expected error while merging arrays

    - by user3677712
    Here is my code, it is asking me to call a class, I am confused as to do this. Noob to java, so any help would be greatly appreciated. line 25 is where the error occurs. This program is merging two arrays together into a new array. public class Merge{ public static void main(String[] args){ int[] a = {1, 1, 4, 5, 7}; int[] b = {2, 4, 6, 8}; int[] mergedArray = merge(a, b); for(int i = 0; i < mergedArray.length; i++){ System.out.print(mergedArray[i] + " "); } } public static int[] merge(int[] a, int[] b){ // WRITE CODE HERE int[] mergedArray = new int[a.length[] + b.length[]]; int i = 0, j = 0, k = 0; while (i < a.length() && j < b.length()) //error occurs at this line { if (a[i] < b[j]) { mergedArray[k] = a[i]; i++; } else { mergedArray[k] = b[j]; j++; } k++; } while (i < a.length()) { mergedArray[k] = a[i]; i++; k++; } while (j < b.length()) { mergedArray[k] = b[j]; j++; k++; } return mergedArray; } } This program is merging two arrays together into a new array.

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